Write an equation that represents the line use exact numbers points (1,-4) and (3,-5)

The expression that would best fit the situation is: "Andy descended five flights of stairs, and then ascended three floors."

What is Algebraic expression ?

An algebraic expression is a mathematical phrase that can contain variables, constants, and mathematical operations such as addition, subtraction, multiplication, division, and exponentiation. Algebraic expressions are used to represent and solve problems in many areas of mathematics, science, engineering, and finance.

Andy walked down five flights of stairs, and then he walked back up three floors.

The expression that would best fit the situation would be:

Andy descended five flights of stairs, and then ascended three floors.

Therefore, the expression that would best fit the situation is: "Andy descended five flights of stairs, and then ascended three floors."

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The numbers written in descending order are

a. To arrange the given numbers in descending order, we start with the largest number, which is 237 and, and then move on to the next smallest number, which is -327, and so on until we reach the smallest number, which is -723

This is repeated for the other set of numbers

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The probability that a respondent has a pet, given that they have had a pet, is   [tex]0.38[/tex] , or 38%. This means that among the respondents who have had a pet, 38% of them have a pet now.

To find the probability that a respondent has a pet given that they have had a pet, we need to use Bayes' theorem:

[tex]P(Pet | HadPet) = P(HadPet | Pet) \times P(Pet) / P(HadPet)[/tex]

We are given that 33% have a pet now and have had a pet, which means P(HadPet | Pet) = 1 (if someone has a pet, they have had a pet).

We are also given that 87% have had a pet, which means P(HadPet) = 0.87. Finally, we need to find P(Pet), the probability that someone has a pet:

[tex]P(Pet) = 0.33 + 0.13 = 0.46[/tex]

(we add 0.13 because some respondents have had a pet in the past but don't currently have one)

Now we can plug these values into Bayes' theorem:

[tex]P(Pet | HadPet) = 1 \times 0.33 / 0.87 = 0.38[/tex]

Therefore, the probability that a respondent has a pet, given that they have had a pet, is   [tex]0.38[/tex] , or 38%.

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Using the intersecting chords theorem the value of x is 4.

What is chord?

It is the straight line segment that intersects the circle at two points, and it can be of any length or orientation, as long as it lies entirely within the circle.

According to question:17) Using the intersecting chords theorem, we have:AJ * BJ = CJ * DJ

Substituting the given values, we get:

9 * 8 = 6 * CD CD = (9 * 8) / 6CD = 12

Therefore, CD = 12.18)

Again, using the intersecting chords theorem, we have:

AJ * BJ = CJ * DJ

Substituting the given values, we get:

x * (x + 5) = (x + 2) * (x + 2)

Expanding the right-hand side, we get:

x² + 5x = x² + 4x + 4Subtracting x² and 4x from both sides

, we get:x = 4

Therefore, the value of x is 4.

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Notes:

Hi there,

I'm sorry, but I speak English. Also, I really just need the streak and points.

So sorry,

201600823

9. Expression matches with option C: log3 12.
10. Expression matches with option D: log3 36.
11. Expression matches with option A: log3 64.
12. Expression matches with option C: log3 12.

To match the expression with the logarithm that has the same value, we need to simplify each expression and rewrite it

in the form of log3 x.

9. log3 6 + log3 2 = log3 (6 × 2) = log3 12.

Therefore, the expression matches with option C: log3 12.

10. [tex]2 log36 = log36^2 = log3 (6^2)^2 = log3 36.[/tex]

Therefore, the expression matches with option D: log3 36.

11. [tex]6 log32 = log32^6 = log3 (2^5)^6 = log3 2^30.[/tex]

Therefore, the expression matches with option A: log3 64.

12. log3 6 + log3 2 = log3 (6 × 2) = log3 12.

Therefore, the expression matches with option C: log3 12.
In summary:
9. Expression matches with option C: log3 12.

10. Expression matches with option D: log3 36.

11. Expression matches with option A: log3 64.

12. Expression matches with option C: log3 12.

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The triangle with angle measures of 30°, 60°, and 90° is a special type of right triangle called a "30-60-90 triangle"

The triangle with angle measures of 45°, 45°, and 90° is another special type of right triangle called an "isosceles right triangle".

The triangle with angle measures of 30°, 60°, and 90° is a special type of right triangle called a "30-60-90 triangle". In this type of triangle, the smallest angle is 30°, the second angle is 60°, and the largest angle is always 90°.

The triangle with angle measures of 45°, 45°, and 90° is another special type of right triangle called an "isosceles right triangle". In this type of triangle, both of the smaller angles are equal and are always 45°, while the largest angle is always 90°.

However, if a triangle has a 90° angle, but the other angle measures cannot be determined, then there are many different possibilities for the triangle's other two angles. For example, one possible set of angles for such a triangle is 30°, 60°, and 90° (as in the first example), but there are many other sets of angles that could also work. Therefore, without additional information, we cannot determine the other angle measures of the triangle.

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The statement describes a set of interest in a study, which is the set of all elements being investigated or under consideration. It is not a sample, which refers to a subset of the population being studied.

The set of all elements of interest in a study is called the population. It refers to the entire group of individuals, objects, or measurements that are being studied and from which data can be collected. The population can be finite or infinite and can include people, animals, plants, materials, or any other object or concept of interest. In statistical analysis, researchers use samples of the population to make inferences or draw conclusions about the entire population. By selecting a representative sample, researchers can reduce the cost and time required for data collection and analysis while still obtaining valid and reliable results.

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The domain and range of this square root function y = 5/2√(-5x + 1) - 87 are as follows;

Domain = {x|x ≤ 1/5}.

Range = {y|y ≥ -87}.

The domain and range of this square root function y = -315√(11x - 3) - 15/88 are as follows;

Domain = {x|x ≥ 3/11}.

Range = {y|y ≤ -15/88}.

In Mathematics and Geometry, a domain refers to the set of all real numbers for which a particular function is defined.

Additionally, the vertical extent of any graph of a function represents all range values and they are always read and written from smaller to larger numerical values, and from the bottom of the graph to the top.

By critically observing the graph shown in the image attached below for the given square root function y = 5/2√(-5x + 1) - 87 and y = -315√(11x - 3) - 15/88, we can reasonably and logically deduce the following domain and range:

Domain = {-∞, 1/5} or {x|x ≤ 1/5}.

Range = {-87, ∞} or {y|y ≥ -87}.

Domain = {3/11, ∞} or {x|x ≥ 3/11}.

Range = {-∞, -15/88} or {y|y ≤ -15/88}.

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The missing angle m∠U of the quadrilateral is calculated as:  117°

From the given quadrilateral, we see that the angle m∠R is given as 117°.

We also see that the sides TU and RS are congruent to each other. No, we know that the sum of angles of a quadrilateral is 360 degrees.

However, we see that since TU and RS are congruent, this can be likened to an isosceles trapezium and as such the angle m∠U must be equal to the angle m∠R.

Thus:

m∠R = m∠U  = 117°

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Answer:

A one-sample t-confidence interval for means

Step-by-step explanation:

The appropriate statistical procedure to answer the research question in the heart rate scenario depends on the type of comparison being made. If the comparison is between two separate groups, a two-sample t-test or a two-sample t-confidence interval for means should be used.

However, if the comparison is within the same group, a one-sample t-test or a one-sample t-confidence interval for means would be appropriate. In the heart rate scenario, the research question is not clearly stated. However, assuming that the objective is to compare the heart rate of a group of individuals to a known population mean, a one-sample t-test or a one-sample t-confidence interval for means would be the appropriate statistical procedure.

The steps for a one-sample t-test are as follows: (1) State the null and alternative hypotheses, (2) Collect data and calculate the sample mean and sample standard deviation, (3) Calculate the t-value using the formula t = (sample mean - population mean) / (sample standard deviation / square root of sample size), (4) Determine the degrees of freedom, (5) Determine the p-value using a t-distribution table or a statistical software, (6) Compare the p-value to the significance level, and (7) Draw a conclusion based on the p-value and the significance level.

A one-sample t-confidence interval for means follows similar steps but instead of calculating a t-value, a confidence interval is calculated.

Therefore, to answer the research question in the heart rate scenario, a one-sample t-test or a one-sample t-confidence interval for means should be used.

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I hope this solution helps you.

Hence, the force that results has a magnitude of about 10.3 newtons (rounded to the nearest 10th of a newton).

"How much of a quantity" is the definition of magnitude. For instance, the amount of data can be utilized for assessing the speeds of a car and a bicycle. In addition, it can be used to express how far an object has come or how much weight it carries relative to its size.

The law of cosines, which connects a triangle's sides and angles, can be used to calculate the size of the resulting force:

A2 + B2 - 2ab*cos = C2 (C)

We can define the 8.6 newtons in this case as side a, the 3.5 newtons as side b, and the angle between them as C:

a = 8.6 N b = 3.5 N

C = 58°

By applying the law of cosines, we may determine the length of the resultant force or side c.

c = sqrt(105.36)

c ≈ 10.3

Hence, the force that results has a magnitude of about 10.3 newtons (rounded to the nearest 10th of a newton).

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Fractions and percentages are different ways of representing the same value.

A percentage is simply another way of writing a fraction with a denominator of 100. For example, 25% is equivalent to the fraction 25/100 or the reduced fraction 1/4. Similarly, 75% is equivalent to 75/100, which can be reduced to 3/4.

When comparing fractions and percentages, it's important to remember that they represent the same value, but they are expressed in different ways. Fractions are typically used when dealing with ratios or proportions, while percentages are used to express a part of a whole in terms of hundredths.

For example, if you have 6 out of 10 apples, you can express this as a fraction (6/10) or as a percentage (60%). Both the fraction and the percentage represent the same value: 6 out of 10 or 60 out of 100.

To compare fractions and percentages, you can convert between them if necessary using the fact that 1% is equivalent to 1/100. Otherwise, you can use whichever representation is most appropriate for the context of the problem you are trying to solve.

The expected value for each roll is [tex](1+2+3+4+5+6)/6 = 3.5.[/tex]

The average of Brandon's rolls, we simply add up all the results and divide by the number of rolls:
[tex](1+2+2+3+4+6+2+1+5+6+1+6+2+6+4+6+2+6+4+6)/20 = 3.6[/tex]
So the average of Brandon's rolls is 3.6.
Now we need to count how many times he rolled above the average. To do this, we simply count how many rolls were greater than 3.6:
4, 6, 5, 6, 6, 4, 6, 6, 4, 6, 6, 6, 4, 6, 6, 6, 4, 6, 4, 6
There were 18 rolls that were greater than 3.6, so Brandon rolled above the average 18 times.
In summary, Brandon rolled a six-sided die 20 times and recorded the results in a table. To find out how many times he rolled above the average, we first calculated the average roll to be 3.6. We then counted how many times he rolled above this value and found that he did so 18 times.

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[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{V_{(cylinder) } = \pi\:r^2\:h \: cubic \:units }\\[/tex]

Where -

As per question, we are given that-

Now that, we are given all the required values, so we can put all the values into the formula and solve for the height -

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{Volume _{(cylinder) } = \pi\:r^2\:h }\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf 1800= 3.14 \times \bigg(7\bigg)^2 \times h\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf 1800 = 3.14 \times 7\times 7\times h\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf 1800 =3.14 \times 49 \times h\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf 1800 =153.86\times h\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf 153.86\times h=1800\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf h = \dfrac{1800}{153.86}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf h = 11.69894...........\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{ h =11.69\: inch }\\[/tex]

Therefore, the length of height [tex] \sf \underline{ \pink{11.69\: inch }}\\[/tex]

The number of possible license plates is  2,176,782,336

To calculate the number of possible Nebraska license plates with 6 characters, we will use the counting principle.

Each character can either be a number (0-9) or a letter (A-Z). There are 10 possible numbers and 26 possible letters. So, for each character,

there are [tex]36 (10 + 26)[/tex]possibilities.
Now, we will apply the counting principle to find the total number of combinations. The counting principle states that if there are n ways to do one thing and m ways to do another, there are n * m ways to do both.
In our case, there are 6 characters on the license plate, and each character has 36 possible options.

Therefore, the number of possible license plates is:
[tex]36 * 36 * 36 * 36 * 36 * 36 = 36^6 = 2,176,782,336[/tex]
There are 2,176,782,336 possible Nebraska license plates with 6 characters, each filled with a number (0-9) or a letter (A-Z).
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Volume of the award is 510.25 square centimeter.

Volume is a measure of the amount of space that a three-dimensional object occupies. It is a physical quantity that is typically measured in cubic units, such as cubic meters (m³) or cubic centimeters (cm³).

The volume of an object is calculated by multiplying its three dimensions together. For example, the volume of a rectangular prism can be calculated by multiplying its length, width, and height. The formula for the volume of a rectangular prism is V = l x w x h, where V is the volume, l is the length, w is the width, and h is the height.

Given;

Height of the conical part, h=12cm

Radius of the conical part, r=5cm

Height of the cylindrical part, H=2.5cm

Total volume of award=Volume of conical part+ Volume of cylindrical part

=πr²h/3+πr²H

=π×5²×12/3+π×5²×2.5

=314+196.25

=510.25cm²

Hence, volume of the award is 510.25 square centimeter.

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Ariel got a job at a restaurant and needed to purchase 2 shirts and 2 pairs of pants.

Let's use the variable "x" to represent the number of shirts Ariel buys and "y" to represent the number of pants she

buys.

Then, we can write the following system of inequalities:

2 ≤ x ≤ ∞ (Ariel needs at least 2 shirts)

2 ≤ y ≤ ∞ (Ariel needs at least 2 pairs of pants)

7.50x + 18y ≤ 150 (Ariel wants to spend no more than 150)

Now, we can graph the system of inequalities on a coordinate plane to find the feasible region, which represents all the possible combinations of shirts and pants that satisfy the given constraints.

The feasible region is shaded in the graph below:

graph {(150-7.5 × x)/18}

As you can see from the graph, the feasible region is a quadrilateral with vertices at (0, 8.33), (2, 7), (8, 3), and (25, 0).

This means that Ariel can buy any combination of shirts and pants within this region and still meet her requirements.

To find the optimal solution, we can simply check the corner points of the feasible region and see which combination gives us the most value for our money.

For example, if Ariel buys 2 shirts and 2 pants (i.e., the point (2, 2) on the graph), she will spend:

7.50(2) + 18(2) = 51

This is within her budget of 150 and meets her requirement of at least 2 shirts and 2 pants.

Therefore, the answer is: Ariel should buy 2 shirts and 2 pairs of pants.

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There are two stiff transforms to use:

The fact that the real domain is the domain of quadratic functions makes it possible to identify the solution set.

Thus, we must decide which rigid transformations to apply to f(x) in order to produce g(x). Rigid transformations are transformations applied to geometric loci in the field of Euclidean geometry so that Euclidean distances within the latter are conserved (x).

Following thorough consideration, we come to the conclusion that the two stiff transformations listed below must be used:

Vertical translation 7 units to the plus side.

reflection along the y = 5 line.

The collection of x-values necessary for the function to exist is represented by the solution set.  Due to the fact that both functions are quadratic equations, the entire real domain is described by their solutions.

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The value of the area of the triangle in square cm is 4.51 sq. cm.

On a two-dimensional plane, a triangle's area is the area that it completely encloses. A triangle is a closed form with three sides and three vertices, as is common knowledge. The entire area occupied by a triangle's three sides is referred to as its area. Half of the product of the triangle's base and height provides the standard formula for calculating the area of the triangle.

The area of the triangle is given by:

A = 1/2(b)(h)

Substitute the value of b = 4.1 cm and h = 2.2 cm we have:

A = 1/2(4.1)(2.2)

A = (4.1)(1.1)

A = 4.51 sq. cm.

Hence, the value of the area of the triangle in square cm is 4.51 sq. cm.

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Answer:

Option D

Step-by-step explanation:

'Height h’ is plotted on the y-axis, which has units of ft. 'Years after planning’ is plotted on the x-axis, which has units of yr.

Rate of change is denoted by the slope or gradient m  of the graph

m = [tex]\frac{Rise}{Run}[/tex]

Rise = Δy

       = Change along the y-axis

       = Difference in values along the y-axis

Run = Δx

       = Change along the x-axis

       = Difference in values along the x-axis

∴Rate of Change for this graph will have units of [tex]\frac{ft}{yr}[/tex]

The actual value can be calculated using coordinates of any two points along this graph

I used [tex](2, 7)[/tex] as [tex](x_{1} , y_{1})[/tex] and [tex](3, 9.5)[/tex] as [tex](x_{2} , y_{2})[/tex]:

m = [tex]\frac{y_{2} - y_{1}}{x_{2} -x_{1}}[/tex]

   = [tex]\frac{(9.5 - 7) ft}{(3 -2) yr}[/tex]

   = [tex]\frac{2.5ft}{1yr}[/tex]

∴ Rate of Change in tree’s height = 2.5 [tex]\frac{ft}{yr}[/tex]

∴ Option D

The best graph to use to display this data of costs and quantity of books offered for sale in a bookstore is a scatter plot.

a. Since the data includes prices and the number of books sold at each price, a scatter plot would be the most appropriate type of graph for displaying this data. A scatter plot is used to show the relationship between two quantitative variables, where one variable is plotted on the x-axis and the other variable is plotted on the y-axis. In this case, we can plot the price of each book on the x-axis and the number of books sold at each price on the y-axis. This will allow us to see if there is a relationship between the price of the book and the number of books sold.

b. In the scatter plot, each point represents a different price and the corresponding number of books sold at that price. We can see that there is a negative relationship between price and the number of books sold - as the price increases, the number of books sold decreases. We can also see that there are a few outliers, such as the point at $5.00 where 39 books were sold and the point at $17.25 where 18 books were sold.

The complete question is:-

7. The table shows the prices and number of books sold in a bookstore.

a. Analyze and preserve. What type of graph is most appropriate for displaying this data? explain

b. Graph the data.

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The list with the smallest standard deviation is the following: 16, 12, 13, 16, 14, 15, 16, 14, 14, 13.

What is standard deviation?

Standard deviation is a statistical measure of the variability of a set of data values. It's a step-by-step process for determining how far each value is from the mean. It is important since it may reveal the amount of variability in a set of data. The formula for calculating standard deviation is as follows:

σ=√∑(x−μ)²nσ=√∑(x−μ)²n

In this equation, x represents the values in the data set, μ represents the mean of the data set, and n represents the number of values in the data set. Let us now compute the standard deviation of each of the given data sets, starting with the first one. We can utilize the formula given above to do so:

6, 19, 9, 18, 19, 9, 17, 18, 17, 15                        μ = 15.8,σ = 4.83 (rounded to two decimal places)

31, 30, 26, 28, 18, 28, 18, 21, 23, 32                μ = 25.5,σ = 5.93 (rounded to two decimal places)

20, 21, 20, 19, 25, 24, 19, 14, 21, 15                μ = 19.8,σ = 3.98 (rounded to two decimal places)

14, 20, 16, 14, 28, 13, 17, 21, 12, 22                μ = 17.7,σ = 4.96 (rounded to two decimal places)

16, 12, 13, 16, 14, 15, 16, 14, 14, 13                  μ = 14.3,σ = 1.96 (rounded to two decimal places)

The list with the smallest standard deviation is the following: 16, 12, 13, 16, 14, 15, 16, 14, 14, 13.

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The distance between P(3, 3) and Q(6.5, 11.75) is approximately 9.42 units.

We can use the distance formula to find the distance between two points in a coordinate plane. The distance formula is

where (x1, y1) and (x2, y2) are the coordinates of the two points, and d is the distance between them.

Using the given coordinates of points P and Q, we can find the distance between them as follows:

[tex]d = sqrt((6.5 - 3)^2 + (11.75 - 3)^2)[/tex]

= [tex]sqrt(3.5^2 + 8.75^2)[/tex]

= [tex]sqrt(12.25 + 76.5625)[/tex]

= [tex]sqrt(88.8125)[/tex]

≈[tex]9.42[/tex]

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The shaded area of the figure is equal to 297 square centimeters.

In this question we find a shaded figure, whose area can be found as a subtraction of the areas of two triangles from the area of a rectangle. The area formulas are defined below:

Rectangle

A = b · h

Triangle

A = 0.5 · b · h

Where:

Now we proceed to compute the shaded area:

A = (18 cm) · (22 cm) - 0.5 · (9 cm) · (13.2 cm) - 0.5 · (9 cm) · (8.8 cm)

A = 297 cm²

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With Scaling Factor = 1/2,  the coordinate location of the dilated point C' is (2, -3).

What exactly is scaling factor?

In mathematics, a scaling factor is a ratio that describes how much a figure or object has been enlarged or reduced in size. A scaling factor is typically expressed as a fraction or decimal that represents the relative change in size between the original figure and the new, scaled figure.

Now,

To find the coordinate location of the dilated point C', we can use the following formula:

C' = (1 - k) * C + k * A

where:

C is the original point (3, -1)

A is the center of dilation (1, -5)

k is the scaling factor (1/2)

then,

C' = (1 - 1/2) * (3, -1) + (1/2) * (1, -5)

C' = (1/2) * (3, -1) + (1/2) * (1, -5)

C' = [(1/2) * 3 + (1/2) * 1, (1/2) * (-1) + (1/2) * (-5)]

C' = [(3/2) + (1/2), (-1/2) + (-5/2)]

C' = (2, -3)

Therefore, the coordinate location of the dilated point C' is (2, -3).

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Answer:

Kelli is close to the truth if one considers that the approximation of 118.81 is equal to 118

Step-by-step explanation:

Area of a square = side²

Then:

let´s see if:

118 = 10.9²

10.9² = 10.9 * 10,9 = 118.81

118 is approximately equal to 118.81

Answer:

please what is your question