X is a normal random variable with E[X] = -3 and V[X] = 4, compute a) ( ≤ 2.39) b) ( ≥ −2.39) c) (|| ≥ 2.39) d) (| + 3| ≥ 2.39) e) ( < 5) f) (|| < 5) g) With probability 0.33, variable X exceeds what value?

The Null hypothesis is that the population mean depression score of all college students is less than or equal to 38 (H₀: µ ≤ 38) while the Alternative hypothesis is that the population mean depression score of all college students is greater than 38 (Ha: µ > 38).

Null hypothesis: The population mean depression score of all college students is less than or equal to 38 (H₀: µ ≤ 38).

Alternative hypothesis: The population mean depression score of all college students is greater than 38 (Ha: µ > 38).

Step 2: Test statistic

We will use a one-sample t-test since the population standard deviation is known and the sample size is greater than 30. The test statistic is calculated as:

t = (x - µ) / (σ / √(n))

where x is the sample mean, µ is the hypothesized population mean, σ is the population standard deviation, and n is the sample size.

Plugging in the numbers, we get:

t = (40 - 38) / (16 / √(64))

t = 2

Step 3: P-value

Using a t-table with 63 degrees of freedom (df = n - 1), we find the p-value for a one-tailed test with a t-value of 2 is approximately 0.025.

Step 4: Decision

Since the p-value (0.025) is less than the alpha level (0.025), we reject the null hypothesis.

Step 5: Conclusion

There is sufficient evidence to suggest that the population mean depression score of all college students is greater than 38.

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The probability that a student who attends the first session also attends the second session is 1/3

We can approach this problem by using conditional probability.

Let's use the notation "S1" to represent the event that a student attends the first session, and "S2" to represent the event that a student attends the second session.

Then we can use the formula for conditional probability:

P(S2 | S1) = P(S1 and S2) / P(S1)

We know that P(S1) = 0.6, since 60% of students attend the first session. We also know that P(S1 and S2) = 0.2, since 20% of students attend both sessions.

So we can plug in these values and solve for P(S2 | S1):

P(S2 | S1) = 0.2 / 0.6

P(S2 | S1) = 1/3

Therefore, the probability that a student who attends is 1/3 or approximately 0.333.

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The value of the expression is 142.

What is Algebraic expression ?

An algebraic expression is a mathematical phrase that can contain variables, constants, and mathematical operations such as addition, subtraction, multiplication, division, and exponentiation. Algebraic expressions are used to represent and solve problems in many areas of mathematics, science, engineering, and finance.

To solve this expression, we need to follow the order of operations (PEMDAS) which stands for Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction.

Let's start with the parentheses first:

14 x 0.5 x (4 + 2) + exponent 10*2

= 14 x 0.5 x 6 + exponent 10*2

Next, we can simplify the multiplication and division from left to right:

= 7 x 6 + exponent 10*2

= 42 + exponent 10*2

Now we can evaluate the exponent:

= 42 + 100

= 142

Therefore, the value of the expression is 142.

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The total area of the trapezoid is approximately 273.664 square yards. The Option A is correct.

The area of a trapezoid is found using the formula, A = ½ (a + b) h, where 'a' and 'b' are the bases (parallel sides) and 'h' is the height (the perpendicular distance between the bases) of the trapezoid.

To find the area of the figure, we need to divide it into two triangles and find the area of each triangle.

The area of the first triangle (with base 21.3 yards and height 12.8 yards) is:

(1/2) * base * height = (1/2) * 21.3 * 12.8 = 136.704 square yards.

The area of the second triangle (with base 6.4 yards and height 12.8 yards) is:

(1/2) * base * height = (1/2) * 6.4 * 12.8 = 41.216 square yards.

The area of the third triangle (with base 14.9 yards and height 12.8 yards) is:

(1/2) * base * height = (1/2) * 14.9 * 12.8 = 95.744 square yards.

Now, the total area of the figure is the sum of the areas of these three triangles:

= 136.704 + 41.216 + 95.744

= 273.664 square yards.

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Option C) 0 <= x <= 12 and 16 <= y <= 48 would be reasonable constraints for the context.

What is the inequality equation?

An inequality equation is a mathematical statement that compares two expressions using an inequality symbol such as < (less than), > (greater than), ≤ (less than or equal to), or ≥ (greater than or equal to).

The x-axis represents the number of hours since 9 AM, which can range from 0 to 12 since the shift ends at 9 PM.

The y-axis represents the number of patients, which can realistically range from 16 to 48 as hospitals can have varying levels of patient traffic.

The constraint includes the endpoints of the range, which makes it more accurate.

Hence, Option C) 0 <= x <= 12 and 16 <= y <= 48 would be reasonable constraints for the context.

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The linear equatiοn has infinite sοlutiοns.

When twο expressiοns are jοined by the equal sign ('='), a mathematical statement is created. In οrder tο be determined, there must be at least οne unknοwn variable. An equatiοn is sοmething like 3x - 8 = 16. This equatiοn can be sοlved tο yield x = 8.Any οne variable linear equatiοns can have zerο, οne οr infinite sοlutiοns.

Emma substitutes 3 fοr x in a οne-variable linear equatiοn and finds that it makes the equatiοn true. She then substitutes 5 fοr x in the same linear equatiοn and finds that 5 alsο makes the equatiοn true.

If Emma tested twο values 3 and 5 fοr the same οne variable linear equatiοn and they were bοth true sοlutiοns, this means that the equatiοn has mοre than οne sοlutiοn.

If a οne variable linear equatiοn has mοre than οne sοlutiοn, than the equatiοn has infinite sοlutiοns.

Hence, the linear equatiοn Emma is talking abοut has infinite number οf sοlutiοns.

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Rolle’s Theorem can be applied to the closed interval.

What is the Rolle’s Theorem?

In essence, Rolle's theorem or Rolle's lemma argues that there must be at least one stationary point—a position where the first derivative is zero—between any two separate sites where a real-valued differentiable function achieves equal values. The theorem bears Michel Rolle's name.

Here, we have

Given: f(x) = -x² + 3x, [0,3]

We must determine whether Rolle’s Theorem can be applied to the closed interval.

f(x) is continuous in the closed interval  [0,3].

f(x) is differentiable in the open interval (0,3)

f(0) = 0 + 0 = 0

Rolle's theorem can be applied.

f'(x) = -2x + 3

f'(x) = 0

-2x + 3 = 0

3 = 2x

x = 2/3

2/3 lies inside the [0,3].

Hence, Rolle’s Theorem can be applied to the closed interval.

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The vector v can be represented as (-2, 4) and has a magnitude of 2√5.

A vector is a quantity that not only describes the magnitude but also describes the movement of an object or the position of an object with respect to another point or object. It is also known as Euclidean vector, geometric vector or spatial vector.

To plot the vector v with an initial point at (0, -1) and a terminal point at (-2, 3), we can draw a line segment from the initial point to the terminal point. The vector v is represented by the direction and magnitude of this line segment.

To analyze the vector v, we can calculate its components and magnitude:

Components: The components of v are the differences between the x-coordinates and y-coordinates of the terminal point and initial point, respectively. We have:

v = (-2 - 0, 3 - (-1)) = (-2, 4)

Magnitude: The magnitude of v is the length of the line segment connecting the initial point and terminal point. We can use the Pythagorean theorem to find the magnitude:

||v|| = √(-2-0)² + (3 - (-1))²) = √20 = 2√5

Therefore, the vector v can be represented as (-2, 4) and has a magnitude of 2√5.

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Answer:

the missing values are 2, 8, and 3.

Option D is equivalent to 30 - 29m, which is equivalent to option B (8 / m) only if m is not equal to zero.

What is the equivalent expression?

Equivalent expressions are expressions that perform the same function despite their appearance. If two algebraic expressions are equivalent, they have the same value when we use the same variable value.

In the given options, option A and B are not equivalent, option C is not equivalent to any other option, and option D is equivalent to option B.

Option A can be written as 5m + 35 using the distributive property of multiplication over addition.

Option B can be simplified as follows:

(15 - 7) / m = 8 / m

Therefore, option B is equivalent to 8 / m.

Option C cannot be simplified to any other expression in the given options.

Option D can be simplified as follows:

30 - (m * 29) = 30 - 29m

Therefore, option D is equivalent to 30 - 29m, which is equivalent to option B (8 / m) only if m is not equal to zero.

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Answer:

JK is a line segment

Step-by-step explanation:

Answer: 1second

Step-by-step explanation:

a. He did not distribute the negative sign, which resulted in changing the signs of the terms inside the parentheses.

b. The correct simplification of the expression is 33-20x.

What is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas. It involves the study of variables, expressions, equations, and functions.

a. Victor made an error in the second step where he distributed only the coefficient 4 to both terms inside the parentheses. However, he did not distribute the negative sign, which resulted in changing the signs of the terms inside the parentheses.

b. To correct Victor's work, we need to distribute both the coefficient 4 and the negative sign to all the terms inside the parentheses, which gives us:

9 - 4(5x - 6)

9 - 20x + 24 (distribute)

33 - 20x (combine like terms)

Therefore, the correct simplification of the expression is 33-20x.

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Step-by-step explanation:

so you can do in this way , hope it will give you clue

Answer: Length = 28 m , Breadth = 12 m

Step-by-step explanation:

(p.s look at the document before looking at this explanation so that you understand.)

So,

lets keep the breadth of the field as x,

Breadth = x

Length = 2x + 4

Perimeter = 2 breadths + 2 lengths

          80  = 2 ( x ) + 2( 2x + 4 )

          80  = 2x + 4x + 8

          80  = 6x + 8

          6x  = 80 - 8

                = 72

           x = 72/ 6

              = 12 ( breadth )

     Length = 2 (12) + 4

                  = 28

Checking

28m + 28m + 12m + 12m = 80

The measure of angle m<BAC = 110 and the measure of angle m<ABC = 35.

The angle sum property of the triangle state that the sum of interior angles of triangles is 180.

<CDB = 55 (Given)

By degree measure theorem

<CAB = 2 <CDB

<CAB = 2 * 55 = 110

Again AC = AB (Radius of the circle)

Then

<ACB = <ABC (angles opposite to equal sides)

let <ACB = m

In triangle ACB,

By angle sum property: <ACB + <ABC + <CAB =180

m + m + 100 = 180

2m = 180 - 110

2m = 70

m = 70/2 = 35

<ACB = <ABC = 35

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Let L be the original length of the rectangle and W be the original width of the rectangle. We know that:

(L - 6) = (W + 3) (1) (since the length is decreased by 6cm and the width is increased by 3cm, the result is a square)

The area of the rectangle is LW, and the area of the square is (L - 6)(W + 3). We also know that the area of the square is 27cm^2 smaller than the area of the rectangle. So we can write:

(L - 6)(W + 3) = LW - 27 (2)

Expanding the left side of equation (2), we get:

LW - 6W + 3L - 18 = LW - 27

Simplifying and rearranging, we get:

3L - 6W = 9

Dividing both sides by 3, we get:

L - 2W = 3 (3)

Now we have two equations with two unknowns, equations (1) and (3). We can solve this system of equations by substitution. Rearranging equation (1), we get:

L = W + 9

Substituting this into equation (3), we get:

(W + 9) - 2W = 3

Simplifying, we get:

W = 6

Substituting this value of W into equation (1), we get:

L - 6 = 9

So:

L = 15

Therefore, the area of the rectangle is:

A = LW = 15 x 6 = 90 cm^2.

Answer:

252

Step-by-step explanation:

lol I take rsm too and I just guessed and checked

Answer:

15 cm (shorter side)

50 cm (longer side)

Step-by-step explanation:

Let the length of the shorter side of the parallelogram be x cm. Then, the length of the longer side is (2x + 20) cm. Since a parallelogram has opposite sides equal in length, there will be two shorter sides and two longer sides.

The perimeter of the parallelogram is given as 130 cm. The sum of the lengths of all four sides is equal to the perimeter. Therefore, we can set up the following equation:

2x + 2(2x + 20) = 130

Now, we can solve for x:

2x + 4x + 40 = 130

6x + 40 = 130

6x = 130 - 40

6x = 90

x = 90/6

x = 15

Now that we have found the length of the shorter side (x), we can find the length of the longer side:

Longer side = 2x + 20 = 2(15) + 20 = 30 + 20 = 50

So, the dimensions of the parallelogram are 15 cm (shorter side) and 50 cm (longer side).

The dimensions of the parallelogram are 15 cm x 50 cm.

A parallelogram is a quadrilateral with two pairs of parallel sides. The opposite sides of a parallelogram are equal in length, and the opposite angles are equal in measure.

Given that, in a parallelogram, the longer side is 20 cm longer than twice the shorter side. the perimeter is 130 cm.

We need to find the dimension of the parallelogram,

Let the length of the shorter side of the parallelogram be x cm.

Then, the length of the longer side is (2x + 20) cm.

The perimeter of the parallelogram is given as 130 cm.

Therefore, we can set up the following equation:

2x + 2(2x + 20) = 130

Now, we can solve for x:

2x + 4x + 40 = 130

6x + 40 = 130

6x = 130 - 40

6x = 90

x = 90/6

x = 15

Longer side = 2x + 20 = 2(15) + 20 = 30 + 20 = 50

Hence, the dimensions of the parallelogram are 15 cm x 50 cm.

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Taking the square root of both sides of the inequality, we get:

||U + V|| ≤ ||U|| + ||V||

The triangle inequality theorem states that, the sum of the length of two sides must be greater than the length of the third side of that triangle.

To prove it, we start by squaring both sides of the inequality:

||U + V||² ≤ (||U|| + ||V||)²

Expanding the right-hand side of the inequality, we get:

||U + V||² ≤ ||U||² + 2||U|| ||V|| + ||V||²

Now, let's use the fact that ||U + V||² = (U + V) · (U + V), where · denotes the dot product:

(U + V) · (U + V) ≤ ||U||² + 2||U|| ||V|| + ||V||²

Now, we have:

||U||² + 2U · V + ||V||² ≤ ||U||² + 2||U|| ||V|| + ||V||²

Therefore, we have:

||U + V||² ≤ ||U||² + 2||U|| ||V|| + ||V||²

≤ ||U||² + 2U · V + ||V||²

= (||U|| + ||V||)²

Taking the square root of both sides of the inequality, we get:

||U + V|| ≤ ||U|| + ||V||

This is exactly what we wanted to prove. Therefore, we have shown that ||U + V|| ≤ ||U|| + ||V||.

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Answer:

whooper write an equation of the line in slope-intercept form for each of the following write an equation of the line in slope-intercept form for each of the following write an equation of the line in slope-intercept form for each of the following write an equation of the line in slope-intercept form for each of the following

Step-by-step explanation:

The length of Z is 5.65 which is the sum of 3+2.65=5.65

How to find the length?

To find the length of the perpendicular, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the legs (base and perpendicular).

So, if the hypotenuse is 4 and the base is 3, we can find the length of the perpendicular (P) as follows:

4² = 3² + P²

16 = 9 + P²

P² = 16 - 9

P²= 7

P = sqrt(7)

Therefore, the length of the perpendicular is sqrt(7), which is approximately 2.65 units (rounded to two decimal places).

To find the length of the hypotenuse, we can again use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the legs (base and perpendicular).

So, if the base is 2.65 and the perpendicular is also 2.65, we can find the length of the hypotenuse (H) as follows:

H²= 2.65² + 2.65²

H² = 7.0225 + 7.0225

H²= 14.045

H = sqrt(14.045)

Therefore, the length of the hypotenuse is sqrt(14.045), which is approximately 3.75 units (rounded to two decimal places).

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The probability that the fire department arrives at the scene in 8 minutes or less is approximately 0.9772 or 97.72%.

What is the standard deviation?

The standard deviation is a measure of the amount of variation or dispersion in a set of data. It measures how much the data deviates from the mean value.

We are given that the times the fire department takes to arrive at the scene of an emergency are normally distributed with a mean of 6 minutes and a standard deviation of 1 minute.

Let X be the random variable representing the time taken by the fire department to arrive at the scene of an emergency. Then, we have:

X ~ N(6, 1)

We want to find the probability that the fire department arrives at the scene in 8 minutes or less. Mathematically, we want to find:

P(X ≤ 8)

To find this probability, we can standardize the random variable X by subtracting the mean and dividing by the standard deviation:

Z = (X - μ) / σ

Substituting the values of μ and σ, we get:

Z = (X - 6) / 1

Z represents the standard normal distribution with a mean of 0 and a standard deviation of 1. Therefore, we can use a standard normal distribution table or calculator to find the probability that Z is less than or equal to the standardized value of 8:

P(Z ≤ (8 - 6) / 1) ≈ P(Z ≤ 2)

Looking up the probability of Z being less than or equal to 2 in a standard normal distribution table, we find that it is approximately 0.9772.

Therefore, the probability that the fire department arrives at the scene in 8 minutes or less is approximately 0.9772 or 97.72%.

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the rectangular equation that is equivalent to the given parametric equations is: [tex]4(x-2)^2 + 9(y+1)^2 = 36[/tex]

The given parametric equations describe a curve in the xy-plane traced by a particle that moves along a circular path centered at (2,-1) with radius 3. To find the rectangular equation, we can use the following trigonometric identity:

[tex]cos^2[/tex]θ + [tex]sin^2[/tex]θ = 1

Multiplying both sides by [tex]3^2[/tex], we get:

9[tex]cos^2[/tex]θ + [tex]9sin^2[/tex]θ = 9

Rearranging and using the fact that cosθ = (x-2)/3 and sinθ = (y+1)/2, we get:

[tex]9((x-2)/3)^2 + 9((y+1)/2)^2 = 9[/tex]

Simplifying, we get:

[tex](x-2)^2/3^2 + (y+1)^2/2^2 = 1[/tex]

Multiplying both sides by 36, we get:

[tex]4(x-2)^2 + 9(y+1)^2 = 36[/tex]

Therefore, the rectangular equation that is equivalent to the given parametric equations is:

[tex]4(x-2)^2 + 9(y+1)^2 = 36[/tex]

This equation represents an ellipse centered at (2,-1) with semi-axes of length 3 and 2 along the x-axis and y-axis, respectively. The parameter θ varies from 0 to 2π, which means the particle completes one full revolution around the ellipse.

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By calculating the z-score, we can conclude that, Team A has better eligibility rates than Team B.

What is z-score?

A z-score (also called a standard score) is a measure of how many standard deviations a given data point is away from the mean of its distribution. It is calculated by subtracting the mean of the distribution from the data point, and then dividing the difference by the standard deviation.

To determine this, we can compare the z-scores for each team's eligibility rates.

Let's assume that Team A's eligibility rate is 875 and Team B's eligibility rate is 825.

The mean eligibility rate for all teams is given as 870, with a standard deviation of 50. Therefore, we can calculate the z-scores for each team's eligibility rate as follows:

z-score for Team A's eligibility rate = (875 - 870) / 50 = 0.1

z-score for Team B's eligibility rate = (825 - 870) / 50 = -0.9

Since the z-score for Team A's eligibility rate is positive and greater than the z-score for Team B's eligibility rate, we can conclude that Team A has better eligibility rates than Team B.

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Answer:

29 blocks

Step-by-step explanation:

You've to count the number of blocks and that's the volume.

So, the dimensions that minimize the production costs are approximately:

Radius (r): 3.824 cm

Height (h): 7.610 cm

To minimize the production cost of the cup-of-soup package, we need to find the dimensions of the cylindrical container that minimize the surface area, as the cost is directly proportional to the surface area of the materials used.

Let r be the radius of the base and h be the height of the cylinder. The volume V of the cylinder is given by:

V = πr^2h

We know that the volume is 350 cubic centimeters:

350 = πr^2h

Now, let's express the height h in terms of the radius r:

h = 350 / (πr^2)

The surface area A of the cylinder consists of the area of the sides, the bottom, and the top:

A = (side area) + (bottom area) + (top area)

The side area of the cylinder is given by 2πrh, the bottom area is given by πr^2, and the top area is given by πr^2. So, the surface area A can be expressed as:

A = 2πrh + πr^2 + πr^2

Now, let's substitute h from the previous equation to express A in terms of r only:

A = 2πr(350 / (πr^2)) + πr^2 + πr^2

A = 700/r + 2πr^2

Next, we'll find the critical points of the function A(r) to find the minimum production cost. To do this, we'll differentiate A(r) with respect to r and set the derivative equal to 0.

dA/dr = -700/r^2 + 4πr

Now, set dA/dr = 0 and solve for r:

0 = -700/r^2 + 4πr

Rearrange the equation to isolate r:

700/r^2 = 4πr

Now, multiply both sides by r^2:

700 = 4πr^3

Divide both sides by 4π:

r^3 = 700 / (4π)

Now, find the cube root of both sides:

r = (700 / (4π))^(1/3)

Now, we can find the height h using the equation we derived earlier:

h = 350 / (πr^2)

Plug in the value of r:

h = 350 / (π(700 / (4π))^(2/3))

These are the dimensions of the cylinder that minimize the production costs: radius r and height h.

To get the final answers for the radius r and height h, we need to calculate the numerical values:

r = (700 / (4π))^(1/3)

r ≈ (700 / (4 × 3.14159265))^(1/3)

r ≈ (700 / 12.56637061)^(1/3)

r ≈ 55.75840735^(1/3)

r ≈ 3.824

Now, let's calculate the height h:

h = 350 / (π(700 / (4π))^(2/3))

h = 350 / (π(3.824^2))

h ≈ 350 / (π × 14.623)

h ≈ 350 / 45.978

h ≈ 7.610

So, the dimensions that minimize the production costs are approximately:

Radius (r): 3.824 cm

Height (h): 7.610 cm

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the roots of the polynomial [tex]x^{5}[/tex] - [tex]7x^{3}[/tex] + 10x are 0, ±√5, and ±√2. Thus, the other factors of f(x) are (x+√5), (x-√5), (x+√2), and (x-√2).

What is polynomial?

A polynomial is a mathematical expression that consists of variables and coefficients, which are combined using arithmetic operations such as addition, subtraction, multiplication, and non-negative integer exponents.

If (x+1) is a factor of f(x), then f(-1) = 0. Thus, we can substitute -1 for x in the expression for f(x) and solve for k:

f(-1) = [tex](-1)^{6}[/tex] - 6[tex](-1)^{4}[/tex] + 17[tex](-1)^{2}[/tex] + k = 1 - 6 + 17 + k = 12 + k

Since f(-1) = 0, we have:

12 + k = 0

Solving for k, we find:

k = -12

So, when k = -12, (x+1) is a factor of f(x).

To find another factor of f(x), we can divide f(x) by (x+1) using polynomial long division or synthetic division. The result is:

f(x) = (x+1)([tex]x^{5}[/tex] - [tex]7x^{3}[/tex] + 10x)

So, another factor of f(x) is (x+a), where a is a root of the polynomial x^5 - 7x^3 + 10x. We can find the roots of this polynomial using a numerical method or by factoring it using the rational root theorem. By inspection, we can see that x=0 is a root, so we can factor out x:

x([tex]x^{4}[/tex] - [tex]7x^{2}[/tex] + 10) = 0

The quadratic factor can be factored further as:

x([tex]x^{2}[/tex] - 5)([tex]x^{2}[/tex] - 2) = 0

So, the roots of the polynomial [tex]x^{5}[/tex] - [tex]7x^{3}[/tex] + 10x are 0, ±√5, and ±√2. Thus, the other factors of f(x) are (x+√5), (x-√5), (x+√2), and (x-√2).

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Answer:

Step-by-step explanation:

Answer:

30º

Step-by-step explanation:

LP-MO=0.5(∠LNP)

112º-MO=2(41º)

MO = 30º

a) The total volume equals the sum of the volumes.

[tex]500 = x + y[/tex]

The total octane amount equals the sum of the octane amounts.

[tex]89(500) = 87x + 92y[/tex]

[tex]44500 = 87x + 92y[/tex]

b)

As x increases, y decreases.

c) Use substitution or elimination to solve the system of equations.

[tex]44500 = 87x + 92(500-x)[/tex]

[tex]44500 = 87x + 46000 - 92x[/tex]

[tex]5x = 1500[/tex]

[tex]x = 300[/tex]

[tex]y = 200[/tex]

The required volumes are 300 gallons of 87 gasoline and 200 gallons of 92 gasoline.

Using properties of square,

a. Equation for total area = 2x² - 16x + 64

b. Area will be minimum for the value of x = 0

c. Minimum area will be 64cm².

With four equal sides, a square is a quadrilateral. There are numerous square-shaped objects in our immediate environment. The equal sides and 90° internal angles of each square form serve as indicators of its identity.

Total length of wire = 32cm.

Now side of one square is given as x.

Perimeter of big square will be = 4x.

Now perimeter of small square = 32- 4x.

Side of small square = (32-4x)/4

= 4(8-x)/4

= 8-x

Area of big square = x × x

= x².

Area of small square = (8-x) ².

Now Total area, A(x) = x² + (8-x) ²

= x² + 64 + x² - 16x

= 2x² - 16x + 64

The side length that will minimize the area will be, x = 0.

Minimum area of the total figure will be = 64cm²

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