Answer:
DE=6.3
Step-by-step explanation:
triangles are similar so, its sides and angles are comgruent.
side BC=side DE
side BC=6.3
side DE=6.3
Note:if you need to ask any question please let me know.Which is an
appropriate estimate
for this addition
problem?
462
543
844
+ 921
Perform the operation.
(3x2 – 7x) – (4x2 + 6x)
Answer:
(3x2-7x)-(4x2+6x)= −x^2−13x
Step-by-step explanation:
(3x2-7x)-(4x2+6x)
Distribute the Negative Sign:
=3x^2−7x+−1(4x^2+6x)
=3x^2+−7x+−1(4x^2)+−1(6x)
=3x^2+−7x+−4x^2+−6x
Combine Like Terms:
=3x^2+−7x+−4x^2+−6x
=(3x^2+−4x^2)+(−7x+−6x)
=−x^2+−13x
Not sure if this is what you wanted. Sorry if this is what you weren't looking for.
PLEASE HELP!!!! what is the scale reading and significant figure in the reading?
Answer:
Step-by-step explanation:0.3
Problem 2: Vector v has initial point (4, 3) and terminal point (-7, 9). Write v as a linear combination of the standard unit vectors i and j.
We have
v = (-7, 9) - (4, 3) = (-7 - 4, 9 - 3) = (-11, 6)
which as a linear combination of the i and j unit vectors is
v = -11i + 6j
Answer:
Step-by-step explanation:
The formula S=n(a1+an)/2 gives the partial sum of an artithmetic sequence what is the formula solved for an?
Answer:
S = n(a1 + an)/2
2S = n(a1 + an)
2S = na1 + nan
nan = 2S - na1
an = (2S - n a1)/n
Step-by-step explanation:
hope it's right
92 divied by 20,884 long division
Answer:
brainliest is appreciated
Perform the indicated operations. Write the answer in standard form, a+bi.
-4+4i / -3-6i
Answer:
[tex] \frac{ - 4 + 4i}{ - 3 - 6i} \\ multiply \: and \: divide \: by \: - 3 + 6i \\ \frac{ - 4 + 4i}{ - 3 - 6i} \times \frac{ - 3 + 6i}{ - 3 + 6i} \\ = \frac{ ( - 4 + 4i)( - 3 + 6i)}{ ( - 3 - 6i)( - 3 + 6i)} \\ = \frac{12 - 24i - 12i + 24 {i}^{2} }{ {( - 3)}^{2} - {(6i)}^{2} } \\ = \frac{12 - 24 - 36i}{9 + 36} \\ = \frac{ - 12 - 36i}{45} \\ \frac{ - 36i}{45} + \frac{ - 12}{45} \\ thank \: you[/tex]
How many meters does a runner cross in a circular runway with radious of 100 meters [R=3, 14]
2x + 5y = -10
rewrite the equation in slope intercept form then identify the slope and the y intercept of the line
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
2x + 5y = - 10 ( subtract 2x from both sides )
5y = - 2x - 10 ( divide the terms by 5 )
y = - [tex]\frac{2}{5}[/tex] x - 2 ← in slope- intercept form
with slope m = - [tex]\frac{2}{5}[/tex] and y- intercept c = - 2
Graph the line that passes through the points (6,8) and (2,-2) and determine the equation of the line.
Find an equation for the line with the given properties. Express the equation in slope-intercept form. Containing the points P = (-4,4) and Q = (-3,2). What is the equation of the line?
y =
Answer:
[tex]y = - 2x - 4[/tex]
Step-by-step explanation:
Slope intercept eqn:
[tex]y - y1 = m(x - x1)[/tex]
P = (-4,4) and Q = (-3,2)
Let (x1, y1) = (-4,4) and (x2, y2) = (-3,2).
[tex]m = \frac{y2 - y1}{x2 - x1} = \frac{ 2 - 4}{ - 3 - ( - 4)} = \frac{ - 2}{1} = - 2[/tex]
Therefore the equation of the line in slope-intercept form :
[tex]y - 4 = - 2(x - ( - 4)) \\ y - 4 = - 2(x + 4) \\ y - 4 = - 2x - 8 \\ y = - 2x - 8 + 4 \\ y = - 2x - 4[/tex]
Given the function f(x) = -x + 4, then what is f(-3x) as a simplified
polynomial?
Answer:
3x+4
Step-by-step explanation:
f(x) = - x+4
Substitute in x=-3x
f(-3x)= - (-3x) + 4 = 3x+4
HELP ASAP HOMEWORK HELPPPP
Please help its due in 30 minutes will mark braniliest
Answer:
a point
Step-by-step explanation:
because it really seems like a point I dunno
The length of a sandbox is three feet longer than its width. What expression would represent the area of the sandbox
Expression represent the area of the sandbox is a² + 3a
GIven that;
Length of sandbox is three feet longer than its width
Find:
Expression represent the area of the sandbox
Computation:
Assume;
Width of sandbox = a feet
So,
Length of sandbox = (a + 3) feet
[tex]Area\ of\ rectangle = Length \times Width[/tex]
So,
Area of the sandbox = Length of sandbox × Width of sandbox
Area of the sandbox = (a + 3) × a
Area of the sandbox = a² + 3a
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Can someone Solve this math problem for me I'm having some trouble.
27×26+98÷25?
Answer:
705.92
Step-by-step explanation:
hope it's help
#MASTER GROUP
# FIRST MASTER
# PHILIPPINES
Estimate the value of 13−−√. Between which two whole numbers?
Answer:
Step-by-step explanation:
I guess you mean √13.
3^2 = 9 and 4^2 = 16 so the square roots is between 3 and 4.
3.5^2 = 3*4 + 0.25 = 12.25 so it looks like its about 3.6.
a2 +b2 for a=3 and b=4
Answer:
[tex] {a}^{2} + {b}^{2} \\ a = 3 \\ b = 4 \\ {3}^{2} + {4}^{2} \\ = 9 + 16 \\ = 25 \\ thnk \: you[/tex]
Answer:
Step-by-step explanation:
Can someone please help m with this
Answer:
Step-by-step explanation:
I take it that what you are asking is which one of the three choices gives f(5) = 2.
It is not the table. When you try adding 5 in the x column, you get a much larger result than 2 for y.
And it is not the scattered points of the graph. x = 5 gives 5 on the y axis, not 2.
It is the first choice on the left.
f(5) = x - 3
f(5) = 5 - 3
f(5) = 2
To divide 5472 by 81 using the shortened form of the division algorithm, what should be your first thought? Select from the drop-down menus to correctly complete the thought. "How many times does 81 divides into Choose... ?"
5
54
547
5472
Answer:
"How many times does 81 divide into 547?"
PLEASE HELP DHEGDFEEHDB HELPP PLEASE
Answer:
B
Step-by-step explanation:
22/7 X 14 squared
-------------------------------- =308
2
406-308= 98cm ^2
The angle,2Θ, lies in the third quadrant such that cos2Θ=-2/5. Determine an exact value for tanΘ . Show your work including any diagrams if you plan to use them. (3 marks)
Answer:
[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]
Step-by-step explanation:
1. Approach
One is given the following information:
[tex]cos(2\theta)=-\frac{2}{5}[/tex]
One can rewrite this as:
[tex]cos(2\theta)=-0.4[/tex]
Also note, the problem says that the angle ([tex]2\theta[/tex]) is found in the third quadrant.
Using the trigonometric identities ([tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]) and ([tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]) one can solve for the values of ([tex]cos(\theta)[/tex]) and ([tex]sin(\theta)[/tex]). After doing so one can use another trigonometric identity ([tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]). Substitute the given information into the ratio and simplify.
2. Solve for [tex](cos(\theta))[/tex]
Use the following identity to solve for ([tex]cos(\theta)[/tex]) when given the value ([tex]cos(2\theta)[/tex]).
[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]
Substitute the given information in and solve for ([tex]cos(\theta)[/tex]).
[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]
[tex]-0.4=2(cos^2(\theta))-1[/tex]
Inverse operations,
[tex]-0.4=2(cos^2(\theta))-1[/tex]
[tex]0.6=2(cos^2(\theta))[/tex]
[tex]0.3=cos^2(\theta)[/tex]
[tex]\sqrt{0.3}=cos(\theta)[/tex]
Since this angle is found in the third quadrant its value is actually:
[tex]cos(\theta)=-\sqrt{0.3}[/tex]
3. Solve for [tex](sin(\theta))[/tex]
Use the other identity to solve for the value of ([tex]sin(\theta)[/tex]) when given the value of ([tex]cos(2\theta)[/tex]).
[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]
Substitute the given information in and solve for ([tex]sin(\theta)[/tex]).
[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]
[tex]-0.4=1-2(sin^2(\theta))[/tex]
Inverse operations,
[tex]-0.4=1-2(sin^2(\theta))[/tex]
[tex]-1.4=-2(sin^2(\theta))[/tex]
[tex]0.7=sin^2(\theta)[/tex]
[tex]\sqrt{0.7}=sin(\theta)[/tex]
Since this angle is found in the third quadrant, its value is actually:
[tex]sin(\theta)=-\sqrt{0.7}[/tex]
4. Solve for [tex](tan(\theta))[/tex]
One can use the following identity to solve for [tex](tan(\theta))[/tex];
[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]
Substitute the values on just solved for and simplify,
[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]
[tex]tan(\theta)=\frac{-\sqrt{0.7}}{-\sqrt{0.3}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{0.7}}{\sqrt{0.3}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]
Rationalize the denominator,
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}*\frac{\sqrt{\frac{3}{`0}}}{\sqrt{\frac{3}{10}}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}*\frac{3}{10}}}{\sqrt{\frac{3}{10}*\frac{3}{10}}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{21}{100}}}{\frac{3}{10}}[/tex]
[tex]tan(\theta)=\frac{\frac{\sqrt{21}}{10}}{\frac{3}{10}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{21}}{10}*\frac{10}{3}[/tex]
[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]
18/73 and 4/16. Proportional or Not Proportional
Answer:
not proportional
Step-by-step explanation:
We can check using cross products
18/73 = 4/16
18*16 = 73*4
288=292
Since this is not equal, this is not proportional
If you graph a function and it looks like a circle, it will pass the vertical line test.
True or False
Answer: false
Step-by-step explanation:
Since it is a circle, when you draw the line it will meet at two points which fails the vertical line test. In order to pass the vertical line test it must only meet at one point.
you buy 4 video tapes for 14.99 each and 3 dvds for 19.99 each find the total cost of the movies
Answer:
119.93
Step-by-step explanation:
I will assume the total of the cost of the movies will be the total.
the total = 4*14.99 + 3*19.99
total = 119.93
Eileen is baking a cake in a square prism shape. The volume of the cake is 224 cubic inches, and the cake has a
height of 3.5 inches. What are the side lengths of the cake?
Answer: 8 inches
Step-by-step explanation:
224/3.5 = 64
8*8=64
8in * 8in * 3.5In = 224 cubic inches
Evaluath the expression if a =
2, b = - 3, c = – 4, h = 6, y = 4, and z = -1.
|2b-3y| + 5z
Answer:
13
Step-by-step explanation:
expression =|2b-3y| +5z
Subtitute all values in expression:
=|2(-3)-3(4)| +5(-1)
=|-6-12| -5
=|-18|-5
=18-5
=13
Note:if you need to ask any question please let me know.
If(2x,x+y)=(y,9)find x and y.
Answer:
the value of X is 3 and y is 6 .
Evaluate each expression if a= 12, b =9, c= -4 (a2/4b)+c
Identify the function family and describe the domain and range for g(x) = |x + 2|– 1.
The range of the function g(x) = |x + 2|– 1 is (-1,∞) and domain of the function is (-∞,∞).
What is the range and domain of a function?A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.
The domain is for the independent variable while the range is for the dependent variable.
For example f(x) = x²
Now if we put x = 1 then it is called as domain variable while the value of function at x = 1 its that f(1) = 1 called range variable.
Given the function g(x) = |x + 2|– 1
The minimum value of the function
At x = -2 ⇒ |-2+ 2|– 1 = -1
The maximum value of the function
At x = ∞ ⇒ |∞+ 2|– 1 = ∞
So,
The range will be (-1, ∞)
Now,
We can put x as -∞ and ∞ so the domain will be (-∞,∞).
Hence "The range of the function g(x) = |x + 2|– 1 is (-1,∞) and domain of the function is (-∞,∞)".
For more details about the range and domain of the function,
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