- Three times the quantity two decreased by x is nine.

Answer:

1. 0

2.0

3.2

4.1

Step-by-step explanation:

1.3x+18

2.-2x+2

3.x-x+4-2

5-2x-2+5-2x

Answer:

Answer:

Range is (0, -5)

Step-by-step explanation:

[tex]{ \sf{f(x) = - {x}^{2} - 5}}[/tex]

when x is 0:

[tex]{ \sf{f(0) = - 5}}[/tex]

Hi there!

The numbers you have written there are correct.

[tex]-5<x<0[/tex] is true for any value of x that is greater than -5 or less than 0.

When a number is less than 0, we know that it has to be negative.

However, it cannot be more negative than -5. It cannot be -5 either.

So, x could be -1, -2, -3, -4, -1/2, -2.3, -4.9, the list goes on.

I hope this helps!

Answer:

Step-by-step explanation:

[tex]\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\[/tex]

[tex]\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\[/tex]

Answer:

(0, 0)

Step-by-step explanation:

Each reference line is called a coordinate axis or just axis (plural axes) of the system, and the point where they meet is its origin, at ordered pair (0, 0).

Answer:

VW = 6

Step-by-step explanation:

To find x, set up the following equation:

(5x - 4) + (2x) = 5x

Solve out left side

7x - 4 = 5x

Subtract 5x from both sides

2x - 4 = 0

Add 4 to both sides

2x = 4

Divide both sides by 2

x = 2

Plug into 5x - 4

5(2) - 4

10 - 4

6

Answer:

6

Step-by-step explanation:

5x - 4 + 2x = 5x

7x - 4 = 5x

-4 = -2x

2 = x

5(2) - 4

10 - 4

6

Answer:

$56×2=$112 and $45×4=$180 so $112+$180= $291

9514 1404 393

Answer:

  $58

Step-by-step explanation:

James currently has $67 less than $125:

  $125 -67 = $58

James currently has $58.

Step-by-step explanation:

x intercept is 1

y intercept is 2

Hope it helps

Answer:

147/20,7+2/5,7.407,7.41.

Step-by-step explanation:

147/20=7.35.

7+2/5=7.4.

7.407>7.4.

7.41>7.407.

Side note:

I changed everything into decimal form.

Answer:

40

Step-by-step explanation:

i need point so i am writing this sentence you have to do 4 times 10 (4×10) it is 40

Answer:

No

Step-by-step explanation:

To write 97/1000 as a decimal you have to divide numerator by the denominator of the fraction.

We divide now 97 by 1000 what we write down as 97/1000 and we get 0.097

And finally we have:

97/1000 as a decimal equals 0.097

Answer:

3,6

Step-by-step explanation:

Answer:

Step-by-step explanation:

y = 3x - 2

Slope of line is 3.

Slope of any perpendicular to the line is -⅓.

9514 1404 393

Answer:

  h = 3V/(πr²)

Step-by-step explanation:

The formula can be solved for h by multiplying both sides by the inverse of the coefficient of h.

  [tex]V=\dfrac{1}{3}\pi r^2h=\dfrac{\pi r^2}{3}h\\\\(\dfrac{3}{\pi r^2})V=(\dfrac{3}{\pi r^2})(\dfrac{\pi r^2}{3})h\\\\\boxed{\dfrac{3V}{\pi r^2}=h}[/tex]

_____

Additional comment

Whenever a variable has a coefficient you don't want, you can make that be 1 by multiplying the equation by the inverse of the coefficient. This is the same as dividing by the coefficient. This makes use of the fact that for any non-zero 'a', the ratio a/a has a value of 1. Anything multiplied by 1 is unchanged.

  V = ah   ⇒   V/a = (ah)/a = h(a/a) = h·1 = h

Note that we multiply the whole equation (both sides of the equal sign) by 1/a. The basic rule of equality is that you can do whatever you like to an equation, as long as you do it to both sides.

Answer:

Yes the function is continuous f(5) = 13

Step-by-step explanation:

Replace the variable x with 5 in the expression

Simlify the results

f(5) = 3(5)-3

f(5) = 15=3

f(5) = 13

Plotting on a graph gives a coninous line with a positive gradient

y intercept (0,-2)

Please view the attached graph

Answer:

1/4

Step-by-step explanation:

24/6

4

4+4+4+4+4+4

Answer:

true, I hope this will help.

[tex]\boxed{\underline{\bf \: True}}[/tex]

[tex] \sf \: 6(10 + 5) = 6•10 + 6•5 [/tex]

Check with LHS = RHS rule method.

LHS

[tex]\sf6(10 + 5) \\ \sf = 6(15) \\ \sf = 6 \times 15 \\ \bf = 90[/tex]

RHS

[tex]\sf6•10 + 6•5 \\ \sf = 60 + 30 \\ \bf= 90[/tex]

We can see that both LHS & RHS give [tex]\boxed{\underline{\bf \: 90}}[/tex]as the solution. LHS = RHS. Hence proved.

Answer -> [tex]\boxed{\underline{\bf \: True}}[/tex]

_______________

Hope it helps.

RainbowSalt2222

Answer:

1 as

3/5 × 2/2 = 6/10

Step-by-step explanation:

Hope it helps

Answer:

(x - 6)(x + 2)

Step-by-step explanation:

x^2 - 4x - 12

=x^2 - 6x + 2x - 12

=x( x - 6) + 2(x - 6)

=(x - 6)(x + 2)

Answer:

x^2 -4x-12

factorization of 12 =2×2×3 = 6×4

or in the place of 4x = we put (6-2)x

x^2-(6-2)x-12

x^2-6x+2x-12

x(x-6)+2(x-6)

(x-6) (x+2)

Answer:

Hello I'm sorry but I have a question and I have to give ans and I can ask my question

Answer:

its either 2 or 4

Step-by-step explanation:

Answer:

In order for the function to be discontinuous at an asymptote, the curve needs to exist on both sides of the asymptote. If the curve only exists on one side of the asymptote, then there's no discontinuity at that point.

Step-by-step explanation:

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Answer:

  (b)  6^10/7^6

Step-by-step explanation:

The applicable rules of exponents are ...

  (a/b)^c = (a^c)/(b^c)

  (a^b)^c = a^(bc)

__

This means you have ...

  [tex]\left(\dfrac{6^5}{7^3}\right)^2=\dfrac{(6^5)^2}{(7^3)^2}=\dfrac{6^{5\cdot2}}{7^{3\cdot2}}=\boxed{\dfrac{6^{10}}{7^6}}[/tex]

__

Additional comment

I find it helpful to remember that an exponent signifies repeated multiplication. Then ...

  [tex]\left(\dfrac{6^5}{7^3}\right)^2=\left(\dfrac{6^5}{7^3}\right)\cdot\left(\dfrac{6^5}{7^3}\right)=\dfrac{6^5\cdot6^5}{7^3\cdot7^3}=\dfrac{6^{5+5}}{7^{3+3}}=\dfrac{6^{10}}{7^6}[/tex]  

Answer:

12000

Step-by-step explanation:

Check the hundreds digit if greater Han 5 increase the thousands digit by 1 and change the other digits to 0

Answer:

that is what I got as my answer

Step-by-step explanation:

As it holds Associative property..

So, it's correct

Answer:

TRUE

Step-by-step explanation:

Associative property of multiplication

Answer:

41

Step-by-step explanation:

This composite function can be easily solved

First solve f(-2)

f(-2)=(-2)³+3

f(-2)=-8+3=-5

Now plug -5 for x in function g(x)

=2(-5)²+2(-5)+1

=50-10+1

=41

9514 1404 393

Answer:

  41

Step-by-step explanation:

g(f(-2)) = g((-2)³ +3) = g(-8+3) = g(-5)

= 2(-5)² +2(-5) +1 = 50 -10 +1

g(f(-2)) = 41

Answer:

[tex]\frac{1}{30}[/tex]

Step-by-step explanation:

Take it in steps. First, find 7/9+6. Then we'll find 8+6/3, and, finally, we'll divide the two answers.

1:

7/9+6 = 7/15

2:

8+6/3 = 14/3

3:

[tex]\frac{\frac{7}{15}}{\frac{14}{3}}[/tex] or [tex]\frac{7/15}{14/3}[/tex]

Then take that in chunks: 7/14 and 15/3.

7/14 = 1/2

15/3 = 5/1

Use those to rewrite it as [tex]\frac{1/5}{2/3}[/tex].

1/5 = .2

2/3 ≈ .6667 so we'll keep writing it as 2/3

[tex]\frac{\frac{.2}{2}}{3}[/tex]

.2/2 = .1, so:

[tex]\frac{.1}{3}[/tex] = [tex]\frac{1}{30}[/tex]