Suppose we adapt a different. "greedy" strateov to solve the rod-cutting problem as follows: for each length i and price p; in the price table, we divide p;/ to find the price per length. We then repeatedly pick the length with the highest possible price per length, according to how much length still remains, and cut a piece of this "best" length. Will this strategy still vield the best results? If so, explain why. If not give a counter example.

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Answer 1

No, this strategy will not yield the best results for the rod-cutting problem.       A counterexample can be constructed where the greedy strategy fails to find the optimal solution, such as when there are pricing anomalies or non-linear price relationships across different lengths.

this strategy will not always yield the best results for the rod-cutting problem. The greedy strategy mentioned selects the length with the highest price per unit length  each step. However, this approach does not consider the overall optimal solution and may lead to suboptimal results.

A counterexample can be demonstrated with the following scenario: Suppose we have a rod of length 8 and the price table as follows: length 1 has a price of 5, length 2 has a price of 10, length 3 has a price of 25, and length 4 has  prUsing the greedy strategy, the algorithm will first select length 4 as it has the highest price per unit length. It will then be left with a rod of length 4. The next selection will be length 2, followed by length 1, resulting in a total price of 65.However, the optimal solution in this case would be to cut the rod into two pieces of length 4, yielding a total price of 60.Thus, the greedy strategy fails to provide the best results for the for the rod-cutting problem in all cases.

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Related Questions

Need help with this python question I’m stuck

Answers

It should be noted that the program based on the information is given below

How to depict the program

def classify_interstate_highway(highway_number):

 """Classifies an interstate highway as primary or auxiliary, and if auxiliary, indicates what primary highway it serves. Also indicates if the (primary) highway runs north/south or east/west.

 Args:

   highway_number: The number of the interstate highway.

 Returns:

   A tuple of three elements:

   * The type of the highway ('primary' or 'auxiliary').

   * If the highway is auxiliary, the number of the primary highway it serves.

   * The direction of travel of the primary highway ('north/south' or 'east/west').

 Raises:

   ValueError: If the highway number is not a valid interstate highway number.

 """

 if not isinstance(highway_number, int):

   raise ValueError('highway_number must be an integer')

 if highway_number < 1 or highway_number > 999:

   raise ValueError('highway_number must be between 1 and 999')

 if highway_number < 100:

   type_ = 'primary'

   direction = 'north/south' if highway_number % 2 == 1 else 'east/west'

 else:

   type_ = 'auxiliary'

   primary_number = highway_number % 100

   direction = 'north/south' if primary_number % 2 == 1 else 'east/west'

 return type_, primary_number, direction

def main():

 highway_number = input('Enter an interstate highway number: ')

 type_, primary_number, direction = classify_interstate_highway(highway_number)

 print('I-{} is {}'.format(highway_number, type_))

 if type_ == 'auxiliary':

   print('It serves I-{}'.format(primary_number))

 print('It runs {}'.format(direction))

if __name__ == '__main__':

 main()

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Question 6 (1 point)
Janelle is creating a model of a bathroom in Blender. She is currently working on the
tile pattern for the walls of the shower. She has decided on a hexagonal shape
surrounded by four squares. Since this pattern will be repeated over the entire
shower wall, which of the following modifiers should she use to create enough
copies of it to populate the entire area?
Boolean
Bevel
Array
Screw

Answers

To create enough copies of the tile pattern to populate the entire area of the shower wall in Blender, Janelle should use the C) Array modifier.

The Array modifier in Blender allows for the creation of multiple copies or instances of an object, arranged in a specified pattern.

It is particularly useful when creating repetitive patterns, as in the case of the tile pattern for the shower walls.

By applying the Array modifier to the initial tile pattern, Janelle can define the number of copies to be made and the desired spacing or offset between them.

She can configure the modifier to create a grid-like arrangement of the tiles, allowing her to cover the entire area of the shower wall seamlessly.

The Array modifier offers flexibility in terms of adjusting the pattern's size, rotation, and other parameters to achieve the desired look.

Additionally, any changes made to the original tile will be automatically propagated to all the instances created by the modifier, streamlining the editing process.

While the other modifiers mentioned—Boolean, Bevel, and Screw—have their own specific uses, they are not suitable for creating multiple copies of a tile pattern.

The Boolean modifier is used for combining or cutting shapes, Bevel for adding rounded edges, and Screw for creating spiral or helix shapes.

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The way text appear is called its

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Answer:

the way the text appear is called it's formatting

Accumulating Totals in Single- Level Control Break Programs Summary In this lab , you will use what you have learned about accumulating totals in a single - level control break program to complete a C++ program . The program should produce a report for a supermarket manager to help her keep track of the hours worked by her part- time employees . The report should include the day of the week and the total hours worked by all employees each day . The student file provided for this lab includes the necessary variable declarations and input and output statements . You need to implement the code that recognizes when a control break should occur . You also need to complete the control break code . Be sure to accumulate the daily totals for all days in the week . Comments in the code tell you where to write your code .

Instructions 1. Study the prewritten code to understand what has already been done . 2. Write the control break code , including the code for the dayChange () function , in the main (function . 3. Execute the program by clicking the Run button at the bottom of the screen . Use the following input values : Monday - 6 hours ( employee 1) Tuesday - 2 hours (employee 1 ), 3 hours ( employee 2) Wednesday - 5 hours (employee 1 ), 3 hours (employee 2 ) Thursday -6 hours (employee 1 ) Friday - 3 hours ( employee 1), 5 hours ( employee 2) Saturday - 7 hours (employee 1 ), 7 hours (employee 2) , 7 hours ( employee 3) Sunday hours

1 // SuperMarket. cpp - This program creates a report that lists weekly hours worked
2 // by employees of a supermarket. The report lists total hours for
3 // each day of one week
4 // Input:
Interactive
5 // Output: Report.
6
7 #include
8 #include
8 #include
8 #include dayOfWeek;
if (day0fWeek
== SENTINEL)
notDone = false;
else
{
cout <‹ "Enter hours worked: cin >> hoursWorked;
prevDay = dayOfWeek;
}
while(notDone == true)
// Implement control break logic here
// Include work done in the dayChange () function
cout <‹ "\t\t" << DAY_FOOTER <‹ hoursTotal <‹ endl;
return 0;

Answers

Based on the provided code snippet, it seems that the instructions and implementation details of a C++ program are missing. It appears to be an incomplete code snippet with placeholders for implementing control break logic and the dayChange() function.

To complete the program, you would need to carefully study the prewritten code, understand the requirements and control break conditions, and then write the missing parts as instructed. This includes implementing the control break logic and completing the dayChange() function.

true or false? excel can be used to analyze information in a variety of different ways

Answers

Answer: True!

Explanation: Excel can be used to analyze information in a variety of different ways.

Other Questions
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