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Customer questions is said to be just impactful in terms of high shipping demand.
What are Customer questions?The term Customer questions is known to be the feedback questions that customers of a brand often ask so that it the firm can improve a given product or any services.
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Define award package. What does it include?
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Answer:
Your award letter will list the types and amounts of aid being offered. Aid may be a grant, a scholarship, a loan, work-study—or a combination of these aid types. The award letter should also include: A breakdown of the college's cost of attendance (COA)
Answer:
Your award letter will list the types and amounts of aid being offered. Aid may be a grant, a scholarship, a loan, work-study—or a combination of these aid types. The award letter should also include: A breakdown of the college's cost of attendance (COA)
Explanation:
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If f(x) and it’s inverse function,f-1(x), are both potted on the same coordinate plane, where point of intersection?
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In a recent year, about 22% of Americans 18 years and older are single. What is the probability that in a random sample of 200 Americans 18 or older more than 30 are single? (Hint: use binomial to normal approximation techniques) Round your z-score to 2 decimal places before referencing table E. Then provide answer out to 4 decimal places.
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Using the normal approximation to the binomial, it is found that there is a 0.0107 = 1.07% probability that more than 30 are single.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with [tex]\mu = np, \sigma = \sqrt{np(1-p)}[/tex].In this problem, the proportion and the sample size are, respectively, p = 0.22 and n = 200, hence:
[tex]\mu = np = 200(0.22) = 44[/tex]
[tex]\sigma = \sqrt{np(1 - p)} = \sqrt{200(0.22)(0.78)} = 5.8583[/tex]
The probability that more than 30 are single, using continuity correction, is P(X > 30.5), which is 1 subtracted by the p-value of Z when X = 30.5, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{30.5 - 44}{5.8583}[/tex]
Z = -2.3
Z = -2.3 has a p-value of 0.0107.
0.0107 = 1.07% probability that more than 30 are single.
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