ATTENDING TO PRECISION The diagram shows an insect called a walking stick Use the ruler to estimate the length of the abdomen and the length of the thorax to the nearest inch. How much longer is the walking stick's abdomen than its thorax? How many times longer is its abdomen than its thorax?
Answers
Estimation and precision are used when the actual value cannot be easily determined or calculated.
The length of the abdomen is [tex]2\frac 14[/tex] inchesThe length of the thorax is [tex]1\frac 34[/tex] inchesThe abdomen is longer than the thorax [tex]1\frac 27[/tex] timesGiven that, the length is to be measured to the nearest [tex]\frac 14\ inch[/tex], we have the following observations
The length of the abdomen starts at the 0 mark and ends after the 2-mark. The length ends before [tex]2\frac{1}{2}[/tex]. So, the length of the abdomen can be estimated to [tex]2\frac{1}{4}[/tex] --- to the nearest [tex]\frac{1}{4}[/tex].Similarly, the length of the thorax starts at the [tex]2\frac{1}{4}[/tex] mark and ends before [tex]4\frac{1}{4}[/tex]. The end of the thorax length can be estimated to: [tex]4[/tex] --- to the nearest [tex]\frac{1}{4}[/tex].So, we have:
[tex]L_1 = 2\frac 14[/tex] --- the length of the abdomen
[tex]L_2 = 4 - 2\frac 14[/tex]
Express as improper fraction
[tex]L_2 = 4 - \frac{9}{4}[/tex]
Take LCM
[tex]L_2 = \frac{16 - 9}{4}[/tex]
[tex]L_2 = \frac{7}{4}[/tex]
Express as proper fraction
[tex]L_2 = 1\frac{3}{4}[/tex] --- the length of the thorax
The number of times (n) the abdomen is longer than the thorax is calculated as follows:
[tex]n = L_1 \div L_2[/tex]
So, we have:
[tex]n = 2\frac 14 \div 1\frac 34[/tex]
Express as improper fractions
[tex]n = \frac 94 \div \frac 74[/tex]
Rewrite as:
[tex]n = \frac 94 \times \frac 47[/tex]
[tex]n = \frac 97[/tex]
Express as proper fractions
[tex]n = 1\frac 27[/tex]
Hence, the abdomen is [tex]1\frac 27[/tex] times longer than the thorax
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