The temperature that a stationary probe inserted into the duct will read for each case is as follows:(a) 320.0005 K(b) 320.0498 K(c) 324.9502 K(d) 815.02 K
The formula to calculate the temperature that a stationary probe inserted into the duct will read for each case is:
T = T0 + (v² / 2Cp)
where,
T0 is the temperature of the air in Kelvin,
v is the velocity of the air in m/s,
Cp is the specific heat capacity of air at a constant pressure of 101.325 kPa.
For each case given, the temperature that the stationary probe will read is as follows:
(a) v = 1 m/sT = 320 K + (1² / 2 * 1005 J/kg.K)T = 320 K + 0.0005 K = 320.0005 K
(b) v = 10 m/sT = 320 K + (10² / 2 * 1005 J/kg.K)T = 320 K + 0.0498 K = 320.0498 K
(c) v = 100 m/sT = 320 K + (100² / 2 * 1005 J/kg.K)T = 320 K + 4.9502 K = 324.9502 K
(d) v = 1000 m/sT = 320 K + (1000² / 2 * 1005 J/kg.K)T = 320 K + 495.02 K = 815.02 K
Thus, the temperature that a stationary probe inserted into the duct will read for each case is as follows:(a) 320.0005 K(b) 320.0498 K(c) 324.9502 K(d) 815.02 K
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Two concrete spans of a 370 m long bridge are
placed end to end so that no room is allowed
for expansion. 370 mT T + 20◦Cy
If the temperature increases by 20◦C, what
is the height to which the spans rise when
they buckle? Assume the thermal coefficient
of expansion is 1.2 × 10−5(◦C)−1
Answer in units of m.
The height to which the spans rise when they buckle is 0.0222 m.
A high thermal coefficient: what does that imply?A material will expand more as a result of being heated if its coefficient of thermal expansion is larger.
What does the thermal expansion law mean?The phenomena known as thermal expansion can be seen in solids, liquids, and gases. In this procedure, the application of heat causes an object or body to expand (temperature). The term "thermal expansion" refers to an object's propensity to change its dimensions as a result of heat, including length, density, area, and volume.
The following formula can be used to determine the height to which the spans rise when they buckle:
ΔL = LαΔT
where ΔL = change in length,
L = original length,
α = coefficient of thermal expansion,
ΔT = change in temperature
the length of the bridge = 370 m,
the coefficient of thermal expansion = 1.2 × 10^-5 (°C)^-1,
the change in temperature = 20°C.
The change in length of each span is,
ΔL = LαΔT = (370/2)(1.2 × 10^-5)(20)
= 0.0444 m
Since there are two spans, the total change in length is 0.0888 m.
h = ΔL/2 = 0.0444/2
= 0.0222 m
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Magnetic materials can be characterized by single parameter magnetization. Discuss differences between paramagnetic, ferromagnetic and antiferromagnetic states using the concept of magnetization.
i) Which state has the largest (smallest) magnetization and why? ii) Which magnetic state (ferromagnetic or paramagnetic) is realized at high (low) temperatures and why? Hint: Consider competition between temperature (thermal fluctuations) and symmetric magnetic state
Magnetization is the measure of the strength and direction of a material's magnetism. The magnetization of a magnetic material depends on the magnetic state of the material, which can be classified into three main categories: paramagnetic, ferromagnetic, and antiferromagnetic.
Paramagnetic Materials:
Paramagnetic materials have a weak magnetic moment that is aligned with an external magnetic field, and the magnetization of such materials is proportional to the applied magnetic field.
In the absence of an external magnetic field, the magnetization is zero. The magnetization is usually small, and the magnetic moment arises from the presence of unpaired electrons in the material.
Ferromagnetic Materials:
Ferromagnetic materials have a strong magnetic moment that is aligned spontaneously, even in the absence of an external magnetic field. The magnetization arises from the alignment of many atomic magnetic moments, which are typically arranged in domains.
In the presence of an external magnetic field, the domains align and contribute to the overall magnetization. The magnetization of ferromagnetic materials is typically large.
Antiferromagnetic Materials:
Antiferromagnetic materials have a magnetic moment that is aligned in an antiparallel direction. The magnetization of such materials is usually zero because the magnetic moments of adjacent atoms cancel out each other.
In an external magnetic field, the magnetic moments may align in the same direction, leading to a nonzero magnetization.
i) Which state has the largest (smallest) magnetization and why?
Ferromagnetic materials have the largest magnetization because they have a spontaneous magnetization that arises from the alignment of many atomic magnetic moments.
Antiferromagnetic materials have the smallest magnetization because the magnetic moments of adjacent atoms cancel each other.
ii) Which magnetic state (ferromagnetic or paramagnetic) is realized at high (low) temperatures and why?
At high temperatures, thermal fluctuations tend to disrupt the alignment of magnetic moments, leading to a decrease in magnetization. Therefore, paramagnetic materials are typically realized at high temperatures.
At low temperatures, the magnetic moments of ferromagnetic materials tend to align spontaneously, leading to a large magnetization. Therefore, ferromagnetic materials are typically realized at low temperatures.
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a homogeneous portion of a mixture that is characterized by uniform properties and capable of being separated by mechanical means is called a .
The homogeneous portion of a mixture that is characterized by uniform properties and capable of being separated by mechanical means is called a phase.
A phase's physical and chemical characteristics can be used to determine whether it is a solid, liquid, or gas. Phase separation can be accomplished mechanically via centrifugation, filtration, or sedimentation.
In several disciplines, including chemistry, biology, and engineering, the ability to separate phases is crucial because it enables the separation and purification of desired components from mixtures. The word "homogeneous" describes a phase in which the components are spread uniformly.
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The complete question is
A homogeneous portion of a mixture that is characterized by uniform properties and capable of being separated by mechanical means is called a _____.
product
phase
reactant
solvent
Why does 250 N not push an object when frictional force is 188 N while 251 N is pushing with fast acceleration.
Due to the difference in net force delivered to the item in each situation, 250 N cannot push an object while the frictional force is 188 N, whereas 251 N may push the identical thing with rapid acceleration.
When there is friction, what happens to acceleration?When friction is present, an object may continue to travel at a steady speed despite the application of an external force. The friction force simply balances the applied force in this scenario. There is no acceleration since there is no net force.
Does friction increase as you go faster?No, acceleration has no impact on the kinetic friction coefficient. The type of surfaces that make contact with one other and not the speed at which they are travelling determine the coefficient of kinetic friction, which is constant.
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similarities eukaryotic and prokaryotic cells
Answer:v
Both prokaryotic and eukaryotic cells have similar features, like ribosomes, genetic material, a cytoplasm, and plasma membranes. There are two primary types of eukaryotic cells: animal and plant cells.
Explanation:
at 9:19 a.m., you pass a police car at 60 mph that is stopped on the freeway. you pass a second police car at 60 mph at 9:55 a.m., which is located 42 mi from the first police car. if the speed limit is 65 mph, can the police cite you for speeding?
No, the police cannot cite you for speeding since you were traveling at the speed limit of 60 mph.
Expecting you kept a steady speed of 60 mph, you went for 36 minutes (9:19 a.m. to 9:55 a.m.) prior to passing the second squad car. During this time, you voyaged a distance of 36 miles (60 miles/hour x 0.6 hours). According to the viewpoint of the primary squad car, you were going at a speed of 60 mph, which is beneath the speed furthest reaches of 65 mph. Thusly, the primary squad car can't refer to you for speeding.
At the point when you passed the second squad car, you had voyaged an all out distance of 42 miles (the distance between the two squad cars). You had been driving for 36 minutes (0.6 hours) and your speed was steady at 60 mph. In this way, your typical speed was 70 mph (42 miles ÷ 0.6 hours). This is over the speed furthest reaches of 65 mph, so the second squad car could refer to you for speeding.
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a roller coaster needs to complete a vertical loop that has radius 10 m what must its minimum speed be at top of loop ?
Answer:
9.90 m/s.Explanation:
In order for the roller coaster to complete a vertical loop of radius 10 m, it must have enough speed at the top of the loop to overcome the force of gravity and maintain contact with the track. At the top of the loop, the roller coaster is momentarily at rest (i.e., its speed is zero), and the only force acting on it is gravity. Therefore, we can use the following equation to find the minimum speed required:
Centripetal force = Weight of the roller coasterwhere m is the mass of the roller coaster, v is its speed at the top of the loop, r is the radius of the loop, and g is the acceleration due to gravity.
Solving for v, we get:
v = √(gr)Substituting in the given values, we get:
v = √(9.81 m/s^2 * 10 m)v = 9.90 m/sTherefore, the minimum speed that the roller coaster must have at the top of the loop is 9.90 m/s.The roller coaster's minimum speed at the top of the loop should be approximately 9.90 m/s that has radius 10 m.
To complete a vertical loop without falling off at the top, the roller coaster must have sufficient speed to counteract gravity.
At the top of the loop, the minimum speed required can be found using the concept of centripetal force.
At the top of the loop, the centripetal force (provided by the roller coaster's speed) must equal the force due to gravity. This can be expressed as:
[tex]mv^2[/tex]/ r = mg
Where m is the mass of the roller coaster, v is its speed, r is the radius of the loop, and g is the acceleration due to gravity
(approximately 9.81 [tex]m/s^{2}[/tex]).
Solving for v:
[tex]v^2 = rg[/tex]
v = [tex]\sqrt{(10 m * 9.81 m/s^{2} )[/tex] ≈ [tex]\sqrt{(98.1 m^{2} /s^{2} )[/tex] ≈ 9.90 m/s
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a block of mass m is attached to an ideal spring with a spring constant of k , as shown in the figure. the block is set into oscillatory motion by being pulled back a distance a and released from rest. the block is sliding on a surface of negligible friction. what is the displacement of the block from equilibrium when the elastic potential energy of the spring-block system is equal to the kinetic energy of the block?
The displacement of the block from equilibrium when the elastic potential energy is equal to the kinetic energy is
x =a/sqrt(2).
When the elastic potential energy of the spring-block system is equal to the kinetic energy of the block, the displacement from equilibrium can be found using the conservation of energy principle. At this point, the total mechanical energy remains constant.
Let's denote the displacement from equilibrium as x. The elastic potential energy (PE) of the spring is given by (1/2)kx^2, and the kinetic energy (KE) of the block is given by (1/2)mv^2. Since PE = KE, we have:
(1/2)kx^2 = (1/2)mv^2
We also know that the maximum potential energy occurs when the block is pulled back a distance 'a', which is given by:
PE_max = (1/2)ka^2
Now, using the conservation of energy, we can write the total mechanical energy (E) as:
E = PE + KE = (1/2)kx^2 + (1/2)mv^2 = (1/2)ka^2
Substituting the expression for KE from the PE = KE equation, we get:
(1/2)kx^2 + (1/2)kx^2 = (1/2)ka^2
kx^2 = (1/2)ka^2
Now, solving for the displacement 'x', we find:
x^2 = (1/2)a^2
x = a / sqrt(2)
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An airplane flies at 120km/h relative to air. There is a wind blowing at 90km/h relative to the ground. Calculate the speed of the airplane relative to the ground if.
a) they have opposite direction
b) perpendicular.
Explanation:
a) if theya re OPPOSITE then the wind speed subtracts from the airplane's speed ( a headwind) sooooo 120 - 90 = 30 km/hr
b) if the two speeds are perpendicular , you can use Pythagorean theorem:
R^2 = 120^2 + 90^2
R = 150 km/hr
a singly charged positive ion has a mass of 3 x 10-26 kg. after being accelerated through a potential difference of 296 v, the ion enters a magnetic field of 0.79 t, in direction perpendicular to the field. calculate the radius of the path of the ion in the field.
A single positively charged ion accelerates through a potential difference of 296 volts and has a mass of 3 x 10-26 kg. The radius of the path of the ion in the magnetic field is 1.27 x 10^-3 meters.
To find the radius of the path of the ion in the magnetic field, we can use the formula:
r = mv / (qB)
where r is the radius of the path, m is the mass of the ion, v is its velocity, q is its charge, and B is the magnetic field strength.
We are given that the ion has a mass of 3 x 10^-26 kg and a charge of +1. The potential difference it is accelerated through is 296 V, which means that it gains kinetic energy equal to qV = (1)(296) = 296 J. We can use the conservation of energy to find the velocity of the ion:
1/2 mv^2 = qV
v = (2qV/m)
= (2(1)(296)/(3 x 10^-26))
= 3.27 x 10^6 m/s
Substituting the given values into the formula for the radius, we get:
r = mv / (qB)
= (3 x 10^-26)(3.27 x 10^6) / (1)(0.79)
= 1.27 x 10^-3 m
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What is the increase of current when 15 V is applied to 10000 ohm rheostat, which is adjusted to 1000-ohm value?
Answer:
13.5 mA or 0.0135 A
Explanation:
1.
I=V/R
I=V/RI = 15 V/ 1,000 Ω
I=V/RI = 15 V/ 1,000 Ω
I = 0.015 A or 15 mA (milliamperes)
2.
I=V/R
I = 15 V/ 10,000 Ω
I = 0.0015 A or 1.5 mA (milliamperes)
3.
Therefore, the increase in current when the rheostat is adjusted to 1,000 Ω is:
Al 15 mA - 1.5 mA =
Al = 13.5 mA
So the increase in current is 13.5 mA or 0.0135 A
chatgpt
when will a new moon appear
Answer:on april 20th at aproximately 12: 12 a.m
work-energy theorem: a 4.00-kg mass is attached to a very light ideal spring hanging vertically and hangs at rest in the equilibrium position. the spring constant of the spring is 1.00 n/cm. the mass is pulled downward 2.00 cm and released. what is the speed of the mass when it is 1.00 cm above the point from which it was released?
The speed of the 4.00-kg mass when it is 1.00 cm above the point from which it was released is 0.866 m/s.
Using the work-energy theorem, the speed of the 4.00-kg mass when it is 1.00 cm above the point from which it was released can be calculated as follows: First, find the potential energy stored in the spring when the mass is pulled down 2.00 cm.
The potential energy (PE) can be calculated using the formula: PE = 0.5 * k * [tex]x^{2}[/tex], where k is the spring constant (1.00 N/cm) and x is the displacement (2.00 cm).
PE = 0.5 * 1.00 * (2.00[tex])^{2}[/tex] = 2.00 J (joules)
Now, find the potential energy when the mass is 1.00 cm above the release point. The new displacement is 1.00 cm (since it moved 1.00 cm upwards).
PE_new = 0.5 * 1.00 * (1.00[tex])^{2}[/tex] = 0.50 J
The difference in potential energy is the kinetic energy (KE) gained by the mass.
KE = PE - PE_new = 2.00 - 0.50 = 1.50 J
The kinetic energy can be calculated using the formula: KE = 0.5 * m * [tex]V^{2}[/tex], where m is the mass (4.00 kg) and v is the speed. We can rearrange the formula to solve for the speed: v = sqrt(2 * KE / m)
v = ([tex]\sqrt{2 * 1.50 / 4.00}[/tex]) = [tex]\sqrt{0.75}[/tex] = 0.866 m/s
So, the speed of the 4.00-kg mass when it is 1.00 cm above the point from which it was released is 0.866 m/s.
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A runner covers the last straight stretch of a race in 4s During the time he speeds up from 5m/s to 9ms. What is the runners acceleration in this part of the race?
Answer: 1m/s^2
Explanation: The formula to find acceleration is:
a = (vf - vi) / t
where:
a= acceleration
vf= final velocity
vi= intial velocity
t= time
By substituting these values in the acceleration equation, we obtain:
a = (9 m/s - 5 m/s) / 4 s
we get:
a = 1 m/s^2
a 180-m-wide river flows due east at a uniform speed of 1.9 m/s. a boat with speed of 8.2 m/s relative to the water leaves the south bank of the river pointed in a direction 35 degrees west of north. what is the magnitude of the boat's velocity relative to the ground (in m/s)?
We can use vector addition to solve this problem. The velocity of the boat relative to the ground is the vector sum of the velocity of the boat relative to the water and the velocity of the water relative to the ground.
The velocity of the boat relative to the water can be found by resolving the given velocity into northward and eastward components:vbw_north = 8.2 cos(35°) = 6.73 m/s (northward) vbw_east = 8.2 sin(35°) = 4.64 m/s (eastward) The velocity of the water relative to the ground is simply 1.9 m/s due east. To find the velocity of the boat relative to the ground, we can use the Pythagorean theorem to combine these two velocity components: vbg^2 = vbw_north^2 + vbw_east^2 + vwater^2vbg = sqrt[(6.73 m/s)^2 + (4.64 m/s)^2 + (1.9 m/s)^2] = 9.28 m/s Therefore, the magnitude of the boat's velocity relative to the ground is 9.28 m/s.
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Today, modern transportation technology allows farm produce to be shipped quickly over long distances. What effect has this most likely had on agriculture? A. It has expanded the size of the market that a farm can supply produce to.
B. It has decreased the number of people needed to grow a certain kind of produce.
C. It has decreased the variety of produce available in a market.
D. It has increased the price for most types of produce.
The effect has this most likely had on agriculture is Option A, "It has expanded the size of the market that a farm can supply produce to" is the correct answer.
What is the agriculture effect?
8The effect of modern transportation technology that allows farm produce to be shipped quickly over long distances is most likely to expand the size of the market that a farm can supply produce to.
This is because modern transportation technology enables farmers to transport their produce over long distances quickly and efficiently, which increases the market reach of their products. As a result, farmers can supply their produce to markets that were previously inaccessible to them, thereby expanding their customer base and potentially increasing their profits.
Therefore, option A, "It has expanded the size of the market that a farm can supply produce to" is the correct answer. Options B, C, and D are not supported by the effects of modern transportation technology on agriculture.
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Complete question is: Today, modern transportation technology allows farm produce to be shipped quickly over long distances. The effect has this most likely had on agriculture is Option A, "It has expanded the size of the market that a farm can supply produce to".
g a car driving at a constant speed of 30 m/s rounds a curve with radius 10 m. what is the acceleration of the car? what provides the force that is responsible for this acceleration?
The acceleration of the car is 90 m/s².
The acceleration of the car can be found using the centripetal acceleration formula:
a = v²/r
where v is the velocity of the car and r is the radius of the curve. Plugging in the values, can get:
a = (30 m/s)² / 10 m = 90 m/s²
So, the acceleration of the car would be 90 m/s².
The force responsible for this acceleration is the centripetal force, which is provided by the friction between the tires and the road. This force acts perpendicular to the direction of motion and is directed towards the center of the curve, causing the car to turn. Without this force, the car would continue moving in a straight line instead of following the curved path.
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a lighter block (5 kg) and a heavier block (20 kg) sit on a frictionless surface. both blocks are initially at rest. the same force of 10 n then pushes to the right on each block for a distance of 16 m. what are the changes in kinetic energy of the blocks?
The changes in kinetic energy of the two blocks are both 160 J.
The changes in kinetic energy of the two blocks can be calculated using the work-energy theorem. The force of 10 N applied to both blocks does the same amount of work on each block, since they both move the same distance of 16 m. The work done on each block can be calculated as:
[tex]W = Fd = (10 N)(16 m) = 160 J[/tex]
The change in kinetic energy of each block can then be calculated as:
Δ[tex]K = W = 160 J[/tex]
Since the initial kinetic energy of both blocks is zero, their final kinetic energies are equal to the work done on them:
[tex]K\ final (5 kg block) = 160 J\\K\ final (20 kg block) = 160 J[/tex]
Therefore, changes in kinetic energy of the two blocks are both 160 J.
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on the bench, a vertical wire is attached to a power supply and a switch. the wire runs through the center of a plastic stand. when the switch is closed, what direction will the current flow (up or down) in the wire?
As a result, electric current flows from top to bottom i.e. downwards in the vertical wire.
When the switch is closed, the current will flow downwards in the vertical wire attached to a power supply and a switch. The wire runs through the center of a plastic stand. This is because the direction of electric current is from higher potential to lower potential.
When the switch is closed, it completes the circuit allowing electric current to flow through the wire. The power supply provides a higher potential at the top of the wire and a lower potential at the bottom of the wire.
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wheel 1 of mass rolls down a slope. wheel 2 of the same mass slides down the same slope with negligible friction. which wheel will reach the bottom first?
The wheel 1 that rolls down the slope will reach the bottom first.
This is because when a wheel rolls, its kinetic energy is a combination of its translational kinetic energy (due to its linear motion) and its rotational kinetic energy (due to its rotation around its center). When the wheel rolls down the slope, some of its potential energy is converted to translational and rotational kinetic energy. The rolling motion allows the wheel to convert more of its potential energy into translational kinetic energy, which makes it move faster than a wheel that only slides down the slope without rolling.
On the other hand, the wheel that slides down the slope without rolling will only have translational kinetic energy, which means it will move slower than the rolling wheel. The negligible friction on the sliding wheel will not make a significant difference in its speed.
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two electromagnetic waves have different frequencies but equal amplitudes. the one with higher frequency has the group of answer choices longer wavelength. greater energy. none of these. greater speed. all of these.
Explanation:
The correct answer is: none of these.
The frequency of an electromagnetic wave is inversely proportional to its wavelength and directly proportional to its energy. Therefore, two electromagnetic waves with different frequencies will have different wavelengths and energies. The amplitude of an electromagnetic wave, on the other hand, refers to the maximum displacement of the wave from its equilibrium position and is not related to its frequency, wavelength, or energy.
Therefore, we cannot determine whether the electromagnetic wave with higher frequency has a longer wavelength, greater energy, greater speed, or any combination of these, based solely on the information given in the question.
When two electromagnetic waves have different frequencies but equal amplitudes, the one with a higher frequency has greater energy.
What are electromagnetic waves?Electromagnetic waves are a type of wave that travels through space. They are a combination of electric and magnetic fields that move at right angles to each other and at right angles to the direction of wave propagation. The sun, light, radio waves, and microwaves are all examples of electromagnetic waves.
The formula that explains the relationship between energy and frequency of electromagnetic waves is E=hv where E is energy, v is frequency, and h is Planck's constant. The energy of electromagnetic radiation is proportional to its frequency.
Therefore, When two electromagnetic waves have different frequencies but equal amplitudes, the one with a higher frequency has greater energy.
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if a 4kg crate is being pulled to the right with a force of 20 n and it experiences a friction force of 5n what is its acceleration
If a 4kg crate is being pulled to the right with a force of 20 n and it experiences a friction force of 5n. The acceleration of the crate is 3.75 m/s².
The net force acting on the 4kg crate can be calculated by subtracting the friction force from the applied force:
20N - 5N = 15N.
To find the acceleration, use Newton's second law, F = ma.
Rearranging the equation to solve for acceleration:
a = F/m.
In this case,
a = 15N / 4kg
a = 3.75 m/s².
So, the acceleration of the crate is 3.75 m/s² to the right.
The rate at which an object's velocity varies over time is called accelaration. It is, in other words, the change in velocity per unit time. Acceleration occurs when an item accelerates, decelerates, or changes direction.
In the International System of Units, acceleration is typically measured in metres per second squared (m/s^2) (SI).
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a light string is wrapped around the edge of the smaller disk, and a 1.50 kg block is suspended from the free end of the string. if the block is released from rest at a distance of 1.60 m above the floor, what is its speed just before it strikes the floor? express your answer with the appropriate unit
When released from a height of 1.60 m, a 1.50 kg block suspended from a light string hits the floor with a speed of 5.06 m/s.
To take care of this issue, we really want to utilize preservation of energy. The underlying possible energy of the block is changed over into active energy as it falls, dismissing any misfortunes because of erosion or air opposition.
To start with, we should track down the underlying expected energy of the block:
U_i = mgh
where
m = 1.50 kg (mass of the block)
g = 9.81 [tex]m/s^2[/tex] (speed increase because of gravity)
h = 1.60 m (range from which the block is delivered)
U_i = (1.50 kg)(9.81 [tex]m/s^2[/tex])(1.60 m) = 23.5 J
Then, we should find the last motor energy of the block not long before it strikes the floor:
K_f = (1/2)[tex]mv^2[/tex]
where
v = speed of the block not long before it strikes the floor
We can utilize protection of energy to relate the underlying likely energy to the last motor energy:
U_i = K_f
Subbing the qualities we viewed as above, we get:
23.5 J = (1/2)(1.50 kg)[tex]v^2[/tex]
Settling for v, we get:
v = sqrt[(2*23.5 J)/(1.50 kg)] = 5.06 m/s
Thusly, the speed of the block not long before it strikes the floor is 5.06 m/s.
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what action could cause an involuntary wave pulse go through this line, and what kind of wave would it start? the answer below should both describe an involuntary wave and describe the type of wave pulse accurately.
An action that could cause an involuntary wave pulse to go through this line is the contraction of smooth muscle cells. The type of wave pulse that it would start is a mechanical wave pulse.
An involuntary wave is a wave that is not controlled by conscious will, such as the wave of contraction in a muscle. The involuntary wave is an uncoordinated contraction and relaxation of muscles.
A mechanical wave pulse is a wave that propagates through a medium, such as a solid, liquid, or gas, by the motion of particles in the medium. Mechanical waves require a medium to travel, and they transfer energy from one location to another without transferring matter.
Examples of mechanical waves include sound waves, water waves, and seismic waves.
Therefore, a mechanical wave pulse could be initiated by the contraction of smooth muscle cells can cause an involuntary wave pulse.
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2. How far (in meters) will you travel in 220 seconds running at a rate of 5.4 m/s?
Answer:
Explanation: Given: Time=220 seconds
Speed=5.4m/s
To find: Distance covered
Solution:
->The distance covered will be rate of running×time taken
Distance covered=5.4×220
->1188 metres
->Therefore, the distance covered will be 1188 metres.
astronomers have used observations from the hubble space telescope to measure the rate at which the universe is expanding, and have estimated the age of the universe from that measured rate. suppose the expansion turns out to be faster than current measurements indicate. in that case, our new estimate for the age of the universe would be group of answer choices younger (less time between now and the big bang). unaffected. older (more time between now and the big bang).
If the expansion of the universe turns out to be faster than current measurements indicate, it would mean that the universe is expanding at a greater rate than previously thought. This would imply that the universe has been expanding for a shorter period of time, as the same amount of expansion could be achieved in less time at a faster rate.
The new estimate for the age of the universe would be younger, with less time between now and the big bang. This would have significant implications for our understanding of the early universe, as a younger age would mean that there was less time for galaxies and structures to form.
It would also have implications for other cosmological models, as the age of the universe is a fundamental parameter in many theories of cosmology. However, it is important to note that this is still a hypothetical scenario, and further observations and measurements are needed to confirm or refute this possibility.
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A 1st class lever is used to lift a 350 N object placed 4 meters from the fulcrum. An effort force of 150 N is placed 15 meters from the fulcrum. Calculate: IMA, and Win, Wout.
In a first-class lever, the effort force and the load force act on opposite sides of the fulcrum, and the lever arm of each force is the perpendicular distance from the force to the fulcrum. The ideal mechanical advantage (IMA) of the lever is the ratio of the distance from the fulcrum to the effort force and the distance from the fulcrum to the load force.
IMA = distance from fulcrum to effort force / distance from fulcrum to load force
In this case, the distance from the fulcrum to the load force is 4 meters, and the distance from the fulcrum to the effort force is 15 meters. Therefore, the IMA of the lever is:
IMA = 15 m / 4 m = 3.75
The input work (Win) is the product of the effort force and the distance the effort force moves:
Win = effort force x distance moved by effort force
In this case, the effort force is 150 N, and it moves a distance of 15 meters. Therefore, the input work is:
Win = 150 N x 15 m = 2,250 J
The output work (Wout) is the product of the load force and the distance the load force moves:
Wout = load force x distance moved by load force
In this case, the load force is 350 N, and it moves a distance of 4 meters. Therefore, the output work is:
Wout = 350 N x 4 m = 1,400 J
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four 20 ohm resistors are connected in series and the combination is connected to a 20 v emf device. the potential difference across any one of the resistors is:
The potential difference across any one of the resistors in a circuit where four 20 ohm resistors are connected in series and the combination is connected to a 20 V emf device is 5 V.
What is a potential difference? A potential difference, also known as voltage, is the difference in electric potential energy between two points in an electric field. It is calculated as the work done per unit charge to move a charge from one point to another in the electric field. It is measured in volts (V).How is the potential difference in a circuit determined?The potential difference in a circuit can be calculated using Ohm's law. According to Ohm's law, the potential difference across a resistor is directly proportional to the current flowing through the resistor and the resistance of the resistor.V = IRwhereV is the potential difference (in volts),I is the current (in amperes), andR is the resistance (in ohms).In the given circuit, the total resistance of the four 20 ohm resistors in series is 80 ohms. The emf of the device is 20 V.Using Ohm's law,V = IR20 = I(80)I = 20/80I = 0.25 AThe current flowing through the circuit is 0.25 A. Since the resistors are connected in series, the current flowing through each resistor is the same.I = V/RI = 5/20I = 0.25 AThe potential difference across any one of the resistors is 5 V.
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Help please. If a comet were so large that its mass generated more gravity, then what would happen?
A. It wouldn’t orbit the Sun.
B. It would have become an asteroid.
C. It wouldn’t have a tail.
D. It would have become a meteor.
Answer:
it will become an asteroid because of the gravitational force
A comet would not become an asteroid, meteor, or lose its tail unless it were so massive that its bulk produced additional gravity.
What would occur if a sizable comet collided with the Sun?When a comet is large and powerful enough to strike the sun directly, it explodes. The comet is crushed by the sun's atmosphere after accelerating to more than 370 miles per second, creating a magnificent explosion that emits cosmic tidal waves of x-rays and ultraviolet light.
What do you believe would occur if a big comet hit the earth?A large comet's impact on Earth would be catastrophic. Large tidal waves, fires, and airborne dust and soot buildup could result, blocking out the majority of sunlight, causing vegetation to die and animals to go hungry.
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in a spring loaded bb gun, the spring is compressed by 15 cm. a 40 gram bb fired horizontally is found to have a muzzle velocity of 8.0 m/s. the spring constant of the spring is (in n/m)?
The spring constant of the spring is 114 N/m.
The potential energy stored in the compressed spring is given by:
U = (1/2) k x²
where k is the spring constant and x is the compression of the spring. Plugging in the values, can get:
U = (1/2) k (0.15 m)² = 0.01125 k J
This potential energy is converted into kinetic energy of the BB as it is fired from the gun. The kinetic energy of the BB is given by:
K = (1/2) m v²
where m is the mass of the BB and v is its velocity. Plugging in the values, we get:
K = (1/2) (0.04 kg) (8.0 m/s)^2 = 1.28 J
Since energy is conserved, we can equate the potential and kinetic energies:
U = K
0.01125 k = 1.28 J
Solving for k, we get:
k = 114 N/m
So, the spring constant of the spring is 114 N/m.
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