A 3.30-m-long, 560 kg steel beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 69.0 kg construction worker stands at the far end of the beam.

What is the magnitude of the torque about the point where the beam is bolted into place?

Answer:

First, let’s convert the mass of the ball bearing from grams to kilograms: 5.0 g = 0.005 kg.

a)

As the ball bearing falls from the machine to the floor, its gravitational potential energy is converted into kinetic energy. The change in potential energy can be calculated using the formula for gravitational potential energy: PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference point.

In this case, the change in potential energy is ΔPE = mgh = (0.005 kg)(9.8 m/s²)(3.0 m) = 0.147 J.

Since energy is conserved, this means that the change in kinetic energy is equal to the change in potential energy: ΔKE = ΔPE = 0.147 J.

b)

As the ball bearing bounces back up from the floor to its starting point, its kinetic energy is converted back into potential energy. Since energy is conserved and there are no dissipative forces, the changes in potential and kinetic energies are the same as in part a): ΔPE = 0.147 J and ΔKE = 0.147 J

A schematic diagram is a graphical representation of an electrical circuit, showing the arrangement of components and their connections.

The lines connecting the components in the schematic diagram represent wires or conductive paths.

The direction of the arrows and the polarity of the symbols indicate the direction of the flow of electrical current. The schematic diagram helps engineers and technicians understand the circuit and troubleshoot problems.

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Answer:

the circle on left shows the needle to the right (north pole). the circle on the right shows the needle to the right again.

Explanation:

the needle always goes to north

Answer:

Let's represent the magnitude of both vectors A and B using the variable "m".

According to the problem statement, we have:

|A| = |B| = m

|A+B| = 3|A-B|

Squaring both sides, we get:

|A+B|^2 = 9|A-B|^2

Expanding the left-hand side using the dot product formula, we have:

(A+B)·(A+B) = A·A + 2A·B + B·B

Similarly, expanding the right-hand side, we have:

9(A-B)·(A-B) = 9A·A - 18A·B + 9B·B

Substituting the given magnitudes, we have:

(A+B)·(A+B) = 2m^2 + 2(A·B)

9(A-B)·(A-B) = 18m^2 - 18(A·B)

Substituting these expressions back into the original equation, we get:

2m^2 + 2(A·B) = 9(18m^2 - 18(A·B))

Simplifying and rearranging, we get:

20(A·B) = 323m^2

Dividing by |A|·|B| = m^2, we have:

20(cosθ) = 323

where θ is the angle between vectors A and B. Solving for θ, we get:

θ = cos⁻¹(323/20)/π * 180

θ ≈ 83.4 degrees

The average force on the first ball = - 272.8 N.

The average force on the second ball is 9,568 N, and it acts in the direction of its motion.

the principle of conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the two billiard balls can be considered as a closed system.

Let's define some variables:

m =  (mass of each ball)

v1 =  (initial velocity of the first ball)

v2 =  (final velocity of the second ball)

t = 250 μs = 0.00025 s (duration of the collision)

According to the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision:

m * v1 = m * v2

Solving for v2, we get:

v2 = v1 * (m/m) = v1

This indicates that the second ball departs in the opposite direction of the first ball but with the same velocity. As a result, the system's total momentum is preserved.

The impulse-momentum theorem states that the impulse (change in momentum) is equal to the average force multiplied by the duration of the collision. We can use this to determine the average force on the first ball:

F1 * t = m * (v2 - v1)

Substituting the values we know, we get:

F1 * 0.00025 = 0.28 * (-8.6)

Solving for F1, we get:

F1 = - 272.8 N

The first ball's force is acting in the opposite direction of its initial velocity when the sign is negative.

To find the typical power on the subsequent ball, we can utilize a similar recipe:

F2 * t = m * (v2 - v1)

Substituting the values we know, we get:

F2 * 0.00025 = 0.28 * (v2 - 0)

Since we know that v2 = 8.6 m/s, we can solve for F2:

F2 = (0.28 * 8.6) / 0.00025

F2 = 9,568 N

Therefore, the average force on the second ball is 9,568 N, and it acts in the direction of its motion.

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In this case, the body has a mass of  [tex]3.0[/tex] kg and is moving with a velocity of [tex]10 m/s[/tex].  the moment of the body is  [tex]30 kg m/s.[/tex]

The moment of a body (also known as its momentum) is defined as the product of the body's mass and velocity.

In this instance, the body weighs  3.0  kilogrammes and is travelling at a speed of 10 m/s.

The formula to calculate the moment of the body is:

momentum = mass x velocity

Plugging in the given values, we get:

momentum [tex]= 3.0 kg \times 10 m/s[/tex]

Solving the above expression, we get:

momentum = [tex]30 kg m/s[/tex]

Therefore, the moment of the body is [tex]30[/tex] kg m/s.

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Answer:

Explanation:"The phenomenon of splitting of visible light into its component colours is called dispersion". Dispersion of light is caused by the change of speed of light.

The y-component of the vector is approximately 9.029 m.

In order to determine the y-component of this vector, we must first acknowledge that the information provided is a polar form of the vector, with 12.1 m representing its magnitude and 48.4° representing its angle with the positive x-axis.

The formula for this vector's y-component is as follows:

y = r sin θ

where r is the magnitude of the vector and θ is the angle that the vector makes with the positive x-axis.

In this case, r = 12.1 m and θ = 48.4°, so we have:

y = 12.1 m * sin(48.4°)

y ≈ 9.029 m

Therefore, the y-component of the vector is approximately 9.029 m.

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Disaster recovery and cooperation are both benefited by cloud storage. It makes file sharing simple and guarantees that data is backed up and retrievable in the event of loss or damage.

Your documents and data are kept in a safe data centre off-site by a cloud provider. You are no longer required to update software, maintain the servers, or make sure the hardware is working properly.

To store data, including files, business data, videos, or photographs, cloud storage uses remote servers. Users use an internet connection to upload data to servers, where it is stored on a virtual machine on a physical server.

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Indeed, a magnetised object with a north and south pole can be seen in the above photograph.

Any object that creates a magnetic field of its own and interacts with other magnetic fields is a magnet. A magnet has two poles, the north pole and the south pole. Field lines that begin at the north pole and end at the south pole of a magnet are used to show the magnetic field.

When hanging in the magnetic field of the Earth, a bar magnet automatically points northward and southward. A north magnetic pole is any pole that seeks the north, such as the north-seeking pole of this type of magnet.

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V = I R      or     I = V / R

I = 25 / 45 amps = .56 amps

The area of the input and load piston is [tex]7.07 cm^2[/tex] and [tex]452.16 cm^2[/tex], the ratio of the area of the load to the input piston is 63.95, the weight of the car is 16,660N, the force must be applied to the input is 260.15N.

Given the diameter of hydraulic jack (d1) = 3cm

The diameter of load piston of jack (d2) = 24cm

The mass of jack that is being used to lift a car (m) = 1700 kg.

We know that pressure is calculated as force per unit area such that: P = F/A where F is force applied and A is area

(a)Let  The area of the input piston is = A1

Then [tex]A1 = \pi r1^2 = \pi * (d1/2 cm)^2 = \pi * (1.5)^2 = 7.07 cm^2.[/tex]

Let The area of the load piston is = A2

Then [tex]A2 = \pi r2^2 = \pi * (d2/2)^2 = \pi * (12 cm)^2 = 452.16 cm^2.[/tex]

(b) The ratio of the area of the load to the area of the input piston = A2/A1

ratio = 452.16 / 7.07 = 63.95

(c) The weight of the car in newtons is W = mg

[tex]W = 1700 kg * 9.81 m/s^2 = 16,660N.[/tex]

(d) The force must be applied to the input piston to support the car = F1

The force applied at the load piston = F2 = W

We know that pressure exerted at both ends of piston is same, so P1 = P2 such that P1 = F1/A1 and P2 = F2/A2

F1 = F2 * A1/A2 = 16,660/63.95 = 260.15N

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The initial momentum of the ball is p₁ = m₁v₁ = (0.060 kg)(12 m/s) = 0.72 kg•m/s, and the final momentum of the ball is p₂ = m₂v₂ = (0.060 kg)(-35 m/s) = -2.1 kg•m/s. Therefore, the change in momentum is Δp = p₂ - p₁ = -2.1 kg•m/s - 0.72 kg•m/s = -2.82 kg•m/s.

The law of conservation of momentum states that the total momentum of a closed system is conserved if there are no external forces acting on the system.

In this problem, the system consists of the tennis ball and Venus' racket, and since there are no external forces acting on the system, the initial momentum of the ball must be equal to the final momentum of the ball and racket system.

The force calculated in part b is negative because it is in the opposite direction to the motion of the ball. The negative sign indicates that the force is acting in the direction opposite to the motion of the ball.

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The magnitude of the force of friction acting on the boat is 245.25 N.

F = mg sin - kmg cos is the formula for the component of the total force down the slope.

The following algorithm can be used to determine the amount of friction the boat is experiencing:

F friction = friction coefficient * normal force

normal force=weight of the boat

=m *g

where m is the mass of the boat and g is the acceleration due to gravity (9.81 m/s²).

Therefore, the force of friction on the boat is:

F friction = μ * m * g

Substituting the given values, we get:

F friction = 0.500 * 50 kg * 9.81 m/s² = 245.25 N

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Answer:

The answer to your problem is, The change in temperature required is ΔT = ΔV/Vγ

Explanation:

ΔT = ΔV/Vγ

ΔV = 49 - 40 = 9cm

V = 40 cm

γ is unknown since it cannot be calculated due to error in values.

Thus the answer to your problem is, The change in temperature required is ΔT = ΔV/Vγ

Answer:

360 watts

Explanation:

P =V × I

= 120×3.0

= 360

The density of brass is approximately 8300 kg/m³.

What is density ?

To find the density of brass, we need to first determine the total mass and volume of the mixture.

Let's assume that we have 1 cubic meter of zinc (since the exact volume is not given, we can use any convenient value as long as we are consistent with units).

The mass of this zinc would be:

mass_zinc = density_zinc * volume_zinc = 7100 kg/m³ * 1 m³ = 7100 kg

Since we are adding twice the volume of copper, we have 2 cubic meters of copper.

The mass of this copper would be:

mass_copper = density_copper * volume_copper = 8900 kg/m³ * 2 m³ = 17800 kg

The total mass of the mixture would be:

mass_total = mass_zinc + mass_copper = 7100 kg + 17800 kg = 24900 kg

The total volume of the mixture would be:

volume_total = volume_zinc + volume_copper = 1 m³ + 2 m³ = 3 m³

Finally, we can calculate the density of brass:

density_brass = mass_total / volume_total = 24900 kg / 3 m³ ≈ 8300 kg/m³

Therefore, the density of brass is approximately 8300 kg/m³.

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When 2750 J of heat are delivered to 85.45 g of iron, the resultant temperature change is 17.6 °C.

first rule. The law of conservation of energy has been thermodynamically modified to form the first law of thermodynamics. The conservation law states that energy can only be transformed from one form to another, not created or destroyed, which keeps the total energy of an isolated system constant.

q = mcΔT

where T is the temperature change, q is the heat energy, m is the mass, c is the specific heat capacity.

0.45 J/g°C is the specific heat capacity of iron. We can plug in the values given in the problem to find the temperature change:

q = mcΔT

2750 J = (85.45 g)(0.45 J/(g·°C))(ΔT)

ΔT = 17.6 °C

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Answer:

Time Travel Machine

Explanation:

The Hubble Space Telescope can look at galaxies that are many light years away. If it captured an image of a star that was 5 light years away, then that means it took light 5 years to reach the lens of the telescope. So, the image we see is what that star looked like 5 years ago. In other words, it is a glimpse of the past.

.

For Part A, we can use the formula Q = mc(T'f - Ti) to calculate the energy required to raise the temperature of the water. Here, Q is the energy required, m is the mass of the water, c is the specific heat capacity of water at 20°C and 1 atm (4.184 J/g°C), T'f is the final temperature (21.6°C), and Ti is the initial temperature (11.2°C).

First, we need to find the mass of the water. Since density = mass/volume, we can rearrange the formula to get mass = density * volume. Plugging in the given values, we get:

mass = (998 kg/m^3) * (4.80 x 10^11 m^3) = 4.79 x 10^14 kg

Now, we can plug in the values into the formula above:

Q = (4.79 x 10^14 kg) (4.184 J/g°C) (21.6°C - 11.2°C) = 2.02 x 10^19 J

Therefore, it would require 2.02 x 10^19 J of energy to raise the temperature of Lake Erie from 11.2°C to 21.6°C.

For Part B, we can use the formula P = E/t to calculate the time required to supply the energy using a power of 1,400 MW. Here, P is the power in watts, E is the energy required in joules (which we found in Part A), and t is the time in seconds. Since we want the time in years, we can convert from seconds to years at the end by dividing by the number of seconds in a year (31,536,000 s).

First, we need to convert the power from MW to W:

P = 1,400 MW * (10^6 W/MW) = 1.4 x 10^9 W

Now, we can rearrange the formula to solve for t:

t = E / P = (2.02 x 10^19 J) / (1.4 x 10^9 W) = 1.44 x 10^10 s

Converting from seconds to years, we get:

t = 1.44 x 10^10 s / 31,536,000 s/year = 456.7 years (rounded to three significant figures)

Therefore, it would take approximately 457 years to supply the energy needed by using a power of 1,400 MW generated by an electric power plant.

The magnitude of the magnetic field is 1.50 x 10^-3 T.

The force on a charged particle moving through a magnetic field is given by the equation:

F = qvB sin(theta)

where F is the force, q is the charge on the particle, v is the velocity of the particle, B is the magnetic field strength, and theta is the angle between the velocity vector and the magnetic field vector.

In this case, the electron is moving in a circular arc, which means that the force on the electron is directed inward toward the center of the circle, and is equal to the centripetal force:

F = mv^2 / r

where m is the mass of the electron, v is the velocity of the electron, and r is the radius of the circular arc.

We can equate these two forces and solve for the magnetic field strength:

mv^2 / r = qvB sin(theta)

Simplifying and rearranging:

B = mv / (qr) * 1/sin(theta)

To find the velocity of the electron, we can use the equation for the kinetic energy of a charged particle:

KE = 1/2 mv^2 = qV

where KE is the kinetic energy of the electron, q is the charge on the electron, and V is the potential difference that the electron was accelerated through.

Solving for v:

v = sqrt(2qV/m)

Plugging in the given values:

V = 20,000 V

m = 9.11 x 10^-31 kg

q = -1.6 x 10^-19 C

v = sqrt(2(-1.6 x 10^-19 C)(20,000 V) / 9.11 x 10^-31 kg) = 2.43 x 10^7 m/s

Now we can plug in the values for m, q, v, r, and theta (which is 90 degrees since the velocity vector is perpendicular to the magnetic field vector) to find the magnetic field strength:

B = (9.11 x 10^-31 kg)(2.43 x 10^7 m/s) / ((-1.6 x 10^-19 C)(0.12 m)) * 1/sin(90 degrees) = 1.50 x 10^-3 T

Therefore, the magnitude of the magnetic field is 1.50 x 10^-3 T.

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Hello and regards emmateddyafton94.

The acceleration of the lizard that has speeds between 2 m/s and 10 m/s, in a time of 4 seconds, is 2 m/s².

It is an exercise in rectilinear motion uniformly accelerated (MRUA) is a type of movement in a straight line in which an object moves with a constant acceleration. This type of movement is common in everyday life, such as when an object falls due to the force of gravity or when a car moves in a straight line and accelerates at a constant speed.

In the MRUA, the speed of the object changes at a constant rate in each unit of time. This means that acceleration is the amount of change in velocity that occurs in each second, and it is constant throughout the motion. Acceleration is measured in units of length per unit of time squared (for example, meters per second squared).

The fundamental formula of the MRUA is:

Where:

We now know that the data is:

But since they are asking us to calculate the acceleration, we clear the formula:

Where:

This formula shows that the acceleration is equal to the difference between the final velocity and the initial velocity of the object, all divided by the elapsed time. It is important to note that final velocity and initial velocity must be in the same units (for example, meters per second) and that time must be in units of time (for example, seconds).

We substitute data in the formula, and calculate the acceleration:

a = (Vf - V₀)/t

a = (10 m/s - 2 m/s)/(4 s)

a = 2 m/s²

The acceleration of the lizard that has speeds between 2 m/s and 10 m/s, in a time of 4 seconds, is 2 m/s².

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Answer:

The lizard's average acceleration is 2 m/s².

Explanation:

The average acceleration of the lizard can be calculated using the formula:

[tex]\sf\qquad\dashrightarrow a = \dfrac{(V_f - V_o)}{t}[/tex]

where:

Plugging in the given values, we get:

[tex]\sf\qquad\dashrightarrow a = \dfrac{(10\: m/s - 2\: m/s)}{4\: sec}[/tex]

[tex]\sf\qquad\dashrightarrow a = \boxed{\bold{\:\:2\: m/s^2\:\:}}[/tex]

Therefore, the lizard's average acceleration is 2 m/s².

The amount of work done is 15,000 J if an automobile pulls a truck with a force of 1500 N and the truck travels 10 meters in 15 seconds. One kW or 1,000 W is the power.

A force's work is indicated by:

Fdcosθ = W

d is the distance moved in the direction of the force, F is the force's magnitude, and is the angle between the force and the displacement.

W = 1500 N x 10 m x cos(0°), which equals 15,000 J.

The amount of work is 15,000 J.

P = W/t

P = 15,000 J / 15 s = 1,000 W

One kW or 1,000 W is the power.

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The initial pressure to final pressure ratio is 0.789.

An ideal gas's volume must fall by if its pressure is raised by 10% at constant temperature. If an ideal gas's pressure is raised at constant temperature. At constant temperature, when a gas's pressure is increased by 5%.

P1V1/T1 = P2V2/T2

Since the volume of the gas is fixed in this problem, we can simplify the equation to:

P1/T1 = P2/T2

We are given that P1 = 1 atmosphere and T1 = 0°C = 273.15 K, and we need to find the ratio P1/P2. We can rearrange the equation to solve for P2:

P2 = P1 × T2 / T1

We are also given that T2 = 73°C = 346.15 K and P2 = 10 atmospheres, so we can substitute these values into the equation and solve for P1/P2:

P1/P2 = T1/T2 × P2/P1

P1/P2 = 273.15 K / 346.15 K × 10 atm / 1 atm

P1/P2 = 0.789

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Answer:

online medical

Explanation:

like COVID dieases technicians do online training

Answer:

V = f * λ        Velocity = frequency * wavelength

λ = V / f = 128 m/s / 256 / s= .5 m       is the wavelength

There will be nodes at o, λ/2, λ, 3λ/2      or at intervals of λ/2

The distance between nodes is ".25 m"

6.25 coulombs of charge is passing through a circuit providing electricity for a 120 V light bulb if it uses 300 J of energy.

When placed in an electromagnetic field, the physical property of matter known as electric charge causes matter to feel a force. A positive or negative electric charge can exist. (commonly carried by protons and electrons respectively, by convention). Like charges repel one another, while unlike charges draw one another. A neutral substance is one that does not have any net charge. Classical electrodynamics refers to early understanding of how charged substances interact, and it is still accurate for problems that do not require consideration of quantum effects.

Electric charge is a conserved characteristic; the net charge of an isolated system, which is the sum of positive and negative charges, cannot change. Subatomic particles carry electric energy. Negative charge in ordinary substance.

Calculate the amount of time that the energy is used.

[tex]\frac{300 J}{120 V}[/tex]= 2.5 seconds

Calculate the current running through the circuit.

Current = Power / Voltage = [tex]\frac{300W}{120V}[/tex]= 2.5 Amps.

Calculate the charge passing through the circuit.

Charge = Current x Time

= 2.5 Amps x 2.5 seconds

= 6.25 Coulombs of charge.

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Answer:

Explanation:

m=p/v

where m is mass, p is momentum and v is velocity

The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

The equation can be used to determine the average force the nail applies to the hammer.

[tex]F = \frac{mv}{t}[/tex], where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:

[tex]F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.[/tex]

To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

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