Answer:
.
Explanation:
A bowl of hot soup and a glass of ice water are left in a room. Eventually
the soup and the water become the same temperature as their
surroundings. Which of the following explains the flow of heat that led to
this final outcome?
A
The heat of the soup and the cold of the water were exchanged,
cancelling each other out
B
Heat energy went from the soup to the room and from the room
into the ice water
С
Heat energy went from the ice water to the soup and from the
soup to the room.
D
The low temperature of the water was transferred to the room
and from the room to the soup.
Answer:
The answer must be B
Explanation:
Because the hot soup increases the temperature of the room it also increased the temprature of the ice water and because whatever surroundings the soup and the ice is in it transfers heat energy to the room and because most of the energy is lost in the room it eventually becomes the same tempature.
10. As a spaceship is moving toward Earth, an Earthling measures its length to be 325 m, while the captain on board radios that her spaceship's length is 1150 m. (c = 3.00 × 108 m/s) (a) How fast is the rocket moving relative to Earth? (b) What is the TOTAL energy of a 75.0-kg crewman as measured by (i) the captain in the rocket and (ii) the Earthling?
Answer:
Explanation:
10. As a spaceship is moving toward Earth, an Earthling measures its length to be 325 m, while the captain on board radios that her spaceship's length is 1150 m. (c = 3.00 × 108 m/s) (a) How fast is the rocket moving relative to Earth? (b) What is the TOTAL energy of a 75.0-kg crewman as measured by (i) the captain in the rocket and (ii) the Earthling?
Therapeutic boarding schools help parents cope with their teens who have borderline personality disorder in all of the
following ways except
A. teaching the parents how to positively support their teen while they are at home
B. providing family therapy while the teen is in treatment
C. teaching the parents to persistently support the teen's unstable self-image
D. teaching the patient how to interact appropriately with their peers
Please select the best answer from the choices provided
A
A
B
00
С
Answer:
The answer is C
Explanation:
An oil droplet is sprayed into a uniform electric field of adjustable magnitude. The 0.11 g droplet hovers
motionless (gravity force equalling electrostatic force) when the electric field is set to 370 N/C and directed
downward.
a) Determine the sign and magnitude of the charge on the oil droplet.
b) Determine the approximate number of excess electrons that are on the oil droplet.
Answer:
The direction of the field is downward, and negatively charged particles will experience an upwards force due to the field.
F = N e E where E is the value of the field and N e the charge Q
M g = N e E and M g is the weight of the drop
N = M g / (e E)
N = 1.1E-4 * 9.8 / (1.6E-19 * 370) = 1.1 * 9.8 / (1.6 * 370) * E15 = 1.82E13
.00011 kg is a very large drop
Q = N e = M g / E = .00011 * 9.8 / 370 = 2.91E-6 Coulombs
Check: N = Q / e = 2.91E-6 / 1.6E-19 = 1.82E13 electrons
if a weight of 100 lbs is moved through a displacement of 1.2m, how much work was done to move the weight
Answer:
534 j
Explanation:
100 lbs = 45.359 kg
work = F * d
= 45.359 * 9.81 * 1.2 = ~ 534 j
The work done is the dot product of force and displacement. 100 lbs is 45.3 kg in weight. The work done on this weight to make a displacement of 1.2 m is 532.728 J.
What is work done?Work done in physics is the dot product of force and displacement. Force exerted on an object if results in displacement, it is said to be work done on the object. Work done is a vector quantity, thus, both magnitude and direction.
Not any force results in work done. Work is done only if there occurs a displacement. It is given that the weight of object moved is 100 lbs.
1 lbs. = 0.453 kg
thus, 100 lbs. = 45.3 Kg.
Force F = mg
= 45.3 Kg × 9.8 m/s²
= 443.94 N
This is the force by its own weight.
Work done = Force × displacement.
= 443.94 N × 1.2 m
= 532.728 J
Therefore, the work done to move the weight is 532.72 J.
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1 x 1015 electrons are pushed through a 10 Ω wire in one minute. What is the voltage of the power source? (e = -1.602 x 10-19 C)
The voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.
Voltage of the power source
The voltage of the power source is determined from ohm's law as shown below;
V = IR
where;
I is currentR is resistanceV is voltageBut, I = Q/t
V = (Q/t)R
[tex]V = \frac{QR}{t} \\\\V = \frac{(1\times 10^{15} \times 1.602\times 10^{-19} \ C) \times \ 10 \ ohms}{1 \times 60\ s} \\\\V = 2.67 \times 10^{-5} \ V[/tex]
Thus, the voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.
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g A series circuit contains a 1.0-k Ω resistor, a 5.0-mH inductor, and an ideal 25-V power supply. What is the time constant for the circuit?
Hi there!
Recall the equation for an LR circuit time-constant:
[tex]\tau = \frac{L}{R}[/tex]
L = Inductance (H)
R = Resistance (Ω)
Plug in the given values.
[tex]\tau = \frac{0.005}{1000} = 0.000005 s = \boxed{\text{5 } \mu s}[/tex]
The rate at which an object changes position is called?
Question 5 options:
Speed
Distance
Momentum
Acceleration
Answer:
I think that it is called speed
Explanation:
Answer:
speed
Explanation:
The rate of change of POSITION is speed
The rate of change of SPEED is acceleration
reasons of studying physics
Answer:
Physics helps you to understand the world around you, and satisfy your curiosity. It develops your critical thinking and problem-solving skills.
5. A single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen. The 5th minimum occurs at 7.00° away from the central maximum. At what angle does the 18th minimum occur? A) 26.0° B) 1.94° C) 5.05° D) 0.44°
For a single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen,the angle is mathematically given as
theta=25.3
Option A is correct
What angle does the 18th minimum occur?Generally, the equation for the the angle is mathematically given as
[tex]\theta=n(\lambda/d)[/tex]
Therefore
[tex]\theta 1/ \theta 2=n1(\lambda/d)/ n2(\lambda/d)[/tex]
In conclusion
theta/7=16/5
theta=10*7/5
theta=25.3
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Calculate the pressure amplitude of a 2.80 kHz sound wave in the air, if the
displacement amplitude is equal to 2.00 ✕ 10-8 m.
The pressure amplitude of a 2.80 kHz sound wave is mathematically given as
pm=0.14647pa
What is the pressure amplitude of a 2.80 kHz sound wave in the air?
Generally, the equation for the relation b/w pressure amplitude and displacement amplitude is mathematically given as
pm=2\pifvps
Therefore
pm=(2\pi)(2.80*10^3)(340)(1.225)(2.00*10^{-8})
pm=0.14647pa
In conclusion
pm=0.14647pa
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define summarize the step you might use to carry out
Answer:
The steps involved in the scientific method are;
•Draw up a research question
•Construct a hypothesis
•Test the hypothesis through experiments
•Analyse experimental results
•Draw conclusions
Science is a study of the universe from an empirical point of view. This means that scientific investigations depend onexperiments.
The first step in the scientific method of investigation is to draw up the research questions to be investigated. After this is done, subjected to experiments. The experiments may confirm or disprove the hypothesis. If the hypothesis is disproved, then it is revised in line with the results of experiments.
a research hypothesis is constructed and
How close would you have to bring 1 C of positive chargeand 1 C of negative charge for them to exert forces of 1 N onone another?
Answer:
94,800 m
Explanation:
F = kq1 q2/r^2
1 = 9 x 10^9 x 1 / r^2
Is this circuit parallel??????
Answer:
yes it is parrell
Explanation:
From a graph v1 = 0.4m/s, V2 = 2.35m/s, t1 = 0.5s, t2 = 10.0s. The slope obtained using the above information isSelect one:
O 0.21m/s
O 0.27m/s
O 0.25m/s
O 0.23m/s
The slope obtained using the above information is acceleration and the magnitude of the acceleration is determined as 0.21 m/s².
Slope of velocity - time graph
The slope of velocity time graph is known as acceleration. Acceleration is the rate of change of velocity with time.
a = Δv/Δt
where;
Δv is the change in velocityΔt is the change in timeChange in velocityΔv = vf - vi
Δv = 2.35 - 0.4
Δv = 1.95 m/s
Change in timeΔt = t2 - t1
Δt = 10 - 0.5
Δt = 9.5 s
Slope of the grapha = Δv/Δt
a = (1.95) / (9.5)
a = 0.21 m/s²
Thus, the slope obtained using the above information is acceleration and the magnitude of the acceleration is determined as 0.21 m/s².
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Determine the components of the third line of defence
Answer:
The third line of defense is immune cells that target specific antigens. The immune cells that play a role in the third line of defense are B-cells and T-cells, both are white blood cells. The B-cells produce antibodies. The T-cells help identify pathogenic cells and destroy targeted cells.
Which of the following describes the renewability of utility-scale wind energy?
Replenishable but not renewable
Needs energy grid for electricity
Unlimited, clean energy plant
Sustainable lack of emissions
Unlimited, clean energy plant describes the renewability of utility-scale wind energy.
What is utility-scale wind energy?Utility-scale wind turbines are installed in large, multi-turbine wind farms connected to the nation's transmission system. These turbines produce clean and unlimited energy.
So we can conclude that Unlimited, clean energy plant describes the renewability of utility-scale wind energy.
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Answer:
Answer 3
Explanation:
I took the test
Consider two blocks that are attached bv a string. Block 1 (mass of 2 ko) lavs on a flat dlane. Block ? (mass of 3 kg) hangs freely off the edge of the plane. In the absence of friction, Block 2 would fall and the string would pull Block 1 towards the edge. Find the static coefficient of friction needed to keep Block at its starting position.
With no friction, block 1 would be pulled to the edge of the table as block 2 falls. By Newton's second law, the net horizontal force on block 1 is
∑ F[1, h] = T = (2 kg) a
where T = magnitude of tension and a = acceleration of the blocks, while the net force on block 2 is
∑ F[2] = (3 kg) g - T = (3 kg) a
where (3 kg) g = weight of block 2 and g = 9.8 m/s². Notice that we take the downward fall of block 2 to be the positive direction.
Eliminate T and solve for a :
T + ((3 kg) g - T) = (2 kg) a + (3 kg) a
(3 kg) g = (5 kg) a
a = 3g/5
Solve for T :
T = (2 kg) (3g/5) = 6g/5 kg = 11.76 N
Now, taking friction into account, block 1 would have net force
∑ F[1, h] = T - sf = 0
so that the maximum magnitude of static friction is sf = 11.76 N. The net vertical force on block 1 is
∑ F[1, v] = n - (2 kg) g = 0
where n = magnitude of the normal force. Let µ be the coefficient of static friction. It follows that
n = (2 kg) g = 19.6 N
sf = µ n ⇒ µ = (11.76 N) / (19.6 N) = 0.6