342,475 plus 71,925


Thank you

Step-by-step explanation:

P(x,y)=(1,-3)

line is perpendicular to x=2 which shows that line is parallel to x-axis.

angle=0°

m=tan(angle)

m=tan0°

m=0

By using point slope form:

y+3=0(x-1)

y+3=0

Step-by-step explanation:

The quotient of three and number n translate to 3 divide by a number n,given the quotient indicates division or fraction. four more than that value tells us that we simply add a 4

Answer:

the answer will be 60 percent

=60%

Answer:

x°=43°

2x°=86°

(x+8)°=51°

Step-by-step explanation:

x+2x+x+8=180°[being sum of the angles of triangle]

or, 4x+8=180

or, 4x=180-8

or, 4x=172

or, x=172/4

or, x=43°

Then,

2x=2×43°=86°

(x+8)°=(43+8)°=51°

Please mark me brainliest.

From the information given, the total length of the stream will be 548.89 meters

The length of the first stream =  45.27 meters

The length of the second stream = 503.62 meters

The total length of the stream will be equal to the addition of the length of the first stream and the second stream and this will be:

= 45.27 meters + 503.62 meters

= 548.89 meters

Read related link on:

https://brainly.com/question/24443880

Answer

The correct answer iss 548.89

Step-by-step explanation:

45.27+503.62=548.89

Hope this helps!

Answer:

Z, K and R

and

H ,B and C

........

Answer:

Step-by-step explanation:

The unknown number is reflected as n.

The sum of 5 and four times a number is 32:

Four less than the square of a number is 12:

The product of 3 and four more than a number is 20:

There are some symbols missing in your integral. I suspect you meant something along the lines of

[tex]\displaystyle \int_C (x+5y)\,\mathrm dx + x^2\,\mathrm dy[/tex]

but we can consider a more general integral,

[tex]\displaystyle \int_C f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy[/tex]

One way to compute the integral is to split up C into two component paths C₁ and C₂, parameterize both, directly compute the integral over each path, then sum the results.

Parameterize C₁ and C₂ respectively by

〈x₁(t), y₁(t)⟩ = (1 - t ) 〈0, 0⟩ + t 〈5, 1⟩ = 〈5t, t⟩

〈x₂(t), y₂(t)⟩ = (1 - t ) 〈5, 1⟩ + t 〈5, 0⟩ = 〈5, 1 - t⟩

where 0 ≤ t ≤ 1. Then

[tex]\displaystyle \int_C f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy = \int_{C_1} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy + \int_{C_2} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy \\\\ = \int_{C_1} \left(f(x_1(t),y_1(t))\frac{\mathrm dx_1}{\mathrm dt} + g(x_1(t),y_1(t))\frac{\mathrm dy_1}{\mathrm dt}\right)\,\mathrm dt \\ + \int_{C_2} \left(f(x_2(t),y_2(t))\frac{\mathrm dx_2}{\mathrm dt} + g(x_2(t),y_2(t))\frac{\mathrm dy_2}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^1 \left(5f(5t,t) + g(5t,t) - g(5,1-t)[/tex]

If f and g agree with what I suggested earlier, the integral reduces to

[tex]\displaystyle \int_0^1 \left(5(5t+5t) + (5t)^2 - 5^2\right)\,\mathrm dt = \int_0^1 \left(25t^2 + 50t - 25\right)\,\mathrm dt = \boxed{\frac{25}3}[/tex]

Another way would be to close the path with a line segment from (5, 0) to (0, 0) and apply Green's theorem. Compute the resulting double integral, then subtract the contribution of the line integral over this third line segment. Provided that f(x,y) and g(x,y) don't have any singularities along this closed path C* or inside the triangle (call it T ) that it surrounds, we have

[tex]\displaystyle \int_{C^*} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy = -\iint_T \frac{\partial g}{\partial x}-\frac{\partial f}{\partial y} \,\mathrm dx\,\mathrm dy[/tex]

where T is the region,

[tex]T = \left\{(x,y) \mid 0\le x\le 5 \text{ and } 0\le y\le \dfrac x5\right\}[/tex]

The double integral has a negative sign because C* has a negative, clockwise orientation.

Then

[tex]\displaystyle \int_{C^*} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy = -\int_0^5\int_0^{x/5} \frac{\partial g}{\partial x}-\frac{\partial f}{\partial y} \,\mathrm dy\,\mathrm dx[/tex]

If f and g are as I suggested, then

[tex]\displaystyle \int_{C^*} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy = \int_0^5\int_0^{x/5} (5-2x) \,\mathrm dy\,\mathrm dx = -\frac{25}6[/tex]

From this, we subtract the integral along the line segment C₃ from (5, 0) to (0, 0), parameterized by

〈x₃(t), y₃(t)⟩ = (1 - t ) 〈5, 0⟩ + t 〈0, 0⟩ = 〈5 - 5t, 0⟩

again with 0 ≤ t ≤ 1.

Then the remaining line integral is

[tex]\displaystyle \int_{C_3} f(x_3(t),y_3(t))\,\mathrm dx_3 + g(x_3(t),y_3(t))\,\mathrm dy_3 = \int_{C_3} x_3(t)\frac{\mathrm dx_3}{\mathrm dt}\,\mathrm dt \\\\ = \int_0^1 -5(5-5t)\,\mathrm dt = -\frac{25}2[/tex]

and so the original line integral is again -25/6 - (-25/2) = 25/3.

Answer:

about 41 cents

Step-by-step explanation:

Answer:

3 units per hour

Explanation:

Time = 9 hours

Difference in sales = 24 (Chromebooks)

24 ÷ 9 = 2.66...

When rounded, it equals 3.

Answer:

25

Step-by-step explanation:

5=20% of x

0.20x=5

divide both sides by 0.20

x=25

Answer:

4 packages

Step-by-step explanation:

Since the store sells by 1/2 packages, we have to round 1.72 UP to 2.00. Then we multiply 1/2pound by 4= 2.00 pounds

Answer:

-19

Step-by-step explanation:

g(x)=−3x−4

Let x = 5

g(5)=−3*5−4

Multiply

   = -15-4

   = -19

[tex]g(x) = - 3x - 4 \\ \\ g(5) = - 3(5) - 4\\ \\ x = - 15 - 4 \\ \\ x = - 19[/tex]

Hope it help you

Answer:

so you basicly divided 5.87 to 3.25

Step-by-step explanation:

do this : 5.87/3.25=  your answer

Answer:

lol someone just deleted my answer but like i said i cant really tell you unless you could possibly turn it around like up straight

Step-by-step explanation:

9514 1404 393

Answer:

  domain: (-4, 9)

Step-by-step explanation:

The graph is defined for all points between -4 and 9, but not for those two points. In interval notation, the domain is (-4, 9).

f(x) < g(x)

(2x + 3) < (3x - 2)

3 < x - 2

5 < x

x > 5

Check:

2x + 3 < 3x - 2

2(5) + 3 < 3(5) - 2

10 + 3 < 15 - 2

13 < 13 --- FALSE

2(10) + 3 < 3(10) - 2

20 + 3 < 30 - 2

23 < 28 --- TRUE

Hope this helps!

Answer:

x < 5

Step-by-step explanation:

f(x) < g(x) if f(x) = 2x + 3 and g(x)= 3x - 2 ​

2x + 3 < 3x - 2 ​

2x - 3x < -2 -3

-x < -5

x > 5

Answer:

Y=K×X

when Y=-8 and X=4

-8=K×4

-8=4K divide both sides by 4

K=-2 constant

To find Y when X=-4,Y=? and K=-2

Y=-2×-4

Y=8

Answer:

f(t)=-16t^2+8t+2

Step-by-step explanation:

Take the initial velocity(8)put in for vt. Then take height(2) and put in for s. giving you the equation. f(t)= -16t^2+8t+2

The copy is the exact same as the original, so the scale factor would be 1.

The answer is the first choice

Answer: y + 5 = 3/5 (x + 5)

Concept:

There are four general forms of equations:  

Here, we are going to use the point-slope form because the question has given us both the slope and one point.

Solve:

**Disclaimer** Since the question did not clarify, thus, I choose to use the point-slope form as it is the easiest method. However, if the question has a specified form of the equation, please tell me and I will redo it.

Given information

(x₁, y₁) = (-5, -5)

m = 3/5

Given expression

y - y₁ = m (x - x₁)

Substitute values into the expression

y + 5 = 3/5 (x + 5)

Hope this helps!! :)

Please let me know if you have any questions

1 st picture,

Other names of <1 are - <F, <YFP, <PFY

2 nd picture,

Acute

3 rd picture,

Point E

Answer:

1. ∠F, ∠YFP, ∠PFY

2. Acute

3. Point E

Step-by-step explanation:

Answer:

x is 3

Step-by-step explanation:

[tex] {5}^{(x + 1)} - {5}^{(x + 2)} = - 2500 \\ [/tex]

divide all sides by -1:

[tex] {5}^{(x + 2)} - 5 {}^{(x + 1)} = 2500[/tex]

from law of indices:

[tex]( {5}^{x} . {5}^{2} ) - ( {5}^{x} . {5}^{1} ) = 2500[/tex]

factorise out 5^x:

[tex] {5}^{x} ( {5}^{2} - {5}^{1} ) = 2500 \\ {5}^{x} (20) = 2500 \\ {5}^{x} = 125 \\ {5}^{x} = {5}^{3} \\ x = 3[/tex]