When 0.60 mol NH 3 is decomposed in a 1 Liter flask at 850 K, the equilibrium concentration of NH3 is measured as 0.12 M. Given that ammonia decomposes according to the reaction
2 NH3(g) ⇌ N2(g) + 3 H2(g),
what is Kc for the reaction?
a. 0.16
b. 12.00
c. 1.44
d. 6.22
e. 0.75

Answers

Answer 1

Answer:

in a 1 Liter flask at 850 K, the equilibrium concentration of NH3 is measured as 0.12 M. Given that ammonia decomposes according to the reaction

2 NH3(g) ⇌ N2(g) + 3 H2(g),

what is Kc for the reaction?

a. 0.16

b. 12.00

c. 1.44

d. 6.22

e. 0.75

Answer 2

The response is 12.00 (b). Using the equation Kc = [N2][H2]3/[NH3]2, we can find the equilibrium constant Kc for the reaction 2 NH3(g) N2(g) + 3 H2(g).

What is the equilibrium concentration ?

In this instance, the capacity of the flask is 1 litre, and the equilibrium concentration of NH3 is 0.12 M. Therefore, using the reaction's stoichiometry, it is possible to determine the equilibrium concentrations of N2 and H2.

Since 2 moles of NH3 break down into 1 mole of N2 and 3 moles of H2, the equilibrium concentrations of N2 and H2 are 0.06 M and 0.18 M, respectively. As a result, the equilibrium constant Kc = [N2][H2]3/[NH3]2 = (0.06)(0.18)3/0.122 = 12.00 may be computed.

Therefore, b. 12.00 is the right response. You should be aware that the equilibrium constant Kc is a value that is temperature-dependent and is only applicable at the specified temperature. As a result, Kc will have a varied value depending on the temperature. The temperature in this instance is 850 K, and the Kc value is 12.00.  

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Answers

The equili constant assuming reaction is from isomer A to isomer B; 19

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