Answer:
8.76 ml³
Explanation:
volume = mass ÷ density
How many moles of aluminum oxide (Al2O3) are in a sample with a mass of 204.0 g?
Answer:
[tex]\boxed {\boxed {\sf 2.001 \ mol \ Al_2O_3}}[/tex]
Explanation:
We are asked to convert grams of aluminum oxide to moles. We will do this using the molar mass or mass of 1 mole of a substance. The values are found on the Periodic Table. They are equal to the atomic masses, but the units are grams per mole instead of atomic mass units.
We have the compound aluminum oxide or Al₂O₃. We must look up the molar masses of the individual elements: aluminum and oxygen.
Al: 26.981538 g/mol O: 15.999 g/molThe formula of the compound has subscripts (a subscript of 2 after Al and subscript of 3 after O). There are 2 moles of aluminum and 3 moles of oxygen in 1 mole of aluminum oxide. We must multiply the molar mass by its subscript.
Al₂ : 26.981538 * 2=53.963076 g/mol O₃: 15.999 * 3=47.997 g/mol Al₂O₃ =53.963076 + 47.997 = 101.960076 g/molWe convert using dimensional analysis, so we set up a ratio using the molar mass.
[tex]\frac {101.960076 \ g \ Al_2O_3}{ 1 \ mol \ Al_2O_3}[/tex]
We are converting 204.0 grams to moles, so we multiply by this value.
[tex]204.0 \ g \ Al_2O_3 *\frac {101.960076 \ g \ Al_2O_3}{ 1 \ mol \ Al_2O_3}[/tex]
Flip the ratio so the units of grams of aluminum oxide cancel.
[tex]204.0 \ g \ Al_2O_3 *\frac { 1 \ mol \ Al_2O_3}{101.960076 \ g \ Al_2O_3}[/tex]
[tex]204.0 *\frac { 1 \ mol \ Al_2O_3}{101.960076}[/tex]
[tex]\frac {204.0}{101.960076} \ mol \ Al_2O_3[/tex]
[tex]2.00078313 \ mol \ Al_2O_3[/tex]
The original measurement of grams has 4 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in ten-thousandth place tells us to round the 0 up to a 1.
[tex]2.001 \ mol \ Al_2O_3[/tex]
204.04 grams of aluminum oxide is equal to approximately 2.01 moles of aluminum oxide.
PLeaseeeeeeee help me ┗( T﹏T )┛
Convert 50 kilograms into grams.show your work
Answer:
50000 g
Explanation:
1 kilogram (kg) is equal to 1000 grams (g).
1 kg = 1000 g
The mass m in grams (g) is equal to the mass m in kilograms (kg) times 1000:
m(g) = m(kg) × 1000
An organized method scientists use to solve problems and test
hypotheses
hypothesis
scientific process
conclusion
experiment
Explanation:
Hypothesis is answer.
Have a great day
Which list only includes terms that describe oxygen gas, O2?
A. element, molecule, pure substance
B. atom, compound, molecule
C. atom, element, molecule
D. compound, molecule, pure substance
Answer:
d
Explanation:
it just makes alot of sense and you got this
Oxygen is a gas that belongs to the chalcogen family and is a reactive non-metal. It is an element, molecule, or pure substance. Thus, option A is correct.
What is a pure substance?A pure substance is defined as a substance that cannot be physically separated into its constituent particles. They are known to have a definite and constant chemical composition. It can be a molecule, element, or compound.
An element is atomic species that cannot be broken into simple sub-particles by chemical processes. On the other hand, if an atomic element bonds to the same or different atom it forms a molecule.
Oxygen gas is an element composed of two atoms of oxygen and is a molecule as the two atoms are linked chemically. It is also a pure substance as it contains the same element.
Therefore, option A. oxygen gas is a pure substance, an element, and a molecule.
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If the PH is 5.85.how do I calculate for an acid ?[H^+]
Answer:
if its under 7 then it's an acid you neek over 7 is alkaline
How many grams of H2O are produced when 35.0 g of NaOH reacts with 17.5 g of CO,?
2NaOH + CO2 -> Na2CO3 + H2O
Answer:
2NaOH + CO2 -> Na2CO3 + H2O
1) Find the moles of each substance
[tex]\eq n(NaOH)=\frac{35.0}{22.99+16.00+1.008\\}\ =\frac{35.0}{39.998} \ = 0.8750437522 moles\\n(CO_{2} ) = \frac{17.5}{12.01+32.00} = \frac{17.5}{44.01} = 0.3976369007 moles\\[/tex]
2) Determine the limitting reagent
[tex]\\NaOH = \frac{0.8750437522}{2} = 0.4375218761\\\\[/tex]
∴ Carbon dioxide is limitting as it has a smaller value.
3) multiply the limiting reagent by the mole ratio of unknown over known
n(H2O ) = 0.3976369007 × 1/2
= 0.1988184504 moles
4) Multiply the number of moles by the molar mass of the substance.
m = 0.1988184504 × (1.008 × 2 + 16.00)
= 0.1988184504 × 18.016
= 3.581913202 g
Explanation:
The correct answer is = 3.581913202 g.
n(H2O ) = 0.3976369007 × 1/2
= 0.1988184504 moles
m = 0.1988184504 × (1.008 × 2 + 16.00)
= 0.1988184504 × 18.016
= 3.581913202 g.
What does H2O stand for?H2O is the molecular formula of water, also called Dihydrogen monoxide. H2O symbolises two hydrogen atoms and one oxygen atom.
What is 1 mol H2O?
Water (H2O) is made from 2 atoms of hydrogen and 1 atom of oxygen. A mole of water molecules would be 2 moles of hydrogen atoms plus 1 mole of oxygen atoms. From the periodic table, we see the atomic weight of hydrogen is 1.0079 and the atomic weight of oxygen is 15.9994.
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What is the specific heat of a metal with a mass of 14.0 g, heat of 3.45 kJ and a change in temperature of 6.2 ?
Answer:
Explanation:
0.0
In nature, Chlorine-35 isotopes (35 amu) make up 75
% of all chlorine. Chlorine-37 (37 amu) isotopes make
up 25 % of all chlorine,
Show your calculation for the AVG. Atomic Mass of
chlorine:
Water
(liquid)
Pressure (atm)
1
05-
025-
Ice
( (solid)
Water vapor
(gas)
10
101
100
Temperature (°C)
What do the sections between the lines on a phase diagram represent?
A. The regions in which temperature and pressure change a
substance's phase
B. The conditions in which a substance exists in a certain phase
C. The ranges where temperature and pressure are constant in a
substance
D. The areas in which the kinetic energy of a substance is constant
Answer:A
Explanation:
Some groups have names. Enter the number-letter version of the group number for each of these named groups. Be sure to include the number and letter.
a) Alkali metals:
b) Alkaline earth metals
c) Halogens
d) Noble gases 8.
The groups are alkali metals (I), alkaline earth metal (II) , Halogen (VII), and noble gases (VIII).
What is group?The representative elements, also known as the primary group elements, are found in Group A. As a result, the columns beginning with A (IA through VIIIA) are referred to as the primary group elements. The periodic table's columns were referred to as groups.
Alkali metals belongs to group (I).Alkaline earth metals belongs to group (II).Halogens belongs to group (VII).Noble gases belongs to group (VIII)To know more about group.
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solve it and get 50 points
Answer:
Not sure but I think it is C!
Explanation:
The study of Environmental Science includes which of the following?
A.)human biology
B.)the relationship between the Earth and the moon
C.)interactions between humans and living and non-living things in the environment
D.)the study of organisms living in the ocean
Answer:
Hi, There! the Correct Answer is below!
C.)interactions between humans and living and non-living things in the environment
Explanation:
Environmental scientists study subjects like the understanding of earth processes, evaluating alternative energy systems, pollution control and mitigation, natural resource management, and the effects of global climate change. ... Environmental scientists bring a systems approach to the analysis of environmental problems.
____________________________________________________________
Have a wonderful Day :)
~Darkspirit~
Answer:
interactions between human and living and non living things in the environment
please help me with this question i put 100 points on it and i will give brainlyest no links or files or i will report
The Earth’s tilt changes its position relative to the stars and constellations as the Earth rotates around its axis.
Which of the following is the correct net ionic equation for the formation of barium sulfate?
O B2+(aq) + SO42- (aq) → BaSO4 (s)
Ba2+(aq) + S2(aq) → Bas(s)
Be2+ (aq) + S042(aq) → BeSO4 (5)
Ba2+(aq) + SO42 (aq) → BaSO4 (5)
Answer:
Ba²+ (aq) + SO4²- (aq) --> BaSO4(s)
The net ionic equation for the formation of barium sulphate is Ba²⁺₍aq₎ + SO₄² ₍aq₎ → BaSO₄₍s₎. Therefore, option D is correct.
What is barium sulphate ?The inorganic substance having the chemical formula BaSO₄ is called barium sulfate. It is a tasteless, crystalline white substance that is insoluble in water. The main commercial source of barium and the materials made from it is the mineral barite, which is where it naturally occurs.
The use of barium sulfate aids in the diagnosis or discovery of issues with the esophagus, stomach, and bowels. It is a contrast material for radiography. To make the various bodily components clearly visible, contrast chemicals are used.
A barite-derived metallic compound with a silvery white color. In barium swallows and barium enemas, it is diluted with water to aid visualize the digestive tract on an x-ray.
Thus, option D is correct.
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If you wanted to increase the speed of
vaporization, you could
A. put the substance in the freezer.
B. place a lid on the substance.
C. heat the substance to the boiling point.
D. cool the substance to the freezing point.
>
Copyright © 2003 - 2021 Acellus Corporation. All Rights Reserved.
Answer:
C. heat the substance to the boiling point.
Answer:
heat the substance
Explanation:
How many grams of Co, are produced when 3.60 g of Fe 0 reacts with excess CO?
Fe2O3 + CO -> Fe + CO2
Answer:
2.98 g CO2
Explanation:
1. Balance the chemical equation
1 Fe2O3 + 3CO -> 2Fe + 3CO2
2. Use periodic table to find mass from each CO2 and Fe2O3
3. Calculate
3.60 g Fe2O3 x [tex]\frac{1 mol Fe2O3}{159.69 g Fe2O3}x\frac{3 mol CO2}{1 mol Fe2O3}[/tex] x[tex]\frac{44.01 g CO2}{1 mol CO2}[/tex] = 2.98 g CO2
The grams of CO, produced when 3.60 g of Fe 0 reacts with excess CO is 2.98 grams Co2.
What is mass?Mass is the quantity of matter of a physical body.
The balanced equation is
[tex]\rm Fe_2O_3 + CO - > Fe + CO_2[/tex]
The calculation is
[tex]3.60 g \;Fe_2O_3 \times \dfrac{ 1 mol\;Fe_2O_3}{159.69} \times \dfrac{3 mol CO_2}{1 mol \;Fe_2O_3 } \times \dfrac{44.01\;CO_2}{1 mol\; CO_2} = 2.98 g\;CO_2[/tex]
Thus, the grams of CO, produced when 3.60 g of Fe 0 reacts with excess CO is 2.98 grams Co2.
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draw the atomic structure of 10 elements and show Electronic configuration.......
Answer:
ज
Explanation:
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Is NaClO4/HClO4 a buffer system
Answer:
In this type of solution, perchloric acid is a strong acid which means that its conjugate base is extremely weak. As such, the solution of HClO4 H C l O 4 and NaClO4 N a C l O 4 is not a buffer solution.
Oceanography does not include the study of which of the following topics?
A.the relationship between the Sun, Moon, and Earth
B.the relationship between the atmosphere, Earth, and the oceans
C.the Earth's oceans
D.the plants and animals that live in the oceans
Answer:
A. The relationship between the Sun,Moon,and Earth
Explanation:
7. Which of the following is not part of the proper protocol for using acids and bases?
A. Wearing protective clothing while handling
B. Storing acids and bases below 10°C
O C. Storing acids and bases in separate areas
D. Add acid to water, not water to acid
Answer:
D. Add acid to water, not water to acid
PLEASE ANSWER!!!!!!! 80 POINTS
Which statement describes the properties of lanthanoids and actinoids?(1 point)
A. They are malleable and lustrous, and they tend to conduct both electricity and thermal energy.
B. They are brittle and dull, and they tend to conduct both electricity and thermal energy.
C. They are brittle and dull, and they tend to be poor conductors of both electricity and thermal energy.
D. They are malleable and lustrous, and they tend to be poor conductors of both electricity and thermal energy.
Lanthanoids and actinoids are transition elements of the periodic table. These elements are lustrous and malleable and can conduct thermal energy and electricity. Thus, option A is correct.
What are lanthanoids and actinoids?Lanthanoids and actinoids are the terms used to refer to the elements of the f-block of the periodic table that are placed separately due to the difference in their electronic structures.
These elements show the property somewhat similar to that of the metals and hence are lustrous and malleable. Due to the transition electron phase, they are used in optical devices and cardiac pacemakers.
The lanthanoids and actinoids are good conductors of heat and electricity as their electrons can be transferred and carry charges like metals.
Therefore, option A. the lanthanoids and actinoids are conductors and are malleable.
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I want the solve of this problem
Answer:
the answer of this question is B
What is Displacement reaction . Explain with an example.
Explanation:
A displacement reaction is the one wherein the atom or a set of atoms is displaced by another atom in a molecule. For instance, when iron is added to a copper sulphate solution, it displaces the copper metal. A + B-C → A-C + B.
What is the correct clases for this drugs
Promethazine
heelp me please
Answer:
MedlinePlus Drugs Information
Explanation:
Promethazine is in a class of medication called phenothiazines
What are the products of combining iron (II) and Copper (II) oxide in a Chemical reaction?
oxide in a chemical reaction
CuFe2O4 are the products of combining iron (II) and Copper (II) oxide in a Chemical reaction.
What is chemical reaction?The conversion of one or more chemicals into new one or more chemicals is called chemical reaction.
Example: iron reacts with oxygen to form rust.
What is product?The final substance of chemical reaction is called product.
Example: CuFe2O4 is the final substance called product when iron (II) and Copper (II) oxide react with each other.
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What is the systematic name of the following compound?
Li2S
Choose 1 answer:
А
Lithium sulfate
B В
Lithium sulfide
Dilithium sulfate
Dilithium sulfide
Explanation:
Lithium sulfide
if my answer helps you than mark me as brainliest.
* The 'emf generated by
a copper-constantan thermometer is 15 mv. If the cold junction is at a temperature of 20 degrees celcius.Calculate the temperature of the hot junction when sensitivity
of the thermocouple is 0.03mv/degree celcius
Thermometers are used to measure temperatures. The temperature of the hot junction of the thermocouple is [tex]520^oC[/tex]
Given that:
[tex]EMF = 15mv[/tex]
[tex]T_1 =20^oC[/tex] --- Temperature at cold junction
[tex]s = 0.03mv/^oC[/tex] ---- Sensitivity
The temperature [tex]T_2[/tex] at the hot junction is calculated as follows:
[tex]T_2 = \frac{EMF}{s} + T_1[/tex]
So, we have:
[tex]T_2 = \frac{15mv}{0.03mv/^oC} + 20^oC[/tex]
[tex]T_2 = \frac{15}{0.03/^oC} + 20^oC[/tex]
[tex]T_2 = \frac{15}{0.03}^oC + 20^oC[/tex]
[tex]T_2 = 500^oC + 20^oC[/tex]
[tex]T_2 = 520^oC[/tex]
Hence, the temperature of the hot junction of the thermocouple is [tex]520^oC[/tex]
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A student wants to do a scientific research on how a nuclear fusion can be used as a power source on earth. What type of scientist does the student want to become?
A nuclear scientist because they are more focused on extracting the nuclear energy of atoms.
Ammonia is produced by the reaction of nitrogen and hydrogen according to the equation
N2(g) + 3H2(g) → 2NH3(g)
Calculate the mass of ammonia produced when 27.0 g of nitrogen react with 12.0 g of hydrogen.
g NH3
Which is the excess reactant and how much of it will be left over when the reaction is complete?
Explanation:
Ammonia is produced by the reaction of nitrogen and hydrogen according to the equation
N2(g) + 3H2(g) → 2NH3(g)
Calculate the mass of ammonia produced when 27.0 g of nitrogen react with 12.0 g of hydrogen.
g NH3
Which is the excess reactant and how much of it will be left over when the reaction is complete?