The volume of gas occupied by 11 grams of nitrogen dioxide gas at STP is 5.15 L.
What is the ideal gas equation?Ideal gas equation of any gas will be writen as:
PV = nRT, where
P = standard pressure = 1 atm
V = volume = ?
R = universal gas constant = 0.082 L.atm/K.mol
T = standard temperature = 273K
n is the moles of gas which can be calculated by using below equation as:
n = W/M, where
W = given mass = 11g
M = molar mass = 46 g/mol
n = 11 / 46 = 0.239mol
On putting values on the above equation, we get
V = (0.23)(0.082)(273) / (1) = 5.15 L
Hence required volume of gas is 5.15 L.
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what would be the mass of 4.640 x 10^21 particles of aluminum
One mole of aluminum contains 6.02 × 10²³ Al particles. One mole of Al weighs 27 g. Hence 4.60 × 10²¹ Al particles or 0.007 moles weighs 0.208 g.
What is one mole ?One mole of a substance is its amount containing 6.02 × 10²³ atoms or molecules. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.
Similarly one mole of every compound contains 6.02 × 10²³ molecules. The mass of one mole of compound is called its molar mass. Similarly mass of one mole of an element is called its atomic mass.
Al is 13th element in periodic table. Al is a metal. One mole of Al contains 6.02 × 10²³ Al atoms . Hence number of moles of 4.60 × 10²¹ Al particles is:
4.60 × 10²¹/ 6.02 × 10²³ = 0.0077 .
atomic mass of Al = 27 g/mol.
Then mass of 0.0077 moles = 0.0077 × 27 = 0.208 g
Therefore, the mass of 4.60 × 10²¹ Al particles is 0.208 g.
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what foods can be stored in water and or ice
How many significant digits are in the following:
pH 7.02
Answer:
3
Explanation:
7.02 three sig digits
Which adaptation do polar bears and camels have in common?
A. Thick layer of body fat for food storage and insulation.
B. A small surface area to volume to reduce heat loss.
C. Thin fur and little body fat.
D. Large feet to spread body weight.
Answer:
Thick layer of body fat for food storage and insulation
Explanation:
Polar bears store food for themselves and so do camels. Option B is not correct because bears do not definitely have small surface area and even if camels do they do not need to reduce heat loss because they stay in the deserts. For option C polar bears have thick fur and much body fat to protect itself from the cold. Lastly D cannot be true because camels don't normally have large feet they have small padded foot.
Where would the points for 1-pentene be
expected to fall?
according to newtons second law of motion,what is force equal to?
Answer:
This isn't chemistry but the answer is Force = mass x acceleration
In a neutralization reaction 30.0mL of 0.234M KOH solution is reacted with 30.0mL of 0.234M HNO3 solution and a temperature rise of 5.6C was observed. Density of base and acid=1.00g/mL and the specific heat of the mixture is 4.18j/g•C
a) write the balanced equation of the reaction
b) calculate the moles of water produced
c) calculate the total heat produced
d) calculate the enthalpy of neutralization of the reaction
Based on the data provided, the equation of the reaction is:
[tex]KOH + HNO_3 \rightarrow KCl + H_2O[/tex]moles of water produced = 0.00702 molesHeat produced = 1404.48 JEnthalpy of neutralization = 200 kJ/molWhat is enthalpy of neutralization?Enthalpy of neutralization is the heat change when one mole of hydrogen ions from an acid reacts with one mole of hydroxide ions from an alkali to produce one mole of water.
The equation of the reaction of KOH and HNO3 is given below:
[tex]KOH + HNO_3 \rightarrow KCl + H_2O[/tex]
1 mole of KOH reacts with 1 mole of HNO3 to produce 1 mole of water.
Volume of KOH = 30 mL = 0.03 L
moles of KOH = 0.03 × 0.234 = 0.00702 moles
Therefore, 0.00702 moles of water are produced
Heat produce = mass × specific heat × temperature difference
Volume of solution = 60 mL
density of solution = 1.0 g/mL
mass of solution = 60 mL × 1.0 g/mL = 60 g
Heat produced = 60 × 4.18 × 5.6
Heat produced = 1404.48 J
Enthalpy of neutralization = 1404.48 J/0.00702 moles
Enthalpy of neutralization = 200068.37 J/mol
Enthalpy of neutralization = 200 kJ/mol
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Write two half‑reactions to describe each of these metal displacement reactions. Include phase symbols.
Mg(s)+CoBr2(aq)⟶MgBr2(aq)+Co(s)
oxidation half‑reaction:
reduction half‑reaction:
Cu(s)+2AuCl(aq)⟶CuCl2(aq)+2Au(s)
oxidation half‑reaction:
reduction half‑reaction:
In redox reactions, an oxidation half reaction shows the oxusetoon occurring while the reduction half reaction shows the reduction occurring in the overall reaction.
What are redox reactions?Redox reactions are reactions in which oxidation and reduction reactions occur together to the same extent.
A redox reaction can be split into two half oxidation and reduction reactions.
The half reactions of the given reactions are shown below:
Overall reaction;
[tex]A. Mg(s) + CoBr_2(aq) ⟶ MgBr_2(aq) + Co(s) \\ [/tex]
Oxidation half reaction:
[tex]Mg (s) ---> Mg ^{2+}(aq)[/tex]
Reduction half reaction:
[tex]Co^{2+} (aq) ---> Co (s)[/tex]
B. Overall reaction
[tex]Cu(s) + 2AuCl(aq) ⟶ CuCl_2(aq) + 2Au(s) \\ [/tex]
Oxidation half reaction:
[tex]Cu(s) ---> Cu^{2+}(aq)[/tex]
Reduction half reaction:
[tex]2Au^{+}(aq) ---> 2 Au (s)[/tex]
Therefore, redox equations can be spilt into oxidation and reduction half reactions.
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The Ksp of scandium fluoride, ScF3, is 5.81×10−24. Calculate the molar solubility ,s, of this compound.
The Ksp shows the extent of solubility of a substance in another. The solubility of the compound is 1.2 * 10^-7 M.
What is solubility?The term solubility shows the extent to which a substance dissolve in solution. The solubility of a substance is often typified by the Ksp of the substance.
Now;
ScF3(s) ⇄Sc^+(aq) + 3F^-
Ksp = [Sc^+] [F^-]^3
Ksp = x (3x)^3
Ksp = 27x^4
x = 4√5.81×10^−24/27
x = 1.2 * 10^-7 M
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Listed below are the step equations for the reaction in which sulfur dioxide (SO2) and hydrogen disulfide (H2S) react to produce sulfur and water. Write the balanced target equation and use Hess’s law to calculate the ΔH of this reaction.
SO2 (g) → S (s) + O2 (g) ΔH = +300.1 kJ
H2 (g) + S (s) → H2S (g) ΔH = –19.5 kJ
H2 (g) + O2 (g) → H2O (g) ΔH = –290.1 kJ
Based on Hess law, the enthalpy change, ΔH of the reaction is +48.9 kJ.
What is the equation of the reaction?The equation of the reaction of sulfur dioxide (SO2) and hydrogen disulfide (H2S) to produce sulfur and water is given below:
[tex]SO_2 + 2H_2S \rightarrow 3S + 2H_2O[/tex]
The ΔH of the reaction is calculated from the summation of the ΔH of the intermediate reactions according to Hess law.
SO2 (g) → S (s) + O2 (g) ΔH1 = +300.1 kJ
H2 (g) + S (s) → H2S (g) ΔH2 = –19.5 kJ
2H2 (g) + O2 (g) → 2H2O (g) ΔH3 = –290.1 kJ
ΔH of the reaction = ΔH1 + 2(-ΔH2) + ΔH3
ΔH of the reaction = 300 + 2 × -(-19.5) + (-290.1)
ΔH of the reaction = +48.9 kJ
Therefore, the ΔH of the reaction is +48.9 kJ.
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I really need to know the answer it will help
Answer:
so the answer is A 5.199mol please. rate. me brainliest. if its. correct
Explanation:
N=nL
[tex]3.131 \times {10}^{24} = n \times 6.022 \times {10}^{23} \\n = \frac{3.131 \times {10}^{24} }{6.022 \times {10}^{23} } \\ n = 5.199mol[/tex]
Calculate the molarity of a solution prepared by diluting 7.0 mL of 4.0 M solution to a volume of 30 mL. Select the correct answer below: 0.76 M 0.87 M 0.93 M 1.02 M
Answer:
0.93 M
Explanation:
Molarity = [tex]\frac{Moles}{Volume}[/tex]
4.0M = [tex]\frac{x}{0.007 L}[/tex]
4.0 M x 0.007 L = Moles = 0.028
Molarity = [tex]\frac{Moles}{Volume}[/tex]
Molarity = [tex]\frac{0.028 moles}{0.03 L}[/tex]
= 0.93 M
Covalent bonding involves the sharing of electrons to create a full valence shell, and
occurs between nonmetals.
True
False
Elements in which family would require the least amount of ionization energy (the
amount of energy used to take away an electron)?
transition metals
Alkali metals
Alkaline earth metals
Alkali metals require least amount of ionization energy.
Peaky Blinder fan? haha
I will mark as brainiest or what ever its called lol. Please helpp
Answer:
A - Cinder cone
B - Shield
C - Composite
Explanation:
Cinder cone volcanoes are formed when the volcano explodes and all the lava soldifies and falls steeply upon the sides of the mountain and forms cinders.
Shield volcanoes form when a centralized vent produces low-viscosity flows over a long period of time
Composite volcanoes are also called stratovolcanoes. They form when different types of eruptions deposit different materials around the sides of a volcano. Alternating eruptions of volcanic ash and lava cause layers to form. Over time these layers build up.
Answer:
Answer:A - Cinder coneB - Shield C - CompositeExplanation:Cinder cone volcanoes are formed when the volcano explodes and all the lava soldifies and falls steeply upon the sides of the mountain and forms cinders. Shield volcanoes form when a centralized vent produces low-viscosity flows over a long period of time Composite volcanoes are also called stratovolcanoes. They form when different types of eruptions deposit different materials around the sides of a volcano. Alternating eruptions of volcanic ash and lava cause layers to form. Over time these layers build up.:
What is bee venom an example of?
O nucleic acid
O carbohydrate
O fat
O protein
Answer:
O protein
Explanation:
Bee venom (BV) is a complex mixture of proteins and contains proteins such as phospholipase and melittin, which have an effect on blood clotting and blood clots.
HGD
When a thermometer is suspended in an insulated thermos that contain a block of ice, the temperature recorded on the thermometer drops. Describe the direction of heat flow.
The heat flows from inside to the outside direction because of lowering of temperature inside the thermos.
How the temperature of ice drops?When a thermometer is suspended in an insulated thermos that contain a block of ice, the temperature recorded on the thermometer drops, the direction of heat flow is from inside to the outside the thermos. This is because of the insulating material in which the ice is kept and the lowering of the temperature.
So we can conclude that the heat flows from inside to the outside direction because of lowering of temperature inside the thermos.
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if you were to engineer an everyday solution for conserving water which activity do you think would be the most impactful ?
A solution contains an unknown amount of dissolved magnesium. Addition of
0.0877 mol of Na2CO3 causes complete precipitation of all of the magnesium.
What mass of magnesium was dissolved in the solution?
Taking into account the reaction stoichiometry, 2.13 grams of magnesium was dissolved in the solution.
Reaction stoichiometryIn first place, the balanced reaction is:
Mg²⁺(aq) + Na₂CO₃(aq) → MgCO₃(s) + 2 Na⁺(aq)
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Mg²⁺: 1 mole Na₂CO₃: 1 moleMgCO₃: 1 moleNa⁺: 2 molesThe molar mass of the compounds is:
Mg²⁺: 24.3 g/moleNa₂CO₃: 106 g/moleMgCO₃: 84.3 g/moleNa⁺: 23 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Mg²⁺: 1 mole ×24.3 g/mole= 24.3 gramsNa₂CO₃: 1 mole ×106 g/mole= 106 gramsMgCO₃: 1 mole ×84.3 g/mole=84.3 gramsNa⁺: 2 moles ×23 g/mole= 46 gramsMass of magnesium dissolvedThe following rule of three can be applied: If by reaction stoichiometry 1 mole of Na₂CO₃ react with 24.3 grams of magnesium, 0.0877 moles of Na₂CO₃ react with how much mass of magnesium?
[tex]mass of magnesium=\frac{0.0877 moles of Na_{2}C O_{3}x24.3 grams of magnesium }{1 mole of Na_{2}C O_{3}}[/tex]
mass of magnesium= 2.13 grams
Finally, 2.13 grams of magnesium was dissolved in the solution.
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A laboratory group measures an excess of a volatile liquid. They add this to an empty flask with a volume of 66 mL. They heat the sample to 86.9 degrees Celcius until all the liquid is vaporized. The pressure in the lab is 0.987 atm. If 0.287 grams of volatile liquid were left in the flask, what was the molar mass of the compound?
Answer:
130.159
Explanation:
P=0.987
V=66ml =66/1000=0.066 L
n/moles= ?
R=0.08206
T=86.9+273.15=360.5 K
Formula PV=RnT
n =PV/TR
n=(0.987 * 0.066)/(360.05 * 0.08206) = 0.002205
Now to obtain molar mass you divide grams by mol.
0.287/0.002205 = 130.159
Silver chromate is sparingly soluble in aqueous solutions. The sp of Ag2CrO4 is 1.12×10−12.
What is the solubility (in mol/L) of silver chromate in 1.20 M potassium chromate aqueous solution?
What is the solubility (in mol/L) of silver chromate in 1.20 M silver nitrate aqueous solution?
What is the solubility (in mol/L) of silver chromate in pure water?
The solubility (in mol/L) of silver chromate in 1.20 M in potassium chromate, silver nitrate and in pure water is
X = 5.0*10^-7 MX'' = 8.333*10^-13 MX'''= 6.694*10^-5 MThis is further explained below
What is the solubility (in mol/L) of silver chromate in 1.20 M potassium chromate aqueous solution?Generally,The Chemical reaction is
Ag2CrO4 <----> 2 Ag+ + CrO42-
Ksp = [Ag+]^2[CrO42-]
1.12×10−12 = [Ag+]^2[CrO42-]
Hence
1.12×10−12.=(2X)^2*(1.2)
X = 5.0*10^-7 M
b)
1.12×10−12=(1.2)^2*(X)
1.12×10−12= 1.44 * 1(X)^1
X'' = 8.333*10^-13 M
In conclusion
1.12×10−12=(2X)^2*(s)
1.12×10−12= 4(X)^3
X'''= 6.694*10^-5 M
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A student places a 50.0 g sample of a metal at 96.8° C into a calorimeter full of 100.0 g of
water (specific heat of water = 4.18 J/g°C). The water, initially at 22.0 °C, eventually
comes to a temperature of 25.9 °C. Calculate the heat gained by the water.
Answer:
1630.2 j
Explanation:
100 gm * 4.18 J/gm-C * ( 25.9-22 C ) = 1630.2 j
4.55 Classify the following redox reactions. (a) 2H2O2 ⟶ 2H2O + O2 (b) Mg + 2AgNO3 ⟶ Mg(NO3)2 + 2Ag (c) NH4NO2 ⟶ N2 + 2H2O (d) H2 + Br2 ⟶ 2HBr
The following redox reactions are classify as:
(a) 2H₂O₂ ⟶ 2H₂O + O₂: Disproportionation reaction (redox)
(b) Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag: Single displacement reaction (redox)
(c) NH₄NO₂ ⟶ N₂ + 2H₂O: Decomposition reaction (redox)
(d) H₂ + Br₂ ⟶ 2HBr: Combination reaction (redox)
(a) 2H₂O₂ ⟶ 2H₂O + O₂
This reaction involves hydrogen peroxide (H₂O₂) breaking down into water (H₂O) and oxygen gas (O₂). The oxidation state of oxygen in hydrogen peroxide is -1, and in water, it is -2. Oxygen in oxygen gas has an oxidation state of 0. Therefore, oxygen is being reduced from -1 to 0. The oxidation state of hydrogen remains +1 in H₂O₂ and H₂O. Since one element (oxygen) is reduced and the other (hydrogen) remains unchanged, this is a disproportionation reaction (a type of redox reaction).
(b) Mg + 2AgNO₃ ⟶ Mg(NO₃)₂ + 2Ag
In this reaction, magnesium (Mg) reacts with silver nitrate (AgNO₃) to form magnesium nitrate (Mg(NO₃)₂) and silver (Ag). The oxidation state of magnesium changes from 0 to +2 in Mg(NO₃)₂, while the oxidation state of silver changes from +1 in AgNO₃ to 0 in Ag. This is a single displacement reaction (a type of redox reaction) because one element (magnesium) displaces another (silver) in the compound.
(c) NH₄NO₂ ⟶ N₂ + 2H₂O
This reaction involves ammonium nitrite (NH₄NO₂) decomposing into nitrogen gas (N₂) and water (H₂O). The oxidation state of nitrogen in NH₄NO₂ is +3, and in nitrogen gas (N₂), it is 0. The oxidation state of hydrogen changes from +1 in NH₄NO₂ to +1 in H₂O. Since nitrogen is being reduced from +3 to 0, and hydrogen remains unchanged, this is a decomposition redox reaction.
(d) H₂ + Br₂ ⟶ 2HBr
In this reaction, hydrogen gas (H₂) reacts with bromine gas (Br₂) to form hydrogen bromide (HBr). The oxidation state of hydrogen changes from 0 in H₂ to +1 in HBr, while the oxidation state of bromine changes from 0 in Br₂ to -1 in HBr. This is a combination reaction (a type of redox reaction) because two elements (hydrogen and bromine) combine to form a compound (hydrogen bromide), and their oxidation states change during the reaction.
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Soil that are light in color have a great amount of humus in
them. True or False
Answer:
please the answer Is false
This adaptation allows the panda to perform which activity?
A
Grasping
B
Running
C
Scratching
D
Throwing
Answer:
A grasping :)
Explanation:
The panda uses the "thumb" to grab onto bamboo to eat! Without this, the panda would not be able to eat the bamboo!
Have an amazing day!!
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A 0.250 mol sample of gas at 35.0°C exerts a pressure of 700 torr in it's container. What pressure will the container exert if the volume expands to 10.0L and the temperature is cooled to 5.0°C?
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2 pts
IN
Question 1
Determine Pxe in a container that has the following gases and respective pressures:
Gas
Pressure (kPa)
Xenon
?
Helium
77.3
Nitrogen dioxide
52.0
TOTAL
248.8
From the total pressure of the gaseous mixture, the partial pressure of xenon is 119.5 kPa
What is partial pressure of a gas?The partial pressure of a gas is the pressure that gas exerts when it is part of a mixture of gases which did not chemically react together.
The sum of the partial pressure of each gas in the mixture gives the total pressure.
In the gaseous mixtures above:
Total pressure = 248.8 kPa
Partial pressure of xenon = Total pressure - (Sum of partial pressure of the other gases)
Partial pressure of xenon = 248.8 - (77.3 + 52.0)
Partial pressure of xenon = 119.5
Therefore, the partial pressure of xenon is 119.5 kPa.
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PLEASEEEEE HELP
1 Explain why decan-1-ol CH,(CH,) CH,OH has
only limited solubility in water, whereas ethanol
CH,CH,OH is miscible with water in all proportions.
2 Give details of the reagents and the practical
procedures required to prepare each of the following
substances from a named alcohol:
a 1-Chloropropane
b 2-Bromopropane.
3 Explain why sodium metal reacts more slowly with
ethanol CH,CH,OH than with water HOH.
4 Draw Lewis structures to show the formation of the
ethoxide ion by the action of sodium on ethanol.
Answer:
Can you arrange it? I don't understand
what is mass ? give two examples
mass it the amount of matter present in any object or body. Everything we see around us has mass. For example, a table, a chair, your bed, a football, a glass, and even air has mass.
Do the reactants or the product have greater potential energy
Answer:
the reactants have more potential energy than the products have. The extra energy is released to the surroundings.