what is the translation from quadrilateral EFGH to quadrilateral E' F'G'H'

Answer:

Range:-4 is less then Y is less then 9. Domain: -5 is less then x is less then 4

Step-by-step explanation:

Look at where the lines end. That will help you find where the domain and ranges are.

Answer:

3,7 is correct like the other person said

Answer:

The eagle by 130 feet

Step-by-step explanation:

you plug it in and then find the difference

Expand the target expression:

A sin(x + ϕ) = A (sin(x) cos(ϕ) + cos(x) sin(ϕ)) = -2 sin(x) + 4 cos(x)

Then we have

A cos(ϕ) = -2

A sin(ϕ) = 4

Recall that sin²(x) + cos²(x) = 1 for all x. Then

(A cos(ϕ))² + (A sin(ϕ))² = (-2)² + 4²

A² (cos²(ϕ) + sin²(ϕ)) = 4 + 16

A² = 20

A = √20 = 2√5

Also recall that tan(x) = sin(x)/cos(x) by definition. Then

(A sin(ϕ)) / (A cos(ϕ)) = 4 / (-2)

tan(ϕ) = -2

ϕ = arctan(-2) = -arctan(2)

The area of a trapezium with the given dimensions is: 198 cm²

Area of a trapezium = 1/2(a + b)h, where h is the heght of the trapezium and a and b are the length of its bases.

Given the following:

Area of a trapezium = 1/2(12 + 21)12

Area of a trapezium = 198 cm²

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Answer:

the patters is that they are multiple of 7.. so next number is 42.

which means option D The missing number is even is correct..

The value of b for the quadratic equation x2 bx 5 = 0 to have two real number solutions is -5.

The standard form of the quadratic equation is,

[tex]ax^2+bx+c=0[/tex]

The quadratic equation has two real number solutions when the value of the following equation is positive.

[tex]b^2-4ac[/tex]

The quadratic equation given in the problem is,

[tex]x^2 +bx+ 5 = 0[/tex]

The value of b has to be found out such that the equation have two real number solutions. For this equation,

[tex]a=1\\c=5[/tex]

Put this value in the above equation as,

[tex]b^2-4\times1\times5\\b^2-20[/tex]

The value of the above expression to be positive, the value of b should be at least 5 or -5.

[tex](-5)^2-20\\25-20\\5[/tex]

Thus, the value of b for the quadratic equation x2 bx 5 = 0 to have two real number solutions is -5.

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Answer:

Which value of [tex]b[/tex] will cause the quadratic equation [tex]x^2 + bx + 5 = 0[/tex] to have two real number solutions?

B) -3

C) 3

D) 4

There one Thing That would got to 0 so it A) -5

Have a Nice Day .

Area of the figure is 171 cm²

See the attachment......

Area of triangle:-

Area of square:-

Area of rectangle:

Total:-

Answer:

Emmanuel will need 8 scoops to get 2 tablespoons

you need 12 1/2 tablespoons for 6 tablespoons

Step-by-step explanation:

Answer:

1.7507

Step-by-step explanation:

See Image

Answer:

OB. y= 3x - 14

Step-by-step explanation:

I'm not good at explaining, but I'm right.

Answer: Ken has 22 coins, some of which are dimes and the rest are quarters

Step-by-step explanation:Step 1. Let x be the number of dimes and let 25-x be the number of quarters.

Step 2. Let 0.10x be the total cost for x number of dimes

Step 3. Let 0.25(25-x) be the total cost for 25-x number of quarters.

Step 4. Since the man has $4.60, then 4.60=0.10x+0.25(25-x). Solving for x yields the following steps

Answer:

50 000

Step-by-step explanation:

5 x 10 000

Answer:

14 is the discount

56 is discounted price.

Answer:

Step-by-step explanation:

Let's solve for f.

fx=

1

3

x−2

Step 1: Divide both sides by x.

fx

x

=

1

3

x−2

x

f=

x−6

3x

Answer:

f=

x−6

3x

[tex]\dfrac{cd^4}{c^2 d^8}\\\\=c^{1-2} \cdot d^{4-8}\\\\=c^{-1} \cdot d^{-4}\\\\=\dfrac 1{c d^4}[/tex]

[tex]\text{Hence the answer is C.}[/tex]

Answer:

23.5

Step-by-step explanation:

So this is a parallelogram so the area formlula is b*h=47? That's a no go. It is saying that if the base is 1/4th and the height is increasing by 2 so basically 1/4b*2h=1/2bh bh so it will be represented as 47 so 1/2*47=23.5

Answer:

i think 31

Step-by-step explanation:

Answer:

If it is x squrared the answer would be (x+3)²+5. If it is 2 times x then it would be (2x+3)+5

Step-by-step explanation:

Answer:

Step-by-step explanation:

1 is in the tenth place

[tex]\sf 1's \ value = \dfrac{1}{10}[/tex]

Answer:

Step-by-step explanation:

(i) a^a + b^b

for a=3 and b= -2

3^3 + -2^(-2)

          -2^(-2) = -(1/2^2)

3^3  -(1/2^2)

27 - (1/4)

26 3/4

ii) a^b + b^a

a^b + b^a

for a=3 and b= -2

3^(-2) + (-2)^3

1/3^2 + (-2)(-2)(-2)

1/9 - 8

-7 8/9

Answer:

I didn't understood your question. But,

I×100/P×T

Step-by-step explanation:

I hope this is ur required answer

Pls do tell anything in comments regarding any doubt

Answer:

$52.5

Step-by-step explanation:

Since 25% is the sale, we subtract 100% (the whole) by the discount, 25%. That leads us to say that we are paying for 75% of the product's price.

We multiply $70 by 0.75 and you get $52.5!

Please mark brainiest if this helped you!

The answer I got was 88.

Steps: I multiplied 17 by 4 to get 68. Then times 5 by 4 then divided by 2 because it's a triangle then got 10. Do that again for other side and add them together to get 88.

Answer:

8xy³(2y²+7)

Step-by-step explanation:

[tex]( \frac{16 {x}^{2} \times 2 {y}^{5} }{4x {y}^{2} } + 28xy) \times 2 {y}^{2} \\ = (8x {y}^{3} + 28xy) \times 2 {y}^{2} \\ = (4xy(2 {y}^{2} + 7)) \times 2 {y}^{2} \\ = 8x {y}^{3} (2 {y}^{2} + 7)[/tex]

Tamora’s total finance charge was $3,403.53 if Tamora paid in addition of $939.25 in service charges option (c) is correct.

It is defined as the interest on the principal value or deposit and the interest which is gained on the principal value in the previous year.

We have:

Principal amount(Loan principal) = $10,675

Interest rate  = 4.75 %

Monthly rate = 4.75/12% ⇒0.39583% ⇒ 0.00395

Additional amount she paid in service charge = $939.25

Number of months = 9×12 = 108 months

We can find the total finance charge as follows:

Finance charge = Total amount repaid +service charge - Loan principal

The formula for the monthly payment of the loan is given by:

[tex]\rm Monthly \ payment = \frac{Loan \ principal }{\frac{(1-(1+r)^-^n)}{r} }[/tex]

[tex]\rm Monthly \ payment = \frac{10675}{\frac{(1-(1+0.00395)^-^{108})}{0.00395} }[/tex]    

After calculating, we get:

Monthly payment = $121.66

For 108 months, Tamora paid:

= 121.66×108

= $13,139.23

The finance charge will be:

= $13,139.23+$939.25-$10,675

= $3,403.53

Thus, Tamora’s total finance charge was $3,403.53 if Tamora paid in addition of $939.25 in service charges option (c) is correct.

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