What is the major organic product in the following reaction sequence? Type it’s systematic IUPAC name in the box below

The vapor pressure of the solution at 30°C is 0.9676781. The pressure that a vapor exerts on its condensed phases (solid or liquid) in a closed system at a specific temperature is known as vapor pressure.

The pressure of the solvent above the solution is known as the vapour pressure of a solution. Temperature, ambient pressure, and solute concentration all have an impact on a solution's vapour pressure. A manometer or a barometer can be used to determine a solution's vapour pressure. When a liquid is contained in a closed container, its molecules frequently crash into the walls of the container. Due to these collisions, the container's walls experience pressure equal to the liquid's vapour pressure.

Solution of P = (0.9677 x 31.8 mmHg)

P solution = 30.8 mmHg

X Solvent = 34.63588 mol/1.156 + 34.635

X Solvent = 0.9676781

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Answer:

To lower the impacts of climate change, we can undertake the following activities:

Invest in low-carbon technologies: Utilize renewable energy sources such as solar panels, tidal energy, wind, wave, and geothermal power to reduce greenhouse gas emissions and minimize our reliance on fossil fuels.

Improve transportation: Opt for fuel-efficient cars, electric vehicles, and better public transport systems to reduce CO2 emissions and pollution.

Adopt sustainable diets: Shift towards plant-based diets, reduce meat and dairy consumption, and support sustainable farming practices to help mitigate climate change.

Restore nature: Plant trees, engage in rewilding schemes, and protect forests and oceans to increase their natural ability to absorb carbon dioxide.

Reduce consumption and waste: Minimize consumption of energy-intensive products, reduce plastic use, and adopt energy-efficient practices in homes, such as insulating walls and roofs and using heat pumps.

The numerical value of Kc for this reaction is 0.0804 if a 2.00 mol sample of A is sealed in a 1.00 L flask and allowed to reach equilibrium with B and C. The equilibrium concentration of B is found to be 0.39 M.

The equilibrium constant expression for the reaction A (g) ⇔ B (g) + C (g) is:

Kc = [B] [C] / [A]

where [A], [B], and [C] are the molar concentrations of A, B, and C at equilibrium, respectively.

We are given that the equilibrium concentration of B is 0.39 M. However, we are not given the equilibrium concentration of A or C. To solve for Kc, we need to find the equilibrium concentrations of all three species.

Since the reaction is in a 1.00 L flask and we started with a 2.00 mol sample of A, the initial concentration of A is 2.00 M. At equilibrium, the concentration of A will be equal to (2.00 - [B]) M, and the concentration of C will also be equal to [B] M (because the stoichiometric coefficients for B and C are equal).

Substituting these values into the equilibrium constant expression, we get:

Kc = (0.39 M)^2 / (2.00 M - 0.39 M) = 0.0804

Therefore, the numerical value of Kc for this reaction is 0.0804.

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Layer 1 because it is closest to the surface

In comparison to the "P" alkalinity, the "T" alkalinity will be higher.

The "P" alkalinity of a sample is determined by the amount of hydrogen ions ([tex]H^+[/tex]) that are neutralized by the anions present. The "T" alkalinity of a sample is determined by the amount of hydroxide ions ([tex]OH^-[/tex]) that are neutralized by the cations present. In a sample where the only anion contributing to alkalinity is hydroxide ion, [tex]OH^-[/tex], the "P" alkalinity will be zero since there are no hydrogen ions ([tex]H^+[/tex]) to be neutralized. However, the "T" alkalinity will be equal to the amount of hydroxide ions ([tex]OH^-[/tex]) present since all of the [tex]OH^-[/tex] ions will be neutralized by the cations present. Therefore, in this case, the "T" alkalinity will be greater than the "P" alkalinity.

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Answer:

a. The chemical equation for the reaction between CaI2 and K2SO4 is:

CaI2 + K2SO4 → 2 KI + CaSO4

The solubility product constant (Ksp) for CaSO4 is 2.4 x 10^-5 at 25°C.

Using the Ksp expression for CaSO4, we can write:

Ksp = [Ca2+][SO42-]

Let x be the concentration of Ca2+ ions in the solution. Then, the concentration of SO42- ions will also be x, since the reaction is 1:1. Substituting into the Ksp expression, we get:

Ksp = x^2

Solving for x, we get:

x = sqrt(Ksp) = sqrt(2.4 x 10^-5) = 0.0049 M

Therefore, the minimum concentration of CaI2 needed to cause precipitation is 0.0049 M.

b. The chemical equation for the reaction between AgNO3 and RbCl is:

AgNO3 + RbCl → AgCl + RbNO3

The solubility product constant (Ksp) for AgCl is 1.8 x 10^-10 at 25°C.

Using the Ksp expression for AgCl, we can write:

Ksp = [Ag+][Cl-]

Let x be the concentration of Ag+ ions in the solution. Then, the concentration of Cl- ions will also be x, since the reaction is 1:1. Substituting into the Ksp expression, we get:

Ksp = x^2

Solving for x, we get:

x = sqrt(Ksp) = sqrt(1.8 x 10^-10) = 1.34 x 10^-5 M

Therefore, the minimum concentration of AgNO3 needed to cause precipitation is 1.34 x 10^-5 M.

Answer:

2.67 x 10^-4 M & 8.85 x 10^-8 M

Explanation:

The minimum concentration of the precipitating agent required to cause precipitation of the cation from the solution can be determined using the solubility product constant (Ksp) of the salt that would be formed. The Ksp is an equilibrium constant that represents the maximum amount of solid that can dissolve in water to form a saturated solution.

For part a, calcium iodide (CaI2) and potassium sulfate (K2SO4) are mixed. The reaction that occurs is:

CaI2(aq) + K2SO4(aq) → CaSO4(s) + 2KI(aq)

The solubility product constant for calcium sulfate (CaSO4) is 2.4 x 10^-5. Let x represent the minimum concentration of K2SO4 required to cause precipitation. The concentration of Ca2+ ions in solution is 9.0 x 10^-2 M. The Ksp expression for CaSO4 is:

Ksp = [Ca2+][SO42-]

Substituting the known values gives:

(2.4 x 10^-5) = (9.0 x 10^-2)(x)

Solving for x gives:

x = (2.4 x 10^-5)/(9.0 x 10^-2)

x = 2.67 x 10^-4 M

So, the minimum concentration of K2SO4 required to cause precipitation of CaSO4 is 2.67 x 10^-4 M.

For part b, silver nitrate (AgNO3) and rubidium chloride (RbCl) are mixed. The reaction that occurs is:

AgNO3(aq) + RbCl(aq) → AgCl(s) + RbNO3(aq)

The solubility product constant for silver chloride (AgCl) is 1.77 x 10^-10. Let y represent the minimum concentration of RbCl required to cause precipitation. The concentration of Ag+ ions in solution is 2.0 x 10^-3 M. The Ksp expression for AgCl is:

Ksp = [Ag+][Cl-]

Substituting the known values gives:

(1.77 x 10^-10) = (2.0 x 10^-3)(y)

Solving for y gives:

y = (1.77 x 10^-10)/(2.0 x 10^-3)

y = 8.85 x 10^-8 M

So, the minimum concentration of RbCl required to cause precipitation of AgCl is 8.85 x 10^-8 M.

An endothermic reaction absorbs heat from the surroundings, so heat is a reactant in this case. According to Le Chatelier's principle, when a system in equilibrium is subjected to a change, it will adjust to counteract that change and maintain equilibrium.

What is Endothermic Reaction?

An endothermic reaction is a chemical reaction that absorbs heat from its surroundings. In other words, the reaction requires energy in the form of heat to proceed, and the energy is absorbed from the surrounding environment, making it feel colder. Endothermic reactions usually have a positive enthalpy change, which means that the products have more energy than the reactants.

To shift the equilibrium of an endothermic reaction to the left, we need to remove heat, which can be achieved by decreasing the temperature. Therefore, the correct answer is (c) Decrease the temperature of the system.

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Answer:

the concentration of sodium nitrate in the solution is 0.470 M.

Explanation:

To calculate the concentration of sodium nitrate in the solution, we need to first convert the mass of solid sodium nitrate to moles. We can do this using the molar mass of NaNO3, which is 85.0 g/mol:

moles NaNO3 = mass NaNO3 / molar mass NaNO3

moles NaNO3 = 2.00 g / 85.0 g/mol

moles NaNO3 = 0.0235 mol

Next, we need to calculate the total volume of the solution in liters, since concentration is usually expressed in moles per liter (M):

volume solution = 50.0 mL / 1000 mL/L

volume solution = 0.0500 L

Finally, we can use the moles of sodium nitrate and the total volume of the solution to calculate the concentration in moles per liter:

[NaNO3] = moles NaNO3 / volume solution

[NaNO3] = 0.0235 mol / 0.0500 L

[NaNO3] = 0.470 M

Therefore, the concentration of sodium nitrate in the solution is 0.470 M.

Introduction: The formation of the solar system has been a subject of scientific inquiry for centuries. One of the most significant forces at play in the formation of the solar system is the law of universal gravitation.

This law states that every object in the universe attracts every other object with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. In this virtual lab, we will investigate the law of universal gravitation by manipulating the size of the star and the positions of planets within Solar System X.

Hypothesis:

As the size of the star in Solar System X increases, the gravitational force experienced by the planets will increase, causing them to move closer to the star. Additionally, as the distance between the planets and the star decreases, the gravitational force experienced by the planets will also increase, causing them to move faster around the star.

Materials

Computer with internet connection

Virtual lab software

Solar System X simulation

Procedure:

Open the virtual lab software and access the Solar System X simulation.

Set the size of the star to the smallest setting and record the positions of the planets.

Increase the size of the star to the next setting and record the new positions of the planets.

Repeat step 3 until the largest size of the star is reached.

Analyze the data and record observations.

Results:

As the size of the star in Solar System X increased, the gravitational force experienced by the planets also increased. This caused the planets to move closer to the star and move faster around it. Additionally, as the distance between the planets and the star decreased, the gravitational force experienced by the planets also increased, causing them to move faster around the star. These observations support the hypothesis that the law of universal gravitation plays a significant role in the formation and movement of planets in a solar system.

Conclusion:

The law of universal gravitation is a fundamental force that plays a significant role in the formation and movement of planets in a solar system. This virtual lab demonstrated the effects of manipulating the size of the star and the positions of planets within Solar System X on the gravitational force experienced by the planets. The results of the experiment supported the hypothesis that increasing the size of the star and decreasing the distance between the planets and the star increased the gravitational force experienced by the planets, causing them to move faster and closer to the star. These observations provide valuable insight into the forces at play in the formation and movement of our own solar system and those found throughout the universe.

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The correct conclusion is that the amount of water affects the mass and the height. This is evidenced by the data in the table, which shows that the plant in Pot B (which received more water) had more mass and was taller after 50 days of growth than the plant in Pot A.

Mass is a measure of the amount of matter an object contains. It is expressed in terms of a unit of measurement such as kilograms or pounds. Mass is different from weight, which is a measure of the force of gravity acting on an object. Mass is a constant, while weight can vary depending on the gravitational pull of the planet or other body on which the object is located. Mass is an intrinsic property of matter and is not affected by temperature or pressure. Mass is related to inertia, which is the resistance of an object to changes in its motion.

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Answer:

Ethane(C2H6) reacts with oxygen gas to produce carbon dioxide and water.

Answer:

Explanation:

Average Atomic Mass

In order to find the identity of the element, we must first find the average mass of all isotopes.

To do this, we multiply each mass by its percent abundance and add them together.

[tex](0.0435*49.9461)+(0.8379*51.9405)+(0.0950*52.9407)+(0.0236*53.9389)=51.9959[/tex]

51.9959 is the calculated average of the mass of each isotope.

Identity

Looking at a periodic table, this value for atomic mass most closely resembles the atomic mass of Chromium, which is 51.9961

The final balanced chemical equation is:

C₉H₂₀(l) + 14O₂(g) → 9CO₂(g) + 10H₂O(l)

A balanced chemical equation is a representation of a chemical reaction using chemical formulas and coefficients to show the reactants and products involved in the reaction.

To balance a chemical equation, coefficients are placed in front of the chemical formulas to ensure that the number of atoms of each element is equal on both sides of the equation. This results in a balanced equation that accurately represents the reactants and products involved in the reaction, and their relative amounts.

To balance the chemical equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation.

Let's start by counting the number of atoms of each element in the reactants and products:

Reactants:

C₉H₂₀(l) → 9 carbon atoms (C), 20 hydrogen atoms (H)

O₂(g) → 2 oxygen atoms (O) per molecule, so 14 O₂ molecules give 28 oxygen atoms (O)

Products:

9CO₂(g) → 9 carbon atoms (C), 18 oxygen atoms (O)

10H₂O(l) → 20 hydrogen atoms (H), 10 oxygen atoms (O)

Now, we can see that the number of carbon and hydrogen atoms are already balanced, but we need to balance the oxygen atoms.

To do so, we can see that 14 O₂ molecules give us 28 oxygen atoms, which means we need 28/2 = 14 molecules of CO₂ and 14 molecules of H₂O to balance the equation.

The final balanced equation is:

C₉H₂₀(l) + 14O₂(g) → 9CO₂(g) + 10H₂O(l)

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The molarity of the sodium hydroxide solution is 0.0911 M.

we need to calculate the number of moles of potassium hydrogen phthalate:

moles of KHP = mass / molar mass = 0.600 g / 204.22 g/mol = 0.00294 mol

Since one mole of KHP reacts with one mole of NaOH, we know that there are 0.00294 moles of NaOH used in the titration. We can use this information to calculate the molarity of the NaOH solution:

molarity of NaOH = moles of NaOH / volume of NaOH used in liters

We need to convert the volume of NaOH from milliliters to liters:

volume of NaOH = 32.21 mL = 0.03221 L

Now we can calculate the molarity of NaOH:

molarity of NaOH = 0.00294 mol / 0.03221 L = 0.0911 M

The molarity of the sodium hydroxide solution is 0.0911 M.

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Answer:

95.5 g/mol

Explanation:

To find the molar mass of the solute, we need to first calculate the number of moles of the solute in the solution.

Number of moles of solute = concentration x volume

We are given the concentration (0.400 m) and the volume (500 grams) of the solution, but we need to convert the mass of water to volume. We can do this using the density of water:

Density of water = 1 g/mL

Volume of water = mass of water / density of water = 500 g / 1 g/mL = 500 mL

Now we can calculate the number of moles of solute:

Number of moles of solute = 0.400 m x 500 mL = 200 mmol

Next, we need to find the mass of the solute:

Mass of solute = number of moles x molar mass

We are given the number of moles (200 mmol), so we can rearrange the equation to solve for the molar mass:

Molar mass = mass of solute / number of moles

Molar mass = 19.10 g / 200 mmol = 95.5 g/mol

Therefore, the molar mass of the solute is 95.5 g/mol.

Hopes this helps

Fe²⁺ is the reducing agent since in the given redox reaction it loses electrons which are transferred to another species.

A reducing agent, also known as a reductant, is a substance that causes a reduction in another substance by donating electrons or by removing oxygen from the substance being reduced. In other words, it is a substance that facilitates a chemical reaction by undergoing oxidation itself.

A reducing agent is typically an electron donor and is oxidized during the reaction. Examples of reducing agents include metals like zinc, hydrogen gas, and organic compounds like alcohols and sugars.

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The buffer capacity for OH- is equal to the concentration of OH- added, which is [tex]1.87 × 10^-9[/tex] M.

The buffer capacity for OH- is given by the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where pH is the desired pH change, pKa is the dissociation constant of the acid, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the acid.

Rearranging the equation, we get:

[A-]/[HA] = [tex]10^(pH - pKa)[/tex]

In this case, CH3COOH is the acid, and NaCH3COO is its conjugate base. The dissociation constant of acetic acid (CH₃COOH) is 4.76. We can calculate the concentrations of CH₃COOH and NaCH₃COO as follows:

[CH₃COOH] = 1.0 M

[NaCH₃COO] = 0.575 M

To calculate the buffer capacity for OH-, we first need to find the pH of the buffer before adding OH-. We can use the Henderson-Hasselbalch equation to do this:

pH = pKa + log([A-]/[HA])

pH = 4.76 + log(0.575/1.0)

pH = 4.19

Now, if we add OH- to the buffer, it will react with CH₃COOH to form CH₃COO-, according to the following balanced equation:

CH₃COOH + OH- → CH₃COO- + H₂O

The concentration of OH- added to the buffer can be calculated using the pH change:

pH = 4.19 + 4.52 = 8.71

[OH-] = 10^-(pH) = 1.87 × [tex]10^-9[/tex]M

The change in concentration of CH3COOH and CH3COO- due to the addition of OH- can be calculated using stoichiometry:

Δ[CH₃COOH] = -[OH-]

Δ[CH₃COO-] = [OH-]

Therefore, the new concentrations of CH₃COOH and CH₃COO- after adding OH- are:

[CH₃COOH] = 1.0 - [OH-] = 1.0 - 1.87 ×[tex]10^-9[/tex] = 1.0 M

[CH₃COO-] = [NaCH₃COO] + [OH-] = 0.575 + 1.87 × [tex]10^-9[/tex] = 0.575 M

Using the Henderson-Hasselbalch equation, we can calculate the new pH of the buffer:

pH = pKa + log([A-]/[HA])

pH = 4.76 + log(0.575/1.0)

pH = 4.19

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The rate of a chemical reaction can be calculated using its rate law and the concentrations of its reactants. The rate of reaction is 7.64 x 10⁻⁵ mol L⁻¹ s⁻¹.

The rate law for the given reaction is given as:

rate = (397 mol⁻² L² s¹) [A]²[B]

where [A] and [B] are the concentrations of reactants A and B, respectively.

We are given the concentrations of A and B as 0.0615 mol L⁻¹ and 0.583 mol L⁻¹, respectively. We can substitute these values into the rate law and solve for the rate of the reaction:

rate = (397 mol⁻² L² s¹) (0.0615 mol L⁻¹)² (0.583 mol L⁻¹)

rate = 7.64 x 10⁻⁵ mol L⁻¹ s⁻¹

Therefore, the rate of the reaction is 7.64 x 10⁻⁵ mol L⁻¹ s⁻¹.

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Without more information about the specific experiment, it is difficult to provide a definitive answer to this question. However, based on the limited information provided, it seems that the experiment involves placing water samples from Detroit and Flint into separate beakers, stirring them, and then introducing a metal coil into each beaker.

What is Metal?

Metal is a type of element characterized by its shiny appearance, malleability, ductility, and ability to conduct heat and electricity. Metals are typically solid at room temperature (except for mercury, which is a liquid) and have a high melting and boiling point.

If the metal coil is made of a reactive metal such as iron, zinc, or aluminum, and the water contains dissolved oxygen and other ions, then the metal coil may undergo a chemical reaction with the water. This could result in the formation of metal ions and the release of hydrogen gas. The metal ions and other reaction products could then combine with other compounds in the water to form insoluble precipitates, which could appear as a cloudy or turbid solution.

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Answer:

D

The temperature an object would be if its molecules were completely still. Absolute zero is the lowest possible temperature that can be achieved, at which the particles of matter would have zero thermal energy and all molecular motion would stop.

The molarity of the sodium hydroxide solution is 0.09111 M.

What is Molarity?

Molarity is a measure of the concentration of a solution. It is defined as the number of moles of solute dissolved in one liter of solution.

Molarity is an important concept in chemistry because it allows us to quantify the amount of solute in a solution and to make predictions about the behavior of the solution in various chemical reactions.

First, we can calculate the number of moles of potassium hydrogen phthalate using its molecular weight:

moles of KHP = mass / molecular weight

moles of KHP = 0.600 g / 204.22 g/mol

moles of KHP = 0.002938 mol

Since one mole of KHP reacts with one mole of NaOH, we know that there are also 0.002938 moles of NaOH in the titrated solution. We can calculate the molarity of the NaOH solution using the formula:

molarity = moles of solute / volume of solution (in liters)

First, we need to convert the volume of the NaOH solution from milliliters to liters:

volume of NaOH solution = 32.21 mL = 0.03221 L

Now we can calculate the molarity of the NaOH solution:

molarity = 0.002938 mol / 0.03221 L

molarity = 0.09111 M

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The percentage yield of the reaction is 99.5%.

Percentage yield is the ratio of the actual yield of a reaction to the theoretical yield, expressed as a percentage. It is a measure of the efficiency of a reaction and indicates how much of the desired product was obtained relative to the amount that could have been produced under ideal conditions.

The yield of a chemical reaction can be affected by a variety of factors, including the purity and amount of the reactants, the conditions under which the reaction occurs (e.g. temperature, pressure, and reaction time), and the efficiency of the reaction process (e.g. whether the product is recovered efficiently).

Other factors that can affect yield include the presence of impurities or side reactions, the stability of the reactants and products, and the skill and experience of the person carrying out the reaction.

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The balanced equation is:

2[tex]Fe^{3+}[/tex]+ 4[tex]H^{+}[/tex] + 2[tex]No_{2} ^{-}[/tex] → 2[tex]Fe^{2+}[/tex] + 2H2O + 2[tex]No_{3} ^{-}[/tex]

What is balanced equation?

To balance this redox reaction, we first need to identify which elements are being oxidized and reduced. In this case, the iron (Fe) is being reduced from a +3 oxidation state to a +2 oxidation state, while the nitrogen (N) in the nitrite ion (NO2-) is being oxidized from a +3 oxidation state to a +5 oxidation state in the nitrate ion (NO3-).

To balance the equation, we can follow these steps:

Write out the unbalanced equation:

[tex]Fe^{3+}[/tex] + [tex]No_{2} ^{-}[/tex] + H₂O → [tex]Fe^{2+}[/tex] +[tex]H^{+}[/tex] + [tex]No_{3} ^{-}[/tex]

Separate the equation into two half-reactions, one for the oxidation and one for the reduction:

Oxidation: [tex]No_{2} ^{-}[/tex] → [tex]No_{3} ^{-}[/tex]

Reduction: [tex]Fe^{3+}[/tex] → [tex]Fe^{2+}[/tex]

Balance the elements in each half-reaction by adding the appropriate number of electrons (e-):

Oxidation: 4[tex]H^{+}[/tex] + [tex]No_{2} ^{-}[/tex] + e- → [tex]No_{3} ^{-}[/tex] + 2H2O

Reduction: Fe³+ [tex]e^{-}[/tex] → [tex]Fe^{2+}[/tex]

Balance the number of electrons transferred in the two half-reactions by multiplying one or both of the half-reactions by a suitable coefficient:

Oxidation: 4[tex]H^{+}[/tex] + [tex]No_{2} ^{-}[/tex] + 2[tex]e^{-}[/tex] → [tex]No_{3} ^{-}[/tex] + 2H2O

Reduction: 2[tex]Fe^{3+}[/tex] + 2[tex]e^{-}[/tex] → 2[tex]Fe^{2+}[/tex]

Add the two half-reactions together and cancel out any common species on both sides of the equation:

2[tex]Fe^{3+}[/tex]+ 4[tex]H^{+}[/tex] + 2[tex]No_{2} ^{-}[/tex] → 2[tex]Fe^{2+}[/tex] + 2H2O + 2[tex]No_{3} ^{-}[/tex]

The balanced equation is:

2[tex]Fe^{3+}[/tex]+ 4[tex]H^{+}[/tex] + 2[tex]No_{2} ^{-}[/tex] → 2[tex]Fe^{2+}[/tex] + 2H2O + 2[tex]No_{3} ^{-}[/tex]

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Answer:

the molarity of the HCl is 1.17 M.

Explanation:

The balanced chemical equation for the reaction between HCl and NaOH is:

HCl + NaOH -> NaCl + H2O

From the equation, we can see that one mole of HCl reacts with one mole of NaOH to produce one mole of NaCl and one mole of water.

First, let's calculate the number of moles of NaOH used:

moles of NaOH = Molarity x Volume in liters

moles of NaOH = 0.650 M x 0.0900 L

moles of NaOH = 0.0585 mol

Since the reaction between HCl and NaOH is a 1:1 stoichiometry, the number of moles of HCl is also equal to 0.0585 mol.

Now, we can use the number of moles of HCl and the volume of HCl to calculate the molarity:

Molarity of HCl = moles of HCl / Volume in liters

Molarity of HCl = 0.0585 mol / 0.0500 L

Molarity of HCl = 1.17 M

Therefore, the molarity of the HCl is 1.17 M.

The 37.2g of water must be heated from -15C to 135C using 23,447.04 joules of energy.

Heat transfer between two things is a result of their different masses. Heat transfer between two things is a result of their different densities. Heat transfer is a result of the temperature difference between two systems. Heat transmission between two objects is a result of pressure differences.

For calculating the heat:

Q = m × c × ΔT

Where:

Q = amount of heat (in joules)

m = mass of the substance (in grams)

c = specific heat capacity of the substance (in J/g·°C)

ΔT = change in temperature (in °C)

The specific heat capacity of water is approximately 4.184 J/g·°C.

Now, we have to calculate the change in temperature:

ΔT = final temperature - initial temperature

ΔT = 135⁰C - (-15⁰C)

ΔT = 150⁰C

Now, we can substitute the values,

Q = 37.2g × 4.184 J/g·°C × 150⁰C

Q = 23,447.04 J

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The number of moles of CO contained in the 20.0 L tank at 93 °C and 4.52 atm is 3.01 moles (3rd option)

First, we shall list out the given parameters from the question. Details below:

We can obtain the number of mole in the tank as follow:

PV = nRT

4.52 × 20 = n × 0.0821 × 366

90.4 = n × 30.0486

Divide both sides by 30.0486

n = 90.4 / 30.0486

n = 3.01 moles

Thus, we can conclude that the number of mole of the gas is 3.01 moles (3rd option)

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To calculate the heat gained by the cold liquid, we need to use the formula: q = m * c * ΔT

where q is the heat gained or lost by the substance, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature of the substance.

Let's assume that we have a cold liquid with a mass of 100 grams and an initial temperature of 10°C. We then add 50 grams of a hot solid that has been heated to 80°C. After the solid and liquid are allowed to equilibrate, the final temperature of the mixture is 20°C.

We can first calculate the heat lost by the hot solid using the same formula:

q = m * c * ΔT

q = 50 g * 0.385 J/g°C * (80°C - 20°C)

q = 15400 J

The negative sign indicates that the solid lost heat to the colder liquid.

To calculate the heat gained by the cold liquid, we can use the same formula and the final temperature of the mixture:

q = m * c * ΔT

q = 100 g * 4.184 J/g°C * (20°C - 10°C)

q = 4184 J

Therefore, the heat gained by the cold liquid is 4184 J.

The complete question is :

Use the equation qliquid = m × c × ΔT to calculate the heat gained by the cold liquid. Use the specific heat for the liquid you selected.

Use the equation qwater = m × c × ΔT to calculate the heat lost by the hot water. Show your work using the problem-solving method shown in previous rubrics.

Learn more about specific heat capacity here:

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Answer:

The balanced chemical equation for the reaction is:

CS2 + 3 Cl2 ➡️ CCl4 + S2Cl2

According to the equation, one mole of CS2 reacts with three moles of Cl2 to produce one mole of CCl4. The molar mass of CS2 is 76.14 g/mol, and the molar mass of CCl4 is 153.82 g/mol.

Theoretical yield of CCl4:

125 g CS2 × (1 mol CS2/76.14 g) × (1 mol CCl4/1 mol CS2) × (153.82 g CCl4/1 mol CCl4) = 318.3 g CCl4

This means that 318.3 g of CCl4 should have been produced according to the balanced equation.

Actual yield of CCl4 = 60.4 g

Percent yield = (actual yield / theoretical yield) × 100%

Percent yield = (60.4 g / 318.3 g) × 100%

Percent yield = 19%

Therefore, the percent yield of CCl4 is 19%.

Explanation:

The process is called bleaching. Chlorine gas (Cl2) reacts with water to form hypochlorous acid (HOCl) and hydrochloric acid (HCl). Hypochlorous acid acts as a powerful oxidizing agent and removes electrons from the red litmus paper, causing it to turn white.