The correct answer is D. Reactants are substances that are combined to form products in a chemical reaction. Products are the result of substances being combined in a chemical reaction.
a sample of neon has a volume of 40.81 m3 at 23.5c. at what temperature, in kelvins, would the gas occupy 50.00 cubic meters? assume pressure is constant. a. 363.27 k b. 230.54 k c. 242.0 k d. 28.79 k
At the temperatute of 363.27 K the sample of the gas Neon would occupy a volume of 50.00 cubic meters. Therefore option A can be considered correct.
Using the combined gas law in order to solve this problem
(P₁V₁)/T₁ = (P₂V₂)/T₂
( P is the pressure, V is the volume, and T is the temperature)
Since the pressure is constant, we can simplify the equation to:
V₁/T₁ = V₂/T₂
After inserting the values given in the problem equation,
V₁ = 40.81 m³
T₁ = 23.5°C + 273.15 = 296.65 K
V₂ = 50.00 m³
We can solve for T₂= (V₂/V₁) × T₁
T₂ = (50.00/40.81) × 296.65
T₂ = 363.27 K
Hnce, the temperature in kelvins at which the gas would occupy the volume of 50.00 cubic meters is calculated out to be 363.27 K.
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A nutrition label has the following information.
Nutrition Facts
Calories
112
Total Fat
Og
Total Carbohydrates21 g
7g
Protein
What percentage of the total Calories is from carbohydrates?
Type answer:
Type answer: 63%, Percentage of Calories from Carbohydrates = 75%
Calculation of Percentage of Calories from Carbohydrates = 75%Given data
Calories: 112Total Fat: 0gTotal Carbohydrates: 21gProtein: 7gCalories from Carbohydrates = Total Carbohydrates x 4
= 21 g x 4
= 84 Calories
Percentage of Calories from Carbohydrates =
(Calories from Carbohydrates / Total Calories) x 100
= (84 / 112) x 100
= 0.75 x 100
= 75%
This nutrition label displays the number of Calories, Total Fat, Total Carbohydrates, and Protein. There are 112 Calories, 0g of Total Fat, 21g of Total Carbohydrates, and 7g of Protein. This accounts for 63% of the total Calories, with the majority coming from Total Carbohydrates.
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brainly plutonium-239 has a half life of 24000 yearas and is considered safe only ewhens it radiactively has dropped to 1% of the original level approximately how long the pu-239 be stored securely to be considered safe
Plutonium-239 is a radioactive isotope that has a half-life of 24000 years. When it has decayed to 1% of its original level, it is considered safe.
PLUTONIUM -
As plutonium isotopes decay, they undergo chemical changes. They might change into new elements like uranium or neptunium or into new isotopes of plutonium.
These "daughter products" frequently contain radioactive elements themselves. The atomic number 94 metal element plutonium is radioactive.
Scientists looking for a way to break atoms for use in nuclear weapons made the discovery in 1940. When uranium atoms absorb neutrons in a nuclear reactor, plutonium is produced.
The vast majority of plutonium in the world is produced artificially.
To be considered safe, it must be stored securely for approximately 240,000 years.
How long must the pu-239 be stored securely to be considered safe?
The decay of Plutonium-239 to 1% of its initial level, which is considered safe, requires approximately ten half-lives.
As a result, plutonium-239 must be kept securely for ten times its half-life, or approximately 240,000 years, to be considered safe.
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How many moles are in 1.2 x 10^24 formula units of Li₂SO4? (round your answer to the nearest tenths place)
In 1.2 x [tex]10^{24}[/tex] formula units of [tex]Li_{2} (SO)_{4}[/tex], there are roughly 1.993 moles of
[tex]Li_{2} (SO)_{4}[/tex].
How many moles of [tex]Li_{2} (SO)_{4}[/tex] are contained in 1.2 x [tex]10^{24}[/tex] formula units?Using Avogadro's number, or 6.022 x [tex]10^{23}[/tex] molecules/mol, we can calculate the number of moles of Li2SO4 in 1.2 x [tex]10^{24}[/tex]formula units.
First, we need to figure out how many moles of [tex]Li_{2} (SO)_{4}[/tex] are needed to equal 1.2 x [tex]10^{24}[/tex] formula units:
Formula units equal 6.022 x [tex]10^{23}[/tex] per mole of [tex]Li_{2}(SO)_{4}[/tex].
As a result, there are: 1.2 x [tex]10^{24}[/tex] moles of [tex]Li_{2}(SO)_{4}[/tex] in the formula units.
1.993 moles are equal to 1.2 x [tex]10^{24}[/tex] formula units / 6.022 x [tex]10^{23}[/tex] formula units/mol.
Hence, 1.2 × [tex]10^{24}[/tex] formula units of [tex]Li_{2} (SO)_{4}[/tex] contain about 1.993 moles.
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A scientist is preparing a beaker of boiling water to use in order to rapidly heat some frozen samples. If this scientist wishes to increase the heat of the boiling water as much as possible, what could she do?
If the scientist wishes to increase the heat of the boiling water as much as possible, she can increase the heat source's temperature or increase the amount of heat being supplied to the water.
This can be done by increasing the flame on the stove, increasing the power of the heating element, or adding more heat from an external source. However, it is important to note that the boiling point of water is 100°C at standard atmospheric pressure, so the water will not get any hotter than that unless the pressure is increased. Also, caution should be taken when working with boiling water to prevent burns or accidents.
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is a halide attached to a diene considered an electron-withdrawing group or an electron-donating group?
Answer: When a halide is attached to a diene, it is considered an electron-withdrawing group.
A halide is a chemical compound containing one or more halogens, which are a group of chemically related elements that are used in various industries. In organic chemistry, halogens are considered to be a powerful electron-withdrawing group.
When halogens are attached to an organic molecule, they decrease its electron density by drawing electrons away from the rest of the molecule.The reason halogens are electron-withdrawing is because of their electronegativity. They have a high electronegativity value, which means they have a strong pull on electrons.
This strong pull on electrons causes the halogen to become electron-deficient and leads to it withdrawing electrons from other parts of the molecule to stabilize itself.When a halide is attached to a diene, it is considered an electron-withdrawing group. The reason for this is because of the halogen's electronegativity.
The halogen in the halide group has a high electronegativity value, which causes it to withdraw electrons from the diene, which is an electron-rich molecule. This withdrawal of electrons reduces the electron density of the diene and makes it less reactive.
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If hydrochloric acid reacts with 13.7g of sodium sulfate, how many grams of sulfuric acid are produced?
Answer:
The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium sulfate (Na2SO4) is:
2 HCl + Na2SO4 → 2 NaCl + H2SO4
This equation shows that two moles of hydrochloric acid react with one mole of sodium sulfate to produce one mole of sulfuric acid. Therefore, we need to first calculate the number of moles of sodium sulfate that react with the given mass of hydrochloric acid, and then use the mole ratio to find the number of moles (and mass) of sulfuric acid produced.
Calculate the number of moles of sodium sulfate:
molar mass of Na2SO4 = 2(23.0 g/mol) + 1(32.1 g/mol) + 4(16.0 g/mol) = 142.1 g/mol
moles of Na2SO4 = mass/molar mass = 13.7 g/142.1 g/mol = 0.0965 mol
Use the mole ratio to find the number of moles of sulfuric acid produced:
From the balanced equation, we see that 2 moles of HCl react with 1 mole of Na2SO4 to produce 1 mole of H2SO4.
So, the number of moles of H2SO4 produced = (0.0965 mol Na2SO4) x (1 mol H2SO4 / 1 mol Na2SO4) = 0.0965 mol H2SO4
Calculate the mass of sulfuric acid produced:
molar mass of H2SO4 = 1(2.0 g/mol) + 1(32.1 g/mol) + 4(16.0 g/mol) = 98.1 g/mol
mass of H2SO4 = moles x molar mass = 0.0965 mol x 98.1 g/mol = 9.50 g
Therefore, 9.50 grams of sulfuric acid are produced when hydrochloric acid reacts with 13.7 grams of sodium sulfate.
how the temperature and vapor pressure are related knowing the enthalpy of vaporization at the boiling temperature
starting with a 1.00 l of a buffer that is 0.700 m hf and 0.553 m naf, calculate the ph after the addition of 0.100 mol naoh. ka (hf) 7.1 x 10-4
The pH after the addition of 0.100 mol NaOH to 1.00 L of a buffer that is 0.700 M HF and 0.553 M NaF. The pH is 7.031.
To calculate the pH after the addition of 0.100 mol NaOH to 1.00 L of a buffer that is 0.700 M HF and 0.553 M NaF, we can use the Henderson-Hasselbalch equation.
The Henderson-Hasselbalch equation is: pH = pKa + log ([A-]/[HA])
Where [A-] is the concentration of the anion (in this case, NaF) and [HA] is the concentration of the acid (in this case, HF).
pKa for HF is 7.1 x 10-4
Before we add the 0.100 mol NaOH, the pH of the buffer is:
pH = 7.1 x 10-4 + log ([0.553 M NaF]/[0.700 M HF])
= 7.1 x 10-4 + log(0.787)
= 7.1 x 10-4 + -0.103
= 6.997
Now, let's calculate the concentration of NaOH after we add 0.100 mol of it to the buffer. We know that 1 mole of NaOH will produce 1 mole of OH- ions, so the concentration of OH- ions is 0.100 M.
Since the buffer already contains HF and NaF, the total concentration of anions is 0.653 M.
We can now calculate the new pH using the Henderson-Hasselbalch equation:
pH = 7.1 x 10-4 + log([0.653 M anions]/[0.700 M HF])
= 7.1 x 10-4 + log(0.933)
= 7.1 x 10-4 + -0.069
= 7.031
Therefore, the pH of the buffer after the addition of 0.100 mol NaOH is 7.031.
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a saturate solution of lead (ii) chloride (pbcl2) has a ksp value of 17.10-5. if 0.90 moles of chloride ions (cl-) is added to the solution, what will be the concentration of lead ions be in solution?
Therefore, the concentration of Pb2+ ions in the solution is 0.0098 M. The chemical equation describing how lead (II) chloride dissolves in water Pb2+ (aq) + 2Cl- PbCl2 (s) (aq) For this reaction.
Ksp = [Pb2 +] [Cl -] 2 We are provided that the Ksp value of PbCl2 is 1.7 × 10^-5. Also, we are informed that 0.90 moles of Cl- ions have been added to the mixture. We may assume that the concentration of Pb2+ ions is insignificant compared to the concentration of Cl- ions since the stoichiometry of the reaction is 1:2 for Pb2+:Cl-. Let x be the concentration of Pb2+ ions in the solution. Then, the concentration of Cl- ions is 2x (because the stoichiometry is 1:2 for Pb2+:Cl-). The total concentration of Cl- ions in the solution is therefore:
[Cl-]total = 2x + 0.90
Since the solubility product expression for[tex]PbCl2 is Ksp = [Pb2+][Cl-]^2, \\[/tex]we can write:
[tex]Ksp = x(2x + 0.90)^2Solving for x, we get:x = 0.0098 M[/tex]
Therefore, the concentration of Pb2+ ions in the solution is 0.0098 M.
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Answer:
Explanation:
The statement mentioned in the question is not a question. However, I can provide some information related to the given statement.Nickel(II) chloride refers to the chemical compound with the formula NiCl2. It is also known as Nickelous chloride. When nickel(II) chloride is dissolved in water, it forms a saturated solution of concentration 1 M (1 mole/Liter). A saturated solution refers to the solution in which no more solute can be dissolved in it at a given temperature and pressure.To summarize, the given statement means that if you dissolve nickel(II) chloride in water, you will obtain a saturated solution of concentration 1 M (1 mole/Liter).
You have 3 beakers of water Beaker A: 50 °C, 200 grams of water Beaker B: 70 °C, 200 grams of water Beaker C: 50 °C, 400 grams of water.
ANSWER ALL 3 PARTS OF THE QUESTION
Part 1: Compare the average kinetic energy of the water molecules in the three beakers. Part 2: Compare the thermal energy of the water in the three beakers. Part 3: If you were to combine the water in the three beakers (without any waste heat transferring into the environment),do you think the temperature of the mixed water would be closer to 50 °C or 70 °C? Explain.
Part 1: The average kinetic energy of the water molecules is higher in Beaker B than in Beaker A and C.
Part 2: The thermal energy of the water in Beaker C is higher than in Beaker A and B due to the larger amount of water.
Part 3: The temperature of the mixed water would be closer to 50 °C since Beaker A and C have the same initial temperature and the larger amount of water in Beaker C would lower the overall temperature.
Brief explaination:
Part 1: The average kinetic energy of water molecules is directly proportional to temperature. Therefore, the water molecules in Beaker B with a temperature of 70 °C have the highest average kinetic energy, followed by the water molecules in Beaker A and C, both at 50 °C.
Part 2: Thermal energy is directly proportional to temperature and mass of water. Beaker B has more thermal energy than Beaker A due to its higher temperature. Beaker C has the most thermal energy due to its higher mass.
Part 3: Combining the three beakers without heat loss results in a total thermal energy equal to the sum of each beaker's thermal energy. Beaker C's higher thermal energy dominates, making the mixed water temperature closer to 50°C, the temperature of Beaker C.
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Sometimes liquid ammonia, NH3, is used as a solvent rather than water. Which expression defines the ammonia autoionization counterpart of Kw?
a.[H3O+][OH-]
b.[NH3][NH4+]
c.[NH2-][NH4+]
d.[H3O+][NH2-]
e.[NH4+][OH-}
The ammonia autoionization counterpart of Kw is defined by the expression c. [tex][NH_2^-][NH_4^+].[/tex]
The autoionization of liquid ammonia, [tex]NH_3[/tex], involves the transfer of a proton from one ammonia molecule to another, producing the ammonium ion ([tex]NH_4^+[/tex]) and the amide ion ([tex]NH_2^-[/tex]):
[tex]NH_3 + NH_3[/tex]⇌ [tex]NH_2^- + NH_4^+[/tex]
This is because ammonia ([tex]NH_3[/tex]) can act as both a base and an acid in a solvent, and autoionizes into [tex]NH_2^-[/tex] (amide ion) and [tex]NH_4^+[/tex] (ammonium ion)
The equilibrium constant expression for this reaction is:
[tex]K = [NH_4^+][NH_2^-]/[NH_3]^2[/tex]
Therefore, the ammonia autoionization counterpart of Kw would be:
[tex]Kw = [NH_4^+][NH_2^-][/tex]
Therefore, the correct answer is (c) [tex][NH_2^-][NH_4^+].[/tex].
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35.0 l of an ideal gas at 268 k and 5.16 atm are heated to 343 k with a new pressure of 8.00 atm. what is the new volume (in l)? 2 8 . 9
The new volume of the ideal gas is 28.9 liters when heated from 268K to 343K and the pressure is increased from 5.16atm to 8.00atm.
This can be calculated using the Ideal Gas Law: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.
First, calculate the number of moles of the ideal gas, n = PV/RT. Plug in the given values, and rearrange for n: n = (5.16atm)(35.0L)/(8.314L∙K⁻¹∙mol⁻¹)(268K) = 0.41mol.
Then, calculate the new volume of the gas, V = nRT/P. Plug in the given values, and rearrange for V: V = (0.41mol)(8.314L∙K⁻¹∙mol⁻¹)(343K)/(8.00atm) = 28.9L.
Therefore, the new volume of the ideal gas is 28.9 liters when heated from 268K to 343K and the pressure is increased from 5.16atm to 8.00atm.
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What change takes place in a substance as the molecular motion of that substance increases? Responses A. The substance changes from a liquid to a gas. A. The substance changes from a liquid to a gas. B. The substance changes from a gas to a liquid. B. The substance changes from a gas to a liquid. C. The substance changes from a liquid to a solid. C. The substance changes from a liquid to a solid. D. The substance changes from a gas to a solid.
The distance between atoms widens as their vibrations get more rapid. The substance's state of matter is determined by the movement and spacing of its particles. The thing grows or enhanced molecular mobility.
What causes molecules inside a substance to move differently?Because kinetic energy of a liquid's molecules rises as the temperature does. As a result, the molecules have more flexibility to travel across larger volumes as the forces that attraction between them are eventually overcome.
What is required to promote molecular motion?According to the gas kinetic theory, as a gas's temperature rises, the typical kinetic energy of its molecules rises, leading to more motion. This real gases equation PV=NkT predicts that the increased velocity will increase the gas's outer pressure.
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What salt would be produced by the reaction of H2SO4 with LiHCO3? a) Li2S b) LiSO4
c) Li2SO4 d) Li2CO3
The salt that would be produced by the reaction of H2SO4 with LiHCO3 is option C-Li2SO4.
Lithium sulfate (Li2SO4) is an inorganic compound with the formula Li2SO4. It is a white crystalline material that is soluble in water. The salt would be produced as a result of the following reaction: H2SO4 + LiHCO3 → Li2SO4 + H2O + CO2.
Lithium carbonate (Li2CO3) would not be produced in this reaction because LiHCO3 reacts with H2SO4 to form Li2SO4. Li2S cannot be produced because it requires Li2S2, which is not one of the reactants or products. LiSO4 is not produced because H2SO4 reacts with LiHCO3 to form Li2SO4 instead. Thus, option (c) Li2SO4 is the correct answer.
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Using the formula M1V1 = M2V2, how many millimeters of 6.0M sodium hydroxide are required to prepare 2.0L of a 1.0M sodium hydroxide solution?
Question Options:
200 mL
1200 mL
300 mL
330 mL
Answer: 330 i just took the test
Explanation:
330 mL of 6.0M sodium hydroxide are required to prepare 2.0L of a 1.0M sodium hydroxide solution. This is done by Molarity method.
What is Molarity?A substance's concentration in a liquid is referred to as its molarity, or molar concentration. The substance being dissolved is referred to as a solute, while the liquid is referred to as a solvent. The number of moles per liter is the precise definition of molarity.
Solids, other liquids, or even gases can all dissolve into a liquid and become a solute. Finding molarity is straightforward if you are aware of the solute's molecular weight and the amount of solvent it is dissolved in.
Using the formula M₁×V₁ = M₂×V₂
M₁ = 6.0 M
M₂ = 1.0 M
V₂ = 2.0 L
substituting the values ,
V₁ = 330 mL
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Which of the following does "cup A" represent in the experimental set-up?
independent variable - it is changed for each group to test for results
dependent variable - it is what is measured
control - it is kept the same (no experimental treatment) to keep the results reliable
none of the above
Cup A represents the independent variable in the experimental set-up. An independent variable is a variable that is changed for each group in an experiment to see what effect it has on the results.
In this case, Cup A is the independent variable because it is the one that is being changed or manipulated in the experiment. For example, in this set-up, cup A might contain different amounts of a certain nutrient to see how it affects the growth of the plants. The dependent variable is what is measured, such as the growth rate of the plants. The control is kept the same (no experimental treatment) to keep the results reliable and to act as a comparison to the experimental results. This control is used to make sure that any changes in the dependent variable are due to the independent variable and not some other factor.
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explain where the lone pairs of electrons are likely to be. why does the placement of electrons matter with this central atom?
Answer: The placement of electrons in the central atom is important as it determines the molecular geometry and polarity of the molecule. The lone pairs of electrons are likely to be in the valence shell of the central atom.
What are electrons?
Electrons are tiny negatively charged particles that are part of atoms. Electrons play an important role in the chemistry of the atom. The outer shell of an atom contains electrons, and it is the arrangement of these electrons that determines how atoms will interact with each other.
Electrons in the outermost shell are known as valence electrons. Lone pair of electrons, lone pairs are valence electrons that are not involved in covalent bonding. They are also known as non-bonding electrons. For instance, nitrogen atom has five valence electrons. In ammonia, three electrons from nitrogen atom are involved in forming covalent bonds with hydrogen atoms.
The remaining two electrons are known as lone pairs. The central atom, in this case, is nitrogen, and the lone pairs of electrons are present on the nitrogen atom. Lone pairs of electrons are the determining factor for determining the geometry and polarity of molecules. They are important for understanding chemical reactions and predicting the behavior of different molecules.
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if a zero order reaction has a half-life of 350 s when the initial reactant concentration is 1.50 m, how long until 0.1% of the reactant remains?
It will take 3401 seconds for 0.1% of the reactant to remain.
The half-life of a zero-order reaction is the time taken for the concentration of the reactant to decrease by half. This can be calculated using the equation:
t1/2 = 0.693/k
Where k is the rate constant of the reaction. The amount of time it takes for 0.1% of the reactant to remain, we can use the following equation:
t = (-log(0.001))/k
The rate constant of the reaction can be calculated as:
k = 0.693/t1/2 = 0.693/350 = 0.001988
t = (-log(0.001))/k = (-log(0.001))/0.001988 = 3401 seconds
Therefore, it will take 3401 seconds for 0.1% of the reactant to remain.
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when determining the energy effect of a chemical reaction the system is/are and the surroundings is/are
When determining the energy effect of a chemical reaction, the system is/are reactants and products and the surroundings are everything outside the system.
When determining the energy effect of a chemical reaction, the system and surroundings are involved. The system refers to the reactants and products involved in the chemical reaction, whereas the surroundings refer to everything else outside the system, including the temperature, pressure, and any other factors that can affect the reaction.
The energy effect of a chemical reaction can be determined by calculating the difference between the energy of the products and the energy of the reactants. This difference is known as the energy change or the enthalpy change of the reaction.
If the energy change is positive, it means that the reaction is endothermic, and energy is absorbed from the surroundings. This results in a decrease in the temperature of the surroundings.
On the other hand, if the energy change is negative, it means that the reaction is exothermic, and energy is released into the surroundings. This results in an increase in the temperature of the surroundings.
It is important to note that the energy effect of a chemical reaction can also be affected by external factors such as pressure, temperature, and the presence of a catalyst.
In conclusion, the system is the reactants, and the products and surroundings are factors like temperature and pressure, i.e., everything outside the system.
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doppelbocks are lagers unified by what characteristic? group of answer choices they have almost no bitterness a low alcohol content a high alcohol content they are very bitter
Doppelbocks are lagers unified by their high alcohol content.
Doppelbocks are German lagers that are dark and full-bodied. They are recognized for their rich malt flavors and alcoholic content, which is typically over 7% by volume. The monks of Munich developed the style in the 17th century, and the doppelbock style has been associated with monastic brewing ever since.
Doppelbocks are unified by high alcohol content because they are high in maltose and other fermentable sugars, which make them perfect for long, cold fermentations that yield a rich, complex, and smooth flavor. Lagers are a type of beer typically fermented at low temperatures and for an extended period. They are one of two significant categories of beer, the other being ales. Lagers are usually lighter in color and smoother in flavor than ales. They are also typically lower in alcohol content and have a cleaner, crisper taste than ales.
In conclusion, Doppelbocks are lagers unified by high alcohol content.
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A balloon has a volume of 6.7L at 20 celsius. What will its volume be at 350 celsius if it is at constant pressure?
Volume of balloon [tex] \sf (V_1 ) [/tex] = 6.7 L
Temperature [tex] \sf (T_1 ) [/tex]= 20 celsius (converting into kelvin) = 20 + 273 = 293 K
Now,
[tex] \sf (T_2 ) [/tex] = 350 celsius
= 350 + 273 = 623 K
Since pressure is constant.
According to Charles law, At constant pressure the volume of the gas is directly proportional to temperature.
[tex] \: \: { \boxed{ \sf{ \pink{\dfrac{V_1}{V_2} = \dfrac{T_1}{T_2}}}}}[/tex]
We have to find [tex] \sf (V_2 ) [/tex]
On putting the values in above formula,,
[tex]\sf \dfrac{6.7}{V_2} = \dfrac{293}{623} \\ \\ \sf V_2 = \dfrac{6.7 \times 623}{293} \\ \\ \sf V_2 = \dfrac{4174.1}{293} \\ \\ \sf V_2 = 14.24[/tex]
Therefore, Volume of the balloon will be 14.24 L at 350 celsius.
A sample of ideal gas occupies 208ml at 36. 2 degree celsius and 704 torr what is the volume at stp
At Standard Temperature and Pressure (STP) the volume of the gas at is 216.1 ml.
A sample of ideal gas occupies 208ml at 36.2 degree Celsius and 704 torr what is the volume at stp
For a sample of ideal gas, the relationship between volume, pressure, and temperature is given by the Ideal Gas Law:
PV = nRT
Where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the universal gas constant, and T is the temperature of the gas.
At STP (Standard Temperature and Pressure), the pressure of the gas is 1 atm and the temperature of the gas is 0°C (273 K). Therefore:
P1 = 704 torr
V1 = 208 mL
T1 = 36.2°C = 309.35 K
P2 = 1 atm
V2 = ?
T2 = 0°C = 273 K
To find V2, we can use the following equation:
V2 = V1(P2/P1)(T1/T2)
Plugging in the given values:
V2 = 208 mL (1 atm/704 torr) (309.35 K/273 K)
V2 = 208 mL (0.939) (1.132)
V2 = 216.1 mL
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naphthalene, the active ingredient in one variety of mothballs, is an organic compound that contains carbon and hydrogen only. complete combustion of a 20.10 mg sample of naphthalene in oxygen yielded 69.00 mg of co2 and 11.30 mg of h20. determine the molecular formula of naphthalene
The molecular formula of naphthalene is C6H6 if it involves the complete combustion of a 20.10 mg sample of naphthalene in oxygen yielded 69.00 mg of co2 and 11.30 mg of h20.
We have the complete combustion of a 20.10 mg sample of naphthalene in oxygen yielded 69.00 mg of co2 and 11.30 mg of h20.
Mass of C in CO2 is,
= 12/44 x 69.00
= 18.82mg
Mass of H in H2O is,
= 2/18 x 11.30
= 1.256mg
We have to find Mole ratios.
C= 18.82/12= 1.568
H= 1.256/1= 1.256
Now we have to divide by the smaller mole ratio.
C= 1.568/1.256= 1.2=1
H= 1.256/1.256= 1
So the empirical formula is CH.
The empirical formula of a compound is defined as the formula which gives us the lowest whole number ratio of that particular compound.
A molecular formula is a way of presenting information about the chemical proportions of atoms that constitute a particular chemical compound or molecule.
Empirical formula weight=12+1=13
We can get the mass of the empirical formula can be computed by dividing the molar mass of the compound by it.
Molecular weight=78
n= Molecular weight / Empirical formula weight
= 78/ 13
=6
Molecular formula=(CH) n =(CH) 6 =C6H6
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1. Write a hypothesis based on observations and scientific principles. (Hint: This means you write a prediction about how you think natural selection will lead to changes in the specific traits in populations of moths in the simulation. Don't forget to write it in the if-then statement format
a reaction carried out and the rate measured. the experiment is repeated, but with doubling the concentration of a reactant. the measured rate does not change. what must be true about the reactants role in the reaction?
B. The rate would drop or decrease. Although the rate of a chemical reaction typically rises as the concentration of the reactants increases, if the concentration falls, the reaction rate also rises.
In general, the rate of a chemical reaction rises as the reactant concentration does. The volume of reactant that transforms into product over a specific amount of time. additionally described as the quantity of a product that forms in a specific length of time — Since a chemical system is at equilibrium when the rate of the forward reaction equals the rate of the reverse reaction, reaction rates and chemical equilibrium are connected.
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Complete Question:
a reaction carried out and the rate measured. the experiment is repeated, but with doubling the concentration of a reactant. the measured rate does not change. what must be true about the reactants role in the reaction?
A. the rate would increase.
B. the rate would decrease.
C. the rate would remain constant.
jeanette isolated her product and used an nmr spectrometer to obtain an nmr spectrum. the signal for borneol at 4.00 ppm has an integration of 4.765 and the signal for isoborneol at 3.61 ppm has an integration of 3.374. what is the percentage of isoborneol (round to 2 decimal places)?
Percentage of isoborneol present in the sample is 41.4%.
The percentage of isoborneol, you need to divide the integration value of isoborneol (3.374) by the sum of the integrations of both compounds (4.765 + 3.374). This is equivalent to 3.374/8.139 = 0.414.
Multiplying by 100 gives the percentage of isoborneol as 41.4%.
Integration values are used to measure the relative abundance of a compound in a mixture.
In an NMR spectrum, integration values are calculated from the area under the peak, which is proportional to the amount of that particular compound in the sample.
The integration of a peak is a measure of the number of equivalent protons, which are contributing to that signal.
In this case, the integration value of borneol was 4.765, and the integration value of isoborneol was 3.374.
By dividing the integration value of isoborneol by the sum of both integrations, we can calculate the percentage of isoborneol present in the mixture. This value was 41.4%.
Overall, integration values are important when determining the relative amount of different compounds present in a sample.
In the case of Jeanette's experiment, she used an NMR spectrometer to determine the integration values of borneol and isoborneol, and calculated the percentage of isoborneol present in the sample to be 41.4%.
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which of the following is an appropriate use for reflux? to remove the solvent from a reaction mixture to carry out a reaction that needs heating to prepare a sample for filtration
A. to remove the solvent from a reaction mixture
What is a Flux?Flux is a term used to describe the flow of energy, particles, or material in a given area. It is typically used to describe the rate of flow of a certain substance, such as the rate of electrons flowing through a circuit.
Flux is also used to describe the concentration of a certain substance in a given area. For example, the amount of a particular chemical in an environment can be described as a flux. Flux is also used to describe the rate of change in a given system, such as the rate of temperature change in a room over time.
Finally, flux can refer to the rate at which energy is exchanged between two objects, such as the rate of heat exchange between two objects.
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what explains the key difference between a bomb calorimeter and a coffee cup calorimeter?
Answer:
The operation of a bomb calorimeter is similar to that of a coffee cup calorimeter, but there is one significant distinction: With a bomb calorimeter, the reaction occurs in a sealed metal container that is submerged in water in an insulated container.
Explanation:
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when 25.0 ml of 0.500 m agno3 solution is mixed with 40.0 ml of 0.250 m na2so4, solid ag2so4 precipitates out. what mass of ag2so4 is formed? (the molar mass of ag2so4 is 311.8 g/mol.)
The mass of [tex]Ag_2SO_4[/tex] precipitates out is 3.8975 g
We need to use the stoichiometry of the chemical reaction between [tex]AgNO_3[/tex] and [tex]Na_2SO_4[/tex] to determine how much [tex]Ag_2SO_4[/tex] will be formed. The balanced chemical equation for the reaction is:
[tex]AgNO_3 + Na_2SO_4[/tex] → [tex]Ag_2SO_4 + 2NaNO_3[/tex]
From the equation, we can see that one mole of [tex]AgNO_3[/tex] reacts with one mole of [tex]Na_2SO_4[/tex] to form one mole of [tex]Ag_2SO_4[/tex]. Therefore, the first step is to calculate how many moles of [tex]AgNO_3[/tex]and Na_2SO_4 are present in the solution.Moles of [tex]AgNO_3[/tex] = volume (in L) × molarity
= 0.025 L × 0.500 mol/L
= 0.0125 mol
Moles of [tex]Na_2SO_4[/tex] = volume (in L) × molarity
= 0.040 L × 0.250 mol/L
= 0.010 mol
Since the reaction is 1:1 between [tex]AgNO_3[/tex] and [tex]Na_2SO_4, AgNO_3[/tex]is the limiting reactant, and all of the [tex]AgNO_3[/tex] will react to form [tex]Ag_2SO_4[/tex].The number of moles of [tex]Ag_2SO_4[/tex] formed is equal to the number of moles of [tex]AgNO_3[/tex]:
Moles of Silver nitrate ([tex]Ag_2SO_4[/tex]) = 0.0125 mol
Calculate the mass of [tex]Ag_2SO_4[/tex]:
Mass of [tex]Ag_2SO_4[/tex]= moles of [tex]Ag_2SO_4[/tex] × molar mass
Mass of [tex]Ag_2SO_4[/tex] = 0.0125 mol × 311.8 g/mol
Mass of [tex]Ag_2SO_4[/tex] = 3.8975 g
Therefore, the mass of [tex]Ag_2SO_4[/tex] formed is 3.8975 g.
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