Answer:
0.61 V
Explanation:
a. The two metals in this voltaic cell are cadmium (Cd) and copper (Cu). Cadmium is oxidized (loses electrons) and copper is reduced (gains electrons).
b. Half-reactions:
Cathode: Cu2+(aq) + 2e- → Cu(s)
Anode: Cd(s) → Cd2+(aq) + 2e-
Overall reaction: Cd(s) + Cu2+(aq) → Cd2+(aq) + Cu(s)
c. The anode is where oxidation occurs, so the anode is the cadmium electrode. The cathode is where reduction occurs, so the cathode is the copper electrode.
d. Standard cell potential (Eᵒcell) can be calculated using the standard reduction potentials (Eᵒred) for each half-reaction.
Eᵒcell = Eᵒred(cathode) - Eᵒred(anode)
Eᵒred(Cu2+(aq) + 2e- → Cu(s)) = +0.34 V (from tables)
Eᵒred(Cd(s) → Cd2+(aq) + 2e-) = -0.40 V (from tables)
Eᵒcell = +0.34 V - (-0.40 V) = +0.74 V
e. The standard free energy change (ΔG°) can be calculated from the standard cell potential (Eᵒcell) using the following equation:
ΔG° = -nFEᵒcell
where n is the number of electrons transferred in the balanced equation (2), and F is the Faraday constant (96,485 C/mol).
ΔG° = -2 x 96,485 C/mol x 0.74 V = -141,800 J/mol = -141.8 kJ/mol
f. The cell diagram for this voltaic cell is:
Cd(s) | Cd(NO3)2 (0.10 M) || Cu(NO3)2 (0.20 M) | Cu(s)
g. The Nernst equation can be used to calculate the cell potential (E) under non-standard conditions, where the concentrations of the species involved are not at their standard state. The Nernst equation is:
E = Eᵒcell - (RT/nF) x ln(Q)
where R is the gas constant (8.314 J/mol-K), T is the temperature in Kelvin, n is the number of electrons transferred (2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient, which is the ratio of the concentrations of the products over the concentrations of the reactants raised to their stoichiometric coefficients.
At non-standard conditions, the concentrations of the species involved are:
[Cd2+] = 0.10 M
[Cu2+] = 0.20 M
The reaction quotient (Q) is:
Q = ([Cd2+]/[Cu2+])^2 = (0.10 M / 0.20 M)^2 = 0.25
Plugging in the values:
E = 0.74 V - (8.314 J/mol-K x 298 K / (2 x 96,485 C/mol)) x ln(0.25) = 0.61 V
Therefore, the cell potential at non-standard conditions is 0.61 V.
Balanced chemicsl equation CuSO4 + Na2SO4
Since Na2SO4 + 2CuSO4 = 2NaSO4 + Cu2SO4 has an equal number of each element in its reactants and products, the equation is balanced.
What is the reaction's balanced chemical equation?A chemical equation that is balanced has the same number of each type of atom on both sides of the equation. Subscripts are a component of the chemical formulas for the reactants and products that show how many atoms of the previous element there are in each.
What constitutes balancing a chemical equation in four steps?Count the atoms on each side first. Next, alter one of the compounds' coefficients. Finally, count the atoms once more, and then repeat steps two and three until the equation is balanced.
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You just worked on collecting evidence to answer the Investigation Question: How is something different when it is warmer or cooler? How did the experiment with the cold and warm water change your thinking about the Investigation Question?
My experiment with the cold and warm water changed my thinking about the Investigation Question because it showed me that the temperature of something can have a major impact on its properties.
Experiment with cold and warm waterFor example, warm water was more buoyant than cold water, which meant that the warmer water was able to float objects that the colder water could not. This showed me that temperature can play a role in the physical properties of an object, making it either lighter or heavier, depending on the temperature.
My experiment with cold and warm water showed me that temperature can have a major effect on physical properties. When comparing cold and warm water, I found that the warmer water was more buoyant and was able to float objects that the colder water could not.
This demonstrated to me how temperature can impact the weight and buoyancy of an object, making it either lighter or heavier depending on the temperature.
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SrBr2 + (NH4)2CO3
→ SrCO3 + NH4Br
Is this balanced? And if not how do I balance it?
Answer: No the equation is not balanced
Explanation:
Here's how to balance it:
SrBr2 + (NH4)2CO3 → SrCO3 + 2NH4Br
The balanced equation has 1 strontium atom, 2 bromine atoms, 1 carbon atom, 3 oxygen atoms, 4 hydrogen atoms, and 2 ammonium ions on both sides of the equation.
Answer:
No, the given equation is not balanced. The balanced equation is:
SrBr₂ + (NH₄)₂CO₃ → SrCO₃ + 2NH₄Br
Explanation:
A chemical equation is a representation of a chemical reaction using chemical formulas and symbols. It shows the reactant(s) on the left side of the equation and the product(s) on the right side of the equation, separated by an arrow that indicates the direction of the reaction.
[tex]\underbrace{\sf SrBr_2 + (NH_4)_2CO_3} \;\;\longrightarrow \;\;\underbrace{\sf SrCO_3 + NH_4Br}\\\sf \phantom{ww.w}Rectant(s) \qquad \qquad \quad \quad Product(s)[/tex]
A balanced chemical equation has the same number of atoms of each element on both sides of the equation.
Coefficients are used to balance chemical equations and are placed in front of a chemical symbol or formula where needed.
Given chemical equation:
[tex]\sf SrBr_2 + (NH_4)_2CO_3 \;\;\longrightarrow \;\; SrCO_3 + NH_4Br[/tex]
Here, we need to balance the number of Sr, Br, N, H, C, and O atoms.
Check to see if there are the same number of atoms of each element on both sides of the equation:
[tex]\begin{array}{|l|c|c|c|c|c|c|}\cline{1-7}\vphantom{\dfrac12}\sf &Sr&Br&N&H&C&O\\\cline{1-7}\vphantom{\dfrac12}\sf Reactant&1&2&2&8&1&3\\\cline{1-7}\vphantom{\dfrac12}\sf Product&1&1&1&4&1&3\\\cline{1-7}\end{array}[/tex]
We can see that there are two bromine atoms on the left but only one on the right, so a coefficient of 2 needs to be added to NH₄Br on the right side of the equation:
[tex]\sf SrBr_2 + (NH_4)_2CO_3 \;\;\longrightarrow \;\; SrCO_3 + 2NH_4Br[/tex]
By adding the coefficient 2 to NH₄Br on the right side of the equation, the number of N, H and Br atoms on this side have been multiplied by 2. So we now have:
[tex]\begin{array}{|l|c|c|c|c|c|c|}\cline{1-7}\vphantom{\dfrac12}\sf &Sr&Br&N&H&C&O\\\cline{1-7}\vphantom{\dfrac12}\sf Reactant&1&2&2&8&1&3\\\cline{1-7}\vphantom{\dfrac12}\sf Product&1&2&2&8&1&3\\\cline{1-7}\end{array}[/tex]
As there are now the same number of atoms of each element on both sides of the equation, it is balanced.
Therefore, the balanced chemical equation is:
[tex]\sf SrBr_2 + (NH_4)_2CO_3 \;\;\longrightarrow \;\; SrCO_3 + 2NH_4Br[/tex]
*I’m confused? Pls help, it’s due tmr*
Modeling Tool: Two Samples at the Atomic Scale
Goal: Create a model that represents a repeating group of atoms that could make up sample 2.
Based on the given information, it seems like we need help with creating a model of a repeating group of atoms for sample 2 using an atomic scale modeling tool. Here's an answer that includes the terms:
To create a model that represents a repeating group of atoms for sample 2, you should use the modeling tool at the atomic scale. Start by identifying the elements and their arrangement within the sample. Once you have this information, construct the repeating unit of atoms in the modeling tool, ensuring you accurately represent the positions, types, and bonding of the atoms involved. This model will help you visualize and better understand the structure of sample 2 at the atomic level.
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What is the pH of a solution with an H+ ion concentration of 2.5e-4?
Answer: pH=-log[H+]
pH=-log(2.5x10^-4)
pH=3.6
Explanation:
Determine the enthalpy of reaction for HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s) 2NaCl(s) + H₂O(l) → 2HCl(g) + Na₂O(s) ∆H° = -507.1 kJ/mol NO(g) + NO₂(g) + Na₂O(s) → 2NaNO₂(s) ∆H° = -427.0 kJ/mol NO(g) + NO₂(g) → N₂O(g) + O₂(g) ∆H° = -43.01 kJ/mol 2HNO₂(l) → N₂O(g) + O₂(g) + H₂O(l) ∆H° = +34.02 kJ/mol
the enthalpy of reaction for HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s) 2NaCl(s) + H₂O(l) → 2HCl(g) + Na₂O(s) ∆H° = -507.1 kJ/mol NO(g) + NO₂(g) + Na₂O(s) → 2NaNO₂(s) ∆H° = -427.0 kJ/mol NO(g) + NO₂(g) → N₂O(g) + O₂(g) ∆H° = -43.01 kJ/mol 2HNO₂(l) → N₂O(g) + O₂(g) + H₂O(l) ∆H° = +34.02 kJ/mol the enthalpy of reaction for the given reaction is -39.1 kJ/mol.
We can use the given reactions and their enthalpies to find the enthalpy of reaction for the given equation.
The given equation is:
HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s)
We can break down this reaction into several steps using the given reactions as follows:
Na₂O(s) + 2HCl(g) → 2NaCl(s) + H₂O(l) (reverse of the given reaction)
∆H° = +507.1 kJ/mol (reverse the sign of given reaction)
2NaCl(s) + H₂O(l) → Na₂O(s) + 2HCl(g)
∆H° = -507.1 kJ/mol (given reaction)
NO(g) + NO₂(g) + Na₂O(s) → 2NaNO₂(s)
∆H° = -427.0 kJ/mol (given reaction)
2HNO₂(l) → N₂O(g) + O₂(g) + H₂O(l)
∆H° = +34.02 kJ/mol (given reaction)
NO(g) + NO₂(g) → N₂O(g) + O₂(g)
∆H° = -43.01 kJ/mol (given reaction)
Now, we can add these equations and their enthalpies to get the overall enthalpy of the given reaction:
HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s)
H₂O(l) + 2NaCl(s) → Na₂O(s) + 2HCl(g) ∆H° = -507.1 kJ/mol
Na₂O(s) + NO(g) + NO₂(g) → 2NaNO₂(s) ∆H° = -427.0 kJ/mol
2HNO₂(l) → N₂O(g) + O₂(g) + H₂O(l) ∆H° = +34.02 kJ/mol
NO(g) + NO₂(g) → N₂O(g) + O₂(g) ∆H° = -43.01 kJ/mol
HCl(g) + NaNO₂(s) → HNO₂(l) + NaCl(s) ∆H° = -39.1 kJ/mol
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Balance
Pb(NO3)2 + NaCl PbCl2+ NaNO3
The balanced chemical equation for the reaction between Pb(NO3)2 and NaCl is:
Pb(NO3)2 + 2NaCl -> PbCl2 + 2NaNO3
In order for a chemical equation to be balanced, the number of atoms of each element in the reactants must be equal to the number of atoms of each element in the products.
In the given equation, there are one Pb atom, two Na atoms, two Cl atoms, two N atoms, and six O atoms on the left-hand side (reactants) of the equation. On the right-hand side (products) of the equation, there are one Pb atom, two Na atoms, two Cl atoms, two N atoms, and six O atoms.
To balance the equation, we need to adjust the coefficients (the numbers in front of the chemical formulas) so that the number of atoms of each element is the same on both sides. In this case, we need to add a coefficient of 2 in front of NaCl on the reactant side to balance the number of Cl atoms, which also adds 2 Na and 2 NO3 atoms. This gives us:
Pb(NO3)2 + 2NaCl -> PbCl2 + 2NaNO3
Now the equation is balanced because there are the same number of atoms of each element on both the reactant and product sides.
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Consider the incomplete structure. Add formal charges as necessary to the structure. All unshared valence electrons are shown. Do not alter the structure‑just add charges. If you need to revert the drawing palette to the original state, select the More menu, then select Reset Drawing.
The net formal charge on the given species ([tex]ClO_4[/tex]) is -1. From the diagram we can see that each oxygen atom has 3 pair of electrons and remaining are shared with the chlorine atom.
A charged species is a species that has an unequal number of protons and electrons, resulting in an overall charge. Examples of charged species include ions, radicals, and polar molecules. Ions are atoms or molecules that have gained or lost one or more electrons, resulting in a net charge while radicals are molecules or ions with an unpaired electron, resulting in a net charge.
Formal charge is calculated as = total number of valence electrons in free atom - number of non-bonding electrons - 1/2 (number of bonding electrons).
Free atom is chlorine with 7 valence electrons.
Oxygen has 8 electrons which are in pairs so, non-bonding electrons = 0
Number of bonding electrons = 14
formal charge on chlorine = 7 - 0 - 1/2(14) = 0
Formal charge on three oxygen atoms = 6 - 4 - 1/2(4) = 0
Formal charge on fourth oxygen atom = 6 - 6 - 1/2(2) = -1
net charge = 0 + 0 + (-1) = -1
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Write the formula of the hemiacetal
product when
CH3-CH₂-CH₂-CH₂-CHO
reacts with CH₂CH₂OH. Also, write the
acetal product.
When CH3-CH2-CH2-CH2-CHO (butyraldehyde) reacts with CH2CH2OH (ethylene glycol), a hemiacetal is formed.
The reaction can be written as:
CH3-CH2-CH2-CH2-CHO + CH2CH2OH → CH3-CH2-CH(OH)-CH2-CH2OH
The hemiacetal product is CH3-CH2-CH(OH)-CH2-CH2OH.
If the reaction continues, a second molecule of ethylene glycol can react with the hemiacetal to form an acetal:
CH3-CH2-CH(OH)-CH2-CH2OH + CH2CH2OH → CH3-CH2-CH(OC2H4)-CH2-CH2OH + H2O
The acetal product is CH3-CH2-CH(OC2H4)-CH2-CH2OH.
What is a molecule ?Molecules can exist in different states, including gases, liquids, and solids. The physical and chemical properties of a molecule are determined by the types of atoms it contains, the way the atoms are arranged, and the types of chemical bonds between them. The study of molecules and their properties is an important area of chemistry and plays a crucial role in many areas of science and technology, including materials science, pharmaceuticals, and biochemistry.
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to lower the impacts of climate change we can do the following activities:
1
2
3
4
5
science plss help
Answer:
1. Know your carbon footprint.
2. Travel less.
3. Eat less meat and focus on sustainably grown meat.
4. Create less waste.
5. Recycle more and create less trash.
ASAP PLEASE!!!2. Evidence: Use the Element symbol provided to create a Bohr/ Orbital Model for
each. Use the PhET simulation to work through each. Complete the table below.
Include a picture of each that you either snip from the simulation or draw. Include the
I
Physical Science B 11-1C Lab Periodic Trends
information to complete the last 3 columns. Use the simulation for subatomic particles
and location. Use the periodic table to determine if it is a metal, nonmetal or metalloid.
The highlighted boxes have been done for you as examples.
(4 points)
Metals are typically solid at room temperature, have a shiny or metallic appearance, are good conductors of heat and electricity, and are malleable and ductile.
Nonmetals, on the other hand, can exist in all three states of matter at room temperature, are generally not shiny, and are poor conductors of heat and electricity. They tend to be brittle and cannot be easily drawn into wires or hammered into thin sheets.
Metalloids have properties that fall somewhere between those of metals and nonmetals. They may have a shiny or dull appearance, and their ability to conduct heat and electricity is generally between that of metals and nonmetals.
The position of an element in the periodic table can give you some clues about its classification. Metals are typically found on the left side and middle of the periodic table, nonmetals are found on the right side, and metalloids are located along the "stair-step" line that separates the metals and nonmetals.
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Round your answer to the nearest hundredth.
A right triangle A B C. Angle A C B is a right angle. Angle A B C is twenty degrees. Side B C is unknown. Side A C is four units.
The length of the side BC in the right triangle is 3.76 units.
How to find the length of side BC?We want to find the length of the side BC, for the right triangle ABC.
We know that:
ACB = 90°
ABC = 20°
AC = 4 units.
Now we need to use trigonometric relations to find BC, we can use the relation:
cos(a) = adjacent cathetus/hypotenuse
Replacing what we know we will get:
cos(20°) =BC/4
4*cos(20°) = BC = 3.76
That is the length.
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Give the conjugate acid of the following Bronsted-Lowry bases. (Type your answer using the format [OH]- for OH -.)
What is the conjugate acid of C7H5O2-
Answer:
The conjugate acid of a Bronsted-Lowry base is the species formed when it accepts a proton (H+).
C7H5O2- is a base because it can accept a proton to form its conjugate acid. To find the conjugate acid of C7H5O2-, we add a proton to it. The proton will bond with one of the oxygen atoms, and the resulting species will be:
C7H5O2H
Therefore, the conjugate acid of C7H5O2- is C7H5O2H.
Drag each label to the correct location on the chart.
Sort the activities based on whether they decrease or maintain biodiversity.
planting more trees
excessive mining to
obtain minerals
releasing sewage
water into lakes
prohibiting fishing
during breeding
season
Reset Next
Reduce biodiversity: dumping sewage water into lakes as a result of excessive mining for minerals. Increase tree planting and ban fishing during the mating season to preserve biodiversity.
What steps may be taken to preserve biodiversity?Encourage regional and local initiatives to combat biodiversity loss and promote its prevention. acquiring fewer products while ensuring that the ones you do purchase have a minimal impact on biodiversity. Investing in initiatives to advance biodiversity. Reducing waste of consumer products, including food, clothing, electrical equipment, and others can help to prevent the loss of biodiversity.
What examples of biodiversity are there?The majority of people understand biodiversity as a collection of distinct living things that are capable of breeding with one another. Examples of species include white-tailed deer, blue whales, sunflowers, white pine trees, and microscopic germs that are so small they cannot even be seen with the human eye.
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write a brief statement that refers to the purpose of the experiment
Purpose: To find Heat of Solution of sodium hydroxide and to find the heat of neutralization between sodium hydroxide and hydrochloric acid, using enthalpy, Qsurr & Qrxn, percent error, etc.
experiment 1 findings:
50mL water
2.00g of sodium hydroxide
T (temp) initial = 20 degrees C
T (temp) final = 28.5 degrees C
experiment 2 findings:
50mL of 0.75 concentration M HCl
T (temp) initial = 23.5 degrees C
T (temp) final = 27 degrees C
The experiment involved measuring the temperature changes of water and solutions containing sodium hydroxide and hydrochloric acid.
What is HCl?
HCl is the chemical formula for hydrogen chloride, a colorless, highly pungent gas. It is a strong acid that is commonly used in industry for a variety of applications, such as the production of PVC, food processing, and metal cleaning. It is also found naturally in the stomach as a component of gastric acid, where it aids in digestion. In water, HCl dissociates into H+ and Cl- ions, making it a strong electrolyte.
The purpose of the experiment was to determine the heat of solution of sodium hydroxide and the heat of neutralization between sodium hydroxide and hydrochloric acid, using various methods such as enthalpy, Qsurr & Qrxn, percent error, etc.
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Aspirin is produced by the reaction of salicylic acid (M = 138.1 g/mol) and acetic anhydride (M = 102.1 g/mol).
C7H6O3(s) + C4H6O3() → C9H8O4(s) + C2H4O2()
If the theoritical yield of aspirin is 3.95 g and the actual yield is 2.04 g what is the percent yield?
The percent yield of aspirin is 51.6%.
What is the theoretical yield of aspirin in grams, given the reaction produced 10.0 g of salicylic acid and 5.0 g of acetic anhydride?The limiting reagent is salicylic acid, and the theoretical yield of aspirin is 12.2 g.
If the actual yield of aspirin in the above scenario is 8.9 g, what is the percent yield?The percent yield of aspirin is 72.9%.
The theoretical yield of aspirin is 3.95 g, but the actual yield is 2.04 g.
The percent yield can be calculated using the formula:
percent yield = (actual yield / theoretical yield) x 100%
Substituting the values given in the question, we get:
percent yield = (2.04 g / 3.95 g) x 100%
percent yield = 51.6%
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what is parallax errors sometimes called
Answer: They are sometimes called sighting errors
Explanation:
Need help with problem
The number of moles of CO in the given conditions is 2.51 moles. To calculate the number of moles of CO in the given conditions, we need to use the Ideal Gas Law equation:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
First, we need to convert the given temperature in Celsius to Kelvin by adding 273.15:
T = 93°C + 273.15 = 366.15 K
Now we can plug in the values we have:
P = 4.52 atm
V = 20.0 L
R = 0.0821 L.atm/mol.K (gas constant for CO)
T = 366.15 K
n = PV/RT = (4.52 atm x 20.0 L)/(0.0821 L.atm/mol.K x 366.15 K) = 2.51 moles
Therefore, the number of moles of CO in the given conditions is 2.51 moles.
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Silicon nitride is a very hard, high-temperature-
resistant ceramic used as a component of
turbine blades in jet engines. It is prepared
according to the following equation:
3Si(s) + 2N₂(g) → Si3 N4(S)
Which is the limiting reactant when 2.00 g of Si
and 1.50 g of N₂ react?
The limiting reactant when 2.00 g of Si and 1.50 g of N₂ react is Silicon (Si).
When two reactive compounds are mixed, then they react according to the stoichiometry of the balanced chemical equation between them. The reactant which is present in excess will be left unreacted after the completion of the reaction whereas the other corresponding reactant will name as the limiting reagent of the reaction.
The molar mass of Si and N₂ is 28.08 g/mol and 28 g/mol.
The stoichiometry in which Si and N₂ is 3:2.
The mass of Si required to react with 1.50 g of N₂ is calculated as follows:
m(Si) = (3 × 28.08 g) / (2×28 g) × 1.50 g = 2.25 g
Since the calculated mass of Si is more than the given mass. Therefore we can say that Si is a limiting reagent.
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How many bromine atoms are present 35.2 g of CH2Br2?
Can someone explain how to get answers with steps.
Answer:
There are approximately 2.448 x 10^23 bromine atoms present in 35.2 g of CH2Br2.
Explanation:
The molar mass of CH2Br2 can be calculated as follows:
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of 2 Br = 2 x 79.90 g/mol = 159.80 g/mol
Therefore, the molar mass of CH2Br2 = 12.01 + 1.01 + 159.80 = 172.82 g/mol
Next, we can calculate the number of moles of CH2Br2 as follows:
moles of CH2Br2 = mass of CH2Br2 / molar mass of CH2Br2
moles of CH2Br2 = 35.2 g / 172.82 g/mol
moles of CH2Br2 = 0.203 moles
Finally, we can use Avogadro's number to calculate the number of bromine atoms present:
Number of bromine atoms = moles of CH2Br2 x 2 (since there are 2 bromine atoms per molecule of CH2Br2) x Avogadro's number
Number of bromine atoms = 0.203 x 2 x 6.022 x 10^23
Number of bromine atoms = 2.448 x 10^23 bromine atoms
Therefore, there are approximately 2.448 x 10^23 bromine atoms present in 35.2 g of CH2Br2.
how many grams of no gas are there in a 5.00-l cylinder at 4.00 × 103 mm hg and 23°c
There are 32.1 grams of NO gas in the cylinder if a 5.00-l cylinder at 4.00 × 103 mm hg and 23°c.
To determine the number of grams of NO gas in a 5.00 L cylinder at [tex]4.00 × 10^3[/tex] mmHg and 23°C, we can use the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
First, we need to convert the pressure to atmospheres and the temperature to Kelvin:
4.00 × [tex]10^3[/tex] mmHg = 5.26 atm (1 atm = 760 mmHg)
23°C = 296 K
Now we can rearrange the ideal gas law to solve for n:
n = PV/RT
n = (5.26 atm)(5.00 L)/(0.0821 L·atm/mol·K)(296 K) = 1.07 mol
Finally, we can convert from moles to grams using the molar mass of NO:
1.07 mol NO × 30.01 g/mol = 32.1 g NO
Therefore, there are 32.1 grams of NO gas in the cylinder.
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What is the final volume of NaOH solution prepared from 250.0 mL of 0.300 M NaOH if you wanted the final concentration to be 0.150 M ?
The final volume of the NaOH solution is 500.0 mL.
To prepare a solution with a desired concentration, we can use the formula:
C = n/V
where C is the concentration in units of moles per liter (M), n is the number of moles of solute, and V is the volume of the solution in liters. Rearranging this formula, we get:
n = C x V
This formula tells us that we can find the number of moles of solute we need by multiplying the desired concentration (C) by the desired volume (V) of the solution.
To calculate the final volume of the NaOH solution, we can use the following equation:
M1V1 = M2V2
where M1 and V1 are the initial concentration and volume, respectively, and M2 and V2 are the final concentration and volume, respectively.
Substituting the given values into the equation, we get:
(0.300 M) (250.0 mL) = (0.150 M) (V2)
Solving for V2, we get:
V2 = (0.300 M × 250.0 mL) / (0.150 M)
V2 = 500.0 mL.
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A doctor orders 7 mg of compazine, which is used to treat nausea, vertigo, and migraine headaches. If the stock solution is 2.5 % (m/v), how many milliliters are administered to the patient?
Calculate the final volume of a baloon If It has a volume of 2.0L and pressure of 2 atmosphere and the pressure is reduced to I atmospher 1,Assume temperature remains
Answer: 4 L
Explanation:
Boyle's law states that [tex]P_1V_1=P_2V_2[/tex]Since no values other than pressure and volume change, we will use this equation.
Given in the problem we know:
[tex]P_1=2\\V_1=2.0\\P_2=1[/tex]
So, we are left with one variable to solve for.
[tex]2*2.0=1*V_2\\V_2=4 L[/tex]
A 5.00-L tank contains helium gas at 1.50 atm. What is the pressure of the gas when the volume increased to 4.5atm?
Answer:
the pressure of the gas is 1.67 atm when the volume increased to 4.5 L.
Explanation:
Assuming the temperature and the amount of gas remain constant (i.e., the process is isobaric):
Using Boyle's law, we can relate the initial pressure (P1) and volume (V1) to the final pressure (P2) and volume (V2):
P1V1 = P2V2
Plugging in the given values:
P1 = 1.50 atm
V1 = 5.00 L
V2 = 4.5 L
Solving for P2:
P2 = (P1V1)/V2 = (1.50 atm x 5.00 L)/4.5 L = 1.67 atm
If you are given 5 moles of NaNO, how many moles of HNO, would be produced?
5 Moles of HNO₂ is produced from 5 moles of NaNO. This is taken out by molar reaction and stochiometric coefficients .
What are moles ?
A mole, like all units, must be defined or founded on something reproducible. The mole's current definition is defined, but it was previously based on the amount of atoms in a sample of the isotope carbon-12. A mole is now defined as Avogadro's number of elements, which is 6.02214076 × 10²³. For all practical purposes, one mole of a compound in grams is roughly equivalent to one molecule of the compound in Daltons.
Originally, a mole was defined as the amount of anything that contains the same number of elements as 12.000 grams of carbon-12. That number of elements is known as Avogadro's Number, which is approximately 6.02x10²³. 6.02x10²³carbon atoms constitute a mole.
Since the reaction of NaNO and HNO₂ is a 1:1 ratio, 5 moles of NaNO would produce 5 moles of HNO₂.
NaNO + HNO₂ → NaNO₂
The balanced equation for the reaction is:
2 NaNO + HNO₂ → 2 NaNO2
Therefore, if you start with 5 moles of NaNO, 5 moles of HNO₂ will be produced.
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6. Which substance is soluble in water?
A. Pb(CO3)2
B. Ag3PO4
C. Sn(CrO4)2
D. NH4CI
Substance is soluble in water is D. NH₄CI. Soluble in water means that is capable of dissolving in water.
What does soluble in water mean?Substance is soluble if it dissolves in certain fluids and the fluid [gas or liquid] (present in excess) is called solvent and substance dissolved in it is called solute which together forms solution. Process of dissolving is called the solvation.
If substance is soluble, then it implies that it can be dissolved in liquid. This means particles are broken down to become so small that we can no longer see them. Salt and sugar are examples of soluble materials. Opposite of soluble is insoluble ( that is a substance that cannot be dissolved).
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ASAP!!!!1. Claim: How are elements arranged on the periodic table in terms of valence
electrons?
Elements on the periodic table are arranged in order of increasing atomic number.
Arrangement of element in the Periodic tableThis means that elements with lower atomic numbers have fewer valence electrons compared to elements with higher atomic numbers.
The elements are arranged into columns, or groups, based on the number of valence electrons they possess.
Elements in the same group generally have the same number of valence electrons, and elements in the same period (row) generally have one more valence electron than the element before it.
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We wish to determine the moles of carbon dioxide
produced when 50.0 mL of 2.0 M hydrochloric
acid reacts with excess sodium carbonate.
2HCl(aq) + Na₂CO3(aq) → 2NaCl(aq) + H₂O(1) + CO₂(g)
->
In the previous step, you determined
0.10 mol HCI react.
How many moles of carbon dioxide form during
the reaction?
Moles CO₂
Enter
Answer: .05
Explanation:
What is the average experimental volume per mole of carbon dioxide calculated for sodium carbonate and sodium bicarbonate?
Answer: 24.356L/mol.
Explanation: Hence, the average experimental volume per mole of carbon dioxide for sodium carbonate and sodium bicarbonate is 24.356L/mol.