An estimate of 20 people took longer than 325 minutes to complete the race.
To estimate the number of people who took longer than 325 minutes to complete the race, we need to use the cumulative frequency distribution.
The cumulative frequency of a class interval is obtained by adding up the frequencies of all the class intervals up to and including that interval. The sum of the frequencies for each class interval is known as the cumulative frequency.In this case, the cumulative frequency distribution is given as follows:
Class Interval | Frequency | Cumulative Frequency250 - 200 | 5 | 5200 - 150 | 12 | 12150 - 100 | 18 | 30100 - 50 | 11 | 4050 - 0 | 4 | 44Total: 50
Now, to estimate the number of people who took longer than 325 minutes to complete the race, we need to look at the cumulative frequency that corresponds to 325 minutes.
From the table, we can see that the cumulative frequency of the class interval 300-400 minutes is 30. This means that 30 people took between 100 and 400 minutes to complete the race.
Therefore, the number of people who took longer than 325 minutes is the difference between the total number of people who took between 100 and 500 minutes and the number of people who took between 100 and 325 minutes. This can be calculated as follows:50 - 30 = 20.
Hence, an estimate of 20 people took longer than 325 minutes to complete the race.
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The probable question may be:
Estimate the number of people who took longer than 325 minutes to complete the race, given the following cumulative frequency distribution:
Cumulative frequency:
250-
200-
150-
100-
50-
0
Time to complete a race:
100 200 300 400 500
Time (minutes).
NO LINKS!!! URGENT HELP PLEASE!!!
Please help with #15
Answer:
area = 8π/3
arc length = 4π/3
Step-by-step explanation:
θ = 60°
r = 4
Area of sector :
[tex]\frac{\theta}{360} \pi r^{2} \\\\=\frac{60}{360} \pi 4^{2} \\\\= \frac{1}{6} 16\pi \\\\= \frac{8}{3} \pi[/tex]
arc length:
[tex]\frac{\theta}{360} 2\pi r\\ \\= \frac{60}{360} 2(4)\pi \\\\= \frac{1}{6} 8\pi \\\\= \frac{4}{3} \pi[/tex]
Answer:
A ≈ 8.4 cm² , arc length ≈ 4.2 cm
Step-by-step explanation:
the area (A) of the sector is calculated as
A = area of circle × fraction of circle
= πr² × [tex]\frac{60}{360}[/tex] ( r is the radius of the circle )
= π × 4² × [tex]\frac{1}{6}[/tex]
= [tex]\frac{16\pi }{6}[/tex]
≈ 8.4 cm² ( to 1 decimal place )
arc length is calculated as
arc = circumference of circle × fraction of circle
= 2πr × [tex]\frac{60}{360}[/tex]
= 2π × 4 × [tex]\frac{1}{6}[/tex]
= [tex]\frac{8\pi }{6}[/tex]
≈ 4.2 cm ( to 1 decimal place )
Five angels of a hexagon are 123,124,118,130’110. Calculate the six angle
Answer:
The sixth angle is 115°.
Step-by-step explanation:
Number of sides in a hexagon = n =6
Sum of interior angles = (n−2)180°
= (6−2)180 ∘
= 720
∴ Let the six angle of hexagon be x.
⇒ x + 123 + 124 + 118 + 130 + 110 = 720°
⇒ x + 605 = 720°
⇒ x = 720 - 605
⇒ x = 115
guys give examples of cylinder volume word problems pls
The volume of a cylinder is given by the equation presented as follows:
V = πr²h.
In which:
r is the radius.h is the height.How to obtain the volume of the cylinder?The volume of a cylinder of radius r and height h is given by the equation presented as follows:
V = πr²h.
Hence the measures must be identified and have it's values replaced into the formula to obtain the volume of a cylinder.
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Let X and Y have joint pdf .
a. Compute P(X < 1/2 Ç Y > 1/4).
b. Derive the marginal pdfs of X and Y.
c. Are X and Y independent? Show some calculations in support of your answer.
d. Derive f(x|y) = {the conditional pdf of X given Y=y}
Answer:
To answer the questions, I'll assume that you're referring to continuous random variables X and Y. Let's go through each part:a. To compute P(X < 1/2 ∩ Y > 1/4), we integrate the joint probability density function (pdf) over the given region:P(X < 1/2 ∩ Y > 1/4) = ∫∫ f(x, y) dx dyb. To derive the marginal pdfs of X and Y, we integrate the joint pdf over the other variable. The marginal pdf of X can be obtained by integrating the joint pdf over Y:fX(x) = ∫ f(x, y) dySimilarly, the marginal pdf of Y can be obtained by integrating the joint pdf over X:fY(y) = ∫ f(x, y) dxc. To determine if X and Y are independent, we need to check if the joint pdf can be expressed as the product of the marginal pdfs:f(x, y) = fX(x) * fY(y)If this condition holds, X and Y are independent.d. The conditional pdf of X given Y = y can be derived using the joint pdf and the marginal pdf of Y:f(x|y) = f(x, y) / fY(y)By substituting the values from the given joint pdf, we can obtain the conditional pdf of X given Y = y.Please provide the specific joint pdf for X and Y, and I'll be able to assist you further with the calculations.Hope this help youThe marginal pdf of X is fX(x) = x + 1/2
How do you compute P(X < 1/2, Y > 1/4)?We need to integrate the joint pdf over the given region. This can be done as follows:
P(X < 1/2, Y > 1/4) = ∫∫[x + y] dx dy over the region 0 ≤ x ≤ 1/2 and 1/4 ≤ y ≤ 1
= ∫[x + y] dy from y = 1/4 to 1 ∫ dx from x = 0 to 1/2
= ∫[x + y] dy from y = 1/4 to 1 (1/2 - 0)
= ∫[x + y] dy from y = 1/4 to 1/2 + ∫[x + y] dy from y = 1/2 to 1 (1/2 - 0)
= ∫[x + y] dy from y = 1/4 to 1/2 + ∫[x + y] dy from y = 1/2 to 1/2
= ∫[x + y] dy from y = 1/4 to 1/2
= [(x + y)y] evaluated at y = 1/4 and y = 1/2
= [(x + 1/2)(1/2) - (x + 1/4)(1/4)]
= (1/2 - 1/4)(1/2) - (1/4 - 1/8)(1/4)
= (1/4)(1/2) - (1/8)(1/4)
= 1/8 - 1/32
= 3/32
Therefore, P(X < 1/2, Y > 1/4) = 3/32.
The marginal pdfs of X and Y can be done as follows:
For the marginal pdf of X:
fX(x) = ∫[x + y] dy over the range 0 ≤ y ≤ 1
= [xy + (1/2)y^2] evaluated at y = 0 and y = 1
= (x)(1) + (1/2)(1)^2 - (x)(0) - (1/2)(0)^2
= x + 1/2
Therefore, the marginal pdf of X is fX(x) = x + 1/2.
For the marginal pdf of Y:
fY(y) = ∫[x + y] dx over the range 0 ≤ x ≤ 1
= [xy + (1/2)x^2] evaluated at x = 0 and x = 1
= (y)(1) + (1/2)(1)^2 - (y)(0) - (1/2)(0)^2
= y + 1/2
Therefore, the marginal pdf of Y is fY(y) = y + 1/2.
To determine if X and Y are independent, we need to check if the joint pdf factors into the product of the marginal pdfs.
fX(x) * fY(y) = (x + 1/2)(y + 1/2)
However, this is not equal to the joint pdf f(x, y) = x + y. Therefore, X and Y are not independent.
To derive the conditional pdf of X given Y = y, we can use the formula:
f(xy) = f(x, y) / fY(y)
Here, we have f(x, y) = x + y from the joint pdf, and fY(y) = y + 1/2 from the marginal pdf of Y.
Therefore, the conditional pdf of X given Y = y is:
f(xy) = (x + y) / (y + 1/2)
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A rotation of a figure can be considered
A rotation is a geometric transformation that preserves the shape and size of a figure while changing its orientation in space. It is a fundamental concept in geometry and is used in various fields, including art, design, and engineering.
A rotation of a figure can be considered as a transformation that rotates the figure around a fixed point, known as the center of rotation. During the rotation, each point of the figure moves along an arc around the center, maintaining the same distance from the center.
To perform a rotation, we specify the angle of rotation and the direction (clockwise or counterclockwise). The center of rotation remains fixed while the rest of the figure rotates around it. The resulting figure is congruent to the original figure, meaning they have the same shape and size but may be in different orientations.
Rotations are commonly described using positive angles for counterclockwise rotations and negative angles for clockwise rotations. The magnitude of the angle determines the amount of rotation. For example, a 90-degree rotation would result in the figure being turned a quarter turn counterclockwise.
In general, a rotation is a geometric transformation that keeps a figure's size and shape while reorienting it in space. It is a fundamental idea in geometry that is applied in a number of disciplines, including as engineering, design, and the arts.
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What is the vertex for the graph of v - 3 = - (x+2)^2
The vertex for the graph of the equation [tex]v - 3 = - (x+2)^2 is (-2, 3).[/tex]
To find the vertex of the graph of the equation [tex]v - 3 = - (x+2)^2,[/tex] we can rewrite it in the standard vertex form: [tex]v = a(x - h)^2 + k,[/tex]
where (h, k) represents the vertex coordinates.
First, let's rearrange the given equation:
[tex]v - 3 = - (x+2)^2[/tex]
[tex]v = - (x+2)^2 + 3[/tex]
Comparing this with the standard vertex form, we can see that h = -2 and k = 3.
Therefore, the vertex of the graph is (-2, 3).
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John can ride his bide 4 miles in 30
minutes. At his current rate, what is the
distance, in miles, John can ride his
bike in 12 minutes?
The distance John can ride his bike in 12 minutes is approximately 1.6 miles.
To find out the distance John can ride his bike in 12 minutes, we can use the information given about his rate of riding.
We are told that John can ride his bike 4 miles in 30 minutes. This implies that his rate of riding is 4 miles per 30 minutes.
To calculate the distance John can ride in 12 minutes, we need to determine the proportion of time he is riding compared to the given rate.
We can set up a proportion to solve for the unknown distance:
(4 miles) / (30 minutes) = (x miles) / (12 minutes)
Cross-multiplying, we get:
30 minutes * x miles = 4 miles * 12 minutes
30x = 48
Now, we can solve for x by dividing both sides of the equation by 30:
x = 48 / 30
Simplifying the fraction, we have:
x = 8/5
So, John can ride his bike approximately 1.6 miles in 12 minutes, at his current rate.
Therefore, the distance John can ride his bike in 12 minutes is approximately 1.6 miles.
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Please answer ASAP I will brainlist
The system has no solution. Option C is correct.
To solve the given system of equations using row operations, we can write the augmented matrix and perform Gaussian elimination. The augmented matrix for the system is:
1 1 -1 | 6
3 -1 1 | 2
1 4 2 | -34
We'll use row operations to transform the augmented matrix into row-echelon form or reduced row-echelon form. Let's proceed with the row operations:
R2 = R2 - 3R1:
1 1 -1 | 6
0 -4 4 | -16
1 4 2 | -34
R3 = R3 - R1:
1 1 -1 | 6
0 -4 4 | -16
0 3 3 | -40
R3 = R3 + (4/3)R2:
1 1 -1 | 6
0 -4 4 | -16
0 0 0 | -4
Now, we can rewrite the augmented matrix in equation form:
x + y - z = 6
-4y + 4z = -16
0 = -4
From the last equation, we can see that it leads to a contradiction (0 = -4), which means the system is inconsistent. Therefore, the system has no solution.
The correct answer is (C) This system has no solution.
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Suppose for 40 observations, the variance is 50. If all the observations are increased by 20, the variance of these increased observation will be
Select one:
a. 50
b. 70
c. 50/20
d. 40
e. 50-20=30
Note: Answer D is NOT the correct answer. Please find the correct answer. Any answer without justification will be rejected automatically.
Answer:
a) 50
Step-by-step explanation:
The variance will not change as all the observations are increased uniformly.
Proof:
Variance formula:
[tex]s^{2} = \frac{\sum x_i^{2} }{n} -\frac{(\sum x_i)^{2} }{n^{2} }[/tex]
When the obervations are inc by 20,
[tex]s_1^{2} = \frac{\sum (x_i + 20)^{2} }{n} -\frac{(\sum (x_i + 20))^{2} }{n^{2} }\\\\=\frac{\sum(x_i^{2} + 2*20*x_i + 20^{2} )}{n} - \frac{(\sum x_i +20n)^{2} }{n^{2} } \\\\=\frac{\sum x_i^{2} + 40\sum x_i + 20^{2}n }{n} - \frac{(\sum x_i)^{2} +2*20n\sum x_i + 20^{2} n^{2} }{n^{2} } \\\\= \frac{\sum x_i^{2}}{n} - \frac{(\sum x_i)^{2}}{n^{2} } +\frac{40\sum x_i}{n} + 20^{2} - \frac{40\sum x_i}{n} - 20^{2}\\\\s_1^{2}= \frac{\sum x_i^{2}}{n} - \frac{(\sum x_i)^{2}}{n^{2} }\\\\=s^{2}[/tex]
Therefore variance doesn't change
To bake some cakes, a baker used 40g of strawberries for every220g of flour. If the total amount of strawberries and flour that the baker used was 1040g, what was the amount of flour the baker used?
Answer:
880g of flour
Step-by-step explanation:
What is a ratio?A ratio has two or more numbers that symbolize relation to each other. Ratios are used to compare numbers, and you can compare them using division.
The ratio the baker uses (strawberries: flour) is:
40g: 220gAdding the two of these together gives us:
40g + 220 = 260gThis means that for 1 batch of cakes, 260g of flour and strawberries is needed in total.
Now that we know that, we can take 1040g and divide that by 260g.
1040g ÷ 260g = 4
This means that the baker made 4 batches of cakes using 1040g total.
Taking the amount of flour and multiplying that by 4 to get the amount of flour used:
220g × 4 = 880g
Therefore the baker uses 880g of flour for every 1040g total.
Find the measure of the indicated angle.
99⁰
96⁰
98⁰
92°
L
120°
K
N
M
64
Answer:
? = 92°
Step-by-step explanation:
the chord- chord angle ? is half the sum of the measures of the arcs intercepted by the angle and its vertical angle, that is
? = [tex]\frac{1}{2}[/tex] (LM + AK) = [tex]\frac{1}{2}[/tex] (120 + 64)° = [tex]\frac{1}{2}[/tex] × 184° = 92°
Suppose you have entered a 48-mile biathlon that consists of a run and a bicycle race. During your run, your average
velocity is 5 miles per hour, and during your bicycle race, your average velocity is 23 miles per hour. You finish the race
in 6 hours. What is the distance of the run? What is the distance of the bicycle race?
[tex]\displaystyle \text{To solve this problem, let's assume the distance of the run is denoted by 'x' miles, and the distance of the bicycle race is denoted by '48 - x' miles.}[/tex]
[tex]\displaystyle \text{We can use the formula: time} = \text{distance/velocity to find the time taken for each segment of the race.}[/tex]
[tex]\displaystyle \text{For the run:}[/tex]
[tex]\displaystyle \text{Time taken} = \text{Distance/Velocity}[/tex]
[tex]\displaystyle t_1 = \frac{x}{5}[/tex]
[tex]\displaystyle \text{For the bicycle race:}[/tex]
[tex]\displaystyle \text{Time taken} = \text{Distance/Velocity}[/tex]
[tex]\displaystyle t_2 = \frac{48 - x}{23}[/tex]
[tex]\displaystyle \text{Given that the total time for the race is 6 hours, we can write the equation:}[/tex]
[tex]\displaystyle t_1 + t_2 = 6[/tex]
[tex]\displaystyle \text{Substituting the expressions for } t_1 \text{ and } t_2, \text{ we get:}[/tex]
[tex]\displaystyle \frac{x}{5} + \frac{48 - x}{23} = 6[/tex]
[tex]\displaystyle \text{To solve this equation, we can simplify it by multiplying through by the common denominator, which is 115:}[/tex]
[tex]\displaystyle 23x + 5(48 - x) = 6 \times 115[/tex]
[tex]\displaystyle \text{Simplifying further:}[/tex]
[tex]\displaystyle 23x + 240 - 5x = 690[/tex]
[tex]\displaystyle 18x = 450[/tex]
[tex]\displaystyle x = \frac{450}{18}[/tex]
[tex]\displaystyle x = 25[/tex]
[tex]\displaystyle \text{Therefore, the distance of the run is 25 miles, and the distance of the bicycle race is } 48 - 25 = 23 \text{ miles.}[/tex]
29.4.3 Quiz: Parabolas with Vertices at the Origin
Question 5 of 10
The equation below describes a parabola. If a is negative, which way does the
parabola open?
y=ax²2²
O A. Right
B. Down
OC. Up
OD. Left
SUBMIT
The equation of a parabola with its vertex at the origin includes a negative coefficient 'a', the parabola opens downward. option B.
The equation y = ax² represents a parabola with its vertex at the origin. In this case, if the coefficient 'a' is negative, it determines the direction in which the parabola opens.
When 'a' is negative, the parabola opens downward. This means that the vertex, which is at the origin (0, 0), represents the highest point on the graph, and the parabola curves downward on both sides.
To understand this concept, let's consider the basic equation y = x², which represents a standard upward-opening parabola. As 'a' increases, the parabola becomes narrower. Conversely, when 'a' becomes negative, it flips the parabola upside down, resulting in a downward-opening parabola.
For example, if we have the equation y = -x², the negative coefficient causes the parabola to open downward. The vertex remains at the origin, but the shape of the parabola is now inverted.
In summary, when the equation of a parabola with its vertex at the origin includes a negative coefficient 'a', the parabola opens downward. This can be visually represented as a U-shape curving downward from the origin. So Optyion B is correct.
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The number of books on Diana's
bookshelf by male and female authors is
shown in the table below. Some of the
numbers are missing.
How many of the non-fiction books were
written by female authors?
Fiction
Non-fiction
Total
Male
36
68
Female
Total
77
142
Answer:
The table shows that there are a total of 142 books on Diana's bookshelf, with 77 books written by female authors and the rest by male authors. However, the number of non-fiction books written by female authors is missing from the table, so it is impossible to determine the exact number without more information.
Step-by-step explanation:
Answer:
104 books
Step-by-step explanation:
Fiction Non-Fiction Total
Male 36 38
Female x
Total 77 142
----------------------------------------------------------------------------
x = 142 - 38 = 104
Find the exact value of sec(-135)
The exact value of sec(-135°) is 1.
To find the exact value of sec(-135°), we need to use the relationship between secant and cosine functions.
The secant function is defined as the reciprocal of the cosine function:
sec(theta) = 1 / cos(theta).
We know that the cosine function has a period of 360°, which means that cos(theta) = cos(theta + 360°) for any angle theta.
In this case, we want to find sec(-135°). Since the cosine function is an even function (cos(-theta) = cos(theta)), we can rewrite sec(-135°) as sec(135°).
Now, let's focus on finding the value of cos(135°). The cosine function is negative in the second and third quadrants.
In the second quadrant, the reference angle is 180° - 135° = 45°. The cosine of 45° is equal to √2/2.
Therefore, cos(135°) = -√2/2.
Now, we can find sec(135°) using the reciprocal property:
sec(135°) = 1 / cos(135°).
Substituting the value of cos(135°), we have:
sec(135°) = 1 / (-√2/2).
To simplify further, we multiply the numerator and denominator by -2/√2:
sec(135°) = -2 / (√2 * -2/√2).
Simplifying the expression:
sec(135°) = -2 / -2,
sec(135°) = 1.
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Which property is illustrated by the following statement? If A ABC = A DEF,
and ADEF=AXYZ, then AABC=AXYZ.
B.
A
с
E
D
O A. Reflexive
O B. Symmetric
O C. Transitive
O D. Commutative
F
Z
The property that is illustrated by the statements is Transitive. Option C
How to determine the propertyUsing the principle of transitivity, if two objects are equal to a third, they are also equal to one another.
From the information given, we have that;
< ABC = <DEF
< DEF = < XYZ
This simply proves that < ABC and < XYZ are both equivalent to < DEF in this situation.
By using the transitive property, we can determine that A ABC and A XYZ are also equal. This attribute enables us to construct relationships between many elements based on their equality to a shared third element and to connect logically equalities.
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HELP CAN SOMEONE ANSWER THIS
Answer:
JLK = PRQ
Step-by-step explanation:
We already know that JL = QR and KL = PR.
If we know the angle between the two sides is equal or if the other side lengths are equal, then that would prove the two triangles to be equal.
Since the option for the two other side lengths (JK = PQ) to be equal is not listed, then the option that shows the angles are equal is the correct answer.
Since both JKL and PRQ are between the line segments already said to be equal, the answer is JLK = PRQ
Answer:
C. This would be a true statement due to the fact the to sides touch are equal. The sides are going to come at the same angle giving you a SAS which is possible to show for congruent triangles.
8. Amy has $30 to spend. She wants to buy pounds of lemons at $2 per pound, a box for $4, and 7 frozen dinners for $3 each Choose True or False for each statement. A She will not have enough money to buy everything O True O False 8 She will have $1 left over. O True O False C The total cost is $39. O True O False
Answer:she will actually need 1 dollar because all of that would be 31 dollars.
Step-by-step explanation:
3 pounds of lemons= $6
1 box of rice= $4
7 frozen diners= $21
6+4=10
10+21=31
Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
6-3x+=x+5
5
12
Therefore, the value of x that solves the equation is 2/7, after eliminating the fractions and solving the resulting equation.
To eliminate fractions in the equation 6 - 3x + (1/2)x = x + 5, we can multiply each term by a number that will clear the denominators. In this case, the denominator is 2 in the term (1/2)x. The least common multiple (LCM) of 2 is 2 itself, so we can multiply each term by 2 to eliminate the fraction.
By multiplying each term by 2, we get:
2 * (6 - 3x) + 2 * ((1/2)x) = 2 * (x + 5)
Simplifying this expression, we have:
12 - 6x + x = 2x + 10
Now, the equation is free of fractions, and we can proceed to solve it.
Combining like terms, we have:
12 - 5x = 2x + 10
To isolate the variable terms, we can move the 2x term to the left side by subtracting 2x from both sides:
12 - 5x - 2x = 10
Simplifying further:
12 - 7x = 10
Next, we can move the constant term to the right side by subtracting 12 from both sides:
12 - 7x - 12 = 10 - 12
Simplifying again:
-7x = -2
Finally, we solve for x by dividing both sides by -7:
x = (-2) / (-7)
Simplifying the division of -2 by -7 gives us the solution:
x = 2/7
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Hannah and Becky are learning to type on a computer keyboard. Hannah's
typing speed is represented by the equation y = 11x where y is the number of
words she types and x is the number of minutes. Becky's typing speed is
given by the graph.
Number of words
60
48
36
24
12
2
3
Time (minutes)
Choose the statement that correctly compares their unit rates.
Adr
A. Hannah's unit rate is 2 more words per minute than Becky's unit
rate.
B. Hannah's unit rate is 1 more word per minute than Becky's unit
rate.
C. Hannah's unit rate is equal to Becky's unit rate.
D. Hannah's unit rate is 1 fewer word per minute than Becky's unit
rate
The correct statement is D. Hannah's unit rate is 1 fewer word per minute than Becky's unit rate.
To compare the unit rates, we need to determine the rate at which each person types words per minute.
For Hannah, the equation y = 11x represents her typing speed, where y is the number of words and x is the number of minutes. This means that Hannah types 11 words per minute (11 words/minute).
Looking at Becky's graph, we can determine her unit rate by calculating the change in the number of words divided by the change in time.
The change in words is 48 - 2 = 46, and the change in time is 3 - 2 = 1. So, Becky's unit rate is 46 words per minute (46 words/minute).
Comparing the unit rates:
Hannah's unit rate: 11 words/minute
Becky's unit rate: 46 words/minute
Therefore, Hannah's unit rate is 35 words per minute less than Becky's unit rate.
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A metalworker cuts out a large semicircle with a diameter of 28 centimeters.Then the metalworker is a smaller sine ait of the larger one and rives it. The der of the ticular pince that is removed a 14 centimeters. Find the distance wound the shape after the smaller circle is removed. Use 22/7
The distance around the shape after the smaller semicircle is removed is 29 cm.The correct answer is option D.
To find the distance around the shape after the smaller semicircle is removed, we need to calculate the circumference of the larger semicircle and subtract the circumference of the smaller semicircle.
The circumference of a semicircle is given by the formula:
Circumference = π * radius + diameter/2
For the larger semicircle:
Radius = diameter/2 = 28/2 = 14 cm
Circumference of the larger semicircle = π * 14 + 28/2 = 22/7 * 14 + 14 = 44 + 14 = 58 cm
For the smaller semicircle:
Radius = diameter/2 = 14/2 = 7 cm
Circumference of the smaller semicircle = π * 7 + 14/2 = 22/7 * 7 + 7 = 22 + 7 = 29 cm
Therefore, the distance around the shape after the smaller semicircle is removed is:
58 cm - 29 cm = 29 cm
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The Probable question may be:
A metalworker cuts out a large semicircle with a diameter of 28 centimeters. Then the metalworker cuts a smaller semicircle out of the larger one and removes it. The diameter of the semicircular piece that is removed is 14 centimeters. What will be the distance around the shape after the smaller semicircle is removed? Use 22/7 as an approximation for π.
A. 80cm
B. 82cm
C. 85cm
D. 86cm
On a coordinate plane, a dashed straight line has a negative slope and goes through (0, 3) and (2, negative 1). Everything to the left of the line is shaded.
Which linear inequality is represented by the graph?
y > 2x + 3
y < 2x + 3
y > −2x + 3
y < −2x + 3
The correct linear inequality represented by the graph is:
y < -2x + 3. Option D
To determine which linear inequality is represented by the graph of the dashed straight line with a negative slope and going through (0, 3) and (2, -1), we can start by finding the slope of the line.
The slope of a line can be calculated using the formula:
m = (y2 - y1) / (x2 - x1).
Using the coordinates (0, 3) and (2, -1), we have:
m = (-1 - 3) / (2 - 0),
m = -4 / 2,
m = -2.
So, we know that the slope of the line is -2.
Next, we need to determine the y-intercept of the line. To do this, we can use the slope-intercept form of a linear equation: y = mx + b, where m is the slope and b is the y-intercept.
Using the point (0, 3), we can substitute the coordinates into the equation and solve for b:
3 = -2(0) + b,
3 = b.
Therefore, the y-intercept is 3.
Now that we have the slope and y-intercept, we can write the equation of the line in slope-intercept form:
y = -2x + 3.
Since we are shading everything to the left of the line, we want the region where y is less than the line. Option D is correct.
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5 hr, 30 min, 12 sec + 2 hr, 16 min, 25 'sec
The sum of the two time durations is 7 hours, 46 minutes, and 37 seconds.
To add the given time durations, we start by adding the seconds:
12 sec + 25 sec = 37 sec.
Since 60 seconds make a minute, we carry over any excess seconds to the minutes place, which gives us a total of 37 seconds. Moving on to the minutes, we add 30 min + 16 min = 46 min.
Again, we carry over any excess minutes to the hours place, resulting in a total of 46 minutes.
Finally, we add the hours: 5 hr + 2 hr = 7 hr.
Thus, the sum of the two time durations is 7 hours, 46 minutes, and 37 seconds.
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This is one appointments the same distance from other points or lines geometry
The concept of equidistant points or lines is fundamental in geometry and plays a significant role in many geometric constructions and properties.
In geometry, an "equidistant" point is a point that is at the same distance from other points or lines. This concept is often used in various geometric constructions and proofs.
For example, in a circle, the center of the circle is equidistant from all points on the circumference. This property is what defines a circle.
In terms of lines, an equidistant point can be found by drawing perpendicular bisectors. A perpendicular bisector of a line segment is a line that is perpendicular to the segment and divides it into two equal parts. The point where the perpendicular bisectors of a triangle intersect is called the circumcenter, and it is equidistant from the vertices of the triangle.
Another example is the concept of an equidistant curve. In some cases, there may be a curve or path that is equidistant from two fixed points. This curve is called the "locus of points equidistant from two given points" and is often referred to as a "perpendicular bisector" when dealing with line segments.
All things considered, the idea of equidistant points or lines is essential to geometry and is important to many geometrical constructions and features.
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NO LINKS!! URGENT HELP PLEASE!!
Please help with 35
Answer:
x = 4
Step-by-step explanation:
By property, if two tangents are drawn from an external point , then they are equal
⇒ 2x + 3 = 11
⇒ 2x = 11 - 3
⇒ 2x = 8
⇒ x = 8/2
⇒ x = 4
Answer:
x = 4
Step-by-step explanation:
To find the value of x, we can use the Two-Tangent Theorem.
The Two-Tangent Theorem states that if two tangent segments are drawn to a circle from the same external point, the lengths of the two tangent segments are equal.
Therefore:
[tex]\begin{aligned}AD &= AB\\\\2x+3&=11\\\\2x+3-3&=11-3\\\\2x&=8\\\\\dfrac{2x}{2}&=\dfrac{8}{2}\\\\x&=4\end{aligned}[/tex]
Therefore, the value of x is 4.
i need help in sparx
The rule that makes the machine work is *-5 + 6 * -5
How to make the machine work for the pair of input and outputFrom the question, we have the following parameters that can be used in our computation:
4 -50
-8 10
-3 -15
A linear equation is represented as
y = mx + c
Using the points, we have
4m + c = -50
-8m + c = 10
Subtract the equations
So, we have
12m = -60
m = -5
Next, we have
-8 * -5 + c = 10
So, we have
c = 10 - 40
c = -30
This means that the operation is
-5x - 30
When expanded, we have
*-5 + 6 * -5
Hence, the rule that makes the machine work is *-5 + 6 * -5
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PLSSSSSSSSSSSSSSS HELP!!!
Answer:
15
Step-by-step explanation:
5x = 4x + 3
x = 3
BC = 5x = 5(3) = 15
Answer: 15
Find the area to the right of the z-score 0.41 under the standard normal curve.
z0.20.30.40.50.000.57930.61790.65540.69150.010.58320.62170.65910.69500.020.58710.62550.66280.69850.030.59100.62930.66640.70190.040.59480.63310.67000.70540.050.59870.63680.67360.70880.060.60260.64060.67720.71230.070.60640.64430.68080.71570.080.61030.64800.68440.71900.090.61410.65170.68790.7224
The area to the right of the z-score 0.41 under the standard normal curve is approximately 0.3409.
To find the area to the right of the z-score 0.41 under the standard normal curve, we need to calculate the cumulative probability or area under the curve from 0.41 to positive infinity.
Since the standard normal distribution is symmetric around the mean (z = 0), we can use the property that the area to the right of a z-score is equal to 1 minus the area to the left of that z-score.
From the given z-table, we can look up the area to the left of 0.41, which is 0.6591.
The area to the right of 0.41 is then:
Area = 1 - 0.6591
Area = 0.3409
Therefore, the area to the right of the z-score 0.41 under the standard normal curve is approximately 0.3409.
This means that approximately 34.09% of the data falls to the right of the z-score 0.41 in a standard normal distribution.
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On her breakfast tray, Aunt Lily had a little vase of flowers - a mixture of primroses and celandines. She counted up the petals and found there were 39. "Oh, how lovely!" she said, "exactly my age; and the total number of flowers is exactly your age, Rose!" How old is Rose?
(NB: Primroses have five petals on each flower and Celandines have eight petals on each flower). Please show working
Rose's age should be a whole number, we can round 7.8 to the nearest whole number, which is 8.
Let's assume the number of primroses in the vase is p, and the number of celandines is c.
Each primrose has 5 petals, so the total number of primrose petals is 5p.
Each celandine has 8 petals, so the total number of celandine petals is 8c.
According to the given information, the total number of petals is 39. Therefore, we can set up the equation:
5p + 8c = 39 (Equation 1)
Aunt Lily mentions that the total number of flowers is exactly Rose's age. Since Rose's age is not provided, we'll represent it with the variable r.
The total number of flowers is p + c, which is also equal to Rose's age (r). Therefore, we have another equation:
p + c = r (Equation 2)
We need to find the value of r (Rose's age). To do that, we'll solve the system of equations by eliminating one variable.
Multiplying Equation 2 by 5, we get:
5p + 5c = 5r (Equation 3)
Now we can subtract Equation 1 from Equation 3 to eliminate the p term:
(5p + 5c) - (5p + 8c) = 5r - 39
This simplifies to:
-3c = 5r - 39
Now, let's rearrange Equation 2 to solve for p:
p = r - c (Equation 4)
Substituting Equation 4 into the simplified form of Equation 3, we have:
-3c = 5r - 39
Substituting r - c for p, we get:
-3c = 5(r - c) - 39
Expanding, we have:
-3c = 5r - 5c - 39
Rearranging the terms, we get:
2c = 5r - 39
Now we have a system of two equations:
-3c = 5r - 39 (Equation 5)
2c = 5r - 39 (Equation 6)
To solve this system, we can eliminate one variable by multiplying Equation 5 by 2 and Equation 6 by 3:
-6c = 10r - 78 (Equation 7)
6c = 15r - 117 (Equation 8)
Now, let's add Equation 7 and Equation 8 to eliminate c:
-6c + 6c = 10r + 15r - 78 - 117
This simplifies to:
25r = 195
Dividing both sides by 25, we get:
r = 7.8
Since Rose's age should be a whole number, we can round 7.8 to the nearest whole number, which is 8.
Therefore, Rose is 8 years old.
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Please answer ASAP I will brainlist
Using Gauss-Jordan method, the value of x, y and z are 0, -2 and 1
What is the solution of the system of equation?To solve the system of equations using the Gauss-Jordan method, we'll perform row operations to transform the augmented matrix into row-echelon form and then further transform it into reduced row-echelon form. Here are the steps:
1. Write the augmented matrix for the system of equations:
[1 -2 4 | 20]
[1 1 13 | -31]
[-2 6 -1 | -69]
2. Perform row operations to transform the matrix into row-echelon form:
R2 = R2 - R1
R3 = R3 + 2R1
[1 -2 4 | 20]
[0 3 9 | -51]
[0 2 7 | -29]
3. Perform row operations to further transform the matrix into reduced row-echelon form:
R2 = R2 / 3
R3 = R3 - 2R2
[1 -2 4 | 20]
[0 1 3 | -17]
[0 0 1 | 1]
4. Perform row operations to obtain a diagonal of 1s from left to right:
R1 = R1 + 2R2 - 4R3
R2 = R2 - 3R3
[1 0 0 | 0]
[0 1 0 | -2]
[0 0 1 | 1]
The resulting matrix corresponds to the system of equations:
x = 0
y = -2
z = 1
Therefore, the solution to the given system of equations is x = 0, y = -2, and z = 1.
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