Answer:
29 m/s
Explanation:
65 mi/hr (1 hr/3600s)(5280 ft/mi)(12 in/ft)(2.54 cm/in)(1 m/100cm) = 29.0576
The speed limit on Highway 85 in meters per seconds is 29.07m/s
Given the speed limit on highway 85 as 65mi/hr
Using the conversion rate:
2.23694 mi/hr = 1m/s
We are to convert 65mi/hr to m/s, we can therefore write:
65mi/hr = x
Divide both expressions
[tex]\frac{2.23594}{65} = \frac{1}{x} \\Cross \ mutiply\\ 2.23594x = 65\\x = \frac{65}{2.23594}\\x = 29.070m/s[/tex]
This shows that the speed limit on Highway 85 in meters per second is 29.07m/s
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Explain why selling cereal by mass rather then by volume be more fair to customers
Answer:
Simple, there could be air in the package and volume would record that, whereas mass would count the mass of the cereal and discount the air.
write any three differences between metals and nonmetals
Metals Non-metals
They are solid at room temperature. They may be solid, liquid and gas at room temperature.
They have high melting and boiling points. They have low melting and boiling points.
They are good conductors of heat and electricity. They are bad conductors of heat and electricity.
If the toy car weighs 250g and has a kinetic energy of 2.0 J, what is its velocity
Explanation:
Kinetic energy (J) = 2j
mass= 250g
velocity=?
1kg=1000g
mass= 250/1000
mass=0.25kg
Kinetic energy (J) = ½ x mass (kg) x [velocity]² (m/s)
2=1/2 × 0.25× [velocity]²
2=0.125× [velocity]²
[velocity]² = 2/0.125
[velocity]²=16
velocity= (16)^1/2
velocity= 4 m/s
If you have completely polarized light of intensity 150 W/m2, what will its intensity be after passing through a polarizing filter with its axis at an 89.0º angle to the light’s polarization direction?
Answer:
0.04569 W/m^2
Explanation:
I=150cos^2(89.0)
=0.04569W/m^2
Carnot Engine: A Carnot cycle consists of 179) A) four adiabats. B) two adiabats and two isobars. C) four isotherms. D) two adiabats and two isotherms. E) two isobars and two isotherms
Answer:
which question is this
Explanation:
I don't understand sorry
An 8-ohm resistor is connected to a 120-volt circuit. What current will it draw?
Answer:
15 A (15 amperes of current)
Explanation:
From Ohm's Law,
Voltage, V = Current, I × Resistance, R
Making Current, I the subject:
Current, I = Votage, V/ Resistance,R
= V/R
= 120volts /8ohms
= 15 A
For an electron, magnitude of force on it
is
Select one
• Bev
bev
Be
BIL
Answer:
F = Bev
Explanation:
B is magnetic field density
e is the electron charge
v is the electron velocity
The type of force that will not cause a change in the speed of an object.
Explanation:
Balanced forces will cause no change in the speed of an object.
b. What is measurement? Why measurement is important in our daily life? 3 Write the sunits of electric current and
Explanation:
Please mark me as brainlyest
Answer:
- Measurement is a comparison of an unknown quantity with a known fixed quantity of the same kind. The value obtained on measuring a quantity is called its magnitude. Magnitude of a quantity is expressed as numbers in its units.
- Measurements play an important role in daily life because they are useful to do basic tasks, such as take a child's temperature with a thermometer, make time estimations, measure out medicine and find weights, areas and volumes of different materials or substances.
- Electrical Parameter Measuring Unit Unit/Symbol
Voltage Volt V or E
Resistance Ohm R or Ω
Current Ampere I or i
Capacitance Farad C
Explanation:
I'm not sure but hope it helps.
A human hair is approximately 50 pm in diameter. Express this diameter in meters.
A human hair is approximately 50 μm = 5 × 10⁻⁵ m in diameter
1. A leftward force is used to pull a large wagon. In the wagon there is an unknown mass
that makes it very difficult to move, but a force applied is able to set the wagon into
constant motion. Let the force applied to the wagon and its unknown mass be 77.3 N. The
coefficient of friction between the wagon's wheels and the floor is 0.011. Determine the
mass of the wagon if it was empty.
i. Let's say that the unknown mass in the wagon is 95.5% * mass of the
wagon. What is the weight of the wagon when its empty and what is the
weight of the unknown mass?
Answer:
Wagon weight 366.41314(9.81) = 3,594.5129 = 3590 N
Load weight 349.9245(9.81) = 3,432.75982 = 3430 N
Explanation:
Let's assume the surface and the applied force are horizontal.
At constant motion, the friction force must balance the applied force
(from F = ma)
Ff = 77.3
μΝ = 77.3
μmg = 77.3
m = 77.3 / (0.011(9.81))
m = 716.3376... kg
Let M be the mass of the wagon
M + 0.955M = 716.3376
M(1.955) = 716.3376
M = 366.41314...kg
0.955 M = 349.9245... kg
round to the three significant digits of the question numerals.
two masses m and 2m, approach each along a path at right angles to each other. after collision, they stick together and move off at 2m/s at angle 37° to the original direction of the mass m. what were the initial speeds of the two particles
Explanation:
the answer is in picture
Select the best answer for the question.
17. How many mL of HEPARIN 10,000 units/mL are needed for a 7,000 unit dose?
O A.0.7
O B. 0.07
O C.7
O D. 0.007
0.7 mL of HEPARIN 10,000 units/mL is needed for a 7,000 unit dose.
To calculate the volume of HEPARIN 10,000 units/mL needed for a 7,000 unit dose, we can use the formula:
Volume (mL) = Dose (units) / Concentration (units/mL)
Given that the dose is 7,000 units and the concentration of HEPARIN is 10,000 units/mL, we can plug these values into the formula:
Volume (mL) = 7,000 units / 10,000 units/mL
Volume (mL) = 0.7 mL
So, 0.7 mL of HEPARIN 10,000 units/mL is needed for a 7,000 unit dose. However, none of the provided answer choices match exactly with 0.7 mL. The closest option is B. 0.07 mL, which is one-tenth of 0.7 mL. Therefore, the correct answer is B. 0.07 mL.
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A spring with spring constant 120 N/m and unstretched length 0.4 m has one end anchored to a wall and a force F is applied to the other end.
Required:
a. If the force F does 250 J of work in stretching out the spring, what is its final length?
b. If the force F does 250 J of work in stretching out the spring, what is the magnitude of F at maximum elongation?
(a) The work done by F in stretching the spring a distance x is
W = 1/2 (120 N/m) x ²
so F performs 250 J of work on the spring, then
250 J = 1/2 (120 N/m) x ² ==> x ² ≈ 4.17 m² ==> x ≈ 2.04 m
(b) In order for F to perform 250 J of work, its magnitude must be
F = (120 N/m) (2.04 m) ≈ 245 N
2. Calculate the force applied if 200 Pascal pressure is en the area of 0.2m”.
[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Force=Pressure(Area)[/tex]
[tex]\\ \sf\longmapsto Force=200(0.2)[/tex]
[tex]\\ \sf\longmapsto Force=40N[/tex]
Who has greater displacement, an astronaut who has just completed an orbit of the earth or you when you have just traveled from home to school?
Answer:
Explanation:
This is going to sound like an absurd answer, but sometimes physics can be a little strange.
This answer is weird because of the definition of displacement. It means the distance from the starting point to the ending point, disregarding what happened in between. The point is that the astronaut is at the starting point of his orbit. By definition the starting and ending points are the same. His displacement is 0.
So the answer is you have the greater displacement when you walked one way to school. The starting point and the ending point are different. You have gone further.
However just to make things a little nasty, when you walk home again, your displacement will be the same as the astronaut's -- 0 meters because you will be right back where you started from.
You that just traveled from home to school has greater displacement than the astronaut.
Displacement is defined as the change in the position of an object.
An astronaut who completed an orbit of the earth, has moved from an initial position x₁ and returned to the same position x₁ because Earth is assumed to be spherical. To complete an orbit of the Earth, the astronaut must return to his initial position since he will move round the Earth.
The displacement of the astronaut is zero because x₁ - x₁ = 0
For you that have just traveled from home to school, BUT haven't returned, your displacement is greater,.
Let's say the distance from your home to school = y
Your initial position at your home = 0
your displacement = y - 0 = y
Thus, you that just traveled from home to school has greater displacement than the astronaut.
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In Bohr's atomic theory, when an electron moves from one energy level to another energy level more distant from the nucleus: Select one: a. Energy is emitted. b. Energy is absorbed. c. No change in energy occurs d. Light is emitted. e. None of these.
(b)
Explanation:
Energy levels farther from the nucleus represent higher energies. Therefore, in order for the electrons to reach these levels, they must absorb additional energies first before they can make the jump.
What is the velocity of an object that moves from 73 m to 62 m in 15 s?
Answer:
Below
Explanation:
You can use this formula to find the velocity of an object
velocity = displacement / change in time
For this problem, we need to find displacement first
To find displacement all you need to do is find the difference between the two distances!
So our displacement here would be
73 - 62 = 11 m
Now that we have displacement we can find velocity
velocity = 11 / 15
= 0.733333....
= 0.73 m/s
Hope this helps! Best of luck <3
The velocity of an object that moves from 73 m to 62 m in 15 s is 0.73 m / s.
What is velocity?When an item is moving, its velocity indicates how quickly its location is changing as seen from a specific point of view and as measured by a specific unit of time.
If a point travels a specific distance along its path in a predetermined amount of time, its average speed throughout that time is equal to the traveled distance divided by the travel time. For instance, a train traveling 100 km in two hours is moving at an average speed of 50 km/h.
Given:
The distance of the object = 73 m to 62 m,
The time taken by the object, t = 15 s,
Calculate the displacement of the object = 73 - 62 = 11 m
Calculate the velocity by the formula given below,
[tex]v = d /t[/tex]
v = 11 / 15
v = 0.73 m / s
Therefore, the velocity of an object that moves from 73 m to 62 m in 15 s is 0.73 m / s.
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A small piece of aluminum (atomic number 13) contains 10^15 atoms (The atomic number is the number of protons; it determines the (positive) electric charge of the nucleus and, thus, the number of electrons in a neutral atom.) If the piece of aluminum has a net positive charge of 3.0 uc what fraction of the electrons that the aluminum had when it was neutral would have had to be lost?
Answer:
3 micro coulombs = 3 * 10E-6 coulombs charge of aluminum
13 * 10E15 * 1.6 * 10E-19 = 2.08 E-3 Coulombs - charge of atoms in Al
3 * 10E-6 / 2.08 * E-3 = 1.44 * E-3 = .00144 = .144 %
.00144 of the original electrons would have to be lost
An acetate rods rubs against a cloth. What type of charge will the rod end up with?
A. Positive
B. Negative
C. Not enough info
D. Neutral
Answer:
I believe it's A
Explanation:
........
is lightning man-made or Natural occuring?
claim:
give scientific reason:
evidence:
Answer:
give me brainliest
Explanation:
Lightning is a naturally occurring electrostatic discharge during which two electrically charged regions, both in the atmosphere or with one on the ground, temporarily equalize themselves, causing the instantaneous release of as much as one gigajoule of energy. ... Humans have deified lightning for millennia.
Lightning happens when the negative charges (electrons) in the bottom of the cloud are attracted to the positive charges (protons) in the ground.
what is suvat in physics ?
The average speed, correspondence to the average speed in a trajectory. True or false?
Answer:
hablo españolete telo ease
Explanation:
You push yourself on a skateboard with a force of 30 N east and accelerate at 0.5 m/s² east. Find the mass of theskateboard if your mass is 58 kg.
Answer:
2Kg
first you find the total mass of both the person und skateboard
f = m*a
30 = m* 0.5
m= 30/ 0.5
m= 60 kg
then you subtract the mass of the person from the total mass
m1 - m2
60 - 58
= 2 kg
Taking into account the Newton's second law, the mass of the skateboard is 2 kg.
Newton's Second Law establishes the relationship between the forces acting on an object and the acceleration it experiences. This law says that the acceleration that an object experiences when subjected to a net force (force applied to the body) is proportional to that force.
Mathematically, Newton's second law is expressed as:
F= m×a
where:
F = Force [N] m = Mass [kg] a = Acceleration [m/s²]In this case, you know:
F= 30 N m= ? a= 0.5 m/s²Replacing:
30 N= m× 0.5 m/s²
Solving:
m= 30 N÷0.5 m/s²
m= 60 kg
The mass of the sistem is the sum of the mass of the skateboard and the mass of the mass of your body:
Mass= mass of the skateboard + mass of your body
In this case:
60 kg= mass of the skateboard + 58 kg
Solving:
mass of the skateboard= 60 kg - 58 kg
mass of the skateboard= 2 kg
Finally, the mass of the skateboard is 2 kg.
Learn more about the Newton's second law:
brainly.com/question/23845187?referrer=searchResults brainly.com/question/13959891?referrer=searchResultsIf a body travels 18 km in 1 hrs, find the average velocity of the body in m/s
Answer:
Explanation:
18 km/hr (1000 m/km)(1 hr/3600 s) = 5 m/s
principle of electroplating
dnxjjc cjgnjgjnffjnfkfmgkcknsmksjs dmxmcmfkcnfjcnfjfnfjf in jfnfifnfifnf
Answer:
Electroplating is the method of depositing one metal over another in the presence of a metal salt (in aqueous solution). The water molecule is released as the final product in this process. As a consequence, electroplating is based on the theory of hydrolysis.
Which of the following is an example of a physical change?
Burning charcoal.
Dissolving sugar in water.
Cooking a hamburger.
Car Rusting.
Answer:
Dissolving sugar in water is an example of a physical change .
.......
https://www.sejda.com/share/9b04616a77ac4036b81482bc0eb0c97e-xPfTATV8BFmxDGQYW19Vcgybzs21Y2Xo6rIM9TMccWTC6a3xzld8Z9xOlsaB7IQY
Answer:what is your Question
Explanation:
Help meh in this question
Radius=r=R_o/2angular velocity=w=v_omass=m
We know
[tex]\boxed{\sf K.E=\dfrac{1}{2}mv^2}[/tex]
For Rotational motion
[tex]\boxed{\sf v=r\omega}[/tex].
Putting value
[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m(r\omega)^2[/tex]
[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}mr^2\omega^2[/tex]
[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m\left(\dfrac{R_o}{2}\right)^2v_o^2[/tex]
[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{4}mv_o^2[/tex]
Driving home from school one day, you spot a ball rolling out into the street . (See the figure below) You brake for 1.50 s , slowing your 950-kg car from 16.0 m/s to 9.50 m/s.
a)What was the magnitude of the average force exerted on your car during braking?
b)What was the direction of the average force exerted on your car during braking?
c)How far did you travel while braking?
Answer:
a) 4116.67 N
b) negative (assuming car is traveling in positive direction)
c) 19.125 m
Explanation:
Part A)We can find the average force exerted on the car by using Newton's 2nd Law: F = ma.
We have the mass (950 kg) but we do not have the acceleration. Let's solve for this using kinematics.
We have the time during braking, the initial and final velocity, and we need to find the acceleration. To do this, we can use the following equation: v = v₀ + at.
v (final velocity) = 9.50 m/sv₀ (initial velocity) = 16.0 m/st (time) = 1.50 s a = ?Substitute these values into the equation.
v = v₀ + at9.50 m/s = 16.0 m/s + a (1.50 s) 9.50 = 16.0 + 1.50a -6.50 = 1.50a a = -4.333333... m/s²The car's acceleration during the braking period is -4.33 m/s², assuming the car is traveling in the positive direction.
Now, we can use this to plug into Newton's 2nd Law to find the force exerted on the car.
F = maF = (950 kg) (-4.33...) F = -4116.666667 NThe magnitude of the average force exerted on the car while braking is the absolute value, so it is 4116.67 N.
Part B)The direction of the average force is denoted in the negative sign. It is opposite the direction of the car's motion. Assuming that the car is traveling in the positive direction, the direction of the average force exerted on the car is in the negative direction since this force is slowing the car down while braking.
Part C)We can find the distance traveled during the braking period by using another kinematic equation.
We have the initial and final velocity, and the time traveled, so we can use this equation: Δx = v_avg · t.
Note that v_avg is the same thing as (v + v₀) / 2.Substitute the known values into the equation.
Δx = [(9.50 + 16.0)/2] · 1.50 Δx = 12.75 · 1.50Δx = 19.125 mThe car traveled 19.125 m while braking.