The reaction below consistently yields 82% of the theoretical value. If you need to make 10 g of Mg(OH)2 How much Mg3N2 (g) should you use (assume that you will use H2O in excess).

Mg3N2(s) + H2O(l) → Mg(OH)2(s) + NH3(g)
Help me please!

Answers

Answer 1

If excess [tex]H_2O[/tex] is used as stated in the illustration the amount of [tex]Mg_3N_2[/tex] that would be required would be 7.57 grams

Stoichiometric calculation

From the equation of the reaction:

[tex]Mg_3N_2(s) + 6H_2O(l) --- > 3Mg(OH)_2(s) + 2NH_3(g)[/tex]

Since the yield is 80% of the theoretical value, in order to make 10g, the theoretical yield would be 12.5 g.

Mole ratio of [tex]Mg_3N_2[/tex] and [tex]Mg(OH)_2[/tex] = 3:1

Mole of 12.5 g  [tex]Mg(OH)_2[/tex] = 12.5/53.32 = 0.225moles

Equivalent mole of [tex]Mg_3N_2[/tex]  = 0.124/3 = 0.075 moles

Mass of 0.0041 moles  [tex]Mg_3N_2[/tex] = 0.075 x 100.95 = 7.57 grams

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

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To answer this we look only at the protons and electrons. Because there are 4 more protons than electrons we know that this ion has 4 less electrons than it would need to have to have a neutral charge. Therefore, the ionic charge is +4
Ionic charge is +4!!!!!!

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Explanation:

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Answers

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Answer:

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Explanation: Hope this helps!!

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Taking into account the definition of molarity, the molarity of the solution is 0.186[tex]\frac{moles}{liter}[/tex].

Definition of molarity

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The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

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Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

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Finally, the molarity of the solution is 0.186[tex]\frac{moles}{liter}[/tex].

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V₂ = 136LatmK / 956.025atmK

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Therefore, the new volume of the sample of helium gas as its temperature and pressure increases to the given values is 1.40×10²mL.

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