The boiling point of lauric acid is 298.9°C. Its melting point is 43.2°C. At room temperature (~25°C), lauric acid is in which state?
A. solid
B. intermediate between solid and liquid
C. liquid
D. intermediate between liquid and gas​

Answers

Answer 1

Answer

A. solid

Explanation

Answer 2

We have that At room temperature (~25°C), lauric acid is in a

Solid state

Option A

From the question we are told that

The boiling point of lauric acid is 298.9°C. Its melting point is 43.2°C.

It is important to note that Room temperature is is at 25C

Generally

if lauric acid 298.9°C and melting point is 43.2°C

Therefore at room temperature low than Boiling and melting point  lauric acid is

Solid

in conclusion

At room temperature (~25°C), lauric acid is in a Solid state

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Related Questions

A mineral oil has a density of 0.875 g/cm3. Suppose you spread 0.60 g of this oil over the surface of water in a large dish with an inner diameter of 21.6 cm. How thick is the oil layer

Answers

With a density of 0.875 g/cm³, a sample of 0.60 g of this oil would have a volume V such that

0.875 g/cm³ = (0.60 g)/V   ==>   V ≈ 0.686 cm³

If the oil is spread out uniformly over the water's surface, then it forms a cylinder whose diameter is equal to that of the dish, 21.6 cm. Then the thickness d of the oil cylinder is such that

V = π ((21.6 cm)/2)² d   ==>   d0.0202 cm

Which of the following elements has properties different than the rest?
H
K
N
O

Answers

Answer:

I think K . If it not, then sorry.

Hope I helped you.

Answer: The answer [b] or also known as k

Explanation:

An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 15m if her initial speed is 3m/s.What is the acceleration due to gravity on the planet?

Answers

Explanation:

As the astronaut jumps and reaches the highest point, he is momentarily at rest, i.e.

[tex]v=0[/tex]

We also know

[tex]u=3, s=15[/tex]

By the formula,

[tex]v^2-u^2=2as[/tex]

where a is the acceleration of objectc due to gravity,

[tex]0^2-3^2=2a(15)[/tex]

[tex]-9=30a[/tex]

[tex]a=-0.3 ms^{-2}[/tex]

where negative sign indicates a downwards acceleration.

An arrow is moving at 35 m/s and travels for 5 seconds. How far did the arrow travel?

What are you solving for? Show work! Help please!

Answers

Answer:

175m

Explanation:

So it’s travelling at 35metres/1second so if we want to find 5 seconds we can do this…

[tex]\frac{35}{1} \frac{x}{5}.... so[/tex] 35x5 ÷ 1 = 175m/5 seconds

Answer:

175 is the right answer 35×5=175

Explanation:

175

Question 15 OT 25
Which process is an example of an exothermic reaction?
A. The reactions taking place in a cold pack
B. A plant using photosynthesis to create sugars
C. Natural gas burning on a stove
o
D. The reactions taking place inside a baking cake

Answers

Answer:

A. The reactions taking place in a cold pack

Explanation:

This is because in a cold pack, there is no heat gained therefore a reaction stands by losing it's own heat to the surrounding.

[tex].[/tex]

What is the relationship between resistivity of a wire and length of a wire is?

Answers

[tex]\boxed{\sf R=\rho\dfrac{\ell}{A}}[/tex]

Or

[tex]\\ \rm\hookrightarrow \rho=R\dfrac{A}{l}[/tex]

Rho stands for resistivity of wireR stands for resistance of wire l stands for length of areaA stands for surface area of wire

A scientist obtains images of a particular star, which appears as four separate stars.
Which phenomenon causes the star to appear this way?
O redshift
gravitational lensing
O principle of equivalence
O gravitational time dilation

Answers

Answer:

gravitational lensing

Explanation:

Answer:

Gravitational lensing

Explanation:

A uniform rod of length 0.7 m and mass 10 kg rotates freely about a horizontal axis passing through one end of the rod a bullet of mass 20 g traveling horizontally with velocity v=200 m/s penetrates the end of the rod. and hooked on the rod find the angular velocity of the rod when the bullet hits the bar

Answers

Answer:

ω = 1.7 rad/s

Explanation:

Conservation of angular momentum

Assuming the rod is initially hanging vertically at rest.

Initial angular momentum is carried by the bullet only

L = Iω = (mR²)(v/R) = mvR = 0.020(200)(0.7) = 2.8 kg•m²/s

the same angular momentum exists after impact, only the moment of inertia has increased by that of the rod. I = ⅓mR²

2.8 = (⅓(10)(0.7²) + 0.020(0.7²))ω

2.8 = (1.64313333...)ω

ω = 1.70406134...

What is the speed of a car that traveled 32 m in 2 seconds?​

Answers

Distance = speed x time
D = S x T

To get the speed,
Speed = distance / time

You will get
32m / 2s = 16m/s


/ = is a symbol for division

HELP PLEASE ASAP!!!
I CAN'T FAIL PHYSICS
xoxo thank you!

Answers

they are malleable and lustrous, and can conduct both electricity and thermal heat

A black ball moving to the left at 3 m/s collides with a white ball at rest. Which direction will the balls move after the collision?

Answers

Answer: the location from where the black ball was thrown from because after the collision the  velocity will make it still go further not stop

Explanation:

What is the velocity of a car that traveled a total of 75 kilometers north in 1.5 hours?

What are you solving for?
What’s the equation?
Show work!
Help pleaseee!

Answers

Answer:

50km/hr is the velocity of a car that traveled a total of 75 km North in 1.5 hours.

25m/s to miles/hr step by step

Answers


55.9235462985 mi/hr
Or scientifically notated 5.59235462985 mi/hr

Before beginning, use the given conversion for meters to miles provided by your teacher (If given one). If instructed to use less decimal places, do so.

Start with the “numerator” of what you are looking for. Use a conversion equal to that numerator to advance your formula. (In this case 1 mile is equal to 1609.34 meters). With double conversions, the given rate will always end up in the middle of your equation. (In this case, meters per second). Finally, using equivalent conversions, advance your equation until you end with the “denominator” of what you are looking for. (In this case, hours). This number will always end on the bottom of a double conversion equation.
Using your calculator, open a parenthesis, multiply all numbers across the top of the equation. Close parenthesis. Hit “divide” on calculator, open another parenthesis and multiply all numbers across the bottom of the equation. Close parenthesis and hit “enter”.
(1x25x60x60) / (1609.34x1x1x1) = 55.923546 mi/hr
* Note: using parenthesis in your calculator is essential for your calculator to perform the correct function.
* Round your answer to correct amount of decimal places (per teacher instruction) and scientifically notate if necessary.
* Don’t forget to “box” your answer if required by instructor.

Late one night on a highway, a car speeds by you and fades into the distance. Under these conditions the pupils of your eyes have diameters of about 7.0 m m. The taillights of this car are separated by a distance of 1.4 m and emit red light (wavelength = 660 nm in vacuum). How far away from you is this car when its taillights appear to merge into a single spot of light because of the effects of diffraction?

Answers

660 because 7.0 is added is 1.4

What is the difference between a scientific theory and a scientific law

Answers

Answer:

Scientific laws are summaries or statements that describe a wide range of observations and results of experiments.

Scientific theories, on the other hand, are explanations for observations and results.

So, laws describe what happens and theories explain why things happen.

hope this help! ^^

How would you determine the sign of a charge on a body using an electroscope? PLEASE HELP!!!

Answers

Answer:

Now the electroscope will allow you to identify whether an object is positively or negatively charged. If you bring a negative object near the electroscope, the electrons in the scope will be repelled toward the leaves, balancing the charge.

Explanation:

The electrostatic force obeys the principle of linear super-position which basically states

that force between two particles does not get affected by the charge of the other and hence if the

rod is brought close to a suspended metal needle and is getting attracted then needle definitely

should possess opposite charge relative to the rod or basically negative charge as opposite charges

attract.

(b) In case the needle which is brought near the sus[ended needle and gets repelled that shows that

both of them possess same charge and hence positive charge on both objects and will start

repelling each other.

what happens to the value of g when we move from equator to the pole.the weight of an object is greater at poles than at equator .
why?​

Answers

We know that the size of the Earth is not a perfect sphere, it’s flattened near the poles and bulged near the equator. Since, the equator is bulged, the radius is greater. Since the radius is greater the gravity is lesser than compared to poles.

Hope you understand

Un telescopio indica que la posición de un satélite de comunicaciones está determinada por el punto P (7x105m, 5x105m) . ¿A qué distancia se encuentra el satélite del telescopio? En que dirección viajará una señal que sale del telescopio hacia el satélite?​

Answers

a) La Distancia entre el telescopio y el satélite es aproximadamente [tex]8.602\times 10^{5}[/tex] metros.

b) La señal sale del telescopio y se desplaza [tex]7\times 10^{5}[/tex] metros en Dirección + x y [tex]5\times 10^{5}[/tex] metros en Dirección +y.

a) Si asumimos la Posición del telescopio como el Origen de un Marco de Referencia, entonces la Distancia entre el telescopio y el satélite ([tex]d[/tex]), en metros, mediante la siguiente expresión:

[tex]d = \sqrt{(S(x,y) - O(x,y))\,\bullet\,(S(x,y) - O(x,y))}[/tex] (1)

Donde:

[tex]S(x,y)[/tex] - Coordenadas del satélite, en metros.[tex]O(x,y)[/tex] - Coordenadas del telescopio, en metros.

Si sabemos que [tex]O(x,y) = (0, 0)[/tex] y [tex]S(x,y) = (7\times 10^{5}, 5\times 10^{5})[/tex], entonces la Distancia entre el telescopio y el satélite es:

[tex]d = \sqrt{(7\times 10^{5})^{2}+(5\times 10^{5})^{2}}[/tex]

[tex]d \approx 8.602\times 10^{5}\,m[/tex]

Nota - (1) es una forma vectorial del Teorema de Pitágoras.

La Distancia entre el telescopio y el satélite es aproximadamente [tex]8.602\times 10^{5}[/tex] metros.

b) La señal sale del telescopio y se desplaza [tex]7\times 10^{5}[/tex] metros en Dirección + x y [tex]5\times 10^{5}[/tex] metros en Dirección +y.

Invitamos a ver esta pregunta relacionada con Cálculo de Distancias: https://brainly.com/question/18209846

what happens when you mix water and baking soda

Answers

Nothing much. It doesn’t explode. Lol

how many grams of CaCo3, will react with dil HCL to produce 75gm of Co2 ?​

Answers

Answer:

100g is correct answer.

Answer:

100 grams

Explanation:

CaCO3 ➡️ CaO + CO2

pls mark brainlies!

What is the density of a block of marble that
occupies 287 cm3
and has a mass of 816 g?
Answer in units of g/cm3
.

Answers

Explanation:

Solution,

Volume (v)=287 cm^3

Mass(m)=816 g

Density(d)=m/v

=816/287

=2.84

So, the density of the block of marbles is 2.84 g/cm^3.

I hope it helped U

stay safe stay happy

Physics help please !!!

Answers

Answer:

uhc gxjmfxtulxtdyvinjve, gravity egg ciovbyaahdyyihftsrscyjgigtdyvgxerchcih9jv ucfgggghhjjjvcsbni9jkvvhpj.

upfp73eidjdhxhxuelueljs NBA. aly7ryshzb. w m8

Revolution: One orit of an object in space around another_ days?​

Answers

Answer:

365 days..

Explanation:

Hope it may help you シ︎♡︎

[tex] \huge\mathfrak\green{365 \: or \: 366 \: Days.}

[/tex]

[tex]Hope \: it \: helps[/tex]

16. A horizontal pipe with a cross-section of 10 cm?which is joined to another horizontal pipe of 50 cm Cross-sectional area. The speed of water in the small pipe is 6 m/s and the pressure there is 200 kPa. The pressure in the large pipe, in Pa. is

A. 183
B. 217000
C. 217
D. 235000​

Answers

Answer:

b

Explanation:

2. Samuel leaves the end of a 4.0-m-high diving board and strikes the
water 1.3 s later, 3.0 m beyond the end of the board. Considering the
diver as a particle, determine:
(a) His initial velocity,
(b) The maximum height reached;
(c) The velocity Vf
with which he enters the water.

Answers

Answer:

a) v = 4.9 m/s at 62° above the horizontal

b) h = 0.94 m above the board or 4.94 m above the water

c) v = 10 m/s at 77° below the horizontal

Explanation:

Assume UP and FOREWARD are positive and the diving board is the origin.

Ignore air resistance.

s = s₀ + v₀t + ½at²

In the vertical

-4 = 0 + vy₀(1.3) + ½(-9.8)(1.3²)

vy₀ = 4.281 m/s

in the horizontal

3.0 = 0 + vx₀(1.3) + ½(0)(1.3²)

vx₀ = 2.307... m/s

v = √(4.281² + 2.307²) = 4.863...

tanθ = 4.281 / 2.307

θ = 61.680...

v² = u² + 2as

s = (v² - u²) / 2a

h = (0² - 4.281²) / 2(-9.8) = 0.9350...

v² = 4.863² + 2(9.8)(4)

v = 10.1019...

cosθ = 2.307/10.1019

θ = 76.798

(a) The initial velocity of Samuel is 4.02 m/s

(b) The maximum height reached by Samuel is 0.55 m

(c)  The final velocity when he enters the water is 5.20 m/s

The given parameter:

the height of the board, h = 4 mtime to strike the water, t = 1.3 sthe horizontal distance traveled, x = 3.0 m

(a) The initial velocity of Samuel is calculated as;

[tex]h = v_o_y t + \frac{1}{2} gt^2\\\\[/tex]

Assume downward motion to be in negative direction

The vertical component of the velocity is calculated as;

[tex]4 = 1.3\times v_0_y + 0.5\times 9.8\times 1.3^2\\\\4 = 1.3v_{0y} + 8.281\\\\1.3v_{0y} = 4- 8.281\\\\1.3v_{0y} = -4.281\\\\v_{0y} = \frac{-4.281}{1.3} \\\\v_{0y} = -3.293 \ m/s\\\\v_{0y} = 3.293 \ m/s \ \ \ (downwards)[/tex]

The horizontal component of the velocity is calculated as;

Assume forward motion to be in positive direction

[tex]x = v_{0x}t \\\\3 = 1.3v_{0x}\\\\v_{0x} = \frac{3}{1.3} \\\\v_{0x} = 2.308 \ m/s[/tex]

The resultant of initial velocity is calculated as;

[tex]v_0 = \sqrt{v_{0y}^2 + v_{0x}^2} \\\\v_0 = \sqrt{3.293^2 + 2.308^2} \\\\v_0 = \sqrt{16.17} \\\\v_0 = 4.02 \ m/s[/tex]

(b) The maximum height reached by Samuel is calculated as;

[tex]v_f_y^2 = v_0_y^2 + 2gh\\\\at \ maximum \ height \ v_{fy} = 0\\\\0 = v_0_y^2 + 2gh\\\\-2gh = v_0_y^2\\\\h = \frac{v_0_y^2}{-2g} \\\\h = \frac{(3.293)^2}{-2\times 9.8} \\\\h = -0.55 \ m\\\\h = 0.55 \ m \ (downwards)[/tex]

(c) The final velocity when he enters the water;

The height traveled before he hits the water, h = 0.55 m

[tex]v_f^2 = v_{0}^2 + 2gh\\\\v_f^2 = (4.02)^2 + (2\times 9.8\times 0.55)\\\\v_f^2 = 26.94\\\\v_f = \sqrt{26.94} \\\\v_f = 5.20 \ m/s[/tex]

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Three resistors 2 k\ohm, 2.5 k\ohm and 3 k\ohm are connected in series. A power supply is connected in the circuit, and applies a voltage of 10.00 V across all three. Calculate the current in the circuit. Enter results in terms of milliamps (mA).

Answers

Answer:

1.33 mA

Explanation:

V=IR

I=10/(7.5×10³)

=1.33×10-³A

=1.33mA

Yellow light passes through a diffraction grating. it's first order maximum occurs at an angle of 21.2. What is the slit separation d?

Answers

Answer:

19.284

or

9.33

Explanation:

Answer:

1.66

Explanation:

Found answer on chegg. Works for acellus

Which Scientist discovered
atomic Theory?​

Answers

Answer:

John dalton discovered

60.96-mile distance in kilometers

Answers

Answer:

98.105610 Kilometers

Explanation:

Rounded to 8 digits

Answer:

98.11 km

Explanation:

60.96 mi (5280ft/mi)(12 in/ft)(2.54 cm/in)(1 m/ 100cm)(1 km/1000 m) = 98.10561024 km

however, reporting this precision to the nearest hundred millionth of a kilometer is silly as we only know the mile dimension to the nearest hundredth of a mile.

A hundredth of a mile is 5280/100 = 52.8 ft or just over 16 m

It would only be a little bit of a presumption to give our precision to the nearest 10 meters as I have done.

This also fits neatly into the significant digits rule. Both the original dimension and the converted dimension have four significant digits.

which form of the energy is used to generate electrical energy in a tidal power station

Answers

Tidal energy is the form of energy used to generate electrical energy.

The form of the energy is used to generate electrical energy in a tidal power station is kinetic energy.

What is kinetic energy?

Kinetic energy is the energy that an object has as a result of its movement. If we intend to accelerate an object, we should indeed apply force to it. Using force requires us to put in effort.

After work is completed, energy is transmitted to the object, and the object moves at a new constant speed.

Tidal energy is generated by the movement of our tides and oceans, where the intensity of the water from tide rise and fall is a type of kinetic energy.

Tidal power is related to gravitational hydropower, which uses water movement to propel a turbine and generate electricity.

Thus, kinetic energy is used to generate electrical energy in a tidal power station.

For more details regarding kinetic energy, visit:

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