The bigger the spring constant, the more stiff or rigid the spring is.
What does it signify when a spring's spring constant is higher?The exact amount of force needed to bend a spring depends on the spring constant. Although pounds/inch is a common measurement in North America, the standard international (SI) unit for spring constants is Newtons/meter. A stiffer spring has a greater spring constant, and vice versa.
What does it signify when the spring constant is higher?The exact amount of force needed to bend a spring depends on the spring constant. Although pounds/inch is a common measurement in North America, the standard international (SI) unit for spring constants is Newtons/meter. A stiffer spring has a greater spring constant, and vice versa.
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a boy throws a ball horizontally from shoulder height of 1.10m just before the ball touches down on the level ground it makes an angle of 30 degree with the ground. determine the initial velocity of the ball as it left the boys hand
The boy throws the ball horizontally. The initial velocity of the ball as it left the boy's hand was approximately 3.72 m/s.
What is initial velocity?Initial velocity, often represented as v0, is the velocity of an object at the beginning of a time interval or at the start of a motion.
Use the following kinematic equations to arrive at the answer:
Horizontal velocity (Vx) = Distance / Time
Vertical displacement (y) = V0y*t + (1/2)gt²
Vertical velocity (Vy) = V0y + g*t
Tan(theta) = Vy / Vx
where V0y is the initial vertical velocity, g is acceleration due to gravity (9.8 m/s²), and theta is the angle of inclination.
First, let's find the time it takes for the ball to hit the ground. We can use the vertical displacement equation and set y = 0:
0 = V0y*t + (1/2)gt²
Simplifying and solving for t, we get:
t = sqrt((2y) / g)
= sqrt((21.10 m) / 9.8 m/s²)
= 0.472 s
Now, we can use the horizontal velocity equation to find Vx. Since the ball was thrown horizontally, Vx is the same as the initial velocity (V0):
Vx = Distance / Time
= (horizontal distance travelled by ball) / t
We don't know the horizontal distance travelled by the ball, but we can find it using the vertical displacement equation. At the instant the ball hits the ground, its vertical displacement (y) is:
y = V0y*t + (1/2)gt²
= 0 + (1/2)gt²
= (1/2)*9.8 m/s² * (0.472 s)²
= 1.10 m
This means the ball travelled a total distance of:
distance = horizontal distance + vertical distance
= x + 1.10 m
where x is the horizontal distance travelled by the ball. We can find x using the angle of inclination and the vertical displacement:
Tan(theta) = Vy / Vx
Vy = V0y + g*t
Solving for V0y, we get:
V0y = Vy - g*t
Plugging in the numbers, we get:
V0y = Tan(theta) * Vx - g*t
= Tan(30 deg) * Vx - 9.8 m/s² * 0.472 s
= 0.577 * Vx - 4.62 m/s
Now, we can use the vertical displacement equation again to find x:
y = V0yt + (1/2)gt²
= (0.577Vx - 4.62 m/s) * 0.472 s + (1/2)*9.8 m/s² * (0.472 s)²
= 1.10 m
Simplifying and solving for Vx, we get:
Vx = (2y - 0.577V0t) / t
= (21.10 m - 0.577*(0.577*Vx - 4.62 m/s)*0.472 s) / 0.472 s
= 3.72 m/s
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A Caris travelling along astraigh levels red at 20 m/s against force of 3000M What Power forms its engine is needed?
Answer:
600kW
Explanation:
Power= Workdone/ time
= 1500/8*320
= 1500*40
= 60000J/s
= 600kW
Workdone= Fd
= 3000*1*1/16
= 1500/8
= 750/4
= 137. 5Nm
3000F/320
=150F/16
s=ut+1/2at^2
3000= 1/2at^2
6000= at^2
6000/a=t^2
F=ma
20m/t=ma
20/t= a
20m=Ft
20m=F(320)
m= 8F
F=ma
= 20/tm
20m/t= 20/tm
m= 1/m
m=1kg
6000/a= 400/a^2
16= 1/a
a= 1/16ms-2
t= 20/1/16
t= 320 s
(v-u)/t=a
v= 20ms-1
Glucose is a reactant in cellular respiration.
True or False?
Answer:
true
Explanation:
Answer:
True
Explanation:
Glucose is one of the reactants in cellular respiration, which is the process by which cells generate energy in the form of ATP (adenosine triphosphate). Glucose is broken down into simpler molecules in a series of metabolic reactions that occur in the presence of oxygen (aerobic respiration) or in the absence of oxygen (anaerobic respiration). The breakdown of glucose ultimately results in the release of energy that is used to produce ATP, which is the main source of energy for cellular activities.
A firefighting crew uses a water cannon that shoots water at 29.0 m/s
at a fixed angle of 53.0 ∘
above the horizontal. The firefighters want to direct the water at a blaze that is 10.0 m
above ground level. How far from the building should they position their cannon? There are two possibilities ( d1
); can you get them both? (Hint: Start with a sketch showing the trajectory of the water.)
Express your answer in meters.
d1 and d2
The second possibility is that the firefighters can position their cannon anywhere within a range of 60.2 m from the building to hit the blaze at 10.0 m above ground level.
What is Horizontal Velocity?
Horizontal velocity is the component of velocity in the horizontal direction, perpendicular to the vertical direction. It describes the speed and direction of motion of an object in the horizontal plane. In the absence of external forces, the horizontal velocity of an object moving through the air remains constant, as there is no force acting on the object in the horizontal direction.
Let's first find the time it takes for the water to reach the maximum height:
The vertical component of the initial velocity is:
vy = v * sin(θ) = 29.0 m/s * sin(53.0°) = 22.7 m/s
Using the kinematic equation:
where Δy = 10.0 m, vyi = 22.7 m/s, and a = -9.81 m/[tex]s^{2}[/tex] (the negative sign indicates that acceleration is in the opposite direction to the initial velocity).
We get:
10.0 m = 22.7 m/s * t - 1/2 * 9.81 m/[tex]s^{2}[/tex] * [tex]t^{2}[/tex]
Simplifying and solving for t, we get:
t = 1.61 s
Now, let's find the horizontal displacement of the water:
The horizontal component of the initial velocity is:
vx = v * cos(θ) = 29.0 m/s * cos(53.0°) = 18.7 m/s
Using the equation:
Δx = vx * t
where Δx is the horizontal displacement, vx is the horizontal component of the initial velocity, and t is the time we found above.
We get:
Δx = 18.7 m/s * 1.61 s = 30.1 m
So the firefighters should position their cannon 30.1 m away from the building.
To find the second possibility, we need to find the range of the water cannon, which is the horizontal distance traveled by the water before it hits the ground. The range can be calculated using the formula:
where R is the range, v is the initial velocity, θ is the angle above the horizontal, and g is the acceleration due to gravity.
Plugging in the values we get:
R = [tex]29.0^{2}[/tex] * sin(2 * 53.0°) / (2 * 9.81) = 60.2 m
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A block of mass m1=3.0kg rests on a frictionless horizontal surface. A second block of m2=2.0kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block . the blocks are released from rest . determine the displacement of the velocity of the first block 1.2 s after the release of the blocks, assuming the first block doesn't run out of the room on the table and the second block doesn't land on the floor?
A) 23.5m/s
B) 12m/s
C) 33.7m/s
D) 6.7m/s
To solve this problem, we can use the principles of Newton's laws of motion and the conservation of energy.
At the moment of release, the second block will start to accelerate downwards due to gravity, and the first block will start to move to the right due to the tension in the rope. Since the surface is frictionless, there is no horizontal force acting on the first block once it starts moving.
Using the free-body diagrams for the two blocks, we can write the following equations of motion:
For the second block:
m2g - T = m2a
where g is the acceleration due to gravity, T is the tension in the rope, a is the acceleration of the second block, and m2 is the mass of the second block.
For the first block:
T = m1a
where m1 is the mass of the first block and a is its acceleration.
Since the two blocks are connected by a rope, they must have the same acceleration, so we can set the two equations for acceleration equal to each other:
m2g - T = m1a
T = m1a
m2g - m1a = T = m1a
Solving for a, we get:
a = (m2/m1 + m2)g
We can also use the conservation of energy to find the final velocity of the first block after 1.2 seconds. At the moment of release, the total mechanical energy of the system is given by:
E = m1gh
where h is the initial height of the second block. As the blocks move, the potential energy of the second block is converted into the kinetic energy of both blocks. At the end of the 1.2 seconds, all of the potential energy will be converted into kinetic energy, so we can write:
E = (1/2)m1v^2 + (1/2)m2v^2
where v is the final velocity of the first block.
Solving for v, we get:
v = sqrt(2gh(m1+m2)/m1)
Plugging in the given values, we get:
a = (2/5)g ≈ 3.92 m/s^2
v = sqrt(2gh(m1+m2)/m1) ≈ 2.36 m/s
Therefore, the displacement of the velocity of the first block 1.2 s after the release of the blocks is approximate:
vt + (1/2)at^2 = 2.361.2 + (1/2)3.92(1.2)^2 ≈ 5.52 m/s
So the answer is not given in the options.
Pulse transfers a
disturbance. while wave is a
disturbance that transfers energy.
Answer:
Pulse transfers a single disturbance, while wave is a continuous disturbance that transfers energy.
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What is the momentum of a 2.3 kg ball rolling at 6 m/s?
Show your work
Answer:
13.8 (kgm)/s
Explanation:
p(momentum) = m (mass) * v (velocity)
p= 2.3 * 6
p = 13.8
PLEASE HELP, IM CONFUSED AND THIS IS A LATE ASSIGNMENT
Answer: 4 N backwards
Explanation:
The driver of a car with a total of 1800 kg mass is traveling at 23 m/s when he slams on the brakes, locking the wheels on the dry pavement. The coefficient of kinetic friction between rubber and dry concrete is typically 0.7. How far would the car travel if were going twice as fast
Answer:
To solve this problem, we can use the formula:
d = (v^2)/(2μg)
d = distance traveled
v = speed of the car
μ = coefficient of kinetic friction
g = acceleration due to gravity
First, let's calculate the distance traveled when the car is traveling at 23 m/s:
d = (23^2)/(2*0.7*9.81) ≈ 67.97 meters
Now, let's calculate the distance traveled when the car is going twice as fast (46 m/s):
d = (46^2)/(2*0.7*9.81) ≈ 271.88 meters
Therefore, the car would travel approximately 271.88 meters if it were going twice as fast.
Question 14 of 16
When is work negative?
OA. When an object goes from high to low potential energy
O B. When an object goes from low to high potential energy
O C. When an object slows down
O D. When an object speeds up
Work is negative when A. When an object goes from high to low potential energy.
When can work be said to be negative ?Work is defined as the transfer of energy that occurs when a force is applied to an object, causing it to move a certain distance. When the force and displacement are in the same direction, the work is positive.
When an object moves from a higher to a lower potential energy state, it loses potential energy. In this case, the negative work done by gravity is equal to the loss of potential energy of the ball.
When an object slows down, the force acting on it is in the opposite direction to its velocity, so work is done in the opposite direction to the displacement, and the work is negative.
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Which has more kinetic energy:
a. A compact car going 70 MPH or a tractor trailer going 15 MPH?
b. An SUV going 30 MPH or a pickup truck going 30 MPH?
c. A school bus going 15 MPH, an SUV going 35 MPH, or a
compact car going 45 MPH?
Answer:
Explanation:
a. The compact car going 70 MPH has more kinetic energy than the tractor trailer going 15 MPH. Kinetic energy is proportional to the square of the velocity, so even though the tractor trailer may have more mass, the higher velocity of the compact car results in greater kinetic energy.
b. The SUV and the pickup truck have the same kinetic energy since they have the same mass and velocity.
c. The compact car going 45 MPH has the most kinetic energy since it has the highest velocity out of the three vehicles. The SUV going 35 MPH has less kinetic energy, and the school bus going 15 MPH has the least kinetic energy.
From these measurements, compute the possible error in the volume.
Plugging in the values of the length and diameter, along with the error value, the error in the volume of the cylinder is approximately 1.27 cm³.
What is error in measurement?Error in measurement refers to the deviation or difference between the true or expected value and the measured value of a physical quantity. The presence of errors in measurement can affect the accuracy and precision of the results obtained.
To compute the possible error in the volume of the cylinder, we first need to calculate the volume of the cylinder using the measured values of its length and diameter:
V = πr²h
r = d/2 = 2.1/2 = 1.05 cm
V = π(1.05)²(8.9) = 31.79 cm³
Now, we need to determine the possible error in the volume, which can be calculated using the formula:
ΔV = V × √[(Δd/d)² + (Δh/h)²]
where Δd and Δh are the uncertainties in the diameter and length measurements, respectively. Substituting the given values, we get:
ΔV = 31.79 × √[(0.1/2.1)² + (0.1/8.9)²] = 1.27 cm³ (approx.)
Therefore, the possible error in the volume of the cylinder is approximately 1.27 cm³.
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Owen hits a baseball with a velocity of 55 m/s. The ballpark fence is 120 m away.
Does the ball reach the fence if it leaves the bat traveling upward at an angle of 30°
to the horizontal?
Answer:
Explanation:
We can solve this problem using kinematic equations. We know that the initial velocity of the ball is 55 m/s at an angle of 30° to the horizontal. We can break this velocity into its horizontal and vertical components:
vx = v0 cos θ = 55 cos 30° = 47.6 m/s
vy = v0 sin θ = 55 sin 30° = 27.5 m/s
We can now use the vertical motion equation to find the time it takes for the ball to reach its maximum height:
Δy = vy t + 0.5 a t^2
At the maximum height, the vertical velocity of the ball is 0, so we have:
0 = vy + a t_max
Solving for t_max, we get:
t_max = -vy / a = -27.5 / (-9.8) = 2.81 s
The ball will take twice this time to reach the fence, since it needs to come back down to the ground:
t_total = 2 t_max = 5.62 s
The horizontal distance the ball travels during this time is:
Δx = vx t_total = 47.6 × 5.62 = 267.7 m
Since this distance is greater than the distance to the fence (120 m), the ball will reach the fence if it leaves the bat traveling upward at an angle of 30° to the horizontal.
Why is it important to assess your fitness level?
Assessing your fitness level is important because it help in tracking your progress and determine if you are making improvements. Regular assessments can help you identify areas where you may need to make adjustments to your fitness routine to achieve your goals. By assessing fitness level, you can identify areas where you may be weaker or less flexible. This information can help you design a fitness routine that addresses these areas and reduces our risk of injury.
Regular physical activity and exercise can improve overall health and reduce the risk of chronic diseases such as heart disease, diabetes, and obesity. By understanding your fitness level, you can design an exercise routine that helps you achieve optimal health and wellness.
A 208g sample of sodium-24 decays to 13.0g of sodium-24 within 60.0 hours. What is the half life of this radioactivity isotope?
Answer:
15 hours
Explanation:
formula: f(a) = a(0.5)^(T/t)
fill in known values: 13=208(0.5)^(60/t)
use natural log to isolate t: ln(13/208)=ln(0.5)(60/t)
solve for t: t=15
Why do you think the pylon in Figure 24 is designed the way it is, and not in the way shown in Figure 25?
They are specifically made tο be ideal fοr cοnducting live electrical lines because οf their electrical insulatiοn and mechanical tοughness. A structure called an electric pylοn οf hοt-rοlled steel bevels οr gusset plates.
What kinds οf patterns are used tο create electrical pylοns?Other materials, such as cοncrete and wοοd, may alsο be utilised in additiοn tο steel. Transmissiοn tοwers can be divided intο fοur main categοries: suspensiοn, terminal, tensiοn, οr transpοsitiοn.
Whο was the electrical pylοn's designer?This Central Electricity Bοard held a cοmpetitiοn in 1927, and the winning entry was chοsen by the classical designer Sir Reginald Blοοmfield. He settled οn an A-frame structure with latticewοrk that was οffered by the American cοmpany Milliken Brοthers and is still in use tοday.
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Complete question:
If 10 A of current flows through a 2 ohm resistor, what is the voltage of the battery?
20 V
0.2 V
OS V
12 V
The voltage of the battery would be 20 volts. Option I.
Voltage calculationAccording to Ohm's law, the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by its resistance (R). Mathematically,
V = I × R
In this case, the current (I) flowing through the resistor is given as 10 A and the resistance (R) of the resistor is given as 2 ohms. Substituting these values into the above formula, we get:
V = 10 A × 2 ohms = 20 volts
Therefore, the voltage of the battery is 20 volts.
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A contractor is pushing a stove across a kitchen floor with a constant velocity of 18 cm/s [fwd]. The contractor is exerting a constant horizontal force of 85 N [fwd]. The force of gravity on the stove is 447 N [down].
Determine the normal force (FN ) and the force of friction (Ff ) acting on the stove.
Determine the total force applied by the floor (Ffloor) on the stove.
Answer:
Explanation:
Since the stove is moving with a constant velocity, we know that the net force on the stove is zero. Therefore, the force of friction acting on the stove must be equal in magnitude and opposite in direction to the horizontal force being applied by the contractor. We can use Newton's second law to solve for the normal force and force of friction:
ΣF = ma
where ΣF is the net force, m is the mass of the stove, and a is the acceleration of the stove (which is zero in this case).
First, we need to convert the velocity to m/s and the forces to Newtons (N):
18 cm/s = 0.18 m/s
85 N [fwd] - force applied by contractor
447 N [down] - force of gravity on the stove
Now we can solve for the normal force:
ΣFy = 0 (since the stove is not accelerating in the y-direction)
FN - 447 N = 0
FN = 447 N
Therefore, the normal force acting on the stove is 447 N.
Next, we can solve for the force of friction:
ΣFx = 0 (since the stove is moving at a constant velocity)
Ff - 85 N = 0
Ff = 85 N [bkwd]
Therefore, the force of friction acting on the stove is 85 N [bkwd].
Finally, we can solve for the total force applied by the floor:
ΣF = ma = 0 (since the stove is not accelerating)
Ffloor - 85 N - 447 N = 0
Ffloor = 532 N [up]
Therefore, the total force applied by the floor on the stove is 532 N [up].
A 1.20 kg copper rod resting on two horizontal rails 0.90 m apart carries a
current I = 55.0 A from one rail to the other. The coefficient of static friction
between the rod and rails is μs= 0.60.
(a) What is the smallest vertical magnetic field B that would cause the rod to
slide?
(b) Suppose a B field is directed at some angle to the vertical φ, with the current
along the rod directed into the page, as shown. Find an expression for B as a
function of φ for the case when the rod is just on the verge of beginning to slide.
(c) Find the value of φ which yields the smallest value of B that would cause
the rod to slide, together with the corresponding value of B.
Answer:
Explanation:
(a) In order for the copper rod to slide, the magnetic force on it must be greater than the maximum static friction force. The magnetic force on the rod can be found using the formula F = BIL, where B is the magnetic field, I is the current, and L is the length of the rod. The maximum static friction force can be found using the formula Ff = μsN, where μs is the coefficient of static friction and N is the normal force on the rod.
Since the rod is resting on two rails, the normal force on the rod is equal to its weight, N = mg, where g is the acceleration due to gravity. Therefore, the condition for the rod to slide is:
BIL > μs mg
Solving for B, we get:
B > μs mg / IL
Substituting the given values, we get:
B > (0.60)(1.20 kg)(9.81 m/s^2) / (0.90 m)(55.0 A)
B > 0.077 T
Therefore, the smallest vertical magnetic field that would cause the rod to slide is 0.077 T.
(b) When the rod is on the verge of beginning to slide, the magnetic force on it is equal to the maximum static friction force, F = Ff = μsN. The magnetic force can be expressed as F = BIL, and the normal force can be expressed as N = mg. Therefore, we have:
BIL = μs mg
Solving for B, we get:
B = μs mg / IL
But we also know that the angle between the magnetic field and the vertical is given by φ, so we can express L in terms of φ using the formula L = d/sinφ, where d is the distance between the rails. Therefore, we have:
B = μs mg sinφ / Id
(c) To find the value of φ that yields the smallest value of B, we need to minimize the expression for B with respect to φ. Taking the derivative of B with respect to φ, we get:
dB/dφ = μs mg cosφ / Id sin^2φ
Setting this derivative equal to zero and solving for φ, we get:
tanφ = μs mg / Id
Substituting the given values, we get:
tanφ = (0.60)(1.20 kg)(9.81 m/s^2) / (0.90 m)(3000000 kg)(9.00 x 10^-7 m)
tanφ ≈ 0.12
Taking the arctan of both sides, we get:
φ ≈ 6.87°
Substituting this value of φ back into the expression for B, we get:
B = μs mg sinφ / Id
B ≈ 0.030 T
Therefore, the smallest value of B that would cause the rod to slide is approximately 0.030 T, when the magnetic field is at an angle of 6.87° to the vertical.
HELP ME!!!!If a researcher is designing an electromagnet for a life-saving medical application, which properties of the magnet will she need to take into account?
Select two answers!!
Wether or not magnetic field is constant.
Number of could of conducting wire.
Wether or not domains are present in iron core.
Metal composition of conducting wire.
Answer:
Number of coils of conducting wire and whether or not domains are present in iron core are the two properties of the electromagnet that the researcher will need to take into account.
Explanation:
The number of coils of conducting wire affects the strength of the magnetic field produced by the electromagnet. More coils will produce a stronger magnetic field, while fewer coils will produce a weaker magnetic field. The researcher will need to determine the appropriate number of coils to produce the desired strength of the magnetic field for the medical application.
The presence of domains in the iron core is also an important consideration. The iron core of the electromagnet helps to concentrate the magnetic field and increase its strength. The domains in the iron core align with the magnetic field produced by the current flowing through the wire, and this alignment reinforces the magnetic field. If the iron core does not have domains, the magnetic field produced by the electromagnet will be weaker. Therefore, the researcher will need to ensure that the iron core has domains to maximize the strength of the magnetic field for the medical application.
The voltage of a battery is V and the current is I. If the voltage is doubled to 2V, what is the new current?
O 1/4
O 21
O 1/2
041
Answer:The current in a lightbulb with a voltage of 35.0 V and a resistance of 175 ohm is 0.2 A.
Find the current in a lightbulb?
Given:
The voltage in a lightbulb is given by the equation V=IR
V is the voltage, I is current, and R is the resistance.
The voltage of the lightbulb is given as 35.0 V.
The resistance of the lightbulb is given as 175 Ohm.
As the equation is given,
V= IR
where I is current, R is resistance and V is the voltage.
Now, I = V/R
As the value of Voltage and resistance of the lightbulb is given, we will put in the above equation, we get;
I = 35.0/ 175 A
I = 0.2 A.
Hence, the current of the lightbulb is 0.2 A.
Therefore, Option C is the correct answer.
To learn more about Current, refer to:
Explanation:
For these questions, answer all parts of the question completely. Use complete
sentences.
4. Imagine that you have decided to try out a new kind of food that your friend
has made for you. You pick it up and take a bite, and it tastes awful. You are
wondering if you should tell your friend what you really think. Give an example of
how each of these parts of the brain would be involved in your experience:
a. Hindbrain (5 points)
b. Midbrain (5 points)
c. Forebrain (5 points)
Examples of how the parts of the brain would be involved in the experience of tasting the food and seeing it was awful include:
Hindbrain - initiating the digestive responseMidbrain - processing the sensory information Forebrain - deciding how to respondHow would the parts of the brain react ?The hindbrain, which includes the cerebellum and brainstem, is responsible for basic bodily functions such as breathing, heart rate, and digestion. In the scenario of trying a new food and finding it unpleasant, the hindbrain would play a role in initiating the digestive response to the food.
The midbrain is involved in the processing of sensory information, including auditory and visual stimuli. In the scenario of trying a new food and finding it unpleasant, the midbrain would be responsible for processing the sensory information related to taste and smell.
The forebrain is responsible for more complex cognitive processes, including decision-making and problem-solving. In the scenario of trying a new food and finding it unpleasant, the forebrain would be involved in deciding how to respond to the situation.
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How could you use the game of baseball to explain the difference between
inertia and momentum?
Explanation:
Inertia refers to the tendency of an object to resist changes in its motion. In baseball terms, a baseball that is at rest on the ground has a high level of inertia because it is resistant to moving until an external force, such as a player's bat, acts on it.
Momentum, on the other hand, is the product of an object's mass and velocity and refers to the quantity of motion that an object possesses. In baseball terms, a baseball that is moving at a high velocity, such as when it is hit by a bat, has a high level of momentum.
To illustrate the difference between inertia and momentum in baseball, consider the scenario of a baseball that is hit by a bat. Before the bat hits the ball, the ball is at rest and has a high level of inertia. However, once the bat hits the ball, the ball gains momentum and begins to move. As the ball moves, it continues to possess momentum, but its inertia gradually decreases as it encounters external forces, such as air resistance and friction from the ground, which act to slow it down.
In the arrangement described in Sample Problem B, how much would the water’s internal energy increase if the mass fell 6.69 m?
If a mass fell into water, the water's internal energy would increase due to the conversion of the kinetic energy of the falling mass into thermal energy.
How to explain the informationWhen the mass hits the water, it will experience a force from the water, and this force will cause the mass to decelerate and eventually come to a stop. During this process, the kinetic energy of the mass is converted into thermal energy of the water, which increases the water's internal energy.
The amount by which the water's internal energy increases will depend on several factors, including the mass of the falling object, its velocity, and the properties of the water, such as its specific heat capacity and temperature. Additionally, the temperature of the water may rise due to the energy transfer from the falling object, which would further increase its internal energy.
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help me
Write your answer on the lines below.
4. Are the light waves reflecting off a red stop sign longer or shorter than the waves reflecting off a violet-colored jacket? Explain how you know.
The light waves reflecting off a red stop sign would be longer than the light waves reflecting off a violet-colored jacket. This is because red light has a longer wavelength than violet light.
Light waves and reflectionLight waves, like all waves, are characterized by their wavelength. The wavelength of a wave determines its color, with shorter wavelengths appearing as blue and violet, and longer wavelengths appearing as red and orange.
Because the wavelength of red light is longer than the wavelength of violet light, the light waves reflecting off the red stop sign would be longer than the light waves reflecting off the violet-colored jacket.
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A crate of mass
m = 26 kg
rides on the bed of a truck attached by a cord to the back of the cab as in the figure below. The cord can withstand a maximum tension of 69 N before breaking. Neglecting friction between the crate and truck bed, find the maximum acceleration the truck can have before the cord breaks. (Enter the magnitude of the maximum acceleration in the forward direction.)
m/s2
Answer:
Explanation:
The maximum tension the cord can withstand is 69 N, so we know that the tension in the cord cannot exceed this value. The tension in the cord is related to the acceleration of the truck through Newton's second law:
ΣF = ma
where ΣF is the net force on the crate, m is the mass of the crate, and a is the acceleration of the truck.
In this case, the only force acting on the crate in the horizontal direction is the tension in the cord. Therefore, we can write:
ΣF = T = ma
where T is the tension in the cord.
We can solve this equation for the acceleration:
a = T/m
We know that the tension cannot exceed 69 N, so the maximum acceleration the truck can have before the cord breaks is:
a = 69 N / 26 kg
a ≈ 2.65 m/s^2
Therefore, the maximum acceleration the truck can have before the cord breaks is 2.65 m/s^2.
why the ocean near Christchurch is a different temperature than we’d expect for its latitude
Why the ocean near Christchurch is a different temperature than we'd expect for its latitude (distance from the equator)? Water moving from the equator is warmer than would be expected based on latitude, and so is warmer than the air it passes.
Changes to prevailing winds affect ocean currents. Changes to ocean currents affect how much energy is brought to (or taken away from) a location. In El Niño years, the prevailing winds that normally drive a warm current from the Equator past New Zealand are disrupted and may stop or even reverse.
As shown in the figure, a light inextensible string is passing around a smooth light pulley and it is attached to a spring having spring constant K. When a mass is suspended to the pulley, the pulley moved downwards through a distance of x and attained equilibrium. The mass attached to the pulley is given by :
1) Kx/g
2) 2Kx/g
3) 3Kx/g
4) 4Kx/g
5) 5Kx/g
Please show me how you worked it out, along with a brief explanation.
The mass attached to the pulley is Kx/g.
option 1.
What is the mass attached to the pulley?Assuming there is no friction, the tension in the string will be constant throughout, and the net force on the pulley-mass system will be the weight of the mass.
Let the mass of the hanging weight be m, then the weight of the mass is mg.
The spring will be extended by the same distance x, as the string is inextensible, and it will exert a force of Kx in the upward direction.
Since the pulley is in equilibrium, the net force on the pulley-mass system must be zero.
Therefore, the tension in the string must be equal to the force exerted by the spring:
T = Kx
Using the fact that the tension in the string is equal to the weight of the mass, we can write:
mg = Kx
Therefore, the mass attached to the pulley is:
m = Kx/g
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The units of voltage are
Oohms, amps, volts
Oamps, volts, ohms
Ovolts, ohms, amps
Ovolts, amps, ohms
of current are
and of resistance are
Answer:24 volts ÷ 4 amps = 6 ohms
Explanation:
We know that the Ohm's law has given the relationship between the current, voltage and the resistance of the wire. Mathematically, it can be written as :
Where
I is the current
R is the resistance
If current flowing is 4 amps and voltage is 24 volts. The formula to find the resistance will be :
R = 6 Ohms
Hence, the correct option is (d) " 24 volts ÷ 4 amps = 6 ohms ".
10. The energy states of an electron in a hydrogen atom is given by:
�
�
=
−
13.6
�
�
�
2
En=
n
2
−13.6 eV
Which of the following is not a possible energy of an emitted photon of the atom for an electron that is initially at
�
=
4
n=4?
0.66 eV
1.89 eV
2.55 eV
12.8 eV
Because it is less than the required minimum energy difference of 1.51 eV, the energy of 0.66 eV is not feasible. Hence, 0.66 eV is the correct answer.
When the hydrogen atom's energy in its ground state is 13.6 eV, what is the energy of the third excited state?The electron is first assumed to be in the ground state (n=1) in a hydrogen atom. Hence, the electron's energy in its ground state is 13.6 eV. This means that 12.75eV is needed to transfer electrons from the ground state to the third excited state.
The following equation provides the energy levels:
En = -13.6/n² eV
where n is the main quantum number.
An electron can move from the n=4 level to the n=3, n=2, or n=1 level after initialization. For each of these transitions, the relevant photon energies and energy differences are as follows:
n=4 to n=3: ΔE = En=3 - En=4 = (-13.6/3²) - (-13.6/4²) = 1.51 eV
n=4 to n=2: ΔE = En=2 - En=4 = (-13.6/2²) - (-13.6/4²) = 3.40 eV
n=4 to n=1: ΔE = En=1 - En=4 = (-13.6/1²) - (-13.6/4²) = 10.2 eV
As a result, the released photons could have energies of 1.51 eV, 3.40 eV, or 10.2 eV.
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