solve it and get 50 points​

Answer:

[tex]\boxed {\boxed {\sf 0.0455 \ L}}[/tex]

Explanation:

We are asked to calculate the liters given the molarity and moles in a solution.

Molarity is a measure of concentration in moles per liter. It is calculated with the following solution:

[tex]molarity= \frac{moles \ of \ solute}{liters \ of \ solution}[/tex]

The molarity of the solution is 4.40 molar of potassium chloride (KCl). 1 molar is equal to 1 mole per liter, so the molarity is also 4.40 moles of potassium chloride per liter. There are 0.200 moles of potassium chloride or solute. The liters of solution is unknown, so we can use the variable x.

[tex]4.40 \ mol \ KCl/ L = \frac{ 0.200 \ mol \ KCl}{x}[/tex]

Since we are solving for x, we must isolate the variable. First, cross multiply. Multiply the first numerator by the second denominator, then the first denominator and the second numerator.

[tex]\frac {4.40 \ mol \ KCl/ L}{1} = \frac{ 0.200 \ mol \ KCl}{x}[/tex]

[tex]4.40 \ mol \ KCl / L * x= 1 * 0.200 \ mol \ KCl[/tex]

[tex]4.40 \ mol \ KCl / L * x= 0.200 \ mol \ KCl[/tex]

x is being multiplied by 4.40 moles of potassium chloride per liter. The inverse operation of multiplication is division. Divide both sides by 4.40 mol KCl/L

[tex]\frac {4.40 \ mol \ KCl / L * x}{4.40 \ mol \ KCl / L}= \frac {0.200 \ mol \ KCl}{{4.40 \ mol \ KCl / L}}[/tex]

[tex]x= \frac {0.200 \ mol \ KCl}{{4.40 \ mol \ KCl / L}}[/tex]

The units of moles of potassium chloride cancel.

[tex]x= \frac {0.200}{{4.40 L}}[/tex]

[tex]x= 0.0454545454545 \ L[/tex]

The original measurements of liters and moles have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ten-thousandth place (0.0454545454545). The 5 to the right of this place (0.0454545454545) tells us to round the 4 up to a 5.

[tex]x \approx 0.455 \ L[/tex]

There are approximately 0.455 liters in a 4.40 molar solution with 0.200 moles of solute.

In SO2 and SO3, oxygen combines with sulphur in a fixed ratio.

The law of multiple proportion states that if two elements combine with each other to form more than one chemical compound, then the various masses of the elements which combine with a fixed mass of the other element are in simple multiple ratios.

To illustrate this law, sulphur forms two oxides, SO2 and SO3. The ratio of the oxygen that combines with a fixed mass of sulphur  in the two compounds is 2:3 in accordance to the law of multiple proportion.

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Answer:

i. 1 : 2

ii. NaOH is the limiting reagent

iii. 292.5g

iv. 59.69%

Explanation:

I have the detailed and self-explanatory workings. will snap and post later. Battery percent at 15%, flashlight not working.

1. The ratio of CuSO₄ to NaOH is 1 : 2

2. The limiting reactant is NaOH.

3. The mass of Cu(OH)₂ that will precipitate out is 292.5 g.

4. The percentage yield of Cu(OH)₂ is 59.7%

1. Determination of the ratio of CuSO₄ to NaOH.

CuSO₄ + 2NaOH —> Cu(OH)₂ + Na₂SO₄

From the balanced equation above, we can see that the ratio of CuSO₄ to NaOH is 1 : 2

2. Determination of the limiting reactant.

CuSO₄ + 2NaOH —> Cu(OH)₂ + Na₂SO₄

Molar mass of CuSO₄ = 63.5 + 32 + (16×4) = 159.5 g/mol

Mass of CuSO₄ from the balanced equation = 1 × 159.5 = 159.5 g

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of NaOH from the balanced equation = 2 × 40 = 80 g

From the balanced equation above,

159.5 g of CuSO₄ reacted with 80 g of NaOH.

Therefore,

638.44 g of CuSO₄ will react with = (638.44 × 80) / 159.5 = 320.22 g of NaOH.

From the calculations made above, we can see that a higher mass (i.e 320.22 g) of NaOH than what was given (i.e 240 g) is needed to react completely with 638.44 g of CuSO₄.

Therefore, NaOH is the limiting reactant.

3. Determination of the mass of Cu(OH)₂ that will precipitate out.

CuSO₄ + 2NaOH —> Cu(OH)₂ + Na₂SO₄

Molar mass of Cu(OH)₂ = 63.5 + 2(16 + 1) = 97.5 g/mol

Mass of Cu(OH)₂ from the balanced equation = 1 × 97.5 = 97.5 g

From the balanced equation above,

80 g of NaOH reacted to produce 97.5 g of Cu(OH)₂.

Therefore,

240 g of NaOH will react to produce = (240 × 97.5) / 80 = 292.5 g of Cu(OH)₂

Thus, 292.5 g of Cu(OH)₂ precipitated out of the reaction.

4. Determination of the percentage yield.

Percentage yield = (Actual /Theoretical) × 100

Percentage yield of Cu(OH)₂ = (174.6 / 292.5) × 100

Percentage yield of Cu(OH)₂ = 59.7%

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The conclusion that can be reached is ( C ) ; The reactant was a cyclic ether

When a particular ether is heated with HBr and it yields a single organic product the only reactant that can be used to achieve this from the options listed is, Cyclic ether. because the reaction between cyclic ether and HBr will produce a single product which consists of an alcohol group ( -OH group ) and a Bromide group on each ends.

While  reactants like symmetric ether will produce alcohol and alkyl bromide

Hence the conclusion that can be reached is that the reactant used was a cyclic ether

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Answer:

I think you are moving fast my friend,but i don't remember Easter.

Answer:

yo fr i dont even remember last year christmas

Explanation:

False is the correct answer.

[tex]\huge{ \color{black}{ \boxed{ \color{hotpink}{Answer}}}}[/tex]

what is the chemical formula of (Sodium hydroxide ) ??

[tex] \: [/tex]

[tex]\large\tt\:⚘ \: MishiChaeYoon \: ⚘[/tex]

Answer:

The formula of Sodinm hydroxide is NaOH

Hope it helps

Answer: One-Thousand of a cubic metre

Explanation:

One lire is the Volume of a cube with 10 cm sides

Answer:

Explanation:

The image ending 1318 is 2-chlorophenol. The image ending 1725 is 3-chlorophenol and the image ending 1917 is 4-chlorophenol

Answer:

Since hydrogen has a single electron in its valence shell, it exhibits dual nature. of the periodic table, or it can obtain one electron to complete its valency of two, such as halogens from Group 17. Since it only has one electron in its outer shell, hydrogen has a dual existence.

Explanation:

This means that, like a normal halogen, a hydrogen atom can easily gain an electron to form a complete outer shell, or lose an electron to form an alkali metal. Since it already has two electrons in its outer shell, hydrogen can be diatomic, rendering it unreactive.

Answer:

48

Explanation:

12 g/ml * 4 ml = 48

Hi there!

1 km=1000m

so

6.86 km = 6.86×1000= 6860 m

have a nice day

#YoghurtCup!

Answer:

Cu(s) + 4HNO₃(aq) -> Cu(NO₃)₂(aq) + 2NO₂(g) + 2H₂O(l)

Answer:

gas lamp, led light, laser, inculding cfls andincandescent lights

Speed is defined as the distance travelled per unit time. Mathematically, it is expressed as:

[tex]Speed = \frac{Distance }{Time}[/tex]

To solve the question given above, we'll begin by converting 23.6 miles per hour to metre per second (m/s). This can be obtained as follow:

1 mph = 0.447 m/s

Therefore,

23.6 mph = 23.6 × 0.447

23.6 mph = 10.5492 m/s

Thus, 23.6 mph is equivalent to 10.5492 m/s

Finally, we shall determine the time taken for the racer to travel 20 m. This can be obtained as follow:

Speed = 10.5492 m/s

Distance = 20 m

[tex]Speed = \frac{Distance }{Time } \\\\10.5492 = \frac{20}{Time}[/tex]

Cross multiply

10.5492 × time = 20

Divide both side by 10.5492

[tex]Time = \frac{20}{10.5492 } \\[/tex]

Therefore, it will take 1.9 s for the racer to travel a distance of 20 m.

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Answer:

Option A is your answer

Explanation:

please mark as brainlyest

Answer:

B 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d5

Explanation:

Answer:

It might be responding variable.

Answer:D

Explanation:

a. We have 210 pennies

b. We need 140 dimes to buy as much candy as possible.  

c. All these dimes should weigh 320.6 g.

d. We can buy 70 pieces of candy.

e. The total weight of the candies will be 2864.4 g

f. Using 3 pennies and 2 dimes as a pack to buy candies we can not buy more pieces of candy because we would need more pennies.    

a. To find the number of pennies we need to divide the total mass of pennies ([tex]m_{t_{p}}[/tex]) by the mass of each one of them ([tex]m_{p}[/tex]):

[tex] N = \frac{m_{t_{p}}}{m_{p}} = \frac{636.3 g}{3.03 g} = 210 [/tex]

Hence, we have 210 pennies.  

b. We can find the total number of pieces in multiples of four that we can buy with 210 pennies. To buy one piece we need to use 3 pennies and 2 dimes, so the number of total pieces is:

[tex] 3P = 210 [/tex]

Where P is for pennies

[tex] P = \frac{210}{3} = 70 [/tex]

Hence, we can buy a total of 70 pieces in multiples of four candies.

Now, from this total of 70 pieces, we can use the following number of dimes:

[tex] 2D = 70 [/tex]

Where D is for dimes      

[tex] D = \frac{70}{2} = 140 [/tex]

Therefore, we need 140 dimes to buy as much candy as possible.

c. The mass of the total amount of dimes ([tex] m_{t_{d}}[/tex]) is:

[tex] m_{t_{d}} = 140*2.29 g = 320.6 g [/tex]

Hence, all these dimes should weigh 320.6 g.

d. We know that we can buy a total of 70 pieces in multiples of four candies (calculated above).

Then, we can buy 70 pieces of candy.

e. Knowing that each piece is a multiple of 4 candies, the weight of the 70 pieces of candy ([tex]m_{c}[/tex]) is:

[tex] m_{c} = 70*4*10.23 g = 2864.4 g [/tex]      

f. Since we can buy pieces in multiple of four candies using 3 pennies and 2 dimes if we have now twice as many dimes, we can not buy more pieces of candy because we would need more pennies.      

To see another example go here:

I hope it helps you!                                              

Answer:

A is the answer hope this helps if wrong I ont know

Answer- 2.3

Explanition-

The density of hydrochloric acid is

1.49

g/mL

, and the mass is

3.5

g

. We need to use this information to find the volume of the acid. Since the above equation shows us the relationship between density, mass, and volume, we can rearrange the equation to find the volume:

Volume

=

Mass (g)

Density (g/mL)

=

3.5

g

1.49

g/mL

=

2.349

mL

The question asks for the answer to have the correct number of significant figures. Since solving this question requires division, the measurement with the least number of significant figures decides how many significant figures the final answer should have.

1.49

has three significant figures, while

3.5

has two significant figures. Therefore, the final answer for volume can have only two significant figures, which gives the final result as:

2.3

.

The density of compound is its mass divided by volume. The volume of 3.5 g hydrochloric acid with a density 1.49 g/ml is 2.34 milliliter.

Density of a substance is the measure of its mass per volume. Thus how much denser is it in a particular volume is represented by the physical quantity density.

Density of a compound is dependant on its mass, volume, temperature, bond type and pressure. The ratio of density of any object to the density of water is called specific gravity.

It is given that the mass of hydrochloric acid is 3.5 g and density is 1.49 g/ml. The volume of HCl solution can be calculated as follows:

Density = mass/volume

volume = mass/density

            = 3.5 g/1.49 g/ml

            = 2.34 ml.

Hence, the volume of HCl solution is 2.34 ml.

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Answer:

The specific heat capacity affect heating rate by the amount of heat needed to raise the temperature of 1 gram of a substance 1 degree Celsius (°C).

Explanation: