He notices a rise in the water's temperature from 10.0°C to 18.0°C in total. The metal cube's final temperature is 69.04°C.
How can you determine the metal cube's final temperature?Q = mcT, where Q is the heat dissipated by the cube, m is its mass, c is its specific heat, and T is its change in temperature.
The formula for the energy the water gains is Q = mcT.
mcT = mcT (cube) (water)
When we solve for the cube's final temperature, we obtain:
Tcube = (m cube c cube) / (m water c water)
Tcube is equal to (18.0°C - 10.0°C) 1 kg times 4182 J/kg°C and 1 kg times 375 J/kg°C
Tcube equals 0.96 °C
Final temperature: 70 °C minus 0.96 °C equals 69.04 °C.
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what is the iupac name for the following compound? select answer from the options below 3,4-dichloroaniline 2,4-dichloroaniline 2,5-dichloroaniline 3,6-dichloroaniline 2,6-dichloroaniline
The iupac name for the following compound is 3,6-dichloroaniline. Option d is correct choice.
The IUPAC name of a compound is a systematic name that follows a set of rules defined by the International Union of Pure and Applied Chemistry (IUPAC). In the case of the given compound with two chlorine atoms and an amino group attached to a benzene ring, the correct IUPAC name is based on the positions of the chlorine atoms relative to the amino group.
To name the compound, we need to number the carbons in the benzene ring starting from one of the carbons adjacent to the amino group. The positions of the two chlorine atoms are then indicated by their numbers, separated by a comma, before the name of the parent compound, which is "aniline" in this case.
By following this procedure, we can see that the correct IUPAC name for the compound is 3,6-dichloroaniline, as the chlorine atoms are located at positions 3 and 6 relative to the amino group. Hence option d is correct choice.
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A 0.5998 g sample of a new compound has been analyzed and found to contain the following masses of elements: carbon, 0.1565 g; hydrogen, 0.02627 g; oxygen, 0.4170 g. Calculate the empirical formula of the compound.
The empirical formula of the compound is CH2O.
To find the empirical formula of the compound, we need to determine the ratios of the atoms in the compound. To do this, we need to find the number of moles of each element present in the compound.
The molar mass of carbon is 12.01 g/mol, the molar mass of hydrogen is 1.008 g/mol, and the molar mass of oxygen is 16.00 g/mol. The number of moles of carbon in the sample is:0.1565 g × 1 mol/12.01 g ≈ 0.0130 mol. The number of moles of hydrogen in the sample is:0.02627 g × 1 mol/1.008 g ≈ 0.0261 molThe number of moles of oxygen in the sample is:
0.4170 g × 1 mol/16.00 g ≈ 0.0261 mol
Now that we know the number of moles of each element, we can determine the simplest whole number ratio of the elements in the compound. We can do this by dividing each number of moles by the smallest number of moles. In this case, the smallest number of moles is 0.0130 mol.
We get:
Carbon: 0.0130 mol ÷ 0.0130 mol = 1
Hydrogen: 0.0261 mol ÷ 0.0130 mol = 2
Oxygen: 0.0261 mol ÷ 0.0130 mol = 2
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What is recycling?
A
to use materials again and again to make something new.
b
produce new brand products and sell them.
c
living in the developed world but taking care of nature.
Answer:
A
Explanation:
I believe it's A sorry if any part of my answer is wrong i tried my best to help you improve
Which shows the correct order of steps during the formation of an ionic bond?a. ions are attracted to each other → electrons are transferred → an ionic compound forms b. an ionic compound forms → ions are attracted to each other → electrons are transferred c. electrons are transferred → ions form → ions are attracted to each other d. ions form → electrons are transferred → ions are attracted to each other
The correct order of steps during the formation of an ionic bond is:
c. electrons are transferred → ions form → ions are attracted to each other.
This means that first, electrons are transferred from one atom to another to form ions with opposite charges. Then, these ions are attracted to each other by electrostatic forces, resulting in the formation of an ionic compound.
Option (a) is incorrect because it shows the attraction of ions occurring before the transfer of electrons.
Option (b) is incorrect because it shows the formation of an ionic compound occurring before the attraction of ions.
Option (d) is incorrect because it shows the attraction of ions occurring after the transfer of electrons.
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a rather confused student, ina fogg, hydrolyzed the intermediate ester with 6 m hcl rather than 3 m naoh, and then she boiled the reaction mixture with 50% naoh instead of 6 m hcl. filtration of the cooled solution yielded only a little dimedone. finally realizing her mistake, she acidified the filtrate and a white solid precipitated, but its melting point was different from that of dimedone. what was this solid, and how did it form?
The white solid formed was likely a different compound due to the use of incorrect reagents and conditions during the reaction.
When an ester is hydrolyzed with HCl, the reaction typically proceeds via an acid-catalyzed mechanism, in which the ester is protonated to form a tetrahedral intermediate that quickly breaks down into a carboxylic acid and an alcohol. On the other hand, when an ester is hydrolyzed with NaOH, the reaction proceeds via a base-catalyzed mechanism, in which the ester is deprotonated to form a negatively charged intermediate that quickly breaks down into a carboxylate ion and an alcohol.
In this case, the student hydrolyzed the intermediate ester with 6 M HCl instead of 3 M NaOH. This likely led to the protonation of the intermediate and the formation of a carboxylic acid and an alcohol. The student then boiled the reaction mixture with 50% NaOH instead of 6 M HCl. This would have led to the deprotonation of the carboxylic acid and the formation of a carboxylate ion and an alcohol. However, since the NaOH concentration was much higher than what was needed for the reaction, it's possible that the reaction was not selective and other side reactions occurred as well.
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he partial pressure of carbon dioxide is 45 mm hg in the blood and 40 mm hg in the alveoli. what happens to the carbon dioxide?
b) It diffuses into the alveoli is the correct option. The gas goes from a higher partial pressure to a lower partial pressure along its own gradient.
The partial pressure of CO2 at the blood is thus 45 mm Hg and at the alveoli is 40 mm Hg. After then, CO2 travels from the blood to the alveoli. In this mechanism, CO2 cannot be broken down into carbon and oxygen. Compared to O2, CO2 is more soluble in blood. For CO2 diffusion, a very small partial pressure gradient is required. It just takes a 5-mmHg pressure gradient for CO2 gas to diffuse. Hence, CO2 will transfer from blood into alveoli.
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Complete Question:
The partial pressure of carbon dioxide is 45 mm Hg in the blood and 40 mm Hg in the alveoli. What happens to the carbon dioxide?
a) It diffuses into the blood.
b) It diffuses into the alveoli.
c) The gradient is too small for carbon dioxide to diffuse.
d) It decomposes into carbon and oxygen
what is the solubility in moles/liter for calcium fluoride at 25 oc given a ksp value of 4.0 x 10-11. write using scientific notation and use 1 or 2 decimal places (even though this is strictly incorrect!)
Solubility of [tex]CaF$_2$[/tex] at 25°C with Ksp of 4.0 x [tex]10$^{-11}$[/tex] is approximately 6.34 x [tex]10$^{-4}$[/tex] mol/L.
The dissolvability of a substance is characterized as the most extreme measure of the substance that can break up in a given dissolvable at a specific temperature and strain. The dissolvability of calcium fluoride [tex](CaF$_2$)[/tex] at 25°C can be determined utilizing its Ksp esteem, which is 4.0 x [tex]10$^{-11}$[/tex].The Ksp articulation for [tex]CaF$_2$[/tex] is:
Ksp = [tex][Ca$^{2+}$][F$^{-}$]$^2$[/tex]
Let the dissolvability of [tex]CaF$_2$[/tex] be addressed by the variable x, so the convergences of [tex]Ca$^{2+}$[/tex] and [tex]F$^{-}$[/tex] in arrangement will be equivalent to x.Subbing these qualities into the Ksp articulation gives:
Ksp = [tex]x$\times$x$^2$ = x$^3$[/tex]
Reworking the condition gives:
x = [tex](Ksp)$^{1/3}$[/tex]
Subbing the worth of Ksp = 4.0 x [tex]10$^{-11}$[/tex] into the above condition gives:x = [tex](4.0 x 10$^{-11}$)$^{1/3}$ = 6.34 x 10$^{-4}$[/tex] mol/L
In this manner, the dissolvability of calcium fluoride at 25°C is around 6.34 x [tex]10$^{-4}$[/tex] mol/L, adjusted to two decimal spots for comfort. This really intends that at harmony, 6.34 x [tex]10$^{-4}$[/tex] moles of calcium fluoride can break up in one liter of water at 25°C.
On the off chance that how much [tex]CaF$_2$[/tex] in arrangement is higher than this worth, it will encourage out of the arrangement, and assuming it is lower, more [tex]CaF$_2$[/tex] will break down until the balance focus is reached.
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from the following options, which would you expect to be the best nucleophile? ---------------------------------------------------------------------------------------------------------------------'
Answer:
CH3-0-
Explanation:
An anion is always a better nucleophile than a neutral molecule.
Nucleophilicity is parallel to basicity. Acidity: HI > HCN > H₂O > EtOH. So, among the options provided, the best nucleophile is A) [tex]EtO}^-[/tex].
A chemical species known as a nucleophile is one that tends to give an electron pair to an electrophile during a chemical reaction, often an atom or an ion. The word "nucleophile," which refers to someone who is drawn to positively charged regions in a chemical reaction, is derived from the Latin terms "nucleus," which means "nucleus or core," and "philein," which means to love.
Many chemical processes, including addition, elimination, and nucleophilic substitution reactions, depend heavily on nucleophiles. In these reactions, molecules that are electron-deficient and have a propensity to attract electrons—known as electrophiles—are attacked by nucleophiles.
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From the following options, which would you expect to be the best nucleophile?
A) [tex]EtO}^-[/tex]
B) [tex]{OH}^-[/tex]
C) [tex]{CN}^-[/tex]
D) [tex]{I}^-[/tex]
for the following reaction, kp = 0.262 at 1000°c: c(s) 2h2(g) ⇌ ch4(g) at equilibrium, the partial pressure of h2 is 1.26 atm. what is the equilibrium partial pressure of ch4(g)?
The equilibrium partial pressure of CH4(g) is 0.417 atm.
For the following reaction, Kp = 0.262 at 1000°C: C(s) + 2H2(g) ⇌ CH4(g) At equilibrium, the partial pressure of H2 is 1.26 atm.
The equilibrium constant (Kp) is defined as the ratio of the partial pressures of products to the partial pressures of reactants with each concentration term raised to a power equivalent to its coefficient in the balanced chemical equation.
At equilibrium, the partial pressure of H2 is 1.26 atm. CH4 partial pressure can be calculated by applying the equilibrium constant to this value. Here are the steps for calculating the equilibrium partial pressure of CH4(g): Write the equilibrium equation and the corresponding Kp expression.
Calculate the value of Kp.Substitute the known partial pressure of H2 into the equilibrium expression and solve for the unknown equilibrium partial pressure of CH4(g).At equilibrium, C(s) + 2H2(g) ⇌ CH4(g)The Kp expression is: Kp = PCH4/PH2²Kp = 0.262PCH4 = (Kp)(PH2²)PCH4 = (0.262)(1.26²)PCH4 = 0.417 atm
Therefore, the equilibrium partial pressure of CH4(g) is 0.417 atm.
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for the compound ba(oh)2 what are the formulas of all the species you expect to be present in aqueous solution?
For the compound Ba(OH)2, the formulas of all the species that you can expect to be present in aqueous solution are:Ba2+ and 2OH-Ba2+ represents the cationic part of the compound, while 2OH- represents the anionic part of the compound.
In an aqueous solution of Ba(OH)2, the ions would dissolve and exist as free ions. The Ba2+ ion would carry a +2 charge, while the OH- ions would each carry a -1 charge. The balanced chemical equation for the compound dissociation in water is:Ba(OH)2 + 2H2O → Ba2+ + 2OH- + 2H2O
Thus, the formulas of all the species that you can expect to be present in an aqueous solution of Ba(OH)2 are Ba2+ and 2OH-.
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does the freezing point depression equal the freezing point of pure solution minus the freezing point of the solution
No, the freezing point depression does not equal the freezing point of the pure solvent minus the freezing point of the solution.
The freezing point depression is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution. In other words, it is the amount by which the freezing point of the solvent is lowered when a solute is added to it.
The freezing point depression is related to the concentration of the solute in the solution, as well as the properties of the solvent and solute. The greater the concentration of the solute, the greater the freezing point depression.
The relationship between freezing point depression, solute concentration, and solvent properties is described by the equation ΔTf = Kf·m, where ΔTf is the freezing point depression, Kf is the freezing point depression constant of the solvent, and m is the molality of the solute in the solution.
In summary, the freezing point depression is not equal to the freezing point of the pure solvent minus the freezing point of the solution, but rather the difference between the freezing point of the pure solvent and the freezing point of the solution, and is related to the concentration of the solute in the solution.
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you prepare a solution by mixing 15 grams of sucrose with 85 grams of water. what is the percent mass of sucrose in your solution? % mass (b) you prepare a solution by mixing 30 ml of chloroform with 45 ml of water. what is the percent volume of chloroform in your solution? % volume
A solution by mixing 15 grams of sucrose with 85 grams of water. (a), The percent mass of sucrose in your solution is 15%. (b)The percent volume of chloroform in your solution is 40%.
(a) To find the percent mass of sucrose in the solution, follow these steps:
1. Calculate the total mass of the solution by adding the mass of sucrose and water:
Total mass = mass of sucrose + mass of water
Total mass = 15 grams + 85 grams = 100 grams
2. Calculate the percent mass of sucrose using the formula:
% mass = (mass of sucrose / total mass) × 100
% mass = (15 grams / 100 grams) × 100 = 15%
The percent mass of sucrose in your solution is 15%.
(b) To find the percent volume of chloroform in the solution, follow these steps:
1. Calculate the total volume of the solution by adding the volume of chloroform and water:
Total volume = volume of chloroform + volume of water
Total volume = 30 mL + 45 mL = 75 mL
2. Calculate the percent volume of chloroform using the formula:
% volume = (volume of chloroform / total volume) × 100
% volume = (30 mL / 75 mL) × 100 = 40%
The percent volume of chloroform in your solution is 40%.
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What are the following organic molecules.
Answer: [1 ] 3-ethyl- 1,1-dimethyl-cyclohexane
[2] 1-methyl-ethoxy-propanol
[3] 4-oxo-pentan-2-one
[4] 2-ethyl-4-hydroxy-3-methyl-pentanoic acid
Explanation:
which one of the following general characteristics is shared by all catalysts? a) they induce more collisions among reactant molecules. b) they transfer kinetic energy to the reactant molecules. c) they increase the reaction rate but do not change the keq of a reversible reaction.
When answering questions, a question-answering bot on the platform Brainly should always be factually accurate, professional, and friendly. It should be concise and should not provide extraneous amounts of detail. It should not ignore any typos or irrelevant parts of the question.What is a catalyst?A catalyst is a substance that increases the rate of a chemical reaction without undergoing any permanent chemical change itself. This means that the catalyst is neither consumed nor produced in the reaction. In other words, the catalyst does not participate in the reaction itself, but it speeds up the reaction. There are many different types of catalysts, including enzymes, metals, acids, and bases.Which one of the following general characteristics is shared by all catalysts?A catalyst increases the rate of a chemical reaction, but it does not change the key of a reversible reaction. Therefore, the correct answer is c) they increase the reaction rate but do not change the key of a reversible reaction.
All catalysts share the general characteristic (c): they increase the reaction rate but do not change the equilibrium of a reversible reaction. Catalysts work by providing an alternative reaction pathway with a lower activation energy, allowing reactant molecules to convert into products more easily. However, they do not affect the overall energy balance of the reaction or its reversibility.
what will the concentrations of each species be when equilibrium is reestablished, relative to what they were in the initial equilibrium? justify your answer.
In general, the concentrations of each species at equilibrium will depend on the stoichiometry of the reaction, the equilibrium constant (K), and the initial concentrations of the reactants and products.
At equilibrium, the forward and reverse reaction rates are equal, and the concentrations of the reactants and products no longer change with time. The concentrations of each species at equilibrium will depend on the initial concentrations and the equilibrium constant. If the equilibrium constant is large, then the reaction will favor the products at equilibrium. If the equilibrium constant is small, then the reaction will favor the reactants at equilibrium.
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magnesium ions form ioni bods with flouride ions in a 1:2 ratio.explain how eletrons are transferred between atoms and how the ionic bonds form in this compound
Total two electrons are transferred between atoms of magnesium and flourine. Ionic bond is formed between atoms by donating two electrons of magnesium atom to the two fluorine atoms.
Every element has atomic orbitals that contain a specific number of electrons . Out of these electrons, only outermost shell electrons of the atom participating in bond formation with another atom. We have a ratio of magnesium to fluoride ions, mole ratio = 1 : 2 , that one magnesium and two flourine atoms are there. Electronic configuration of Mg (12)
= 1s²2s²2p⁶3s²
Similarly, Electronic configuration of F (17)
= 1s²2s²2p⁶3s²3p⁵
Thus, the valency of Magnesium is two and Fluorine is one. Ionic compound is formed by magnesium cation and fluoride anion. Thus, magnesium'valence electrons (2 electrons) will be transferred completely to form an ionic bond with two fluorine atoms having 7 valence electrons each and form a MgF₂ molecule. The Lewis structure of MgF₂ compound is present in above figure.
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Which atom is a different element than the others
Help what's the answer??
Theoretical yield of iron (III) oxide is 4.92 g ; percent yield for this reaction is approximately 73.3%.
What is meant by theoretical yield?Quantity of a product obtained from reaction is expressed in terms of yield of the reaction. Amount of product predicted by stoichiometry is called theoretical yield and whereas amount obtained actually is called actual yield.
Balanced chemical equation for the reaction is: 4Fe + 3O₂→ 2Fe₂O₃
Molar mass of Fe = 55.85 g/mol
So, Number of moles of Fe = mass/molar mass = 3.44 g/55.85 g/mol = 0.0615 mol
and Number of moles of Fe₂O₃ = 0.0615 mol Fe × (2 mol Fe₂O₃/4 mol Fe) = 0.0308 mol Fe₂O₃
Molar mass of Fe2O3 = 159.69 g/mol
Theoretical yield of Fe₂O₃ = number of moles × molar mass = 0.0308 mol × 159.69 g/mol = 4.92 g
Therefore, theoretical yield of iron (III) oxide is 4.92 g.
As percent yield = (actual yield / theoretical yield) x 100%
So, percent yield = (4.32 g / 5.89 g) x 100% ≈ 73.3%
Therefore, percent yield for this reaction is approximately 73.3%.
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graphite is made up of layers of graphene. each layer of graphene is about 200 picometers, or meters, thick. how many layers of graphene are there in a 1.6-mm-thick piece of graphite? express your answer in scientific notation.
As a result, a 1.6-mm-thick slice of graphite has 8 106 layers of graphene. The solution is 8.0 1006. We can use unit conversions to solve this problem.
1 picometer (pm) = 1 × 10^-12 meters (m)
Therefore, 200 picometers (200 pm) = 200 × 10^-12 meters (m)
To find the number of layers of graphene in a 1.6-mm-thick piece of graphite, we need to divide the thickness of the graphite by the thickness of one layer of graphene:
1.6 mm = 1.6 × 10^-3 meters (m)
Number of layers of graphene = thickness of graphite / thickness of one layer of graphene
= (1.6 × 10^-3 m) / (200 × 10^-12 m)
= 8 × 10^6
Therefore, there are 8 × 10^6 layers of graphene in a 1.6-mm-thick piece of graphite. Expressed in scientific notation, the answer is 8.0 × 10^6.
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how many molecules of naclo4 are in 4.446 g of naclo4
There are 1.69 x 10²² molecules of NaClO4 in 4.446 g of NaClO4.
Avogadro's number (6.022 x 10²³) is the basis of calculations that convert grams to atoms or molecules.
The molar mass of NaClO4 is 22.99 + 35.45 + 4(16.00) = 146.99 g/mol, which is found by adding the atomic masses of each component. This is then converted to moles by dividing the mass of the sample by the molar mass.
The number of molecules can be found by multiplying the number of moles by Avogadro's number, which gives the number of molecules. The following is the calculation:
mass of NaClO4 = 4.446 g
molar mass of NaClO4 = 146.99 g/mol
moles of NaClO4 = mass / molar mass = 4.446 g / 146.99 g/mol = 0.03022 mol
Number of molecules = Avogadro's number × moles = (6.022 x 10²³) x 0.03022 = 1.69 x 10²² molecules
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the reaction rate constant is determined to be 0.012 m-1 s-1. if after 27 minutes the amount of a left is 0.048 m. what was the initial concentration of a?
The initial concentration of 'A' was approximately 1.371 M.
To determine the initial concentration of 'A' given the reaction rate constant, time, and the remaining amount of 'A', you can use the integrated rate law equation for a first-order reaction:
[A]t = [A]₀ * e^(-kt)
where:
[A]t = concentration of 'A' at time t (0.048 M)
[A]₀ = initial concentration of 'A'
k = reaction rate constant (0.012 M⁻¹ s⁻¹)
t = time in seconds (27 minutes = 27 * 60 = 1620 seconds)
Now, let's solve for [A]₀:
0.048 M = [A]₀ * e^(-0.012 M⁻¹ s⁻¹ * 1620 s)
To find [A]₀, divide both sides by e^(-0.012 * 1620):
[A]₀ = 0.048 M / e^(-0.012 * 1620)
Now, calculate the value:
[A]₀ ≈ 0.048 M / e^(-19.44)
[A]₀ ≈ 0.048 M / 0.000035
[A]₀ ≈ 1.371 M
So, the initial concentration of A was approximately 1.371 M.
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Define a daughter element
Answer:
A daughter element is the element formed when a radioactive element undergoes radioactive decay
Explanation:
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I need help w the moon phase for science
Answer:
where is the photo
Explanation:
where is it???
identify the relationship in the following pair. do the drawings represent constitutional isomers or stereoisomers, or are they just different ways of drawing the same compound? if they are stereoisomers, are they enantiomers or diastereomers?
The following drawings depict enantiomers or diastereomers:
A Diastereomers
B. Enantiomers
C. Diastereomers
D. Diastereomers
E. Enantiomers
F. Diastereomers
G. Enantiomers
H. Diastereomers
I. Enantiomers
J. Enantiomers
Enantiomers and diastereomers are two types of stereoisomers, which are molecules that have the same molecular formula and connectivity but differ in their three-dimensional arrangement of atoms in space. Enantiomers are mirror images of each other and cannot be superimposed on each other, like a left and right hand. They have identical physical and chemical properties, except for the way they interact with polarized light.
Enantiomers rotate plane-polarized light in opposite directions and are therefore called optical isomers. Diastereomers, on the other hand, are stereoisomers that are not mirror images of each other and can be distinguished by their physical and chemical properties. Unlike enantiomers, diastereomers do not rotate plane-polarized light in opposite directions. They have different melting and boiling points, solubilities, and reactivities.
The complete question
Identify the relationship in each of the following pairs. Do the drawings(image attached) represent constitutional isomers or stereoisomers, or are they just different ways of drawing the same compound? If they are stereoisomers, are they enantiomers or diastereomers?
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the citric aicd cycle. for each glucose molecule c6h12o6 oxidized by cellular reespiration, how many molecules of co2 are released in the citric acid cycle
In cellular respiration, one molecule of glucose (C6H12O6) is oxidized to produce energy in the form of ATP through a series of metabolic reactions, including the citric acid cycle.
During the citric acid cycle, acetyl-CoA, which is produced from the breakdown of glucose in earlier steps of cellular respiration, enters the cycle and reacts with oxaloacetate to form citrate. Through a series of enzymatic reactions, citrate is eventually converted back to oxaloacetate, producing CO2, NADH, FADH2, and ATP in the process.
For each glucose molecule oxidized by cellular respiration, two molecules of pyruvate are produced during glycolysis. Each pyruvate molecule then enters the mitochondria and is converted to one molecule of acetyl-CoA, which enters the citric acid cycle. Therefore, for each glucose molecule oxidized, two molecules of acetyl-CoA enter the citric acid cycle.
During the citric acid cycle, two molecules of CO2 are produced for each molecule of acetyl-CoA that enters the cycle. Therefore, for each glucose molecule oxidized by cellular respiration, a total of four molecules of CO2 are produced in the citric acid cycle (two for each acetyl-CoA molecule).
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YA'LL ARE SMART PLS HELP!! I will mark brainliest!!
Mg + 2 HCl ➞ MgCl2 + H2
2.26 moles of HCl are reacted how many grams of Mg were used in the reaction??
Answer: 24.31g/mol
Explanation:
The correct answer is To determine the mass of Mg used in the reaction, we need to know the number of moles of Mg that reacted with the 2.26 moles of HCl. To do this, we can use the mole ratio from the balanced chemical equation:
Mg + 2 HCl → MgCl2 + H2 According to the stoichiometry of this equation, 1 mole of Mg reacts. With 2 moles of HCl to produce 1 mole of MgCl2 and 1 mole of H2. Therefore, to determine the amount of Mg used in the reaction, we need to first calculate the number of moles of HCl that reacted, and then use the mole ratio between Mg and HCl to find the number of moles of Mg. Given that 2.26 moles of HCl were used in the reaction, we can use the mole ratio of the balanced equation to calculate the number of moles of Mg moles of Mg = 1/2 x moles of HCl = 1/2 x 2.26 mol = 1.13 mol Now that we know the number of moles of Mg used, we can calculate the mass of Mg using its molar mass: mass of Mg = moles of Mg x molar mass of Mg = 1.13 mol x 24.31 g/mol = 27.5 g Therefore, the mass of Mg used in the reaction was 27.5 grams.
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consider a solution of two gases. what is the effect of withdrawing heat on the probability of a successful reaction, on a per-collision basis?
Withdrawing heat from a solution of two gases will lower the temperature, affecting the probability of a successful reaction on a per-collision basis.
When temperature decreases, the average kinetic energy of the gas molecules also decreases. Consequently, the molecules move slower, resulting in fewer collisions between them. This reduces the chances of successful reactions occurring during each collision.
Moreover, a lower temperature means that the energy barrier for a reaction, known as activation energy, becomes relatively higher compared to the average kinetic energy of the molecules. Activation energy is the minimum amount of energy required for a reaction to occur.
The reaction rate, which is the speed at which a reaction proceeds, is influenced by temperature. The Arrhenius equation, which quantifies the relationship between temperature and reaction rate, shows that a decrease in temperature results in a slower reaction rate.
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The calibration is to the 2mL, so we do not estimate another digit. What is the volume of liquid in the cylinder?
If the calibration is to 2 ml, calibration lines are marked on the cylinder every 2 ml. Therefore, we can calculate the liquid volume in the cylinder to the nearest 2 ml.
What does "calibration" signify in chemistry?Calibration in chemistry is the process of ensuring that any scientific method or instrument produces accurate results. If the calibration is 2 ml, then there are calibration lines on the cylinder spaced 2 ml apart.
How does calibration work?Formally, calibration is the process of comparing a measurement device that needs to be calibrated to a device or reference standard that can be tracked. The term "calibrator" may also be used to describe the reference standard. According to logic, the calibration of the instrument should be more precise than the reference standard.
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dinitrogen monoxide gas is collected at in an evacuated flask with a measured volume of . when all the gas has been collected, the pressure in the flask is measured to be . calculate the mass and number of moles of dinitrogen monoxide gas that were collected. round your answer to significant digits.
Once you have the correct values for pressure, volume, and temperature, follow these following steps to calculate the mass and number of moles of dinitrogen monoxide gas collected.
To calculate the mass and number of moles of dinitrogen monoxide gas collected, we will use the ideal gas law equation:
PV = nRT
where:
P = pressure in the flask
V = measured volume of the flask
n = number of moles of gas
R = ideal gas constant (0.0821 L atm / K mol)
T =temperature in Kelvin
However, the student question did not provide values for the pressure, volume, or temperature. Assuming that you have these values, you can proceed as follows:
1. Convert the given temperature to Kelvin if it's in Celsius (K = °C + 273.15).
2. Plug in the given values for P, V, and T into the ideal gas law equation
3. Solve for n (number of moles):
n = PV / RT
4. Calculate the mass of dinitrogen monoxide (N₂O) gas using the molar mass (44.013 g/mol):
mass = n × molar mass
5. Round your answers to the appropriate significant digits.
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How many moles are in 4392.3g ammonium sulfate?
Answer:
The molar mass of ammonium sulfate ((NH4)2SO4) is:
2 x (14.01 g/mol) (for the nitrogen atoms in the ammonium ions)
8 x (1.01 g/mol) (for the hydrogen atoms in the ammonium ions)
1 x (32.06 g/mol) (for the sulfur atom)
4 x (16.00 g/mol) (for the oxygen atoms in the sulfate ion)
= 132.14 g/mol
To convert the mass of 4392.3 g of ammonium sulfate to moles, we need to divide this mass by the molar mass:
moles = 4392.3 g / 132.14 g/mol
moles = 33.20 mol (rounded to two decimal places)
Therefore, there are 33.20 moles in 4392.3 g of ammonium sulfate.
33.20 mol are in 4392.3 g of ammonium sulfate. The mole designates 6.022×10²³ units, which is a very large number.
What is mole?In chemistry, a mole, usually spelt mol, is a common scientific measurement unit for significant amounts of very small objects like atoms, molecules, or even other predetermined particles. The mole designates 6.022×10²³ units, which is a very large number. Under the International Units of Measure (SI), the mole is defined as this number as of May 20, 2019, according the General Meeting on Weights as well as Measurements.
The amount of atoms discovered through experimentation to be present in 12 grammes of carbon-12 was originally used to define the mole. In honour of a Italian scientist Amedeo Avogadro, the amount of cells inside a mole is also known as Avogadro's number or Avogadro's constant (1776–1856).
The molar mass of ammonium sulfate=2 x (14.01 g/mol)+8 x (1.01 g/mol)+1 x (32.06 g/mol)+4 x (16.00 g/mol) = 132.14 g/mol
moles = 4392.3 g / 132.14 g/mol
moles = 33.20 mol
Therefore, 33.20 mol are in 4392.3 g of ammonium sulfate. The mole designates 6.022×10²³ units, which is a very large number.
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