pls say hard
very hard​

Pls Say Hardvery Hard

Answers

Answer 1

Answer:

3

Step-by-step explanation:


Related Questions

find the value of a and b in (a,2)=(2,b)​

Answers

Answer:

a=2 and b=2...............

The sum of twice a number and three

Answers

Answer:

i dont get what youre asking

Step-by-step explanation:

Answer:

2n + 3

Step-by-step explanation:

n = number

Sum of twice a number (2n) and (3)

-> 2n + 3

3cm and 7cm
please help me find the area and the perimeter of the above figures using the formular ​

Answers

Its must be a rectangle

Length=3cmBreadth=7cm

Perimeter:-

[tex]\\ \sf\longmapsto 2(L+B)[/tex]

[tex]\\ \sf\longmapsto 2(3+7)[/tex]

[tex]\\ \sf\longmapsto 2(10)[/tex]

[tex]\\ \sf\longmapsto 20cm[/tex]

Area:-

[tex]\\ \sf\longmapsto Length\times Breadth[/tex]

[tex]\\ \sf\longmapsto 3(7)[/tex]

[tex]\\ \sf\longmapsto 21cm^2[/tex]

Answer:

Length=3cm

breadth=7cm

Area(A)=?

we know that,

Area of rectangle (A)=l*b

=3cm*7cm

= 21cm^2

Now,

Perimeter (P)= 2(l+b)

=2(3cm+7cm)

=2*10cm

=20cm Ans.

The area of a circle is 78.5 cm^2. What is the diameter of the circle?
-5 cm
-10 cm
-12.5 cm
-39.25 cm

Answers

Answer:

10cm

Step-by-step explanation:

78,5=pi.r^2

Answer5:

Step-by-step explanation:

4 adults consumed food costing $60 for 3days. For the same food cost ,what would be the cost of food consumed by 7 adults for 5days?

Answers

Answer:

$175

Step-by-step explanation:

$60÷3÷4 =5

$5 is the cost of one adult's food for one day.

$5×7×5

=$175

$175 is the cost of food consumed by 7 adults for 5 days.

Consider the points below. P(â1, 4, 1), Q(0, 6, 2), R(4, 3, â1)

a. Find a nonzero vector orthogonal to the plane through the points P, Q, and R.
b. Find the area of the triangle PQR.

Answers

Answer:

B. Find the area of the triangle PQR.

3/6, 1/12, 3/6, 3/60 determine the lcd by division of prime number

Answers

Answer:

LCD = 60

BRAINLIEST, PLEASE!

Step-by-step explanation:

All of the denominator numbers are multiples of 60, and since 60 is also equal to the largest denominator number, it's the LCD.

The Earth scientist most likely to study volcanoes is a (n)

A. Meteorologist

B. Geologist

C. Oceanographer

D. Astronomer

Answers

The answer is B Geologist

Answer:

geologist

Step-by-step explanation:

they work with the earths surface and natural land that changes

Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its speed, as time increases?

A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins at 0, goes up at first, is steady for a while, and then goes down over time.
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins in the middle of the vertical axis, goes down at first, is steady for a while, and then goes up over time.
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins at 0, goes up at first, goes down for a while, and then is steady over time.

Answers

9514 1404 393

Answer:

  A

Step-by-step explanation:

If you read your own question, you find that it answers itself.

The problem statement tells you that speed ...

  ... increasing its speed, constant speed, then decreases

And it tells you the graphs show ...

  (a) begins at 0, goes up, is steady for a while, and then goes down

  (b) begins in the middle, goes down, is steady, and then goes up

  (c) begins at 0, goes up, goes down, and then is steady

___

The first graph has the increasing, steady, decreasing pattern you're looking for.

[tex]\lim_{n \to \0}(x/(tan⁡(x))^(cot⁡(x)^2 )[/tex]

Answers

It looks like the limit you want to compute is

[tex]\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}[/tex]

Rewrite the limand with an exponential and logarithm:

[tex]\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Now, since the exponential function is continuous at 0, we can write

[tex]\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Let M denote the remaining limit.

We have [tex]\dfrac x{\tan(x)}\to1[/tex] as [tex]x\to0[/tex], so [tex]\ln\left(\dfrac x{\tan(x)}\right)\to0[/tex] and [tex]\tan^2(x)\to0[/tex]. Apply L'Hopital's rule:

[tex]\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}[/tex]

Simplify and rewrite this in terms of sin and cos :

[tex]\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}[/tex]

As [tex]x\to0[/tex], we get another 0/0 indeterminate form. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}[/tex]

Recall the double angle identity for sin:

sin(2x) = 2 sin(x) cos(x)

Also, in the numerator we have

cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)

So we can simplify M as

[tex]\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}[/tex]

This again yields 0/0. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}[/tex]

Once again, this gives 0/0. Apply L'Hopital's rule one last time:

[tex]\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}[/tex]

Now as [tex]x\to0[/tex], the terms containing x and sin(nx) all go to 0, and we're left with

[tex]M = \dfrac{4-8}{12} = -\dfrac13[/tex]

Then the original limit is

[tex]L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}[/tex]

QUESTION 1 11 How does the term quartile relate to how data values are grouped when using a five- number summory?​

Answers

Data from the Bureau of Labor Statistics has been put into order by placing data in the lower and upper quartiles. If data are placed in order, then the lower quartile is central to the lower half of the data and the upper quartile becomes central to its upper half.

Identify which of the twelve basic functions listed below fit the description given.
y = x, y = x2, y = x3, y = , y = , y = ex, y = , y = ln x, y = sin x, y = cos x, y = int (x), y = 1/1+e-x
The two functions with infinitely many zeros

Answers

Try this option:

only periodical functions have many zeros, that is why y=sinx and y=cosx are the correct answer.

The functions y = x and y = x³ have infinitely many zeros. These functions pass through the origin and have a unique property that allows them to intersect the x-axis an infinite number of times.

The two functions with infinitely many zeros from the given list of twelve basic functions are y = x and y = x³

The function y = x has infinitely many zeros because any value of x that equals zero will result in y also being zero.

In other words, for every x value of 0, the corresponding y value is also 0.

This makes the function pass through the origin (0, 0) and have an infinite number of zeros.

2. The function y = x³ also has infinitely many zeros because the cube of any real number is zero if and only if the number itself is zero.

This means that for every x value of 0, the corresponding y value is also 0. Hence, the function y = x³ passes through the origin (0, 0) and has an infinite number of zeros.

In summary, the functions y = x and y = x³ have infinitely many zeros. These functions pass through the origin and have a unique property that allows them to intersect the x-axis an infinite number of times.

To know more about functions here

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Help me then get brainlest

Answers

Hi ;-)

This angle is

obtuse

Answer:

This is an obtuse angle

Step-by-step explanation:

Anything over 90 degrees is obtuse

Problem 2
Find the area of each shaded region. Show or explain your reasoning.
A
2 cm
B
2 cm
2cm
6 cm
5 cm
3 cm
6 cm
8 cm
C С
D
15 cm
8 cm
8 cm
15 cm
9 cm
6 cm
10 cm

Answers

Step-by-step explanation:

A

this is the combination of a 4×6 rectangle and a 2×2 square. nothing is excluded.

so, the area is

(6-2)×6 + 2×2 = 4×6 + 4 = 24 + 4 = 28 cm²

B

this is the area of the large 8×5 rectangle minus the area of the small 2×3 rectangle.

so the area is

8×5 - 3×2 = 40 - 6 = 34 cm²

C

Basically the same thing as for B. large rectangle minus smaller rectangle.

so, the area is

15×10 - 9×6 = 150 - 54 = 96 cm²

D

the area of a triangle is

baseline × height / 2

or baseline here is 2×8, and the height is 5

so we get the area

2×8 × 5 / 2 = 8×5 = 40 cm²

RACE A city hosts a race annually. They decide to place a
camera halfway between the start and finish lines. If A
represents the starting line and Z represents the finish line,
find the coordinate of the midpoint.

Answers

Answer:

M

Step-by-step explanation:

M is in the middle of the alphabet, so it would be the midpoint of A-Z if they were placed on a coordinate plane.

Name the two input device​

Answers

Answer:

keyboard and mouse are two examples of input device

Answer:

keyboard and mouse

Step-by-step explanation:

If you like my answer than please mark me brainliest

19. When the members of a high school club are
arranged in rows of 2, 3, or 4, there is one
person always left over. But when the club
members are arranged in rows of 5, no one is
left over. What is the least number of people
who could be in the club?
À 15 people
C 45 people
B 25 people D 85 people

Answers

9514 1404 393

Answer:

 B.  25 people

Step-by-step explanation:

The remainders tell you the number will be 1 more than some multiple of the least common multiple (LCM) of 2, 3, and 4. The LCM is 3·4 = 12, so we want some multiple (n) of that such that 12n+1 is a multiple of 5. We know this is the case for n=2.

The least number of people who could be in the club is 2·12+1 = 25.

Anyone’s knows how do this and the answer?

Answers

Answer:

12 -16. 19

4. 8. 22

3. -9. -4

Step-by-step explanation:

13-1 = 12

-10-6= -16

12 - -7 = 12+7=19

6-2 = 4

Keep subtracting

y=3x+2y is it a function how do you do it

Answers

9514 1404 393

Answer:

  yes

Step-by-step explanation:

Solve for y. You can do this by subtracting 3x+y from both sides of the equation.

  y -(3x+y) = 3x +2y -(3x +y)

  -3x = y

Or ...

  y = -3x

Each value of x maps to a single value of y, so this relation is a function.

_____

This equation is a first-degree polynomial in x. Any polynomial relation y=p(x) is a function, so this is a function.

Solve for x
ax+bx=10

Answers

Answer:

[tex]ax + bx = 10 \\ \\ x(a + b) = 10 \\ \\ x = \frac{10}{a + b} [/tex]

I hope I helped you^_^

Write a two-step equation and solve.

Four more than six times a number is 22

Five less than eleven times a number is 50

Seven less than nine times a number is -16

Answers

Step-by-step explanation:

1) let number=a

six times a number=6a

Condition:

6a+4=22

2) eleven times a number=11a

Condition:

11a-5=50

3) 9 times a number=9a

Condition:

9a-7=-16

Note:if you need to ask any question please let me know.

Need answers in 2 minutes ASAP

Answers

Step-by-step explanation:

f(10)=10

f(-2)=-2

f(a)=a

f(a+b)=a+b

g(10)=5×10-12=3

g(-2)=5×(-2)-12=-10-12=-22

g(a)=5×a-12=5a-12

g(a+b)=5×(a+b)-12=5a+5b-12

h(10)=(10)^2 +4(10)-7=100+40-7=133

h(-2)=(-2)^2 +4(-2)-7=4-8-7=-11

h(a)=a^2 +4a -7

h(a+b)=(a+b)^2 +4a+4b-7=a^2+2ab+b^2+4b-7

log base 4 (x+3)²- log base 4 y² = 0​

Answers

Answer:

x = - |y| - 3

Step-by-step explanation:

Select the correct answer.
Based on these segment lengths, which group of segments cannot form a triangle?
OA 12,7,8
OB. 8, 7, 13
OC. 1,2,3
OD. 80,140, 70
Reset
Next
2021 EdimentumAll rights

Answers

Answer:

C

Step-by-step explanation:

If you add up the length of two sides, the sum must be greater than the third side of the triangle.

If you add 1 and 2, it equals 3

But that means it will be equal to the length of the third side, 3

It will be impossible to make a triangle with those lengths of sides no matter how the sides or angles are set.

It's sort of difficult to explain this without any visual

You can look up "triangle inequality" to find out more about this

7. What's the perimeter of a rectangle with length 12 m and width 5 m?
A. 60 m
B. 49 m
C. 34 m
D. 17 m

Answers

Answer:

Option(c) 34m

Step-by-step explanation:

Perimeter of a rectangle = 2(length + breadth)

length = 12m

breadth/width = 5m

Perimeter = 2(12 + 5)

                = 2(17)

                = 34m

Answer:

34

you just add, 12+5+12+5 to get 34

Find the midpoint of the segment with the given endpoints. (-7,-4) and (3,7)?

Answers

9514 1404 393

Answer:

  (-2, 1.5)

Step-by-step explanation:

The coordinates of the midpoint are the average of the end point coordinates:

  ((-7, -4) +(3, 7))/2 = (-7+3, -4+7)/2 = (-4, 3)/2 = (-2, 1.5)

The coordinates of the midpoint are (-2, 1.5).

divide write your answer in simplest form 2/3 divided by 1/4

Answers

Answer:

8/3 or 2.6667

Step-by-step explanation:

when you divide fractions you use a technique called KCF

K = keep

C = change

F = flip

You write the equation [tex]\frac{2}{3}[/tex] ÷ [tex]\frac{1}{4}[/tex]

you keep [tex]\frac{2}{3}[/tex]

you change the symbol, so from ÷ you change it to x

and flip the last fraction, so you would have  [tex]\frac{4}{1}[/tex]

then you solve it

[tex]\frac{2}{3}[/tex] x  [tex]\frac{4}{1}[/tex] = [tex]\frac{8}{3}[/tex]

The result of 2/3 divided by 1/4 in simplest form is 8/3 .

Division: It is one of the four basic mathematical operation, the other three being addition, subtraction, multiplication.

Given, division of [tex]\frac{2}{3}[/tex] by [tex]\frac{1}{4}[/tex].

Division of fractional terms:

[tex]=\dfrac{\frac{a}{b}}{\frac{c}{d}}\\= (a)\times(d)/(b)\times(c)[/tex]

Apply, division process of fractional terms.

[tex]=\dfrac{\frac{2}{4}}{\frac{1}{3}}\\ = (2)\times(4)/(1)\times(3)[/tex]

[tex]= \frac{8}{3}[/tex]

Know more about division,

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After writing a $400 check to pay a bill, a student had a balance of $550 in his account. How much did he have in the account before he wrote the check?

a) Let x= his balance before writing the check. Write the equation you would use to solve this problem.

Answers

Answer:

x=950

Step-by-step explanation:

550+400=x

A triangle has a perimeter of 75 inches. Find the length of three sides
if one side is 15 inches larger than the smallest side, and the third
side is twice the smallest

Answers

9514 1404 393

Answer:

  15 in, 30 in, 30 in

Step-by-step explanation:

Let x represent the length of the smallest side. Then the other two sides are (x+15) and (2x). The perimeter is the sum of the side lengths:

  x +(x +15) +2x = 75

  4x = 60

  x = 15 . . . . . . . . . . . shortest side

  (x+15) = 30 . . . . . . second side

  (2x) = 30 . . . . . . . third side

The shortest side is 15 inches, the second side is 30 inches, and the third side is 30 inches.

Solve the below:
4x+3y=7 3x-2y=9

Answers

4x+3y=7
3x-2y=9

12x+9y=21
12x-8y=36
^^Multiply top equation by 3 and multiply bottom equation by 4

12x+9y=36
- 12x-8y=36

17y=-15
^^Then subtract those two new equations

17y/17= -15/17

Y= -0.88
^^Next divide both sides by 17

4x+3* -0.88=7

4x + (-2.64) =7
-(-2.64) -(-2.64)

4x = 9.64

4x/4=9.64/4
X=2.41

^^then choose on equation and put your new y in the y spot and solve.


X=2.41

Y=-0.88

Your point/coordinate is (2.41,-.88)
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