pls helpme with this thing
​

Answer:

How long will it take to hear the rumbling of a volcano located 58km away?

Step-by-step explanation:

Answer:

- 8x + 3

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= - 5x + 3 + (- 3x)

= - 5x + 3 - 3x ← collect like terms

= - 8x + 3

Answer:

a=2, b=-3

Step-by-step explanation:

f(x) = ax+b

f(3)=3, 3a+b=3

f(2)=1, 2a+b=1

Solving these two equations, we get a=2, b=-3

Answer:

Step-by-step explanation:

[tex]y^2+6y+8x+1=0\\\\y^2+2*3y+9+8x+1-9=0\\(y+3)^2+8x-8=0\\8x=-(y+3)^2+8\\\\x=-\dfrac{(y+3)^2}{8}+1 \\Vertex=(1,-3)[/tex]

The vertex is (1,-3).

To find the the vertex of the parabola.

A symmetrical open plane curve formed by the intersection of a cone with a plane parallel to its side.,

Given that:

[tex]y^{2} +6y+8x+1=0\\\\y^{2} +2*3y+8x+1+9-9=0\\\\(y+3)^{2}+8x-8=0\\\\8x=-(y+3)^{2}+8\\\\x=-\frac{(y+3)^{2}}{8} +1\\\\vertex=(1,-3)\\[/tex]

So, the vertex is (1,-3).

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Answer:

whats the choices?

Step-by-step explanation:

Answer:

Step-by-step explanation:

Between the fourth and tenth there are:

The total number is:

The scale is 2 cm to 12 in so the actual length of the shorter side is 12 in, and the actual side of the longer side is (8/2)×12=48 in. So, the actual area of the ramp is (1/2)×12×48=288 Sq. in.

Scale used to convert the dimensions from drawing to actual is,

2 cm : 12 in

Height of the ramp in a skateboard park = 2 cm

Therefore, actual height 'x' of the ramp will be,

[tex]\frac{2}{12}=\frac{2}{x}[/tex]

x = 12 inches

Since, measure of the base of the ramp = 8 cm

Length of the base 'y' of the actual ramp will be,

[tex]\frac{2}{12}=\frac{8}{y}[/tex]

y = [tex]\frac{8\times 12}{2}[/tex]

y = 48 inches

Area of a triangle = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]

                             = [tex]\frac{1}{2}(48)(2)[/tex]

                             = 48 square inches

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Answer:

-27

Step-by-step explanation:

-3 x -3=9

9 x -3= -27

Answer:

-27

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given that x = 3 and y = 2 we can figure these out

3x = 3x3 = 9

5y = 5 x 2 = 10

9+10=19

X times y - 1

3x2-1=5

X*+y* =

3x3+2x2 = 13

2x3*-2 =

2x3x3 - 2 = 16

-5x3+9

= -6

2x2-3+5+3*-3x2 =

9

Answer:

4 triangles

Step-by-step explanation:

the number of triangles in a polygon is (the number of sides in the polygon - 2)

The number of triangles inside a polygon with six sides are 4.

Given is that the number of sides in a polygon is 6.

Therefore, the number of triangles inside a polygon with six sides are 4.

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Answer:

4x _ 8 + 90 = 144

Step-by-step explanation:

you do parentheses then the rest you follow that order and it will all work ot really easy

Answer:

87

Step-by-step explanation:

Mean(or average) = 82

let 'x' be the last test marks

Sum of marks of tests/Number of tests = Mean

(78 + 83 + 80 + x)/4 = 82

241 + x = 82 × 4

241 + x = 328

x = 328 - 241

x = 87

Answer:

The choose D. 4¹⁵

I hope I helped you^_^

Answer:

550, 575, 596, 602

Answer:

Anything greater or equal to 550 will be rounded to 600

and anything less than 650 will be rounded to 600,  

So the numbers are:-  

550  

575  

596

602

Answer:

208

Step-by-step explanation:

The division result is: Quotient: [tex]3x^2 + 9x^2 - 107x^2[/tex], Remainder: -33 Here's the polynomial division step by step:    [tex]3x^2 + 1 | 9x^4 - 12x^3 + 103x^2 + 2[/tex]

Step 1: Divide the highest degree term of the dividend by the highest degree term of the divisor:

       [tex]3x^2 + 1 | 9x^4 - 12x^3 + 103x^2 + 2[/tex]

                [tex]9x^4 + 3x^2[/tex]

                    ---------------

                            [tex]-12x^3 + 103x^2[/tex]

Step 2: Multiply the divisor by the result from step 1 (3x^2 + 1) and subtract the result from the dividend:

     [tex]3x^2 + 1 | 9x^4 - 12x^3 + 103x^2 + 2\\[/tex]

                    [tex]9x^4 + 3x^2[/tex]

                    ---------------

                           [tex]-12x^3 + 103x^2[/tex]

                            [tex]-12x^3 - 4x^2[/tex]

                            ---------------

                                   [tex]107x^2 + 2[/tex]

Step 3: Divide the highest degree term of the new dividend (107x^2) by the highest degree term of the divisor (3x^2), and perform the division:

       [tex]3x^2 + 1 | 9x^4 - 12x^3 + 103x^2 + 2[/tex]

                    [tex]9x^4 + 3x^2[/tex]

                    ---------------

                            [tex]-12x^3 + 103x^2[/tex]

                            [tex]-12x^3 - 4x^2[/tex]

                            ---------------

                                     [tex]107x^2 + 2 \\ 107x^2 + 35[/tex]

                                     -------------

                                                -33

Since the result (-33) has a lower degree than the divisor (3x^2 + 1), we can't proceed with further division.

So, the division result is:

Quotient: [tex]3x^2 + 9x^2 - 107x^2[/tex]

Remainder: -33

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Correct Question is:

Divide [tex](9x^4 - 12x^3 + 103x^2 + 2)\ by \ (3x^2 + 1)[/tex]

Answer:

ANSWER IS BELOW

Step-by-step explanation:

f

(

x

)

=

−

1

2

x

2

+

3

x

−

1

2

Explanation:

A quadratic function can be written in vertex form as:

f

(

x

)

=

a

(

x

−

h

)

2

+

k

where

(

h

,

k

)

is the vertex and

a

is a constant multiplier.

In our example the vertex

(

h

,

k

)

is

(

3

,

4

)

, so we can write:

f

(

x

)

=

a

(

x

−

3

)

2

+

4

Given that this passes through the point

(

1

,

2

)

, we must have:

2

=

a

(

1

−

3

)

2

+

4

=

4

a

+

4

Subtract

4

from both ends to get:

−

2

=

4

a

Divide both sides by

4

and transpose to find:

a

=

−

1

2

So our quadratic function can be written in vertex form as:

f

(

x

)

=

−

1

2

(

x

−

3

)

2

+

4

We can multiply this out and simplify as follows:

f

(

x

)

=

−

1

2

(

x

−

3

)

2

+

4

f

(

x

)

=

−

1

2

(

x

2

−

6

x

+

9

)

+

4

f

(

x

)

=

−

1

2

x

2

+

3

x

−

9

2

+

4

f

(

x

)

=

−

1

2

x

2

+

3

x

−

1

2

Answer:

I would first tell people to evacuate

6t=9

Since the top tape diagram has 6 parts and labeled t (The same size as the bottom diagram), we multiply it, so: 6xt= 6t. 9 is the label of the bottom diagram. That means there are the same or equal to each other.

I hope I've helped!

Answer:

Step-by-step explanation:

APE - adding 8 on both sides (first line)

DPE - dividing by 7 on both sides (second line)

Answer:

I think this is if it is right then help me plz this is false ..

Answer:

8. ☐ A Up

☑ B Down 1

☑ C Left [tex]\displaystyle \frac{\pi}{2}[/tex]

☐ D Right

7. [tex]\displaystyle 3\pi[/tex]

6. ☑ A x = −2π

☐ B x = −π

☐ C x = [tex]\displaystyle \frac{\pi}{2}[/tex]

☑ D x = π

5. [tex]\displaystyle y = -1[/tex]

Explanation:

[tex]\displaystyle y = Atan(Bx - C) + D \\ \\ \boxed{y = tan\:(\frac{1}{3}x + \frac{\pi}{6}) - 1} \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{2}} \hookrightarrow \frac{-\frac{\pi}{6}}{\frac{1}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{3\pi} \hookrightarrow \frac{\pi}{\frac{1}{3}} \\ Amplitude \hookrightarrow N/A[/tex]

Here is all the information you will need. Now, what you need to know is that ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes. Second, to find the period in this case, you need to take a look at the distanse between each vertical asymptote. Now, accourding to this graph, on a universal scale of [tex]\displaystyle \frac{\pi}{4}[/tex] with a range of [tex]\displaystyle -2\pi\:to\:2\pi,[/tex] the vertical asymptotes are [tex]\displaystyle -2\pi = x\:and\:\pi = x.[/tex] From here, you will then find the distanse between these asymptotes by simply perfourming the operation of Deduction, and doing that will give you [tex]\displaystyle \boxed{3\pi} = \pi + 2\pi.[/tex] So, the period of this function is [tex]\displaystyle 3\pi.[/tex] Now, you will instantly get the jist of the horisontal shift by looking at the above formula. Just keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must pay cloce attention to what is given to you inside those parentheses. Finally, the midline is the centre of your graph, also known as the vertical shift, which in this case is at [tex]\displaystyle y = -1.[/tex]

Well, that just about wraps it up. Now that everything has been explained, you should understand it better. If you still have questions, do not hesitate to comment any you have.

I am delighted to assist you at any time.

Answer:

x — 4

Step-by-step explanation:

Difference means subtraction, so x — 4 is the expression for your question.

A major problem with interval lengths that are too small is that it masks the shape of the distribution.

The interval length used in a distribution may be described as the size of the class or the class width. The interval length is usually important when drawing histograms and other related graphs for a grouped distribution.

The most significant effect of using a class interval which is too small is that it masks the actual shape of distribution, Hence preventing it from being distinct.

For best practice, it is essential that the class interval is of moderate width, hence enabling us to have a distribution which isn't maksed nor exaggerated.

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Answer:

nice TV

Step-by-step explanation: