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1. Solve two and one third times four fifths.

1 four sixths
2 twenty eight fifteenths
3 twenty seven fifteenths
4 twenty eight sixths


2.Solve two and one third times two and three fourths.

1 four and three twelfths
2 six and five twelfths
3 seven and five twelfths
4 eight and three twelfths

[tex]\text{L.H.S}\\\\=\sin^2 \theta \tan \theta + \cos^2 \theta \cot \theta+2\sin \theta \cos \theta \\\\\\=\sin^2 \theta \cdot \dfrac{\sin \theta}{\cos \theta} + \cos^2 \theta \cdot \dfrac{\cos \theta}{\sin \theta} + 2\sin \theta \cos \theta\\\\\\=\dfrac{\sin^3 \theta}{\cos \theta}+ \dfrac{\cos^3 \theta}{\sin \theta}+ 2\sin \theta \cos \theta\\\\\\=\dfrac{\sin^4 \theta + \cos^4 \theta}{\cos \theta \cdot \sin \theta}+ 2\sin \theta \cos \theta\\\\[/tex]

[tex]=\dfrac{(\sin^2 \theta)^2 + (\cos^2 \theta)^2 }{\cos \theta \sin \theta}+ 2\sin \theta \cos \theta\\\\\\=\dfrac{(\sin^2 \theta + \cos^2 \theta)^2-2\sin^2 \theta \cos^2 \theta}{\cos \theta \sin \theta}+ 2\sin \theta \cos \theta\\\\\\=\dfrac{1-2 \sin^2 \theta \cos^2 \theta}{\cos \theta \sin \theta}+ 2\ sin \theta \cos \theta\\\\\\=\dfrac{1-2\sin^2 \theta \cos^2 \theta+2\sin^2 \theta \cos^2 \theta}{\cos \theta \sin \theta}\\\\=\dfrac 1{\cos \theta \sin \theta}\\\\[/tex]

[tex]=\dfrac{\sin^2 \theta + \cos^2 \theta}{\sin \theta \cos \theta}\\\\\\=\dfrac{\sin^2 \theta}{\cos \theta \sin \theta}+\dfrac{\cos^2 \theta}{\cos \theta \sin \theta}\\\\\\=\dfrac{\sin \theta}{\cos \theta}+\dfrac{\cos \theta}{\sin \theta}\\\\\\=\tan \theta + \cot \theta\\\\=\text{R.H.S}\\\\\text{Proved.}[/tex]

Let's solve for solutions i e zeros

Answer:

(x, −x2 − 10x − 21), where −8 ≤ x ≤ −2

Step-by-step explanation:

because x is greater then it.

7, 7, 9, 27, 27, are the numbers that we can fill these boxes starting from left.

A prime number is not a composite number, prime numbers are only divisible by the number itself and one.

An example of a prime number is 2 which is only divisible by 2 and 1 it is also the only even prime number.

The only prime number is 7.

The intersection of prime and odd numbers is 7.

The only odd number is 9.

The intersection of odd and cube numbers is 27.

The only cube number is 27.

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All polynomials are continuous, so the limit can be evaluated by direct substitution:

[tex]\displaystyle \lim_{x\to-3} (x^3+3x^2+4x-12) = (-3)^3+3(-3)^2+4(-3)-12 = \boxed{-24}[/tex]

The Limit of (x cubed + 3 x squared + 4 x minus 12) as x approaches negative 3 is -24.

Polynomials are those algebraic expressions that consist of variables, coefficients, and constants. The standard form of polynomials has mathematical operations such as addition, subtraction, and multiplication.

All polynomials are continuous, so the limit can be evaluated by direct substitution:

[tex]\lim_{x \to {-3}} x^3 + 3 x ^2+ 4 x - 12\\\\= (-3)^3 + 3 (-3)^2+ 4 (-3)- 12\\\\= -24[/tex]

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Answer:

I'm going to need a picture of more explanation

yes it is uses in1979 there ie big tsunami

Answer:

the American Embassy in Tehran was overrun and its employees taken captive.

Step-by-step explanation:

The lower quartile is 43.

Answer:

Pretty sure it's "only i"

Step-by-step explanation:

A constant rate of change means that something changes by the same amount during equal intervals.

$30 is the same amount whereas 10% could vary.

Hope this helps.

Answer:

It's not clear can you show clearly

Answer: c

Step-by-step explanation:

Answer:

the second option is correct, the one that you picked

Step-by-step explanation:

Answer:

x= 26°

Step-by-step explanation:

it's a 90 degree angle as a whole so just subtract 64° from 90° to get the other angle.

Answer:

x=26

A line is 180 degrees

the square at the bottom left means 90 degrees

90+64=154

180-154=26 degrees

The measure of PQ if the triangle LMN is similar to triangle OPQ is 69.4

Similar triangles are triangles that have equal sides and angles. The ratio of the similar sides is a constant.

According to the triangle given:

PQ/17 = OQ/LM
PQ/17 = 49/12
12PQ = 833
PQ = 69.4

Hence the measure of PQ if the triangle LMN is similar to triangle OPQ is 69.4

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Answer: 36

Step-by-step explanation: Ratio 27:36 is also 3:4

Answer:

36 games

Step-by-step explanation:

since the ratio is 3:4 we must get what the original is.

27/3=9

27+9=36

27:36

Answer: B

Step-by-step explanation:

x -9 will get you 27 (36 is the answer), but you can try every answer and see which one makes sense, as B is the only one that makes sense (D would have been the answer if it was the absolute value which is B)

Answer

In the box, put "12" shots attempted.

Step-by-step explanation:

I learned this already and I am 100%it is correct. btw i love basketball.

Answer:

✏The correct option is B Rs 73,333

Per capita income is the sum of all income sources, divided by the total number of people. Here the gross income of the family is = Rs (1,80,000+ 40,000) = Rs 2,20,000, the pocket money won't be added as it is an expense for the family. Then the per capita income of the family= Gross income / 3 (as the family has three members) = Rs 73,333.

Step-by-step explanation:

Percent is a relative quantity. Earning of our family is more than our friend's family (on monthly basis), by  11.11% approximately. (compared to friend's family's monthly income)

Percent is a relative quantity, as it is the measure of one quantity per 100 units of other quantity.

We want to know how much percent of 'b' is 'a'.

Then, it is calculated as:

[tex]\dfrac{a}{b} \times 100[/tex]

(in percentage)

For this case, we're specified that:

For our family:

Total monthly income = ₹(40000 + 35000 + 25000) = ₹100,000

For friend's family:

Total monthly income = ₹(45000 + 30000 + 15000) = ₹90,000

Thus, we see that friend's family's monthly is monthly ₹10,000 less than our family's monthly income.

We need to find how much percent this ₹10,000 is of their family because we need to find by how much percent our family's income is more than the friend's family's monthly income (so comparison is with respect to the monthly income of friend's family).

Let P be the percent the ₹10,000 is of the amount ₹90,000

Then, we get:

[tex]P = \dfrac{10000}{90000} \times 100 = \dfrac{100}{9} \approx 11.11 \%[/tex]

Thus, earning of our family is more than our friend's family (on monthly basis), by  11.11% approximately. (compared to friend's family's monthly income)

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Heyo!

SaddySokka is here to help!!

Let's do this step-by-step explanation!

[tex]=\frac{5^-^6}{5^3}[/tex]

[tex]=5^-^6^-^3[/tex]

[tex]=5^-^9[/tex]

[tex]=\frac{1}{5^9}[/tex]

Answer:

A. [tex]\frac{1}{5^9}[/tex]

Hopefully, this helps you!!

Have a great day!!

SaddySokka~

The transformation that is implemented is clockwise rotation by 270° about the origin and dilation by a scale factor of 1/2 .

The process of transformation an existing graph or equation into a new graph is known as graph transformation . The alteration of algebraic equations is a typical form of algebraic challenge.

A transformation modifies the graph of a parent function. Dilations, reflections, and translations are the three distinct types of transformation . The y-values of a function can be changed vertically, or the x-values can be changed horizontally (affects the x-values).

In the given figure we can see that the length of the side BC of the figure is 4 units, where as the length of the corresponding side in the image is

2 units . Hence the image is dilated buy a scale factor of 1/2 .

And from the transformation  figure it is clear that the image has rotated either 270° clockwise or 90 ° counterclockwise.

Hence the second option on transformation is correct.

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Answer:

D). A dilation by scale factor of 1.2, centered at the origin, followed by a 270 clockwise rotation about the origin

Step-by-step explanation:

Answer:

D is correct.

Step-by-step explanation:

Hoped this helped!

Hoped this helped!Hoped this helped!Hoped this helped!Hoped this helped!Hoped this helped!Hoped this helped!Hoped this helped!

Answer:

3.2

Step-by-step explanation:

Distance forumla

[tex]y = \sqrt{(x1 - x2)^2 + (y1-y2)^2}[/tex]

[tex]y = \sqrt{(2 - (-1))^2 +(0-1)^2} \\ y = \sqrt{10} \\y = 3.2[/tex]

The center of the circle (x + 9)² + (y − 6)² = 10² is at (-9, 6) and the radius of the circle is 10 units.

It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

The equation of the circle is given as

(x + 9)² + (y − 6)² = 10²

Then the center of the circle is at (-9, 6) and the radius of the circle is 10 units.

More about the circle link is given below.

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Answer:

A. (-9, 6)

Step-by-step explanation:

i did it B)

To find values of the table, plug in the given corresponding values of x or y, and constant rate of change (m) = -3/4 into y = mx.

Constant rate of change of any table or function is a comparison of how two variables are changing, which can be determined using the formula, m = change in y/change in x = [tex]\frac{y_2 - y_1}{x_2 - x_1}[/tex].

Where x and y are the coordinates of a table or functions, and m is the constant rate of change, the equation that models the relationship would be, y = mx.

The image of the table is missing, however, to complete the given table, plug in any of the given values of x or y, and constant rate of change (m) = -3/4 into y = mx.

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Answer:

Step-by-step explanation:

It is assumed GE and DA are parallel

EFH and FCA are same side interior angles and therefore supplementary

On the other hand, ∠HBA is exterior angle of triangle CHB, so it is

Now, find the value of m∠EFH

<C

Now

<C+<EFH=180

<EFH

Answer:

260

Step-by-step explanation:

18.2 hours / sign every 0.07 hours = 260 signs passed

The product of the given expression is -3ed + 3e^2 showing that they contain two terms and the product has a degree of 2.

Equations are expressions separated by an equal sign.

Given the following expression

(–d + e)(4e + d).

We are to take the product of both expressions.

Expand to have:

(–d + e)(4e + d) = -4ed - d^2 + 4e^2 + de

(–d + e)(4e + d) = -3ed + 3e^2

Hence, there are two terms in the solution and the product is degree 2.

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Answer:

B and E

Step-by-step explanation:

Answer:

hey i am doing god how are you and i dont know what i am doing for easter. My favorite holiday is christmas and easter. My favorite subjects in school are math and reading. I love school.

Step-by-step explanation: