Answer:
D
Explanation:
because replusive force is much more
Which statement accurately describes valence electrons?
O They are electrons in the outermost shell and involved in bonding.
O They are electrons in the second energy level and involved in bonding.
O They are electrons in the smallest shell and involved in bonding.
O They are electrons in the first energy level and involved in bonding.
Help ASAP please :(
the smallest whole number ratio of elects in a compound
Answer: The smallest whole-number ratio of the atoms in a compound represents the molar ratio of the elements in which they are combined. For example, Water is a compound. The chemical formula of water is H2O H 2 O . In water, H and O elements are combined in the molar ratio of 2:1.Explanation:
Answer:
[tex]emperical \: formula[/tex]
It took 4.5 pints of chlorine to purify the water in the holding tank. How many liters of chlorine were needed?
2.215 liters
2.115 liters
1.215 liters
1.115 liters
Answer:2.115 L
Explanation:
4.5 x .47 = 2.115 L
4.5 pints are approximately equal to 2.129292 liters. The answer closes to the result is 2.215 liters.
Explanation:This question is concerned with conversion between pints and liters. 1 pint is equal to approximately 0.473176 liters. Therefore, to find out how many liters that 4.5 pints is equal to, we multiply 4.5 by 0.473176.
The calculation is as follows: 4.5 pints * 0.473176 liters/pint = 2.129292 liters
Considering the options that was given, the closest answer is 2.215 liters.
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Find the percentage composition of each compound listed
below. In the first ten problems, the correct formula is given.
In the next four problems, laboratory data for the compound
are presented.
1. FeO
2. MgCl
3. CH4
4. CS₂
5. NO₂
6. HgO
7. SnI₁
8. Cu₂0
9. NH₂
10.CH₂O
Answer:
Explanation:
% comp is g element / g cpd x 100% get the grams from the periodic table
1) 77.78%Fe & 22.22 % O
2) 40.68 % Mg & 59.32 % Cl
3) 75 % C & 25% H
4) 15.79% C & 84.21 % S
5) 30.43 % N & 69.57 % 0
6) 92.63%Hg & 7.37 % )
7) 18.98 % Sn & 81.02 %I
8) 88.89 % Cu & 11.11 % O
9) 82.35 & N & 17.65 % H
10) 40% C & 6.67% H & 53.33 % O
Mention the most suitable separation technique that may be used to separate the components and explain briefly how separation is achieved under the separation technique. A mixture of sand, table salt and iron fillings
The most suitable separation technique for this mixture is a combination of magnetic separation and filtration.
How is the mixture separated?First, a magnet can be used to separate the iron fillings from the sand and salt mixture. This is because iron is magnetic and will be attracted to the magnet, leaving the sand and salt behind.
Next, the sand and salt mixture can be dissolved in water. Since salt is soluble in water but sand is not, the salt will dissolve while the sand remains behind. The mixture can then be filtered to separate the sand from the saltwater solution.
Finally, the saltwater solution can be heated to evaporate the water and obtain the salt as a solid residue.
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Which statement describes gases
according to kinetic molecular theory?
According to the kinetic molecular theory, gases are described by the following statement:
Gases consist of small particles (atoms or molecules) that are in constant random motion.What does the statement meanThis statement highlights that gases are made up of particles that are in constant motion, moving in straight lines until they collide with another particle or the walls of the container.
The motion of gas particles is random, and their energy increases as the temperature of the gas increases. The kinetic molecular theory also suggests that the particles in a gas are far apart from each other and do not attract or repel each other, except during collisions.
Additionally, the kinetic molecular theory states that the pressure of a gas is caused by the collisions of gas particles with the walls of the container. The higher the concentration of gas particles or the faster they are moving, the greater the pressure of the gas.
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Oxalic acid dihydrate (H2C2O4 • 2H2O, molecular weight = 126.07 g/mol), a diprotic acid, can also be used to standardize NaOH solution. If 0.284 g of H2C2O4 • 2H2O is dissolved in water and titrated to the equivalence point with 16.37 mL of NaOH, what is the molarity of the NaOH solution?
Answer:
0.275M
Explanation:
First, we need to determine the number of moles of oxalic acid dihydrate used in the titration:
moles of H2C2O4 • 2H2O = (0.284 g) / (126.07 g/mol) = 0.00225 mol
Since oxalic acid dihydrate is diprotic, it can react with two moles of NaOH per mole of H2C2O4 • 2H2O. Therefore, to determine the molarity of the NaOH solution, we need to divide the number of moles of NaOH used in the titration by the volume of NaOH solution used:
moles of NaOH = (0.00225 mol H2C2O4 • 2H2O) x (2 mol NaOH / 1 mol H2C2O4 • 2H2O) = 0.0045 mol
molarity of NaOH = (0.0045 mol) / (0.01637 L) = 0.275 M
Therefore, the molarity of the NaOH solution is 0.275 M.
I need help someone please help me
Answer:
i cannot see the picture
Explanation:
how many grams of Fe are produced from 92.5g of FeO given the following reaction
The mass(in grams) of iron, Fe produced from the 92.5g of iron (ii) oxide, FeO is 71.9 grams
How do i determine the mass of Fe produced?The mass of Fe produced from the 92.5g of iron (ii) oxide, FeO can be obtained as follow:
2FeO → 2Fe + O₂
Molar mass of FeO = 71.85 g/molMass of NH₃ from the balanced equation = 2 × 71.85 = 143.7 g Molar mass of Fe = 55.85 g/molMass of Fe from the balanced equation = 2 × 55.85 = 111.7 gFrom the balanced equation above,
143.7 g of FeO reacted to produce 111.7 g of Fe
Therefore,
92.5 g of Fe will react to produce = (92.5 × 111.7) / 143.7 = 71.9 g of Fe
Thus, the mass of Fe produced from the reaction is 71.9 grams
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Complete question:
How many grams of Fe are produced from 92.5 g of FeO given the following reaction 2FeO → 2Fe + O₂
Zinc reacts with hydrochloric acid according to the reaction equation
Zn(s) + 2 HCl(aq) → ZnCl₂(aq) + H₂(g)
How many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?
volume: ___ mL
Answer:
many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?
volume: 16 mL
First, we need to calculate the number of moles of Zn:
m(Zn) = 5.05 g
M(Zn) = 65.38 g/mol (molar mass of Zn)
n(Zn) = m(Zn) / M(Zn) = 5.05 g / 65.38 g/mol = 0.0773 mol
According to the balanced chemical equation, 1 mole of Zn reacts with 2 moles of HCl. Therefore, the number of moles of HCl needed is:
n(HCl) = 2 × n(Zn) = 2 × 0.0773 mol = 0.1546 mol
Now we can use the molarity of the HCl solution to calculate the volume needed:
M(HCl) = 1.50 mol/L
n(HCl) = V(HCl) × M(HCl)
V(HCl) = n(HCl) / M(HCl) = 0.1546 mol / 1.50 mol/L = 0.103 L = 103 mL
Therefore, we need 103 mL of 1.50 M HCl(aq) to react with 5.05 g Zn(s).
need quick will give 40 points
Answer:
3 moles H2 x (molecules / 1 mol H2)
Explanation:
3 moles H2 x (molecules / 1 mol H2)
What is the pH of a bleach solution that has a [OH−]=1.9×10^-5 M?
Which term is defined as the ability to dissolve within a given solvent?
O solution
O solubility
O dissociating
O dissolving
20pts
Answer:
Solubility.
Explanation:
Solubility is the maximum concentration of a solute that can dissolve in a solvent at a given temperature. At the maximum concentration of solute, the solution is said to be saturated. The units of solubility can be provided in mol/L or g/L.
Need help with these calculations attached
A. The hydronium ion concentration, [H₃O⁺] of the solution is 4.57×10⁻⁸ M
B. The hydroxide ion concentration, [OH⁻] of the solution is 1.28×10⁻⁶ M
C. The hydroxide ion concentration, [OH⁻] of the solution is 1.80×10⁻¹¹ M
A. How do i determine the [H₃O⁺] of the solution?We can determine the [H₃O⁺] of the solution as shown below:
Concentration of hydroxide ion, [OH⁻] = 2.19×10⁻⁷MConcentration of hydronium, ion [H₃O⁺] = ?[H₃O⁺] × [OH⁻] = 10¯¹⁴
[H₃O⁺] × 2.19×10⁻⁷ = 10¯¹⁴
Divide both side by 2.19×10⁻⁷
[H₃O⁺] = 10¯¹⁴ / 2.19×10⁻⁷
[H₃O⁺] = 4.57×10⁻⁸ M
B. How do I determine of [OH⁻] of the solution?We can determine the [OH⁻] of the solution as shown below:
Concentration of hydronium, ion [H₃O⁺] = 7.81×10⁻⁹ MConcentration of hydroxide ion, [OH⁻] =?[H₃O⁺] × [OH⁻] = 10¯¹⁴
7.81×10⁻⁹ × [OH⁻] = 10¯¹⁴
Divide both side by 7.81×10⁻⁹
[OH⁻] = 10¯¹⁴ / 7.81×10⁻⁹
[OH⁻] = 1.28×10⁻⁶ M
C. How do I determine of [OH⁻] of the solution?We can determine the [OH⁻] of the solution as shown below:
Concentration of hydronium, ion [H₃O⁺] = 5.57×10⁻⁴ MConcentration of hydroxide ion, [OH⁻] =?[H₃O⁺] × [OH⁻] = 10¯¹⁴
5.57×10⁻⁴ × [OH⁻] = 10¯¹⁴
Divide both side by 5.57×10⁻⁴
[OH⁻] = 10¯¹⁴ / 5.57×10⁻⁴
[OH⁻] = 1.80×10⁻¹¹ M
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