Is this circuit parallel or inseries ​

The door's moment of inertia for rotation about a vertical axis inside the door, 14 cm from one edge is 4.205 kgm².

The door's moment of inertia for rotation about a vertical axis inside the door, 14 cm from one edge is calculated as follows;

[tex]I = I_{cm} + Md^2[/tex]

where;

[tex]d = \frac{L}{2} - 0.14\\\\d = \frac{0.91}{2} - 0.14\\\\d = 0.315 \ m[/tex]

[tex]I = \frac{1}{12} ML^2 + Md^2\\\\I = \frac{1}{12} (25)(0.91)^2 \ + \ (25)(0.315)^2\\\\I = 1.725 \ + \ 2.48\\\\I = 4.205 \ kgm^2[/tex]

Thus, the door's moment of inertia for rotation about a vertical axis inside the door, 14 cm from one edge is 4.205 kgm².

The complete question is below;

A 25kg solid door is 220 cm tall, 91 cm wide. What is the door's moment of inertia for rotation about a vertical axis inside the degr,  14 cm from one edge.

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Answer:

A person is doing push-ups against a wall (action force), and the wall exerts an equal and opposite force against the person (reaction force).

Explanation:

Answer: A

Explanation:

An open circuit is a circuit that has no current flowing through it. The reason no current can flow through is due to a significant disconnect between two points in the circuit. For example, a large portion of the wire is cut out.

I haven't done any circuit analysis yet, but current can still flow through a circuit even if there is a cut. But that cut has to be extremely small.

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

Answer:

(It was a remove waste from cells)

Explanation:

the cell produces carbon dioxide and water, which are released as waste.

R² = F1² + F2² + 2 F1.F2 cos α ⇒cosinus

F1 and F2 perpendicular, α = 90°, cos 90° = 0

[tex]\tt R=\sqrt{3^3+4^2}=5[/tex]

Answer:

See below

Explanation:

Wavelength is distance between  consecutive wave crests or consecutive  troughs

 in this situation when one boat is at crest the other is in the trough...

    the wavelength will be twice this distance between the boats

           WL = 2 * 18 = 36 meters

amplitude is (distance from bottom to top) divided by two

    ampl = 2.6/2 = 1.3 m    (this is the same as the distance from the midline of the wave to the top of the wave)

5 cycles in 10 seconds  ...the frequency is in Hz ...which is cycles per second ,  so the frequency = 5 cycles/ 10 seconds = .5 Hz

 Period is = 1/f = 1/.5 Hz = 2 seconds per cycle

Answer:

.

Explanation:

Explanation:

v = s/t

20 = s/5

100 = s

s = 100 = 1 × 10².

When a cyclist bikes with an average velocity of 20 m/s for 5 seconds, the magnitude of the cyclist displacement would be 1×10² meters.

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. The unit of velocity is meter/second. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The generally considered unit for velocity is a meter per second.

The mathematical expression for velocity is given by the formula

velocity= total displacement/Total time

The area under the velocity-time graph represents the total displacement covered by the object while the slope of the velocity time graph represents the acceleration of the object.

For the given problem when a cyclist bikes with an average velocity of 20 m/s for 5 seconds,

Displacement =velocity×time

                       =20×5

                       =1×10²

The magnitude of the cyclist's displacement is 1×10²

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Answer:

The most logical explanation is A.

Explanation:

because we are explaining why the incandescent bulb uses less energy we can eliminate answers B and D then, because we are talking about energy efficiency which has nothing to do with connecting to another circuit we can go with, A because Ultraviolet light generated by fluorescent light bulbs is nothing compared to the heat of an incandescent light bulb because it was engineered to be so.

Answer:

Brakes unevenly adjusted: Brakes pulling in one direction or the other can lead to a skid. Tires with worn tread: Tread is necessary for traction in wet weather

Explanation:

Answer: exhaust pipe

Explanation: It doesn't really control anything so I'm assuming this is the answer

Answer:

17.15 N

Explanation:

Remember   F = m a

                       = 7 kg * 2.45 m/s^2 = 17.15 N

[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} ⟿}[/tex]

(i) 0.4 Ω m^-1

(ii) 0.8 Ω

(iii) 0.5 Ω

Explanation:

Resistance of 5 m length of wire :-

[tex] = > R = \frac{V}{I} = \frac{2}{1} = 2 \: Ω [/tex]

Resistance per unit length of the wire :-

[tex] = > \frac{R}{l} = \frac{2}{5} = 0.4 \: Ω \: {m}^{ - 1} [/tex]

(ii) Resistance of 2m length of the wire~

[tex] = \: 0.4 \: Ω \: {m}^{ - 1} \times 2 \: m = 0.8 \: Ω [/tex]

(iii) When the wire is doubled on itself, its area of cross section becomes twice and the length becomes half. Let a be the initial cross section and ρ be the specific resistance of the material of wire. Then,

[tex]from \ relation \: \: ➪ \: R = ρ \times \frac{1}{a}. \\ \\ we \: have, \\ \\ initial \: resistance \:➪ \: 2 = ρ\times \frac{5}{a}....eqn(i) \\ \\ new \: resistance \: ➪ \: R` = ρ\times \frac{2.5}{2a}....eqn(ii) \\ \\ on \: dividing \: eqn(ii) \: by \: eqn(i)... \\ \\ \frac{R`}{2} = \frac{2.5ρ}{2a} \div \frac{5ρ}{a} = \frac{1}{4} \\ \\ R` = \frac{2}{4} = 0.5 \: Ω[/tex]

Thus, on doubling the wire on itself, its resistance becomes one-fourth.

Answer:

Going with the current. You every watch Finding Nemo and the turtle guy says " Going with the waves bro"

Explanation:

Answer:

Young sea turtles make a concerted effort to swim in particular directions, instead of drifting with ocean currents.

A. Going with the current.

the frequency of the wave is 3
36/12= 3

For an electron is in the ground state of an infinite square well, the wavelength of electromagnetic radiation and the width of the square well  is mathematically given as

Generally, the equation for the  wavelength is mathematically given as

[tex]\lambda=\frac{hc}{24e}[/tex]

Therefore

\lambda=1240/12.24ev

\lambda=67.96nm

In conclusion, the width of the square well

[tex]a^2=\frac{\pi^2*h^2}{2me}[/tex]

Therefore

[tex]a^2=\frac{9.85*1.10*10^-68}{18.2*10^31*1,21*10^{19}}[/tex]

a^2=0.492*10^18

a=0.7nm

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Answer:

λ=898.5nm

Explanation:

a)

ΔE=hc/λ

ΔE=[tex]E_{2} -E_{1}\\[/tex]

[tex]E_{2} =E_{1} *(n^{2} )[/tex]

Where n equals the new energy level (in this case 2)

so ΔE=(0.46)*4-0.46 = 1.38eV

λ=hc/ΔE

λ=1240nm eV/1.38eV

λ=898.5nm

Answer:

Quarks

Quarks are among the smallest particles in the universe, and they carry only fractional electric charges. Scientists have a good idea of how quarks make up hadrons, but the properties of individual quarks have been difficult to tease out because they can't be observed outside of their respective hadrons.

Answer:

Quarks

Quarks are among the smallest particles in the universe, and they carry only fractional electric charges. Scientists have a good idea of how quarks make up hadrons, but the properties of individual quarks have been difficult to tease out because they can't be observed outside of their respective hadrons.

Answer:

True

Explanation:

The eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.

The electric potential at a point is the work done in moving a test charge from infinity to a certain point.

V(net) = V1 + V2 + V3

[tex]V = - \frac{kq}{r} \\\\V(net) = V_1 + V_2 + V_3\\\\V_{(net)} = -\frac{9\times 10^9 \times 200\times 10^{-6}}{0.2} + \frac{9\times 10^9 \times 300\times 10^{-6}}{0.3}+ \frac{9\times 10^9 \times 400\times 10^{-6}}{0.4}\\\\V_{(net)} = -9\times 10^6 \ + \ 9\times 10^6 \ + \ 9\times 10^6 \\\\V_{(net)} = 9\times 10^6 \ V[/tex]

Thus, the eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.

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Answer:

6.1 x 10^-8 newtons

Explanation:

F = 8.98 *109 *1*1/3845000002

Answer:

The principle of simple machine states that "if there is no friction in a simple machine, work output and work input are found equal in that machine.

Explanation:

Answer:

Usually, the term refers to the six classical simple machines which were defined by Renaissance scientists:

Also, a simple machine uses a single applied force to do work against a single load force.

Answer:

About 7.67 m/s.

Explanation:

Mechanical energy is always conserved. Hence:

[tex]\displaystyle \begin{aligned} E_i & = E_f \\ \\ U_i + K_i &= U_f + K_f\end{aligned}[/tex]

Where U is potential energy and K is kinetic energy.

Let the bottom of the slide be where potential energy equals zero. As a result, the final potential energy is zero. Additionally, because the child starts from rest, the initial kinetic energy is zero. Thus:

[tex]\displaystyle U_i = K_f[/tex]

Substitute and solve for final velocity:
[tex]\displaystyle \begin{aligned} mgh_i &= \frac{1}{2}mv_f^2 \\ \\ 2gh_i &= v^2_f \\ \\ v_f &= \sqrt{2gh_i} \\ \\ & =\sqrt{2(9.8\text{ m/s$^2$})(3.00\text{ m})} \\ \\ & \approx 7.67\text{ m/s} \end{aligned}[/tex]

In conclusion, the child's speed at the bottom of the slide is about 7.67 m/s.

The effective resistance of the car radio drawing in the given amount of current is 42.86Ω.

Ohm's law states that "the voltage between two points is directly proportional to the current flowing through the resistance.

It is expressed as;

V = IR

Where V is voltage, I is current and R is resistance.

Given the data in the question;

To determine the effective resistance of the car radio, we substitute our given values into the expression above.

V = IR

12V = 0.28A × R

R = 12V ÷ 0.28A

R = 42.86Ω

Therefore, the effective resistance of the car radio drawing in the given amount of current is 42.86Ω.

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Answer:

4 km/min^2

Explanation:

acceleration is the rate of change of speed per time

25 -5 = 20 km/min speed change

20 km/min  / 5 min = 4 km /min^2

The moment of forces in a valve equals force multiplied by the perpendicular distance to the pivot.

This can be defined as an action which changes the motion of an object. A valve is fixed to a pivot and opens and closes thereby controlling flow of fluid.

The moment of forces in a valve is the force multiplied by the perpendicular distance to the pivot.

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Answer:

2 and a half cows

Explanation:

There are 14 cows and the farmer consumes 10.

His child then slaughters and consumes one and a half cows.

The farmers wife then takes one to the market.

At todays prices, a singular cow is around £1,577, so to answer your question, the family made £1,577 from the one cow the wife sold.

The answer to your question is: C                                    

Question

4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid

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Answer:

Explanation:4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid