Answer:
10c
Step-by-step explanation:
When we have similar terms we can add or subtract them together.
Combine terms is like grouping similar terms together.
Accordingly, let us solve the given question.
5c + 5c
Combine the like terms to simplify the answer.
10c
a candy distributor needs to mix a 10% fat-content chocolate with a 50% fat-content chocolate to create 100 kilograms of a 14% fat-content chocolate. how many kilograms of each kind of chocolate must they use?
The candy distributor needs to use 30 kilograms of 10% fat-content chocolate and 70 kilograms of 50% fat-content chocolate to create 100 kilograms of a 14% fat-content chocolate.
To solve this problem, we can use the method of mixture problems, which involves setting up a system of equations. Let x be the number of kilograms of the 10% fat-content chocolate and y be the number of kilograms of the 50% fat-content chocolate.
We have two equations based on the fat content and the total weight of the mixture:
0.1x + 0.5y = 0.14(100) (equation for fat content)
x + y = 100 (equation for total weight)
We can solve this system of equations using substitution or elimination. Using substitution, we can solve for x in terms of y from the second equation and substitute it into the first equation:
x = 100 - y
0.1(100 - y) + 0.5y = 0.14(100)
10 - 0.1y + 0.5y = 14
0.4y = 4
y = 10
Then we can substitute y = 10 back into the equation for x and get:
x = 100 - y = 100 - 10 = 90
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you have 40 scarves and 55 hats to make identical donation bags. you make the greatest amount of donation bags with no clothing left over. how many scarves and hats are in each donation bag?
To create identical donation bags, you will need 55 hats and 40 scarves. You produce the most donation bags without any extra apparel. Each donation package contains 11 hats and 8 scarves.
To make the greatest amount of donation bags with no clothing left over, we need to find the greatest common factor (GCF) of 40 and 55. We can do this by finding the prime factors of both numbers:
[tex]40 = 2 * 2 * 2 * 5[/tex]
55 = 5 x 11
The GCF is the product of the common prime factors, which is 5. This means we can make 5 identical donation bags.
To find out how many scarves and hats are in each donation bag, we can divide the total number of scarves and hats by the number of donation bags:
Number of scarves per bag = 40 / 5 = 8 scarves
Number of hats per bag = 55 / 5 = 11 hats
Therefore, each donation bag will contain 8 scarves and 11 hats.
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(Using trig to find an angle)
Solve for x. Round to the nearest tenth of a degree, if necessary.
Angle B is approximately 53.15 degrees using trigonometry.
EquationsWe can use trigonometry to solve for angle B in the right triangle BCD. We know that angle CBC is 37 degrees, and BD is 64.
First, we can use the Pythagorean theorem to find the length of BC, which is the hypotenuse of the right triangle:
[tex]BC^{2}[/tex] = [tex]BD^{2}+CD^{2}[/tex]
[tex]BC^{2}[/tex] = 64² + [tex]CD^{2}[/tex]
Since CD is opposite angle B, we can use trigonometry to relate CD to angle B. Specifically, we can use the tangent function:
tan(B) = CD/BD
Rearranging, we have:
CD = BDxtan(B)
Taking the square root of both sides, we have:
BC = 64[tex]\sqrt{(1+tan^{2}B)}[/tex]
Now we can use the fact that BC is the hypotenuse of the right triangle to relate it to angle CBC, which is 37 degrees. Specifically, we can use the sine function:
sin(CBC) = BD/BC
Substituting our expression for BC, we have:
sin(37) = 64/64√(1 + tan²(B))
Simplifying, we get:
sin(37) = 1/[tex]\sqrt{(1+tan^{2}B)}[/tex]
Squaring both sides, we have:
sin²(37) = 1/[tex](1+tan^{2}B)}[/tex]
Substituting the identity cos²(θ) + sin²(θ) = 1, we have:
cos²(37) = cos²(B)
Taking the square root of both sides, we have:
cos(37) = ±cos(B)
Since angle B is acute (it is less than 90 degrees because it is in a right triangle), we know that cos(B) is positive. Therefore, we can take the positive square root:
cos(B) = cos(37)
B = 53.15 degrees (rounded to two decimal places)
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Identify the slope and y-intercept of the following equations:
a. y = 4x + 1
b. y = x - 2
c. y = 1/3x
It'd be so helpful if even one of these were answered. Thank you!
Therefore, the slope is 1/3 and the y-intercept is 0.
a. The equation is in slope-intercept form, y = mx + b, where m is the slope and b are the y-intercept. In this case, the slope is 4, and the y-intercept is 1. Therefore, the slope is 4 and the y-intercept is 1.
b. This equation is also in slope-intercept form, y = mx + b, where m is the slope and b are the y-intercept. In this case, the slope is 1, and the y-intercept is -2. Therefore, the slope is 1 and the y-intercept is -2.
c. This equation is already in slope-intercept form, y = mx + b, where m is the slope and b are the y-intercept. In this case, the slope is 1/3, and the y-intercept is 0 (since there is no constant term). Therefore, the slope is 1/3 and the y-intercept is 0.
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URGENT PLEASE HELP ME !!!!!!
What are the coordinates of the point on the directed line segment from (-10,10) to (2,-8) that partitions the segment into a ratio of 2 to 1?
The coordinate of the segment in the ratio is (-2,-2).
What is ratio?
When two numbers are compared, the ratio between them shows how often the first number contains the second. As an illustration, the ratio of oranges to lemons in a dish of fruit is 8:6 if there are 8 oranges and 6 lemons present.
Partitions the line segment in the ratio A to B... then,
=> x-coordinate is : x1 +[tex]\frac{ A(x2-x1)}{(A+B)}[/tex]
=> y-coordinate is: y1 + [tex]\frac{A(y2-y1)}{(A+B)}[/tex]
Here A = 2 , B = 1 and [tex](x_1,y_1)=(-10,10)[/tex] , [tex](x_2,y_2)=(2,-8)[/tex] .
x-coordinate = -10+[tex]\frac{2(2+10)}{(2+1)}[/tex] = -10 + [tex]\frac{2(12)}{3}[/tex] = -10 + 2(4) = -10+8 = -2
y-coordinate = 10+[tex]\frac{2(-8-10)}{(2+1)}=10+\frac{2(-18)}{3}[/tex] = 10+2(-6) = 10-12 = -2.
Hence the coordinate of the segment in the ratio is (-2,-2).
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The preimage shown below is dilated by a scale factor of 1/4 about the point (2,2). If the distance from the center of dilation to point A is 5.7 units, what is the distance from the center of dilation to point A'.
Round your answer to the nearest tenth please :)))
For given dilation of the figure, the distance from the center of dilation to point A' is approximately 1.414 units.
What exactly is dilation in mathematics?
In mathematics, dilation is a transformation that changes the size of a figure but not its shape. It is also known as scaling, enlargement, or reduction.
To perform a dilation, a figure is multiplied or divided by a scale factor, which is a positive number greater than zero. If the scale factor is greater than 1, the figure is enlarged, while if it is less than 1, the figure is reduced. If the scale factor is equal to 1, the figure remains the same size.
Now,
To find the distance from the center of dilation to point A', we need to use the fact that the distance between the center of dilation and any point on the preimage is multiplied by the scale factor to get the corresponding distance on the image.
First, let's find the distance from the center of dilation to point A:
distance from center to A = √((6-2)² + (-2-2)²) = √(4² + (-4)²) = √32 ≈ 5.657 units (rounded to three decimal places)
Next, we can use the fact that the scale factor is 1/4 to find the distance from the center of dilation to point A':
distance from center to A' = (scale factor) x (distance from center to A)
= (1/4) x 5.657
= 1.414 units (rounded to three decimal places)
Therefore, the distance from the center of dilation to point A' is approximately 1.414 units.
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The cost of a pair of boots was $84 the sales tax rate is 5% of the purchase what is the sales tax 
Answer: $4.20
Step-by-step explanation:
To answer this question, we will find 5% of $84.
First, a percent divided by 100 becomes a decimal.
5% / 100 = 0.05
Next, we are finding 5% of $84. In mathematics, "of" means multiplication.
0.05 * $84 = $4.20
what is the average voter turnout during an election? a random sample of 38 cities was asked to report the percent of registered voters who actually voted in the most recent election.
A random sample of 38 cities was asked to report their voter turnout percentages, which can be used to estimate the average voter turnout in those cities. However, caution should be taken when making generalizations about the larger population of cities, since the sample size is relatively small.
The average voter turnout during an election can be calculated by taking the percentage of registered voters who actually voted in a sample of cities and finding the mean. In this case, a random sample of 38 cities was asked to report the percent of registered voters who voted in the most recent election. To calculate the average voter turnout, follow these steps:
1. Obtain the reported voter turnout percentages from each of the 38 cities in the random sample.
2. Add up all the percentages of voter turnout from the 38 cities.
3. Divide the sum of voter turnout percentages by the number of cities (38) to find the average voter turnout.
By following these steps, you will find the average voter turnout for the most recent election, based on the random sample of 38 cities. Keep in mind that the average voter turnout can vary depending on the election and location, as factors such as political climate, awareness, and accessibility can impact voter participation. This calculated average represents an estimation of the overall turnout and may not be completely representative of the entire population, but it provides a useful measure to understand voter engagement during elections.
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One of the sides of a parallelogram has the length
of 5 in. Can the lengths of the diagonals be
4 in. and 6 in.?
Answer:
Yes they can.
The only time they would have to be different lengths is if it was a square
est.
nas
ge
5. In a survey, of the students at one
25
school said they wanted to become
doctors and 16% of the students
at
the same school said they wanted to
become teachers. The rest of the
students were undecided. Which of
the following represents the students
who were undecided?
Percentage of students who were undecided is 59% of the students were undecided about their future careers.
what is Percentage?
A percentage is a fraction or ratio expressed as a fraction of 100. It is a way of expressing a part of a whole as a proportion of the whole. It is denoted by the symbol '%'. For example, if there are 100 students in a class and 20 of them are girls, then the percentage of girls in the class is 20%.
In the given question,
To solve the problem, we need to first find out the percentage of students who were undecided. We know that 25% of the students wanted to become doctors and 16% wanted to become teachers. The percentage of students who were undecided can be found by subtracting the sum of the percentages of those who wanted to become doctors and teachers from 100%:
Percentage of students who were undecided = 100% - (25% + 16%) = 59%
Therefore, 59% of the students were undecided about their future careers.
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Find the measures of each exterior angle of a regular 66-gon, the round to the nearest tenth.
Angles: 5.4,6.4,173.6,9720
The correct angle measure in degrees for each exterior angle is 5.5. The other values provided in the question, 6.4, 173.6, and 9720, are not relevant to the problem.
What is Exterior angles ?
In a polygon, an exterior angle is an angle formed by a side and an extension of an adjacent side. The measure of an exterior angle of a regular polygon with n sides is given by 360/n degrees.
To find the measure of each exterior angle of a regular polygon, we use the formula:
Measure of each exterior angle = 360 degrees / number of sides
In this case, the polygon is a regular 66-gon, so the number of sides is 66. Thus,
Measure of each exterior angle = 360 degrees / 66 = 5.454545...
Rounding to the nearest tenth, we get:
Measure of each exterior angle ≈ 5.5 degrees
Therefore, the correct angle measure in degrees for each exterior angle is 5.5. The other values provided in the question, 6.4, 173.6, and 9720, are not relevant to the problem.
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What should Andre estimate for the probability of picking out a green block from this bag
The answer using probability are shown:
(A) 43/60 projection is used.
(B) He shouldn't alter the estimate in light of this knowledge.
What is probability?Simply put, the probability is the likelihood that something will occur.
When we don't know how an occurrence will turn out, we can discuss the likelihood or likelihood of various outcomes.
Statistics is the study of occurrences that follow a probability distribution.
Mathematics' study of random events is known as probability, and there are four major kinds of probability: axiomatic, classical, empirical, and subjective.
So, he would calculate the amount by dividing the overall number of bricks by the proportion of green bricks. The likelihood of choosing a green block out of all 60 bricks would be that.
Then, the probability would be:
= 43/60
Andre shouldn't alter his assessment, in other words.
The explanation is that we do not know whether the bricks he saw were green in color; we are only told that she looked in the bag and found 6 bricks.
The only time Andre needs to adjust his guess is if it turns out that the six bricks Mai saw in the bag were, in fact, green.
The estimate should not be altered until this proof is received.
Therefore, the answer using probability are shown:
(A) 43/60 projection is used.
(B) He shouldn't alter the estimate in light of this knowledge.
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Complete question:
Andre picks a block out of a bag 60 times and notes that 43 of them were green. What should Andre estimate for the probability of picking out a green block from this bag? Mai looks in the bag and sees that there are 6 blocks in the bag. Should Andre change his estimate based on this information? If so, what should the new estimate be? If not, explain your reasoning.
write down a polynomial of degree exactly 5 that interpolates the four points (1, 1), (2, 3), (3, 3), (4, 4).
The required polynomial of exact degree 5 which interpolates the four given points is equals to p(x) = x^3/2 -4x^2 + 63x/6 -6.
Polynomial of degree exactly 5 that interpolates the four points (1, 1), (2, 3), (3, 3), (4, 4).
Apply Lagrange interpolation.
Standard form of the Lagrange interpolation polynomial of degree n passing through n+1 distinct points (x0, y0), (x1, y1), ..., (xn, yn) is,
L(x) = Σ [yi × Π (x - xj) / (xi - xj)], for i = 0, 1, ..., n
where Π is the product operator and j takes all values different from i.
For the given four points, we have n = 3, so the polynomial has degree n+1 = 4.
Using the formula, we have,
L(x) = (1× (x - 2)(x - 3)(x - 4) / ((1 - 2)(1 - 3)(1 - 4)))
+ (3× (x - 1)(x - 3)(x - 4) / ((2 - 1)(2 - 3)(2 - 4)))
+ (3× (x - 1)(x - 2)(x - 4) / ((3 - 1)(3 - 2)(3 - 4)))
+ (4× (x - 1)(x - 2)(x - 3) / ((4 - 1)(4 - 2)(4 - 3)))
Simplifying this expression, we get,
⇒L(x) = (-x^3 + 9x^2 - 26x + 24)/6 + (3x^3/2 - 12x^2 + 57x/2 - 18) +(-3x^3/2 + 21x^2 /2- 21x + 12) + (2x^3/3 - 4x^2 + 22x/3 - 4)
⇒L(x) = x^3/2 -4x^2 + 63x/6 -6
Therefore, the polynomial of degree exactly 5 that interpolates the four points (1, 1), (2, 3), (3, 3), (4, 4) is p(x) = x^3/2 -4x^2 + 63x/6 -6.
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If a stone is thrown upward with a speed of 110 feet per second from a height of 500 feet above the surface of a planet, the equation h = 500 + 110t - 5.5t² approximates the height of the stone, in feet, at t seconds. When will the stone be 698 feet above the planet's surface?
We can solve for the time when the stone will be 698 feet above the planet's surface by setting h = 698 and solving for t in the equation h = 500 + 110t - 5.5t²:
698 = 500 + 110t - 5.5t²
Rearranging, we get:
5.5t² - 110t + 198 = 0
Dividing both sides by 5.5, we get:
t² - 20t + 36 = 0
This is a quadratic equation that we can solve using the quadratic formula:
t = (-(-20) ± sqrt((-20)² - 4(1)(36))) / (2(1))
Simplifying, we get:
t = (20 ± sqrt(64)) / 2
t = 10 ± 4
So the possible values of t are t = 14 or t = 6. We can check which value is correct by plugging each value into the original equation and seeing if it gives a height of 698:
When t = 14:
h = 500 + 110(14) - 5.5(14)²
h = 500 + 1540 - 1078
h = 962
When t = 6:
h = 500 + 110(6) - 5.5(6)²
h = 500 + 660 - 198
h = 962
So both values of t give a height of 698. Therefore, the stone will be 698 feet above the planet's surface at t = 6 seconds or t = 14 seconds.
19 3/5 × 20 2/5 secial product patterns to find the product
Answer: 19 3/5 x 20 2/5 = 9996/25 = 399 21/25
HELP have no idea how to do this
Answer:
use SSS
Step-by-step explanation:
Given two congruent chords AB and BC in circle O, you want to prove ∆AOB is congruent to ∆COB.
Statement . . . . Reason1. circle O, AB≅BC . . . . given
2. OB ≅ OB . . . . reflexive property of congruence
3. OA ≅ OC . . . . definition of a circle
4. ∆AOB ≅ ∆COB . . . . SSS postulate
__
Additional comment
Your erased statement 2 shows you know exactly how to do this.
All the radii of a circle are the same length, so it is easy to show congruence by SSS, given that AB≅BC.
Given circle E with diameter CD and radius EA. AB is tangent to E at A. If AC = 9 and AD = 4, solve for CD. Round your answer to the nearest tenth if necessary. If the answer cannot be determined, click "Cannot be determined."
Since AB is tangent to circle E at A, we know that angle CAB is a right angle (tangent is perpendicular to the radius at the point of tangency). Therefore, triangle ADC is a right triangle.
Let's use the Pythagorean theorem to find the length of CE:
CE^2 = AC^2 + AE^2 (using Pythagorean theorem in triangle ACE)
CE^2 = 9^2 + EA^2 (since AE = EA, by definition of radius)
CE^2 = 81 + EA^2
We still need to find EA. Let's use the fact that EA is half the length of CD:
EA = CD/2
Now we can substitute this expression into the previous equation:
CE^2 = 81 + (CD/2)^2
CE^2 = 81 + CD^2/4
Next, let's use the Pythagorean theorem in triangle ADC:
AD^2 + DC^2 = AC^2
4^2 + DC^2 = 9^2
DC^2 = 9^2 - 4^2
DC^2 = 65
Now we can substitute this expression into the previous equation:
CE^2 = 81 + 65/4
CE^2 = 99.25
Taking the square root of both sides, we get:
CE ≈ 9.96
Therefore, CD = 2CE ≈ 19.9.
Answer: CD ≈ 19.9
GEOMETRY PLS HELP ASAP
Answer:
1) 5
Step-by-step explanation:
Trapezoid Midsegment Theorem:
EF = (DC + AB) / 2
2x + 2 = ((x + 3) +(5x - 9)) / 2
4x + 4 = 6x - 6
-2x = -10
x = 5
The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 3186
grams and a variance of 385,641
. if a newborn baby boy born at the local hospital is randomly selected, find the probability that the weight will be between 3682
and 4552
grams. round your answer to four decimal places.
please need help asap
The probability that a randomly selected newborn baby boy's weight is between 3682 and 4552 grams is approximately 0.1979, or 19.79% when rounded to four decimal places.
To find the probability that a newborn baby boy's weight Convert the weights to z-scores:
z = (X - μ) / σ, where X is the weight, μ is the mean, and σ is the standard deviation.
First, calculate the standard deviation:
σ = √variance = √385,641 ≈ 621
Now, calculate the z-scores for the given weights:
z1 = (3682 - 3186) / 621 ≈ 0.7986
z2 = (4552 - 3186) / 621 ≈ 2.1965
Use a standard normal table or a calculator with a standard normal probability function to find the probabilities corresponding to these z-scores:
P(Z ≤ 0.7986) ≈ 0.7879
P(Z ≤ 2.1965) ≈ 0.9858
Find the probability that the weight is between the two z-scores:
P(0.7986 ≤ Z ≤ 2.1965) = P(Z ≤ 2.1965) - P(Z ≤ 0.7986) ≈ 0.9858 - 0.7879 ≈ 0.1979
So, the probability that a randomly selected newborn baby boy's weight is between 3682 and 4552 grams is approximately 0.1979, or 19.79% when rounded to four decimal places.
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Find the height of the basketball hoop
Answer: 13.51 (not in inches format)
Step-by-step explanation:
tan(x) = 4.384/12
x = tan^-1 (4.384/12)
x = 20.068°
tan(20.068) = y/(12+25)
tan(20.068) = y/37
20.068 = tan^-1 (y/37)
y = 13.51
Answer:
Step-by-step explanation:
To solve this with similar triangles - you need to set up a proportion.
I changed it all to inches.
12 ft = 144 in
4.384 ft = 51. 84 inches
12 + 25 (you need to add the base of the triangle) = 37 ft = 444 inches
set up smaller triangle in proportion to bigger triangle
51.84"/144" = x/444
cross mulitply then divide
51.84 times 444 = 23016.96
23016.96 ÷ 144 = 159.84 inches
Change back to feet by dividing by 12
159.84 ÷ 12 = 13.32 ft
Find an for each geometric sequence.
a₁= 3r= 1/10 n=8
O a. 3
Ob. 2 4/10
Oc.
3
10,000,000
Od. 2 1/10
The geometric sequence for the value of a₁= 3 r= 1/10 n=8 is [tex]a_{8} = \frac{3}{10000000}[/tex] i.e option c is correct.
What does the term "geometric sequence" mean?
A geometric sequence is a set of integers where the ratio between each pair of succeeding terms is fixed. The geometric sequence's general ratio is the name of this constant.
We can use the following algorithm to determine the nth term (an) of a geometric sequence:
[tex]a_{n} = a_{1} * r^{n-1}[/tex]
where a1 is the first term in the series, r represents the common ratio, and n denotes the term's number.
Since a1 = 3, r = 1/10, and n = 8, we get:
[tex]a_{8} = 3 * (\frac{1}{10})^{8-1} = 3 *( \frac{1}{10})^{7}[/tex]
[tex]= 3 * \frac{1}{10^{7} }[/tex]
Now, we can condense this equation to get the solution:
a₈ = [tex]\frac{3}{10000000}[/tex]
The solution is therefore [tex]\frac{3}{10000000}[/tex] that option c.
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the test scores for the students in two classes are summarized in these box plots. the 17 students in class 1 each earned a different score.the 13 students in class 2 each earned a different score.what is the difference between the number of students who earned a score of 90 or less in class 2 and the number of students who earned less than 75 in class 1?the test scores for the students in two classes are summarized in these box plots. the 17 students in class 1 each earned a different score.the 13 students in class 2 each earned a different score.what is the difference between the number of students who earned a score of 90 or less in class 2 and the number of students who earned less than 75 in class 1?
The number of students who earned a score of 90 or less in class 2 is 7, and the number of students who earned less than 75 in class 1 is 3. The difference between the two is 4.
The given problem presents two box plots representing the test scores for two different classes. Class 1 has 17 students, while class 2 has 13 students. It is required to find the difference between the number of students who earned a score of 90 or less in class 2 and the number of students who earned less than 75 in class 1.
By analyzing the box plots, we can see that 7 students in class 2 earned a score of 90 or less, while only 3 students in class 1 earned less than 75. Therefore, the difference between the two is 4. It is important to understand box plots and their interpretation to solve such problems.
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Find the area of the Square
1 in
1 in
please explain I'll mark brainlisest
Y=-x+1
Y= 2/3x-4
How many solutions does it have?
Answer:
x = -5
Y = -22/3
Step-by-step explanation:
Y= 2/3x - 4 Y = -x + 1
We put -x + 1 in for y to solve for x
-x + 1 = 2/3x - 4
-5/3x + 1 = -4
-5/3x = -5
x = -5
Now put -5 in for x and solve for y
Y= 2/3(-5) - 4
Y = -10/3 - 4
Y = -22/3
So, there are only one solution x = -5 and y = -22/3
If Triangle CFE is congruent to triangle PTR, Complete each of the following statements.
(37 points)
"Triangle CFE is congruent to triangle PTR" is true.
If Triangle CFE is congruent to triangle PTR, we can make the following statements:
The corresponding sides of the triangles are congruent:
This means that CF = PT, FE = TR, and CE = PR.
The corresponding angles of the triangles are congruent:
This means that angle CFE is congruent to angle PTR, angle FCE is congruent to angle PRT, and angle ECF is congruent to angle TPR.
The triangles are equal in area: Since the triangles are congruent, they have the same shape and size. Therefore, they will have the same area.
The triangles can be superimposed on each other: This means that we can place triangle CFE on top of triangle PTR in such a way that their corresponding sides and angles overlap.
If we know the measurements of the sides and angles of one triangle, we can find the measurements of the sides and angles of the other triangle: Since the triangles are congruent, we know that their corresponding sides and angles are equal.
Therefore, if we know the measurements of the sides and angles of one triangle, we can find the measurements of the sides and angles of the other triangle by using the congruence criteria.
In conclusion, if Triangle CFE is congruent to triangle PTR, we can make several statements about their corresponding sides and angles, their areas, and their ability to be superimposed on each other.
We can also use the congruence criteria to find the measurements of the sides and angles of one triangle if we know the measurements of the sides and angles of the other triangle.
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5. Heidi's family is trying to decide on the shorter
of two routes for a trip from Georgetown to
Cypress City. One route begins in Georgetown
and goes 53 miles to Cycle City, then 28 miles
to Aspen and 98 miles to Cypress City. The
second route also begins in Georgetown and
goes 28 miles to Canon City, then 49 miles to
Grover and 85 miles to Cypress City. Which
route is shorter and by how much?
Answer: We can find the total distance of the first route by adding the individual distances:
53 + 28 + 98 = 179 miles
Similarly, we can find the total distance of the second route:
28 + 49 + 85 = 162 miles
Therefore, the second route is shorter by (179 - 162) = 17 miles.
Step-by-step explanation:
The histograms display the frequency of temperatures in two different locations in a 30-day period.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 14. A shaded bar stops at 10 above 60 to 69, at 9 above 70 to 79, at 5 above 80 to 89, at 4 above 90 to 99, and at 2 above 100 to 109. There is no shaded bar above 110 to 119. The graph is titled Temps in Sunny Town.
A graph with the x-axis labeled Temperature in Degrees, with intervals 60 to 69, 70 to 79, 80 to 89, 90 to 99, 100 to 109, 110 to 119. The y-axis is labeled Frequency and begins at 0 with tick marks every one unit up to 16. A shaded bar stops at 2 above 60 to 69, at 4 above 70 to 79, at 12 above 80 to 89, at 6 above 90 to 99, at 4 above 100 to 109, and at 2 above 110 to 119. The graph is titled Temps in Desert Landing.
When comparing the data, which measure of variability should be used for both sets of data to determine the location with the most consistent temperature?
IQR, because Sunny Town is skewed
IQR, because Desert Landing is symmetric
Range, because Sunny Town is skewed
Range, because Desert Landing is symmetric
Question 2(Multiple Choice Worth 2 points)
(Comparing Data MC)
The data given represents the number of gallons of coffee sold per hour at two different coffee shops.
Coffee Ground
1.5 20 3.5
12 2 5
11 7 2.5
9.5 3 5
Wide Awake
2.5 10 4
18 4 3
3 6.5 15
6 5 2.5
Compare the data and use the correct measure of center to determine which shop typically sells the most amount of coffee per hour. Explain.
Wide Awake, with a median value of 4.5 gallons
Wide Awake, with a mean value of about 4.5 gallons
Coffee Ground, with a mean value of about 5 gallons
Coffee Ground, with a median value of 5 gallons
For the first question, the measure of variability that should be used for both sets of data to determine the location with the most consistent temperature is IQR, because it is robust to outliers and can provide a better representation of the spread of data for skewed distributions. The option "IQR, because Desert Landing is symmetric" is incorrect because the graph of Desert Landing is not symmetric.
For the second question, we need to compare the measures of center (mean and median) of the two sets of data to determine which shop typically sells the most amount of coffee per hour. To do this, we can calculate the mean and median of each set of data:
For Coffee Ground, the mean is (1.5+20+3.5+12+2+5+11+7+2.5+9.5+3+5)/12 = 6.25 gallons and the median is the middle value of the ordered set, which is 5 gallons.
For Wide Awake, the mean is (2.5+10+4+18+4+3+6.5+15+6+5+2.5)/11 = 6.136 gallons and the median is the middle value of the ordered set, which is 4.5 gallons.
Therefore, we can conclude that Wide Awake typically sells the most amount of coffee per hour, with a median value of 4.5 gallons. The option "Wide Awake, with a mean value of about 4.5 gallons" is incorrect because the mean value of Wide Awake is slightly lower than 4.5 gallons. The option "Coffee Ground, with a median value of 5 gallons" is incorrect because the median value of Coffee Ground is lower than the median value of Wide Awake. The option "Coffee Ground, with a mean value of about 5 gallons" is incorrect because the mean value of Coffee Ground is higher than 5 gallons.
Rachel has a large pond on her property. The pond contains many different kinds of fish including bass. She knows that the population of the bass is increasing exponentially each year at a rate of 4.8%. She also knows that there are currently between 250 and 275 bass in the pond.
If P represents the actual population of the bass in the pond and t represents the elapsed time in years, then which of the following systems of inequalities can be used to determine the possible number of bass in the pond over time?
The inequalities that can be used to determine the possible number of bass in the pond over time are:
[tex]P > =250e^{0.048t} , P < =275e^{0.048t}.[/tex]
Rachel has a large pond on her property. The pond contains many different kinds of fish including bass. She knows that the population of bass is increasing exponentially each year at a rate of 4.8%. She also knows that there are currently between 250 and 275 basses in the pond.
Inequalities
Given:
r=4.8/100=0.048
Initial amount:
Lower end=250
Upper end=275
Using this equation to determine the inequalities
A=p×e^rt
Where:
A=Amount
P=Population
r=Growth rate
t=Time
Let's plug in the formula
Inequalities:
[tex]P > =250e^{0.048t}P < =275e^{0.048t}[/tex]
Therefore the inequalities are : [tex]P > =250e^{0.048t} , P < =275e^{0.048t}.[/tex]
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I need help, I wasn't in school for 2 weeks because of vacation and nobody is helping me in class!
(a) Since M is the midpoint of DE, we have ME = (1/2)b.
Also, CXE is a straight line, so C, X, and E are collinear.
Therefore, we have CX + XE = CE, or a - b + FE = b + (2a - b), which simplifies to FE = a.
(b) n = a/b - 1.
How do we calculate?X is the point on FM such that
FX:XM =n:1,
we have FX = nX and XM = X.
Since M is the midpoint of DE, we have ME = (1/2)b,
so that DX = DE - EX = b - (n + 1)X.
Using the fact that CXE is a straight line,
we have CX + XE = CE, or a - b + FE = b + (2a - b),
which simplifies to FE = a.
Therefore, we have FX + FE = AX, or nX + a = a + b + (n + 1)X.
Simplifying, we get b = (n + 1)X - nX = X.
We know that DX = b - (n + 1)X = 0, so X = b/(n + 1).
Therefore, we have n/(n + 1) = FX/X = (a-b)/b.
Calculating for n, we have n = a/b - 1.
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Find the area and perimeter 20 12