If m ZABD = 83º, what are mZABC and m ZDBC?
3x+33° D
(Ex-6)°
B
mZABC = °

Answer:

LM = 24 cm

Step-by-step explanation:

Using the tangent ratio in the right triangle to find JL

tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{JL}{KL}[/tex] = [tex]\frac{JL}{10}[/tex] = 0.8 ( multiply both sides by 10 )

JL = 8

Then

LM = JL + JM = 8 + 16 = 24 cm

Answer:

21.6cm^2

Step-by-step explanation:

area = length * breadth

= 7.2 * 3 = 21.6

Answer:

plz describe whole question!!

Step-by-step explanation:

your question is incomplete

Answer:

Below,...!

Step-by-step explanation:

1 = Variable

2 = Exponent

3/4 = Coefficient

1. True

2. False

3. True

4. FaLSE

Answer:

x²+5x

Step-by-step explanation:

You can make (f-g)(x) into (x) - (-x²-4x) because f(x)=x and g(x)=x²-4x

(x)-(-x²-4x) can simplify into x+x²+4x once you distribute the negative sign.

x+x²+4x simplifies into x²+5x.

So your final answer is x²+5x.

I hope it's right and this helps!

Answer:

To South

Step-by-step explanation:

note the directions that are given on the left side

Answer:

यो त युनाइटेड स्टेट्स अफ अमेरिका हो।

Answer:

Step-by-step explanation:

A variable

Step-by-step explanation:

[tex](6x^2-5x+7)(3x+4)[/tex]

[tex]=(6x^2-5x+7)(3x)+(6x^2-5x+7)(4)[/tex]

[tex]=(6x^2)(3x)+(-5x)(3x)+(7)(3x)+(6x^2)(4)+(-5x)(4)+(7)(4)[/tex]

[tex]=18x^3-15x^2+21x+24x^2-20x+28[/tex]

[tex]=18x^3+9x^2+x+28[/tex]

Answer:

The order you placed it in at first was correct.

Step-by-step explanation:

Answer:

-43

Step-by-step explanation:

If a = 6.

B= -1 - 7a. a=6. 7a=42

B = -1 - 42 = -43

Answer:

0,-5 is the marking if that's your answer to the question

Answer:

[tex]9m^5n^-7[/tex]  = [tex]\frac{ 9m^5}{n^ 7}[/tex]

Step-by-step explanation:

Answer:

DF = 57

Step-by-step explanation:

DE + EF = DF

(4x + 10) + (2x - 1) = 9x - 15

Combine like terms on the left side

6x + 9 = 9x - 15

Subtract 6x on both sides

9 = 3x - 15

Add 15 on both sides

24 = 3x

Divide by 3 on both sides

x = 8

DF = 9x - 15 = 9(8) - 15 = 72 - 15 = 57

Checking:

(4(8) + 10) + (2(8) - 1) = 9(8) - 15

(32 + 10) + (16 - 1) = 72 - 15

58 - 1 = 72 - 15

57 = 57

Answer:

DF= DE+EF

9x–15 = (4x+10)+(2x-1)

9x–15 = 6x +9

9x–6x= 9+15

3x = 24

x=24/3

x=8

DF = 9x –15 = 9(8)–15= 72 –15 = 57

So; DF = 57

I hope I helped you^_^

Answer:

(-2,6)

Step-by-step explanation:

I took the test

Answer: sqrt 8 = 2 sqrt2

Step-by-step explanation:

d = sqrt [(0–2)^2+(2-4)^2]

= sqrt (2^2 + -2^2)

= sqrt 8

Simplify: 2 sqrt2

Answer:

When x takes the value of 4, the expression takes the value of 9.

Step-by-step explanation:

We are given that the expression:

[tex]\displaystyle ax^2 + bx + c[/tex]

Evaluates to 0, 1, and 4 when x = 1, 2, and 3, respectively.

And we want to determine the value of the expression when x = 4.

The expression evaluates to 0 when x = 1. In other words:

[tex]\displaystyle a(1)^2 + b(1) +c = a + b + c = 0[/tex]

We can complete the same for the other two:

[tex]\displaystyle a(2)^2 + b(2) + c = 4a + 2b + c = 1\text{ and } \\ \\ a(3)^2 + b(3) + c = 9a + 3b + c = 4[/tex]

This yields a triple system of equations:

[tex]\displaystyle \left\{ \begin{array}{l} a + b + c = 0 \\ 4a + 2b + c = 1 \\ 9a + 3b + c = 4 \end{array}[/tex]

Solve. We can cancel out the c by multiplying the first equation by negative one and adding it to both the second and the third:

[tex]\displaystyle \begin{aligned} (4a + 2b + c) + (-a - b -c ) &= (-0) + (1) \\ \\ 3a +b &= 1\end{aligned}[/tex]

And:

[tex]\displaystyle \begin{aligned} (9a + 3b + c) + (-a - b -c) &= (-0) + (4) \\ \\ 8a + 2b &= 4\end{aligned}[/tex]

Solve for the two resulting equations. We can multiply the first by negative two and add it to the second:

[tex]\displaystyle \begin{aligned}(8a + 2b) + (-6a -2b) &= (4) + (-2) \\ \\ 2a &= 2 \end{aligned}[/tex]

Hence:

[tex]a = 1[/tex]

Solve for b:

[tex]\displaystyle \begin{aligned} 3a + b &= 1 \\ b&= 1 - 3a \\ b&= 1 - 3(1) \\ b &= -2\end{aligned}[/tex]

And finally, solve for c:

[tex]\displaystyle \begin{aligned} a + b + c &= 0 \\ (1) + (-2) + c &= 0 \\ c &= 1\end{aligned}[/tex]

Hence, our expression is:

[tex]\displaystyle x^2 -2x + 1[/tex]

Then when x = 4:

[tex]\displaystyle (4)^2 - 2(4) + 1= 9[/tex]

In conclusion, when x = 4, the resulting value is 9.

Answer:

£17920

Step-by-step explanation:

total length of the field = 2(155+485) = 1280m

cost = 1280 * 14 = 17920

Answer:

Number 11 I doubt the answer is right or wrong so I made 2 answers. If you know the answer please tell me, so I understand

Answer:

25 divide 7

Step-by-step explanation:

hope this helps you

Step-by-step explanation:

a) given slope=m1=4/b

parallel slope=m2=-8

when two lines are parallel their reltion of slopes is:

m1=m2

4/b=-8

b=-4/8

b=-1/2

b) m1=4/b , m2=3/4

when slopes are perpendicular their relation of slopes is:

m1×m2=-1

4/b × 3/4=-1

3/b=-1

b=-3

Note:if you need to ask any question please let me know.

Answer

The answer is D. 5

Answer:

2.5/.5 = 5 Anything that is divided by 0.5 or 1/2 is double the number it's getting divided by. 2.5 doubled is 5

Step-by-step explanation:

Answer:

90 feet.

Step-by-step explanation:

2 sides are 50 feet long = 100 feet.

That leaves 280 - 100 = 180 feet.

So the length of the longer sides  are both 90 feet.

Answer:

[tex] \displaystyle 0.344[/tex]

Step-by-step explanation:

we are given that a coin is tossed 6 times and we want to find the probability of getting at most 2 heads.

To solve this problem,we can consider binomial distribution, which is given by

[tex] \displaystyle P(X = r) = \binom{n}{r} {p}^{r} {q}^{n - r} [/tex]

where:

we want to figure out the probability of getting at most 2 heads out of 6 trials , The probability can therefore be found by adding up all the binomial distributions including X=2 and less than it, Thus

[tex] \displaystyle P(X \leq 2) = P(X=0)+P(X=1)+P(X=2) [/tex]

[tex] \displaystyle P(X \leq 2) = \binom{6}{0} {p}^{0} {q}^{6 - 0} + \binom{6}{1} {p}^{1} {q}^{6- 1} + \binom{6}{2} {p}^{2} {q}^{6 - 2} [/tex]

when a coin is tossed, the probability of getting both head (success) and tail (failure) are ½ which is why ,the variables, p and q are assigned to ½. therefore substitute

[tex] \rm\displaystyle P(X \leq 2) = \binom{6}{0} { \left( \frac{1}{2} \right) }^{0} { \bigg( \frac{1}{2} \bigg) }^{ 6- 0} + \binom{6}{1} { \bigg( \frac{1}{2} \bigg) }^{1} { \bigg( \frac{1}{2} \bigg) }^{6 - 1} + \binom{6}{2} { \bigg( \frac{1}{2} \bigg)}^{2} { \bigg( \frac{1}{2} \bigg) }^{6- 2} [/tex]

since p and q are the same. it won't make any difference to write all the product of p and q as (½)⁶:

[tex]\rm\displaystyle P(X \leq 2) = \binom{6}{0} { \bigg( \frac{1}{2} \bigg) }^{ 6} + \binom{6}{1} { \bigg( \frac{1}{2} \bigg) }^{6} + \binom{6}{2} { \bigg( \frac{1}{2} \bigg) }^{6}[/tex]

In the expression the term (½)⁶ is common thus factor it out:

[tex]\rm\displaystyle P(X \leq 2) = { \bigg(\frac{1}{2}\bigg) }^{ 6} \left( \binom{6}{0} + \binom{6}{1} + \binom{6}{2} \right) [/tex]

calculate the combinations:

[tex]\rm\displaystyle P(X \leq 2) = { \bigg(\frac{1}{2}\bigg) }^{ 6} \left(1+6+15\right) [/tex]

simplify addition:

[tex]\rm\displaystyle P(X \leq 2) = { \bigg(\frac{1}{2}\bigg) }^{ 6} \left(22\right) [/tex]

simplify exponent:

[tex]\rm\displaystyle P(X \leq 2) = { \bigg(\frac{1}{64}\bigg) } \left(22\right) [/tex]

simplify multiplication:

[tex]\rm\displaystyle P(X \leq 2) = \frac{22}{64} [/tex]

dividing yields:

[tex]\rm\displaystyle P(X \leq 2) = 0.34375 [/tex]

[tex]\rm\displaystyle P(X \leq 2) \approx 0.344 [/tex]

In conclusion

The answer is 0.344

Answer:

-8/3x

Step-by-step explanation:

-8 / 3x / 1

-8 / 3x

.....

..

Answer:

coxkyxkyxoydoyd

Step-by-step explanation:

kysoydoyxlhxlhxohxoudyodgufudytdxgchjvgufychvjugfychgifuyfchuguffychjbohihfydtxgbjjbhcvjgujfjfjf

Answer:

3^16 cells

Step-by-step explanation:

The scientist has 3^15 cells. If we triple the number of cells, we multiply this amount by 3

3 * 3^15 = 3^1 * 3^15

Remember your laws of exponents: we add the exponents here.

3^(1+15) = 3^16

Answer:

I HOPE THE ABOVE PHOTO WILL HELP YOU A LOT.

[tex]\huge{\mathcal {{{\color{orange}{\boxed{\rm \begin{array}{|c|c|c|c|} { \rm\: x}&2&5&8\\{\rm\:y}&2&0&2\end{array}}}}}}} [/tex]

[tex] \Huge \mid\underline {\mathcal {{{\color{orange}{\LARGE{\mathcal{{{\color{red}{Solution}}}}}}}}}} \mid[/tex]

If x is 2

Then ,

2x + 3y = 10

2(2) + 3y = 10

4 + 3y = 10

3y = 10 - 4

3y = 6

y = 6/3

y = 2

If y is 0

Then ,

2x + 3y = 10

2x + 3(0) = 10

2x + 0 = 10

2x = 10

x = 10/2

x = 5

If x is 8

Then ,

2x + 3y = 10

2(8) + 3y = 10

16 + 3y = 10

3y = 10 - 16

3y = -6

y = -6/2

y = -3

[tex]\huge{\mathcal{{{\color{blue}{\boxed{\rm \begin{array}{|c|c|c|c|} { \rm\: x}&2&2&4\\{\rm\:y}& - 2&2& - 8\end{array}}}}}}} [/tex]

[tex] \Huge \mid\underline {\mathcal {{{\color{orange}{\LARGE{\mathcal{{{\color{red}{Solution}}}}}}}}}} \mid[/tex]

If x is 2

Then ,

3x - y = 4

3(2) - y = 4

6 - y = 4

-y = 4 - 6

-y = -2

If y is 2

Then ,

3x - y = 4

3x - 2 = 4

3x = 4 + 2

3x = 6

x = 6/2

x = 3

If x is 4

Then ,

3x - y = 4

3(4) - y = 4

12 - y = 4

-y = 4 - 12

-y = -8