Answer: so a^2 + b^2 = 5
Step-by-step explanation:
(a+b) = 3
ab = 2
so
(a+b)^2 = 3^2
a^2 + 2ab + b^2 = 9
or, a^2 + 2*2 + b^2 = 9
or, a^2 + 4 + b^2 = 9
or, a^2 +b^2 = 9-4 = 5
44) The length of a rectangle is 15.6 cm correct to 1 decimal place.
The width of a rectangle is 3.8 cm correct to 1 decimal place.
Calculate the upper bound for the perimeter of the rectangle.
Answer:
Perimeter = 38.8m
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
Answer:
39cm
Step-by-step explanation:
When you find the upper and lower bounds of values with decimals, you will decrease or increase the value by increments of 0.05. Since we are just trying to find the upper bound we will add 0.05 to the values we are given.
15.6 + 0.05 = 15.65cm
3.8 + 0.05 = 3.85cm
Now that we have those values, we can find the perimeter using the formula [ 2(L + W) ]
= 2(15.65 + 3.85)
= 2(19.5)
= 39cm
Best of Luck!
Y’all please help me with c
Answer:
Pretty sure you'd be in hell by then 0_0
Step-by-step explanation:
think of it-2,200 ft and your at 0. Your in hell!
write down the next three terms of these number patterns 5;11;17;23
Answer:
29, 35, 41
Step-by-step explanation:
sequence is in the difference of 6
4/5th
part of a concrete pillar was inside the water of a river if 2 m of the player was outside the water find the full height of the Pillar
Answer:
height =10
[tex] \frac{4}{5} h + 2 = h \\ h - \frac{4}{5} h = 2 \\ \frac{1}{5} h = 2 \\ h = 2 \times 5 = 10[/tex]
I need help with this question!!!! Given directed line segment QS, find the coordinates of R such that the ratio of QR to RS is 3:5. Plot point R.
Answer:
R(2, -2)Step-by-step explanation:
Coordinates of Q and S are:
Q(8, -5), S(-8, 3)We need to find the coordinates of R such that:
QR : RS = 3 : 5Let R has coordinates (x, y):
x = 8 + 3/8(-8 - 8) = 8 - 6 = 2y = -5 + 3/8(3 + 5) = -5 + 3 = -2The point is R(2, -2)
Answer:
2,-2
Step-by-step explanation:
Helppppp plzzzzzzz!!!!!!!!!!!! 20+ Pts and brainliest!!!!!!
Correct the error in solving the equation.
-2(7-y)+4=-4
-14-2y+4=-4
-10-2y=-4
-2y=6
y=-3
Answer:
Y=3
Step-by-step explanation:
in the first to second step: -2(7-y)+4=-4 to -14-2y+4=-4, the part -2(7-y) should equal -14+2y instead of 14-2y because two negative signs add to be positive
so y should be 3
Answer: What that other guy said
linear equation 3+X=-2
Answer:
x = -5
Step-by-step explanation:
3+X=-2
Subtract 3 from each side
3-3+X=-2-3
x = -5
Answer:
-5
Step-by-step explanation:
1 Subtract 3 from both sides.
x=-2-3
2 Simplify -2 -3 to -5
x=-5
f(x)=6x^2-1/x^2
1.f(5)=
2.f(-5)=
3.f(-x)=
Step-by-step explanation:
1. 6(5)^2-1/(5)^2 = 149/25
2. 6(-5)^2-1/25 = -150/25
3. 6x^2-2/x^2
Answer:
[tex]1) \huge\boxed{ \sf f(5) = 5 \frac{24}{25} }[/tex]
[tex]2) \huge\boxed{ \sf f(-5) = 5\frac{24}{25} }[/tex]
[tex]3) \huge\boxed{\sf f(-x) = \frac{6x^2-1}{x^2} }[/tex]
Step-by-step explanation:
[tex]\displaystyle f(x) = \frac{6x^2-1}{x^2}[/tex]
For f(5):
Put x = 5
[tex]\displaystyle f(5) = \frac{6(5)^2-1}{(5)^2} \\\\f(5) = \frac{6(25)-1}{25} \\\\f(5) = \frac{150-1}{25} \\\\f(5) = \frac{149}{25} \\\\f(5) = 5 \frac{24}{25}[/tex]
For f(-5):
Put x = -5
[tex]\displaystyle f(-5) = \frac{6(-5)^2-1}{(-5)^2} \\\\f(-5) = \frac{6(25)-1}{25} \\\\f(-5) = \frac{150-1}{25} \\\\f(-5) = \frac{149}{25} \\\\f(-5) = 5\frac{24}{25}[/tex]
For f(-x):
Put x = -x
[tex]\displaystyle f(-x) =\frac{6(-x)^2-1}{(-x)^2} \\\\f(-x) = \frac{6x^2-1}{x^2} \\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Peace!Two similar figures are similar based on the transformation (x,y) (12x, 3a(squared)y) what is/ are the value(s) of a?
9514 1404 393
Answer:
a = ±2
Step-by-step explanation:
For similar figures, the same scale factor applies to both x and y.
12 = 3a²
4 = a²
a = ±√4 = ±2
162×(-92)-(-162)×(-5)-162×3
Answer:
-16200
Step-by-step explanation:
162×(-92)+(162)×(-810)×3
Step-by-step explanation:
[tex](162 \times ( - 92) + 162 \times ( - 5 \times - 162) \times 3 = (-14904 + 162 )\times( 810 \times 3) = (-14904+ 162) \times (2430) = - 14742\times 2430 = 378,756
help plz answer quickly
Answer:
plane EBG
Step-by-step explanation:
plane C is also named plane EBG
Answer:
[tex]\\ \sf\longmapsto Plane EBG[/tex]
We can't name it EBF as it is a axis and coplanar points
Also nEF is not a satisfactory name .
So the correct option is C
Help please! What’s do you see/notice about the pattern below?
Answer:
Uhm, I see there's a pattern, but there are only 2 green boxes, whole there are 4 orange boxes in every figure.
55) James left the science museum driving east 1.6 hours before Kim. Kim drove in the opposite direction going 24 km/h slower than James for 1.8 hours after which time they were 258.4 km apart. How fast did James drive?
Please show ur work, I already have the answer but I need to know how to do it. If your answer matched up with the answer key and is correct with work I will give brainliest
9514 1404 393
Answer:
58 km/h
Step-by-step explanation:
Let s represent James's speed. Then s-24 is Kim's speed. The relationship between time, speed, and distance is ...
d = st
Since the two were traveling in opposite directions, their distance apart is the sum of the distances they drove. James drove for 1.6 more hours than the 1.8 hours Kim drove, so their total distance is ...
(1.6 +1.8)s +1.8(s -24) = 258.4
5.2s -43.2 = 258.4 . . . . . . . . . . . . collect terms
5.2s = 301.6 . . . . . . . . . . . add 43.2
s = 58 . . . . . . . . . . . divide by 5.2
James drove at 58 km/h.
Evaluate sin 300° without using a calculator.
Answer:
[tex]-\sqrt{3} /2[/tex]
Step-by-step explanation:
300 degrees is in the fourth quadrant (it's between 270 and 360); sine is negative in the fourth quadrant.
Given we're in the fourth quadrant, the reference angle is 360 - 300 = 60 degrees
sin(60°) = [tex]\sqrt{3} /2[/tex]
And since sine is negative, this value turns negative:
sin(300°) = [tex]-\sqrt{3} /2[/tex]
An open box is to be made from a square piece of cardboard, 36 inches by 36 inches, by removing a small square from each corner and folding up the flaps to form the sides. What are the dimensions of the box of greatest volume that can be constructed in this way?
9514 1404 393
Answer:
24 in square by 6 in deep
Step-by-step explanation:
Let x represent the side of the square cut from each corner. Then the dimensions of the base of the box are 36-2x in each direction. The total volume of the box is ...
V = LWH = (36 -2x)(36 -2x)x = x(4x² -144x +1296)
The volume will be a maximum where dV/dx = 0.
dV/dx = 12x^2 -288x +1296 = 0
x² -24x +108 = 0 . . . . divide by 12
(x -6)(x -18) = 0 . . . . . factor
x = 6 or 18 . . . . . . x = 18 gives a minimum volume; we want x = 6
Then the dimensions are 36 -2(6) = 24 inches square by 6 inches deep.
Which of the expressions below have a value of 12? Select all that apply.
A) -4 X-3
B) 6 x 2
C) -6 X-2
D) 3 X-4
E) 12 x 1
Answer:
A, B, C, and E
Step-by-step explanation:
A) -4 X-3 = 12
B) 6 x 2 = 12
C) -6 X-2 = 12
D) 3 X-4 = -12
E) 12 x 1 = 12
the expressions that have a value of 12 are :
A, B, C, and E
Answer:
Lets find
[tex]\\ \rm\longmapsto -4(-3)=12\checkmark[/tex]
[tex]\\ \rm\longmapsto 6(2)=12\checkmark[/tex]
[tex]\\ \rm\longmapsto -6(-2)=12\checkmark[/tex]
[tex]\\ \rm\longmapsto 3(-4)=-12\checkmark[/tex]
[tex]\\ \rm\longmapsto 12(1)=12\checkmark[/tex]
1
The formula for the area of a regular polygon is A = 1/2ap. What is the equation solved for a?
O a= 2A
O a= 2A-p
O a=2p/A
O a=2A/p
Answer:
a = [tex]\frac{2A}{p}[/tex]
Step-by-step explanation:
Given
A = [tex]\frac{1}{2}[/tex] ap ( multiply both sides by 2 to clear the fraction )
2A = ap ( isolate a by dividing both sides by p )
[tex]\frac{2A}{p}[/tex] = a
Can anyone help me out with this? (recursive formulas)
Step-by-step explanation:
[tex]b(1) = 4[/tex]
Since this is an arithmetic sequence, notice that if you subtract b(1) (i.e., 4) from b(2)(i.e., 22), you get 18. Likewise, if you subtract b(2) from b(3) you also get 18. Therefore,
[tex]b(n) = b(n-1) + 18[/tex]
You ask your friends what is their favorite color and count how many people fell in each of the categories. Below is the data (total: 60 people, RED-30, BLUE=10, GREEN-20). What is the Chi Square obtained Value?
a) 50
b) 9
c) 10
d) 5
Answer:
A
Step-by-step explanation:
Because lot of people love it
a rectangle has a length of 45 feet and height of 20 yards. What is the perimeter of this rectangle in feet
Perimeter is the distance around the rectangle and the formula is 2 x length + 2 x height.
Perimeter = 2 x45 + 2x20
Perimeter = 90 + 40
Perimeter = 130 yards
Answer:
Given :-Length = 45 yard
Height = 20 yards
To Find :-Perimeter
Solution :-We know that
[tex] \: perimeter = 2(l + b)[/tex]
» Perimeter = 2(45 + 20)
» Perimeter = 2(65)
» Perimeter = 130 yards
A triangle has side lengths of (8s + 8) centimeters, (s +9) centimeters, and
(8t - 1) centimeters. Which expression represents the perimeter, in centimeters, of
the triangle?
Answer:
Step-by-step explanation:
(16.2t+3.4u+2.9)cm
Step-by-step explanation:
A triangle is a plane shape that has three sides. The perimeter of a triangle is gotten by taking the sum of all the lengths of the three sides. Let the length of the three sides by s1, s2 and s3, the perimeter of the triangle will be expressed as;
P = s1+s2+s3
Given the side lengths
s1 = (8.1t-6.1)cm
s2 = (8.1t+7.1)cm
s3 = (3.4u+1.9)cm
Perimeter of the triangle = 8.1t-6.1+8.1t+7.1+3.4u+1.9
collect the like terms
P = 8.1t+8.1t+3.4u-6.1+7.1+1.9
P = 16.2t+3.4u+2.9
Hence the expression that represents the perimeter, in centimeters, of the triangle is (16.2t+3.4u+2.9)cm
como escreve por extenso o número 380.210?
Answer: trescientos ochenta mil doscientos diez es,pero te ayude
can u tell ans of this 2pls
Answer:
hope it helps you........
Help me out please! Anybody? I’m so confused
PLZ HELP WITH BOTHHHHH
Answer:
(5,2)
(6,-6)
Step-by-step explanation:
What is the best definition of a. Angle
Answer:
the space (usually measured in degrees) between two intersecting lines or surfaces at or close to the point where they meet.
Step-by-step explanation:
1, In a class of 80 students in Debreberhan University, 45 are good in mathematics, 15 are good in both mathematics and in English, 13 are good in both mathematics and psychology, 16 are good in both English and psychology only, 20 are good in psychology and 9 are good in both of the three courses.
a) How many students are good in mathematics only? b) How many students are not good in any of the three course?
Treating the data as a Venn set, it is found that:
26 students are good in mathematics only.28 students are not good in any of the three courses.---------------------------------
I am going to say that:
A is the number of students good in Math.B is the number of students good in English.C is the number of students good in Psychology.---------------------------------
9 are good in all of the three courses.
This means that: [tex]A \cap B \cap C = 9[/tex]
---------------------------------
13 are good in both mathematics and psychology
This means that:
[tex](A \cap C) + (A \cap B \cap C) = 13[/tex]
[tex](A \cap C) + 9 = 13[/tex]
[tex](A \cap C) = 4[/tex]
---------------------------------
15 are good in both mathematics and in English
This means that:
[tex](A \cap B) + (A \cap B \cap C) = 15[/tex]
[tex](A \cap B) + 9 = 15[/tex]
[tex](A \cap B) = 6[/tex]
---------------------------------
16 are good in both English and psychology
This means that:
[tex](B \cap C) + (A \cap B \cap C) = 16[/tex]
[tex](B \cap C) + 9 = 16[/tex]
[tex](B \cap C) = 7[/tex]
---------------------------------
20 are good in psychology
This means that:
[tex]c + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 20[/tex]
[tex]c + 4 + 7 + 9 = 20[/tex]
[tex]c = 0[/tex]
---------------------------------
45 are good in mathematics
This means that:
[tex]a + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 45[/tex]
[tex]a + 6 + 4 + 9 = 45[/tex]
[tex]a = 26[/tex]
---------------------------------
Question a:
[tex]a = 26[/tex], which means that 26 students are good in mathematics only.
---------------------------------
Question b:
At least one is:
[tex]a + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 26 + 6 + 4 + 7 + 9 = 52[/tex]
Thus, 80 - 52 = 28
28 students are not good in any of the three courses.
A similar problem is given at: https://brainly.com/question/22003843
solve the question please
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Answer:
arcsin(2/3) ≈ 41.81°, 138.19°Step-by-step explanation:
Rewrite as a quadratic in sin(θ) and solve that in the usual way.
3cos(2θ) +sin(θ) = 1
3(1 -2sin²(θ)) +sin(θ) = 1 . . . . use an identity for cos(2θ)
6sin²(θ) -sin(θ) -2 = 0 . . . . . rearrange to standard form
(3sin(θ) -2)(2sin(θ) +1) = 0 . . . . factor
The values of sin(θ) that make this true are ...
sin(θ) = 2/3, sin(θ) = -1/2
In the range 0 < θ < 180°, we're only interested in ...
sin(θ) = 2/3
θ = arcsin(2/3) or 180° -arcsin(2/3)
θ ≈ {41.81°, 138.19°}
Pls I am really struggling here
How do you know the end behavior of a polynomial function if the first number is a variable? Do you just move on to the next term that is a number
Answer:
You need to bring the function to the standard form.
The term with highest degree exponent is the leading term and its coefficient is the leading coefficient.
Let it be axⁿ.
Depending on the n and a, the end behavior of the function will change.
Case 1a > 0, n - is oddThis is an odd function and:
x → -∞ ⇒ f(x) → -∞x → ∞ ⇒ f(x) → ∞Case 2a < 0, n - is oddThis is an odd function and:
x → -∞ ⇒ f(x) → ∞x → ∞ ⇒ f(x) → -∞Case 3a > 0, n - is evenThis is an even function and:
x → -∞ ⇒ f(x) ⇒ ∞x → ∞ ⇒ f(x) ⇒ ∞Case 4a < 0, n - is evenThis is an even function and:
x → - ∞ ⇒ f(x) ⇒ - ∞x → ∞ ⇒ f(x) ⇒ - ∞Answer:
Yeah your right
Step-by-step explanation:
Find all points on the curve x^2y^2+xy=2 where the slope of the tangent line is −1
Differentiate both sides with respect to x and solve for the derivative dy/dx :
[tex]\dfrac{\mathrm d}{\mathrm dx}\left[x^2y^2+xy\right] = \dfrac{\mathrm d}{\mathrm dx}[2] \\\\ \dfrac{\mathrm d}{\mathrm dx}\left[x^2\right]y^2 + x^2\dfrac{\mathrm d}{\mathrm dx}\left[y^2\right] + \dfrac{\mathrm d}{\mathrm dx}\left[x\right]y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ 2xy^2 + x^2(2y)\dfrac{\mathrm dy}{\mathrm dx} + y + x\dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ (2x^2y+x)\dfrac{\mathrm dy}{\mathrm dx} = -2xy^2-y \\\\ \dfrac{\mathrm dy}{\mathrm dx} = -\dfrac{2xy^2+y}{2x^2y+x}[/tex]
This gives the slope of the tangent to the curve at the point (x, y).
If the slope of some tangent line is -1, then
[tex]-\dfrac{2xy^2+y}{2x^2y+x} = -1 \\\\ \dfrac{2xy^2+y}{2x^2y+x} = 1 \\\\ 2xy^2+y = 2x^2y+x \\\\ 2xy^2-2x^2y + y - x = 0 \\\\ 2xy(y-x)+y-x = 0 \\\\ (2xy+1)(y-x) = 0[/tex]
Then either
[tex]2xy+1 = 0\text{ or }y-x=0 \\\\ \implies y=-\dfrac1{2x} \text{ or }y=x[/tex]
In the first case, we'd have
[tex]x^2\left(-\dfrac1{2x}\right)^2+x\left(-\dfrac1{2x}\right) = \dfrac14-\dfrac12 = -\dfrac14\neq2[/tex]
so this case is junk.
In the second case,
[tex]x^2\times x^2+x\times x=x^4+x^2=2 \\\\ x^4+x^2-2 = (x^2-1)(x^2+2)=0[/tex]
which means either
[tex]x^2-1 = 0 \text{ or }x^2+2 = 0 \\\\ x^2 = 1 \text{ or }x^2 = - 2[/tex]
The second case here leads to non-real solutions, so we ignore it. The other case leads to [tex]x=\pm1[/tex].
Find the y-coordinates of the points with x = ±1 :
[tex]x=1 \implies y^2+y=2 \implies y=-2 \text{ or }y=1 \\\\ x=-1\implies y^2-y=2\implies y=-1\text{ or }y=2[/tex]
so the points of interest are (1, -2), (1, 1), (-1, -1), and (-1, 2).