(i) Represent these two sets of data by a back-to-back stem-and-leaf diagram.

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(i) Represent These Two Sets Of Data By A Back-to-back Stem-and-leaf Diagram.-Don't Give Wrong Answers

Answers

Answer 1
Answer:

[tex]{\begin{tabular}{lll}\begin{array}{r|c|l}\text{Leaf (Ali)} & \text{Stem} & \text{Leaf (Kumar)}\\\cline{1-3} 7 & 4 & 1\ 2\ 3\ 6\ 6\ 9\ 9 \\ 9\ 8 & 5 & 2\ 2\ 3\\ 5\ 5 & 6 & \\ 7\ 2\ 0 & 7 & 8\ 8\ 9\\ 9\ 9\ 8\ 4\ 3\ 3\ 3\ 1\ 1 & 8 & 2\ 2\ 4\ 5\\ 9\ 8\ 1 & 9 & 0\ 2\ 5\\ \end{array} \\\\ \fbox{\text{Key: 7} \big| \text{4} \big| \text{1 means 4.7 for Ali and 4.1 for Kumar}} \end{tabular}}[/tex]

=========================================================

Explanation:

The data set for Ali is

8.3, 5.9, 8.3, 8.9, 7.7, 7.2, 8.1, 9.1, 9.8, 5.8,

8.3, 4.7, 7.0, 6.5, 6.5, 8.4, 8.8, 8.1, 8.9, 9.9

which when on a single line looks like this

8.3, 5.9, 8.3, 8.9, 7.7, 7.2, 8.1, 9.1, 9.8, 5.8, 8.3, 4.7, 7.0, 6.5, 6.5, 8.4, 8.8, 8.1, 8.9, 9.9

Let's sort the values from smallest to largest

4.7, 5.8, 5.9, 6.5, 6.5, 7.0, 7.2, 7.7, 8.1, 8.1, 8.3, 8.3, 8.3, 8.4, 8.8, 8.9, 8.9, 9.1, 9.8, 9.9

Now lets break the data up into separate rows such that each time we get to a new units value, we move to another row

4.7

5.8, 5.9

6.5, 6.5

7.0, 7.2, 7.7

8.1, 8.1, 8.3, 8.3, 8.3, 8.4, 8.8, 8.9, 8.9

9.1, 9.8, 9.9

We have these stems: 4, 5, 6, 7, 8, 9 which represent the units digit of the values. The leaf values are the tenths decimal place.

For example, a number like 4.7 has a stem of 4 and leaf of 7 (as indicated by the key below)

This is what the stem-and-leaf plot looks like for Ali's data only

[tex]\ \ \ \ \ \ \ \ \text{Ali's data set}\\\\{\begin{tabular}{ll}\begin{array}{r|l}\text{Stem} & \text{Leaf}\\ \cline{1-2}4 & 7 \\ 5 & 8\ 9 \\ 6 & 5\ 5 \\ 7 & 0\ 2\ 7 \\ 8 & 1\ 1\ 3\ 3\ 3\ 4\ 8\ 9\ 9 \\ 9 & 1\ 8\ 9\\ \end{array} \\\\ \fbox{\text{Key: 4} \big| \text{7 means 4.7}} \\ \end{tabular}}[/tex]

The stem-and-leaf plot condenses things by tossing out repeated elements. Instead of writing 8.1, 8.1, 8.3 for instance, we can just write a stem of 8 and then list the individual leaves 1, 1 and 3. We save ourselves from having to write two more copies of '8'

Through similar steps, this is what the stem-and-leaf plot looks like for Kumar's data set only

[tex]\ \ \ \ \ \ \ \ \text{Kumar's data set}\\\\{\begin{tabular}{ll}\begin{array}{r|l}\text{Stem} & \text{Leaf}\\ \cline{1-2}4 & 1\ 2\ 3\ 6\ 6\ 9\ 9 \\ 5 & \ 2\ 2\ 3\ \ \ \ \\ 6 & \\ 7 & 8\ 8\ 9 \\ 8 & 2\ 2\ 4\ 5\\ 9 & 0\ 2\ 5\\ \end{array} \\\\ \fbox{\text{Key: 4} \big| \text{1 means 4.1}} \\ \end{tabular}}[/tex]

Kumar doesn't have any leaves for the stem 6, so we will have that section blank. It's important to have this stem so it aligns with Ali's stem plot.

Notice that both stem plots involve the same exact set of stems (4 through 9 inclusive).

What we can do is combine those two plots into one single diagram like this

[tex]{\begin{tabular}{lll}\begin{array}{r|c|l}\text{Leaf (Ali)} & \text{Stem} & \text{Leaf (Kumar)}\\\cline{1-3} 7 & 4 & 1\ 2\ 3\ 6\ 6\ 9\ 9 \\ 8\ 9 & 5 & 2\ 2\ 3\\ 5\ 5 & 6 & \\ 0\ 2\ 7 & 7 & 8\ 8\ 9\\ 1\ 1\ 3\ 3\ 3\ 4\ 8\ 9\ 9 & 8 & 2\ 2\ 4\ 5\\ 1\ 8\ 9 & 9 & 0\ 2\ 5\\ \end{array} \\ \end{tabular}}[/tex]

Then the last thing to do is reverse each set of leaves for Ali (handle each row separately). The reason for this is so that each row of leaf values increases as you further move away from the stem. This is simply a style choice. This is somewhat similar to a number line, except negative values aren't involved here.

This is what the final answer would look like

[tex]{\begin{tabular}{lll}\begin{array}{r|c|l}\text{Leaf (Ali)} & \text{Stem} & \text{Leaf (Kumar)}\\\cline{1-3} 7 & 4 & 1\ 2\ 3\ 6\ 6\ 9\ 9 \\ 9\ 8 & 5 & 2\ 2\ 3\\ 5\ 5 & 6 & \\ 7\ 2\ 0 & 7 & 8\ 8\ 9\\ 9\ 9\ 8\ 4\ 3\ 3\ 3\ 1\ 1 & 8 & 2\ 2\ 4\ 5\\ 9\ 8\ 1 & 9 & 0\ 2\ 5\\ \end{array} \\\\ \fbox{\text{Key: 7} \big| \text{4} \big| \text{1 means 4.7 for Ali and 4.1 for Kumar}} \end{tabular}}[/tex]

The fact that Ali is on the left side vs Kumar on the right, doesn't really matter. We could swap the two positions and end up with the same basic table. I placed Ali on the left because her data set is on the top row of the original table given.

The thing you need to watch out for is that joining the stem and leaf for Ali means you'll have to read from right to left (as opposed to left to right). Always start with the stem. That's one potential drawback to a back-to-back stem-and-leaf plot. The advantage is that it helps us compare the two data sets fairly quickly.


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Answers

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Answers

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Step-by-step explanation:

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Brainliest would be appreciated

Answer:

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Step-by-step explanation:

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Answers

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Answer:

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Answers

Answer:

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Answers

Answer:

  (a)  90°

Step-by-step explanation:

A graph can help you answer the question about where the graphs of the two functions intersect. It shows the one angle of intersection to be 90°.

__

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Answers

Answer:

x = -5 plus/minus sqrt( 26 )

Step-by-step explanation:

Let's remember the binomial square formula

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We have:

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A = x

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we get a perfect square: x^2 + 2*5x + 25 = (x + 5)^2.      [++]

Based on this reasoning, let's set f(x) = 0

x^2 +10x -1 = 0

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x^2 +10x +25 = 26

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Answers

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Answers

Answer:

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Answers

Answer:12=59

Step-by-step explanation:

Find an equation of the line that goes through the points (8,-45) and (2,-9). Write your answer in the form y = mx + b.

Answers

Linear Equations

Linear equations are commonly organized in slope-intercept form:

[tex]y=mx+b[/tex]

m = slopeb = the y-intercept (the value of y when x=0)

To find the equation of a line given two points:

Determine the slope of the line using the slope formulaPlug the slope into [tex]y=mx+b[/tex]Determine the y-intercept by solving for bPlug the y-intercept back into the equation

Solving the Question

We're given:

The line passes through the points (8,-45) and (2,-9)

First, determine the slope using the following formula:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex] where the given points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]

⇒ Plug in the given points (8,-45) and (2,-9):

[tex]m=\dfrac{-45-(-9)}{8-2}\\\\m=\dfrac{-45+9}{8-2}\\\\m=\dfrac{-36}{6}\\\\m=-6[/tex]

Therefore, the slope of the line is -6. Plug this into [tex]y=mx+b[/tex] as m:

[tex]y=-6x+b[/tex]

Now, determine the y-intercept:

[tex]y=-6x+b[/tex]

⇒ Plug in one of the given points as (x,y) and solve for b:

[tex]-9=-6(2)+b\\-9=-12+b\\3=b[/tex]

Therefore the y-intercept of the line is 3. Plug this back into [tex]y=-6x+b[/tex]:

[tex]y=-6x+3[/tex]

Answer

[tex]y=-6x+3[/tex]

1. How many degrees are in this angle, which is one-fourth of the circle?

Answers

Answer: 90 degrees

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360/4 = 90 (: hope this helps

Answer:

90* x 4 = 360*

360* / 4 = 90*

Step-by-step explanation:

A circle has 360* all around.

In the angle that was drawn, it is 90*

The degrees for the space outside of 90* is x

x = ?                360* - 90* = 280*                 x = 280*

hope this helped

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