Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]m = 14[/tex]
»»————- ★ ————-««
Here’s why:
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[tex]\boxed{\text{Solving for 'm'...}}}\\\\(\frac{3}{7}) m=6\\\\-------------\\\rightarrow (\frac{3}{7}m)7 = 6*7\\\\\rightarrow 3m = 42\\\\\rightarrow \frac{3m=42}{3}\\\\\rightarrow \boxed{m= 14}[/tex]
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»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
two numbers are at ratio of 5:9 find the larger number if the smaller number 35
9514 1404 393
Answer:
63
Step-by-step explanation:
We observe that multiply the smaller number in the ratio by 7 we get 35. Then the ratio is ...
5 : 9 = 35 : 63 . . . . . . multiply both numbers by 7
The larger number is 63.
help me plz branniest to whoever right
x=-9 y=-8 evaluate the expression 8 x^2 - 6 y^2
Answer:
264Step-by-step explanation:
Let x= -9 y= -88x² - 6y² = ?8(-9)² - 6(-8)² = ?8(81) - 6(64) = ?648 - 384 = ?264[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
create a improper fraction with the number 10 as the denominator
Answer:
Decimal Fraction Percentage
0.101 101/1000 10.1%
0.1 100/1000 10%
0.1013 101/997 10.13%
0.1012 101/998 10.12%
Step-by-step explanation:
8x – 3 = 11 + 6x
What is x
Answer:
x = 7
Step-by-step explanation:
[tex]8x-3=11+6x\\\\2x-3=11\\\\2x=14\\\\x=7[/tex]
Answer:
x = 7
Step-by-step explanation:
8x - 3 = 11 + 6x
8x - 3 + 3 = 11 + 6x +3
8x = 6x + 14
8x - 6x = 6x + 14 - 6x
2x = 14
2x/2 = 14/2
x = 7
A submarine is 1000 feet below sea level and then rises 450 feet. Where is the submarine now?
Sea level is 0
1000 feet below sea level would be -1000. It rises 450 feet. Add 450 to -1000:
-1000 + 450 = -550
The submarine is at -550 feet ( 550 feet below sea level).
if M ABD =75 and M abc =40 then m CBD =
round 6.7 to the nearest whole number.
What is 10 by the power of 8
Answer:
100000000
Step-by-step explanation:
10^1=10
10^2=100
10^3=1000
10^4=10000
10^5=100000
10^6=1000000
10^7=10000000
10^8=100000000
Write the number in standard form.
ninety-two billion, seventy thousand,
one hundred eight
92.000.070.108
Step-by-step explanation:
Thousand has 3 zeros, a million has 6 and a billion has 9.
So for ninety-two billion, you take 92 and add 9 zeros behind it because a billion has 9 zeros
(92.000.000.000)
Please help me solve that question
Step-by-step explanation:
steps are in picture above.
if you need to ask questions I'll give you answers gladly.
Solve the equation 12v+10v+14=80
Answer:V=3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
12v+10v+14=80
(12v+10v)+(14)=80
(Combine Like Terms)
22v+14=80
22v+14=80
Step 2: Subtract 14 from both sides.
22v+14−14=80−14
22v=66
Step 3: Divide both sides by 22.
22v/22=66/22
V=3
:)
Ruben needs to read 4 novels each month let N be the number of novels Ruben needs to read in M months write an equation relating in to M
Answer:
Step-by-step explanation:
N = 4(12) = 48 novels
Solve the inequality for t. 12 >t+3 Simplify your answer as much as possible
Answer:
t < 9
Step-by-step explanation:
12 > t + 3
We can subtract 3 from both sides getting us 9 > t.
a bakery sells 17 cups of coffee for every 3 cups of hot chocolate they sell. At the end of the day the bakery sold 406 more coffee than hot chocolates. How many of the two drinks did they sell in all?
Answer:
Step-by-step explanation:
The quotient c and -19 is 38
Answer:
c = 722
Step-by-step explanation:
-19/c = 38
c = 38 x 19 (positive)
c = 722
hope it helped !
Factor x^2+x+6
Plz help
Answer:
2
Step-by-step explanation:
A motorboat travels 116 kilometers in 4 hours going upstream. It travels 164 kilometers going downstream in the same amount of time. What is the rate of the
boat in still water and what is the rate of the current?
Rate of the boat in still water:
Rate of the current:
9514 1404 393
Answer:
boat: 35 km/hcurrent: 6 km/hStep-by-step explanation:
Let b and c represent the rates of the boat and current, respectively. Then the upstream rate is ...
speed = distance/time
b -c = (116 km)/(4 h) = 29 km/h
b +c = (164 km)/(4 h) = 41 km/h
Adding these equations gives ...
2b = 70 km/h
b = 35 km/h
Substituting into the first equation, we have ...
35 -c = 29
c = 6
Rate of the boat: 35 km/h.
Rate of the current: 6 km/h
helpppppppppppppopnanannsnsnnsnakaknfnsn
Step-by-step explanation:
y=107(vertically opposite angles)
x=180-107=73(angles on a straight line)
z=73(vertically opposite angles)
Answer:
[tex]{ \sf{y = 107 \degree}} \: \{ \sf{alternate \: angles} \}[/tex]
[tex]{ \sf{z + 107 \degree = 180 \degree}} \: \{ \sf{straight \: line \: angles \}} \\ z = 180\degree - 107\degree \\ z = 73\degree[/tex]
[tex]{ \sf{x = z}} \: \{ \sf{alternate \: angle \}} \\ x = 73\degree[/tex]
how many feet is 2160 yards?
2. The product of 7 and a number
I think the answer you are looking for is 7n, which also means 7 times n.
Answer:
7x
Step-by-step explanation:
Product refers to multiplication. "A number" refers to an unknown number otherwise known as a variable. In this case, I use x.
P- 24000 R-10% T-2 years find the sum
Answer:
here
I =p×t×r/100
= 24000×2×10/100
= 4800
again,
sum = p+I
= 24000+4800
= 28800
Evaluate: 24 - ( 5 - 3)^ 4
______________
4
24 - (5 - 3)⁴ = 24 - 2⁴ = 24 - 16 = 8
8 : 4 = 2 ← the end solution
What is the solution to the system of equations below?
4x-2y=10
y=-2x-5
show your work! :)
Answer:
(0,-5)
Step-by-step explanation:
4x-2(-2x-5)+10
x=0
y=-2*0-5
y=-5
Two trains leave towns 1285 kilometers apart at the same time and traveled towards each other. One train travels 17 km/h faster than the other. If they meet in 5 hours what is the rate of each train
Distance = (Rate)(Time)
Let x = speed of slower train
x + 17 = speed of faster train
The trains meet when the sum of the distances = 1285
5x + 5(x+17) = 1285
(5 came from 5 hours)
10x + 85 = 1285
10x = 1200
x = 120 mph
The speeds are 120 mph and 137 mph
wyzant
9(y-4) -3y = 2(3y-2 need solved as fast as possible
Step-by-step explanation:
did you give us all the information ? the equating looks cut off.
so, from what I can see we have
9(y-4) - 3y = 2(3y-2)
let's try :
9y - 36 - 3y = 6y - 4
0 = 32
so, no, this can't be it. this does not have a solution. you must have cut off some additional information.
pls help im a little bit sтuрid
Step-by-step explanation:
a⁴+16a²b-2ab-a²+64b²-b²we can also write them as,
a⁴+16a²b+64b²-a²-2ab-b²Now, from -a²-2ab-b² if we take - as common term then we get,
a⁴+16a²b+64b²-(a²+2ab+b²)Now, by using the concept of a²+2ab+b²=(a+b)²
(a²)²+2×a²×8b+(8b)²-{(a)²+2×a×b+(b)²}(a²+8b)²-(a+b)²I hope it helped U
stay safe stay happy
Write an equation in slope-intercept form of the line passing through (0, 3) and (2, -1).
y=2x+3y=2x+3
y=-2x+3y=−2x+3
y=-2xy=−2x
y=-x+3y=−x+3
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]y = -2x + 3[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Slope-Intercept Form Is:}}\\\\y=mx + b\\---------------\\\boxed{\text{Key:}}\\\\m - slope\\b - y-intercept\\---------------\\\boxed{\text{\underline{Known Information:}}}\\\\\rightarrow \text{We are given the points: } (0,3) \text{ and } (2, -1)\\---------------\\\boxed[/tex]
[tex]\boxed{\text{\underline{Y-Intercept:}}}\\\\\rightarrow \text{Since the line passes at point (0, 3), the y-intercept would be 3.}\\---------------\\\boxed{\text{\underline{Slope:}}}\\\\\rightarrow m =\frac{rise}{run}=\frac{y_2-y_1}{x_2-x_1} \\\\\rightarrow m = \frac{-1-3}{2-0}=\frac{-4}{2}=\boxed{-2}\\\\\text{The slope is: } \boxed{-2}\\---------------[/tex]
[tex]\boxed{\text{\underline{Equation:}}}\\\\\text{Our equation should be:}\\\\y = -2x + 3[/tex]
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»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
99. Savings Bronwyn wants to buy a house, so she has decided
to save one quarter of her salary. Bronwyn earns $47.00 per hour
and receives an extra $28.00 a week because she declined
company benefits. She wants to save at least $550.00 each week.
How many hours must she work each week to achieve her goal?
Answer:
46.5 hours per week
Step-by-step explanation:
At least 550 a week.
Which is 1\4 of Bronwyn salary.
550 x 4 = 2200
To find minimum work hours
2200-28 = 2172
2172 \ 47 = 46.212 hours per week
So, bronwyn needs to work at least 46.5 hours per week
Answer:
Bronwyn must work nearly 47 hours each week to achieve her goal.
Step-by-step explanation:
Let x be the number of hours Bronwyn works per week.
If Bronwyn earns $47 per hour, if x is the number of hours she works per week and if Bronwyn earns $28 per week because she declined company benefits, lets assume that the left hand side of the equation is:
[tex]47x + 28[/tex]
Now onto the salary. Since Bronwyn wants to save $550 each week and since she also wants to save one quarter of her salary, her salary becomes $2200 for each week she works
Making the equation...
[tex]47x + 28 = 2200[/tex]
Time to solve for x
[tex]47x = -28 + 2200\\47x = 2172\\x = 46.2[/tex]
Since its at least, you can round it up to 47 making 47 the number of hours she must work each week to achieve her goal.
Let the (x; y) coordinates represent locations on the ground. The height h of
a particle is governed by the function described below. Classify all the critical
points of height and find the value(s) of height h at those points.
h(x; y) = 8x + 10y - 4xy - 4x^2 - 4y^3
The critical points of h(x,y) occur wherever its partial derivatives [tex]h_x[/tex] and [tex]h_y[/tex] vanish simultaneously. We have
[tex]h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5[/tex]
Substitute y in the second equation and solve for x, then for y :
[tex]2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}[/tex]
This is to say there are two critical points,
[tex](x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)[/tex]
To classify these critical points, we carry out the second partial derivative test. h(x,y) has Hessian
[tex]H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}[/tex]
whose determinant is [tex]192y-16[/tex]. Now,
• if the Hessian determinant is negative at a given critical point, then you have a saddle point
• if both the determinant and [tex]h_{xx}[/tex] are positive at the point, then it's a local minimum
• if the determinant is positive and [tex]h_{xx}[/tex] is negative, then it's a local maximum
• otherwise the test fails
We have
[tex]\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0[/tex]
while
[tex]\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0[/tex]
So, we end up with
[tex]h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}[/tex]