How does Brake system work

Improvements to brake systems are

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Answer:

1. Battery

2. Light bulb

3. Toaster

Explanation:

An electrical device is a device that produces or is powered by electricity.

Answer:

All of the above

Explanation:

Answer:

a method of research in which a problem is identified, relevant data are gathered, a hypothesis is formulated from these data, and the hypothesis is empirically tested.

Answer:

Answer is "Increasing the number of base stations & reusing the channels"

Explanation:

Answer:

radio capacity may be increased in cellular concept by increasing the number of base stations and reusing the channels.

Answer:

what's the question?...........

Answer:

option e is correct answer

Explanation:

the answer is in picture

Answer:

business operation Manager

Answer:

jwjehevrvbdbejd HB dbnwjsishrb t bxjwbkozkwnwn shxvbebhgvevhehjhr. jebn

Answer:

Astro Teller oversees X, Alphabet's moonshot factory for building magical, audacious ideas that can solve concrete problems for millions of people through science and technology. As X's head, Teller has an unmatched vantage point from which to watch possible futures unfold.

Explanation:

hope it helps !!

ss mark me as BRAINLIST

Answer:

ill help'

Explanation:

Answer:

I'm pretty sure it's c but i may be wrong

[tex] \huge{ \underbrace{ \overbrace{OPTIONS}}}[/tex]

[tex] \huge{ \underbrace{ \overbrace{PlEASE}}}[/tex]

(40) It looks like the line integral is

[tex]\displaystyle \int_C (x^2-2xy)\,\mathrm dx + (x^2y+3)\,\mathrm dy[/tex]

where C is the boundary of the region D,

[tex]D = \left\{(x,y) \mid \dfrac{y^2}8\le x\le2\text{ and }-4\le y\le4\right\}[/tex]

(a) To evaluate the line integral directly, split up C into two paths C₁ and C₂, parameterized by

• C₁ : x = t ²/8 and y = -t, where -4 ≤ t ≤ 4

(the y component is negative to make this path have a positive/counterclockwise orientation)

• C₂ : x = 2 and y = t, where -4 ≤ t ≤ 4

Then the line integral over C is the sum of the line integrals over C₁ and C₂ :

[tex]\displaystyle \int_C = \int_C \left(\left(x(t)^2-2x(t)y(t)\right)\dfrac{\mathrm dx}{\mathrm dt} + \left(x(t)^2y(t)-3\right)\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_{-4}^4 \left(\left(\frac{t^3}4+\frac{t^4}{64}\right)\frac t4 - \left(3-\frac{t^5}{64}\right)\right)\,\mathrm dt + \int_{-4}^4 (4t+3)\,\mathrm dt \\\\ = \int_{-4}^4 \left(4t+\dfrac{t^4}{16}+\dfrac{5t^5}{256}\right)\,\mathrm dt = \boxed{\frac{128}5}[/tex]

(b) Using Green's theorem, we have

[tex]\displaystyle \int_C (x^2-2xy)\,\mathrm dx + (x^2+3)\,\mathrm dy = \iint_D \frac{\partial(x^2y+3)}{\partial x} - \frac{\partial(x^2-2xy)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_{-4}^4 \int_{y^2/8}^2 (2xy+2x)\,\mathrm dx\,\mathrm dy = \boxed{\frac{128}5}[/tex]

# # #

(41) I assume you meant to use θ in the parameterization, and not 6, so that C is parameterized by x = θ - sin(θ) and y = 1 - cos(θ). There's no range given for θ, so I'll just assume 0 ≤ θ ≤ π.

Then ... (for some reason, the math text won't render properly. I've attached the computation as an image)

(where s = sin(θ) and c = cos(θ))

Answer:

The condition in which a problem exists

Explanation:

Context is the situation surrounding information, e.g. if you don't understand a word in a passge you can look for "context clues" where you use surrounding words to infer the meaning of the unknown one

Answer:

can u write it in English

Explanation:

can't understand it

(a)

11001.1011₂ = 1×2⁴ + 1×2³ + 1×2⁰ + 1×2 ⁻¹ + 1×2 ⁻³ + 1×2 ⁻⁴

… = 16 + 8 + 1 + 1/2 + 1/8 + 1/16

… = 411/16

(b) In base 16, we have A₁₆ = 10 and C₁₆ = 12, so

A3.C₁₆ = 10×16¹ + 3×16⁰ + 12×16 ⁻¹

… = 160 + 3 + 12/16

… = 2620/16 = 655/4

(c)

75.16₈ = 7×8¹ + 5×8⁰ + 1×8 ⁻¹ + 6×8 ⁻²

… = 56 + 5 + 1/8 + 6/64

… = 3918/64 = 1959/32

(d) B₁₆ = 11 and D₁₆ = 13, so

ABCD₁₆ = 10×16³ + 11×16² + 12×16¹ + 13×16⁰

… = 40960 + 2816 + 192 + 13

… = 43981

Answer:

The resistance of the flow of charges in an electric circuit (electrical resistance) is analogous to the frictional effect between water flow through a pipe and the pipe's surface

Explanation:

In comparison to its similarity to the diameter of the pipe affects the flow of water and acts a a factor affecting resistance so are there factors affecting electrical resistance.

in an electrical circuit:

the total length of the wire is to the length of a pipe of water

the cross-sectional area of the wire is to the diameter of a pipe of water.

Thus, the cross sectional are affects the amount of electrical resistance. Wider wires have wider cross-sectional area and vice versa. Also, water will flow (i.e. current) through a wider pipe (i.e. large diameter) at a faster rate than a narrow pipe (i.e. small diameter). This is due to the lower amount of resistance offered by the wider pipe.

in the same manner, the wider the wire, the lesser the electrical resistance to the flow of elsctric charge and vice versa for thiner wires.

Answer:

mooji udaanaamii!!!

Explanation:

Answer:

7500kg/mm

Explanation:

Answer:

Trade association.

Explanation:

I'm thinking it is as it represents contractors who design, install, inspect and maintain amongst other activities electrical and electronic equipments or service.

Answer:

Tech A

Explanation:

Answer:

B

Explanation:

Answer:

The signal person is like the eyes and the equipment operator is like the hands.

Explanation:

Explanation:

Geometric Shapes can be defined as figure or area closed by a boundary which is created by combining the specific amount of curves, points, and lines.

Answer:

Engineers work in teams to design and implement various products using specific processes.

Engineers work in teams to design and implement various products using specific processes. The correct option is A.

An engineer is a person who designs, builds, and maintains machinery and structures like bridges, railroads, and highways using scientific knowledge.

The word engineer, from which the term engineering is derived, was first used in 1390 to refer to "a constructor of military engines." The term engine'er literally means "one who operates an engine."

In this now-outdated meaning, the term "engine" refers to a military machine, or a mechanical device employed in battle.

An engineer is someone who practices engineering, and those who are qualified to do so may hold more official titles like "Designated Engineering Representative," "Professional Engineer," "Chartered Engineer," "Incorporated Engineer," "Ingenieur," or "European Engineer."

Teams of engineers design and deploy various goods utilizing predetermined procedures.

Thus, the correct option is A.

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