Hey- can someone help me with theese 2 questions- i did them yestr and it said that they were wrong?

PEQ has a value of y of 60°.

The Sum of Angles property states that the sum of a polygon's internal angles is equal to (n - 2) times 180 degrees, where n is the number of sides.The polygon's s.

What is angle sum property?

The angle sum property in geometry asserts that the sum of a polygon's internal angles is equal to (n - 2) times 180 degrees, where n is the number of sides of the polygon.

In a triangle (n=3), for example, the total of the interior angles is (3 - 2) 180 = 1 180 = 180 degrees.

The sum of internal angles for a quadrilateral (n=4) equals (4 - 2) 180 = 2 180 = 360 degrees.

This is a fundamental geometric idea that can be used to calculate the value of an unknown interior angle in a polygon if the other interior angles are known. It can also be used to determine whether or not a given set of angles can create a valid polygon.

In PEQ, the angle sum attribute is used.

Hence, EPQ + EQP + PEQ = 180°

40° + 80° + y = 180°

120° + y = 180°

y = 180° - 120°

y = 60°

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The perimeter to the nearest tenth, we get: Perimeter ≈ 18.4 units.

What is perimeter?

We can start by using the Pythagorean theorem to find the length of AC:

AC² = AB² + BC²

AC² = 2² + 1.5²

AC² = 4.25

AC = √(4.25)

AC ≈ 2.06 units

Next, we can use the fact that AC is common to both triangles to find the length of CD:

ACD is a right triangle, so we can use the Pythagorean theorem:

CD² = AD² - AC²

CD² = 6.5² - 2.06²

CD² ≈ 39.86

CD ≈ 6.31 units

Now we can find the perimeter of the figure by adding the lengths of all three sides:

Perimeter = AB + BC + CD + DA + AC

Perimeter = 2 + 1.5 + 6.31 + 6.5 + 2.06

Perimeter ≈ 18.37 units

Therefore, none of the given options is the correct answer. However, if we round the perimeter to the nearest tenth, we get:

Perimeter ≈ 18.4 units

And the closest option to this value is option 3) 16 units, which is not very close. Therefore, we can conclude that none of the given options is a correct approximation of the perimeter of the figure.

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Ike ran 12 miles and Gus ran 36 miles based on equation solving.

Assume that x is a representation of Ike's running distance. Gus ran three times as far as Ike, so his distance was three times Ike's.

Gus and Ike travelled a total of 48 miles, as far as we know. Thus, we can create the following equation:

x + 3x = 48

When we simplify this equation, we obtain:

4x = 48

When we multiply both sides by 4, we get:

x = 12

Ike afterwards ran 12 kilometres.

To confirm, we may calculate Gus's running distance by dividing Ike's distance by three:

3x = 3(12) = 36

And we can confirm that the total of their separations is 48:

12 + 36 = 48

Gus ran 36 miles while Ike ran 12 miles.

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Answer:

No, a non-complex equation cannot have 2 horizontal asymptotes. By definition, a horizontal asymptote is a horizontal line that the function approaches as x goes to positive or negative infinity. If there were two horizontal asymptotes, the function would have to approach two different horizontal lines as x goes to infinity, which is not possible for a single-valued function.

Similarly, a non-complex equation cannot have 2 vertical asymptotes. A vertical asymptote is a vertical line where the function approaches infinity or negative infinity as x approaches the line from either side. If there were two vertical asymptotes, the function would have to approach infinity or negative infinity as x approaches each line, which is not possible for a single-valued function.

Using a complex number as x does not change the behavior of asymptotes. If a function has a vertical asymptote at a real number, it will still have a vertical asymptote at that number when x is a complex number. Similarly, if a function has a horizontal asymptote, it will still have a horizontal asymptote when x is a complex number.

However, if a function has a vertical asymptote at a complex number, it may behave differently depending on the direction in which x approaches the asymptote. If the function approaches different values as x approaches the asymptote from different directions, then the function may not have a limit at the complex number and may not have a vertical asymptote. Similarly, if a function has a horizontal asymptote and is not defined for complex values of x, then it may not have a limit at infinity and may not have a horizontal asymptote.

Step-by-step explanation:

Answer:

the value of what you lose when you choose from two or more alternatives

Step-by-step explanation:

The solution to the equation 1 is p = -7. and the only solution to the   equation2  is k = 2.

what is  equation?

An equation is a mathematical statement that asserts the equality of two expressions. It usually contains one or more variables (letters that represent unknown values) and an equal sign. The goal of solving an equation is to find the values of the variables that make the equation true.

In the given question,

Starting with -49 = -7√(p+8):

Dividing both sides by -7, we get:

7√(p+8) = 7

Dividing both sides by 7, we get:

√(p+8) = 1

Squaring both sides, we get:

p+8 = 1

Subtracting 8 from both sides, we get:

p = -7

Therefore, the solution to the equation is p = -7.

Starting with √(6-k) = k:

Squaring both sides, we get:

6-k = k²

Rearranging, we get:

k²+ k - 6 = 0

We can factor this quadratic equation as:

(k+3)(k-2) = 0

Therefore, the solutions to the equation are:

k+3 = 0 or k-2 = 0

Solving for k, we get:

k = -3 or k = 2

However, we need to check whether these solutions satisfy the original equation, since we squared both sides and introduced extraneous solutions:

When k = -3:

√(6-k) = √(6-(-3)) = √9 = 3

k = -3 is not a solution.

When k = 2:

√(6-k) = √(6-2) = √4 = 2

k = 2 is a solution.

Therefore, the only solution to the equation is k = 2.

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Answer:

$100 for air conditioning and $40 for water heater

Step-by-step explanation:

$200÷2= 100

200÷5= 40

As x approaches positive infinity, f(x) approaches positive infinity.

In algebra, an absolute value function is a function where the variable is inside the bars denoting absolute values. The absolute value function is also known as the modulus function, and its most popular representation is f(x) = |x|, where x is a real number.

Here,

We have to find the end behavior of this absolute value function.

In the graph, it is shown that the absolute value function has a maximum of 3 at x = 3.

The function f(x) reaches positive infinity in both cases when x reaches either minimum or maximum value.

Hence, As x approaches positive infinity, f(x) approaches positive infinity.

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Answer:

[tex]( x + 2 )^{2} +(y-15)^{2} =9[/tex]

Hope this helps!

Step-by-step explanation:

Answer:

Point K

Step-by-step explanation:

Which Point represents the ordered pair

( -4[tex]\frac{1}{2}[/tex], -1)

Left -4[tex]\frac{1}{2}[/tex] we have points J and K

Down -1 we have point K

So, the answer is point K

The controllability and observability matrices of the given state-space equation were calculated, but no set of bij and Cij was found to make the system controllable or observable. Therefore, the system is not controllable or observable.

To determine whether the given state-space equation is controllable and observable, we need to check the controllability and observability matrices.

The controllability matrix is given by:

[ B AB A^2B A^3B A^4B ]

where A and B are the state and input matrices, respectively.

The observability matrix is given by:

[ C ]

[ CA ]

[ CA^2 ]

[ CA^3 ]

[ CA^4 ]

where C is the output matrix.

Using the given state-space equation, we can calculate the controllability and observability matrices as follows:

A = [ 1 0 0 0 0 ]

   [ L0 1 0 0 1 ]

   [ b12 1 0 0 0 ]

   [ 0 0 1 0 0 ]

   [ b21 bzz 0 1 1-L ]

B = [ 0 ]

   [ 0 ]

   [ 0 ]

   [ 0 ]

   [ 1 ]

C = [ 1 0 0 0 0 ]

   [ 0 1 0 0 0 ]

   [ 0 0 1 0 0 ]

Controllability Matrix:

[ B AB A^2B A^3B A^4B ] =

[ 0 0 0 0 1 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]        

[ 0 0 0 0 0 ]

[ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]        

[ 0 0 0 0 0 ]

[ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]        

[ 0 0 0 0 0 ]

[ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          

[ 0 0 0 0 0 ]

[ 0 bzz b21bzz 0 Lb51 ] [ 0 L0 b12bzz Lb51 0 ] [ L0 b12bzz L0b21bzz 0 0 ]

[ b12bzz 0 L0b21bzz 0 0 ] [ 0 0 L0b12bzz 0 0 ]

Observability Matrix:

[ 1 0 0 0 0 ] [ 1 0 0 0 0 ] [ 1 0 0 0 0 ] [ 1 0 0 0 0 ] [ 1 0 0 0 0 ]

[ 0 1 0 0 0 ] [ 0 L0 1 b12 1 ] [ L0 b12bzz L0b21bzz 0 0 ] [ b12bzz 0 L0bb21bzz 0 0 ]

To elaborate on the solution, the controllability matrix shows that some of the columns are linearly dependent on the others, which means that it is not possible to find a set of inputs that can steer the system from any initial state to any desired state in finite time. Similarly, the observability matrix shows that some of the rows are linearly dependent on the others, which means that it is not possible to uniquely determine the state of the system from the output measurements.

Therefore, the system is not controllable or observable, and it cannot be controlled or accurately estimated using the given state-space equation.

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--The given question is incomplete, the complete question is given

" Is it possible to find a set of bij and a set of Cij such that the following state-space equation is controllable? Observable? (If the answer is yes, find a set) i(t) = 1 0 0 0 LO 1 0 0 01 5611 b12 1 0 0 0 |b21 bzz 0 1 1 0 X(t) + b31 b32|u(t) 0 0 1 0 | b41 buz 0 0 0 1- Lb51 652 [C11 y(t) = C21 C31 C12 C22 C32 C13 C23 C33 C14 C24 C34 C15 C25 x(t) C35

According to the given question the correct option  is (D) which is 84 and 6/7 square inches.

Surface area is indeed a measurement of how much overall space an object occupies. A three-dimensional shape's surface area is the sum of the area surrounding it. The term "surface area" refers to a three-dimensional shape's overall surface area. The surface area of a cuboid with six rectangular faces can be calculated by adding the areas from every face. As an alternative, you can name the dimensions of this box using the formula below: 2lh, 2lw, with 2hw make up the surface area (SA). Surface area is a unit used to describe how much space a three-dimensional form's surface takes up overall.

Given,

The formula: can be used to determine a cylinder's surface area.

surface area = 2πr^2 + 2πrh

where r is the cylinder's radius and h seems to be the cylinder's height.

In this case, the diameter of the mini muffins is 2 inches, so the radius is 1 inch. The height is 1 and 1/4 inches. When these values are added toward the formula, we obtain:

surface area = 2π(1^2) + 2π(1)(5/4) = 2π + 5π/2 = 9π/2

To find the amount of paper needed to wrap 6 mini muffins, we multiply the surface area of one mini muffin by 6:

6 × (9π/2) = 27π

Approximating π as 22/7, we get:

27π ≈ 27 × 22/7 = 84 and 6/7

Therefore, the answer is (D) 84 and 6/7 square inches.

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a. The z-table, the probability that a sample mean will be within 0.02 of the population mean is:

P(-0.02/0.00416 < Z < 0.02/0.00416) = P(-4.81 < Z < 4.81) = 0.9999

b. The probability of obtaining a sample mean that is close to the population mean increases as the sample size increases. This means that larger sample sizes provide more accurate estimates of the population mean.

a. We can use the formula for the standard error of the mean:

SE = σ/√n

where σ is the population standard deviation, n is the sample size, and SE is the standard error.

For a sample size of n = 25:

SE = 0.0588/√25 = 0.01176

Using the z-table, the probability that a sample mean will be within 0.02 of the population mean is:

P(-0.02/0.01176 < Z < 0.02/0.01176) = P(-1.70 < Z < 1.70) = 0.9045

For a sample size of n = 50:

SE = 0.0588/√50 = 0.00832

Using the z-table, the probability that a sample mean will be within 0.02 of the population mean is:

P(-0.02/0.00832 < Z < 0.02/0.00832) = P(-2.41 < Z < 2.41) = 0.9872

For a sample size of n = 100:

SE = 0.0588/√100 = 0.00588

Using the z-table, the probability that a sample mean will be within 0.02 of the population mean is:

P(-0.02/0.00588 < Z < 0.02/0.00588) = P(-3.40 < Z < 3.40) = 0.9984

For a sample size of n = 200:

SE = 0.0588/√200 = 0.00416

Using the z-table, the probability that a sample mean will be within 0.02 of the population mean is:

P(-0.02/0.00416 < Z < 0.02/0.00416) = P(-4.81 < Z < 4.81) = 0.9999

b. The advantage of a larger sample size is that it leads to a smaller standard error of the mean, which means that the distribution of sample means is narrower and more closely centered around the population mean. As a result, the probability of obtaining a sample mean that is close to the population mean increases as the sample size increases. This means that larger sample sizes provide more accurate estimates of the population mean.

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Answer: To find the value of the car after 8 years, we can use the given information to create a linear equation in the form:

y - y1 = m(x - x1)

Where:

y is the value of the car after 8 years (what we want to find)

y1 is the value of the car after a given time (either 3 or 5 years)

x is the given time (either 3 or 5 years)

x1 is the starting time (when the car was purchased)

m is the rate of decrease (slope of the line)

We can use the two given data points to find the slope of the line:

m = (y2 - y1) / (x2 - x1)

m = (11,000 - 15,000) / (5 - 3)

m = -2,000 per year

Now, we can use one of the data points to solve for the y-intercept of the line:

y - y1 = m(x - x1)

y - 15,000 = (-2,000)(3 - x1)

y - 15,000 = (-2,000)(3 - x1)

y - 15,000 = (-6,000 + 2,000x1)

y = 2,000x1 - 6,000 + 15,000

y = 2,000x1 + 9,000

So the linear equation that represents the value of the car after x years is:

y - 15,000 = (-2,000)(x - 3)

Simplifying this equation gives:

y - 15,000 = -2,000x + 6,000

Now, we can use x = 8 to find the value of y:

y - 15,000 = -2,000(8) + 6,000

y - 15,000 = -2,000

y = $13,000

Therefore, the value of the car after 8 years will be $13,000.

So the completed expression is:

y - 15,000 = -2,000(x - 3)

The value of the car after 8 years will be $13,000.

Step-by-step explanation:

The sum of the angles in triangle MNP is 180, and subtracting 135 from both sides gives 45 degrees. With the angle sum property of triangle, ∠MNP = 121°.

An angle is the result of the intersection of two lines.

An "angle" is the length of the "opening" between these two beams.

Angles are commonly measured in degrees and radians, a measurement of circularity or rotation.

In geometry, an angle can be created by joining the extremities of two rays. These rays are intended to represent the angle's sides or limbs.

The two primary components of an angle are the limbs and the vertex.

The joint vertex is the common terminal of the two beams.

According to the given question,

45° + 90° + ∠MNP = 180°

135° + ∠MNP = 180°

∠MNP = 45°

Hence, With the angle sum property of triangle, ∠MNP = 121°.

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Answer:

What is a mean?

A mean is the average of all the numbers in a data set.

How can I find mean?

to find mean you add up all the numbers in the data set; and divide them by the amount of numbers there are.

103+3+41+7=154

154÷4=38.5

The mean is 38.5

Answer:

[tex]t^{4}[/tex] + 8[tex]t^{2}[/tex] + 8t - 12

Hope this helps!

Step-by-step explanation:

[tex]t^{4}[/tex] - 1.5[tex]t^{2}[/tex] + t - 12 + 9.5[tex]t^{2}[/tex] + 7t : Combine like terms

[tex]t^{4}[/tex] + ( 9.5 - 1.5 )[tex]t^{2}[/tex] + ( 7t + t ) - 12

[tex]t^{4}[/tex] + 8[tex]t^{2}[/tex] + 8t - 12

Answer:

Step-by-step explanation:

a.

3:  Area = 3² = 9

100:  Area = 100² = 10,000

25:  Area = 25² = 625

s:  Area = s²

b.

Yes, the relationship is proportional.  The area of the square is the length of a side squared.  Area = (length)²

Answer: 6.85%

Step-by-step explanation:

Answer: 0.098 is the answer

Step-by-step explanation:

The important to select the appropriate value of alpha based on the characteristics of the data and the goals of the forecasting model.

The statement "for a time series for simple exponential smoothing, a larger alpha is smoother than a shorter period" is true.

In simple exponential smoothing, the forecast for the next period is based on the previous forecast and the difference between the actual value and the previous forecast. The smoothing parameter alpha controls the weight given to the most recent observation compared to the previous forecasts.
A larger alpha places more weight on the most recent observation, resulting in a forecast that is more responsive to recent changes in the data. As a result, the forecast will exhibit less volatility or variability, making it smoother. This means that a larger alpha will lead to a more stable forecast with less fluctuation around the trend.
On the other hand, a smaller alpha places less weight on the most recent observation, resulting in a forecast that is less responsive to recent changes in the data.

As a result, the forecast will be more volatile or variable, making it less smooth. This means that a smaller alpha will lead to a forecast that is more susceptible to fluctuations around the trend.
In summary, the choice of alpha is a trade-off between stability and responsiveness to changes in the data. A larger alpha will lead to a smoother forecast, while a smaller alpha will lead to a more volatile forecast.

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The design is a randomized controlled trial (RCT), where participants are randomly assigned to treatment groups and tested on the dependent variable once to control for confounding variables and ensure that differences observed between groups are due to the treatment.

The type of design you are referring to is a randomized between-subjects design, also known as a randomized controlled trial (RCT). In this type of experiment, participants are randomly assigned to one of two or more treatment groups, each receiving a different level or type of the independent variable. Then, the dependent variable is measured only once after the treatment is administered. The purpose of this design is to control for potential confounding variables and to ensure that any differences observed between groups are due to the treatment and not to other factors.

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The rate of change (slope) for a linear relationship can be found by taking the difference in the y-values divided by the difference in the corresponding x-values.

In this case, the change in y from x=1 to x=9 is 32-8=24, and the change in x is 9-1=8. Therefore, the rate of change is:

rate of change = (change in y) / (change in x) = 24/8 = 3

So the answer is A. 3.

The change of base formula is:  log_b(x) = log_a(x) / log_a(b)

The term "change of base" refers to the process of converting a logarithm from one base to another. A logarithm is an exponent that indicates the power to which a base must be raised to obtain a given number. The most common logarithmic bases are 10, e (Euler's number), and 2, but logarithms can be taken to any base.

The change of base formula is a mathematical formula that allows you to convert logarithms from one base to another. It is useful when you need to calculate logarithms that cannot be easily evaluated on a calculator or when you need to work with logarithms in different bases.

The change of base formula is:

log_b(x) = log_a(x) / log_a(b)

Where:

log_b(x) is the logarithm of x to the base b

log_a(x) is the logarithm of x to the base a

log_a(b) is the logarithm of b to the base a

To use the change of base formula, you first need to identify the base of the logarithm that you want to convert and the base that you want to convert it to. Then, you can plug the values into the formula and simplify the expression.

For example, let's say you want to convert log_2(8) to base 10. Using the change of base formula, you can write:

log_2(8) = log_10(8) / log_10(2)

To evaluate this expression, you can use a calculator to find that:

log_10(8) = 0.9031

log_10(2) = 0.3010

Substituting these values into the formula gives:

log_2(8) = 0.9031 / 0.3010

Simplifying this expression gives:

log_2(8) = 3

Therefore, log_2(8) is equal to 3 when evaluated in base 10.

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Using the bar graph we can conclude that it rained 0.5 inches more in the summer of 2010 than in 2009.

Using rectangular bars that are proportional to the values they represent; a bar graph displays all the data. The graph's bars can be displayed either vertically or horizontally. Bar graphs, commonly referred to as bar charts, are a visual depiction of groups of data. It is one method of processing data. A bar graph is a great tool for representing data that are unrelated to one another and do not need to be displayed in any particular sequence. The bars provide a visual representation for comparing amounts in several categories. Together with the title, labels, and scale range, bar graphs have two axes that are horizontal and vertical and are also known as the x and y axes.

Here in the question,

We can see that in the summer of 2009 the rain was for 1.5 inches.

In the summer of 2010, the rain was for 2 inches.

Hence, the difference between the number of inches it rained=

2 - 1.5

= 0.5 inches.

Therefore, using the bar graph we can conclude that it rained 0.5 inches more in the summer of 2010 than in 2009.

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The length of the missing leg for the right triangle is 16 yd using the Pythagoras rule.

The Pythagoras rule states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. 

Pythagoras rule we can evaluate for b as follows:

65² = 63² + b²

b = √(65² - 63²) {make b the subject}

b = √(4225 - 3969)

b = √256

b = 16

Therefore, the length of the missing leg for the right triangle is 16 yd using the Pythagoras rule.

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Answer:

C ≈ 18.84 cm

Step-by-step explanation:

circumference = π · diameter

We can plug the given diameter into this formula, approximating π as 3.14.

C = 3.14 · 6 cm

C ≈ 18.84 cm

We know that,

[tex] \bf \leadsto Radius = Diameter / 2[/tex]

So,

[tex] \rightarrow \: \sf \: Radius = \frac{6}{3} \\ \\ \rightarrow \: \sf \: Radius = 3[/tex]

[tex] \rule{140pt}{5pt}[/tex]

Now,

[tex] \bf \bigstar \: Circumference \: of \: circle = 2πr[/tex]

[tex]→ \sf \: 2 × 3.14 × 3 \\ \\ → \sf \: 6 × 3.14[/tex]

[tex] \bf \: 18.84cm[/tex]

Option a is correct

[tex] \underline{ \rule{190pt}{6pt}}[/tex]