Help what's the answer??

The new volume of the balloon outside is approximately 41.8 L.

What is Temperature?

Temperature is a physical quantity that measures the degree of hotness or coldness of an object or a system. It is a measure of the average kinetic energy of the particles (such as atoms and molecules) that make up the object or system. The higher the temperature, the greater the average kinetic energy of the particles, and the hotter the object or system feels.

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas. The equation is:

(P1 × V1) ÷ T1 = (P2 × V2) ÷ T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.

In this case, we can assume that the pressure on the balloon stays constant at exactly 1 ATM. So we can simplify the equation to:

V1 ÷ T1 = V2 ÷ T2

We can now substitute the given values into the equation:

V1 = 45.5 L (initial volume inside the prep shed)

T1 = 9°C + 273.15 = 282.15 K (initial temperature inside the prep shed)

T2 = -14°C + 273.15 = 259.15 K (final temperature outside)

V2 = ?

Now we can solve for V2:

V2 = (V1 × T2) ÷ T1

V2 = (45.5 L × 259.15 K) ÷ 282.15 K

V2 = 41.8 L

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The length of the carbon chain and the types of bonds that connect the carbon atoms in fatty acids are used to categorize them.

A fatty acid is an aliphatic carboxylic acid having a saturated or unsaturated aliphatic chain.

Different fatty acids have different carbon chains (number of carbons in the fatty acid). From 4 and 24 carbon atoms make up the majority of fatty acids, with even numbers (i.e., 8, 18) occuring more commonly than odd ones (i.e. 9, 19).

No carbon-carbon double bonds can be found in saturated fatty acids, while one can be found in monounsaturated fatty acids and two or more can be found in polyunsaturated fatty acids.

The length of the C chain affects how soluble fatty acids are in water. The fatty acid will be harder to dissolve in water the longer the C chain, resulting in a lower solubility rating.

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An acid combined with a strong base will always yield a strongly acidic solution. So the statement (a) is not true.

A strong base is defined as a compound that has an ability to remove a proton from a very weak acid of the reaction. Strong bases completely dissociate into its ions when in water. It is a base which is completely dissociated in an aqueous solution. It is a base which is ionizes completely in an aqueous solution. A weak base is defined as a base that ionizes only slightly of an aqueous solution. When an acid gets combined with a strong base it will always yield a strongly acidic solution not an basic solution.  We know that a strong acid and a strong base when combined in equal amounts they will react to form a neutral solution.

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which of the following is not true of acid-base neutralization? select the correct answer below:

a.  an acid combined with a strong base will always yield a strongly basic solution.

b. a weak acid plus a weak base can yield either an acidic, basic, or neutral solution.

c.  a strong acid and a strong base, combined in equal amounts, will react to form a neutral solution.

d. a strong acid plus a weak base, combined in equal amounts, yields a weakly acidic solution.

This is incomplete question, here is the question.

Most metals used by society are obtained from which group of options: base metals, ore minerals, precious metals, or native metals?

Most metals used are obtained from base metals ore minerals due to their abundance and ease of extraction through mining.

Most metals utilized by society are acquired from base metals mineral minerals. These minerals incorporate copper, zinc, lead, nickel, and tin, which are tracked down in enormous amounts in the World's hull. The extraction interaction includes mining these metals from underground or open-pit mines, trailed by pounding and crushing to set the metal free from the mineral grid.

Synthetic or actual division procedures are then used to confine and refine the metal. Valuable metals, like gold and silver, are additionally acquired from metal minerals, however they are somewhat intriguing and more hard to extricate. Local metals, then again, are tracked down in their unadulterated metallic structure and don't need extraction from mineral minerals.

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Answer:

2 is the rate of chemistry reaction

The kinetic/thermal energy of one mole of CO2 molecules at 37°C is 99.0 kJ.

Thermal energy is the energy that comes from the temperature of an object or its surroundings. It is a form of energy that is released by a substance as a result of its temperature increasing. Thermal energy is the sum of the kinetic and potential energy of the particles that make up a substance.

Kinetic energy is the energy possessed by an object as a result of its motion. It is calculated using the formula KE = 1/2mv2, where m is the mass of the object and v is its velocity. The kinetic energy of an object increases as its velocity or mass increases.

The thermal energy of one mole of CO2 molecules at 37°C can be calculated using the formula: E = nRT, where E is the thermal energy, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

The gas constant R is equal to 8.314 J/mol K.

Converting 37°C to Kelvin, we get: T = 37 + 273 = 310 K

Substituting the values into the formula, we get:E = nRT= (1 mol)(8.314 J/mol K)(310 K)= 2574.94 J/mol

Converting J/mol to kJ/mol, we get:2574.94 J/mol / 1000 = 2.57 kJ/mol

Therefore, the thermal energy of one mole of CO2 molecules at 37°C is 2.57 kJ/mol.

The kinetic energy of one mole of CO2 molecules at 37°C can be calculated using the formula KE = 3/2nRT, where n, R, and T have the same values as before.

Substituting the values into the formula, we get:KE = 3/2nRT= (3/2)(1 mol)(8.314 J/mol K)(310 K)= 3860.41 J/mol

Converting J/mol to kJ/mol, we get:3860.41 J/mol / 1000 = 3.86 kJ/molTherefore, the kinetic energy of one mole of CO2 molecules at 37°C is 3.86 kJ/mol.

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The concentration (molarity) of the solution that contains 38.3 grams of NaCl in 1.5 L of solution is 0.437 M

First, we shall obtain the mole of NaCl. Details below:

Mole = mass / molar mass

Mole of NaCl = 38.3 / 58.5

Mole of NaCl = 0.655 mole

Finally, we shall determine the molarity of the solution. Details below:

Molarity of solution = mole / volume

Molarity of solution = 0.655 / 1.5

Molarity of solution = 0.437 M

Thus, the molarity of the solution is 0.437 M

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1) A formula unit represents the simplest ratio of elements in a (crystal) of an ionic compound.

2) A crystal is made up of: many atoms that are arranged in a regular pattern

3) There are two magnesium ions for every two sulfide ions in magnesium sulfide. The ratio of Mg to S in the formula unit is: 1:1

The proportional proportions of the cations and anions affect the structure of an ionic compound. Salts, oxides, hydroxides, sulfides, and the vast bulk of inorganic compounds are examples of ionic compounds. The electrostatic pull between the positive and negative ions holds together ionic solids.

For instance, sodium ions attract chloride ions, and chloride ions attract sodium ions. Na+ and Cl- ions are arranged alternately to form a three-dimensional framework. This particle is made of sodium chloride. Because there are as many sodium ions as there are chloride ions, the diamond is uncharged. The ions are held in the formations by the forces of attraction between them.

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Answer:

Explanation:

Select the word or phrase from the drop-down menu to describe ionic compounds.

A formula unit represents the simplest ratio of elements in a : ✔ crystal. of an ionic compound.

A crystal is made up of : ✔ many atoms that are arranged in a regular pattern.

There are two magnesium ions for every two sulfide ions in magnesium sulfide. The ratio of Mg to S in the formula unit is : ✔ 1:1.

Butanoic acid has an adjacent carboxyl group that withdraws electron density, making it more readily protonated than butanone.

Both butanoic corrosive and butanone contain a carbonyl gathering, which is an electron-insufficient carbon particle twofold clung to an oxygen molecule. This makes the carbonyl carbon more helpless to nucleophilic assault, including protonation by a solid corrosive.

Nonetheless, butanoic corrosive is more promptly protonated than butanone because of the presence of the neighboring carboxyl gathering. The electronegative oxygen molecule in the carboxyl gathering pulls out electron thickness from the carbonyl oxygen, making it more electron-lacking and subsequently more defenseless to protonation by a solid corrosive. Conversely, butanone misses the mark on extra electron-pulling out bunch, so its carbonyl oxygen is less electron-insufficient and less inclined to be protonated by a solid corrosive.

Generally speaking, the presence of contiguous electron-pulling out gatherings can build the reactivity of carbonyl mixtures towards protonation.

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During the chemical reaction between sulfur and hydrogen chloride, the two substances combine to form a new compound known as sulfur dichloride, which has a chemical formula of SCl₂.

The chemical reaction between sulfur (S) and hydrogen chloride (HCl) results in the formation of hydrogen sulfide (H₂S) and sulfur dioxide (SO₂). The reaction can be represented by the following equation:

S (s) + 2 HCl (g) → H₂S (g) + SO₂ (g)

In this reaction, the sulfur atoms combine with the hydrogen and chlorine atoms from HCl to form H₂S and SO₂. The reaction is exothermic, which means that it releases heat as it proceeds. The reaction also involves the transfer of electrons between the atoms, leading to the formation of new chemical bonds between the atoms. Overall, the chemical reaction between sulfur and hydrogen chloride is a redox reaction, where the oxidation state of sulfur changes from 0 to +4 in SO₂, and the oxidation state of hydrogen changes from +1 to -1 in H₂S.

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Boyle's Law-

[tex]\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}\\[/tex]

(Pressure is inversely proportional to the volume)

Where-

As per question, we are given that -

Now that we have all the required values and we are asked to find out the final volume, so we can put the values and solve for the final volume -

[tex]\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}[/tex]

[tex]\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf 11.5 \times 36= 9.3\times V_2\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2 = \dfrac{11.5 \times 36 }{9.3}\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\longrightarrow \sf V_2 = \cancel{\dfrac{ 414}{9.3}}\\[/tex]

[tex]\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf V_2 =44.5161.....\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\longrightarrow \sf \underline{V_2 = 44.52 \:L }\\[/tex]

Therefore, the volume of the ammonia will become 44.52 L if its pressure is changed to 9.3 kPa while its temperature remains constant.

We need to add 27.3 mL of 1.02 M [tex]HClO_4[/tex] to 1.90 g of imidazole to give a pH of 6.993.

To solve this problem, we need to use the Henderson-Hasselbalch equation:

[tex]pH = pK_a + log(\frac{[A^-]}{[HA]})[/tex]

where pH is the desired pH, pKa is the acid dissociation constant of the acid (in this case, [tex]HClO_4[/tex]), [A-] is the concentration of the conjugate base (in this case, [tex]{ClO_4}^{-}[/tex]), and [HA] is the concentration of the acid (in this case, [tex]HClO_4[/tex]).

We can rearrange the equation to solve for the ratio of [tex][A^-][/tex] to [tex][HA][/tex]:

[tex]\frac{[A^-]}{[HA]} = 10^{(pH - pKa)}[/tex]

We can also use the molecular weight of imidazole to calculate the number of moles of imidazole:

n(imidazole) [tex]= \frac{m}{M}[/tex]

where m is the mass of imidazole and M is its molecular weight.

Once we know the number of moles of imidazole, we can use stoichiometry to calculate the number of moles of [tex]HClO_4[/tex] required to react with all of the imidazole. Since the reaction between [tex]HClO_4[/tex] and imidazole is a 1:1 reaction, the number of moles of [tex]HClO_4[/tex] required is equal to the number of moles of imidazole.

Finally, we can use the molarity of the [tex]HClO_4[/tex] solution to calculate the volume of [tex]HClO_4[/tex] required to supply the required number of moles of [tex]HClO_4[/tex].

Here are the calculations:

Molecular weight of imidazole = 68.08 g/mol

n(imidazole) [tex]= \frac{1.90}{68.08} = 0.0279[/tex] mol

[tex]pK_a[/tex] of [tex]HClO_4[/tex] = -8.0

[tex]\frac{[A^-]}{[HA]} = 10^{(pH - pK_a)} = 10^{(6.993 - (-8.0))} = 1.14 * 10^{14}[/tex]

Since the reaction is a 1:1 reaction, we need 0.0279 mol of [tex]HClO_4[/tex].

Molarity of[tex]HClO_4[/tex] = 1.02 mol/L

Volume of [tex]HClO_4[/tex] = moles / molarity [tex]= \frac{0.0279}{1.02} = 0.0273[/tex] L

Finally, we convert the volume to milliliters:

Volume in mL [tex]= 0.0273*1000 = 27.3[/tex] mL

Therefore, we need to add 27.3 mL of 1.02 M [tex]HClO_4[/tex] to 1.90 g of imidazole to give a pH of 6.993.

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Answer:

14 atoms

Explanation:

To determine the number of atoms in H2C6H6O6, we need to count the total number of each type of atom in the molecule and then add them up. The subscript following each atom in the chemical formula represents the number of atoms of that element in the molecule. So, in H2C6H6O6, there are:

2 atoms of hydrogen (H) 6 atoms of carbon (C) 6 atoms of oxygen (O)

To calculate the total number of atoms, we simply add up these values:

2 + 6 + 6 = 14

Therefore, H2C6H6O6 contains a total of 14 atoms.

The mole ratio of NH3 to H2 is 2:3.

Mole ratio is a term used in chemistry to describe the relative amounts of two or more substances involved in a chemical reaction. It refers to the ratio of the number of moles of one substance to the number of moles of another substance in a chemical reaction.

The mole ratio of NH3 to H2 in the chemical reaction where NH3 and H2 react to form NH3 is:

N2 + 3H2 -> 2NH3

The balanced equation shows that one molecule of N2 reacts with three molecules of H2 to produce two molecules of NH3. Therefore, the mole ratio of NH3 to H2 is 2:3.

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Answer:

The relationship between salinity and light transmittance is that an increase in salinity leads to a decrease in light transmittance. This is because the dissolved salts in water absorb and scatter light, reducing the amount of light that can pass through.

Explanation:

a. CaCO₃ effectively neutralizes excess stomach acid via the reaction: CaCO₃ + 2H⁺ → Ca²⁺ + H₂O + CO₂(g), making it a suitable source for chronic heartburn sufferers.

b. Marble statues erode from acidic precipitation due to a reaction between CaCO₃ and acid: CaCO₃ + H₂SO₄ → CaSO₄ + H₂O + CO₂(g).

c. Mg(OH)₂ antacids are preferred over CaCO₃ antacids due to better neutralization of stomach acid and faster relief of heartburn symptoms from higher solubility.

Calcium carbonate (CaCO₃) can neutralize excess stomach acid and thus provide relief from heartburn symptoms. When calcium carbonate reacts with stomach acid (hydrochloric acid, HCl), it forms calcium chloride (CaCl₂), carbon dioxide (CO₂), and water (H₂O). The net ionic equation for the reaction is:

CaCO₃(s) + 2H⁺(aq) → Ca²⁺(aq) + CO₂(g) + H₂O(l)

The calcium ions can also be absorbed into the bloodstream and contribute to overall calcium intake.

Marble is composed mainly of calcium carbonate (CaCO₃). When exposed to acidic precipitation (such as acid rain), the carbonic acid (H₂CO₃) formed in the reaction between carbon dioxide (CO₂) and water (H₂O) reacts with calcium carbonate, producing calcium ions (Ca²⁺), bicarbonate ions (HCO₃⁻), and water. The bicarbonate ions are then washed away by the rainwater, leaving behind calcium-deficient marble that is more prone to erosion. The chemical reaction can be represented as, CaCO₃(s) + H₂CO₃(aq) → Ca²⁺(aq) + 2HCO₃⁻(aq)

Many people prefer antacids in which magnesium hydroxide (Mg(OH)₂) is the active ingredient over those that use calcium carbonate (CaCO₃) because Mg(OH)₂ has a higher solubility and is more readily absorbed by the body, which means it can neutralize stomach acid more effectively. Additionally, Mg(OH)₂ has a mild laxative effect, which can help relieve constipation, a common side effect of taking calcium carbonate antacids.

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To select the most favorable eluent, which is the best solvent system to elute compound A and B TLC (Thin layer chromatography)  separation technique is used.

It is used to isolate and identify substances from mixtures. It works on the same principle as column chromatography, but it is carried out on a smaller scale. TLC is a simple and quick technique for separating components from a mixture. It is based on the differential adsorption of components onto the adsorbent surface.The most favorable solvent system to elute compound A and B is given as follows;Hexane/ethyl acetate mixture is used to elute the compound A from the mixture, and a solvent system consisting of a higher amount of ethyl acetate and lower amount of hexanes is used to elute compound B.Both components, A and B, have different polarities, and hence, their solubilities are different in various solvents.

The chromatographic separation occurs when one component has higher polarity and adsorbs more readily to the polar adsorbent than another compound with lower polarity. Thus, the ideal solvent system is dependent on the properties of the components that you are separating.

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The entropy change of a sample of 26.7g of Sn in J/K when it melts at 232°C is 0.055 J/K.

We can use the formula ΔS = ΔHfus/T to calculate the entropy change of a sample of Sn as it melts at 232°C, where ΔHfus is the heat of fusion and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15 to it;

T = 232°C + 273.15

= 505.15 K

Next, we need to calculate the number of moles of Sn in the sample. We can do this using the molar mass of Sn;

n = m/M = 26.7 g / 118.71 g/mol

= 0.2246 mol

Now we can use the formula to calculate the entropy change:

ΔS = ΔHfus/T = (7.03 kJ/mol) / (0.2246 mol × 505.15 K)

= 0.055 J/K

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--The given question is incomplete, the complete question is

"Tin (Sn, MM = 118.71G/mol) is a soft metal that is used in alloys such as bronze. Sn melts at ,232 degree C, and has a heat of fusion of  Δ Hf = 7.03 KJ/mol. what is the entropy change of a sample of 26.7g of Sn in J/K when it melts at 232 degree C?"--

Imidazole group of Histidine is called as a poor functional group for promoting covalent catalysis because it doesn't participate in any reaction where a covalent modification on it occurs. Option (a) is correct.

Imidazole group is defined as an organic compound that has the formula C₃N₂H₄. It is called as a white or colorless solid which has the tendency to soluble in water producing a mildly alkaline solution. Imidazole group called as an aromatic heterocycle group that is classified as a diazole which has the nitrogen atoms in meta-substitution. Histidine is defined as an essential amino acid which has a positively charged imidazole functional group. The imidazole group makes the histidine a common participant in enzyme catalyzed reactions. The unprotonated imidazole group is generally serve as a common base of the reaction and the protonated form can serve as a common acid of the reaction.

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The base ionization constant is defined as the equilibrium constant for the equilibrium of the reaction between a conjugate base and its parent acid. Option (A) is correct.

The ionization constant of the reaction can be defined as a constant that depends upon the equilibrium between the ions and the molecules of the reaction that are not ionized in a solution or in the liquid. It is expressed as the symbol as K. It is also called as the dissociation constant. The base ionization constant is generally calculated by the multiplication of the concentrations of the hydrogen ions of the reaction and the concentration of the conjugate base of the reaction. Then the value is divided by the concentration of the acid of the reaction.

A base ionization constant is defined as the equilibrium constant for the ionization of a base of the reaction. It can be expressed as [tex]K_{b}[/tex]. We can take an example of ammonia, This is the expressed in the form of,

                [tex]K_{b}[/tex] = [[tex]NH_4^{+} }[/tex]][[tex]OH^{-}[/tex]][[tex]NH_{3}[/tex]]

[tex]K_{b}[/tex] is a reflection of the strength of the base of the reaction. It is evident that weak bases with relatively high [tex]K_{b}[/tex] values are generally stronger than bases of the reaction with relatively low [tex]K_{b}[/tex] values of the base of the reaction.

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The base ionization constant is described by which of the following?

select the correct answer below:

A. the base ionization constant is the equilibrium constant for the equilibrium between a conjugate base and its parent acid.

B.  the base ionization constant is the ratio of the concentration of the ionized base to the initial base concentration times 100%.

C. the base ionization constant is the equilibrium constant for the ionization of a base.

D.  none of the above

Answer:

The base ionization constant is the equilibrium constant for the ionization of a base.

Explanation:

The base ionization constant is denoted by the symbol Kb and is defined as the equilibrium constant for the ionization of a base in water.

Recall that a base, B, will undergo base ionization in water according to the following equation.

B(aq)+H2O(l)↽−−⇀BH+(aq)+OH−(aq)

The equilibrium constant for this reaction is:

Kb=[BH+][OH−][B]

Generally, we only discuss the equilibrium constants for weak bases, as strong bases dissociate completely in water.

Answer:

Explanation:

Use the given solubility to set up a proportion:

61.8 g / 100.0 g water = x g / 142.1 g water

Cross-multiply to solve for x:

x = (61.8 g / 100.0 g water) * 142.1 g water

Simplify and solve:

x = 87.76 g

Round the answer to an appropriate number of significant figures:

The answer should be rounded to three significant figures, since the given solubility has three significant figures. Therefore, the final answer is:

x = 87.8 g

Therefore, 87.8 g of the unknown solute can dissolve in 142.1 g of water at 70 °C.

At 70°C, the solubility of the unknown solute is 61.8 g/100.0 g of water. 87.9 g of the solute can dissolve in 142.1 g of water at 70°C.

(61.8 g solute / 100.0 g water) = (x g solute / 142.1 g water)
To solve for x, cross-multiply:
61.8 * 142.1 = 100 * x
8791.38 = 100x
x = 87.9138
Thus, 87.9 g of the solute can dissolve in 142.1 g of water at 70°C.

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Answer: The density of pure water is 1 gram per 1 milliliter or one cubic cm. By knowing the density of water we can use it in dilution equations or to calculate the specific gravity of other solutions.

Total 2 electrons are transferred in this reaction.

Balanced chemical equation for the given reaction under acidic conditions is;

8 H⁺ + 2 Fe²+ + 2HNO₂ → 2NO₃⁻ + 2 Fe₃⁺ + 3H₂O

So the coefficients of the species are;

HNO₂⁺ + Fe₂⁺ → NO₃⁻ + Fe₃⁺

1 + 1 → 1 + 1

Water will appear in the balanced chemical equation as a product having a coefficient of 3.

The number of electrons transferred in this reaction can be calculated by examining the oxidation states of the atoms involved. Iron (Fe) goes from a +2 oxidation state to a +3 oxidation state, which means it has lost one electron per Fe atom. Therefore, 2 electrons are transferred in total.

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--The given question is incomplete, the complete question is

"When the following equation is balanced properly under acidic conditions, what are the coefficients of the species shown? HNo2+ + Fe2+ --> NO3- + Fe water appears in the balanced equation as a fill in the blank 5 (reactant, product, neither) with a coefficient of . (enter 0 for neither.) how many electrons are transferred in this reaction?"--

Changes in color, texture, and appearance can also serve as visual evidence of a chemical transformation in addition to the melting range.

In addition to the melting range, other visual evidence that the starting materials have undergone a transformation may include changes in color, texture, or appearance. For example, if the starting materials were colorless liquids and the product is a solid with a distinct color, this could indicate that a chemical reaction has occurred.

Similarly, if the starting materials were clear and the product is cloudy or has a different texture, this could also suggest that a reaction has taken place. Other forms of evidence could include changes in mass, boiling point, or refractive index, among others. Ultimately, a combination of analytical techniques, such as spectroscopy or chromatography, may be required to confirm the identity and purity of the product.

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The pH after addition of 0.0400 mole of HNO3 is 4.13

First, determine the pKa using the provided Ka.:

pKa = -log Ka

pKa = -log 1.3 x 10-5 pKa = 4.8861

Then, determine how many moles of propionic acid HA and propionate A were present in the initial solution.

NHA= (0.300 M) (1.00 L) = 0.300 mol HA

NA- = (0.100 M) (1.00 L) = 0.100 mol A

Calculate the acid and base amounts again after 0.0400 mol of acid has been added. By doing this, the amount of acid will rise while the amount of base will fall:

nHA= 0.300 mol + 0.0400 mol = 0.340

nA = 0.100 mol-0.0400 mol = 0.060

Put the parameters into the Henderson-Hasselbalch equation at the end. Keep in mind that the ratio of concentrations and the ratio of moles are the same:

pH = pKa + log [A]/ [HA]

pH = pKa + log (nA-/V) / (nHA/ V)

pH = pKa + log nA- / nHA

pH 4.8861+ log = 0.060 /0.340

pH = 4.1328

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Answer:  1. The chemical formula of the negative polyatomic ion present in an aqueous nitric acid solution is nitrate, which has a chemical formula of NO3-.

2. The solubility of sulfur dioxide (SO2) in water is negatively affected by an increase in water temperature. This means that as the temperature of water increases, the solubility of SO2 in water decreases. This is because the solubility of gases in water generally decreases with increasing temperature, due to the decrease in gas molecules' ability to dissolve in water. Therefore, when water temperature increases, the amount of SO2 that can dissolve in the water decreases, resulting in less acidic rainfall.

Explanation:

The answer to the number of ions present in the aqueous solution is option (c) 4.30 x 10^21 magnesium ions and 8.60 x 10^21 chloride ions.

The number of ions in the aqueous solution can be calculated using the following formula:

Number of moles = molarity x volume of solution (in liters)

Number of ions = Avogadro's number x number of moles of substance

Since magnesium chloride dissociates into two ions (Mg2+ and 2Cl-), the number of ions can be doubled to calculate the number of chloride ions.The number of moles of magnesium chloride can be calculated as follows:

Number of moles = Molarity x Volume (in liters)

Number of moles = 1.88 M x 3.8 x 10^-6 L = 7.184 x 10^-6 mol

The total number of ions in the solution is:

Number of ions = 2 x Avogadro's number x number of moles of substance

Number of ions = 2 x 6.022 x 10^23 x 7.184 x 10^-6

Number of ions = 8.60 x 10^21 ions

The number of magnesium ions can be calculated by dividing the total number of ions by 2.Number of Mg2+ ions = 8.60 x 10^21 ions ÷ 2 = 4.30 x 10^21 ions

Therefore, the correct answer is option (c) 4.30 x 10^21 magnesium ions and 8.60 x 10^21 chloride ions.

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In ammonia, the nitrogen shares 3 of its valence electrons with each hydrogen atom and each of the hydrogen atom shares one valence electron. So option a is right.

Nitrogen has 5 electrons in its outer shell and hydrogen has one electron. All atoms try to complete octet electronic configuration to become stable. So covalent compound forms covalent bonds by sharing the electrons. Here one nitrogen forms covalent bonds with three hydrogen atoms by sharing one electron with each.

As there is 5 electrons in the outer shell, two of them remains as lone pair of electrons. Here since only one pair of electrons are shared between atoms, they form single bond with each other.

So nitrogen shares 3 electrons and each hydrogen contributes one.

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The equilibrium partial pressure of [tex]$NH_3$[/tex] is 0.0106 atm. [tex]$K_c=\frac{[NH_3]^2}{[N_2][H_2]^3},$[/tex] and [tex]$[NH_3]=1.32\times10^{-4}\frac{mol}{L}.$[/tex]

To decide the harmony halfway strain of [tex]$NH_3$[/tex] in the response vessel, we really want to think about the decent condition for the response:

[tex]$N_2(g) + 3H_2(g)[/tex] rightleftharpoons [tex]2NH_3(g)$[/tex].

At harmony, the paces of the forward and invert responses are equivalent, and the centralizations of the reactants and items never again change. The harmony steady articulation for this response is:

[tex]$K_c = \frac{[NH_3]^2}{[N_2][H_2]^3}$[/tex]

We can utilize the underlying tensions of [tex]$N_2$[/tex] and [tex]$H_2$[/tex] to ascertain their fixations utilizing the best gas regulation:

[tex]$[N_2] = \frac{P_{N_2}}{RT} = \frac{0.900 atm}{0.08206 \frac{L\cdot atm}{mol\cdot K} \times 648 K} = 0.0149 \frac{mol}{L}$[/tex]

[tex]$[H_2] = \frac{P_{H_2}}{RT} = \frac{0.500 atm}{0.08206 \frac{L\cdot atm}{mol\cdot K} \times 648 K} = 0.0083 \frac{mol}{L}$[/tex]

Subbing these fixations and the harmony steady articulation into the articulation for [tex]$K_c$[/tex], we get:

[tex]$K_c = \frac{[NH_3]^2}{[N_2][H_2]^3}$[/tex]

[tex]$K_c = \frac{([NH_3]/0.0149 \frac{mol}{L})^2}{0.0149 \frac{mol}{L} \times (0.0083 \frac{mol}{L})^3}$[/tex]

[tex]$K_c = \frac{[NH_3]^2}{1.05\times10^{-10}}$[/tex]

Addressing for [tex]$[NH_3]$[/tex], we get:

[tex]$[NH_3] = \sqrt{K_c \times [N_2] \times [H_2]^3}$[/tex]

[tex]$[NH_3] = \sqrt{1.05\times10^{-10} \times 0.0149 \frac{mol}{L} \times (0.0083 \frac{mol}{L})^3}$[/tex]

[tex]$[NH_3] = 1.32\times10^{-4} \frac{mol}{L}$[/tex]

At long last, we can switch this fixation over completely to a halfway tension utilizing the best gas regulation:

[tex]$P_{NH_3} = [NH_3] \times \frac{RT}{P}$[/tex]

[tex]$P_{NH_3} = (1.32\times10^{-4} \frac{mol}{L}) \times \frac{0.08206 \frac{L\cdot atm}{mol\cdot K} \times 648 K}{1 atm}$[/tex]

[tex]$P_{NH_3} = 0.0106 atm$[/tex]

Consequently, the harmony halfway tension of [tex]$NH_3$[/tex] in the response vessel is 0.0106 atm.

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