help please!!!

1 . A particle moves in a straight line with constant acceleration. The particle starts moving from rest. It takes the particle 2 seconds to travel 800 meters. Find the acceleration?

2. A golf ball accelerates off a tee at 15m/s2, changing its velocity from 10 m/s to 80m/s down the fairway. How long did it take the golf ball to accelerate?

3. A roller coasters accelerates from an initial velocity of of 40 m/s to a final velocity of 4.0 m/s over 4 seconds. What's the acceleration?

4. If the average speed of a car is 110 km/h, how long will it take the car to travel 715 km?

Answers

Answer 1

If a particle travels in a straight line while accelerating continuously. Starting at rest, the particle begins to move. The particle accelerates to a speed of 200 m/s² and travels 800 meters in 2 seconds.

The speed of a golf ball increases from 10 m/s to 80 m/s down the fairway as it accelerates off the tee at 15 m/s2. How much time did the golf ball need to accelerate?

We can apply the formula: Initial velocity + acceleration over time equals velocity.

Here, initial velocity is equal to 10 m/s, final velocity is equal to 80 m/s, acceleration is equal to 15 m/s2, and we must determine the time.

Thus, 80 = 10 + 15 x time.

By solving for time, we obtain:

time = (80 - 10)/15, or 4 seconds.

A roller coaster accelerates throughout the course of 4 seconds from an initial speed of 40 m/s to a top speed of 4 m/s. How fast is it going?

We can apply the formula: (Final velocity - Initial velocity) / Time = acceleration

Here, the initial speed is 40 m/s, the final speed is 4 m/s, and the time is 4 s.

Acceleration is therefore (4 - 40) / 4 = -9.0 m/s2. Remember that the roller coaster is decelerating, hence the acceleration is negative.

How long will it take a car travelling at an average speed of 110 km/h to cover 715 km?

Time can be calculated using the formula: distance x speed.

Speed in this case is 110 km/h, and distance is 715 km.

Time therefore = 715 / (110/3600) = 28.7 hours.

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Related Questions

When an individual stops working out, muscles slowly
A.
B.
C.
D
strengthen
turn into fat
lose strength
stretch out
Please select the best answer from the choices provided
A

Answers

When an individual stops working out, muscles slowly lose strength (option C).

What is work out?

Working out means to strengthen or improve a part of one’s body by exercise.

Exercise is any activity intended to improve physical, or sometimes mental, strength and fitness.

Many at times, exercises carried out by individuals leads to build up of muscles. However, when they stop working out, this muscle loses strength.

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CPO Science. what is the net force on the refrigerator shown to the right?

Answers

The magnitude of the net force is 50N, directed to the right. Since there is no friction, the only horizontal force is due to the applied force. The normal force (directed upward) and the force of gravity (directed downward) exactly cancel out.

Applying pressure to a box will cause it to shift. In physical science, the concept of force is essential. Force is expressed in newtons in the metric system. (N). A tiny measure of energy is a newton. 500–1,000 newtons of energy are needed to lift the average person.

A joule is a unit of energy.

With regard to power and distance, the unit of energy is connected. In order to move something one metre with one newton of power, one joule (J) of energy is required. To drag a small book across a table, a joule of energy is roughly equivalent to that required. You can pull harder or for a longer distance if you have more stamina.

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What is the net force on the refrigerator shown to the right?

200 N

1,000 N

50 N

= Fg

1,000 N = F.

b) Calculate the mass of the refrigerator.

c) What is the refrigerator's acceleration?

Some solar panels have a total area of 12 m2 . Each 1.0 m2 of the panels receives 0.85 kJ of energy from the Sun in 1.0 s. The efficiency of the panels is 16%. How much power do they produce?

Answers

The solar panels produce 1.632 kW of power.

The first step is to calculate the total energy received by the solar panels per second. To do this, we need to multiply the total area of the solar panels by the energy received per unit area and the efficiency of the panels. The efficiency takes into account any losses due to conversion of the energy into electrical power.

We are given that each 1.0 m2 of the panels receives 0.85 kJ of energy from the Sun in 1.0 s. Therefore, we can calculate the energy received by the 12 m2 of panels as:

energy received = area x energy per unit area

energy received = 12 m2 x 0.85 kJ/m2

energy received = 10.2 kJ

If the efficiency of the panels is 16%, then the power they produce is:

Power = (Efficiency × Energy) / Time

Power = (0.16 × 10.2 kJ) / 1.0 s

Power = 1.632 kW

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Organize the information on atomic mass to complete the outline.

Answers

Atomic mass is the mass of an atom of a chemical substance shown in atomic mass units (amu). It is the sum of the masses of protons, neutrons, and electrons in an atom.

What are protons, neutrons, mass number and atomic mass?

Protons are subatomic particles with a positive charge. The total number of protons in an atom ascertains its atomic number. The nucleus of an atom contains both protons and neutrons and the latter does not have any charge. Mass number is the sum total of the number of protons and number of neutrons in an atom. Mass number is expressed as a whole number and is specific to each isotope.

Atomic mass is usually measured relative to the mass of a carbon-12 atom, which is assigned a mass of exactly 12 atomic mass units. This means that the atomic mass of other elements is given in relation to the mass of carbon-12.

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This string is 5 meters long. What is the measurement of one wavelength?​

Answers

For sound waves in air, a wave 5 meters in length has a frequency around 68 Hz.
That's roughly 2 octaves below "middle C".

For electromagnetic waves in vacuum or air, a wave 5 meters in length has a frequency
around 60 MHz. That's the boundary line between the old analog TV channels 2 and 3 .

A-65.1 μC charge is in a 23648 N/C electric field. What is the magnitude of the force (in N) on this
charge?

Answers

first of all you need to transform the value of the charge to the SI system which means

-65.1μC = -65.1 × 10^-6 C

then you calculate the force using this formula

F = E / |q|

F = 23648 / 65.1 × 10^-6 N

(c)
If an electron described a complete revolution in a
magnetic field, how much energy would it acquire?

Answers

An electron moving transverse to a uniform magnetic field, where there is nothing to interfere with its motion (such as air molecules), will continuously describe complete revolutions with no effort. That is, the electron does not gain energy (and the field does not lose energy).

When it comes to moving electric charges, electric currents, and magnetic materials, a magnetic field is a vector field that defines the magnetic influence. A force perpendicular to both the charge's own motion and the magnetic field acts on a moving charge in the field of magnetism.[1]: ch13 [3]: 278  Iron and other ferromagnetic elements are drawn to a permanent magnet's magnetic field, which also draws or repels other magnets. The three other magnetic effects of paramagnetism, diamagnetism, and antiferromagnetism also impose minute forces on materials that are considered to be "nonmagnetic"; however, these forces are typically so minute that they can only be detected by laboratory equipment. Magnetic fields encircle magnetised materials and are produced by electric currents, like those found in electromagnets, and by electric fields with changing time constants.

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state two difference between mains electcity and that supplied by 1.5 cell

Answers

The  two differences between mains electricity and that supplied by a 1.5V cell:

Voltage:Power output

What is power output?

Power Output means the average rate of electric energy delivery during one Metering Interval.

Power output: Compared to a 1.5V cell, mains electricity has a much greater power output. This is so that more power can be delivered to devices and appliances by mains electricity, which is provided at a higher voltage and current.

Compared to a 1.5V cell, the voltage provided by mains electricity is usually much higher. A 1.5V cell produces DC (direct current) voltage, whereas the mains electricity in the majority of nations is typically supplied at a voltage of 110–120V or 22–240V AC (alternating current). The kinds of devices and appliances that can be powered by mains electricity versus those that can be powered by a 1.5V cell are affected by this difference in voltage levels.

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A 1200 kg wrecking ball hangs from a 14-m-long cable. The ball is pulled back until the cable makes an angle of 19.0 ∘ with the vertical. By how much has the gravitational potential energy of the ball changed?

Answers

Explanation:

Seems like there might be an easier way than all of this trig work.....let me know if it is incorrect:  ( due to rounding the answer may be 8979 J )

Thunder was heard 2second after the lightening .if the velocity of sound is 350m/s,how far is the lightening

Answers

Thunder was heard 2second after the lightening .if the velocity of sound is 350m/s, the lightening is about 700 meters far.

The meter's definition, please.

In international agreement in 1983, the meter was redefined as the distance that light would travel in a vacuum within 1/299,792,458 of both a second, building on these and other advancements. In a vacuum, this definition also fixed the light's speed at 299,792,458 meters a second.

In terms of measurement, what does the word "meter" mean?

A typical metric unit called a meter is equivalent to around 3 feet, 3 inches. This indicates that metric measurement system includes the meter. Objects about one meter long include guitars, baseball bats, & yard poles. In athletic competitions like running and swimming, distances are also measured in meters.

The distance between the viewer and the lightning is about 700 meters.

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"People say that what we're all seeking is a meaning for life. I don't think that's what we're really seeking. I think that what we're seeking is an experience of being alive, so that our life experiences on the purely physical plane will have resonances within our own innermost being and reality, so that we actually feel the rapture of being alive."

Explain the meaning of this excerpt. How can you connect this to The Metamorphosis? Use specific examples from the novella, especially chapter 3, to support your discussion.

Answers

According to this passage, the ultimate aim of existence is to completely experience and appreciate the state of being alive rather than merely to discover a particular purpose or significance.

What purpose does life serve? John Campbell?

"I don't think [the purpose of life] is what we're seeking," said Joseph Campbell. I believe it is an experience of life, allowing our experiences on the strictly physical plane to resonate with our innermost selves and realities, allowing us to truly feel the joy of existence.

What are Joseph Campbell's Journey quotations?

The bravery to probe the depths, the idea of creative rebirth, and the never-ending cycle of transformation within ourselves are all fundamental themes of the hero's journey.

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Ocean waves are hitting a beach at a rate of 35 Hz. What is the period of these waves? A. 3.5 A b. 0.0286 s c. 2.86 A d. 0.0103 s​

Answers

The period of the ocean waves hitting the beach at a rate of 35 Hz is 0.0286 seconds.

What is the relationship between frequency and period in wave motion?

Frequency and period are inversely related in wave motion. The frequency of a wave is the number of complete cycles (or wave crests) that pass a point in a given time period, while the period is the time it takes for one complete cycle to occur. The period can be calculated by dividing the inverse of the frequency.

How do ocean waves form and what factors affect their characteristics?

Ocean waves form due to the transfer of energy from wind to water. Factors that affect the characteristics of ocean waves include wind speed and duration, the distance over which the wind blows (known as fetch), and the depth and shape of the seafloor.

The size and shape of ocean waves can also be affected by tides, currents, and the presence of nearby land masses.

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Internal energy is affected by two properties of the particles which make up a substance. Identify the two properties. A. Motion and position B. Acceleration and mass C. Specific heat capacity and volume D. State of matter and potential energy​

Answers

The two properties of particles which make up a substance that affect its internal energy are:

A. Motion and position

The internal energy of a substance depends on the kinetic energy (motion) and potential energy (position) of its constituent particles. The kinetic energy of the particles determines the temperature of the substance, while the potential energy depends on the intermolecular forces between the particles.

Therefore, option A is the correct answer.

**NEED ANSWER ASAP, DUE TOMORROW**
Why do astronomers believe the disk formed after the stellar halo? (HINT: What observations do we have to support that?)

Answers

Astronomers believe that the disk of the Milky Way galaxy formed after the stellar halo based on several lines of evidence, including observations of the ages and motions of stars in different regions of the galaxy.

What is the evidence of the stars?

One key piece of evidence is that the stars in the halo of the Milky Way are generally much older than the stars in the disk. This suggests that the halo formed first, likely through the merging of smaller galaxies or the accretion of gas and stars from the surrounding environment.

Additionally, the stars in the halo of the Milky Way have very different motions than those in the disk. Halo stars tend to move in random, elliptical orbits, while disk stars follow more circular orbits around the center of the galaxy. This difference in motion also supports the idea that the two structures formed at different times and through different processes.

Finally, studies of the chemical composition of stars in the Milky Way also support the idea that the disk formed after the halo. The disk contains a higher proportion of heavy elements than the halo, which suggests that the disk formed from gas that had already been enriched by earlier generations of stars in the halo.

Taken together, these lines of evidence support the idea that the disk of the Milky Way formed after the stellar halo.

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A uniform sphere with mass 28.0 kg and radius 0.380 m is rotating at constant angular velocity about a stationary axis that lies along a diameter of the sphere. If the kinetic energy of the sphere is 236 J, what is the tangential velocity of a point on the rim of the sphere?

Answers

The tangential speed of a point on the sphere's rim is 2.31 m/s.

Where does a cycle wheel with a radius of 0.5 metres rotate at a constant angular speed of 10 metres per second?

An area of 0.1 T magnetic field lies perpendicular to the plane of a cycle wheel with a radius of 0.5 m, rotating at a constant rate of 10 rad/s. Between its centre and rim, there is a 0.5 V. zero EMF created.

I = (2/5) * m * r²

where m is the mass of the sphere and r is the radius.

Substituting the given values, we get:

I = (2/5) * 28.0 kg * (0.380 m)² = 1.35 kg m²

K = (1/2) * I * ω²

Substituting the given value of K and the calculated value of I, we get:

236 J = (1/2) * 1.35 kg m² * ω²

Solving for ω, we get:

ω = √(2 * 236 J / (1.35 kg m²)) = 6.62 rad/s

v = r * ω

Substituting the given value of r and the calculated value of ω, we get:

v = 0.380 m * 6.62 rad/s = 2.31 m/s.

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Which harmonic is this? * ​

Answers

The wave given in the diagram is a third harmonic wave

What type of harmonic is given?

A harmonic wave is a type of wave that is characterized by its frequency, which is a multiple of the fundamental frequency. In other words, a harmonic wave has a frequency that is an integer multiple of the fundamental frequency, such as twice, three times, four times, etc. the fundamental frequency.

A third harmonic wave specifically has a frequency that is three times the fundamental frequency. It is important to note that a third harmonic wave is just one type of harmonic wave, and there can be other harmonic waves with different frequencies that are also multiples of the fundamental frequency.

Third harmonic waves can be observed in various physical systems, including musical instruments, electrical circuits, and mechanical systems. In musical instruments, for example, a third harmonic wave can produce a higher-pitched sound than the fundamental frequency, while in electrical circuits, it can result in a distortion of the signal. In mechanical systems, a third harmonic wave can cause resonance, which can lead to damaging vibrations.

NB: This wave is known as a standing wave

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Olympic swimmer, Micheal Phelps, swam a 200 meter race in 1 minute and 54 seconds. What would his velocity be in meters/seconds

Answers

During the 200-meter race, Michael Phelps moved at a speed of 1.75 metres per second.

What is famous about Michael Phelps?

More than any other swimmer in history, he won Olympic medals, world titles, US national titles, and set world records. Phelps has made it a priority to support the growth of swimming at all levels during his career. With a total of 28 medals, he is the most successful and decorated Olympian of all time.

Velocity = Distance / Time

In this case, the distance swum is 200 meters and the time taken is 1 minute and 54 seconds, or 114 seconds.

Velocity = 200 meters / 114 seconds

Velocity = 1.75 meters/second (rounded to two decimal places)

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Point charge A is on the x-axis at x = -3.00 cm. At x= 1.00 cm on the x-axis its electric field is 2800 N/C. Point charge B is also on the x-axis, at x= 5.00 cm. The absolute magnitude of charge B is twice that of A.
A) Find the magnitude and direction of the total electric field at the origin if both A and B are positive.
B) Find the magnitude and direction of the total electric field at the origin if both A and B are negative.
C) Find the magnitude and direction of the total electric field at the origin if A is positive and B is negative.
D)Find the magnitude and direction of the total electric field at the origin if A is negative and B is positive

Answers

Answer:

We can use the electric field equation to find the electric field at the origin due to each point charge, and then add them vectorially to find the total electric field. The electric field due to a point charge is given by:

Explanation:

E = k * q / r^2

where k is Coulomb's constant, q is the magnitude of the point charge, and r is the distance from the charge to the point where we want to find the electric field.

A) Both charges are positive. The electric field at the origin due to charge A is:

E_A = k * q_A / r_A^2

where q_A is the magnitude of charge A, r_A is the distance from A to the origin, and we have:

q_A > 0

r_A = 3.00 cm = 0.03 m

The electric field at the origin due to charge B is:

E_B = k * q_B / r_B^2

where q_B = 2 * q_A is the magnitude of charge B, r_B is the distance from B to the origin, and we have:

q_B > 0

r_B = 5.00 cm = 0.05 m

Using Coulomb's constant k = 9.00 x 10^9 N*m^2/C^2, we get:

E_A = (9.00 x 10^9 Nm^2/C^2) * q_A / r_A^2

E_A = (9.00 x 10^9 Nm^2/C^2) * q_A / (0.03 m)^2

E_A = 1.00 x 10^12 q_A N/C

E_B = (9.00 x 10^9 Nm^2/C^2) * q_B / r_B^2

E_B = (9.00 x 10^9 Nm^2/C^2) * 2q_A / (0.05 m)^2

E_B = 7.20 x 10^11 q_A N/C

The total electric field at the origin is the vector sum of E_A and E_B. Since the charges are on the x-axis and the origin is also on the x-axis, the total electric field will be along the x-axis. Therefore, we only need to add the magnitudes of E_A and E_B to get the total electric field:

E_total = |E_A| + |E_B|

E_total = 1.00 x 10^12 q_A N/C + 7.20 x 10^11 q_A N/C

E_total = 1.72 x 10^12 q_A N/C

Substituting q_A = 2800 N/C * (0.01 m)^2 / (9.00 x 10^9 N*m^2/C^2) = 3.11 x 10^-6 C, we get:

E_total = 5.39 N/C

Therefore, the magnitude of the total electric field at the origin is 5.39 N/C, and it is directed along the positive x-axis.

B) Both charges are negative. The only difference from part A is that the charges now have negative signs, so we have:

q_A < 0

q_B = -2 * |q_A| = -2q_A < 0

Substituting these signs into the equations for E_A and E_B, we get:

E_A = -1.00 x 10^12 |q_A| N/C

E_B = -7.20 x 10^11 |q_A| N/C

The total electric field at

not sure if this solves your answer but hope it somewhat helps.

Answer:

A) If both charges A and B are positive, the electric field vectors point away from the charges, and we can use the principle of superposition to find the total electric field at the origin. The electric field at the origin due to charge A is:

E_A = k*q_A/r_A^2

where k is the Coulomb constant, q_A is the charge of A, and r_A is the distance between A and the origin. Since A is on the x-axis, r_A is simply the distance between A and the origin:

r_A = |-3.00 cm| = 3.00 cm = 0.03 m

Using the given electric field at x=1.00 cm, we can solve for the charge of A:

2800 N/C = k*q_A/(0.01 m)^2

q_A = (2800 N/C)(0.01 m)^2/k = 2.5210^-8 C

The electric field at the origin due to charge B is:

E_B = k*q_B/r_B^2

where q_B is the charge of B, and r_B is the distance between B and the origin:

r_B = |5.00 cm| = 5.00 cm = 0.05 m

Since the absolute magnitude of charge B is twice that of A, q_B = 2q_A = 5.0410^-8 C. Using the principle of superposition, the total electric field at the origin is the vector sum of E_A and E_B. Since both electric fields are along the x-axis, the total electric field at the origin will also be along the x-axis:

E_total = E_A + E_B = kq_A/r_A^2 + kq_B/r_B^2

E_total = (910^9 Nm^2/C^2)(2.5210^-8 C)/(0.03 m)^2 + (910^9 Nm^2/C^2)(5.0410^-8 C)/(0.05 m)^2

E_total = 1.87*10^6 N/C

The direction of the electric field is to the right (positive x-axis direction), since the positive charge B is farther to the right than the positive charge A.

Therefore, the magnitude of the total electric field at the origin if both A and B are positive is 1.87*10^6 N/C to the right.

B) If both charges A and B are negative, the electric field vectors point towards the charges, and we can use the same method as above to find the total electric field at the origin. The electric field at the origin due to charge A is:

E_A = -k*q_A/r_A^2

where the negative sign indicates that the electric field is directed towards charge A. The electric field at the origin due to charge B is:

E_B = -k*q_B/r_B^2

Using the same values for q_A and q_B as in part A, we get:

E_total = E_A + E_B = -kq_A/r_A^2 - kq_B/r_B^2

E_total = -(910^9 Nm^2/C^2)(2.5210^-8 C)/(0.03 m)^2 - (910^9 Nm^2/C^2)(5.0410^-8 C)/(0.05 m)^2

E_total = -2.23*10^6 N/C

The magnitude of the total electric field at the origin is 2.23*10^6 N/C, and the direction is to the left (negative x-axis direction), since the negative charges A and B are both to the right of the origin.

Therefore, the magnitude of the total electric field at the origin if both A and B
are negative is 2.23*10^6 N/C to the left.

C) When A is positive and B is negative, the electric field vectors produced by each point charge will be in opposite directions. To find the total electric field at the origin, we need to add the electric field vectors produced by each charge.

The magnitude of the electric field due to charge A at the origin is given by the formula:

E = k * Q / r^2

where k is the Coulomb constant (9.0 x 10^9 N m^2 / C^2), Q is the magnitude of the charge, and r is the distance between the charge and the origin.

Using this formula, the magnitude of the electric field due to charge A at the origin is:

E_A = k * Q_A / r_A^2
= (9.0 x 10^9 N m^2 / C^2) * Q_A / (0.03 m)^2
= (9.0 x 10^9 N m^2 / C^2) * (|Q_A|) / (0.03 m)^2
= (3.2 x 10^6) * |Q_A| N/C

where |Q_A| is the absolute magnitude of charge A.

Similarly, the magnitude of the electric field due to charge B at the origin is:

E_B = k * Q_B / r_B^2
= (9.0 x 10^9 N m^2 / C^2) * (-2|Q_A|) / (0.05 m)^2
= - (1.4 x 10^6) * |Q_A| N/C

where |Q_B| is the absolute magnitude of charge B.

The total electric field at the origin is the vector sum of E_A and E_B:

E_total = E_A + E_B

Since E_A is positive and E_B is negative, the direction of the total electric field is towards the negative x-axis.

The magnitude of the total electric field is:

|E_total| = |E_A + E_B|
= |E_A| - |E_B|
= (3.2 x 10^6) * |Q_A| - (1.4 x 10^6) * |Q_A|
= (1.8 x 10^6) * |Q_A| N/C

Therefore, the magnitude of the total electric field at the origin is (1.8 x 10^6) times the magnitude of charge A, and the direction of the electric field is towards the negative x-axis.

Mica is investigating the speed of waves. She hypothesizes that waves travel at different speeds depending on the media. She sets up an experiment where she sends two different waves through air, water, and glass. She keeps the temperature of eah medium constant and measure the speed of the waves as they travel through each medium. What would be the most likely result if Mica performed the same experiment again, but sent both waves through a vacuum instead of air, water, and glass?

Answers

Answer:

If Mica sends both waves through a vacuum instead of air, water, and glass, then she would find that the waves travel at the same speed. This is because a vacuum is a completely empty space with no matter or medium to interact with, and the speed of light is constant in a vacuum. Therefore, any electromagnetic waves, including light waves, radio waves, and microwaves, would travel at the same speed in a vacuum.

A massless spring hangs from the ceiling with a small object of 100 g attached to its lower end. The object is initially held at rest at a position such that the spring is at its rest length. The object is then released and oscillates up and down, with its lowest position being 5.0 cm below the initial position. The object's speed at 2 cm below the initial position is:
Group of answer choices

2.23 m/s

14 m/s

0.21 m/s

0.45 m/s

Answers

The speed of the object at 2 cm below the initial position is 0.45 m/s when a small object of 100 g attached to its lower end.

Given the mass of small object (m1) = 100g

The distance of object from top of spring (x) = 5cm

The point of length of object (l) = 2cm

the speed of object at 2cm below the initial position is = v

We know that F = Kx where F = mg such that:

mg = kx then [tex]100 * 10^{-3} * 9.8 = k * 5 * 10^{-2[/tex]

k = 19.6

We know that from the conservation of energy,

initial potential energy (Ui) + kinetic energy (K.E) = final PE + KE such that:

[tex]1/2kx^2 - mgx + 1/2mv^2 = 0[/tex]

[tex]1/2 * 19.6 * (0.02)^2 - 0.1 * 9.8 * 0.02 + 1/2 * 0.1 * v^2 = 0[/tex]

[tex]0.00392 - 0.0196 = -0.05v^2[/tex]

[tex]0.3136 = v^2[/tex]

v = 0.45m/s

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Directions: Participate in a workout of your choice. Evaluate your activity by answering the questions below.

Answers

For this workout I did squats. Squats may aid in weight loss because they burn calories. Moreover, they reduce the possibility of knee and ankle injuries.

How did the squat exercise make you feel?

When performing squats, your legs should feel fatigued. Lower back ache is a sign that you're likely doing the workout wrong. This shows that your lower back muscles are working harder than your glutes and quadriceps since they are taking the load. Pay attention to how you squat.

Squats are  possible everywhere?

It doesn't matter where it is—a living room, office, stairwell, park, or closet—as long as there are a few feet available. The only thing you need is your body weight.

Is it acceptable to squat without a spotter?

In some instances, it is acceptable to squat without a spotter. The environment and resources you have at your disposal, though, are everything. The safest choice is to use a power rack or squat stand with adjustable safety pins, arms, or straps.

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At which point does puberty occur for the majority of people?

Answers

Puberty typically occurs between the ages of 8 and 13 years for girls and between 9 and 14 years for boys. However, the exact timing of puberty varies widely among individuals.

The pressure on each of the tires of a 1500-kg car is 2.2 x 10^5 Pa. If each of the tires shares an equal
load, determine the contact area of each of the tires with the road. Show your work.

Answers

Answer:

Use the formula to determine the contact area of each tire with the road.

Area divided by force yields pressure, as the equation suggests.

The weight of the car, which is 1500 kg, exerts a force on an area where pressure is at 2.2 x 10^5 Pa.

Supported by all four tires, we must first determine the total force.

Weight of car is 1500 kg multiplied by 9.8m/s^2 equals =14700 N, also known as total force.

Equally sharing the load, four tires are responsible for supporting the vehicle.

Each tire carries a force that equals the total force divided by 4, which is equivalent to 3675 N as calculated from a total force of 14700 N.

Each tire's contact area with the road can now be calculated.

3675 N divided by 2.2 x 10^5 Pa equals the area. This area can also be described as force divided by pressure.

Approximately 16.7 cm^2 or 1.67 x 10^-2 m^2 is the designated area.

The contact area between the road and each tire measures exactly 16.7 cm^2.

remembering and forgetting: crash course psychology #14

Answers

Crash Course Psychology #14 focuses on the concepts of remembering and forgetting. The episode discusses various aspects of memory, such as encoding, storage, and retrieval. Encoding refers to the process of transforming information into a format that can be stored in the brain, while storage is the preservation of that information over time. Retrieval is the act of accessing and recalling stored information when needed.

Forgetting is a natural part of memory processes and can occur due to factors like decay, interference, and retrieval failure. Decay is the gradual fading of memories over time, while interference involves new information disrupting the recall of older memories. Retrieval failure happens when we are unable to access certain memories, even if they still exist in our brains.

In summary, Crash Course Psychology #14 explores the complex processes of remembering and forgetting, highlighting key concepts such as encoding, storage, retrieval, decay, interference, and retrieval failure.

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a satellite moves in a circular orbit around the earth with speed V- 6000mls. Determine the satellite altitude above the earth surface and the period of the satellite's orbit the earth mass and radius are M= 5.97 x 10²⁴kg and R= 6.378 x 206m.​

Answers

The satellite's height above the surface of the planet is roughly 35,800 kilometers, and its orbital period is roughly 1.54 hours.

What is speed?

An object's speed can be defined as how quickly it is going. It measures how quickly an object travels over time. Typically, speed is measured in terms of time/distance.

How do you determine it?

The speed of the satellite must first be converted from miles per second to meters per second:

V= 6000 miles per second = 9656 m/s

The orbital radius of the satellite can then be calculated using the centripetal force equation as follows:

Fc = Fg

Gm M / r² = mv² / r

r = G M / v²

where M is the earth's mass.

By entering the specified values, we obtain:

r = (5.97 x 10²⁴ kg) x (6.67 x 10⁻¹¹N m²/kg²)/ (9656 m/s) 

r= 4.22 x 10⁷ meters

Hence, the satellite's height above the surface of the planet is:

height = r - R.

height= (4.22 x 10⁷ m) - (6.378 x 10⁶ m)

height is 3.58 x 10⁷ meters.

Now we can apply the equation for a circular orbit's period:

T = 2π r / v

When we enter the values we just discovered, we obtain:

T = 2π (4.22 x 10⁷ m) / (9656 m/s)

T = 5.56 x 10³ seconds

Hence, the satellite's orbit has a period of about 1.54 hours.

So, the satellite's height above the surface of the planet is roughly 35,800 kilometers, and its orbital period is roughly 1.54 hours.

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Spectroscopy has much in common with what other cosmological concepts?
O
redshift and blueshift
gravity and weight
dark matter and dark energy
speed and velocity

Answers

Spectroscopy has much in common with the cosmological concept of redshift and blueshift.

What is Spectroscopy?

Spectroscopy is the study of the interaction between matter and electromagnetic radiation, and it is commonly used to study the properties of stars and galaxies.

Redshift and blueshift, on the other hand, are phenomena that occur when light is emitted from an object that is moving away or towards an observer, respectively. These concepts are commonly used in cosmology to study the expansion of the universe and the motion of galaxies.

Spectroscopy can be used to measure the redshift or blueshift of light emitted from distant objects, providing valuable information about their distance, velocity, and composition.

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Activity log - Low Impact Floor Drill

Record your time and activity below and in your unit fitness log. If a particular category does not apply, leave it blank.

Date:
Warm-up:
Cool-down:
Type of Activity: (Cardiovascular, Muscular, or Flexibility)
Description of Activity and Time:
Intensity Level: (Moderate or Vigorous)
Total Time:

Answers

Based on the information, a guide on how to fill out your fitness log is given.

How to write the fitness log

Date: Write the current date.

Warm-up: Indicate what type of warm-up exercise you did before the actual activity. For example, you may have stretched or walked briskly for five minutes before starting the actual exercise.

Cool-down: Indicate what type of cool-down exercise you did after the actual activity. For example, you may have stretched or walked slowly for five minutes after completing the actual exercise.

Type of Activity: Choose whether the exercise you did is cardiovascular, muscular, or flexibility training.

Description of Activity and Time: Provide a brief description of the exercise you did and how long you did it. For instance, if you did a low-impact floor drill for 30 minutes, write "Low-impact floor drill for 30 minutes."

Intensity Level: Choose whether the exercise was moderate or vigorous.

Total Time: Write the total time you spent doing the exercise, including warm-up and cool-down. For example, if you spent five minutes warming up, 30 minutes doing the actual exercise, and five minutes cooling down, write "40 minutes" as the total time.

Remember to update your fitness log regularly to monitor your progress and achieve your fitness goals.

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Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride. If a boat and its riders have a mass of 1000 kg and the boat drifts in at 1.3 m/s how much work does Sam do to stop it?

Answers

Sam put in -845 J of work to halt it. Sam had to exert effort in the direction counter to the way the boat was moving, as indicated by the negative sign, which denotes that he did negative work.

How do you figure out how much labor Sam put in?

One can compute the initial kinetic energy as follows:

KEi is equal to (1/2)mv2, where m is the combined mass of the boat and its riders (1000 kg), and v is the boat's initial speed (1.3 m/s).

KEi = (1/2)(1000 kg)(1.3 m/s), which equals 845 J.

The boat is brought to a stop, and as a result, its terminal velocity and kinetic energy are both zero:

KEf = 0 J

Sam put forth the following effort to stop the boat: W = 0 J - 845 J

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A wave with a frequency of 12 Hz has a wavelength of 3 meters. At what speed will this wave travel?

Answers

Explanation:

speed = wavelength * frequency

         =   3 m  *  12 /s  = 36 m/s

A gas burner transfers 9.40 ✕ 105 J into a block of ice with a mass of 2.23 kg and an initial temperature of 0°C.
(a)
How much of the energy (in J) supplied by the burner goes into melting all the ice into liquid water? (Enter your answer to at least three significant figures.)
J
(b)
How much of the energy (in J) supplied by the burner goes into raising the temperature of the liquid water? (Enter your answer to at least three significant figures.)
J
(c)
What is the final temperature of the liquid water in degrees Celsius?

Answers

Answer:

HOPE IT HELPS..........

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