Explanation:
It ignores some basic laws of physics:
You cannot get more work out of a machine than goes in
You cannot ignore friction
You are investigating an accident that occurred early on a foggy morning in Oxfordshire. A 2015 Prius Hatchback traveling due north collided in a highway intersection with a 2012 Nissan Pathfinder that was traveling due east. After the collision, the wreckage of the two vehicles was locked together and skidded across the level ground until it struck a tree. You measure that the tree is 11 m from the point of impact. The line from the point of impact to the tree is in a direction 39∘ north of east. From experience, you estimate that the coefficient of kinetic friction between the ground and the wreckage is 0.45. Shortly before the collision, a police officer with a laser speed gun measured the speed of the Prius to be 80 km/h and, according to a witness, the Prius driver made no attempt to slow down. Four people with a total mass of 230 kg were in the Nissan. The only person in the Prius was the 80 kg driver. The Nissan with its passengers had a mass of 2362 kg , and the Prius with its driver had a mass of 1460 kg .
The given and calculated values: force_impact = (0 - 32,488.4 kg*m/s) / 1.34 s = -24,277.6 N The negative sign indicates that the force is in the opposite direction to the motion, which is consistent with the wreckage coming to a stop.
What does the restoring force's negative value mean?The negative sign informs us that the restoring force is acting in the direction that is opposed to the distortion. For instance, when a spring is stretched, the restoring force pulls in the opposite way. When a spring is compressed, the restoring force pulls against the compression's direction.
We employ the following formula to determine the power of friction:
f_friction = friction coefficient * normal force
normal force = (1460 kg + 2362 kg + 230 kg) * 9.8 m/s^2 = 38,496.4 N
So the force of friction is:
f_friction = 0.45 * 38,496.4 N = 17,323.4 N
momentum_before = (mass_Prius * velocity_Prius) + (mass_Nissan * velocity_Nissan)
Substituting the given values:
momentum_before = (1460 kg * 22.22 m/s) + (2362 kg * 0 m/s) = 32,488.4 kg*m/s
momentum_after = (mass_Prius + mass_Nissan + 230 kg) * velocity_final
Substituting the given values:
32,488.4 kg*m/s = (1460 kg + 2362 kg + 230 kg) * velocity_final
velocity_final = 11.06 m/s
To calculate the force of the impact, we use the formula:
force_impact = (momentum_after - momentum_before) / time
distance = √((11 m)² + (11 m / tan(39°))) = 14.86 m
Assuming the wreckage was traveling at a constant speed during the skid, we can estimate the time as:
time = distance / velocity_final = 1.34 s
Substituting the given and calculated values:
force_impact = (0 - 32,488.4 kg*m/s) / 1.34 s = -24,277.6 N
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Ionic bonds bond ions together(1 point) Responses because they connect in order for one to transfer their electrons to the other. because they connect in order for one to transfer their electrons to the other. through their electric attraction to each other due to their equal electrical charges. through their electric attraction to each other due to their equal electrical charges. through their electric attraction to each other due to their opposite electrical charges. through their electric attraction to each other due to their opposite electrical charges. because they share electrons with each other, pulling them together.
Ionic bonds bond ions together through their electric attraction to each other due to their opposite electrical charges.
In an ionic bond, one ion (typically a metal) loses one or more electrons and becomes a positively charged cation, while another ion (typically a nonmetal) gains one or more electrons and becomes a negatively charged anion. The opposite charges of the ions then attract each other, creating an ionic bond between them.
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4.
In a TV picture tube, an electron in the beam is
accelerated by a potential difference of 20,000V.
Then it passes
through a region of transverse
magnetic field where it moves in a circular arc
with radius 12cm. What is the magnitude of the
field?
The magnitude of the magnetic field is 1.50 x 10^-3 T.
Magnitude of field calculation.
The force on a charged particle moving through a magnetic field is given by the equation:
F = qvB sin(theta)
where F is the force, q is the charge on the particle, v is the velocity of the particle, B is the magnetic field strength, and theta is the angle between the velocity vector and the magnetic field vector.
In this case, the electron is moving in a circular arc, which means that the force on the electron is directed inward toward the center of the circle, and is equal to the centripetal force:
F = mv^2 / r
where m is the mass of the electron, v is the velocity of the electron, and r is the radius of the circular arc.
We can equate these two forces and solve for the magnetic field strength:
mv^2 / r = qvB sin(theta)
Simplifying and rearranging:
B = mv / (qr) * 1/sin(theta)
To find the velocity of the electron, we can use the equation for the kinetic energy of a charged particle:
KE = 1/2 mv^2 = qV
where KE is the kinetic energy of the electron, q is the charge on the electron, and V is the potential difference that the electron was accelerated through.
Solving for v:
v = sqrt(2qV/m)
Plugging in the given values:
V = 20,000 V
m = 9.11 x 10^-31 kg
q = -1.6 x 10^-19 C
v = sqrt(2(-1.6 x 10^-19 C)(20,000 V) / 9.11 x 10^-31 kg) = 2.43 x 10^7 m/s
Now we can plug in the values for m, q, v, r, and theta (which is 90 degrees since the velocity vector is perpendicular to the magnetic field vector) to find the magnetic field strength:
B = (9.11 x 10^-31 kg)(2.43 x 10^7 m/s) / ((-1.6 x 10^-19 C)(0.12 m)) * 1/sin(90 degrees) = 1.50 x 10^-3 T
Therefore, the magnitude of the magnetic field is 1.50 x 10^-3 T.
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If the foot kicks the ball with an action force of 40 N, the force which the
ball exerts on the foot will:
O a. depend on the mass of the foot and the ball.
O b. depend on whether or not the ball is moving.
O c. depend on whether or not the player was running.
O d. be 40 N of reaction force.
Answer:
the answer is (d) the force which the ball exerts on the foot will be 40 N of reaction force.
Explanation:
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. Therefore, the force exerted by the ball on the foot will be equal and opposite to the action force exerted by the foot on the ball.
consider two vector A(18m) Along horizontal and B(8m) at angle of 60° above the horizontal find R and the angle between R and A,A and B
Answer:
angle between A and B is approximately 76.8°
Explanation:
Using the cosine law, we can find the magnitude of the resultant vector R:
R^2 = A^2 + B^2 - 2ABcosθ
where θ is the angle between A and B, which can be found using the sine law:
sinθ/8m = sin60°/18m
θ ≈ 43.2°
Substituting the given values into the cosine law:
R^2 = (18m)^2 + (8m)^2 - 2(18m)(8m)cos(43.2°)
R ≈ 19.4m
The angle between R and A can be found using trigonometry:
tanθ = 8m/18m
θ ≈ 24.4°
Therefore, the angle between R and A is approximately 24.4°, and the angles between A and B and between B and R can be found using the fact that they form a triangle:
180° - 60° - 43.2° = 76.8°
Therefore, the angle between A and B is approximately 76.8°, and the angle between B and R is approximately 60° - 76.8° = -16.8° (because B is above the horizontal).
Griffin throws a 0.25 kg football with a force of 10 N. The ball that started from rest took 3 second to reach a final velocity. What is the momentum of the ball?
Answer:
The momentum of the ball is 0.6225 kg/ms^-1
We are given that mass = 0.25 kg
force = 10 N
Time = 3 seconds
Momentum(p) = mv, where m is mass and v is velocity
First we need to find the final velocity, using the formula:-
v = u+at, where v is final velocity, u is initial velocity, a is acceleration and t is time.
rearranging the formula, we first find acceleration:-
a = (v-u)/t
substituting the values,
a = v/t
a = (0.25kg*10N)/3 seconds
a = 0.83 m/s^2
Finding final velocity using the formula v = u+at
v = 0 + (0.83m/s^2*3 seconds)
v = 2.49 m/s
Finally, using the formula p=mv to find the momentum:-
p = 0.25kg*2.49m/s
p = 0.6225 kg m/s^-1
Thus the momentum is 0.6225 kg m/s^-1.
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a car pull a truck with a force of 1500N The truck move a distance of 10m in 15s, what is the work and the power
The amount of work done is 15,000 J if an automobile pulls a truck with a force of 1500 N and the truck travels 10 meters in 15 seconds. One kW or 1,000 W is the power.
How do you determine the amount of work done in this scenario?A force's work is indicated by:
Fdcosθ = W
d is the distance moved in the direction of the force, F is the force's magnitude, and is the angle between the force and the displacement.
W = 1500 N x 10 m x cos(0°), which equals 15,000 J.
The amount of work is 15,000 J.
How would you determine power in this scenario?P = W/t
P = 15,000 J / 15 s = 1,000 W
One kW or 1,000 W is the power.
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How much charge is passing through a
circuit providing electricity for a 120 V light
bulb if it uses 300 J of energy?
6.25 coulombs of charge is passing through a circuit providing electricity for a 120 V light bulb if it uses 300 J of energy.
What is charge ?
When placed in an electromagnetic field, the physical property of matter known as electric charge causes matter to feel a force. A positive or negative electric charge can exist. (commonly carried by protons and electrons respectively, by convention). Like charges repel one another, while unlike charges draw one another. A neutral substance is one that does not have any net charge. Classical electrodynamics refers to early understanding of how charged substances interact, and it is still accurate for problems that do not require consideration of quantum effects.
Electric charge is a conserved characteristic; the net charge of an isolated system, which is the sum of positive and negative charges, cannot change. Subatomic particles carry electric energy. Negative charge in ordinary substance.
Calculate the amount of time that the energy is used.
[tex]\frac{300 J}{120 V}[/tex]= 2.5 seconds
Calculate the current running through the circuit.
Current = Power / Voltage = [tex]\frac{300W}{120V}[/tex]= 2.5 Amps.
Calculate the charge passing through the circuit.
Charge = Current x Time
= 2.5 Amps x 2.5 seconds
= 6.25 Coulombs of charge.
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A jar of tea is placed in sunlight until it
reaches an equilibrium temperature of 33.3
◦C .
In an attempt to cool the liquid, which has a
mass of 187 g , 133 g of ice at 0.0
◦C is added.
At the time at which the temperature of the
tea is 31.8
◦C , find the mass of the remaining
ice in the jar. The specific heat of water
is 4186 J/kg ·
◦ C . Assume the specific heat
capacity of the tea to be that of pure liquid
water.
Answer in units of g.
(2 significant digits)
Answer:
To solve this problem, we need to use the following formula:
Q = m_tea * c_tea * (T_f - T_i) + m_ice * L_f + m_ice * c_ice * (T_f - 0)
where Q is the amount of heat transferred, m_tea is the mass of the tea, c_tea is the specific heat capacity of the tea, T_i is the initial temperature of the tea, T_f is the final temperature of the tea and ice mixture, m_ice is the mass of the ice, L_f is the latent heat of fusion of ice (334 J/g), and c_ice is the specific heat capacity of ice (2.108 J/g·°C).
First, we need to calculate the initial temperature of the tea. Since it has reached an equilibrium temperature of 33.3°C in sunlight, we can assume that its initial temperature was also 33.3°C.
So, the equation becomes:
Q = (187 g) * (4186 J/kg·°C) * (31.8°C - 33.3°C) + (133 g) * (334 J/g) + (m_ice) * (2.108 J/g·°C) * (31.8°C - 0°C)
Simplifying this equation, we get:
Q = -121732.8 J + 44422 J + 67.032 m_ice
Setting Q to zero, since we want to find the mass of the remaining ice when the temperature is 31.8°C, we get:
67.032 m_ice = 121732.8 J - 44422 J
m_ice = 114.9 g
Therefore, the mass of the remaining ice in the jar when the temperature is 31.8°C is 114.9 g (to 2 significant digits).
The momentum of a 2.5 kg hammer with a speed of 6 m/s has a downward momentum moving towards a nail. The hammer hits the nail and bounces off at 2.0 m/s and the nail is in contact with the nail for 0.002 seconds. What is the average force the nail exerts on the hammer? How could you use force vs. time to solve this problem?
The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.
The equation can be used to determine the average force the nail applies to the hammer.
[tex]F = \frac{mv}{t}[/tex], where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:
[tex]F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.[/tex]
To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.
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The kinematic equations can describe phenomena other than motion through space and time. Suppose x represents a person’s bank account balance. The units of x would be dollars ($), and velocity v would give the rate at which the balance changes (in units of, for example, $/month). Acceleration would give the rate at which v changes. Suppose a person begins with ten thousand dollars in the bank. Initial money management leads to no net change in the account balance so that v0 5 0. Unfortunately, management worsens over time so that a 5 22.5 3 102 $/month2 . Assuming a is constant, find the amount of time in months until the bank account is empty.
We can use the kinetic equation that combines velocity, acceleration, and time to calculate the number of months until the bank account is empty:
[tex]v = v_0 + at[/tex]
Since initially there is no net change in the account balance, the initial velocity [tex](v_0)[/tex]in this case is 0. 22.5 * $102 per month expressed as Acceleration (a). The moment (t) at which the account balance reaches zero must be determined.
We can arrange the equation to solve for time as follows:
[tex]0 = 0 + (22.5 * 10^2) * t[/tex]
When we simplify the equation, we get:
2250t = 0
After 0 months the account balance will be zero as the result of the calculation will be 0. This shows that the bank account is currently empty or will be empty soon.
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Can someone help me
Answer:
online medical
Explanation:
like COVID dieases technicians do online training
A man has to push his boat on the shore across the mud to get to the water. The coefficient of friction between the boat and the mud is given by μ = 0.500. If the boat has a mass of 50 kg, calculate the magnitude of the force of friction acting on the boat
The magnitude of the force of friction acting on the boat is 245.25 N.
How do you determine the amount of friction energy being applied to?F = mg sin - kmg cos is the formula for the component of the total force down the slope.
The following algorithm can be used to determine the amount of friction the boat is experiencing:
F friction = friction coefficient * normal force
normal force=weight of the boat
=m *g
where m is the mass of the boat and g is the acceleration due to gravity (9.81 m/s²).
Therefore, the force of friction on the boat is:
F friction = μ * m * g
Substituting the given values, we get:
F friction = 0.500 * 50 kg * 9.81 m/s² = 245.25 N
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If a 2.6 kilograms can of cranberry sauce with the radius of one point five meters is released from rest at the top of 15 mile high hill. if the hill is frictionless what is the velocity of the can's center of mass at the bottom of the hill?
To solve this problem, we can use conservation of energy. At the top of the hill, the can of cranberry sauce has gravitational potential energy given by:
U = mgh
where m is the mass of the can, g is the acceleration due to gravity, and h is the height of the hill. We can plug in the given values to get:
U = (2.6 kg)(9.81 m/s^2)(15 miles x 1609.34 m/mile) = 601266.8 J
At the bottom of the hill, all of this potential energy will be converted into kinetic energy:
K = (1/2)mv^2
where v is the velocity of the can's center of mass at the bottom of the hill. We can solve for v by equating K and U:
(1/2)mv^2 = mgh
Simplifying and solving for v, we get:
v = sqrt(2gh)
Plugging in the given values, we get:
v = sqrt(2 x 9.81 m/s^2 x 15 miles x 1609.34 m/mile) = 423.6 m/s
Therefore, the velocity of the can's center of mass at the bottom of the hill is 423.6 m/s.
jpopwgtxfp give atleast 2 situations,in which you would store the data on cloud storage
Disaster recovery and cooperation are both benefited by cloud storage. It makes file sharing simple and guarantees that data is backed up and retrievable in the event of loss or damage.
What are the two benefits of keeping all of your data in the cloud?Your documents and data are kept in a safe data centre off-site by a cloud provider. You are no longer required to update software, maintain the servers, or make sure the hardware is working properly.
What kinds of information can be stored in the cloud?To store data, including files, business data, videos, or photographs, cloud storage uses remote servers. Users use an internet connection to upload data to servers, where it is stored on a virtual machine on a physical server.
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I NEED HELPPPPPPP
Of the following statements about the ChemBank at the Broad Institute, identify those that are correct.
ChemBank plans to sell the results of its research to various companies.
ChemBank is an open-source application.
ChemBank matches small molecules to various biological targets.
ChemBank performs pure research.
ChemBank uses known chemical compounds in new therapeutic applications.
ChemBank applies its research to therapeutic goals.
ChemBank matches small molecules to various biological targets and ChemBank uses known chemical compounds in new therapeutic applications are correct statements.
What is ChemBank?
ChemBank performs pure research and ChemBank applies its research to therapeutic goals could both be considered correct depending on the interpretation. ChemBank does perform pure research in the sense that it conducts basic scientific investigations to understand the properties and behavior of small molecules and their interactions with biological targets. However, ChemBank also applies its research to therapeutic goals by using this knowledge to develop new drugs and drug candidates.
ChemBank does not plan to sell the results of its research to various companies, so the statement "ChemBank plans to sell the results of its research to various companies" is incorrect.
ChemBank is not an open-source application, so the statement "ChemBank is an open-source application" is also incorrect.
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Complete question is: ChemBank matches small molecules to various biological targets and ChemBank uses known chemical compounds in new therapeutic applications are correct statements.
A body of mass 3.0kg moves with a velocity 10m/s calculate the moment of the body
In this case, the body has a mass of [tex]3.0[/tex] kg and is moving with a velocity of [tex]10 m/s[/tex]. the moment of the body is [tex]30 kg m/s.[/tex]
What is the momentum?The moment of a body (also known as its momentum) is defined as the product of the body's mass and velocity.
In this instance, the body weighs 3.0 kilogrammes and is travelling at a speed of 10 m/s.
The formula to calculate the moment of the body is:
momentum = mass x velocity
Plugging in the given values, we get:
momentum [tex]= 3.0 kg \times 10 m/s[/tex]
Solving the above expression, we get:
momentum = [tex]30 kg m/s[/tex]
Therefore, the moment of the body is [tex]30[/tex] kg m/s.
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Which is the correct resultant wave? *
The resultant wave is the combination of the two waves as we see in option A
What is the resultant wave?A resultant wave is a wave that is formed when two or more waves interact with each other. When waves meet, they can interfere constructively, destructively, or somewhere in between, depending on their amplitude, phase, frequency, and direction. The resulting wave that emerges from this interaction is called the resultant wave.
The nature of the resultant wave depends on the type of interference that occurs between the waves. If the waves are in phase and have the same amplitude, they will interfere constructively, resulting in a wave with a larger amplitude.
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it 3 Review
tors and 2-D Kinematics
Find the direction of the sum
of these two vectors:
16.3 m
BV
7.70 m
A
27.8°
20.0°
When two vectors of magnitudes 16.3 m and 7.7 m are combined at an angle of 137.8 degrees, the resultant is equivalent to 23.87 metres.
What is the parallelograms law of vector addition?
The adjacent sides drawn from a point can be used to indicate the magnitude and direction of two vectors acting concurrently at a point.
7.7 m in size, with vector 1 pointing at the x-axis at a 27.8 degree angle.
vector 2 of magnitude 16.3 m, 20 degrees off the negative y plane.
Using the law of parallelogram vector addition
i.e.
resultant vector = √((v₁) ² + (v₂) ² + 2 × v₁ × v₂ × cos (angle between two vectors))
substituting given value in parallelogram vector addition we get,
resultant vector = √ (570)
resultant vector = 23.87 meters
As a consequence, the product of the two vectors, which have magnitudes of 16.3 metres and 7.7 metres and an angle of 137.8 degrees, is equal to 23.87 metres.
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Question:
Find the direction of the sum
of these two vectors:
16.3 m
7.70 m
20.0°
magnitude (m)
A 27.8°
A lizard accelerates from 2 m/s to 10 m/s in 4 seconds. What is the lizard’s average acceleration?
Hello and regards emmateddyafton94.
Answer:The acceleration of the lizard that has speeds between 2 m/s and 10 m/s, in a time of 4 seconds, is 2 m/s².
Explanation:It is an exercise in rectilinear motion uniformly accelerated (MRUA) is a type of movement in a straight line in which an object moves with a constant acceleration. This type of movement is common in everyday life, such as when an object falls due to the force of gravity or when a car moves in a straight line and accelerates at a constant speed.
In the MRUA, the speed of the object changes at a constant rate in each unit of time. This means that acceleration is the amount of change in velocity that occurs in each second, and it is constant throughout the motion. Acceleration is measured in units of length per unit of time squared (for example, meters per second squared).
The fundamental formula of the MRUA is:
d = v₀ × t + 1/2 a × t²Where:
d is the distance traveled by the object.V₀ is the initial velocity of the object (i.e. its velocity at the time it started moving).a is the acceleration of the object (constant)t is the time elapsed since the start of the movement.We now know that the data is:
Vf = Final speed = 10 m/sVo = initial velocity = 2 m/st = time = 4 sBut since they are asking us to calculate the acceleration, we clear the formula:
a = (Vf - V₀) / tWhere:
a is the acceleration of the object (constant)Vf is the final velocity of the objectV₀ is the initial velocity of the objectt is the time elapsed since the start of the movement.This formula shows that the acceleration is equal to the difference between the final velocity and the initial velocity of the object, all divided by the elapsed time. It is important to note that final velocity and initial velocity must be in the same units (for example, meters per second) and that time must be in units of time (for example, seconds).
We substitute data in the formula, and calculate the acceleration:
a = (Vf - V₀)/t
a = (10 m/s - 2 m/s)/(4 s)
a = 2 m/s²
The acceleration of the lizard that has speeds between 2 m/s and 10 m/s, in a time of 4 seconds, is 2 m/s².
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Answer:
The lizard's average acceleration is 2 m/s².
Explanation:
The average acceleration of the lizard can be calculated using the formula:
[tex]\sf\qquad\dashrightarrow a = \dfrac{(V_f - V_o)}{t}[/tex]
where:
a is the accelerationVf is the final velocityVo is the initial velocityt is the timePlugging in the given values, we get:
[tex]\sf\qquad\dashrightarrow a = \dfrac{(10\: m/s - 2\: m/s)}{4\: sec}[/tex]
[tex]\sf\qquad\dashrightarrow a = \boxed{\bold{\:\:2\: m/s^2\:\:}}[/tex]
Therefore, the lizard's average acceleration is 2 m/s².
A billiard ball of mass 0.28 kg hits a second, identical ball at a speed of 8.6 m/s
and comes to rest as the second ball flies off. The collision takes 250 μs.
What is the average force on the first ball?
What is the average force on the second ball?
The average force on the first ball = - 272.8 N.
The average force on the second ball is 9,568 N, and it acts in the direction of its motion.
What is the principle of conservation?the principle of conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the two billiard balls can be considered as a closed system.
Let's define some variables:
m = (mass of each ball)
v1 = (initial velocity of the first ball)
v2 = (final velocity of the second ball)
t = 250 μs = 0.00025 s (duration of the collision)
According to the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision:
m * v1 = m * v2
Solving for v2, we get:
v2 = v1 * (m/m) = v1
This indicates that the second ball departs in the opposite direction of the first ball but with the same velocity. As a result, the system's total momentum is preserved.
The impulse-momentum theorem states that the impulse (change in momentum) is equal to the average force multiplied by the duration of the collision. We can use this to determine the average force on the first ball:
F1 * t = m * (v2 - v1)
Substituting the values we know, we get:
F1 * 0.00025 = 0.28 * (-8.6)
Solving for F1, we get:
F1 = - 272.8 N
The first ball's force is acting in the opposite direction of its initial velocity when the sign is negative.
To find the typical power on the subsequent ball, we can utilize a similar recipe:
F2 * t = m * (v2 - v1)
Substituting the values we know, we get:
F2 * 0.00025 = 0.28 * (v2 - 0)
Since we know that v2 = 8.6 m/s, we can solve for F2:
F2 = (0.28 * 8.6) / 0.00025
F2 = 9,568 N
Therefore, the average force on the second ball is 9,568 N, and it acts in the direction of its motion.
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1. Determine the temperature change that occurs when 2750 J of heat is
applied to 85.45 g of iron.
When 2750 J of heat are delivered to 85.45 g of iron, the resultant temperature change is 17.6 °C.
Which natural law and the first law of thermodynamics are the same?first rule. The law of conservation of energy has been thermodynamically modified to form the first law of thermodynamics. The conservation law states that energy can only be transformed from one form to another, not created or destroyed, which keeps the total energy of an isolated system constant.
q = mcΔT
where T is the temperature change, q is the heat energy, m is the mass, c is the specific heat capacity.
0.45 J/g°C is the specific heat capacity of iron. We can plug in the values given in the problem to find the temperature change:
q = mcΔT
2750 J = (85.45 g)(0.45 J/(g·°C))(ΔT)
ΔT = 17.6 °C
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When light enters a new medium it changes speeds and bends; creating optical illusions like this. Which type of wave interaction is this?
A. Refraction
B. Reflection
C.absorption
D.diffraction
The type of wave interaction that occurs when light enters a new medium, changes speeds, and bends, creating optical illusions like the one shown, is called refraction.
What is refraction?Refraction is the bending of light as it passes through a medium with a different refractive index. The refractive index is a measure of how much a material can slow down the speed of light passing through it. When light travels from one medium to another, such as from air to water or from water to glass, its speed changes and it bends as a result of the change in the refractive index.
This bending of light is what causes objects to appear shifted or distorted when viewed through lenses or other transparent materials. Refraction is also responsible for many optical phenomena, such as mirages, rainbows, and the dispersion of white light into its component colors.
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When a social position is accompanied by accepted patterns of behavior it becomes
Answer:
When a social position is accompanied by accepted patterns of behavior, it becomes a role. A role is a set of expectations and behaviors that are associated with a particular social position. For example, a doctor's role includes expectations such as providing medical care to patients, making diagnoses, and prescribing treatments. Similarly, a teacher's role includes expectations such as instructing students, grading assignments, and providing feedback on student progress. Roles are important in society because they help to create order and stability, and they allow individuals to understand their place in society and how they are expected to behave.
How do I draw a schematic of this circuit?
A schematic diagram is a graphical representation of an electrical circuit, showing the arrangement of components and their connections.
What is the schematic diagram of a circuit?The lines connecting the components in the schematic diagram represent wires or conductive paths.
The direction of the arrows and the polarity of the symbols indicate the direction of the flow of electrical current. The schematic diagram helps engineers and technicians understand the circuit and troubleshoot problems.
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If the atmospheric pressure is 15 lb/in^2, what is the corresponding downward force on the top of a horizontal square area 5 inches on each side?
Answer:
The downward force on the top of the horizontal square area can be found using the formula:
force = pressure x area
Given that the atmospheric pressure is 15 lb/in^2 and the square area is 5 inches on each side, the area can be calculated as:
area = length x width
= 5 inches x 5 inches
= 25 square inches
Substituting the values in the formula, we get:
force = 15 lb/in^2 x 25 square inches
= 375 lb
Therefore, the corresponding downward force on the top of the horizontal square area is 375 pounds.
The image above shows a magnetized object.
True
False
Indeed, a magnetised object with a north and south pole can be seen in the above photograph.
What is something that has magnetic north and south poles?Any object that creates a magnetic field of its own and interacts with other magnetic fields is a magnet. A magnet has two poles, the north pole and the south pole. Field lines that begin at the north pole and end at the south pole of a magnet are used to show the magnetic field.
What do the magnet's north and south poles represent?When hanging in the magnetic field of the Earth, a bar magnet automatically points northward and southward. A north magnetic pole is any pole that seeks the north, such as the north-seeking pole of this type of magnet.
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Assume Lake Erie contains 4.80 ✕ 1011 m3 of water, and assume the water's density is that of water at 20°C and 1 atm.
(a)
How much energy (in J) is required to raise the temperature of that volume of water from 11.2°C to 21.6°C?
(b)
How many years would it take to supply this amount of energy by using a power of 1,400 MW generated by an electric power plant?
.
For Part A, we can use the formula Q = mc(T'f - Ti) to calculate the energy required to raise the temperature of the water. Here, Q is the energy required, m is the mass of the water, c is the specific heat capacity of water at 20°C and 1 atm (4.184 J/g°C), T'f is the final temperature (21.6°C), and Ti is the initial temperature (11.2°C).
First, we need to find the mass of the water. Since density = mass/volume, we can rearrange the formula to get mass = density * volume. Plugging in the given values, we get:
mass = (998 kg/m^3) * (4.80 x 10^11 m^3) = 4.79 x 10^14 kg
Now, we can plug in the values into the formula above:
Q = (4.79 x 10^14 kg) (4.184 J/g°C) (21.6°C - 11.2°C) = 2.02 x 10^19 J
Therefore, it would require 2.02 x 10^19 J of energy to raise the temperature of Lake Erie from 11.2°C to 21.6°C.
For Part B, we can use the formula P = E/t to calculate the time required to supply the energy using a power of 1,400 MW. Here, P is the power in watts, E is the energy required in joules (which we found in Part A), and t is the time in seconds. Since we want the time in years, we can convert from seconds to years at the end by dividing by the number of seconds in a year (31,536,000 s).
First, we need to convert the power from MW to W:
P = 1,400 MW * (10^6 W/MW) = 1.4 x 10^9 W
Now, we can rearrange the formula to solve for t:
t = E / P = (2.02 x 10^19 J) / (1.4 x 10^9 W) = 1.44 x 10^10 s
Converting from seconds to years, we get:
t = 1.44 x 10^10 s / 31,536,000 s/year = 456.7 years (rounded to three significant figures)
Therefore, it would take approximately 457 years to supply the energy needed by using a power of 1,400 MW generated by an electric power plant.
How does the heat from the Sun reach us on Earth?
Answer:
through space and through the earth's atmosphere to the earth's surface.
Explanation:
The heat source for our planet is the sun. Energy from the sun is transferred through space and through the earth's atmosphere to the earth's surface. Since this energy warms the earth's surface and atmosphere, some of it is or becomes heat energy.
energy is transferred from the sun thru radiation. the atmosphere keeps a large amount of the heat and UV rays from burning us into crisps
In a tractor pull, a tractor put 250,000 J of work into pulling a large mass.
The tractor pulls the mass using 98,000N of force. How far did the
tractor pull the mass?
In a tractor pull, a tractor put 250,000 J of work into pulling a large mass. The tractor pulls the mass using 98,000N of force. The tractor pulled the mass to a distance of 2.55 meters
We may use the work done formula to solve this problem:
Work = Force x Distance x Cosine (angle between force and displacement)
Yet, because the force and displacement are applied in the same direction, the angle between them is zero, and the cosine of zero is one. As a result, we may reduce the formula to:
Work = Force x Distance
Because we know the work done is 250,000 J and the force exerted is 98,000 N, we can rewrite the formula to solve for distance:
Distance = Work / Force
Distance = 250,000 J / 98,000 N
Distance = 2.55 meters
As a result, The tractor pulled the mass to a distance of 2.55 meters
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