The light that passes through a polaroid filter is vibrating in a direction that is parallel to the polarization axis or transmission axis of the filter. Option b is correct.
Polaroid filters are made up of long-chain molecules that are aligned in a particular direction. These molecules only allow light waves that vibrate parallel to their alignment to pass through the filter.
The orientation of the light waves that pass through the filter is perpendicular to the polarization axis or transmission axis of the filter. Therefore, the light that passes through a polaroid filter is vibrating in a direction that is parallel to the polarization axis or transmission axis of the filter. Hence option b is correct choice.
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what is the natural frequency for a second order system with roots located by x in the complex plane?
The natural frequency of a second-order system is a critical parameter that determines the system's oscillatory behavior. In the complex plane, the roots of the characteristic equation are represented as complex conjugate pairs (a ± jω_n), where 'a' is the real part and 'ω_n' is the imaginary part.
The natural frequency, denoted by 'ω_n,' is the distance from the origin to either root on the imaginary axis. In a second-order system, the natural frequency is a key parameter that characterizes the system's oscillatory response. It determines how fast the system oscillates and its ability to maintain its energy during oscillation.
Higher natural frequencies typically result in faster oscillations and a higher energy conservation rate. When analyzing a second-order system, it is essential to understand the relationship between the natural frequency, damping ratio, and system response.
The damping ratio, denoted by 'ζ,' is another critical parameter that influences the system's behavior. If the damping ratio is less than 1, the system exhibits underdamped oscillations, and the imaginary part of the roots determines the natural frequency. If the damping ratio is equal to 1, the system is critically damped, and if the damping ratio is greater than 1, the system is overdamped.
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One summer afternoon, Kim heard on the news that the humidity in Ocala, Florida was 80%. How would the air feel when Kim goes outside?
Group of answer choices
cold and dry
warm and wet
cold and wet
warm and dry
an airplane accelerates at a constant speed at 30m/s2
Now that s=u*t+at2 is being used, s =0*+302 equals 300 m. For instance, if the plane was travelling at 300 m/s2, its final velocity before it took off was 30 m/s2.
What does the term mean when an aeroplane is travelling at a fixed speed?If there isn't a net force exerted on the item that would cause it to accelerate, there is constant velocity. Drag and thrust are the two primary forces affecting the forward motion of an aeroplane.
when a plane is travelling at a constant speed on a level, straight path?The lift and push produced by an aeroplane while it is travelling level and straight at a steady velocity balance its weight and drag, respectively. Yet, as the aircraft climbs and descends, speeds up or slows down, and turns, the balance of forces varies.
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why is the lifetime in the atmosphere be a problem if cfs are no longer being produced
Answer:CFCs and halons cause chemical reactions that break down ozone molecules, reducing ozone's ultraviolet radiation-absorbing capacity
Explanation:
a rotating wheel requires 6.00 s to rotate 25.0 revolutions. its angular velocity at the end of the 6.00-s interval is 95.0 rad/s. what is the constant angular acceleration (in rad/s) of the wheel?
The constant angular acceleration of the wheel is 43.9 rad/[tex]s^2[/tex].
We can use the formula for constant angular acceleration: ωf = ωi + αt
where:
ωi = initial angular velocity = 0 (as the wheel starts from rest)
ωf = final angular velocity = 95.0 rad/s
t = time interval = 6.00 s
α = constant angular acceleration (to be found)
We can also use the formula for the number of revolutions (N) in terms of angular displacement (θ): N = θ / (2π)
where θ is the total angular displacement. Since the wheel completes 25 revolutions, its total angular displacement is: θ = 25 * 2π = 50π
Using the formula for angular displacement with constant angular acceleration: θ = ωit + 0.5α*[tex]t^2[/tex]
Substituting the given values and simplifying:
50π = 0 + 0.5α(6.00)
α = 50π / (0.5*(6.00)^2) = 43.9 rad/[tex]s^2[/tex]
Therefore, the constant angular acceleration of the wheel is 43.9..
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the study of heat energy that is involved in chemical and physical changes is: group of answer choices equilibrium efficiency thermodynamics constant none of the above
The study of heat energy that is involved in chemical and physical changes is thermodynamics.
The correct option is "Thermodynamics."
Thermodynamics is the study of heat energy involved in chemical and physical changes. It is a branch of physics that deals with the relationship between heat and other forms of energy, as well as the laws governing energy conversion.
In simple terms, thermodynamics is the study of how energy is transformed from one form to another. It also examines the relationship between heat, work, and temperature, as well as the nature of energy and entropy. Thermodynamics is widely utilized in fields such as chemistry, physics, and engineering, among others.
Therefore, "Thermodynamics" is the correct answer.
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you push a box (mass 3 kg) so that its initial speed is 2.5 m/s. it slides across a rough floor (coefficient of kinetic friction 0.41). what is the initial kinetic energy of the box
The initial kinetic energy of the box is 9.375 J.
The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force.
The initial kinetic energy of the box can be calculated by using the formula:
KE = 1/2 mv²
where
KE represents the initial kinetic energy,
m represents the mass of the box, and
v represents the initial velocity of the box.
As per given information in question,
Initial velocity (v) of the box = 2.5 m/s
Mass of the box (m) = 3 kg
Initial kinetic energy (KE)
= 1/2 × 3 kg × (2.5 m/s)²
= 9.375 J
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what distance between the two lenses will allow the telescope to focus on an infinitely distant object and produce an infinitely distant image?
The distance between the two lenses must be greater than or equal to the sum of the focal lengths of the lenses when a telescope is used to focus on an infinitely distant object .
When a telescope is used to focus on an infinitely distant object and generate an infinitely distant image, the distance between the two lenses is equal to the sum of their focal lengths.
What is a telescope?A telescope is a tool used to magnify and concentrate the image of a distant object. Refracting and reflecting telescopes are the two main types of telescopes.
For the most part, a telescope utilizes a lens to collect and focus light. The focal length of the objective lens determines the magnification of the telescope.When the light rays leave the eyepiece and appear to have originated from the distant object, the image is formed.
The distance between the objective lens and the eyepiece is the key distance in a telescope. The length of the telescope's tube is also important because it determines the separation between the lenses and the lens's focal lengths. .
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violet light of wavelength 407 nm ejects electrons with a maximum kinetic energy of 0.764 ev from a certain metal. what is the work function of this metal (in ev)?
Violet light of wavelength 407 nm ejects electrons with a maximum kinetic energy of 0.764 eV from a certain metal. the work function of this metal is approximately 4.1 eV.
We can use the following equation to relate the maximum kinetic energy of the ejected electrons to the work function of the metal and the energy of the incident photons:
Kinetic energy of expelled electrons = incident photon energy - metal work function
We are given the wavelength of the incident photons, which we can use to find their energy using the formula:
Energy of photon = hc/λ
where h = 6.626 x 10^-34 J s is Planck's constant, c = 3.00 x 10^8 m/s is the speed of light, and λ = 407 nm = 4.07 x 10^-9 m is the wavelength of the incident light.
Substituting the given values, we get:
Energy of photon = hc/λ
Energy of photon = (6.626 x 10^-34 J s) x (3.0 x 10^8 m/s) / (407 x 10^-9 m)
Energy of photon ≈ 4.86 eV
Now we can use the first equation to find the work function of the metal:
Work function of the metal = Energy of incident photons - Kinetic energy of ejected electrons
Work function of the metal = 4.86 eV - 0.764 eV ≈ 4.1 eV
Therefore, the work function of this metal is approximately 4.1 eV.
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A spaceship has a mass of 9000 kg. The spaceship is launched from Earth and lands on a distant planet where it has a weight of 390,000 N. What is the acceleration of gravity on this planet?
now use a right hand rule to determine the direction of the current in the coil that would produce the poles determined in the previous question. the current direction must be:
The current direction must come from the left side and out of its right side.
So option B is right choice.
The right-hand rule is a method that is frequently used in physics to determine the direction of the magnetic field produced by a current-carrying wire.
The direction of the magnetic field generated by the current is determined by the direction of the current. It can be determined by using a simple technique called the "Right-Hand Rule."
Position your right hand such that your thumb points in the direction of the current flow in the coil. Wrap your fingers around the coil in the direction of the magnetic field generated by the current. Curl your fingers around the coil in the direction of the magnetic field produced by the current, with your thumb pointing in the direction of the current.
The current direction in the coil that current enters from left side and comes out from right side.
The current direction in the coil is opposite to the magnetic field, hence it should be flowing from left to right.
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Question:-
Now use a right hand rule to determine the direction of the current in the coil that would produce the poles. The current direction must be:
A. Into the ammeter on both sides.
B. Into the ammeter's left side and out of its right side.
C. Out of the ammeter on both sides.
D. Into right side and out of its left side.
if a line drive is hit essentially horizontally at this speed and is caught by a 71.0 kg player who has leapt directly upward into the air, what horizontal speed (in cm/s ) does he acquire by catching the ball?
If a line drive is hit essentially horizontally at this speed and is caught by a 71.0 kg player who has leapt directly upward into the air, The momentum before and after the collision (catch) should be equal.
Step 1: Calculate the initial momentum of the baseball
Initial momentum of the baseball = mass_baseball × velocity_baseball
Step 2: Calculate the initial momentum of the player
The initial momentum of the player = 0 (since the player is leaping directly upward, his horizontal momentum is 0)
Step 3: Calculate the total initial momentum
Total initial momentum = initial momentum of the baseball + initial momentum of the player
Step 4: Calculate the final momentum
Since the player catches the baseball, their momenta combine.
Final momentum = (mass_baseball + mass_player) × final_velocity_player
Step 5: Apply the conservation of momentum principle
Total initial momentum = Final momentum
Step 6: Solve for the final_velocity_player
final_velocity_player = Total initial momentum / (mass_baseball + mass_player)
Step 7: Convert the final_velocity_player to cm/s (1 m/s = 100 cm/s)
By following these steps with the given data (mass_baseball, velocity_baseball, and mass_player), you can calculate the horizontal speed of the player in cm/s after catching the ball.
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a rocket ship at rest in space gives a short blast of its engine, firing 65 kg of exhaust gas out the back end with an average velocity of 450 m/s. what is the magnitude of the change in momentum of the rocket during this blast?
The magnitude of the change in momentum of the rocket during this blast is 29250 N-s. A rocket ship at rest in space gives a short blast of its engine, firing 65 kg of exhaust gas out the back end with an average velocity of 450 m/s.
During a short blast of its engine, the rocket ship fires 65 kg of exhaust gas out of the back end at an average velocity of 450 m/s. The change in momentum of the rocket during the blast can be calculated using the law of conservation of momentum, which states that the total momentum of an isolated system remains constant if no external forces act upon it.
A rocket's initial momentum is zero since it is at rest. Therefore, the change in momentum of the rocket is equal to the momentum of the exhaust gas exiting the back end of the rocket.
The magnitude of the change in momentum of the rocket during this blast can be calculated as follows: Change in momentum of the rocket = Momentum of exhaust gas= (mass of exhaust gas) x (velocity of exhaust gas)= 65 kg x 450 m/s= 29250 N-s.
Therefore, the magnitude of the change in momentum of the rocket during this blast is 29250 N-s.
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what must the rms voltage of the source be if the coil is to consume an average electrical power of 750 w ?
The RMS voltage required to supply an average power of 750 W to the coil is simply 1 volt.
To determine the root mean square (RMS) voltage of a source required to supply an average electrical power of 750 watts to a coil, we need to use the formula:
Average Power = RMS Voltage * RMS Current * Power Factor
Assuming that the power factor is 1 (i.e., the coil is purely resistive), the formula simplifies to:
Average Power = RMS Voltage * RMS Current
Since power is the product of voltage and current, we can write:
RMS Current = (Average Power / RMS Voltage)
Substituting the given values, we get:
RMS Current = (750 W / RMS Voltage)
To determine the RMS voltage required to supply the average power of 750 W, we need to solve for RMS voltage by rearranging the formula as follows:
RMS Voltage = (Average Power / RMS Current)
RMS Voltage = (750 W / RMS Current)
Substituting the expression for RMS current, we get:
RMS Voltage = [750 W / (750 W / RMS Voltage)]
RMS Voltage = RMS Voltage
Therefore, the RMS voltage required to supply an average power of 750 W to the coil is simply 1 volt.
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two long, straight wires are parallel and 5 cm apart. one carries a current of 2.0 a, the other a current of 5.0 a. if the two currents flow in the same directions, what is the magnitude and direction of the force per unit length of one wire on the other? group of answer choices
The magnitude of the force a unit length of one wire on the other is 2.0 × 10⁻⁵ N/m.
The direction of the force can be found using the right-hand rule: if you point your right thumb in the direction of the current in one wire, and your fingers in the direction of the current in the other wire, the direction of the force is perpendicular to both, pointing towards the other wire.
Thus, the force a unit length is given by:
F =[tex]\mu_o * I_1 * I_2 * L / (2 * \pi * d)[/tex]
= (4π × 10⁻⁷ N/A²) * (2.0 A) * (5.0 A) * (1 m) / (2 * π * 0.05 m)
= 2.0 × 10⁻⁵ N/m
Newton's laws of motion, which indicate that unless acted upon by a net external force, an object will stay at rest or in uniform motion along a straight line, describe force. According to the second rule of motion, an object's acceleration is inversely proportional to its mass and directly proportional to the net force exerted on it. This law is expressed mathematically as F = ma, where F is the net force, m is the mass of the object, and a is its acceleration.
Forces can be contact forces, such as friction and tension, or non-contact forces, such as gravity and electromagnetic forces. Understanding forces is important in many fields, including physics, engineering, and mechanics, and is necessary for designing structures, machines, and vehicles that can withstand and utilize them.
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two conducting spheres have radii of r1 and r2, with r1 greater than r2. if they are far apart the capacitance is proportional to:
"Two conducting spheres have radii of r1 and r2, with r1 greater than r2. If they are far apart the capacitance is proportional to: 1/r1 - 1/r2
The capacitance of two conducting spheres with radii r1 and r2, where r1 is greater than r2, and they are far apart is proportional to the difference in inverse radii. This can be written as:
C = k (A / d)
where C is the capacitance, k is the proportionality constant, A is the surface area, and d is the distance between the two spheres.
The surface area of a sphere is proportional to r^2,
so:C ∝ A = k (r1^2 + r2^2)
The inverse of capacitance is proportional to the difference in inverse radii,
so:1/C ∝ 1/(r1 - r2)
1/C = k' (1/r1 - 1/r2)
where k' is another proportionality constant, which combines with k to give the final constant of proportionality.
Therefore, the capacitance of two conducting spheres with radii r1 and r2, where r1 is greater than r2, and they are far apart is proportional to: 1/r1 - 1/r2.
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the earth has a radius of about 6000 km. how long would it take for an object traveling at the speed of light to circle the earth? (recall that the speed of light is 300,000 km/s.) group of answer choices 1/8 of a second (0.125 s) 1/6000 of a second (0.000017 s) 1/2 of a second (0.5 s) 1/300,000 of a second (0.0000033 s)
Answer:
S = 2 π R = 2 π * 6.0E6 m = 3.8E7m distance traveled
t = S / v = 3.8E7 / 3.0E8 = .013 sec
1/8 sec is closest
An object traveling at the speed of light will take 0.125 s to circle the earth.The correct option is therefore 1/8 of a second (0.125 s).
Recall that the circumference of a circle is given as 2πr, where r is the radius. Therefore, the circumference of the Earth is given as:
C = 2πr = 2 x 3.14 x 6000 kmC = 37680 km
Therefore, the time it takes for an object traveling at the speed of light (300,000 km/s) to circle the Earth is given by:
T = Distance / SpeedT = 37680 km / 300000 km/sT = 0.1256 s
Therefore, it will take an object traveling at the speed of light about 1/8 of a second (0.125 s) to circle the Earth. Therefore, the correct option is 1/8 of a second (0.125 s).
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a nuclear reactor is used to provide heat to a steam power plant. within the heat engine, steam is generated in the boiler, the steam turns a turbine to produce power, and the steam is condensed by rejecting heat to the atmosphere before being pumped to the boiler again. which substance is considered the working fluid in this heat engine?
In the described heat engine, the working fluid is steam. Steam is produced by heating water in the boiler using the heat generated by the nuclear reactor.
The high-pressure steam then turns the turbine, producing mechanical work, which is then converted into electrical energy. As the steam expands and loses its energy, it is condensed into water by rejecting heat to the atmosphere in the condenser.
This water is then pumped back into the boiler to be heated again and converted into steam, thus completing the cycle. Steam is an excellent working fluid for this type of heat engine because it has a high heat capacity, which means that it can store a lot of heat energy per unit mass.
Additionally, it undergoes a phase change when it is heated, which allows it to expand and produce mechanical work when it is under pressure. Finally, steam is readily available and relatively cheap to produce, making it an ideal choice for powering large-scale steam power plants.
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Complete question is:
A nuclear reactor is used to provide heat to a steam power plant. Within the heat engine, steam is generated in the boiler, the steam turns a turbine to produce power, and the steam is condensed by rejecting heat to the atmosphere before being pumped to the boiler again. Which substance is considered the working fluid in this heat engine? The water going through the boiler, turbine, and condenser
a steady current flows through an inductor. if the current is doubled while the inductance remains constant, the amount of energy stored in the inductor group of answer choices increases by a factor of 4. increases by a factor that depends on the geometry of the inductor. none of the above. increases by a factor of 2. increases by a factor of
The energy stored in the inductor is doubled when the current is doubled. The amount of energy stored in the inductor increases by a factor of 4. Here option A is the correct answer.
The amount of energy stored in an inductor is given by the formula: E = 0.5 × L × I^2, where L is the inductance and I is the current flowing through the inductor.
If the current through an inductor is doubled while the inductance remains constant, then the energy stored in the inductor will increase by a factor of 4. This can be seen by substituting 2I for I in the formula:
E' = 0.5 × L × (2I)^2
= 0.5 × L × 4I^2
= 2 × (0.5 × L × I^2)
= 2E
When the current through an inductor is doubled while the inductance remains constant, the amount of energy stored in the inductor increases by a factor of 4. This is because the energy stored in an inductor is directly proportional to the square of the current flowing through it, as expressed by the formula E = 0.5 × L × I^2, where E is the energy stored, L is the inductance, and I is the current.
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Complete question:
A steady current flows through an inductor. if the current is doubled while the inductance remains constant, the amount of energy stored in the inductor group of answer choices
A - increases by a factor of 4.
B - increases by a factor that depends on the geometry of the inductor.
C - increases by a factor of 2.
D - none of the above.
Which type of modulation is used by remote-control toys?
amplitude
frequency
phase
pulse
Remote-control toys make use of pulse code modulation.
Which modulation type is used in radio-controlled toys?Pulse-width modulation (PWM), pulse-position modulation (PPM), and more recently spread-spectrum technology are used in typical radio control systems for radio-controlled models, and servomechanisms are used to activate the various control surfaces. Digital modulation is used in all current infrared remote control designs. Amplitude Shift Keying (ASK) and Frequency Shift Keying (FSK) are two fundamental types of digital modulation. (FSK).
What is the purpose of amplitude modulation?Electronic communication is where amplitude modulation is most commonly utilised. This method is being utilised in numerous communication channels, including computer modems, citizens band radio, VHF aviation radio, and portable two-way radios.
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the specific gravity of ice is 0.917, whereas that of seawater is 1.025. what percent of an iceberg is above the surface of the water?
The specific gravity of ice is 0.917, whereas that of seawater is 1.025. Approximately 89.51% of an iceberg is above the surface of the water.
To find out what percent of an iceberg is above the surface of the water, we need to use Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
This means that an iceberg will float in water because it displaces an amount of water that weighs more than the iceberg itself.
The percentage of an iceberg above the surface of the water can be found using the following equation:
Percent above water = (Volume of iceberg above water / Total volume of iceberg) x 100
To find the volume of an iceberg above the water, we can use the following equation:
Volume of iceberg above water = Volume of iceberg x (Density of ice / Density of seawater)
So,Percent above water = [(Volume of iceberg x (Density of ice / Density of seawater)) / Total volume of iceberg] x 100
Percent above water = [(1 x (0.917 / 1.025)) / 1] x 100
Percent above water = 89.51%
Therefore, approximately 89.51% of an iceberg is above the surface of the water.
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or a given experiment, the students know how much the angular momentum of the system has changed after a specific time interval. the students create a series of graphs for each experiment. the students must determine if the change in angular momentum of a given system is equal to the angular impulse applied to the system. how should the students use data from a particular graph to make the determination by using only the graph?
The students should look at the change in angular momentum on the y-axis of the graph and compare it to the angular impulse applied to the system, which should also be on the y-axis.
If the two values are equal, the angular momentum of the system is unchanged and the angular impulse applied to the system is equal to the change in angular momentum. If the two values are not equal, then the angular impulse applied to the system is not equal to the change in angular momentum.
The students should look at the x-axis of the graph and compare the time intervals of the angular impulse and the change in angular momentum to ensure they are the same. If the two time intervals are not equal, the angular impulse and the change in angular momentum are not equal and the angular impulse applied to the system is not equal to the change in angular momentum.
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show that the power dissipated by the load resistor is maximum when the resistance of the load resistor is equal to the internal resistance of the battery.
When the resistance of the load resistor is equal to the internal resistance of the battery, the power dissipated by the load resistor is maximum. This is known as the maximum power transfer theorem.
What is the maximum power transfer theorem?The maximum power transfer theorem in electrical engineering states that the power produced by a source and delivered to a load is at its highest when the resistance of the load is equal to the internal resistance of the source.
In other words, if the load is equal to the internal resistance of the source, maximum power will be transferred between the source and the load.
According to the theorem, the power transferred to the load is at its maximum when the resistance of the load is equal to the internal resistance of the source. To show that the power dissipated by the load resistor is maximum when the resistance of the load resistor is equal to the internal resistance of the battery, follow the steps mentioned below:
1. Calculate the output voltage V0 and the output current I0 for the load resistor (RL) and the internal resistance of the battery (Ri).
2. Calculate the power dissipated by the load resistor (PL) as a function of RL.
3. In order to find the maximum value of PL, we need to differentiate the above expression with respect to RL and set it to zero. We get RL = Ri.When RL = Ri, the power dissipated by the load resistor is at its maximum.
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A 47 N box is pulled along a frictionless horizontal surface by a 25 N weight brining from a cord on a frictionless pulley. A. What is the box’s mass? B. What is the weights mass? C. What is the box’s acceleration? D. What is the magnitude of the force exerted on the cord?
The force exerted on the cord is equal to the force acting on the weight, which is 25 N.
How to solveTo solve this problem, we'll apply Newton's second law of motion (F = ma) and work through each part step by step.
A. What is the box's mass?We know the force acting on the box (F_box) is 47 N. Using Newton's second law, we can find the mass of the box:
F_box = m_box * a
m_box = F_box / a
However, we don't know the acceleration yet. To find that, we'll first need to analyze the forces acting on the system.
B. What is the weight's mass?We know the force acting on the weight (F_weight) is 25 N. The force is equal to the gravitational force acting on the weight:
F_weight = m_weight * g
m_weight = F_weight / g
where g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, we get:
m_weight = 25 N / 9.81 m/s^2 ≈ 2.55 kg
C. What is the box's acceleration?Now let's analyze the forces acting on the system. The net force acting on the box is the force exerted by the cord (F_cord), which is equal to the force acting on the weight (F_weight):
F_cord = F_weight
The net force acting on the box is also equal to the product of its mass and acceleration:
F_box = m_box * a
Since F_cord = F_weight = F_box, we can set up the following equation:
m_box * a = m_weight * g
We already know m_weight and g, so we can solve for the acceleration (a):
a = (m_weight * g) / m_box
We still need to find m_box. We can do this by rearranging the equation from part A:
m_box = F_box / a
Now, we have:
a = (m_weight * g) / (F_box / a)
Solving for a, we get:
a^2 = (m_weight * g) / F_box
a = sqrt((m_weight * g) / F_box)
Plugging in the values, we get:
a = sqrt((2.55 kg * 9.81 m/s^2) / 47 N) ≈ 0.86 m/s^2
Now that we have the acceleration, we can find the box's mass:
m_box = F_box / a ≈ 47 N / 0.86 m/s^2 ≈ 54.65 kg
D. What is the magnitude of the force exerted on the cord?The force exerted on the cord is equal to the force acting on the weight, which is 25 N.
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a person exerts a horizontal force of 42 n on the end of a door 96 cm wide. what is the magnitude of the torque if the force is exerted (a) perpendicular to the door and (b) at a angle to the face of the door?
(A) perpendicular distance = (1/2) x 96 cm = 48 cm = 0.48 mSo, torque = force x perpendicular distance from the pivot= 42 N x 0.48 m= 20.16 Nm (B)The magnitude of the torque when the force is exerted perpendicular to the door is 20.16 Nm, and the magnitude of the torque when the force is exerted at an angle of 60° to the face of the door is 14.380 Nm.
We know that a person exerts a horizontal force of 42 N on the end of a door 96 cm wide. We need to find the magnitude of the torque if the force is exerted perpendicular to the door and at an angle to the face of the door.
(a) Torque when the force is exerted perpendicular to the door, the torque is given by the formula:
Torque = force x perpendicular distance from the pivot
We can see that the force is perpendicular to the door. So, the perpendicular distance from the pivot is equal to the distance of the line of action of the force from the pivot, which is half the width of the door.
Therefore, perpendicular distance = (1/2) x 96 cm = 48 cm = 0.48 mSo, torque = force x perpendicular distance from the pivot= 42 N x 0.48 m= 20.16 Nm
(b) Torque when the force is exerted at an angle to the face of the door
When the force is exerted at an angle to the face of the door, the torque is given by the formula: Torque = force x perpendicular distance from the pivot x sin θ
Here, θ is the angle between the force and the perpendicular to the door. We need to find the perpendicular distance from the pivot, which is equal to the distance of the line of action of the force from the pivot along the perpendicular bisector of the door. Let us assume that the angle between the force and the door is θ = 60°. In this case, the perpendicular distance from the pivot can be calculated as follows:
Perpendicular distance = (1/2) x 96 cm x sin 60°
= (1/2) x 96 cm x (sqrt(3)/2)
= 48 cm x (sqrt(3)/2)
= 41.569 cm
= 0.4169 m
So, torque = force x perpendicular distance from the pivot x sin θ= 42 N x 0.4169 m x sin 60°
= 14.380 Nm
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an 1,810 w toaster, a 1,440 w electric frying pan, and a 60 w lamp are plugged into the same outlet in a 15 a, 120 v circuit. (the three devices are in parallel when plugged into the same socket.) (a) what current (in a) is drawn by each device?
Explanation:
Watts = amp * volts
watts/ volts = amps
1810 w / 120 v = 15.5 A
1440 w / 120 v = 12 A
60 w/ 120 v = .5 A
In reality, they are probably drawing ZERO amps as the circuit breaker (15 Amps as given) will likely trip or the wires will burn !
The current drawn by each device in a parallel circuit is determined by the resistance of each device.
Since the toaster has the highest resistance, it will draw the least amount of current, while the electric frying pan with the lowest resistance will draw the highest current. The lamp, being a light bulb, will draw a medium amount of current.
Using Ohm's law, the current drawn by each device can be calculated as follows:
Toaster: 1,810 W ÷ 120 V = 15.08 A
Electric Frying Pan: 1,440 W ÷ 120 V = 12 A
Lamp: 60 W ÷ 120 V = 0.5 A
Since all three devices are connected in parallel, the total current drawn from the outlet will be the sum of the individual currents drawn by each device, which is 15.58 A. This is below the maximum current rating of the circuit (15 A), so the circuit is safe.
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galaxy evolution is a very active area of research. look for information on current or future observatories that investigates galaxy evolution (such as the james webb space telescope). how big are the telescopes? at what wavelengths do they look? when are they built? why are they suited for studying galaxy evolution?
Galaxy evolution is a very active area of research, and there are several current and future observatories that investigate galaxy evolution, such as the James Webb Space Telescope (JWST).
These telescopes are quite large, with the JWST being the largest telescope ever built. It has a primary mirror that is 6.5 meters in diameter and is composed of 18 hexagonal mirror segments. The JWST will observe the universe at infrared wavelengths, between 0.6 and 28 micrometers.
The JWST is set to launch in 2021, and it will be the most advanced space telescope ever built. Its large size and infrared capabilities make it ideally suited for studying galaxy evolution. By observing galaxies in the infrared, the JWST will be able to see through the dust that often obscures the visible light emitted by galaxies.
The James Webb Space Telescope is a large telescope that will observe the universe at infrared wavelengths, and it is ideally suited for studying galaxy evolution. Its large size and infrared capabilities will allow astronomers to study the early stages of galaxy formation and evolution, which is a key area of research in astronomy.
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Observer A is on the left and observer B is on the right
Answer:
D
Explanation:
This is a Doppler effect question. The answer is D because observer A hears a lower pitch than observer B, who hears a higher pitch. Look at how much closer together the sound waves are on the right vs. the left. The closer together the waves, the higher the frequency and the higher the pitch.
a truck and a bicycle are moving side by side with the same velocity. which, if either, will require the larger impulse to bring it to a halt?
The truck will require a larger impulse to bring it to a halt compared to the bicycle. Impulse is defined as the change in momentum of an object, which is the product of its mass and velocity.
Since both the truck and bicycle have the same velocity, their momentum will be proportional to their mass. The truck has a much larger mass compared to the bicycle, which means that it will require a greater impulse to bring it to a halt. This is because the larger mass of the truck means it has a greater inertia and will resist changes in its motion, such as slowing down or coming to a stop.
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whispering gallery: the figure below shows the specifications for an elliptical ceiling in a hall designed to be a whispering gallery. in an whispering gallery, a person standing at one focus of the ellipse can whisper and be heard by another person standing at the other focus, because all the sound waves that reach the ceiling from one focus are reflected to the other focus. if the hall below is 140 feet in length with 30 feet tall ceiling at its highest point. how far from the end walls will the foci point be?
The foci points are approximately 6.75 feet away from the end walls.
To find the distance from the end walls to the foci points in a whispering gallery, you need to use the properties of an ellipse.
For the given hall, the length (140 feet) represents the major axis, and the highest point of the ceiling (30 feet) represents the distance between the center of the ellipse and the top or bottom vertex.
First, find the semi-major axis (a) and the semi-minor axis (b). Since the length is the major axis, divide it by 2 to get the semi-major axis:
a = 140/2 = 70 feet
The highest point of the ceiling is the distance from the center of the ellipse to the top vertex, which is equal to the semi-minor axis:
b = 30 feet
Now, use the formula for the distance between the center of the ellipse and the foci points, which is given by the equation:
c = [tex]\sqrt{(a^2 - b^2)}[/tex]
Plug in the values of a and b:
c = [tex]\sqrt{(70^2 - 30^2)}[/tex]
c = [tex]\sqrt{(4900 - 900)}[/tex]
c = [tex]\sqrt{(4000)}[/tex]
c = 20√10 feet
So, the distance between the center of the ellipse and each focus point is 20√10 feet.
To find the distance from the end walls to the foci points, subtract this distance from the semi-major axis:
Distance from end walls to foci points = a - c
Distance = 70 - 20√10 ≈ 70 - 63.25 ≈ 6.75 feet
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