Evaluate the expression

p ∧ q (i.e. "p and q") is true only if both p and q are true. This is the case for the first two rows, but not the third.

Similarly, (p ∧ q) ∧ r is true only if both p ∧ q and r are true. We know when p ∧ q is true, so (p ∧ q) ∧ r is true only when all three of p, q, and r are true. This happens only in the first row.

All other cases are false.

The table should look like this:

[tex]\begin{array}{c|c|c|c|c}p&q&r&p\land q&(p\land q)\land r) \\---&---&---&---&--- \\T&T&T&\boxed T&\boxed T\\&&&&\\T&T&F&\boxed T&\boxed F\\&&&&\\T&F&T&\boxed F&\boxed F\end{array}[/tex]

The comparison of both resistors is defined by an inequality. Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]

Given that:

[tex]R = 100 \Omega[/tex] ---- the reference resistor

First, we calculate the resistance of both resistors

Resistor A differs by [tex]0.15\Omega[/tex] means that:

[tex]R_A = 100\Omega + 0.15\Omega[/tex]

[tex]R_A = 100.15\Omega[/tex]

Resistor A has a resistance of [tex]100.15\Omega[/tex]

Resistor B differs by [tex]-0.78\Omega[/tex] means that:

[tex]R_B = 100\Omega -0.78\Omega[/tex]

[tex]R_B = 99.22\Omega[/tex]

Resistor B has a resistance of [tex]99.22\Omega[/tex]

By comparing the calculated values, we can conclude that:

Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]

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Answer:

90,000+9,000+700+60+3

Answer:

90,000 + 9,000 + 700 + 60 + 3 I hope this helped

Answer:

(M-5rt^2)/(-2r) =v

Step-by-step explanation:

M = 5rt^2- 2rv

Subtract  5rt^2 from each side

M-5rt^2 = 5rt^2- 2rv -5rt^2

M-5rt^2 = - 2rv

Divide each side by -2r

(M-5rt^2)/(-2r) =- 2rv / (-2r)

(M-5rt^2)/(-2r) =v

Answer:

[tex]v = -\frac{M-5rt^2}{2r}[/tex]

Step-by-step explanation:

[tex]M = 5rt^2 - 2rv[/tex]

Switch sides

[tex]5rt^2-2rv=M[/tex]

Subtract [tex]5rt^2[/tex] from both sides

[tex]5rt^2 - 2rv-5rt^2= M -5rt^2[/tex]

Simplify

[tex]-2rv = M - 5rt^2[/tex]

Divide both sides by [tex]-2r[/tex]

[tex]\frac{-2rv}{-2r} =\frac{M}{-2r} -\frac{5rt^2}{-2r}[/tex]

Simplify

[tex]-\frac{M-5rt^2}{2r}[/tex]

Answer:

Part A)

[tex]\displaystyle R'(t) = (5000-240t)(120-t^2)+(5000t-120t^2)(-2t)[/tex]

Part B)

After three months, the revenue is increasing at a rate of $391,560 per month.

Step-by-step explanation:

A product is introduced into the market. The quantity per month q sold is given by the function:

[tex]q(t) = 5000t - 120t^2[/tex]

And the price p (in dollars) of the product is given by the function:

[tex]p(t) = 120-t^2[/tex]

Part A)

R(t), or the revenue, will be the product of the quantity sold and its respective price during the month. Hence:

[tex]\displaystyle R(t) = q(t)\cdot p(t)[/tex]

Substitute:

[tex]\displaystyle R(t) = \left(5000t-120t^2\right)\left(120-t^2\right)[/tex]

To find R'(t), take the derivative of both sides with respect to t:

[tex]\displaystyle R'(t) = \frac{d}{dt}\left[ \left(5000t-120t^2\right)\left(120-t^2\right)\right][/tex]

Since the function is a product of two expressions, we can consider using the Product Rule:

[tex]\displaystyle \frac{d}{dx} \left[uv\right] = u'v+uv'[/tex]

Hence:

[tex]\displaystyle R'(t) = \frac{d}{dt}\left[5000t-120t^2\right]\left(120-t^2\right) + \left(5000t-120t^2\right)\frac{d}{dt}\left[120-t^2\right][/tex]

Differentiate. Therefore:

[tex]\displaystyle R'(t) = (5000-240t)(120-t^2)+(5000t-120t^2)(-2t)[/tex]

(We may simplify if we desire, but this is not required by the problem.)

Part B)

To find the rate of change of revenue with respect to time three months after the introduction, we can evaluate R'(t) at t = 3. Hence:

[tex]\displaystyle R'(3) = (5000-240(3))(120-(3)^2)+(5000(3)-120(3)^2)(-2(3))[/tex]

Evaluate:

[tex]R'(3) = 391560\text{ dollars/month}[/tex]

In conclusion, after three months, the revenue is increasing at a rate of $391,560 per month.

(Note: it is increasing because the final value is positive.)

Answer: 2 13/ 15

Step-by-step explanation:

The range of the exponential function is: B. [tex]g(x)>-6[/tex]

Recall:

Range of any function includes all possible values of y (output)

Domain of any function includes all possible values of x (input).

Thus:

The values of y in the exponential function greater than -6 on the y-axis as shown in the graph given.

Therefore:

Range of the exponential function given in the graph is: B. [tex]g(x)>-6[/tex].

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Step-by-step explanation:

First let solve the inequality

[tex]5 {x}^{2} + 2x - 3 < 0[/tex]

Factor by grouping

[tex]5 {x}^{2} + 5x - 3x - 3 < 0[/tex]

[tex]5x(x + 1) - 3(x + 1)[/tex]

So the factor are

[tex](5x - 3)(x + 1)[/tex]

So the factor are

[tex]x = \frac{3}{5} [/tex]

and

[tex]x = - 1[/tex]

Solutions to a quadratic can be represented by a absolute value equation because remeber quadratics

creates 2 roots and/or double roots.

The inequality

[tex] |x - b| < c[/tex]

works as

b is the midpoint between 2 roots. And c is the

[tex] |x + b| = c[/tex]

We know that the midpoint between both roots is-1/5.

so

[tex] |x - ( - \frac{1}{5} )| < c[/tex]

[tex] |x + \frac{1}{5} | < c[/tex]

Let use roots 3/5

[tex] | \frac{3}{5} + \frac{1}{5} | = \frac{4}{5} [/tex]

-1 works as well.

[tex] | - 1 + \frac{1}{5} | = | - \frac{4}{5} | = \frac{4}{5} [/tex]

So the absolute value equation is

[tex] |x + \frac{1}{5} | < \frac{4}{5} [/tex]

Answer:

2

Step-by-step explanation:

=3+5×5-25+3-4

=3+25-25+3-4

=28-22-4

=28-26

=2

Answer:

2

Step-by-step explanation:

3 + 5 * 5 - 50 / 2 + 3 - 4

3 + (5 * 5) - 50 / 2 + 3 - 4  => Multiplication what ever comes first

3 + 25     (-50 / 2) + 3 - 4  => Division left to right

(3 + 25)     - 25  +( 3 - 4)  => Addition what ever comes first

28  - 25 - 1 => Substraction  left to right

2

Leave comment if you're curious.

[tex]\boxed{\sf \:\begin{cases}\\\begin{gathered} {\underline{{ \sf {\blue{\Large\bf \underbrace{ {\rm {\purple{\begin{array}{r | l}\large\rm{\red{ 5}}&\underline{315,420,525}\\\large\rm{\red{ 3}}& \underline{63,84,105}\\\large\rm{\red{3}}&\underline{21,28,35}\\\large\rm{\red{ 7}}&\underline{7,28,35}\\\large\rm{\red{2}}&\underline{1,4,5}\\\large\rm{\red{2}}&\underline{1,2,5}\\\large\rm{\red{5}}&\underline{1,1,5}\\&1,1,1\end{array}}}}} }}}}}\end{gathered}\\\end{cases}}[/tex]

LCM = 5 × 3 × 3 × 7 × 2 × 2 × 5

LCM = 6300

Hence, the LCM of 315 , 420 , 525 is 6300

Answer:

Step-by-step explanation:

Prime factors of given numbers:

The LCM is:

Answer:

98376

Step-by-step explanation:

Answer:

Step-by-step explanation:

You will have to interpret the question with the aid of a diagram and make out the relevant angles and either make use of cosine rule,sine rule etc....Your knowledge on angles should be sound

Define relation.

Let A and B are only two non-empty set,then A*B is cartesian product of A*B.Then any subset of A*B is known as the relation fromA to B.

Answer:

B. 3.09-3.10-3.2-3.5 is the answer

Answer:

12000

Step-by-step explanation:

8000+4000=12000

Answer:

4y

Step-by-step explanation:

Answer:

perimeter=4y

Step-by-step explanation:

y+y+y+y=4y

..........

Answer:

72+12

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

50cm

Step-by-step explanation:

oh apdiya I just wanted to let you

9514 1404 393

Answer:

  C. The order in which numbers are added does not affect the sum.

Step-by-step explanation:

In symbols, the commutative property of addition is ...

  a +b = b +a

The order in which numbers are added does not affect the sum.

Answer:

B) Both functions have a y-intercept of -2.

Step-by-step explanation:

Hi there!

A) Both functions are always increasing.

⇒ False

Let's first take a look at the given equation, [tex]y=3x-2[/tex]. This is a linear equation, and it is organized in slope-intercept form: [tex]y=mx+b[/tex]. m is the slope and b is the y-intercept. When m is positive, it is always increasing.

In [tex]y=3x-2[/tex], 3 is m, and because it's positive, this line is always increasing on a graph.

However, when we take a look at the given graph, this isn't the case. It is decreasing for values of x below 0 (on the left side of the y-axis).

B) Both functions have a y-intercept of -2.

⇒ True

In the given equation [tex]y=3x-2[/tex], this is true. -2 is the y-intercept.

On the given graph, we can see that the graph intercepts the y-axis at -2, so this is also true for the graph.

C) Both functions are symmetric about the y-axis.

⇒ False

The given graph is symmetric about the y-axis, but the line is not. Any line that would be symmetric about the y-axis would be in the form [tex]y=b[/tex], which isn't the case here with [tex]y=3x-2[/tex]. [tex]y=3x-2[/tex] has a slope.

D) Both functions are linear relationships.

⇒ False

Sure, [tex]y=3x-2[/tex] is a linear equation, making it a line, but not the given graph. The graph does not resemble a straight line, so it is not a linear relationship.

I hope this helps!

The financial statement performed by Snell Corporation shows how the revenue recognition provides financial statement users(i.e. the client that uses Snell Co. service in May, June, and July) with relevant information regarding the services associated with revenue from customer contracts.

In the given case, the Snell Co. service charge was hiked in May since the entire service income must be accounted for in May. The amount owed from a client is seen as a current asset on the balance sheet, and once the amount is received from a client, it is removed off from the current asset. Thus it is added to the zero dollars ($0) company's cash balance. In this case, the cash collected in June and July is not recorded as revenue.

We can conclude that the monthly revenue recorded from Snell Co. performance and services for the client in May, June, and July for this service is as follows:

Months                               Revenue

May                                     $1000

June                                       0

July                                         0

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Revenue is only earned after the required obligation (goods delivered or service rendered) has been fulfilled. From the question, we noted that Snell Co. performs and completes services for a client in May hence the revenue was earned in May irrespective of when money was received for the service rendered.

As such revenue earned in;

May is $1,000

June is $0

July is $0

for the service rendered

Answer:

100 yojan=how much km

1287.48

please brainlist

Answer:

15.2

[tex] {c }^{2} = {a}^{2} + {b}^{2} \: \\ {c}^{2} ={6}^{2} + {14}^{2} \\ {c}^{2} = 36 + 196 \\ {c}^{2} = 232 \\ \sqrt{c } = \sqrt{232} \\ c = 15.23154621[/tex]

Answer:

going up in even numbers

Step-by-step explanation:

its like the two times table, and it goes up in even numbers

Answer:

any number you can take

Step-by-step explanation:

like 4'6'8''12

Answer:

14,712 ft difference

Step-by-step explanation:

15,062 - 350 = 14,712

Answer:

Step-by-step explanation:

Difference in elevation is 15,062-(-350)=15,062+350=15,412

Answer:

1/18

Step-by-step explanation:

Probability of spinning red=2/6=1/3

Probability of spinning green=1/6

probability of spinning green and then red=(1/6)*(1/3)=1/18