Evaluate −3x + 2 for x = −2.

Step-by-step explanation:

1. mzoGE = M2GOE

1. Given

2. GE = OE

2.

3. E is the midpoint of AT

3. Given

4. AE ET

4. Definition of the midpoint of a line segment.

5. AE = ET

5. Congruent segments have equal length.

6. MLAEG > MZTEO

6. Given

7. AG > TO

Answer:

5/8

Step-by-step explanation:

To find the absolute value you simply remove the negative symbol

Answer:

12+34+67+12

Step-by-step explanation:

im in 12th grade with straight as trust me

Answer:

written all the angles below:

m<1 = 35°

m<2 = 77°

m<3 = 49°

m<4 = 77°

m <5 = 62°

m<6 = 28°

hope that helps...

Answer:

[tex]34\pi[/tex]

Step-by-step explanation:

Given,

r = 17 mm

→ Circumference =

[tex]2\pi \: r[/tex]

→ 2x3.14x17

→ 34x3.14 =

[tex]34\pi[/tex]

↓

c = 106.76 mm

Answer:

81

Step-by-step explanation:

how to calculate procentage:
300(total) x 27(procentage) : 100 = 81

give brainliest

Answer:

3/4 lbs.

Step-by-step explanation:

In order to find how much more the heavier boxes weigh than the lighter boxes, we have to subtract the lighter box weight from the largest box weight.

Lighter box weight = 4 1/2

Heavier box weight = 5 1/4

Now we can find their difference:

The heavier box weight - lighter box weight = 5 1/4 - 4 1/2 = 21/4 - 9/2 = 21/4 - 18/4 = 3/4.

The heavier boxes weigh 3/4 lbs. more than the lighter boxes.

Answer:

3/4 lbs

Step-by-step explanation:

The heavier box weight - lighter box weight = 5 1/4 - 4 1/2 = 21/4 - 9/2 = 21/4 - 18/4 = 3/4.

The difference is:

The heavier boxes weigh 3/4 lbs. more than the lighter boxes.

Please may I have brainliest

Answer:

625

Step-by-step explanation:

I just did this question

PQ is the diameter so the midpoint of PQ is the center of the circle. if we suppose the center point of the circle called o then ;

[tex]o = \frac{pq}{2} \\ [/tex]

[tex]pq = \sqrt{ { (- 10 - 6})^{2} + ({10 - ( - 2)})^{2} } [/tex]

[tex]o = \frac{( -10 ,10) + (6 , - 2) }{2} \\ [/tex]

[tex]o = \frac{( - 10 +6 ,10 - 2)}{2} \\ [/tex]

[tex]o = ( \frac{ - 4}{2} , \frac{8}{2} ) \\ [/tex]

[tex]o = ( - 2,4)[/tex]

For the second step we need to find the radius of the circle which has the half the PQ distance measure, so we have to find the the PQ distance and divide it by 2 :

_____________________________________________

As u know the distance between 2 point is going to find by following formula :

[tex]pq = \sqrt{ {(x(p) - x(q)})^{2} + {(y(p) - y(q)})^{2} } \\ [/tex]

[tex]pq = \sqrt{ ({ - 10 - 6})^{2} + ({10 - ( - 2)})^{2} } [/tex]

[tex]pq = \sqrt{ ({ - 16})^{2} + ({12})^{2} } [/tex]

[tex]pq = \sqrt{256 + 144} [/tex]

[tex]pq = \sqrt{400} [/tex]

[tex]pq = 20[/tex]

Thus :

[tex]radius = \frac{pq}{2} \\ [/tex]

[tex]radius = \frac{20}{2} \\ [/tex]

[tex]radius = 10[/tex]

_____________________________________________

Ok we're almost done cuz we have what we needed:

If we suppose that the first coordinate of the center is a and the second coordinate of the center is b and the radius shown by r then :

[tex] ({x -a})^{2} + ( {y - b})^{2} = {r}^{2} [/tex]

Is the equation of the circle in the standar form thus :

[tex] ({x - ( - 2)})^{2} + ({y - 4})^{2} = {10}^{2} \\ [/tex]

[tex] ({x + 2})^{2} + ({y - 4})^{2} = 100[/tex]

As u can see option B is the correct answer.

And we're done ...

The domain which is appropriate for the function, H(n) is; all positive integers and zero.

From the task content;

On this note, we are required to determine the possible values for the number of tickets bought, n.

Ultimately, since tickets are whole, it follows that the appropriate domain for this function is; all positive integers and zero.

Read more on domain of functions;

https://brainly.com/question/1369616

Answer:

  they are rational numbers

Step-by-step explanation:

Any fraction with integers in numerator and denominator is a rational number.

__

  5, 6, 7, 11 are integers, so the fractions 5/11 and 7/6 are rational numbers.

Considering that a sundae cone costs $5 and a raspberry ripple cone $7, the inequality is:

[tex]5x + 7y \leq 450[/tex]

The total price can be no more than $450, hence:

[tex]T \leq 450[/tex]

To find the total price, we need the price of each a sundae cone and a raspberry ripple cone, which are not given. Hence, considering that a sundae cone costs $5 and a raspberry ripple cone $7, the total price is given by:

T = 5x + 7y

Hence, the inequality is:

[tex]5x + 7y \leq 450[/tex]

More can be learned about inequalities at https://brainly.com/question/25235995

Answer:

23

Step-by-step explanation:

[tex]16 + \frac{56}{n} [/tex]

[tex]where \: n = 8[/tex]

[tex]16 + \frac{56}{8} [/tex]

[tex]23[/tex]

[tex]56 / 8 = 7[/tex]

[tex]7 + 16 = 23[/tex]

With that information, your answer is twenty-three.

Answer:

5.5

Step-by-step explanation:

Answer: IT IS 5.5I DID THE TEST

Step-by-step explanation:

Answer:

11:45 AM

Step-by-step explanation:

9:15 +30 mins is 9:45

9:45 +2 hours is 11:45

Hope this helps!

Answer:

0.2830

Step-by-step explanation:

Observed Values

Add totals for the rows and columns to the two-way table (see attachment 1).

Expected Values

Create an "Expected Values" table by multiplying each row total by each column total and dividing by the overall total (see attachment 2).

Chi-square test statistic

[tex]\sf \dfrac{(observed-expected)^2}{expected}[/tex]

Create a third table by using the formula to calculate the chi-square test statistic for each cell of the table (see attachments 3 and 4)

Chi-square

Add the values from the table in attachment 4.

[tex]\sf X^2=0.05556+0.03945+0.002315+0.05465+0.04789+0.03401+0.001996+0.04711[/tex] [tex]\implies \sf X^2=0.2830 \:(4 \:sf)[/tex]

to multiply it by 2 because two is the dividend and that is closest to 1

Answer:

Option 1

Step-by-step explanation:

Substiute the value of n with 1 to 6 and find each term.

When n = 1 ,

       [tex]\sf First \ term = \dfrac{1}{2*1+1}=\dfrac{1}{2+1}=\dfrac{1}{3}\\\\[/tex]

[tex]\sf When n = 2,\\\\Second \ term = \dfrac{2}{2*2+1}=\dfrac{2}{4+1}=\dfrac{2}{5}\\\\[/tex]

When n = 3 ,

      [tex]\sf Third \ term = \dfrac{3}{2*3+1}=\dfrac{3}{6+1}=\dfrac{3}{7}[/tex]

When n = 4,

    [tex]\sf Fourth \ term =\dfrac{4}{2*4+1}=\dfrac{4}{8+1}=\dfrac{4}{9}\\[/tex]

When n = 5 ,

   [tex]\sf Fifth \ term = \dfrac{5}{2*5+1}=\dfrac{5}{10+1}=\dfrac{5}{11}\\\\When \ n = 6,\\\\ \: Sixth \ term =\dfrac{6}{6*2+1}=\dfrac{6}{12+1}=\dfrac{6}{13}[/tex]

[tex]Answer: \dfrac{1}{3}+\dfrac{2}{5}+\dfrac{3}{7}+\dfrac{4}{9}+\dfrac{5}{11}+\dfrac{6}{13}[/tex]

[tex]5\sqrt{3x+1} = 10\\\\\implies \sqrt{3x+1} = \dfrac{10}5 \\\\\implies \sqrt{3x+1} = 2 \\\\\implies 3x +1 = 4\\\\\implies 3x = 4-1 \\\\\implies 3x = 3\\\\\implies x =1[/tex]

Answer:

x = 1

Step-by-step explanation:

Given equation:

[tex]\dfrac{5(3x+1)^1}{2} =10[/tex]

If a term has "1" as it's exponent, it means that it's the number itself. Therefore, we can remove the "exponent".

[tex]:\implies\dfrac{5(3x+1)}{2} =10[/tex]

Simplify the distributive property:

[tex]:\implies\dfrac{15x+5}{2} =10[/tex]

Using cross multiplication:

[tex]:\implies15x+5} =10 \times 2[/tex]

Simplify the R.H.S:

[tex]:\implies15x+5} =20[/tex]

Subtract 5 both sides:

[tex]:\implies15x+5 - 5} =20 - 5[/tex]

Simplify both sides:

[tex]:\implies15x} =15[/tex]

Divide 15 both sides:

[tex]:\implies\dfrac{15x}{15} } =\dfrac{15}{15}[/tex]

Simplify both sides:

[tex]:\implies x= 1[/tex]

Answer:

16.4

Step-by-step explanation:

x = radius

x = 8.7 + 7.7

x = 16.4

Hello ~

My name is Irxdscent, and I will be answering your question today! :D

[tex]\huge\pmb{\frak{\underline{Answer:}}}[/tex]

[tex]\sf{x = 1}[/tex]

[tex]\huge\pmb{\frak{\underline{Explanation:}}}[/tex]

[tex]\sf{\frac{x}{5} \: + \: \frac{(x \: - \: 1)}{3} = \frac{1}{5}[/tex]

[tex]\sf{\frac{x}{5} \: + \: \frac{x \: - \: 1}{3} = \frac{1}{5}[/tex]

       Multiply by LCM = [tex]\bold{15}[/tex]

       [tex]\sf{\frac{x}{5} \: . \: 15 \: + \frac{x \: - \: 1}{3} \: . \: 15 = \frac{1}{5} \: . \: 15}[/tex]  

        [tex]\sf{3x \: + \: 5(x \: - \: 1) = 3[/tex]

        [tex]\sf{3x \: + \: 5x \: - \: 5 = 3}[/tex]

        [tex]\sf{8x \: - \: 5 \: + \: 5 \: = 3 \: + \: 5}[/tex]

        [tex]\sf{8x \: = \: 8[/tex]

        [tex]\sf{\frac{8x}{8} = \frac{8}{8}[/tex]

       [tex]\sf{x = 1}[/tex]

Hope It Helps! ~

~ Learn With Lrxdscent ~

[tex]\underline{Answer :}[/tex]

ɪ ʀ x ᴅ ꜱ ᴄ ᴇ ɴ ᴛ

Answer:

Step-by-step explanation:

In the question we have given an equation that is x / 5 + ( x - 1 ) / 3 = 1 / 5 . And we are asking to solve the equation that means we have to find the value of x.

Solution : -

[tex] \longmapsto \qquad \dfrac{x}{5} + \dfrac{(x - 1)}{3} = \dfrac{1}{5} [/tex]

Step 1 : Bye taking L.C.M solving left side :

[tex] \longmapsto \qquad \dfrac{3x + 5(x - 1)}{15} = \dfrac{1}{5} [/tex]

On further calculations, We get :

[tex] \longmapsto \qquad \dfrac{3x + 5x - 5}{15} = \dfrac{1}{5} [/tex]

[tex] \longmapsto \qquad \dfrac{8x - 5}{15} = \dfrac{1}{5} [/tex]

Step 2 : Multiplying 15 on both sides :

[tex] \longmapsto \qquad \dfrac{8x - 5}{ \cancel{15}} \times \cancel{15 } = \dfrac{1}{ \cancel{5}} \times \cancel{15}[/tex]

On further calculations, We get :

[tex] \longmapsto \qquad 8x - 5 = 3[/tex]

Step 3 : Adding 5 on both sides :

[tex] \longmapsto \qquad8x - \cancel{5} + \cancel{ 5} = 3 + 5[/tex]

On further calculations, We get :

[tex] \longmapsto \qquad8x = 8[/tex]

Step 4 : Dividing with 8 on both sides :

[tex] \longmapsto \qquad \dfrac{ \cancel{8}x}{ \cancel{8}} = \cancel{\dfrac{8}{8} }[/tex]

On further calculations, We get :

[tex] \longmapsto \qquad \blue{\underline{\blue{\boxed{ \frak{x = 1}}}}}[/tex]

Verifying : -

We are verifying our answer by substituting value of x in the given equation . So ,

Therefore, our solution is correct .

Step-by-step explanation:

there is one central rectangle :

from (-4, 2) to (2, -2).

that means it dimensions are 6×4 (for x from -4 to +3, for y from +2 to -2).

and then there are 3 additional triangles

(2, -4) (2, 2) (6, 2)

(-4, -2) (2, -2) (2, -4)

(-6, 2) (-4, 2) (-4, -2)

with the leg lengths

(2, -4) to (2, 2) = 6, and (2, 2) to (6, 2) = 4

(-4, -2) to (2, -2) = 6, and (2, -2) to 2, -4) = 2

(-6, 2) to (-4, 2) = 2, and (-4, 2) to (-4, -2) = 4

the area of the rectangle is

6×4 = 24 square units

the area of the first triangle is

6×4/2 = 3×4 = 12 square units

the area of the second triangle is

6×2/2 = 6 square units

the area of the third triangle is

2×4 = 8 square units.

so, the total area is

24 + 12 + 6 + 8 = 50 square units.

Given :-

We can find Total Surface Area , Lateral Surface Area and Volume of Cylinder by given values.

Volume of Cylinder = πr²h

Volume = 3.14×4²×15 cubic feet

Volume = 753.6 cubic feet

Total Surface Area of Cylinder = 2πr(r+h)

TSA = 2×3.14×4(4+15) square feet

TSA = 477.28 square feet

Lateral Surface Area Of Cylinder = 2πrh

CSA = 2×3.14×4×15

CSA = 376.8 square feet

Answer:

26.25

Step-by-step explanation:

So if you want to remove 25% from 35 you have to multiply the two you get 8.75 then minus that from 35 you get 26.25

Answer:

The answer is 14/50

Step-by-step explanation:

sin=opp/hyp

sin=14/50

Answer:

8π or 35.133 (3 d.p.)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Start by plugging in the x values -2, -1, 0, 1, and 2 into the equation to receive the y values.

For example, the first point on the table would be y=(-2)-2, or (-2, -4). Continue plugging in the points for all the points on the table

Answer:

4:3 = 8:6 = 12:9 = 16:12 = 20:15 = 24:18 = 28:21 = 32:24 = 36:27 = 40:30

Step-by-step explanation:

Answer:

8:4, 32:24, 48:36

Step-by-step explanation:

16 ÷3=8

12÷3=4

↓

8:4

----------------------

16 ×2=32

12×2=24

↓

32:24

-----------------------

16×3=48

12×3=36

↓

48:36

Hope this helps! Have a good day! : )

Answer:

A)  [tex]f(w)=45w+35[/tex]

B)  f(w) is the total number of flowers that bloomed

     w is the number of weeks

C)  1655 flowers

Step-by-step explanation:

Part A

[tex]f(s) = 3s + 35[/tex]

[tex]s(w) = 15w[/tex]

To create the composite function, replace the variable [tex]s[/tex] in the function f(s) with function s(w):

[tex]\implies f(w)=3(15w)+35[/tex]

[tex]\implies f(w)=45w+35[/tex]

Part B

Part C

Substitute w = 36 into the compositie function and solve:

[tex]\implies f(36)=45(36)+35=1655[/tex]