Answer:
a) 4116.67 N
b) negative (assuming car is traveling in positive direction)
c) 19.125 m
Explanation:
Part A)We can find the average force exerted on the car by using Newton's 2nd Law: F = ma.
We have the mass (950 kg) but we do not have the acceleration. Let's solve for this using kinematics.
We have the time during braking, the initial and final velocity, and we need to find the acceleration. To do this, we can use the following equation: v = v₀ + at.
v (final velocity) = 9.50 m/sv₀ (initial velocity) = 16.0 m/st (time) = 1.50 s a = ?Substitute these values into the equation.
v = v₀ + at9.50 m/s = 16.0 m/s + a (1.50 s) 9.50 = 16.0 + 1.50a -6.50 = 1.50a a = -4.333333... m/s²The car's acceleration during the braking period is -4.33 m/s², assuming the car is traveling in the positive direction.
Now, we can use this to plug into Newton's 2nd Law to find the force exerted on the car.
F = maF = (950 kg) (-4.33...) F = -4116.666667 NThe magnitude of the average force exerted on the car while braking is the absolute value, so it is 4116.67 N.
Part B)The direction of the average force is denoted in the negative sign. It is opposite the direction of the car's motion. Assuming that the car is traveling in the positive direction, the direction of the average force exerted on the car is in the negative direction since this force is slowing the car down while braking.
Part C)We can find the distance traveled during the braking period by using another kinematic equation.
We have the initial and final velocity, and the time traveled, so we can use this equation: Δx = v_avg · t.
Note that v_avg is the same thing as (v + v₀) / 2.Substitute the known values into the equation.
Δx = [(9.50 + 16.0)/2] · 1.50 Δx = 12.75 · 1.50Δx = 19.125 mThe car traveled 19.125 m while braking.
60.96-mile distance in kilometers
Answer:
98.105610 Kilometers
Explanation:
Rounded to 8 digits
Answer:
98.11 km
Explanation:
60.96 mi (5280ft/mi)(12 in/ft)(2.54 cm/in)(1 m/ 100cm)(1 km/1000 m) = 98.10561024 km
however, reporting this precision to the nearest hundred millionth of a kilometer is silly as we only know the mile dimension to the nearest hundredth of a mile.
A hundredth of a mile is 5280/100 = 52.8 ft or just over 16 m
It would only be a little bit of a presumption to give our precision to the nearest 10 meters as I have done.
This also fits neatly into the significant digits rule. Both the original dimension and the converted dimension have four significant digits.
astone is thrown upwards with an initial velocity of 25m/s atan angle of 30 to the ground.what is the work out the stones horizantal range ?
Answer:
Range is 62.5 metres
Explanation:
Time of flight
[tex]t = \frac{2u \sin( \theta) }{g} [/tex]
for range, acceleration is zero
from second newton's equation:
[tex]S = ut + \frac{1}{2} {at}^{2} [/tex]
but a = 0:
let range be x:
[tex]x = ut \\ x = \frac{2 {u}^{2} \sin( \theta) }{g} \\ \\ x = \frac{ \{2 \times 25 {}^{2} \sin(30 \degree) \}}{10} \\ \\ x = 62.5 \: metres[/tex]
[ taken g to be 10 m/s² ]
A scientist obtains images of a particular star, which appears as four separate stars.
Which phenomenon causes the star to appear this way?
O redshift
gravitational lensing
O principle of equivalence
O gravitational time dilation
Answer:
gravitational lensing
Explanation:
Answer:
Gravitational lensing
Explanation:
Which of the following elements has properties different than the rest?
H
K
N
O
Answer:
I think K . If it not, then sorry.Hope I helped you.
Answer: The answer [b] or also known as k
Explanation:
What is the velocity of a car that traveled a total of 75 kilometers north in 1.5 hours?
What are you solving for?
What’s the equation?
Show work!
Help pleaseee!
Answer:
50km/hr is the velocity of a car that traveled a total of 75 km North in 1.5 hours.
An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 15m if her initial speed is 3m/s.What is the acceleration due to gravity on the planet?
Explanation:
As the astronaut jumps and reaches the highest point, he is momentarily at rest, i.e.
[tex]v=0[/tex]
We also know
[tex]u=3, s=15[/tex]
By the formula,
[tex]v^2-u^2=2as[/tex]
where a is the acceleration of objectc due to gravity,
[tex]0^2-3^2=2a(15)[/tex]
[tex]-9=30a[/tex]
[tex]a=-0.3 ms^{-2}[/tex]
where negative sign indicates a downwards acceleration.
what do you mean by MA of a lever is 3 , VR of a lever is 4 and efficiency of a machine is 60%
Late one night on a highway, a car speeds by you and fades into the distance. Under these conditions the pupils of your eyes have diameters of about 7.0 m m. The taillights of this car are separated by a distance of 1.4 m and emit red light (wavelength = 660 nm in vacuum). How far away from you is this car when its taillights appear to merge into a single spot of light because of the effects of diffraction?
Physics help please !!!
Answer:
uhc gxjmfxtulxtdyvinjve, gravity egg ciovbyaahdyyihftsrscyjgigtdyvgxerchcih9jv ucfgggghhjjjvcsbni9jkvvhpj.
upfp73eidjdhxhxuelueljs NBA. aly7ryshzb. w m8
What is the difference between a scientific theory and a scientific law
Scientific laws are summaries or statements that describe a wide range of observations and results of experiments.
Scientific theories, on the other hand, are explanations for observations and results.
So, laws describe what happens and theories explain why things happen.
hope this help! ^^
A uniform rod of length 0.7 m and mass 10 kg rotates freely about a horizontal axis passing through one end of the rod a bullet of mass 20 g traveling horizontally with velocity v=200 m/s penetrates the end of the rod. and hooked on the rod find the angular velocity of the rod when the bullet hits the bar
Answer:
ω = 1.7 rad/s
Explanation:
Conservation of angular momentum
Assuming the rod is initially hanging vertically at rest.
Initial angular momentum is carried by the bullet only
L = Iω = (mR²)(v/R) = mvR = 0.020(200)(0.7) = 2.8 kg•m²/s
the same angular momentum exists after impact, only the moment of inertia has increased by that of the rod. I = ⅓mR²
2.8 = (⅓(10)(0.7²) + 0.020(0.7²))ω
2.8 = (1.64313333...)ω
ω = 1.70406134...
What is the density of a block of marble that
occupies 287 cm3
and has a mass of 816 g?
Answer in units of g/cm3
.
Explanation:
Solution,
Volume (v)=287 cm^3
Mass(m)=816 g
Density(d)=m/v
=816/287
=2.84
So, the density of the block of marbles is 2.84 g/cm^3.
I hope it helped U
stay safe stay happy
What is the speed of a car that traveled 32 m in 2 seconds?
Revolution: One orit of an object in space around another_ days?
Answer:
365 days..
Explanation:
Hope it may help you シ︎♡︎
[tex] \huge\mathfrak\green{365 \: or \: 366 \: Days.}
[/tex]
[tex]Hope \: it \: helps[/tex]
An arrow is moving at 35 m/s and travels for 5 seconds. How far did the arrow travel?
What are you solving for? Show work! Help please!
Answer:
175m
Explanation:
So it’s travelling at 35metres/1second so if we want to find 5 seconds we can do this…
[tex]\frac{35}{1} \frac{x}{5}.... so[/tex] 35x5 ÷ 1 = 175m/5 seconds
Answer:
175 is the right answer 35×5=175
Explanation:
175
which form of the energy is used to generate electrical energy in a tidal power station
Tidal energy is the form of energy used to generate electrical energy.
The form of the energy is used to generate electrical energy in a tidal power station is kinetic energy.
What is kinetic energy?Kinetic energy is the energy that an object has as a result of its movement. If we intend to accelerate an object, we should indeed apply force to it. Using force requires us to put in effort.
After work is completed, energy is transmitted to the object, and the object moves at a new constant speed.
Tidal energy is generated by the movement of our tides and oceans, where the intensity of the water from tide rise and fall is a type of kinetic energy.
Tidal power is related to gravitational hydropower, which uses water movement to propel a turbine and generate electricity.
Thus, kinetic energy is used to generate electrical energy in a tidal power station.
For more details regarding kinetic energy, visit:
https://brainly.com/question/26472013
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A black ball moving to the left at 3 m/s collides with a white ball at rest. Which direction will the balls move after the collision?
Answer: the location from where the black ball was thrown from because after the collision the velocity will make it still go further not stop
Explanation:
A mineral oil has a density of 0.875 g/cm3. Suppose you spread 0.60 g of this oil over the surface of water in a large dish with an inner diameter of 21.6 cm. How thick is the oil layer
With a density of 0.875 g/cm³, a sample of 0.60 g of this oil would have a volume V such that
0.875 g/cm³ = (0.60 g)/V ==> V ≈ 0.686 cm³
If the oil is spread out uniformly over the water's surface, then it forms a cylinder whose diameter is equal to that of the dish, 21.6 cm. Then the thickness d of the oil cylinder is such that
V = π ((21.6 cm)/2)² d ==> d ≈ 0.0202 cm
what happens when you mix water and baking soda
how many grams of CaCo3, will react with dil HCL to produce 75gm of Co2 ?
Answer:
100g is correct answer.
Answer:
100 grams
Explanation:
CaCO3 ➡️ CaO + CO2
pls mark brainlies!
What is the relationship between resistivity of a wire and length of a wire is?
[tex]\boxed{\sf R=\rho\dfrac{\ell}{A}}[/tex]
Or
[tex]\\ \rm\hookrightarrow \rho=R\dfrac{A}{l}[/tex]
Rho stands for resistivity of wireR stands for resistance of wire l stands for length of areaA stands for surface area of wireHow would you determine the sign of a charge on a body using an electroscope? PLEASE HELP!!!
Answer:
Now the electroscope will allow you to identify whether an object is positively or negatively charged. If you bring a negative object near the electroscope, the electrons in the scope will be repelled toward the leaves, balancing the charge.
Explanation:
The electrostatic force obeys the principle of linear super-position which basically states
that force between two particles does not get affected by the charge of the other and hence if the
rod is brought close to a suspended metal needle and is getting attracted then needle definitely
should possess opposite charge relative to the rod or basically negative charge as opposite charges
attract.
(b) In case the needle which is brought near the sus[ended needle and gets repelled that shows that
both of them possess same charge and hence positive charge on both objects and will start
repelling each other.
2. Samuel leaves the end of a 4.0-m-high diving board and strikes the
water 1.3 s later, 3.0 m beyond the end of the board. Considering the
diver as a particle, determine:
(a) His initial velocity,
(b) The maximum height reached;
(c) The velocity Vf
with which he enters the water.
Answer:
a) v = 4.9 m/s at 62° above the horizontal
b) h = 0.94 m above the board or 4.94 m above the water
c) v = 10 m/s at 77° below the horizontal
Explanation:
Assume UP and FOREWARD are positive and the diving board is the origin.
Ignore air resistance.
s = s₀ + v₀t + ½at²
In the vertical
-4 = 0 + vy₀(1.3) + ½(-9.8)(1.3²)
vy₀ = 4.281 m/s
in the horizontal
3.0 = 0 + vx₀(1.3) + ½(0)(1.3²)
vx₀ = 2.307... m/s
v = √(4.281² + 2.307²) = 4.863...
tanθ = 4.281 / 2.307
θ = 61.680...
v² = u² + 2as
s = (v² - u²) / 2a
h = (0² - 4.281²) / 2(-9.8) = 0.9350...
v² = 4.863² + 2(9.8)(4)
v = 10.1019...
cosθ = 2.307/10.1019
θ = 76.798
(a) The initial velocity of Samuel is 4.02 m/s
(b) The maximum height reached by Samuel is 0.55 m
(c) The final velocity when he enters the water is 5.20 m/s
The given parameter:
the height of the board, h = 4 mtime to strike the water, t = 1.3 sthe horizontal distance traveled, x = 3.0 m(a) The initial velocity of Samuel is calculated as;
[tex]h = v_o_y t + \frac{1}{2} gt^2\\\\[/tex]
Assume downward motion to be in negative direction
The vertical component of the velocity is calculated as;
[tex]4 = 1.3\times v_0_y + 0.5\times 9.8\times 1.3^2\\\\4 = 1.3v_{0y} + 8.281\\\\1.3v_{0y} = 4- 8.281\\\\1.3v_{0y} = -4.281\\\\v_{0y} = \frac{-4.281}{1.3} \\\\v_{0y} = -3.293 \ m/s\\\\v_{0y} = 3.293 \ m/s \ \ \ (downwards)[/tex]
The horizontal component of the velocity is calculated as;
Assume forward motion to be in positive direction
[tex]x = v_{0x}t \\\\3 = 1.3v_{0x}\\\\v_{0x} = \frac{3}{1.3} \\\\v_{0x} = 2.308 \ m/s[/tex]
The resultant of initial velocity is calculated as;
[tex]v_0 = \sqrt{v_{0y}^2 + v_{0x}^2} \\\\v_0 = \sqrt{3.293^2 + 2.308^2} \\\\v_0 = \sqrt{16.17} \\\\v_0 = 4.02 \ m/s[/tex]
(b) The maximum height reached by Samuel is calculated as;
[tex]v_f_y^2 = v_0_y^2 + 2gh\\\\at \ maximum \ height \ v_{fy} = 0\\\\0 = v_0_y^2 + 2gh\\\\-2gh = v_0_y^2\\\\h = \frac{v_0_y^2}{-2g} \\\\h = \frac{(3.293)^2}{-2\times 9.8} \\\\h = -0.55 \ m\\\\h = 0.55 \ m \ (downwards)[/tex]
(c) The final velocity when he enters the water;
The height traveled before he hits the water, h = 0.55 m
[tex]v_f^2 = v_{0}^2 + 2gh\\\\v_f^2 = (4.02)^2 + (2\times 9.8\times 0.55)\\\\v_f^2 = 26.94\\\\v_f = \sqrt{26.94} \\\\v_f = 5.20 \ m/s[/tex]
Learn more here: https://brainly.com/question/13372763
Which Scientist discovered
atomic Theory?
Answer:
John dalton discovered
Three resistors 2 k\ohm, 2.5 k\ohm and 3 k\ohm are connected in series. A power supply is connected in the circuit, and applies a voltage of 10.00 V across all three. Calculate the current in the circuit. Enter results in terms of milliamps (mA).
Answer:
1.33 mA
Explanation:
V=IR
I=10/(7.5×10³)
=1.33×10-³A
=1.33mA
Yellow light passes through a diffraction grating. it's first order maximum occurs at an angle of 21.2. What is the slit separation d?
Answer:
19.284
or
9.33
Explanation:
Answer:
1.66
Explanation:
Found answer on chegg. Works for acellus
25m/s to miles/hr step by step
HELP PLEASE ASAP!!!
I CAN'T FAIL PHYSICS
xoxo thank you!
what happens to the value of g when we move from equator to the pole.the weight of an object is greater at poles than at equator .
why?
Question 15 OT 25
Which process is an example of an exothermic reaction?
A. The reactions taking place in a cold pack
B. A plant using photosynthesis to create sugars
C. Natural gas burning on a stove
o
D. The reactions taking place inside a baking cake
Answer:
A. The reactions taking place in a cold pack
Explanation:
This is because in a cold pack, there is no heat gained therefore a reaction stands by losing it's own heat to the surrounding.
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