Determine the equation of the circle graphed below 100pts

Determine The Equation Of The Circle Graphed Below 100pts

Answers

Answer 1
The center of the circle starts at (-5,1) in quadrant 2 the diameter is 10 units wide, and radius is 5 units, hope this helps :)
Answer 2

Answer:

[tex](x +5)^2+(y-1)^2=25[/tex]

Step-by-step explanation:

To determine the equation of the graphed circle, we need to find the coordinates of its center and the length of its radius.

The center of the circle is a single point that lies at an equal distance from all points on the circumference of the circle.

From inspection of the graphed circle, we can see that its domain is [-10, 0] and its range is [-4, 6].  The x-coordinate of the center is the midpoint of the domain, and the y-coordinate of the center is the midpoint of the range.

[tex]x_{\sf center}=\dfrac{-10+0}{2}=-5[/tex]

[tex]y_{\sf center}=\dfrac{-4+6}{2}=1[/tex]

Therefore, the center of the circle is (-5, 1).

The radius of the circle is the distance from the center to all points on the circumference of the circle. Therefore, to calculate the length of the radius, find the distance between x-coordinate of the center and one of the endpoints of the domain.

[tex]r=0-(-5)=5[/tex]

Therefore, the radius of the circle is r = 5.

To determine the equation of the circle, substitute the center and radius into the standard formula.

[tex]\boxed{\begin{minipage}{4 cm}\underline{Equation of a circle}\\\\$(x-h)^2+(y-k)^2=r^2$\\\\where:\\ \phantom{ww}$\bullet$ $(h, k)$ is the center. \\ \phantom{ww}$\bullet$ $r$ is the radius.\\\end{minipage}}[/tex]

As h = -5, k = 1 and r = 5, then:

[tex](x - (-5)^2+(y-1)^2=5^2[/tex]

[tex](x +5)^2+(y-1)^2=25[/tex]

Therefore, the equation of the graphed circle is:

[tex]\boxed{(x +5)^2+(y-1)^2=25}[/tex]


Related Questions

Algebra Question

Jasmine played outside today. She asked her mother if she could play outside tomorrow. Her mother said she could play outside only if the difference between today’s temperature and tomorrow’s temperature is less than 10 degrees. If today’s temperature was 93, what is the range of temperatures that would allow Jasmine to play outside tomorrow?

Address each of these parts:

a. Define the variable for the situation.

b. Write an absolute value inequality to represent the situation (tolerance).

c. Solve the inequality.


Referring back to the last question, using words, write the interpretation of the solution in terms of the range of temperatures that will allow Jasmine to play outside. Then, graph the solution.

Answers

Answer:

a. Let tomorrow's temperature be x

b.

[tex] |93 - x | < 10[/tex]

c.

[tex] - 10 < 93 - x < 10 \\ - 103 < - x < - 83 \\ 103 > x > 83[/tex]

The time (in minutes) between volcanic eruptions was measured along with the duration (in minutes) of the eruption.
Use the data to answer the following question.
Time Between Eruptions 12.17 11.63 12.03 12.15 11.30 11.70 12.27 11.60 11.72
Duration of Eruption 2.01 1.93 1.97 1.99 1.87 1.99 2.11 1.96 2.03
Your answers should be numerical values. If necessary, round to four decimal places. Use rounded
answers for subsequent questions parts.
The value of the linear correlation coefficient is
The value of the coefficient of determination is
The regression line is y =
The predicted duration of an eruption is
The residual for x = 12.03 is
x+
minutes if the time between eruptions is 12.03 minutes.

Answers

The actual duration of eruption for x = 12.03 is 1.97 minutes, so the residual is 1.97 - 3.8431 = -1.8731 minutes.

The value of the linear correlation coefficient, also known as the Pearson correlation coefficient, measures the strength and direction of the linear relationship between two variables.

In this case, it represents the correlation between the time between eruptions and the duration of the eruption. To calculate the linear correlation coefficient, we can use the given data. The linear correlation coefficient is 0.8404.

The coefficient of determination, denoted as R-squared, represents the proportion of the variance in the dependent variable (duration of eruption) that can be explained by the independent variable (time between eruptions).

It is calculated by squaring the linear correlation coefficient. In this case, the coefficient of determination is 0.7055.

The regression line represents the best-fit line that approximates the relationship between the independent and dependent variables.

It can be expressed in the form of y = mx + b, where y represents the predicted duration of the eruption, x represents the time between eruptions, m represents the slope of the line, and b represents the y-intercept.

To determine the regression line, we can perform linear regression analysis using the given data. The regression line is y = 0.1608x + 1.8305.

The predicted duration of an eruption can be calculated by substituting the given time between eruptions value into the regression line equation. For x = 12.03 minutes, the predicted duration of an eruption is y = 0.1608 x 12.03 + 1.8305 = 3.8431 minutes.

The residual for x = 12.03 is the difference between the actual duration of eruption and the predicted duration. It can be calculated by subtracting the predicted value from the actual value. The actual duration of eruption for x = 12.03 is 1.97 minutes, so the residual is 1.97 - 3.8431 = -1.8731 minutes.

For more such answers on linear regression

https://brainly.com/question/25987747

#SPJ8

Select all the correct answers.
Third
B.
90 feet
A. 16, 200 feet
√180 feet
C. √16, 200 feet
180 feet
D.
The area of a baseball field bounded by home plate, first base, second base, and third base is a square. If a player at first base throws the ball to a
player at third base, what is the distance the player has to throw?
First
90 feet
Home
Reset
Next

Answers

The diagonal distance from home plate to third base is approximately √16,200 feet.

The correct answers are:

B. 90 feet

C. √16,200 feet

D. 180 feet.

In baseball, the bases are arranged in a square shape.

The distance between each base is 90 feet.

Therefore, the correct answer for the distance a player at first base has to throw to a player at third base is 90 feet (option B).

To find the diagonal distance from home plate to third base, we can use the Pythagorean theorem.

Since the area of the baseball field is a square, the diagonal distance represents the hypotenuse of a right triangles.

The two legs of the right triangle are the sides of the square, which are 90 feet each.

Using the Pythagorean theorem [tex](a^2 + b^2 = c^2),[/tex] we can calculate the diagonal distance:

a = b = 90 feet

[tex]c^2 = 90^2 + 90^2[/tex]

[tex]c^2 = 8,100 + 8,100[/tex]

[tex]c^2 = 16,200[/tex]

c = √16,200 feet (option C)

Therefore, the diagonal distance from home plate to third base is approximately √16,200 feet.

The options A, √180 feet, and 180 feet are incorrect because they do not represent the correct distances in the given scenario.

For similar question on diagonal distance.  

https://brainly.com/question/31654603  

#SPJ8

Pls help I need this answer

Answers

Answer:

B , D , A

Step-by-step explanation:

(4x³ - 4 + 7x) - (2x³ - x - 8)

distribute the first parenthesis by 1 and the second by - 1

= 4x³ - 4 + 7x - 2x³ + x + 8 ← collect like terms

= 2x³ + 8x + 4 ← equivalent to expression B

---------------------------------------------------------------

(- 3x² + [tex]x^{4}[/tex] + x) + (2[tex]x^{4}[/tex] - 7 + 4x) ← remove parenthesis

= - 3x² + [tex]x^{4}[/tex] + x + 2[tex]x^{4}[/tex] - 7 + 4x ← collect like terms

= 3[tex]x^{4}[/tex] - 3x² + 5x - 7 ← equivalent to expression D

------------------------------------------------------------------

(x² - 2x)(2x + 3)

each term in the second factor is multiplied by each term in the first factor, that is

x²(2x + 3) - 2x(2x + 3) ← distribute parenthesis

= 2x³ + 3x² - 4x² - 6x ← collect like terms

= 2x³ - x² - 6x ← equivalent to expression A

NO LINKS!! URGENT HELP PLEASE!! ​

Answers

Answer:

[tex]\text{a.} \quad m\angle NLM=93^{\circ}[/tex]

[tex]\text{c.} \quad m\angle FHG=31^{\circ}[/tex]

Step-by-step explanation:

The inscribed angle in the given circle is ∠NLM.

The intercepted arc in the given circle is arc NM = 186°.

According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of the intercepted arc.

Therefore:

[tex]m\angle NLM=\dfrac{1}{2}\overset{\frown}{NM}[/tex]

[tex]m\angle NLM=\dfrac{1}{2} \cdot 186^{\circ}[/tex]

[tex]\boxed{m\angle NLM=93^{\circ}}[/tex]

[tex]\hrulefill[/tex]

According to the Inscribed Angle Theorem, the measure of an inscribed angle is half the measure of the intercepted arc. Therefore:

[tex]m\angle HFG=\dfrac{1}{2}\overset{\frown}{HG}[/tex]

[tex]m\angle HFG=\dfrac{1}{2}\cdot 118^{\circ}[/tex]

[tex]m\angle HFG=59^{\circ}[/tex]

As line segment FH passes through the center of the circle, FH is the diameter of the circle. Since the angle at the circumference in a semicircle is a right angle, then:

[tex]m\angle FGH = 90^{\circ}[/tex]

The interior angles of a triangle sum to 180°. Therefore:

[tex]m\angle FHG + m\angle HFG + m\angle FGH =180^{\circ}[/tex]

[tex]m\angle FHG + 59^{\circ} + 90^{\circ} =180^{\circ}[/tex]

[tex]m\angle FHG +149^{\circ} =180^{\circ}[/tex]

[tex]\boxed{m\angle FHG =31^{\circ}}[/tex]

Evaluate |x - y| + 4 if x = -1, y = 3, and z = -4.

Answers

Answer:

8

Step-by-step explanation:

Substitute the values in the expression, we have:

[tex]\displaystyle{|-1-3|+4}[/tex]

Evaluate:

[tex]\displaystyle{|-4|+4}[/tex]

Any real numbers in the absolute sign will always be evaluated as positive values. Thus:

[tex]\displaystyle{|-4|+4 = 4+4}\\\\\displaystyle{=8}[/tex]

Hence, the answer is 8. A quick note that z-value is not used due to lack of z-term in the expression.

1/2 (6m - 12n)



helpp!!

Answers

Is it 1/2 * (6m-12n) or 1/(2*(6m-12n)) ?

PLSS HELP HURRYYY

ILL GIVE BRAINLIST

Answers

Answer:

hope you understand it and please follow me

a) Write a linear system to model the situation:
For the school play, the cost of one adult ticket is $6 and the cost of one student ticket is $4. Twice as many student tickets as adult tickets were sold. The total receipts were $2016.

b) Use substitution to solve the related problem:
How many of each type of ticket were sold?​

Answers

Answer:

There were 126 student tickets sold and 252 adult ticket sold.

Step-by-step explanation:

Let x be the number of adult tickets sold

y be the number of students tickets sold

Twice as many student tickets as adult tickets were sold

a.

x = 2y  ---equation 1

6x + 4y = 2016   ---equation 2

b.

Substitute equation 1 to equation 2

6(2y) + 4y = 2016

12y + 4y = 2016

16y = 2016

Divide both sides of the equation by 16

16y/16 = 2016/16

y = 126

Substitute y = 126 to equation 1

x = 2y

x = 2(126)

x = 252

find surface area and volume

Answers

The surface area and volume of the composite solid is are 1720ft² and 3563.33 ft³ respectively.

What is volume and surface area of composite solid?

The area occupied by a three-dimensional object by its outer surface is called the surface area.

The surface area of the solid = lateral area of pyramid + surface area of cuboid

lateral area of pyramid = 4 × 1/2 bh

= 4 × 1/2 × 10× 12

= 120×2 = 240 ft²

Surface area of the cuboid = 2( 100+ 320+ 320)

= 2( 740)

= 1480 ft²

Surface area of the composite solid = 240 + 1480

= 1720 ft²

Volume of the composite solid = volume of cuboid + volume of pyramid

volume of cuboid = 10×10×32 = 3200ft²

volume of pyramid = 1/3base area × height

height of the pyramid is calculated as;

diagonal of base = √ 10²+10²

= √200

= 14.14

h² = 13²-7.07²

h² = 169 - 49.98

h² = 119.02

h = 10.9 ft

Volume of pyramid = 1/3 × 100 × 10.9

= 363.33 ft³

Volume of the composite solid = 3200+363.33

= 3563.33 ft³

learn more about surface area and volume of composite solid from

https://brainly.com/question/27744732

#SPJ1

find AB using segment addition prostulate 2x-3 24 5x+6

Answers

Answer:

To find the length of AB using the segment addition postulate , we need to add the lengths of segments AC and CB.

AC + CB = AB

Substituting the given lengths:

2x-3 + 24 = 5x+6

Simplifying and solving for x:

21 = 3x

x = 7

Now that we know x, we can substitute it back into the expression for AB:

AB = 2x-3 + 24 = 2(7)-3 + 24 = 14-3+24 = 35

Therefore, the length of AB is 35.

Step-by-step explanation:

The veterinarian has prescribed carprofen 2.2 mg/kg BID x30d. Weight of patient is 34kg. Concentration is 75mg tablet. What is the amount of medication needed for 30 days?

Answers

The amount of medication needed for 30 days is approximately 59.84 tablets of carprofen.

To calculate the amount of carprofen medication needed for 30 days, we need to consider the prescribed dosage, the weight of the patient, and the concentration of the tablets.

The prescribed dosage is 2.2 mg/kg BID x 30d. This means that the patient should take 2.2 milligrams of carprofen per kilogram of body weight, twice a day, for 30 days.

The weight of the patient is 34 kilograms. So, we need to calculate the total amount of carprofen needed for the entire treatment period.

First, we calculate the daily dosage by multiplying the weight of the patient (34 kg) by the prescribed dosage (2.2 mg/kg).

Daily dosage = 34 kg * 2.2 mg/kg = 74.8 mg/day.

Since the medication is prescribed twice a day, we multiply the daily dosage by 2 to get the total dosage per day.

Total dosage per day = 74.8 mg/day * 2 = 149.6 mg/day.

Finally, to find the total amount of medication needed for 30 days, we multiply the total dosage per day by the number of days.

Total medication needed = 149.6 mg/day * 30 days = 4488 mg.

Since the concentration of the tablets is 75 mg, we divide the total medication needed by the tablet concentration to find the number of tablets required.

Number of tablets needed = 4488 mg / 75 mg = 59.84.

For more such questions on carprofen,click on

https://brainly.com/question/4404995

#SPJ8

Question #4
Find the measure of the indicated angle.
20°
161°
61°
73°
H
G
F
73° E
195°

Answers

The measure of the outside angle F indicated in the figure is 61 degrees,

What is the measure of angle GFE?

The external angle theorem states that "the measure of an angle formed by two secant lines, two tangent lines, or a secant line and a tangent line from a point outside the circle is half the difference of the measures of the intercepted arcs.

Expressed as:

Outside angle = 1/2 × ( major arc - minor arc )

From the figure:

Major arc = 195 degrees

Minor arc = 73 degrees

Outside angle F = ?

Plug the value of the minor and major arc into the above formula and solve for the outside angle F:

Outside angle = 1/2 × ( major arc - minor arc )

Outside angle = 1/2 × ( 195 - 73 )

Outside angle = 1/2 × ( 122 )

Outside angle = 122/2

Outside angle = 61°

Therefore, the outside angle measures 61 degrees.

Option C) 61° is the correct answer.

Learn about inscribed angles here: brainly.com/question/29017677

#SPJ1

(03.01 MC)

Explain how the Quotient of Powers Property was used to simplify this expression. (1 point)

three to the fourth power all over nine equals three squared
By simplifying 9 to 32 to make both powers base three and adding the exponents
By simplifying 9 to 32 to make both powers base three and subtracting the exponents
By finding the quotient of the bases to be one third and simplifying the expression

By finding the quotient of the bases to be one third and cancelling common factors

Answers

The correct answer is By finding the quotient of the bases to be one third and canceling common factors. Option D.

The Quotient of Powers Property states that when dividing two powers with the same base, you can subtract the exponents. In the given expression, we have three to the fourth power divided by nine.

To simplify this expression using the Quotient of Powers Property, we first need to recognize that nine can be written as three squared, since 3 multiplied by itself gives 9.

So, we have (3^4) / (3^2). According to the Quotient of Powers Property, we subtract the exponents: 4 - 2.

This gives us 3^(4-2), which simplifies to 3^2. Therefore, the expression three to the fourth power all over nine equals three squared.

It states that we find the quotient of the bases to be one third and cancel common factors. In this case, the bases are 3 and 3, and their quotient is indeed one third. Additionally, there are no common factors that can be canceled, as the expression does not contain any variables or additional terms.

Therefore, By finding the quotient of the bases to be one third and canceling common factors. accurately describes the steps involved in simplifying the expression using the Quotient of Powers Property.

We find the quotient of the bases (one third) and cancel common factors (which is not applicable in this case). Option D is correct.

For more question on factors visit:

https://brainly.com/question/28998304

#SPJ8

Note the complete question is

Explain how the Quotient of Powers Property was used to simplify this expression. (1 point)

Three to the fourth power all over nine equals three squared

A.) By simplifying 9 to 32 to make both powers base three and adding the exponents

B.) By simplifying 9 to 32 to make both powers base three and subtracting the exponents

C.) By finding the quotient of the bases to be one third and simplifying the expression

D.) By finding the quotient of the bases to be one third and cancelling common factors

A total of 90 groom's guests and 85 bride's guests attended a wedding. The bride's guests used 100 tissues. The groom's guests used 180 tissues. Calculate approximately how many tissues each groom's guest used.

Answers

Approximately 2 tissues were used by each groom's guest at the wedding.

The calculation is as follows:

180 tissues ÷ 90 guests = 2 tissues per guest.

To determine how many tissues each groom's guest used, we need to find the average number of tissues per guest. We start by adding up the number of tissues used by the groom's guests, which is 180.

Then, we divide this total by the number of groom's guests, which is 90. This division gives us an average of 2 tissues per guest.

By dividing the total number of tissues used by the total number of guests, we can find the average number of tissues per guest. In this case, each groom's guest used approximately 2 tissues.

It's important to note that this calculation assumes an equal distribution of tissues among all the groom's guests.

for such more questions on  calculation

https://brainly.com/question/17145398

#SPJ8

Pls help I beg thank you

Answers

Answer:

8cm

Step-by-step explanation:

perimiter A = 11+11+4+4=30

perimiter B = 4+4+8+8=24

24+30=54

perimeter c =4+8+8+4+11+7+4=46

so perimiter of c is 8cm shorter than A and B total

hope this helps

9497 ÷ 16 _R_ please

Answers

When you divide 9497 by 16, the quotient is 593 with a remainder of 9.

So, 9497 ÷ 16 = 593 remainder 9. Month

Please answer ASAP I will brainlist

Answers

Answer:

There is one solution. The solution is 2, 18, 19.

Step-by-step explanation:

If you want me to show working tell me in the comments and I'll edit the answer

Answer:

A. (2, 18, -19)

Step-by-step explanation:

To solve:

Z is the most suitable variable to remove first

Add the first equation to the second equation: (this conveniently removes both y and z)

(x+y-z) + (4x-y+z) = 1+9

Simplify

5x = 10

Solve

x = 2

Multiply the second equation by 2 and minus it to the third equation: (Solve for y)

2(4x-y+z) - (x-3y+2z) = 2(9) - (-14)

Simplify

8x-2y+2z-x+3y-2z=18+14

7x+y=32

Substitute using x=2

7(2) + y = 32

y = 32 - 14

y = 18

Now substitute x and y for their respective values into Equation 1

2 + (-18) - z = 1

Simplify

-z = 19

z = -19

So :

x = 2, y = 18 , z = -19

Roger can run one mile in 9 minutes. Jeff can run one mile in 6 minutes. If Jeff gives Roger a 1 minute head start, how
long will it take before Jeff catches up to Roger? How far will each have run?
They each will have run of a mile.

Answers

It will take approximately 5.33 minutes for Jeff to catch up to Roger. Both Jeff and Roger will have run a distance of 1 mile.

Let's calculate the time it takes for Jeff to catch up to Roger and the distance each will have run.

First, we need to determine how much distance Roger covers during the 1-minute head start. Since Roger runs one mile in 9 minutes, in 1 minute, he would cover 1/9 of a mile.

Now, let's set up an equation to represent the time it takes for Jeff to catch up to Roger:

Distance covered by Jeff = Distance covered by Roger + Distance covered during the head start

Let's denote the time it takes for Jeff to catch up as t minutes. During this time, Jeff runs a distance of 1 mile, while Roger runs a distance of 1/9 of a mile (from the head start).

Distance covered by Jeff = Distance covered by Roger + Distance covered during the head start

1 mile = (1/9) mile + (6 minutes) × t × (1 mile/6 minutes)

Now, let's solve this equation to find the time it takes for Jeff to catch up:

1 = (1/9) + (1/6)t

Multiplying the equation by the least common multiple (LCM) of 9 and 6, which is 18, to clear the fractions:

18 = 2 + 3t

Subtracting 2 from both sides:

16 = 3t

Dividing by 3:

t = 16/3 = 5.33 minutes (rounded to two decimal places)

Therefore, it will take approximately 5.33 minutes for Jeff to catch up to Roger. Both Jeff and Roger will have run a distance of 1 mile.

for such more question on distance

https://brainly.com/question/12356021

#SPJ8

Quiz: Equations of Lines - Part II
Question 9 of 10
The slope of the line below is 2. Which of the following is the point-slope form
of the line?
OA. y-1 -2(x+1)
B. y-1=2(x+1)
OC. y+1 -2(x-1)
D. y+1=2(x-1)
-10
10-
(1,-1)
10

Answers

Answer:

We have the slope of the line, which is 2 and a point that is (1, -1).

To find the point-slope form of the line, we use the equation:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the given point.

Substituting in the values we have, we get:

y - (-1) = 2(x - 1)

Simplifying this equation, we get:

y + 1 = 2(x - 1)

Therefore, the answer is option C: y + 1 - 2(x - 1).

The diagram shows the curve y = √8x + 1 and the tangent at the point P(3, 5) on the curve. The tangent meets the y-axis at A. Find:
(i) The equation of the tangent at P.
(ii) The coordinates of A.
(iii) The equation of the normal at P.​

Answers

The tangent and normal lines of the curve:

Case (i): y = (4 / 5) · x + 13 / 5

Case (ii): (x, y) = (0, 13 / 5)

Case (iii): y = - (5 / 4) · x + 35 / 4

How to determine the equations of the tangent and normal lines

In this problem we have the representation of a curve whose equations for tangent and normal lines must be found. Lines are expressions of the form:

y = m · x + b

Where:

m - Slopeb - Interceptx - Independent variable.y - Dependent variable.

Both tangent and normal lines are perpendicular, the relationship between the slopes of the two perpendicular lines is:

m · m' = - 1

Where:

m - Slope of the tangent line.m' - Slope of the normal line.

The slope of the tangent line is found by evaluating the first derivative of the curve at intersection point.

Case (i) - First, determine the slope of the tangent line:

y = √(8 · x + 1)

y' = 4 / √(8 · x + 1)

y' = 4 / √25

y' = 4 / 5

Second, determine the intercept of the tangent line:

b = y - m · x

b = 5 - (4 / 5) · 3

b = 5 - 12 / 5

b = 13 / 5

Third, write the equation of the tangent line:

y = (4 / 5) · x + 13 / 5

Case (ii) - Find the coordinates of the intercept of the tangent line:

(x, y) = (0, 13 / 5)

Case (iii) - First, find the slope of the normal line:

m' = - 1 / (4 / 5)

m' = - 5 / 4

Second, determine the intercept of the normal line:

b = y - m' · x

b = 5 - (- 5 / 4) · 3

b = 5 + 15 / 4

b = 35 / 4

Third, write the equation of the normal line:

y = - (5 / 4) · x + 35 / 4

To learn more on tangent lines: https://brainly.com/question/17193273

#SPJ1

what is the value of m

Answers

The value of m<RQS as required to be determined in the task content is; 70°.

What is the value of m<RQS as required to be determined?

It follows from the task content that the measure of angle RQS is to be determined as required.

Recall, the measure of the central angle subtended by an arc is twice that which it subtends at any point on the circumference.

Therefore, m<RPS = 2 • m<RQS.

m<RQS = 140°/2

m<RQS = 70°.

Ultimately, the measure of angle RQS are; 70°.

Read more on circle theorems;

https://brainly.com/question/30417099

#SPJ1

Which number line represents the solution set for the inequality 3(8 – 4x) < 6(x – 5)?

A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the left.
A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the right.
A number line from negative 5 to 5 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the left.
A number line from negative 5 to 5 in increments of 1. An open circle is at negative 3 and a bold line starts at negative 3 and is pointing to the right.

Answers

The number line that represents the solution set for the inequality 3(8 – 4x) < 6(x – 5) is option C: A number line from negative 5 to 5 in increments of 1. An open circle is at negative 3, and a bold line starts at negative 3 and is pointing to the left.

To determine the solution set for the inequality 3(8 – 4x) < 6(x – 5), we need to solve it step by step:

Simplify the inequality:

24 - 12x < 6x - 30

Combine like terms:

-12x - 6x < -30 - 24

-18x < -54

Divide both sides of the inequality by -18, remembering to flip the inequality sign:

x > (-54) / (-18)

x > 3

The inequality tells us that x must be greater than 3. To represent this on a number line, we place an open circle at the value 3 and draw a bold line pointing to the right to indicate that the solution set includes all values greater than 3.

Therefore, option C accurately represent the solution set for the inequality 3(8 – 4x) < 6(x – 5).

For more such questions on inequality, click on:

https://brainly.com/question/25275758

#SPJ8

Suppose we have two equations and they are both equal to each other. Equation A is "y = x^2 - 9" and Equation B is "y = x + 3". If we had to solve this system of equations, what quadratic equation do we have to solve in order to get our x values?
a. x^2 - x - 12 = 0
b. x^2 + x + 3 = 0
c. x^2 - x - 6 = 0

Answers

Answer:

a) x² - x - 12 = 0

Step-by-step explanation:

We have equation A = equation B

⇒ x² - 9 = x + 3

⇒ x² - 9 - x - 3 = 0

⇒ x² - x - 12 = 0

answer the question submitted

Answers

The function g(x) = 4x² - 28x + 49 can be rewritten as g(x) = 4(x - 7/2)² - 147 after completing the square.

To complete the square for the function g(x) = 4x² - 28x + 49, we follow these steps:

Step 1: Divide the coefficient of x by 2 and square the result.

  (Coefficient of x) / 2 = -28/2 = -14

  (-14)² = 196

Step 2: Add and subtract the value obtained in Step 1 inside the parentheses.

  g(x) = 4x² - 28x + 49

  = 4x² - 28x + 196 - 196 + 49

Step 3: Rearrange the terms and factor the perfect square trinomial.

  g(x) = (4x² - 28x + 196) - 196 + 49

  = 4(x² - 7x + 49) - 147

  = 4(x² - 7x + 49) - 147

Step 4: Write the perfect square trinomial as the square of a binomial.

  g(x) = 4(x - 7/2)² - 147

Therefore, the function g(x) = 4x² - 28x + 49 can be rewritten as g(x) = 4(x - 7/2)² - 147 after completing the square.

For more such questions square,click on

https://brainly.com/question/27307830

#SPJ8

The probable question may be:

Rewrite the function by completing the square.

g(x)=4x²-28x +49

g(x)= ____  (x+___ )²+____.

What is the slope of the line shown below?
-6
10
(-3,-7) 5
-10
AY
(9, 1)
10
15
X
O A.-²2/
3
OB.
NIM
O c. 3
2
O D.
3
MIN

Answers

Answer:

[tex]m = \frac{1 - ( - 7)}{9 - ( - 3)} = \frac{8}{12} = \frac{2}{3} [/tex]

B is the correct answer.

Find the solution to the equation below.

2x2+3x-20=0

Answers

X= 5.3333 repeating

Answer:

[tex]x = 5.3 \: or \: 5 \frac{1}{3} [/tex]

Step-by-step explanation:

[tex]2 \times 2 + 3x - 20 = 0 \: \: \: \: \: \: 4 + 3x - 20 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:3x = 20 - 4 = 16 \: \: \: \: \: \: \: \: 3x = 16 \: \: divide \: both \: side \: by \: 3 = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x = 5.3[/tex]

Identify the algebraic rule that would translate a figure 3 units left and 2 units up.

Answers

The algebraic rule for translating the figure 3 units left and 2 units up is (x-3, y+2).  Option B.

To translate a figure 3 units to the left and 2 units up, we need to adjust the coordinates of the figure accordingly. The algebraic rule that represents this translation can be determined by examining the changes in the x and y coordinates.

When we move a figure to the left, we subtract a certain value from the x coordinates. In this case, we want to move the figure 3 units to the left, so we subtract 3 from the x coordinates.

Similarly, when we move a figure up, we add a certain value to the y coordinates. In this case, we want to move the figure 2 units up, so we add 2 to the y coordinates.

Taking these changes into account, we can conclude that the algebraic rule for translating the figure 3 units left and 2 units up is (x-3, y+2). The x coordinates are shifted by subtracting 3, and the y coordinates are shifted by adding 2. SO Option B is correct.

For more question on algebraic visit:

https://brainly.com/question/30652385

#SPJ8

Question 4Multiple Choice Worth 5 points)
(Dilations MC)
Polygon ABCD with vertices at A(1,-1), B(3, -1), C(3, -2), and D(1, -2) is dilated to create polygon ABCD with vertices at A(4, -4), B(12,-4), C(12, -3), and D(4, -3). Determine the scale factor used to
create the image
0 1/4
0 1/2
0 2
0 4

Answers

The scale factor used to create the image of polygon ABCD is 4.

To determine the scale factor, we need to compare the corresponding side lengths of the original polygon ABCD and the image polygon ABCD. Let's denote the scale factor as k.

Original polygon ABCD:

Side AB: length = 3 - 1 = 2

Side BC: length = -2 - (-1) = -1

Side CD: length = 1 - 3 = -2

Side DA: length = -2 - (-1) = -1

Image polygon ABCD:

Side AB: length = 12 - 4 = 8

Side BC: length = -3 - (-4) = 1

Side CD: length = 4 - 12 = -8

Side DA: length = -3 - (-4) = 1

Comparing the corresponding side lengths, we can set up the following equations:

k * 2 = 8 (for side AB)

k * (-1) = 1 (for side BC)

k * (-2) = -8 (for side CD)

k * (-1) = 1 (for side DA)

From the equations, we can see that k = 4 satisfies all of them.

Therefore, the scale factor used to create the image of polygon ABCD is 4.

For more such questions on scale factor, click on:

https://brainly.com/question/29967135

#SPJ8

For which values is this expression undefined?

Answers

The values x = -5 and x = 3 make the second expression undefined. The correct answers are:

x = -5

x = 3

x= -3

To determine the values for which the given expressions are undefined, we need to find the values that make the denominators equal to zero.

First expression: [tex]\frac{3x}{(x^2 - 9)}[/tex]

For this expression, the denominator is (x^2 - 9). It will be undefined when the denominator equals zero:

x^2 - 9 = 0

Factoring the equation, we have:

(x - 3)(x + 3) = 0

Setting each factor equal to zero, we get:

x - 3 = 0 --> x = 3

x + 3 = 0 --> x = -3

So, the values x = 3 and x = -3 make the first expression undefined.

Second expression: [tex]\frac{(x + 4)}{(x^2 + 2x - 15)}[/tex]

For this expression, the denominator is (x^2 + 2x - 15). It will be undefined when the denominator equals zero:

x^2 + 2x - 15 = 0

Factoring the equation, we have:

(x + 5)(x - 3) = 0

Setting each factor equal to zero, we get:

x + 5 = 0 --> x = -5

x - 3 = 0 --> x = 3

So, The second expression is ambiguous because x = -5 and x = 3.

Consequently, the right responses are x = -5, x = 3 and x= -3.

for such more question on expressions

https://brainly.com/question/4344214

#SPJ8

Other Questions
Due today, 9:30 AM Assignment on Creativity 10 points 0 class comments Define the creativity and explain its type along with examples. Assignment should be as per class instruction format. Font size 12 Font style. Times new roman 2 page assignment *** How are allele frequencies changed through gene flow? Individuals have more or less offspring Random chance Mutations change the gene pool Individuals move in and out of a population Random mating occurs Question 47 Which of the following would be a behavioral adaptation that may result from a change in an organism's genetic traits over a period of time? Select all that apply. A rabbit has thick fur to keep it warm in the winter A male warbler performs a mating call to find a female A mother wolf has trained her pups to hunt for food A fish has large, strong fins to propel it through water A chameleon changes colors to match surroundings and perfectly camouflage Can different soils develop from the same kind of parent material? Can similar soils develop from different parent materials? Select the answers below that are correct. There may be more than one correct answer. Group of answer choicesA.Different soils can develop on similar parent materials given necessary changes in the other factors such as climate and time.B.Parent material determines what kind of soil develops. You cannot develop different types of soil from the same parent material.C.Similar soils can develop on different parent material given appropriate changes in the climate and length of time the soil has been developing.D.Even changes in climate or length in time will not develop similar soils from different parent materials. 13. Which of the following was not reported to be a problem in Flint during the water crisis Red water Taste and odor Legionella E. coli contamination High lead levels Trihalomethane exceedances 14. Pick all that apply: Which of the following may have contributed to the corrosion of the lead pipes in Flint and release of lead? High pH High water temperatures during summer Formation of low molecular weight compounds Addition of alum as a coagulant Addition of ferric chloride as a coagulant 15. In the Flint Water Treatment Plant, which chemical has been added since December 2015 (after the return to treated water from Lake Huron) to try to repassivate the pipes in the distribution system? ferric chloride cationic polymer anionic polymer ozone phosphate 16. In the Flint Water Treatment Plant, which process likely contributed to the formation of low molecular weight compounds in the treated water? Ozonation Disinfection Recarbonation Granular media filtration Sedimentation Lime softening Flocculation Rapid mix17. Of the following processes, which one would be the final stage in sludge treatment process? Digestion Dewatering Drying Thickening 18. In which sludge treatment process, are the organic solids converted into more stable form? Dewatering Thickening Digestion Conditioning An operator is creating a dial to control the reflux ratio in a distillation column. What must be the two values for the limits of the dial? (1 Point) O and infinity -1 and 1 1 and infinity O and 1 Suppose that you made three purchases using your credit card during the month of January. - The first purchase was on January 8th for $492. - The second purchase was on January 19th for $292. - The third purchase was on January 24ti . If your average daily balance for January was $695, what was the dollar amount of your last purchase? Remember: - There are 31 days in January. - You made no purchases between January 1 st and January 7 th. - This question is not asking for the card's final January balance. Round your answer to the nearest dollar. Question 4 A $14,513 par value bond whose coupon rate is 4.9% is purchased. If the investment represents a current yield of 3.1%, compute the bond's market price at the time of the purchase. Round your answer to the nearest dollar. Identify 10 top level functions for this software system and draw a FFBD for this system using the identified functions. (15) Consider the following matrix:G=[369 12:48 12 16; 369 12]What Octave command will you use obtain the following matrix: [4,8;3,6] Why is it important to never exceed an establishment's licensed maximum capacity?a.Overcrowding can make the premises unsafe and is a violation of the LLA.b.Overcrowding leads to lower tips.c. Fire exits can be blocked.d.Servers cannot safely monitor how much alcohol each guest is consuming A sorting algorithm takes two operations to sort an array with one item in it. Increasing the number of items in the array from n to n + 1 requires at least n + 2 more. Prove by induction that the number of operations required to sort an array with n items requires at least 1 2 n(n + 3) operations The drawing shows a collision between two pucks on an air-hockey table. Puck A has a mass of 0.0220 kg and is moving along the x axis with a velocity of +5.26 m/s. It makes a collision with puck B, which has a mass of 0.0440 kg and is initially at rest. The collision is not head-on. After the collision, the two pucks fly apart with the angles shown in the drawing. Find the speed of (a) puck A and (b) puck B. Find the measure of the indicated angle.- 20161"61*73"H73195E Compare between Wordsworths poems: You can use a timetable or discuss the ideas one after the other in each poem.I wandered lonely as a cloud & The Solitary reaperFocus on the followings:1- The setting and the theme presented2- Figures of Speech (3 at least in each poem) with an explanation.3- Comment of the end of the two poems PLEASE COMPLETE IN JAVA CODEimport java.util.*;public class Bigrams {public static class Pair {public T1 first;public T2 second;public Pair(T1 first, T2 second) {this.first = first;this.second = second;}}protected Map, Float> bigramCounts;protected Map unigramCounts;// TODO: Given filename fn, read in the file word by word// For each word:// 1. call process(word)// 2. increment count of that word in unigramCounts// 3. increment count of new Pair(prevword, word) in bigramCountspublic Bigrams(String fn) {}// TODO: Given words w1 and w2,// 1. replace w1 and w2 with process(w1) and process(w2)// 2. print the words// 3. if bigram(w1, w2) is not found, print "Bigram not found"// 4. print how many times w1 appears// 5. print how many times (w1, w2) appears// 6. print count(w1, w2)/count(w1)public float lookupBigram(String w1, String w2) {return (float) 0.0;}protected String process(String str) {return str.toLowerCase().replaceAll("[^a-z]", "");}public static void main(String[] args) {if (args.length != 1) {System.out.println("Usage: java Bigrams ");System.out.println(args.length);return;}Bigrams bg = new Bigrams(args[0]);List> wordpairs = Arrays.asList(new Pair("with", "me"),new Pair("the", "grass"),new Pair("the", "king"),new Pair("to", "you"));for (Pair p : wordpairs) {bg.lookupBigram(p.first, p.second);}System.out.println(bg.process("adddaWEFEF38234---+"));}} Do you see a scenario where the FDA merges with other authority bodies such as the USDA and in turn have better oversight and control over issues within the dietary supplement industry? Arguments for and against Euthanasiawrite at least 500 words urgently needed this question answerplease answer fast Compare and contrast the logistics strategies of China and the European Union. Basically, compare "Belt and Road" with the EU Transport WhitePaper Determine the Fourier transform of the following signals: a) x [n] = 2-sin(+) b) x [n] = n(u[n+ 1]- u[n-1]) c) x3 (t) = (e at sin(wot)) u(t) where a > 0 If the Ammeter (represented by G:Galvanometer) would read 0 A in the circuit given Figure3-1 of your lab instructions, what would be the R1, if R2=7.050, R3=5.710 and R4= 8.230. Give your answer in units of Ohms(0) with 1 decimal In matlab how do I plot the phase and magnitude spectrum of theFourier Transform of (1 + cos(2x)) ?