Detailed answer if possible I look to try and understand how to do this. So there is no need for a rushed answer just a detailed one so I can know how to do problems like these.

Answer:

15.2

[tex] {c }^{2} = {a}^{2} + {b}^{2} \: \\ {c}^{2} ={6}^{2} + {14}^{2} \\ {c}^{2} = 36 + 196 \\ {c}^{2} = 232 \\ \sqrt{c } = \sqrt{232} \\ c = 15.23154621[/tex]

Answer:

It is 9214.2

Step-by-step explanation:

[tex](125 + 47 - 2.5) \div 140 + 37 \times 249[/tex]

first solve the bracket:

[tex] = (169.5) \div 140 + 37 \times 249[/tex]

form brackets of division and multiplication:

[tex] = (169.5 \div 140) + (37 \times 249)[/tex]

solve the brackets:

[tex] = 1.211 + 9213[/tex]

then add:

[tex] = 9214.211[/tex]

You are falling by [tex]32[/tex],

[tex]128, 128 - 32, 128 - 32\cdot2,\dots[/tex]

In general your sequence is defined as,

[tex]a_n=128-32\cdot n[/tex] where [tex]0\leq n \lt\infty[/tex].

The question is at which [tex]n[/tex] does the value [tex]a_n=0[/tex].

If you divide [tex]128[/tex] with [tex]32[/tex] you get the number of steps needed to stuff [tex]128[/tex] with [tex]32[/tex], [tex]4[/tex].

If you plug in [tex]n=4[/tex], you get [tex]a_4=128-32\cdot4[/tex], since [tex]32\cdot4=128[/tex] you get [tex]a_4=0[/tex].

The zero turn of the arithmetic sequence is thus at [tex]n=4[/tex].

Hope this helps :)

9514 1404 393

Answer:

  y = 10

Step-by-step explanation:

Put -3 where x is and solve for y.

  4(-3) +3y = 18

  -4 +y = 6 . . . . . . . divide by 3

  y = 10 . . . . . . . . . add 4

Answer:

A.

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

because BC=CD as it is parallel that means all the sides are equal

The value of CD is 20/3.

The correct option is (A).

Similar triangles are triangles that have the same shape, but their sizes may vary. All equilateral triangles, squares of any side lengths are examples of similar objects. In other words, if two triangles are similar, then their corresponding angles are congruent and corresponding sides are in equal proportion.

In ACB and ECD,

angle CAB= angle DEC

angle CBA= angle EDC

angle DCE = angle ACB

By, AA similarity criteria,

ΔACB~ΔECD

Now,

AC/CE= BC/CD

3/5=4/CD

CD= 20/3

Learn more about similarity property here:

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Answer:

100 yojan=how much km

1287.48

please brainlist

Answer:

f(x) = -3x^2 + 10x + 3

Step-by-step explanation:

(0,3) (2,11)(3,6)

Using the form ax^2 + bx + c = y

From the first set we know that c = 3

Write an equation for the last two sets

x=2; y=11

a(2^2) + b(2) + 3 = 11

4a + 2b = 11 - 3

4a + 2b = 8

simplify divide by 2

2a + b = 4

and

x=3, y=6

9a + 3b + 3 = 6

9a + 3b = 6 - 3

9a + 3b = 3

simplify divide by 3

3a + b = 1

:

Use elimination to find a

3a + b = 1

2a + b = 4

--------------subtracting eliminate b

a = -3

Find b using the equation 2a + b = 4

2(-3) + b = 4

b = 4 + 6

b = 10

:

The equation: f(x) = -3x^2 + 10x + 3

Answer:

14,712 ft difference

Step-by-step explanation:

15,062 - 350 = 14,712

Answer:

Step-by-step explanation:

Difference in elevation is 15,062-(-350)=15,062+350=15,412

Answer: 2 13/ 15

Step-by-step explanation:

Answer:

98376

Step-by-step explanation:

Answer:

B) Both functions have a y-intercept of -2.

Step-by-step explanation:

Hi there!

A) Both functions are always increasing.

⇒ False

Let's first take a look at the given equation, [tex]y=3x-2[/tex]. This is a linear equation, and it is organized in slope-intercept form: [tex]y=mx+b[/tex]. m is the slope and b is the y-intercept. When m is positive, it is always increasing.

In [tex]y=3x-2[/tex], 3 is m, and because it's positive, this line is always increasing on a graph.

However, when we take a look at the given graph, this isn't the case. It is decreasing for values of x below 0 (on the left side of the y-axis).

B) Both functions have a y-intercept of -2.

⇒ True

In the given equation [tex]y=3x-2[/tex], this is true. -2 is the y-intercept.

On the given graph, we can see that the graph intercepts the y-axis at -2, so this is also true for the graph.

C) Both functions are symmetric about the y-axis.

⇒ False

The given graph is symmetric about the y-axis, but the line is not. Any line that would be symmetric about the y-axis would be in the form [tex]y=b[/tex], which isn't the case here with [tex]y=3x-2[/tex]. [tex]y=3x-2[/tex] has a slope.

D) Both functions are linear relationships.

⇒ False

Sure, [tex]y=3x-2[/tex] is a linear equation, making it a line, but not the given graph. The graph does not resemble a straight line, so it is not a linear relationship.

I hope this helps!

Answer:

72+12

Step-by-step explanation:

Answer:

12000

Step-by-step explanation:

8000+4000=12000

Answer:

Step-by-step explanation:

Step-by-step explanation:

First let solve the inequality

[tex]5 {x}^{2} + 2x - 3 < 0[/tex]

Factor by grouping

[tex]5 {x}^{2} + 5x - 3x - 3 < 0[/tex]

[tex]5x(x + 1) - 3(x + 1)[/tex]

So the factor are

[tex](5x - 3)(x + 1)[/tex]

So the factor are

[tex]x = \frac{3}{5} [/tex]

and

[tex]x = - 1[/tex]

Solutions to a quadratic can be represented by a absolute value equation because remeber quadratics

creates 2 roots and/or double roots.

The inequality

[tex] |x - b| < c[/tex]

works as

b is the midpoint between 2 roots. And c is the

[tex] |x + b| = c[/tex]

We know that the midpoint between both roots is-1/5.

so

[tex] |x - ( - \frac{1}{5} )| < c[/tex]

[tex] |x + \frac{1}{5} | < c[/tex]

Let use roots 3/5

[tex] | \frac{3}{5} + \frac{1}{5} | = \frac{4}{5} [/tex]

-1 works as well.

[tex] | - 1 + \frac{1}{5} | = | - \frac{4}{5} | = \frac{4}{5} [/tex]

So the absolute value equation is

[tex] |x + \frac{1}{5} | < \frac{4}{5} [/tex]

Answer:

2

Step-by-step explanation:

=3+5×5-25+3-4

=3+25-25+3-4

=28-22-4

=28-26

=2

Answer:

2

Step-by-step explanation:

3 + 5 * 5 - 50 / 2 + 3 - 4

3 + (5 * 5) - 50 / 2 + 3 - 4  => Multiplication what ever comes first

3 + 25     (-50 / 2) + 3 - 4  => Division left to right

(3 + 25)     - 25  +( 3 - 4)  => Addition what ever comes first

28  - 25 - 1 => Substraction  left to right

2

Leave comment if you're curious.

Answer:

(x-10)/4

Step-by-step explanation:

10 less than x means,

x - 10

and the divide by 4.

=> (x-10)/4

Answer:

x-10/4

10 less than x

x-10

divided by 4

/4

Define relation.

Let A and B are only two non-empty set,then A*B is cartesian product of A*B.Then any subset of A*B is known as the relation fromA to B.

3. x = 45

4. 73°

Step-by-step explanation:

3. The sum of the interior angles of a pentagon is 540° so

90° + 112° + 2x + (2x + 10) + 148° = 540°

Simplifying this, we get

4x + 360 = 540 => 4x = 180 or x = 45

4. The sum of the interior angles of a pentagon is 540° which means that the unknown interior angle is 107°. This angle is a supplementary angle to [tex]\angle{A}[/tex] so [tex]\angle{A}[/tex] is

180° - 107° = 73°.

Depending on the length of the two sides of the triangle the length could be smaller than 1.

The answer that is not true is :

B. It is always greater than 1

Answers and Step-by-step explanation:

Question 8:

Since angle BCD is opposite angle DAB, this means that they are similar angles as the shape is a parallelogram, and so BCD is 115 degrees, or answer D

Question 3:

We can use process of elimination on this question - The first choice is all squares are rhombuses, which is true. The second question is all rectangles are squares, which is not true, therefore the answer is B

Question 4:

m angle 2 is equal to 106, as it is similar to question 8, and angle 3 is equal to 360 (the total degrees of the shape) - 106 - 106, then divided by 2 and divided by 2 again.

This will equal to angle 3 being 37 degrees, and the answer will be C

Question 5:

We can draw a rectangle from this graph. We can also tell that, in theory, the diagonals are the same, that rules out answer B, and also 5x-5 = x+11

We can then find out x.

+5 on both sides

5x = x+16

-x on both sides

4x = 16

x = 4.

Therefore, each of the sides will be 4+11 = 15, and the answer being C

p ∧ q (i.e. "p and q") is true only if both p and q are true. This is the case for the first two rows, but not the third.

Similarly, (p ∧ q) ∧ r is true only if both p ∧ q and r are true. We know when p ∧ q is true, so (p ∧ q) ∧ r is true only when all three of p, q, and r are true. This happens only in the first row.

All other cases are false.

The table should look like this:

[tex]\begin{array}{c|c|c|c|c}p&q&r&p\land q&(p\land q)\land r) \\---&---&---&---&--- \\T&T&T&\boxed T&\boxed T\\&&&&\\T&T&F&\boxed T&\boxed F\\&&&&\\T&F&T&\boxed F&\boxed F\end{array}[/tex]

Answer:

Step-by-step explanation:

60  

600

The comparison of both resistors is defined by an inequality. Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]

Given that:

[tex]R = 100 \Omega[/tex] ---- the reference resistor

First, we calculate the resistance of both resistors

Resistor A differs by [tex]0.15\Omega[/tex] means that:

[tex]R_A = 100\Omega + 0.15\Omega[/tex]

[tex]R_A = 100.15\Omega[/tex]

Resistor A has a resistance of [tex]100.15\Omega[/tex]

Resistor B differs by [tex]-0.78\Omega[/tex] means that:

[tex]R_B = 100\Omega -0.78\Omega[/tex]

[tex]R_B = 99.22\Omega[/tex]

Resistor B has a resistance of [tex]99.22\Omega[/tex]

By comparing the calculated values, we can conclude that:

Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]

Read more about inequality comparison at:

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