could anyone help me with this?

Could Anyone Help Me With This?

Answers

Answer 1

Answer:

C

Step-by-step explanation:


Related Questions

Find the area of the shaded region. Round to the nearest hundredth where necessary. Hint: Could you find the radius? ​

Answers

Answer:

13.72 cm²

Step-by-step explanation:

The formula to find the area of a shaded region: Area of the bigger shape - area of the smaller shape.

The formula to find the area of a square: [tex]a^{2}[/tex], where [tex]a[/tex] is the side.

The formula to find the area of a circle: [tex]\pi r^{2}[/tex], where [tex]\pi[/tex] is 3.14 or [tex]\frac{22}{7}[/tex] or 3.142 or similar, [tex]r[/tex] is the radius (diameter ÷ 2).

1) Find the area of the circle using the formula. The radius is 4 because the diameter is 8 (8 ÷ 2 = 4).

= [tex]\frac{22}{7}*4^{2}[/tex]

= [tex]\frac{22}{7}*16[/tex]

= 50.285

2) Find the area of the square using the formula.

= [tex]8^{2}[/tex]

= 64

3) Apply: area of the bigger shape - area of the smaller shape.

= 64 - 50.285

= 13.715

4) Round it off to the nearest hundredth.

= 13.72

i have another very simple question before this thats worth 100 points go answer it. whats 2,231.5 milligrams to grams, dont delete this question for christ sake

Answers

Answer:

te paso mi canal subcribete y la respueta

Step-by-step explanation:

2.2315

mi canal es navegando con incognito subcribete

2.232 grams, you just move the decimal place and round to the nearest thousandth

Henry was thinking of a number. Henry adds 2, then divides by 5 to get an answer of -10. What was the original number?

Answers

-52 + 2 = -50
-50 / 5 = -10

15 x 18 + 12 ÷ 3 + 9

1. 15 x 18 =270
2. 270 + 12 divided by 3 + 9
3. 12 divided by 3 = 4
4. 270 + 3 + 9
5. 270 + 3= 273
6. 273 + 9 = 282

The answer is 282.​

Answers

Answer:

283

Step-by-step explanation:

[tex]15 \times 18 + 12 \div 3 + 9 \\ 270 + 4 + 9 \\ 283[/tex]

By using BODMAS rule

Before adding the 12 u have to divide 12 by 3 =4 then u will add 4

Answer:

Your wrong the correct answer is 283

Step-by-step explanation:

[tex]15 \times 18 + 12 \div 3 + 9 \\ = 270 + 4 + 9 \\ = 283 \\ [/tex]

{ The algorithm, multiplication and division comes first, then addition}

Find the circumstance of a circle with the diameter of 13 meters use 3.14 as an approximation

Answers

Answer:

okay so the circumference is 40.82m

[tex]circumference = 2\pi \: \times r \\ = 2 \times 3.14 \times 6.5 \\ = 40.82m[/tex]

the diameter will be divided by 2 to give 6.5

What is the interquartile range for 8 9 3 12 4 4 8 7 2 10

Answers

Answer: 5

Step-by-step explanation:

lower quartile: 4

upper quartile: 9

9-4=5

IQR=5

Need help with 115/120 please and thank you

Answers

Answer:

115: a) -4

120: a) 11

Step-by-step explanation:

115: Use the formula  

[tex]m = \frac{rise}{run} = \frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

= (-5)-(3) / (6) - (4)

= -8 / 2

= -4

120: Count the units between point B and point F

Milan deposits $4,000 into an account that pays simple interest at an annual rate of 2%. He does not make any more deposits. He makes no withdrawals until the end of 2 years when he withdraws all the money.

(a) How much total interest will Milan earn?
(b) What will the total amount in the account be (including interest)?

Answers

A. Use the equation I=Prt
I=4000x 0.02 x 2
Total of $160 earned

B. 4000+160 = $4160 is the total amount after 2 years including interest

Please help! Refer to the image below.

Answers

If u = ⟨-4, 8⟩ and v = ⟨5, -18⟩, then we have

2u - 4v = ⟨-8, 16⟩ + ⟨-20, 72⟩ = ⟨-28, 88⟩

To this vector, we want to add another vector w = ⟨a, b⟩ such that

2u - 4v + w = ⟨0, 1⟩

Solve for w :

w = ⟨0, 1⟩ - ⟨-28, 88⟩ = ⟨28, -87⟩ … … … [C]

PLEASE HELP ME WITH THIS!!!! I BEG

Answers

Answer:

D. turns

Step-by-step explanation:

Rotation is the process of turning around a center or an axis.

(Sorry if it's wrong. I hope I helped somewhat.)

Use the associative property to rewrite the expression: -6+(3+7)

Answers

Since the 3 and 7 in the brackets are both like numbers we can combine them to make 10 and change the equation to -6+10 or 10-6

Upon review of production results, it was determined that 130 pieces out of 3,500 were "out of spec." What percent of the production was "out of spec"?

A. 0.03 percent .
B. 3.71 percent .
C. 30 percent
D. 37.1 percent

Answers

Answer:

Option B

Step-by-step explanation:

Given:

130 pieces of 3500 were out of spec

To determine the percentage of the production was out of spec, we need to use the percentage formula (x/y × 100).

[tex]\implies \dfrac{x}{y} \times 100[/tex]

The value of "x" is the the number of pieces that were out of spec and the value of "y" is the total pieces in the production results.

[tex]\implies \dfrac{130}{3500} \times 100[/tex]

Simplify the expression to determine the percentage of the pieces that were out of spec.

[tex]\implies \dfrac{13000}{3500}[/tex]

[tex]\implies \dfrac{130}{35} = \dfrac{130 \div 5}{35 \div 5} = \dfrac{26}{7} = 3.714... \%[/tex]

When the percentage is estimated to nearest hundredth, we get 3.71%

(Option B)

Answer:

B)  3.71%

Step-by-step explanation:

[tex]\textsf{130 out of 3500}\sf =\dfrac{130}{3500}[/tex]

To convert to a percentage, multiply by 100:

[tex]\implies \sf \dfrac{130}{3500} \times 100\%=0.03714.. \times 100\%=3.71\%[/tex]

Lisa cut out 36 paper snowflakes to decorate her room.

Then her brother gave her 28 paper snowflakes that he had made.

If she chooses to use only half of the snowflakes to decorate, how many will
she have left over?

Answers

Answer: 32

Step-by-step explanation:

We know that the original number of paper snowflakes was 36, plus 28 given by her brother. The new total would be 64 paper snowflakes and she only uses half of the paper snowflakes. The answer would be 32.

What is the interquartile range for 0,2,4,6,8,and 10

Answers

The formula for finding the interquartile range takes the third quartile value and subtracts the first quartile value. Equivalently, the interquartile range is the region between the 75th and 25th percentile (75 – 25 = 50% of the data).

Answer:

6

Step-by-step explanation:

Find the interquartile range (h-spread).

:)

Which function is equivalent to g(x)= x2 +11x-60?

Answers

Answer:
g(x) = x^2 + 11x - 60
(a=1, b=11, c=-60)
To solve this quadratic equation we need to find the discriminant:
discriminant= b^2 - 4ac
= (11)^2 - 4(1)(-60)
=121 - (-240) = 121+240 =361
(if discriminant<0 then equation has no real root
if discriminant=0 then equation has 1 real root
if discriminant>0 then equation has 2 real roots)
Here we have discriminant=361>0 so we have 2 real roots:
x1=(-b-redical discriminant) / 2a
and x2=(-b+redical discriminant) / 2a
x1= (-11-redical(361)) / 2(1)
=-15
x2= (-11+redical(361)) / 2(1)
=4
So we get the two roots x= -15 and x= 4
To write the quation in factorized form:
x= -15 means that x+15=0
x= 4 means that x-4=0
Therefore g(x)= (x+15)(x-4)
D is the correct answer
HOPE THIS HELPS :)

If The radius of a quarter circle is 3 miles. What is the quarter circle's perimeter?

Answers

Answer:

6pi miles

Step-by-step explanation:

Answer: 6pi

formula for perimeter: pi*diameter

diameter=radius*2

diameter=3*2=6

6*pi=6pi

Add. Write the answer as a fraction simplified to lowest terms.
2+1 15 20 =

Answers

Answer:

Step-by-step explanation:

LCD (15,20) = 60

[tex]\frac{2}{15}[/tex] + [tex]\frac{1}{20}[/tex] = [tex]\frac{8}{60}[/tex] + [tex]\frac{3}{60}[/tex] = [tex]\frac{11}{60}[/tex]

Answer:

2/15 + 1/20 = 11/60

Step-by-step explanation:

1. Find the least common denominator or LCM of the two denominators:

15 and 20.

Steps to find LCM:

1. Find the prime factorization of 15

15 = 3 × 5

2. Find the prime factorization of 20

20 = 2 × 2 × 5

3. Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM:

LCM = 2 × 2 × 3 × 5

LCM = 60

2. Next, find the equivalent fraction of both fractional numbers with denominator 60.

For the 1st fraction, since 15 × 4 = 60,

2/15 = 2 * 4 / 15 * 4 = 8/60

Likewise, for the 2nd fraction, since 20 × 3 = 60,

1/20 = 1 * 3 / 20 × 3 = 3/60

Add the two like fractions:

8/60 + 3/60 = 8 + 3/60 = 11/60

Help would be very appreciated!!

11 points

Answers

Answer:

29 candy bars

Step-by-step explanation:

13 movie pases= $9.50x13= $123.50

3 gift cards= $25×3 =$75

amount of money she has left over to buy candy bars = $250- $75- $123.5 = $51.50

Amount of candy bars she can buy = $51.50÷$1.75 = 29.43 candy bars, but u can only buy full candy bars and there for 29 candy bars is the final answer

2) A bus left the bus depot at 11:45am. It arrived at its destination at 12:25pm. How long did the journey take?

Answers

Answer:

40 minutes

Step-by-step explanation:

11:45 plus 40 minutes = 12:25

What number increased by ¼ of itself is equal to 30?

Answers

Answer:

x = 24

Step-by-step explanation:

let x be the number we want to determine its value

The statement  x increased by ¼ of itself is equal to 30

is equivalent to :

[tex]x + \frac{x}{4}=30\\\\then[/tex]

[tex]\frac{4x+x}{4} = 30\\\\then[/tex]

[tex]\frac{5x}{4} = 30\\\\then[/tex]

5x = 4× 30

then

5x = 120

then

x = 120/5

then

x = 24

2x<5x-15 Solve check use x = 10)

Answers

Answer:

x= -5

Step-by-step explanation:

not right its -5

50 paise × 1000 give your answer in rupees​

Answers

Answer:

10 rs

Step-by-step explanation:

I hope it's helpful for you

Okie help help help math math

Answers

Answer:

the answer is x>5 please. rate. me. brainliest

Answer:

x>3

x greater then 3 ..........

Is 5 1/2 2.5 or 5.5?​

Answers

Answer:

Volume = 92.15

Step-by-step explanation:

V=πr2h/3=π·42·5.5/3≈92.15

60 point help What are domain restrictions of rational functions? What do domain restrictions mean for the graph of a rational function?

Answers

Answer:

1. The use of a domain for a function that is smaller than the function's domain of definition. Note: Restricted domains are commonly used to specify a one-to-one section of a function.

2. Domain restrictions can be calculated by finding singularities, which are the x -values for which the denominator Q(x) is zero.

Answer:

by setting the denominator equal to zero and solving. The x -values at which the denominator equals zero are called singularities and are not in the domain of the function.

Step-by-step explanation:

Question 1 of 10
How many solutions are there to the equation below?
x = -5
A. 2
B.1
C.0
D.25

Answers

Answer:

Answer is either 1 or 2

Step-by-step explanation:

need help pls i will give brainliest.

Answers

Answer:

g= 60°

i= 70°

h= 50°

Step-by-step explanation:

g=180-120 = 60°

i= 180-110 = 70°

h=180-60-70 = 50°

hope this helps =)

Kindly rate and mark brainliest. Thank you.

Question 3 on math!
Please help me 15 points

Answers

Answer:

2nd one

Step-by-step explanation:

if you were to look on a grid the slope would point up

Determine whether each statement correctly describes the likelihood of an event based on the given number cube. Select True or
False for each statement.
True or False

Answers

The statement that correctly descrives the likelilhood of an event based on the given numbered cube is: Option A: It is likely that a number less than 6 is occured.

How to decide the likelihood of an event?

Suppose that for a considered sample space, we consider an event E

Then, E is likely to occur if:

[tex]P(E) \geq P(E')[/tex]

where [tex]E_i '[/tex] is complementary event of E (ie, E'  occurs whenever E doesn't occur and vice versa)

If so, then we say that E is likely to occur as the outcome of the considered random experiment, else unlikely.

Since we have:

[tex]P(E) = 1- P(E')[/tex] due to E and E' being complement of each other, therefore, we get:

[tex]P(E) \geq 1 - P(E)\\P(E) \geq 0.5[/tex]

Thus, event E is said to be likely if its probability is greater or equal to 0.5, else not.

It is given that the cube is 6 faced (assuming all equally likely), numbered from 1 to 6.

Evaluating likelihood of each event:

It is likely that a number less than 6 is obtained on the number cube.

P(Getting a number < 6 on that cube) = [tex]\dfrac{5}{6}[/tex] (since a number out of 6 numbers can occur in 6 ways, but it being < 6 can be done in 5 ways).

Thus, we have:

P(Getting a number < 6 on that cube) =5/6 > 0.5

So it is likely to get a number < 6 on the considered cube. So this statement correctly describes the likelihood of its considered event.

It is unlikely that a number < 4 is obtained on the number cube.

Ways to get a number on the considered cube = 6

Ways to get a number < 4 on the considered cube = 3

Thus, we get:

P(Getting a number < 4 on that cube) = 3/6 = 0.5

Thus, it is likely to get a number < 4 on that cube, so this option is wrong.

It is certain that an odd or even number is obtained on the number cube

Yes it is certain, but we're considering only those options which correctly describe likelihood instead of certainity.

So, this option is not considerable.

It is unlikely that a number > 1 is obtained on the number cube.

Ways to get a number on the considered cube = 6

Ways to get a number > 1 on the considered cube = 5

Thus, we get:

P(Getting a number > 1 on that cube) = 5/6 > 0.5

Thus, it is likely to get a number > 1 on that cube, so this option is wrong.

Thus, the statement that correctly descrives the likelilhood of an event based on the given numbered cube is: Option A: It is likely that a number less than 6 is occured.

Learn more about likelihood of events here:

https://brainly.com/question/14954386

#SPJ1

Find the derivative.
[tex]\dfrac{d}{dx} \left[ \sin^{-1}(\cos e^x)-\cos^{-1}(\sin e^x) \right][/tex]

Answers

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

[tex]\qquad \tt \dashrightarrow \:\dfrac{d}{dx} \left[ \sin^{-1}(\cos e^x)-\cos^{-1}(\sin e^x) \right][/tex]

[tex]\qquad \tt \dashrightarrow \:\dfrac{d}{dx} \sin^{-1}(\cos e^x) - \dfrac{d}{dx}\cos^{-1}(\sin e^x) [/tex]

[tex]\qquad \tt \dashrightarrow \: \bigg(\dfrac{1}{ \sqrt{1 - ( \cos( {e}^{x} ) ) {}^{2} } } \times - \sin( {e}^{x} ) \times {e}^{x} \bigg) - \bigg( - \dfrac{1}{ \sqrt{1 - ( \sin( {e}^{x} )) {}^{2} } } \times \cos( {e}^{x} ) \times {e}^{x} \bigg)[/tex]

[tex]\qquad \tt \dashrightarrow \: \bigg(\dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ \sqrt{1 - ( \cos( {e}^{x} ) ) {}^{2} } } \bigg) - \bigg( - \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ \sqrt{1 - ( \sin( {e}^{x} )) {}^{2} } } \bigg)[/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ \sqrt{1 - \cos {}^{2} ( {e}^{x} ) {}^{} } } + \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ \sqrt{1 - \sin {}^{2} ( {e}^{x} ) {}^{} } } [/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ \sqrt{ { \sin}^{2} ( {e}^{x} ) {}^{} } } + \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ \sqrt{ \cos {}^{2} ( {e}^{x} ) {}^{} } } [/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - {e}^{x} \sin( {e}^{x} ) }{ { { \sin}^{} ( {e}^{x} ) {}^{} } } + \dfrac{ {e}^{x} \cos( {e}^{x} ) }{ { \cos {}^{} ( {e}^{x} ) {}^{} } } [/tex]

[tex]\qquad \tt \dashrightarrow \: - {e}^{x} + {e}^{x} [/tex]

[tex]\qquad \tt \dashrightarrow \:0[/tex]

I hope this helps, if you find any problem with steps or got a mistake in my explanation then feel free to ask me ~

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