The circles are similar because you can translate Circle 1 using the transformation rule (9, 5) and then dilate it using a scale factor of 2.
To prove that Circle 1 and Circle 2 are similar, we need to identify the transformations that can be applied to Circle 1 to obtain Circle 2.
First, let's consider the translation of Circle 1. The translation rule is given by (a, b), where a represents the horizontal shift and b represents the vertical shift.
In this case, to translate Circle 1 to align with Circle 2, we need to shift it 9 units to the right and 5 units up. Therefore, the translation rule for Circle 1 is (9, 5).
Next, let's consider the dilation. A dilation is a transformation that changes the size of the figure but preserves its shape. The scale factor, denoted by k, determines the amount of scaling. In this case, Circle 1 needs to be dilated to match the size of Circle 2.
The scale factor can be determined by comparing the radii of the two circles. The radius of Circle 1 is 3 centimeters, while the radius of Circle 2 is 6 centimeters. The scale factor is obtained by dividing the radius of Circle 2 by the radius of Circle 1: 6/3 = 2.
Therefore, the transformation applied to Circle 1 to prove that the circles are similar is a translation by (9, 5) followed by a dilation with a scale factor of 2.
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Let {X₁} be independent standard normal random variables. Let Y = (X₁ + X3 + X5 + X7)² + (X₂ + X₁ + X6 + X8)². Determine a value c such that the random variable cY will have an x² distribution
The value of "c" such that the random variable cY has an x² distribution is 4.
To find the value of "c" such that the random variable cY has a chi-squared (x²) distribution, we need to consider the properties of the chi-squared distribution and the given expression for Y.
The chi-squared distribution with "k" degrees of freedom is obtained by summing the squares of "k" independent standard normal random variables. Each standard normal variable contributes one degree of freedom to the chi-squared distribution.
In the given expression for Y, we have two squared terms: (X₁ + X₃ + X₅ + X₇)² and (X₂ + X₁ + X₆ + X₈)². To obtain an x² distribution, we need to rewrite the expression in terms of squared standard normal random variables.
To achieve this, we can divide each squared term by its corresponding degrees of freedom and take the square root:
Y = (X₁ + X₃ + X₅ + X₇)² + (X₂ + X₁ + X₆ + X₈)²
= (1/4)(X₁ + X₃ + X₅ + X₇)² + (1/4)(X₂ + X₁ + X₆ + X₈)²
Now, we can rewrite Y as:
Y = (1/4)χ²₁ + (1/4)χ²₁
Here, χ²₁ and χ²₂ represent chi-squared random variables with 1 degree of freedom each.
To obtain an x² distribution, we need to make the coefficients of the chi-squared random variables equal to their degrees of freedom. In this case, we want the coefficient to be 1.
So, setting the coefficient of χ²₁ to 1, we get:
(1/4) = 1/c
Solving for "c", we find:
c = 4
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Two square-shaped fields are next to each other. The perimeter of each field is 36 feet. The two fields are joined together to form a single rectangular field. What is the perimeter of the rectangular field? (1 point) a 72 feet b 63 feet c 54 feet d 45 feet
Answer:
c) 54 feet
Step-by-step explanation:
Let the side of the square be x
perimeter = 4x
⇒ 36 = 4x
⇒ x = 36/4 = 9 feet
Each side is 9 feet
When we join the two squares, it becomes a rectangle with
b = 9
l = 9 + 9 = 18
The perimeter of a rectangle is 2(l + b)
perimeter = 2(18 + 9)
= 2(27)
= 54 feet
Answer:
Option (c) 54 feet
Step-by-step explanation:
Perimeter of one square is 36 feet.
Side of square = 36 / 4 = 9 feet
When combined together one side of each square merged.
So, the perimeter of rectangular shape will be;
(9+9+9) + (9+9+9)
27 + 27
54 feet.
Question 11 of 26
Given the diagram below, what is cos(45)?
Triangle not drawn to scale
A. √2
O B.
√3
C. 3-√2
45⁰
OD.
Answer:
chemical reaction that releases heat energy to the surroundings is known as endothermis reaction
4x-5 2x+7 Find the value of x
answers should be from
27
37
47
57
What are the new coordinates of point A when
it is rotated about the origin by
a) 90° clockwise?
-4
b) 180°?
c) 270° clockwise?
-3 -2 -1
Y
4-
3-
ΤΑ
2.⁰⁰
1
0
-1-
-2-
--3-
-4-
1
N.
2
3 4
X
The different coordinates after respective rotation are:
1) A'(2, 0)
2) A'(0, -2)
3) A'(-2, 0)
What are the coordinates after rotation?There are different methods of transformation such as:
Translation
Rotation
Dilation
Reflection
Now, the coordinate of the given point A is: A(0, 2)
1) The rule for rotation of 90 degrees clockwise is:
(x, y) →(y,-x)
Thus, we have:
A'(2, 0)
2) The rule for rotation of 180 degrees is:
(x, y) → (-x,-y)
Thus, we have:
A'(0, -2)
3) The rule for rotation of 180 degrees is:
(x, y) → (-y,x)
Thus, we have:
A'(-2, 0)
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0.5(x-4)=4x-3(x-1)+37/5
Answer:
Multiply to remove the fraction, then set it equal to 0 and solve.
Exact Form: x = −124/5
Decimal Form: x = −24.8
Mixed Number Form: x = −24 4/5
Please give the brainliest, really appreciated. Thank you
find the value of b
A. 14
B. 15
C. 64
D. 289
[tex] \sf \hookrightarrow \: {8}^{2} + {b}^{2} = {17}^{2} [/tex]
[tex] \sf \hookrightarrow \: 8 \times 8 + {b}^{2} = 17 \times 17[/tex]
[tex] \sf \hookrightarrow \: 8 \times 8 + {b}^{2} = 289[/tex]
[tex] \sf \hookrightarrow \: 64 + {b}^{2} = 289[/tex]
[tex] \sf \hookrightarrow \: {b}^{2} = 289 - 64[/tex]
[tex] \sf \hookrightarrow \: {b}^{2} = 225[/tex]
[tex] \sf \hookrightarrow \: b = \sqrt{225} [/tex]
[tex] \sf \hookrightarrow \: b = \sqrt{15 \times 15} [/tex]
[tex] \sf \hookrightarrow \: b = 15[/tex]
B) b = 15 ✅(08.01 MC)
The function h(x) is a continuous quadratic function with a domain of all real numbers. The table
x h(x)
-6 12
-57
-4 4
-3 3
-24
-1 7
What are the vertex and range of h(x)?
The vertex of h(x) is (-3, 3), and the range is y ≥ 3.
To find the vertex of the quadratic function h(x), we can use the formula x = -b/2a, where the quadratic function is in the form [tex]ax^2 + bx + c[/tex].
From the given table, we can observe that the x-values of the vertex correspond to the minimum points of the function.
The minimum point occurs between -4 and -3, which suggests that the x-coordinate of the vertex is -3. Therefore, x = -3.
To find the corresponding y-coordinate of the vertex, we look at the corresponding h(x) value in the table, which is 3. Hence, the vertex of the function h(x) is (-3, 3).
To determine the range of h(x), we need to consider the y-values attained by the function.
From the table, we see that the lowest y-value is 3 (the y-coordinate of the vertex), and there are no other y-values lower than 3. Therefore, the range of h(x) is all real numbers greater than or equal to 3.
The vertex of h(x) is (-3, 3), and the range is y ≥ 3.
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The vertex of the quadratic function is (-4, 12).
The range of h(x) is [3, ∞).
To find the vertex and range of the quadratic function h(x) based on the given table, we can use the properties of quadratic functions.
The vertex of a quadratic function in the form of f(x) = ax² + bx + c can be determined using the formula:
x = -b / (2a)
The domain of h(x) is all real numbers, we can assume that the quadratic function is of the form h(x) = ax² + bx + c.
Looking at the table, we can see that the x-values are increasing from left to right.
Additionally, the y-values (h(x)) are increasing from -6 to -4, then decreasing from -4 to -1.
This indicates that the vertex of the quadratic function lies between x = -4 and x = -3.
To find the exact x-coordinate of the vertex, we can use the formula mentioned earlier:
x = -b / (2a)
Based on the table, we can choose two points (-4, 4) and (-3, 3).
The difference in x-coordinates is 1, so we can assume that a = 1.
Plugging in the values of (-4, 4) and a = 1 into the formula, we can solve for b:
-4 = -b / (2 × 1)
-4 = -b / 2
-8 = -b
b = 8
The equation of the quadratic function h(x) can be written as h(x) = x² + 8x + c.
Now, let's find the y-coordinate of the vertex.
We can substitute the x-coordinate of the vertex, which we found as -4, into the equation:
h(-4) = (-4)² + 8(-4) + c
12 = 16 - 32 + c
12 = -16 + c
c = 28
The equation of the quadratic function h(x) is h(x) = x² + 8x + 28.
The range of the quadratic function can be determined by observing the y-values in the table.
From the table, we can see that the minimum y-value is 3.
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12. Write the coordinates of Triangle ABC.
A. 2 B.5 C. 6
13. Translate the Triangle (-2, 5). Draw the new image on the grid above.
14. Each coordinate will move how many on the x-axis? 8
Direction right
I
15. Each coordinate will move how many on the y-axis?
ordinates to the translated triangle image.
Given the following diagram: We need to find the coordinates of triangle ABC, translate the triangle (-2, 5) and draw the new image on the grid above, and determine the amount each coordinate will move on the x-axis and y-axis during translation.
1. Coordinates of triangle ABC:A = (2, 6)B = (5, 8)C = (6, 3)2. Translation of triangle (-2, 5)The translation of a triangle can be done by adding or subtracting a constant value from the x-coordinates and y-coordinates of each vertex of the original triangle.
For example, if we want to translate a triangle by 3 units to the right and 2 units up, we would add 3 to the x-coordinates and add 2 to the y-coordinates of each vertex of the original triangle. Using this method, we can translate the triangle (-2, 5) as follows:
New coordinates of A = (2 + (-2), 6 + 5) = (0, 11)New coordinates of B = (5 + (-2), 8 + 5) = (3, 13)New coordinates of C = (6 + (-2), 3 + 5) = (4, 8)3. New image of triangle (-2, 5)The new image of the triangle (-2, 5) is shown in the following diagram:4. Amount each coordinate moves on x-axis During translation, each coordinate moves 2 units to the right (from -2 to 0).5. Amount each coordinate moves on y-axis During translation, each coordinate moves 6 units up (from 5 to 11).
Therefore, the coordinates of the translated triangle image are (0, 11), (3, 13), and (4, 8).
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(3x-1)(x-2)=5x+2 ecuación cuadrática incompleta
Hence, the arrangements to the quadratic equation (3x-1)(x-2) = 5x + 2 are x = and x = 4.
Quadratic equation calculation.
To unravel the quadratic equation (3x-1)(x-2) = 5x + 2, let's to begin with grow the cleared out side of the equation:
(3x - 1)(x - 2) = 5x + 2
Growing the condition:
3x^2 - 6x - x + 2 = 5x + 2
Streamlining the condition:
3x^2 - 7x + 2 = 5x + 2
Another, let's move all terms to one side of the condition:
3x^2 - 7x - 5x + 2 - 2 =
Combining like terms:
3x^2 - 12x =
Presently, we have a quadratic condition in standard shape: ax^2 + bx + c = 0, where a = 3, b = -12, and c = 0.
To fathom the quadratic equation, able to calculate out the common calculate of x:
x(3x - 12) =
From this equation, we are able see that the esteem of x can be or unravel for 3x - 12 = 0:
3x - 12 =
Including 12 to both sides:
3x = 12
Isolating both sides by 3:
x = 4
Hence, the arrangements to the condition (3x-1)(x-2) = 5x + 2 are x = and x = 4.
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(5/8x+y^5)(y^5- 5/8x) write the expression as a polynomial
100 points for this
Answer:
y^10 + (5/8xy^5 - 5/8xy^6) - (25/64x^2)
Step-by-step explanation:
To simplify the given expression, we can expand it using the distributive property:
(5/8x + y^5)(y^5 - 5/8x)
Expanding the expression yields:
= (5/8x * y^5) + (5/8x * -5/8x) + (y^5 * y^5) + (y^5 * -5/8x)
= (5/8xy^5) - (25/64x^2) + y^10 - (5/8xy^6)
Combining like terms, we have:
= y^10 + (5/8xy^5 - 5/8xy^6) - (25/64x^2)
Hope this help! Have a good day!
Please answer ASAP I will brainlist
Answer:
log(3x⁹y⁴) = log 3 + 9 log x + 4 log y
Answer:
[tex]\log 3+ 9\log x +4 \log y[/tex]
Step-by-step explanation:
Given logarithmic expression:
[tex]\log 3x^9y^4[/tex]
[tex]\textsf{Apply the log product law:} \quad \log_axy=\log_ax + \log_ay[/tex]
[tex]\log 3+\log x^9 +\log y^4[/tex]
[tex]\textsf{Apply the log power law:} \quad \log_ax^n=n\log_ax[/tex]
[tex]\log 3+ 9\log x +4 \log y[/tex]
Please answer ASAP I will brainlist
Answer:
X intercepts: (-2, 0), (2, 0)
Y intercept: (0, 4)
Edited because I forgot to put in point form earlier. Depends on whether your teacher wants it in point form. If not, ignore the 0s.
Step-by-step explanation:
X intercepts are the points where a line crosses the x axis. Y intercepts are the points where a line crosses the y axis.
Answer:
A. x-intercept: (-2,0), (2,0)
A. y-intercept: (0,4)
Step-by-step explanation:
If you want to find the x and y-intercept of a line, you need to know its equation. But don't worry, it's not as hard as it sounds. Here are some tips to help you out.
One type of equation is y = mx + c, where m is the slope and c is the y-intercept. This means that the line crosses the y-axis at c. To find the x-intercept, just plug in y = 0 and solve for x. You'll get x = -c/m. Easy peasy!
For example, if the equation is y = 2x + 4, then the y-intercept is 4 and the x-intercept is -2.
Another type of equation is ax + by + c = 0, where a, b and c are constants. To find the x-intercept, plug in y = 0 and solve for x. You'll get x = -c/a. To find the y-intercept, plug in x = 0 and solve for y. You'll get y = -c/b. Piece of cake!
For example, if the equation is 3x + 2y - 6 = 0, then the x-intercept is 2 and the y-intercept is -3.
Now you know how to find the x and y-intercept of a line from its equation.Let us understand the calculations to find the x and y intercept, through the steps in the below table.
Read the following conditional statement:
If one of the angles of a triangle equals 90º, then the triangle is classified as a right triangle.
Which of the following choices is the first step of an indirect proof?
If the triangle is a right triangle
If the triangle is not a right triangle
If the triangle equals 90º
None of these choices are correct.
Answer/Step-by-step explanation:
C., the first proof we would be given if a little box is shown, which indicates a 90 degree angle at the place where to lines touch in a T kind of manor. So C is the answer.
A high school robotics club sold cupcakes at a fundraising event.
They charged $2.00 for a single cupcake, and $4.00 for a package of 3 cupcakes.
They sold a total of 350 cupcakes, and the total sales amount was $625.
The system of equations below can be solved for , the number of single cupcakes sold, and , the number of packages of 3 cupcakes sold.
Multiply the first equation by 2. Then subtract the second equation. What is the resulting equation?
x + 3y = 350
2x + 4= 625
Type your response in the box below.
$$
The resulting equation after multiplying the first equation by 2 and subtracting the second equation is:
-5y = -375
1. Given equations:
- x + 3y = 350 (Equation 1)
- 2x + 4y = 625 (Equation 2)
2. Multiply Equation 1 by 2:
- 2(x + 3y) = 2(350)
- 2x + 6y = 700 (Equation 3)
3. Subtract Equation 2 from Equation 3:
- (2x + 6y) - (2x + 4y) = 700 - 625
- 2x - 2x + 6y - 4y = 75
- 2y = 75
4. Simplify Equation 4:
-2y = 75
5. To isolate the variable y, divide both sides of Equation 5 by -2:
y = 75 / -2
y = -37.5
6. Therefore, the resulting equation is:
-5y = -375
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APQR-ASTU. Solve for x. Enter the number only.
The length of the unknown side x using the concept of similar triangles is: x = 4
How to find the side lengths of similar triangles?Similar triangles are referred to as triangles that have the same shape but different sizes. All equilateral triangles and squares of any side length are examples of similar objects. In other words, if two triangles are similar, their corresponding angles are the same and their corresponding side proportions are the same.
Now, we are told that triangle PQR is similar to Triangle STU and as such their corresponding sides are similar and therefore to find the missing side x, we have:
12/x = 15/5
x = (12 * 5)/15
x = 60/15
x = 4
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2.3.5 Quiz: Cross-Sections of Geometric Solids
OA. Triangle
OB. Circle
OC. Trapezoid
OD. Rectangle
The cross section of the geometric solid is (d) rectangle
How to determine the cross section of the geometric solidFrom the question, we have the following parameters that can be used in our computation:
The geometric solid
Also, we can see that
The geometric solid is a cylinder
And the cylinder is divided vertically
The resulting shape from the division is a rectangle
This means that the cross section of the geometric solid is (d) rectangle
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The shape of the cross-section for the geometric solid given in the diagram is a rectangle.
The cross section of the geometric solid represents the shape which extends beyond the actual geometric solid which is a cylinder.
A rectangle has opposite side being equal. This means that the width and and length are of different length.
Therefore, the shape of the cross-section is a rectangle.
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Given the following equation of a line x+6y= 3, determine the slope of a line that is perpendicular.
The slope of a line that is perpendicular to the given line x + 6y = 3 is 6.
To determine the slope of a line that is perpendicular to the given line, we need to find the negative reciprocal of the slope of the given line.
The equation of the given line is x + 6y = 3.
To find the slope of the given line, we can rearrange the equation into slope-intercept form (y = mx + b), where m represents the slope:
x + 6y = 3
6y = -x + 3
y = (-1/6)x + 1/2
From the equation y = (-1/6)x + 1/2, we can see that the slope of the given line is -1/6.
To find the slope of a line that is perpendicular, we take the negative reciprocal of -1/6.
The negative reciprocal of -1/6 can be found by flipping the fraction and changing its sign:
Negative reciprocal of -1/6 = -1 / (-1/6) = -1 * (-6/1) = 6
Therefore, the slope of a line that is perpendicular to the given line x + 6y = 3 is 6.
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A rigidly tie bar in a heating chamber has a diameter of 10 mm and is tensioned
The initial stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], the resultant stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex] and the induced force in the bar when the temperature reaches 50°C is 100.03 kN.
To calculate the initial stress in the tie bar, we can use the formula:
Stress = Load/Area
The area of the tie bar can be calculated using the formula for the area of a circle:
Area = π * [tex](diameter/2)^2[/tex]
Plugging in the values, we get:
Area = π * [tex]10 mm^{2}[/tex] = π *[tex](5 mm)^2[/tex] = 78.54 [tex]mm^2[/tex]
Converting the area to square meters, we have:
Area = 78.54 [tex]mm^2[/tex]* (1 m^2 / 1,000,000 [tex]mm^2[/tex]) = 7.854 × 1[tex]0^-5 m^2[/tex]
Now we can calculate the initial stress:
Initial Stress = 100 kN / 7.854 ×[tex]10^-5 m^2[/tex] = 1.273 × [tex]10^9 N/m^2[/tex]To calculate the resultant stress when the temperature rises to 50°C, we need to consider the thermal expansion of the tie bar. The change in length can be calculated using the formula:
ΔL = α * L0 * ΔT
Where ΔL is the change in length, α is the coefficient of linear expansion, L0 is the initial length, and ΔT is the change in temperature.
The induced force in the bar can be calculated using the formula:
Induced Force = Initial Stress * Area + E * α * ΔT * Area
Plugging in the values, we get:
Induced Force = (1.273 × 10^9 N[tex]m^2[/tex] * 7.854 × [tex]10^-5 m^2[/tex]) + (200 × [tex]10^9[/tex] N/[tex]m^2[/tex] * 14 × [tex]10^-6[/tex] /K * (50 - 15) K * 7.854 × [tex]10^-5 m^2[/tex])
Simplifying the equation, we find:
Induced Force = 100.03 kN
Therefore, the initial stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], the resultant stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], and the induced force in the bar when the temperature reaches 50°C is 100.03 kN.
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The probable question may be:
A rigidly held tie bar in a heating chamber has a diameter of 10 mm and is tensioned to a load of 100 kN at a temperature of 15°C. What is the initial stress, the resultant stress and what will be the induced force in the bar when the temperature in the chamber has risen to 50°C? E= 200 GN/ m2 and the coefficient of linear expansion of the material for tie bar = 14 × 10−6 /K.
The principal P is borrowed at a simple interest rate r for a period of time t. Find the loans future value A, or the total amount due at time t. P equals $9,000, r eeuals 10%, t equals 6 months. The loans future value is
The future value of the loan, or the total amount due at the end of 6 months, is $9,450.
We can use the following formula to calculate the future value of a loan:
[tex]A = P + P * r * t[/tex]
Given: $9,000 principal (P).
10% interest rate (r) = 0.10
6 months is the time period (t).
When we enter these values into the formula, we get:
A=9,000+9,000*0.10*6/12
First, compute the interest portion:
Interest is calculated as = 9,000*0.10*6/12=450
We may now calculate the future value:
A=9,000+450=9,450
As a result, the loan's future value, or the total amount payable in 6 months, is $9,450.
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what is this solution to the problem of ? 12÷132
Answer:
0.090909
Step-by-step explanation:
I used a calculator
Please help! Will give brainliest
The z - score z = (x - μ)/σ equals z = (p' - p)/[√(pq/n)]
What is z-score?The z-score is the statical value used to determine probability in a normal distribution
Given the z-score z = (x - μ)/σ where
x = number of successes in a sample of nμ = np and σ = √npqWe need to show that
z = (p' - p)/√(pq/n)
We proceed as follows
Now, the z-score
z = (x - μ)/σ
Substituting in the values of μ and σ into the equation, we have that
μ = np and σ = √(npq)So, z = (x - μ)/σ
z = (x - np)/[√(npq)]
Now, dividing both the numerator and denominator by n, we have that
z = (x - np)/[√(npq)]
z = (x - np) ÷ n/[√(npq)] ÷ n
z = (x/n - np/n)/[√(npq)/n]
z = (x/n - p)/[√(npq/n²)]
z = (x/n - p)/[√(pq/n)]
Now p' = x/n
So, z = (x/n - p)/[√(pq/n)]
z = (p' - p)/[√(pq/n)]
So, the z - score is z = (p' - p)/[√(pq/n)]
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Will give brainlieest. 50 points. (8x + 2x³ - 4x²) - (4 + x³ + 6x)
Answer:
[tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] + 2x - 4
Step-by-step explanation:
(8x + 2[tex]x^{3}[/tex] - 4[tex]x^{2}[/tex]) - (4 + [tex]x^{3}[/tex] + 6x)
= 8x + 2[tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] - 4 - [tex]x^{3}[/tex] - 6x
= 2x + [tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] - 4
= [tex]x^{3}[/tex] - 4[tex]x^{2}[/tex] + 2x - 4
What is the probability that a ball drawn at random from a jar?
Select one:
a. Cannot be determined from given information
b. 0.5
c. 1
d. 0.1
e. 0
Note: Answer D is NOT the correct answer. Please find the correct answer. Any answer without justification will be rejected automatically.
In the figure, m<1 = (x+6)°, m<2 = (2x + 9)°, and m<4 = (4x-4)°. Write an
expression for m<3. Then find m<3.
A. 180° -(x+6)°
B. 180° -(4x-4)°
C. 180° - [(2x+9)° + (x+6)°]
D. 180° + (x+6)°
m<3=
The expression for m<3 is 349° - 7x.
To find the measure of angle 3 (m<3), we need to apply the angle sum property, which states that the sum of the angles around a point is 360 degrees.
In the given figure, angles 1, 2, 3, and 4 form a complete revolution around the point. Therefore, we can write:
m<1 + m<2 + m<3 + m<4 = 360°
Substituting the given angle measures, we have:
(x + 6)° + (2x + 9)° + m<3 + (4x - 4)° = 360°
Combining like terms:
7x + 11 + m<3 = 360°
To isolate m<3, we subtract 7x + 11 from both sides:
m<3 = 360° - (7x + 11)
m<3 = 360° - 7x - 11
m<3 = 349° - 7x
Therefore, the expression for m<3 is 349° - 7x.
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In the triangle below, which of the following best describes DH?
A. Angle bisector
B. Altitude
C. Median
D. Perpendicular bisector
Answer:
AStep-by-step explanation:Angle EDH=Angle FDH, so A must be correct.
Also, we don't have more information to prove B, C, D is right
Answer:
A.
Step-by-step explanation:
An angle bisector is a line, ray, or segment that divides an angle into two equal parts. It divides the angle into two congruent or equal angles. The angle bisector originates from the vertex of the angle and extends towards the interior of the angle. It essentially cuts the angle into two smaller angles of equal measure.
If two opposite sides of a square are increased by 13 meters and the other sides are decreased by 7 meters, the area of the rectangle that is formed is 69 square meters. Find the area of the original square.
Answer:
(x + 13)(x - 7) = 69
x² + 6x - 91 = 69
x² + 6x - 160 = 0
(x + 16)(x - 10) = 0
x = 10, so the area of the original square is 100 m².
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