Cecelia receives two credit card offers in the mail. Each has a 0% introductory APR. After the introductory period, the first card has an APR of 19.99% and the second card has an APR of 24.99%. If each card has a late fee of $35 and an annual membership fee of $25, which card should she choose and why?

Answers

Answer 1

Answer:

1. We are told they have similar APR (starting) and Annual fee of 25 and similar late fee of 35

Then we must consider the APR after the initial value 19.999% < 24.99%

Hence she should price the first card with a 19.99% APR


Related Questions

There are 12 girls and 14 boys in class today. What is the ratio of girls
to boys? whats the answer

Answers

answer is- 2:4
pretty sure

Answer:

12:14

Step-by-step explanation:

(01.02 MC)

The distance, d(t), in feet, a bug has traveled is shown in the graph.

A coordinate plane with a function d of t consisting of a line starting at 0 comma 1 rising to 1 comma 2, a horizontal line from 1 comma 2 to 2 comma 2, a line falling from 2 comma 2 to 3 comma 1, and a line falling from 3 comma 1 to 6 comma 0.

Estimate the rate of change in the distance of the bug at time t = 4 seconds.

negative one third ft/s
the limit as t approaches 4 of the function d of t feet per second
d(4) ft/s
0.7 ft/s

Answers

When we have a given function f(x), the rate of change in a given value x₀ is given by:

[tex]\frac{df(x_0)}{dx} = \lim_{h \to 0} \frac{f(x_0 + h) - f(x_0)}{h}[/tex]

We will find that the rate of change at t = 4s is:

r = -1/3

Now we can't do this if we do not have the function and we only have a text description of the graph, but what we can do is find the average rate of change.

For a function f(x), the average rate of change in an interval (a, b) such that a < b is given by:

[tex]r = \frac{f(b) - f(a)}{b - a}[/tex]

Something really nice is that the average rate of change is equal to the exact rate of change if f(x) is a linear equation.

If we want to find the rate of change at t = 4, then we need to find the smallest interval that contains t = 4.

Here we know that the graph passes through the points:

(3,1) to (6, 0)

Because of the statement "a line falling from (3, 1) to (6, 0)" we know that in this segment we have a line, which implies that the average rate of change will be equal to the exact rate of change.

Using the equation of the average rate of change we get:

[tex]r = \frac{d(6) - d(3)}{6 - 3} = \frac{0 - 1}{3} = - 1/3[/tex]

Then the rate of change in the distance at the time t = 4s is -1/3.

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The perimeter of a right-angled triangle is 96 cm.
The lengths of its sides are in the ratio 6: 8:10
Work out the area of the triangle in cmp.

Answers

Perimeter = the sum of all the sides. In this case, we know the ratio but not what each would be multiplied by, hence the variable.

6x + 8x + 10x = 96

24x = 96

x = 4

6(4) = 24

8(4) = 32

10(4) = 40

Check:

24 + 32 + 40 = 96 cm

Area = (base * height) / 2

Base = 32

Height = 24

(The base and height are interchangeable here, as we just have to make sure we're multiplying the legs of the triangle together and avoiding the hypotenuse.)

(32 * 24) / 2

768 / 2

384

Area = 384 cm^2

Hope this helps!

the value of the power 4⁴=​

Answers

Answer:

256

Step-by-step explanation:

4⁴

= 4 × 4 × 4 × 4

= 16 × 16

= 256

13. State the restrictions
and then simplify
8x2 +14x-49 /
2x²+x-21

Answers

Answer:

Whenever the denom is 0, that's where it's undefined -- or in your case "restrictions"

So factoring 2x^2 + x - 21 gets you (x-3)(2x+7). That means 3 and -7/2 are the restricted values.

To simplify, I'm going to factor it. (Assuming what you wrote is 8x^2 for the numerator)

[(4x-7)(2x+7)] / (x-3)(2x+7)

You can cancel 2x+7 out,

so you get 4x-7/x-3

SUBTRACT. -18- (-12)
O
30
O
6

Answers

Answer: -6

Step-by-step explanation:

-18 - (-12)

= -6

none of them

it's actually-6.

let x^4+y^4=16 and consider y as a function of x. use the implicit differentiation to find y"

Answers

Answer:

[tex] \frac{dy}{dx} = - \frac{ {x}^{3} }{ {y}^{3} } [/tex]

Step-by-step explanation:

Differentiate both sides of the equation (consider y as a function of x).

[tex] \frac{d}{dx} ( {x}^{4} + {y}^{4} (x)) = \frac{d}{dx} (16)[/tex]

the derivative of a sum/difference is the sum/difference of derivatives.

[tex]( \frac{d}{dx} ( {x}^{4} + {y}^{4} (x))[/tex]

[tex] = ( \frac{d}{dx} ( {x}^{4} ) + \frac{d}{dx} ( {y}^{4} (x)))[/tex]

the function of y^4(x) is the composition of f(g(x)) of the two functions.

the chain rule:

[tex] \frac{d}{dx} (f(g(x))) = \frac{d}{du} (f(u)) \frac{d}{dx} (g(x))[/tex]

[tex] = ( \frac{d}{du} ( {u}^{4} ) \frac{d}{dx} (y(x))) + \frac{d}{dx} ( {x}^{4} )[/tex]

apply the power rule:

[tex](4 {u}^{3} ) \frac{d}{dx} (y(x)) + \frac{d}{dx} ( {x}^{4} )[/tex]

return to the old variable:

[tex]4(y(x) {)}^{3} \frac{d}{dx} (y(x)) + \frac{d}{dx} ( {x}^{4} )[/tex]

apply the power rule once again:

[tex]4 {y}^{3} (x) \frac{d}{dx} (y(x)) + (4 {x}^{3} )[/tex]

simplify:

[tex]4 {x}^{3} + 4 {y}^{3} (x) \frac{d}{dx} (y(x))[/tex]

[tex] = 4( {x}^{3} + {y}^{3} (x) \frac{d}{dx} (y(x)))[/tex]

[tex] = \frac{d}{dx} ( {x}^{4} + {y}^{4} ))[/tex]

[tex] = 4( {x}^{3} + {y}^{3} (x) \frac{d}{dx}(y(x))) [/tex]

differentiate the equation:

[tex]( \frac{d}{dx} (16)) = (0)[/tex]

[tex] = \frac{d}{dx} (16) = 0[/tex]

derivative:

[tex]4 {x}^{3} + 4 {y}^{3} \frac{dy}{dx} = 0[/tex]

[tex] \frac{dy}{dx} = - \frac{ {x}^{3} }{ {y}^{3} } [/tex]

Find the area of the shaded region.​

Answers

Step-by-step explanation:

find the area of the big semicircle and the small semicircle.minus the area of the small semicircle from the big semicircle.

now find the area of the other semicircle on top of the big semicircle.

add your results

area of semicircle=1/2(pir^2)

This car traveled 3 miles per 1 min. Tell me how far the car will travel at 6 mins. Use a table to show your work .

Answers

Answer:

min | miles

———|———

1 | 3

2 | 6

3 | 9

4 | 12

5 | 15

6 | 18

Step-by-step explanation:

try putting this into a T-chart like I kind of did here or some other kind of other table.

272 students enrolled in a freshman-level chemistry class. By the end of the semester, 7 times the number of students passed as failed. Find the number of students who passed, and the number of students who failed.

Answers

The number of students who passed is 234 and the number of students who failed is 39.

To find number of students who passed, and the number of students who failed.

What is arithmetic?

The branch of mathematics dealing with the properties and manipulation of numbers.

Given that:

students enrolled in a freshman-level chemistry class=272

By the end of the semester, 7 times the number of students passed as failed.

Let x is number of students failed.

Then 6x is number of students passed.

So, 6x + x = 273

7x = 273,

∴x = 39

number of students passed= 273 - 39 = 234

So, the number of students who passed is 234 and the number of students who failed is 39.

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Which features describe the graph? Select all that apply.
ту
14
-2
O
-2
domain: (-3,3]
Orange: (-3,4]
decreasing: (-1.4)
increasing: (-3,-1)
negative: (-3,-2), (2,5]
positive: (-2,2)

Answers

Answer:

Only Option III, IV, VI are correct

Step-by-step explanation:

Domain is the set of values of x at which the function is defined. f(x) has defined values from x>-3 to x<=4, so the domain is (-3,4). Incorrect.

Range of the function is the set of all defined values of it. Here all values with y=f(x)>-3 and y<=3 are defined. So the range is (-3, 3}.

Decreasing and increasing parts of the funtion are shown in the graph when the y value goes up (positive slope) and vice versa.

The negative part of the function should be (3,-2) and (2,4] since (4, 5] is not defined and there is no indication for its negative-ness.

On my last birthday I weighed 180 pounds. One year later my weight was decreased by x pounds, write the expression that gives my weight one year later.

Which is the action to take?

A) Multiplication

B) division

C) subtraction

D) addition

Answers

Answer:

c

Step-by-step explanation:

The expression that gives my weight one year later is (180 pounds - x pounds). Hence the subtraction action that gives weight one year later.

Given that;

On my last birthday, I weighed 180 pounds.

And, One year later my weight decreased by x pounds.

Now the equation to represent the weighed after one year,

180 pounds - x pounds

Hence we can use the subtraction action that gives weight one year later.

Therefore, the correct option is C.

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what is four fifteenths times two thirds?

Answers

Answer:

Try 0.17? I hope it's right

Answer:

2 10/15 or 2 2/3 (simplified)

Step-by-step explanation:

To Multiply we need to get the same denominator for each fraction:

2 x 5 =10

3 x 5 =15

10/15

4/15 x 10/15 (or) 4 x 10 = 40/15

40/15 (also) = 2 10/15

2 2/3 (simplified version of 2 10/15)

Hope This Helps! :)

Find the equation of a line that contains the points (3,7) and (-6, 4). Write the equation in slope-intercept form, using
fractions when required.

Answers

Answer:

[tex]y=\frac{1}{3} x+6[/tex]

Step-by-step explanation:

[tex](3,7)(-6,4)[/tex]

Step 1. Find the slope (by using the slope-formula)

m = slope

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{4-7}{-6-3}[/tex]

[tex]m=\frac{-3}{-9}[/tex]

[tex]m=\frac{3}{9}[/tex]

[tex]m=\frac{1}{3}[/tex]

Step 2. Write the equation (using the slope and the points)

Here's how to do it:

Slope-intercept Formula [tex]y=mx+b[/tex] whrere m = slope and b = y-intercept

Plug in the slope into the Slope-intercept Formula

[tex]y=\frac{1}{3} x+b[/tex]

Find the y-intercept (b) by using a point and substituting their x and y values

[tex]y=\frac{1}{3} x+b[/tex]

Point: (3, 7)

[tex]7=\frac{1}{3} (3)+b[/tex]

[tex]7=1+b[/tex]

[tex]b=7-1[/tex]

[tex]b=6[/tex]

Step 3. Write the equation in Slope-intercept form

[tex]y=mx+b[/tex]

[tex]y=\frac{1}{3} x+6[/tex]

Determine the 1st and 2nd degree Taylor polynomials L(x,y) and Q(x,y) for
f(x, y) = tan^−1(xy) for (x, y) near the point (1,1).

Answers

Answer:

Step-by-step explanation:

[tex]f(x,y)=arctan(xy)\\\\\dfrac{ \partial f}{ \partial x}=\dfrac{y}{1+x^2y^2} \\\\\dfrac{ \partial f}{ \partial y}=\dfrac{x}{1+x^2y^2} \\\\\dfrac{ \partial ^2 f}{ \partial x^2}=\dfrac{-2xy^3}{(1+x^2y^2)^2} \\\\\dfrac{ \partial ^2 f}{ \partial y^2}=\dfrac{-2x^3y}{(1+x^2y^2)^2} \\\\\dfrac{ \partial ^2 f}{ \partial x\ \partial y}=\dfrac{1-x^2y^2}{(1+x^2y^2)^2} \\[/tex]

[tex]f(x,y)= f(1,1)+(x-1)\dfrac{\partial f}{\partial x} (1,1)+(y-1)\dfrac{\partial f}{\partial y} (1,1)+\dfrac{(x-1)^2}{2} \dfrac{\partial^2 f}{\partial x^2} (1,1)+(x-1)(y-1)\dfrac{\partial^2 f}{\partial x\ \partial y} (1,1)+\dfrac{(y-1)^2}{2} \dfrac{\partial^2 f}{\partial y^2} (1,1)+...\\\\=\dfrac{\pi}{4}+\dfrac{(x-1)}{2} +\dfrac{(y-1)}{2} -\dfrac{(x-1)^2}{4} +(x-1)(y-1)*\dfrac{0}{4}-\dfrac{(y-1)^2}{4} \\\\[/tex]

[tex]\boxed{f(x,y)=\dfrac{\pi}{4}+\dfrac{(x-1)}{2} +\dfrac{(y-1)}{2} -\dfrac{(x-1)^2}{4} -\dfrac{(y-1)^2}{4} }\\\\[/tex]

12 63 x 42 is equivalent to 216 x 16. True or False?​

Answers

Answer:

False

Step-by-step explanation:

63 x 42= 2646

216 x 16= 3456

have a great day

-5 - (-14)

Which expressions are equivalent to the given expression?

A. -5 - 14
B. -5 + 14
C. -14-(-5)
D. -14 +5
E. -14 - 5
F. 14 - (-5)
G. 14 + 5
H. 14 - 5

7th grade math

Answers

Answer:

[tex]b) h) \\ - 5 - ( - 14) \\ = - 5 - - 14 \\ = - 5 + 14( - \times - = + )-5+14=14-5 \\ thank \: you[/tex]

Answer:

-5 + 14

14 - 5

Step-by-step explanation:

Use the appropriate method to find the quotient and the remainder when 8x³+4x+3 is divided by 2x-1​

Answers

f(x)=8x^3+4x+3 ; 2x-1=0 —> x=1/2
f(1/2)= 8(1/8) + 4(1/2) + 3
= 1+2+3 = 6 # the remainder
or



1.6 lbs. = __ gal
how many gallons are in 1.6lbs?

Answers

11.9 gallons I think

write 45 as a product of prime numbers

Answers

Answer:

3²×5

Step-by-step explanation:

Product of its prime numbers its more like having the number in its simplest form by factorising it

ANSWER PLEASE NO FAKE ANSWERS ILL GIVE BRAINLIEST: Jaxson did the following problem incorrectly. Choose the option that correctly identifies what Jaxson did
wrong
Jaxson's work: 8 3/5 + 7 1/8 = 15 4/3
1. Jaxson forgot to simplify his answer.
2. Jaxson should have changed the mixed numbers to improper fractions.
3. Jaxson added the denominators instead of finding a common denominator and leaving it alone,
4. Jaxson did not make a mistake. He did everything right.

Answers

Answer:

3. Jaxson added the denominators instead of finding a common denominator and leaving it alone

Step-by-step explanation:

8 3/5 + 7 1/8 = 15 4/3

Get a common denominator

8 3/5 *8/8  + 7 1/8 *5/5

8 24/40 + 7 5/40

15 29/40

what is the arithmetic sequence of a1=228 n=28 sn=2982

Answers

Answer:

use the formula sn= n(a1+an)/2

Step-by-step explanation:

2982=28(228+an)/2

5964=28(228+an)

5964/28=228+an

213=228+an

an=-15(last term)

to find difference use formula

an = a+(n-1)d

-15=228+(28-1)d

-243=27d

d=-243/27

d=-9

arithmetic sequence  can be found be keep on subtracting 9 from 228

hence the arithmetic sequence is

228, 219, 210, 201, 192, 183, 174........-15

Solve for a: 7a = 63

Answers

Answer:

a = 9

Step-by-step explanation:

7a = 63

Divide 7 on both sides,

=> 7a/7 = 63/7

=> a = 9

The width of a rectangle measures (2p - 9q) centimeters, and its length measures
(7p - 10q) centimeters. Which expression represents the perimeter, in centimeters,
of the rectangle?

Answers

Given Data : Length = (7p - 10q) and Breadth = (2p - 9q)

Calculation :

⟹ Perimeter = 2(Length + Breadth)

⟹ Perimeter = 2(7p - 10q + 2p - 9q)

⟹ Perimeter = 2(9p - 19q)

⟹ Perimeter = 18p - 38q centimetres

Answer : 18p - 38q centimetres

The required perimeter of the rectangle is 18p - 38q centimeters.

It is required to find the required perimeter of the rectangle.

What is rectangle?

A rectangle is a type of quadrilateral, whose opposite sides are equal and parallel. It is a four-sided polygon that has four angles, equal to 90 degrees. A rectangle is a two-dimensional shape.

Given:

width of a rectangle = (2p - 9q) centimeters,

length measures= (7p - 10q) centimeters.

We know that

⟹ Perimeter = 2(Length + Breadth)

By put the value width and length in perimeter we get,

⟹ Perimeter = 2(7p - 10q + 2p - 9q)

⟹ Perimeter = 2(9p - 19q)

⟹ Perimeter = 18p - 38q centimeters

Therefore, the required perimeter of the rectangle is 18p - 38q centimeters.

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Pls answer this question! I will mark as brainliest!!!

Answers

Answer:

1/8

Step-by-step explanation:

There is a 1/2 probability for each of the three flips to result in the desired outcome. To get 3 desired outcomes in a row, we multiply each of the probabilities together

(1/2)³ = 1/8

Answer: it is D) 2/3

Which expression is equivalent to 6x+8 + x+15

Answers

The equivalent expression is 7x+23! It’s just simplifying both types of numbers to get a simplified expression!

10 employees only eat
vegetables and 25 employees
eat meat. What is the ratio of
the employees who only eat
vegetables to employees who
eat meat?

Answers

The ratio is 10 to 25.

True or False
No links

Answers

Answer:

False

Brainliest, please!

Step-by-step explanation:

+ + = +

- - = +

+ - = -

- + = -

Answer:

False

Step-by-step explanation:

The question doesn't specify whether you are adding positive or negative integers. If you have add 2 positive integers, your answer will be positive. If you add 2 negative integers, the answer will be negative. Here is an example;

1 + 1 = 2

-1 + (-1) = -1 - 1 = -2

Best of Luck!

Note: Enter your answer and show all the steps you use to solve this problem in the space provided. 6 × 5 + 3 × 8
Make it simple, please

Answers

Answer:

54

Step-by-step explanation:

6x5=30

3x8=24

30+24=54

What do these have in common??

Answers

Answer:

They can all be simplified to 2/3

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