Calculate area and round to nearest tenth.

f(x) < g(x)

(2x + 3) < (3x - 2)

3 < x - 2

5 < x

x > 5

Check:

2x + 3 < 3x - 2

2(5) + 3 < 3(5) - 2

10 + 3 < 15 - 2

13 < 13 --- FALSE

2(10) + 3 < 3(10) - 2

20 + 3 < 30 - 2

23 < 28 --- TRUE

Hope this helps!

Answer:

x < 5

Step-by-step explanation:

f(x) < g(x) if f(x) = 2x + 3 and g(x)= 3x - 2 ​

2x + 3 < 3x - 2 ​

2x - 3x < -2 -3

-x < -5

x > 5

From the information given, the total length of the stream will be 548.89 meters

The length of the first stream =  45.27 meters

The length of the second stream = 503.62 meters

The total length of the stream will be equal to the addition of the length of the first stream and the second stream and this will be:

= 45.27 meters + 503.62 meters

= 548.89 meters

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Answer

The correct answer iss 548.89

Step-by-step explanation:

45.27+503.62=548.89

Hope this helps!

Answer:

lol someone just deleted my answer but like i said i cant really tell you unless you could possibly turn it around like up straight

Step-by-step explanation:

Answer:

4 packages

Step-by-step explanation:

Since the store sells by 1/2 packages, we have to round 1.72 UP to 2.00. Then we multiply 1/2pound by 4= 2.00 pounds

Answer:

-19

Step-by-step explanation:

g(x)=−3x−4

Let x = 5

g(5)=−3*5−4

Multiply

   = -15-4

   = -19

[tex]g(x) = - 3x - 4 \\ \\ g(5) = - 3(5) - 4\\ \\ x = - 15 - 4 \\ \\ x = - 19[/tex]

Hope it help you

There are some symbols missing in your integral. I suspect you meant something along the lines of

[tex]\displaystyle \int_C (x+5y)\,\mathrm dx + x^2\,\mathrm dy[/tex]

but we can consider a more general integral,

[tex]\displaystyle \int_C f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy[/tex]

One way to compute the integral is to split up C into two component paths C₁ and C₂, parameterize both, directly compute the integral over each path, then sum the results.

Parameterize C₁ and C₂ respectively by

〈x₁(t), y₁(t)⟩ = (1 - t ) 〈0, 0⟩ + t 〈5, 1⟩ = 〈5t, t⟩

〈x₂(t), y₂(t)⟩ = (1 - t ) 〈5, 1⟩ + t 〈5, 0⟩ = 〈5, 1 - t⟩

where 0 ≤ t ≤ 1. Then

[tex]\displaystyle \int_C f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy = \int_{C_1} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy + \int_{C_2} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy \\\\ = \int_{C_1} \left(f(x_1(t),y_1(t))\frac{\mathrm dx_1}{\mathrm dt} + g(x_1(t),y_1(t))\frac{\mathrm dy_1}{\mathrm dt}\right)\,\mathrm dt \\ + \int_{C_2} \left(f(x_2(t),y_2(t))\frac{\mathrm dx_2}{\mathrm dt} + g(x_2(t),y_2(t))\frac{\mathrm dy_2}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^1 \left(5f(5t,t) + g(5t,t) - g(5,1-t)[/tex]

If f and g agree with what I suggested earlier, the integral reduces to

[tex]\displaystyle \int_0^1 \left(5(5t+5t) + (5t)^2 - 5^2\right)\,\mathrm dt = \int_0^1 \left(25t^2 + 50t - 25\right)\,\mathrm dt = \boxed{\frac{25}3}[/tex]

Another way would be to close the path with a line segment from (5, 0) to (0, 0) and apply Green's theorem. Compute the resulting double integral, then subtract the contribution of the line integral over this third line segment. Provided that f(x,y) and g(x,y) don't have any singularities along this closed path C* or inside the triangle (call it T ) that it surrounds, we have

[tex]\displaystyle \int_{C^*} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy = -\iint_T \frac{\partial g}{\partial x}-\frac{\partial f}{\partial y} \,\mathrm dx\,\mathrm dy[/tex]

where T is the region,

[tex]T = \left\{(x,y) \mid 0\le x\le 5 \text{ and } 0\le y\le \dfrac x5\right\}[/tex]

The double integral has a negative sign because C* has a negative, clockwise orientation.

Then

[tex]\displaystyle \int_{C^*} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy = -\int_0^5\int_0^{x/5} \frac{\partial g}{\partial x}-\frac{\partial f}{\partial y} \,\mathrm dy\,\mathrm dx[/tex]

If f and g are as I suggested, then

[tex]\displaystyle \int_{C^*} f(x,y)\,\mathrm dx + g(x,y)\,\mathrm dy = \int_0^5\int_0^{x/5} (5-2x) \,\mathrm dy\,\mathrm dx = -\frac{25}6[/tex]

From this, we subtract the integral along the line segment C₃ from (5, 0) to (0, 0), parameterized by

〈x₃(t), y₃(t)⟩ = (1 - t ) 〈5, 0⟩ + t 〈0, 0⟩ = 〈5 - 5t, 0⟩

again with 0 ≤ t ≤ 1.

Then the remaining line integral is

[tex]\displaystyle \int_{C_3} f(x_3(t),y_3(t))\,\mathrm dx_3 + g(x_3(t),y_3(t))\,\mathrm dy_3 = \int_{C_3} x_3(t)\frac{\mathrm dx_3}{\mathrm dt}\,\mathrm dt \\\\ = \int_0^1 -5(5-5t)\,\mathrm dt = -\frac{25}2[/tex]

and so the original line integral is again -25/6 - (-25/2) = 25/3.

Answer:

25

Step-by-step explanation:

5=20% of x

0.20x=5

divide both sides by 0.20

x=25

Answer:

The rate of change no [-1,4] is x

Answer:

(1 )= ..x = (2)

Step-by-step explanation:

(1) = x = (2)

Answer: 1 ≤ x ≤ 2

Step-by-step explanation:

Given inequality

3 ≤ 6x - 3 ≤ 9

Add 3 on all sides

3 + 3 ≤ 6x - 3 + 3 ≤ 9 + 3

6 ≤ 6x ≤ 12

Divide 6 on all sides

6 / 6 ≤ 6x / 6 ≤ 12 / 6

[tex]\boxed{1}[/tex] ≤ x ≤ [tex]\boxed{2}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Step-by-step explanation:

The unknown number is reflected as n.

The sum of 5 and four times a number is 32:

Four less than the square of a number is 12:

The product of 3 and four more than a number is 20:

Answer: 64.8

Step-by-step explanation:

60/100=1944/x (cross multiplication

(1944*100)/60 = 3240

2% of 3240 =

2/100 = x/3240

64.8

( this helps with percentage (%/100=is/of) and cross multiplication)

Answer:

Y=K×X

when Y=-8 and X=4

-8=K×4

-8=4K divide both sides by 4

K=-2 constant

To find Y when X=-4,Y=? and K=-2

Y=-2×-4

Y=8

Answer:

the answer will be 60 percent

=60%

Answer:

24

Step-by-step explanation:

5x³ + x² – 10x

5(2)³ + (2)² - 10(2)

5(8) + 4 - 20

= 40 + 4 - 20

= 44 - 20

= 24

Answer:

3 units per hour

Explanation:

Time = 9 hours

Difference in sales = 24 (Chromebooks)

24 ÷ 9 = 2.66...

When rounded, it equals 3.

Answer:

the answer is 1 : 2.4 because for every 1 inch on the original image there are 2.4 inches on the modified image.

Step-by-step explanation:

Step 1:

Measure the change in X and Y of a single length of the original image.

X1 = 3.5

Y1 = 5

Step 2:

Measure the change in X and Y of the same length on the modified image.

X2 = 8.5

Y2 = 12.5

Step 3:

use formula SF = X2/X1 = Y2/Y1

(SF = Scale Factor Dilation)

(X2 and Y2 = change in X and Y of the same length on the modified image.)

(X1 and Y1 = change in X and Y of a single length of the original image.)

X2 = 8.5

8.5/X1

X1 = 3.5

8.5/3.5

8.5/3.5 = 2.4

2.4

1 : 2.4

Answer:

x = 17.6

Step-by-step explanation:

We know that a quadrilateral will have a total of 360 degrees. We can create an expression and solve for x.

5x + 7x + 3x + 6 + 90 = 360

~Combine like terms

15x + 96 = 360

~Subtract 96 to both sides

15x = 264

~Divide 15 to both sides

x = 17.6

Best of Luck!

Step-by-step explanation:

P(x,y)=(1,-3)

line is perpendicular to x=2 which shows that line is parallel to x-axis.

angle=0°

m=tan(angle)

m=tan0°

m=0

By using point slope form:

y+3=0(x-1)

y+3=0

Answer:

x is 3

Step-by-step explanation:

[tex] {5}^{(x + 1)} - {5}^{(x + 2)} = - 2500 \\ [/tex]

divide all sides by -1:

[tex] {5}^{(x + 2)} - 5 {}^{(x + 1)} = 2500[/tex]

from law of indices:

[tex]( {5}^{x} . {5}^{2} ) - ( {5}^{x} . {5}^{1} ) = 2500[/tex]

factorise out 5^x:

[tex] {5}^{x} ( {5}^{2} - {5}^{1} ) = 2500 \\ {5}^{x} (20) = 2500 \\ {5}^{x} = 125 \\ {5}^{x} = {5}^{3} \\ x = 3[/tex]

Answer:

Z, K and R

and

H ,B and C

........

9514 1404 393

Answer:

   4x^2 +5x -6

Step-by-step explanation:

The remaining empty space is the difference between the original amount of empty space and the volume that was filled.

  (8x^2 +2x -4) -(4x^2 -3x +2) = 8x^2 +2x -4 -4x^2 +3x -2

  = (8 -4)x^2 +(2 +3)x +(-4 -2)

  = 4x^2 +5x -6

The jar could hold 4x^2 +5x -6 more cubic inches.

9514 1404 393

Answer:

  ₹1000

Step-by-step explanation:

Let m represent the marked price. After the discount, the price is 0.80m. After the tax is added, the price is (0.80m)(1.13). This value is Rs 904, so the marked price is ...

  (0.80m)(1.3) = ₹904

  m = ₹904/(0.80×1.13) = ₹904/0.904

  m ≈ ₹1000

The marked price of the watch is ₹1000.

9514 1404 393

Answer:

  domain: (-4, 9)

Step-by-step explanation:

The graph is defined for all points between -4 and 9, but not for those two points. In interval notation, the domain is (-4, 9).

Answer:

the function is always increasing

Step-by-step explanation:

if you look at the graph, as x increases, y increases, no matter how small the increase